Answer:
The volume of this cone is V = 50 (~50.27)
(I'm assuming that 'his' is height?)
Answer: 50
Step-by-step explanation:
find the length of the arc . round your answers to the nearest tenth PLEASE HURRY
Answer:
10.2
Step-by-step explanation:
Length of arc=(2*pi*r)*(theta/360)
Length of arc=(2*pi*3)*(195/360)=10.2
A hypothesis test is to be performed in order to test the proportion of people in a population that have some characteristic of interest. Select all of the pieces of information that are needed in order to calculate the test statistic for the hypothesis test:
No piece of information is supplied to choose from ; However, the requirements for the test statistic of the hypothesis in question is given below.
Answer:
Kindly check explanation
Step-by-step explanation:
The hypothesis in the question above which is to be tested is a one sample proportion test ;
The test statistic formula for a one sample proportion test is given as :
Test statistic = (Phat - P) / √[P(1 - P) / n] ;
Where;
Phat = sample proportion
P = population proportion
n = sample size
Sample proportion = x / n ;
Therefore, once the parameters (Sample proportion, population proportion and sample size are given) then obtaining the test statistic is possible.
25 points, look at the picture.
Answer:
1080
Step-by-step explanation:
PEMDAS says multiply and divide from left to right
9*5*6*3÷3*4*6÷6
45*6*3÷3*4*6÷6
270*3÷3*4*6÷6
810÷3*4*6÷6
270*4*6÷6
1080*6÷6
6480÷6
1080
The whole number 23 is an example of a ____ number.
prime or composite?
The answer is prime! I hope this helps you out!
Answer:
23 is a prime number. Reason: Prime number are those numbers which are divisible by 1 and itself. Example: 5 is divisible by 1 and 5 only.
A local rectangular shaped pool used by lap swimmers has dimensions 25 yd by 30 yd and is 5.1 feet deep. Find the cost for filling the pool if the city charges $1.50 per 1000 gallons. Use the conversion 1 gallon
Answer:
the cost of filling the pool is $386.3
Step-by-step explanation:
Given;
dimension of the rectangular pool, = 25 yd by 30 yd by 5.1 ft
covert the given dimensions to feet;
1 yd = 3 ft
25 yd = 25 x 3 ft = 75 ft
30 yd = 30 x 3 ft = 90 ft
The volume of the rectangular pool in cubic feet (ft³);
Volume = 75 ft x 90 ft x 5.1 ft
Volume = 34,425 ft³
Convert the volume to gallons;
1 ft³ = 7.481 gallons
10,125 ft³ = 34,425 x 7.481 gallons
= 257,533.425 gallons
The cost per a 1000 gallons is $1.50, then cost of the 257,533.425 gallons is calculated as;
[tex]cost = \frac{\$ 1.50}{1000 \ gallons} \times 257,533.425 \ gallons = \$ 386.3[/tex]
Therefore, the cost of filling the pool is $386.3
Quan điểm quản lý của trường phái đưc trị
.・。.・゜✭・Srry but which language is this!?
Which equation is represented by the graph below?
Answer:
Hello,
Answer C
Step-by-step explanation:
Since ln(1)=0
if x=1 then y=4 ==> y=ln(x)+4
y=ln(x) is translated up for 4 units.
2. Write the equation of the line in point-slope form.
(-1,3) and (2,9)
Answer:
y - 9 = 2 (x - 2)
Step-by-step explanation:
y2 - y1 / x2 - x1 9 - 3 / 2 - (-1) 6/3 = 2
y - 9 = 2 (x - 2)
find the value of x in 81^x=1/3?
