Answer:
-2x -8
Step-by-step explanation:
1+9+40-40+40+10x2 equals what?
Answer:
70
Step-by-step explanation:
1+9+40-40+40+10*2
----------------------- 20
10+40-40+40+20
50 (-40+40 cancels out to 0) +20
50+20= 70
(Following PEMDAS)
Multiply, add, subtract.
if you were to instead go through it left to right, you would get 120, which is incorrect.
Find m∠DFC.
A. 23
B. 167
C. 46
D. 69
Answer:
A.23
maaf kalosalah !(!)!(!)!(!)!(!)!(!)!(!)!(!)!(!)!
Hurry quick i have more questions answer then all for a total of about 100 points
Answer:
1/5
Step-by-step explanation:
.7555555(repeating )
writing as a fraction
x = .755555555
10 x = 7.555555
Subtract the two
10x = 7.555555
-x = .75555555
--------------------------
9x =6.8
Divide each side by 9
x = 6.8/9
x = 68/90
Divide by 2
x = 34/45
We do the same for .555555 repeating
y = .5555 repeating
10 y = 5.5 repeating
10y = 5.5
-y = .555
-------------------
9y = 5
y = 5/9
Subtract x - y
34/45 - 5/9
Get a common denominator
34/45 - 25/45
9/45
1/5
which of the following are ordered pairs for the given function f(x)=1+x.? (1,2) (3,3) (0,2) (1,0) (0,1)
Answer:
no,
(
1
,
0
)
is not an ordered pair of the function
f
(
x
)
=
1
+
x
.
Step-by-step explanation:
Ordered pairs are usually written in the form
(
x
,
y
)
by tradition.
so usingthe function,
f
(
x
)
=
1
+
x
we can rewrite it as,
y
=
1
+
x
any pair of x and y that satisfy this equation are solutions to the equation.
so subbing in
(
1
,
0
)
,
0
=
1
+
(
1
)
0
=
2
which is not true so the point does not make the function true.
It might be easier to see graphically,
graph{1+x [-10, 10, -5, 5]}
any combination of x and y on this line make the equation true and as such are an ordered pair of the function.
Answer:
Step-by-step explanation:
-3x > 12
What is the value of x? Use substitution to support your answer.
Answer:
x < -4
Step-by-step explanation:
-3x > 12
----- ----
-3 -3
12 ÷ -3 = -4
Which means:
x < -4
(The sign changes because the equation is divided by a negative number)
Hope this helped.
Answer:
x <-4
Step-by-step explanation:
-3x > 12
Divide each side by -3. remembering to flip the inequality
-3x/-3 > 12/-3
x <-4
a cubical water tank is 80 CM broad how many CC of water does it hold
Answer:
I think: vol of h20 inside = side³ = (80cm)³ =512000 cm³
Please refer!
Step-by-step explanation:
I'm not sure but hope it helps.
438 Friday night, 820 Saturday night and 636 Sunday afternoon. How many more people attended the play on Sunday than on Friday?
Answer:
198 more people attended the play on Sunday than on Friday
Step bye step explanation:
638 - 438 = 198.
(438 Friday night
(438 Friday night 636 Sunday night)
A square has a side length of 520
meters. What is the perimeter of
the square in kilometers?
Answer: 2.08 km
Step-by-step explanation:
Side of Square = 520 m
Perimeter of Square = Side × 4
= 520 × 4
= 2080 m
1000 m = 1km
2080 m = 2080 ÷ 1000
= 2.08 km
find the missing side. round your answer to the nearest tenth. PLEASE HURRY!
Answer:
44.8
Step-by-step explanation:
Using the Cosine formula, we first have Cos 48 = 30/x. So then we just solve for x and get 44.8342965, which rounds to 44.8
I hope this helped! :D
Complete the equation: x^ 2 +6x+__ =(_)^ 2
Answer:
x^2+6x+9= (x+3)^2
Step-by-step explanation:
x^ 2 +6x+__ =(_)^ 2
The formula is a^2+2ab+b^2= (a+b)^2
x^2= a^2
x=a
6x=2ab where a=x
6x=2x*b
b=3
b^2=9
x^2+6x+9= (x+3)^2
Correct the formula
Please
Answer:
The addition should be divided by 4 and not 3 since there are 4 meals.