Answer:
x = -1/4
Step-by-step explanation:
[tex]81^{x}[/tex] = 1/3
[tex]3^{4}^{x}[/tex] = [tex]3^{-1}[/tex]
4x = -1
x = -1/4
Answer:
x = - [tex]\frac{1}{4}[/tex]
Step-by-step explanation:
Using the rules of exponents
[tex](a^m)^{n}[/tex] = [tex]a^{mn}[/tex] , [tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex]
Given
[tex]81^{x}[/tex] = [tex]\frac{1}{3}[/tex] [ note that 81 = [tex]3^{4}[/tex] ] , then
[tex](3^4)^{x}[/tex] = [tex]3^{-1}[/tex] , that is
[tex]3^{4x}[/tex] = [tex]3^{-1}[/tex]
Since the bases on both sides are equal, both 3, then equate exponents
4x = - 1 ( divide both sides by 4 )
x = - [tex]\frac{1}{4}[/tex]
what translation was the similarity moved through ?
Solve each equation for the indicated variable. Solve for pi.
9514 1404 393
Answer:
π = 2A/r²
Step-by-step explanation:
Multiply by the inverse of the coefficient of π.
A = π(r²/2)
π = 2A/r²
The daily production of electronic motors at a certain factory averaged 120 with a variance of 100. The fraction of days that will have production levels between 100 and 140 assuming doubt about the normality of the data is
The square in the middle has an area of 1 square unit. What is the area of the entire rectangle in square units?
Answer:
4 i believe that's the answer
relationship between the two number
b 70.908
7.908
Which one is greater
Answer:
70.908 is greater than 7.908 .
I hope your day goes nice
Answer:
70.9 0 8 is Greaterboth are different because of different placement of point.
Li wants to buy as many bags of mulch as possible with his
$305, and he would like them to be delivered to his house. The
cost is $7.50 per bag and there is a $35.75 delivery charge. The
mulch is only sold in full bags. How many bags can Li buy?
Answer:
35 full bags
Step-by-step explanation:
$305-$35.75=$269.25
$269.25 divided by $7.50=35.9 bags (round off to lowest for number of full bags)
look at the image below
find the missing side round to the nearest tenth
Answer:
[tex]cos49 = \frac{26}{x} \\ x = 39.6305[/tex]
Write an inequality for the shaded region shown in the figure.
Answer:
the equation of the circle is x^2 + y^2 < 36
NOT LESS OR EQUAL cause of the dotted lines
and the theory behind this is because the square root of 36 is +-6 so when the equation is less than +-6 the shade cannot go outside these point, if you know what i mean
hope that answers your question :)
A polynomial function has real coefficients, a leading coefficient of 1, and the zeros -6, 1, and 1. Write a polynomial function of least degree in standard form.
Answer:
[tex]{ \sf{ \underline{ {x}^{2} + 5x - 6 }}}[/tex]
Step-by-step explanation:
[tex](x + 6)(x - 1) \\ = {x}^{2} - x + 6x - 6 \\ = {x}^{2} + 5x - 6[/tex]
Question:
9 1/8 + 4 5/6=?
If a line has a slope of -2 and goes through the point (1,-3) then the equation for the line in slope-intercept form is what?
Answer:
y=-2x-1
Step-by-step explanation:
The slope is - 2. The equation is y=-2x-1
Determine if the outside temperature is a function of the time of day or if the time of day is a function of temperature and explain why or why not.
Answer:
Step-by-step explanation:
Temperature is a function of the time of day. There can be only one temperature at any particular time.
In contrast, a particular temperature can occur more than one time in a day, so time is not a function of temperature.
8.) It takes Fred 9 minutes to type and spell check 13 pages of a manuscript. Find how long it takes him to type and spell check 60 pages. Round to the nearest whole number. answer: minutes
It will take Fred 42 minutes to type and spell check 60 pages.
Let the first scenario be A.Let the second scenario be B.Let the unknown time be X.Given the following data;
Time taken A = 9 minutesNumber of pages A = 13 pagesNumber of pages B = 60 pagesTime taken B = X minutesTo find how long it takes him to type and spell check 60 pages;
We would use direct proportion to express the work described and solve for the unknown variable (time).
[tex]9 \;minutes : 13 \;pages\\\\X \;minutes : 60 \;pages[/tex]
Cross-multiplying, we have;
[tex]9[/tex] × [tex]60[/tex] [tex]= 13[/tex] × [tex]X[/tex]
[tex]540 = 13X\\\\X = \frac{540}{13}[/tex]
X = 41.54 ≈ 42 minutes
Therefore, it will take Fred 42 minutes to type and spell check 60 pages.
Find more information: https://brainly.com/question/89674
88%
19. What is the solution X in this equation? 2(3x - 7) + 4(3x + 2) = 6(5x+9) + 3
[tex]\\ \sf\longmapsto 2(3x-7)+4(3x+2)=6(5x+9)+3[/tex]
[tex]\\ \sf\longmapsto 6x-14+12x+8=30x+54+3[/tex]
[tex]\\ \sf\longmapsto 6x+12x-14+8=30x+57[/tex]
[tex]\\ \sf\longmapsto 18x+6=30x+57[/tex]
[tex]\\ \sf\longmapsto 30x-18x=6-57[/tex]
[tex]\\ \sf\longmapsto 12x=51[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{51}{12}[/tex]
Is speed the rate of change in the velocity of a moving body?
Mindy cheers at 16 regular season football games each year. She cheers for a total of 58.35 minutes each game. If her teams make the playoffs, she will cheer at each game for 59.15 minutes. How many total minutes will mindy cheer if she cheers at all regular season games and two playoff games?
Answer:
1051.9 minutes
Step-by-step explanation:
16 games at 58.35 minutes =
16* 58.35 =933.6 minutes
2 playoffs at 59.15
2 * 59.15 = 118.3 minutes
Add them together
933.6+118.3 =1051.9 minutes
Answer:
the answer is 1051.9 minutes
Step-by-step explanation:
[tex]\sf{}[/tex]
♛┈⛧┈┈•༶♛┈⛧┈┈•༶
How long will it take for a sum of 500$ attracting simple interest
can someone help me, please?
Answer:
0
2
-1
Step-by-step explanation:
from f(0) we find that
y = mx - 1
from f(-1) we find that the equation is
y = -3x - 1
1)
inverse f(x) :
x = -3y - 1
y = -(x + 1) / 3 x = -1
y = -(-1 + 1) / 3
y = 0
2)
y also equal to 0 since x = -1
3)
f^-1(2) = -(2+1) / 3
= -3/3
= -1
f(-1) = 2
help
I need to know what this is asap
Calculate the equivalent resistance Req of the network shown in Fig. 3.87 if R1 = 2R2 = 3R3 = 4R4 etc. and R11 = 3
The equivalent resistance of the network shown is: [tex]R_{eq}=16.463\Ohm[/tex]
So, first of all, we can start by determining what each of the resistances is equal to. In this case we can start by saying that [tex]R_{1}=11R_{11}[/tex] This means that:
[tex]R_{1}=11(3\Ohm)[/tex]
Therefore:
[tex]R_{1}=33\Ohm[/tex]
We can now use this value to find the value of the other resistances. The given condition for the resistances can be represented with the following formula:
[tex]R_{n}=\frac{R_{1}}{n}[/tex]
so:
[tex]R_{2}=\frac{R_{1}}{2}=\frac{33}{2}\Ohm[/tex]
[tex]R_{3}=\frac{R_{1}}{3}=\frac{33}{3}\Ohm=11 \Ohm[/tex]
[tex]R_{4}=\frac{R_{1}}{4}=\frac{33}{4}\Ohm[/tex]
[tex]R_{5}=\frac{R_{1}}{5}=\frac{33}{5}\Ohm[/tex]
[tex]R_{6}=\frac{R_{1}}{6}=\frac{33}{6}\Ohm=\frac{11}{2}\Ohm[/tex]
[tex]R_{7}=\frac{R_{1}}{7}=\frac{33}{7}\Ohm[/tex]
[tex]R_{8}=\frac{R_{1}}{8}=\frac{33}{8}\Ohm[/tex]
[tex]R_{9}=\frac{R_{1}}{9}=\frac{33}{9}\Ohm=\frac{11}{3}\Ohm[/tex]
[tex]R_{10}=\frac{R_{1}}{10}=\frac{33}{10}\Ohm[/tex]
[tex]R_{11}=3\Ohm[/tex]
So now that we know what each resistance is equal to, we can go ahead and analyze the circuit.