Step-by-step explanation:
1) Santhosh packed 240 oranges and 288 apples in boxes. He packed oranges and apples in separate boxes. He put equal number of fruits in each box. What is the maximum number of fruits that can be put in each box?
The maximum no of fruits that could be put in each box is 48
For determining the maximum no of fruits, we have to find out the highest common factor i.e. HCf between two numbers i.e. 240 and 288
So,
For 240 = [tex]2 \times 2 \times 2 \times 2 \times 3 \times 5[/tex]
And, for 288, it is = [tex]2 \times 2 \times 2 \times 2 \times 2 \times3 \times 3[/tex]
So, the highest common factor between two numbers is
= [tex]2\times 2\times 2\times 2\times 3[/tex]
= 48
So we can conclude that the maximum no of fruits that could be put in each box is 48
Learn more about numbers here: brainly.com/question/17429689?
Answer:
the maximum number of fruits that can be put in each box=48
Given :
Total number of oranges = 240
Total number of apples = 288
we find maximum number of fruits by finding highest common factor HCF
Step-by-step explanation:
Lets find out HCF of 240 and 288
Write the prime factors for 240 and 288
[tex]288=2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 3 \cdot 3\\240=2 \cdot 2 \cdot 2 \cdot 2 \cdot 3 \cdot 5[/tex]
Now write the common factor for both numbers
[tex]2 \cdot 2 \cdot 2 \cdot 2 \cdot 3 =48[/tex]
So, GCF is 48
We have to put 48 fruits in each box.
Learn more :
brainly.in/question/8084599
Someone PLEASE HELP!!! Nowwww
how far from 0" is the green rectangle for both
Answer:
C. 3 3/4
Step-by-step explanation:
just is
id k how to explain
a potter is making cups and saucers. each cup takes c minutes to produce, and each saucers takes s minutes. Th epotter can produce three cups and two saucers in 19 mnutes
Answer:
1) 3c+2s=19
4c+5s=30
2) c=5 s=2
3)42minutes
Step-by-step explanation:
The potter need 3c minutes to make three cups and 2s to make two saucers, then he needs 3c+2s minutes to make both of them
3c+2s=19
He needs 4c+5s minutes to produce 4 cups and 5 saucers
4c+5s=30 (half of an hour is 30 minutes)
So the equations are
3c+2s=19
4c+5s=30
2) to solve you should express c from the first equation and use it in the second equation
3c=19-2s
c=19/3-(2/3)*s
4(19/3-(2/3)*s) +5s=30
76/3-(8/3)*s+5s=30
(7/3)*S= (14/3)
s=2
3c=19-4
3c=15
c=5
3) 6c+6s= 6(c+s)= 6(5+2)=6*7=42
Find x so that the points (x,x+1), (x+2,x+3) and (x+3,2x+4) form a right-angled triangle.
Let a, b, and c be vectors each starting at the origin and terminating at the points (x, x + 1), (x + 2, x + 3), and (x + 3, 2x + 4), respectively.
Then the vectors a - b, a - c, and b - c are vectors that point in directions parallel to each of the legs formed by the triangle with these points as its vertices.
If this triangle is to contain a right angle, then exactly one of these pairs of vectors must be orthogonal. In other words, one of the following must be true:
(a - b) • (a - c) = 0
or
(a - b) • (b - c) = 0
or
(a - c) • (b - c) = 0
We have
a - b = (x, x + 1) - (x + 2, x + 3) = (-2, -2)
a - c = (x, x + 1) - (x + 3, 2x + 4) = (-3, -x - 3)
b - c = (x + 2, x + 3) - (x + 3, 2x + 4) = (-1, -x - 1)
Case 1: If (a - b) • (a - c) = 0, then
(-2, -2) • (-3, -x - 3) = (-2)×(-3) + (-2)×(-x - 3) = 2x + 12 = 0 ==> x = -6
which would make a - c = (-3, 3) and b - c = (-1, 5), and their dot product is not zero. Then the triangles vertices are at the points (-6, -5), (-4, -3), and (-3, -8).