In this case we can see that [tex]R_{10}[/tex] and [tex]R_{11}[/tex] are parallel, so we can calculate their equivalent resistance.
[tex]R_{1011}=\frac{R_{10}R_{11}}{R_{10}+R_{11}}[/tex]
Which yields:
[tex]R_{1011}=\frac{(\frac{33}{10}\Ohm)(3\Ohm)}{\frac{33}{10}\Ohm+3\Ohm}[/tex]
[tex]R_{1011}=\frac{11}{7}\Ohm[/tex]
Now, [tex]R_{8}[/tex], [tex]R_{9}[/tex] and [tex]R_{1011}[/tex] are connected in series, so we can calculate their equivalent resistance like this:
[tex]R_{891011}=R_{8}+R_{9}+R_{1011}[/tex]
[tex]R_{891011}=\frac{33}{8}+\frac{11}{3}+\frac{11}{7}[/tex]
[tex]R_{891011}=\frac{1573}{168}\Ohm[/tex]
Now, we can see that [tex]R_{7}[/tex] and [tex]R_{891011}[/tex] are parallel, so we can calculate their equivalent resistance.
[tex]R_{7891011}=\frac{R_{7}R_{891011}}{R_{7}+R_{891011}}[/tex]
Which yields:
[tex]R_{7891011}=\frac{(\frac{33}{7}\Ohm)(\frac{1573}{168})}{\frac{33}{7}\Ohm+\frac{1573}{168}\Ohm}[/tex]
[tex]R_{7891011}=\frac{4719}{1505}\Ohm[/tex]
Now, [tex]R_{5}[/tex], [tex]R_{6}[/tex] and [tex]R_{7891011}[/tex] are connected in series, so we can calculate their equivalent resistance like this:
[tex]R_{567891011}=R_{5}+R_{6}+R_{7891011}[/tex]
[tex]R_{567891011}=\frac{33}{5}\Ohm+\frac{11}{2}\Ohm+\frac{4719}{1505}\Ohm[/tex]
[tex]R_{567891011}=15.236\Ohm[/tex]
Next, we can see that [tex]R_{4}[/tex] and [tex]R_{567891011}[/tex] are parallel, so we can calculate their equivalent resistance.
[tex]R_{4567891011}=\frac{R_{4}R_{567891011}}{R_{4}+R_{567891011}}[/tex]
Which yields:
[tex]R_{4567891011}=\frac{(\frac{33}{4}\Ohm)(15.236\Ohm)}{\frac{33}{4}\Ohm+15.236\Ohm}[/tex]
[tex]R_{4567891011}=5.352\Ohm[/tex]
Now, [tex]R_{2}[/tex], [tex]R_{3}[/tex] and [tex]R_{4567891011}[/tex] are connected in series, so we can calculate their equivalent resistance like this:
[tex]R_{234567891011}=R_{2}+R_{3}+R_{4567891011}[/tex]
[tex]R_{234567891011}=\frac{33}{2}\Ohm+11\Ohm+5.352\Ohm[/tex]
[tex]R_{234567891011}=32.852\Ohm[/tex]
Finally, we can see that [tex]R_{1}[/tex] and [tex]R_{234567891011}[/tex] are parallel, so we can calculate their equivalent resistance.
[tex]R_{eq}=\frac{R_{1}R_{234567891011}}{R_{1}+R_{234567891011}}[/tex]
Which yields:
[tex]R_{eq}=\frac{(33\Ohm)(32.852\Ohm)}{33\Ohm+32.852\Ohm}[/tex]
[tex]R_{eq}=16.463\Ohm[/tex]
See attached picture for images on how to reduce the circuit.
You can find further information in the following link.
https://brainly.com/question/21538325?referrer=searchResults