Case 2: If (a - b) • (b - c) = 0, then
(-2, -2) • (-1, -x - 1) = (-2)×(-1) + (-2)×(-x - 1) = 2x + 4 = 0 ==> x = -2
which would make a - c = (-3, -1) and b = (-1, 1), and their dot product is also not zero. The vertices are the points (-2, -1), (0, 1), and (1, 0).
Case 3: If (a - c) • (b - c) = 0, then
(-3, -x - 3) • (-1, -x - 1) = (-3)×(-1) + (-x - 3)×(-x - 1) = x ² + 4x + 6 = 0
but the solutions to x here are non-real, so we throw out this case.
So there are two possible values of x that make a right triangle, x = -6 and x = -2.
Workbook
WB-21
38. What is the circumference of a circle that has a diameter of 12 inches? (Use
3.14 for 1.)
a. 15.14 inches
b. 37.68 inches
c. 376.8 inches
d. 9.42 inches
Answer:
37.68
Step-by-step explanation:
Formula for finding the circumference of a circle is C = 2πr
If you substitute the numbers in you should get 37.68.
11. A surveyor at point S discovers that the angle between peaks A and B is 3 times as large as the angle
between peaks B and C. The surveyor knows that ZASC is a right angle. Find mzASs and m2BSC.
The measures of the angles between the peaks are;
m∠BSC = 22.5°
m∠ASB = 67.5°
The reason for arriving at the above angles is as follows:
The known values are;
The location of the surveyor = Point S
The angle between peaks A and B = m∠ASB = 3 times as large as the angle between peaks B and C = 3 × m∠BSC
The measure of angle m∠ASC = A right angle = 90°
Required:
To find m∠ASB and m∠BSC
From the given diagram, we have;
m∠ASC = 90°
m∠ASC = m∠ASB + m∠BSC (angle addition postulate)
m∠ASB = 3 × m∠BSC
∴ m∠ASC = 3 × m∠BSC + m∠BSC = 4 × m∠BSC
m∠ASC = 4 × m∠BSC = 90°
m∠BSC = 90°/4 = 22.5°
m∠BSC = 22.5°
m∠ASB = 3 × m∠BSC
∴ m∠ASB = 3 × 22.5° = 67.5°
m∠ASB = 67.5°
Learn more about angle addition postulate here:
https://brainly.com/question/4208193
which is an example of an algebraic expression
A.4(3+8)
B.18^2
C. 3-a
D. 12•4
Answer:
C: 3-a
Step-by-step explanation:
The answer is C because an algebraic expression needs to have a variable in it. The variable is "a," so the answer has to be C.
Answer:
Option C : as in algebraic expression there must a variable and constant.
Find the distance between the points (0, 10) and (–9, 1).
[tex]\\ \sf\longmapsto \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]\\ \sf\longmapsto \sqrt{(-9-0)^2+(1-10)^2}[/tex]
[tex]\\ \sf\longmapsto \sqrt{(-9)^2+(-9)^2}[/tex]
[tex]\\ \sf\longmapsto \sqrt{81+81}[/tex]
[tex]\\ \sf\longmapsto \sqrt{162}[/tex]
[tex]\\ \sf\longmapsto 12.42[/tex]
look at the image below plzz urgant help !!!!!! NEED DONE IN TEN MINUTES
Answer:
V≈113.1
Step-by-step explanation:
V=πr2h
3=π·32·12
3≈113.09734
Suppose a statistics instructor believes that there is no significant difference between the mean class scores of statistics day students on Exam 2 and statistics night students on Exam 2. She takes random samples from each of the populations. The mean and standard deviation for 35 statistics day students were 75.86 and 16.91. The mean and standard deviation for 37 statistics night students were 75.41 and 19.73. What conclusion can be made based on the data
PLEASE ANSWER ASAP THANK YOU!!! How much money will be in a bank account after 3 years if $9 is deposited at an interest rate of 5% compounded annually? Round to the nearest dollar.....
Answer:
10 bucks
Step-by-step explanation:
Money=9*(1+0.05)^3
Money=9*(1.05)^3=10.41≈10
Make a substitution to express the integrand as a rational function and then evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.)
2 sec^2(t)/tan^2(t) + 14 tan(t) + 48 dt
Complete the square in the denominator to get
tan²(t ) + 14 tan(t ) + 48 = tan²(t ) + 14 tan(t ) + 49 - 1
… = (tan(t ) + 7)² - 1
Substitute u = tan(t ) + 7 and du = sec²(t ) dt. Then the integral becomes
[tex]\displaystyle \int \frac{2\sec^2(t)}{\tan^2(t)+14\tan(t)+48} \,\mathrm dt = 2 \int \frac{\mathrm du}{u^2-1}[/tex]
Separate the integrand into partial fractions:
[tex]\dfrac1{u^2-1} = \dfrac12 \left(\dfrac1{u-1}-\dfrac1{u+1}\right)[/tex]
Then we get
[tex]\displaystyle \int \frac{2\sec^2(t)}{\tan^2(t)+14\tan(t)+48} \,\mathrm dt = \int \left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm du \\\\ =\ln|u-1|-\ln|u+1| + C \\\\ = \ln\left|\frac{u-1}{u+1}\right|+C \\\\ = \boxed{\ln\left|\frac{\tan(t)+6}{\tan(t)+8}\right|+C}[/tex]
what is the lub and glb of the following sets, in the set of real numbe if exists E={ 0.2,0.23,0.234,0.2343,0.23434,0.23434,...}
Answer:
Hello,
Step-by-step explanation:
[tex]LUB(E)=0.2=\dfrac{1}{5} \\\\GUB(E)=0.2 34 34 34 ....=0.2+\dfrac{1}{10} *0.343434....\\\\=\dfrac{1}{5} +\dfrac{1}{10} *\dfrac{34}{99} \\\\=\dfrac{198+34}{990} \\\\=\dfrac{116}{495}[/tex]
You pick a marble from a bag containing 1 green marble, 4 red marbles, 2 yellow marbles, and 3 black marbles. You replace the first marble and then select a second ones find p(blue, then black).
If you do not replace the first marble in the previous question before you select the 2nd one, find p(red, then red)
Show your work!!
Answer:
First question:0
Second question:2/15
Step-by-step explanation:
First:
Total of marbles=10
since there is no blue the probability is 0, since black is 3. then prob= number of black/total number of marbles. =3/10
therefore 0*3/10 =0
second:
probability of red is 4/10
since the first marble wasn't returned,the total number of marbles=9
therefore probability if the second red marble is =3/9 =1/3
probability of first marble *probability of second marble
(4/10)*(1/3) =(4/30)= 2/15
Can someone help me please need the answer ASAP
Answer: 445.5 (choice C)
Work Shown:
[tex]S_n = \frac{n}{2}(a_1+a_n)\\\\S_{11} = \frac{11}{2}(8+73)\\\\S_{11} = 5.5(81)\\\\S_{11} = 445.5\\\\[/tex]
Adding the first 11 terms of this arithmetic sequence yields the sum 445.5
write two properties of Zero
Answer:
the addition properties of zero and multiplication properties of zero
zero is even, not odd not neutral.
zero is neither positive or negative.
2. The table shows the probabilities of winning or losing when the team is playing away or is playing at home.
Home Away Total
Win 0.2 0.05 0.25
Loss 0.6 0.15 0.75
Total 0.8 0.20 1.00
(a) Are the events “winning” and “playing at home” independent? Explain why or why not.
(b) Are the events “losing” and “playing away” independent? Explain why or why not.
Answer:
The sum of the lengths of any two sides of a triangle must be greater than the third side. If a triangle has one side that is 18 inches and a second side that is 3 inches less than twice the third side, what are the possible lengths for the second and third sides?
Answer: One side could be 18 and the other side will be 33.
Step-by-step explanation:
Side #1 = 18Side #2 = 2x - 3Side #3 = xOne way of setting up the inequality is: Side #2 + Side #3 > Side #1
[tex]2x-3+x>18\\3x-3>18\\3x>18+3\\3x>21\\x>7[/tex]
Another way of setting up the inequality is: Side #1 + Side #3 > Side #2
[tex]18+x>2x-3\\18+3>2x-x\\x<21[/tex]
Final way of setting up the inequality is: Side #1 + Side #2 > Side #3
[tex]18+2x-3>x\\15>x-2x\\15>-x\\x>-15[/tex]
Therefore, we have the range for our value of x, which is between 7 and 21. Any possible value between works. Negative measurements are rejected. One of the sides would equal the x-value, while the other side would equal the value of 2x-3.
