Answer:
Explanation:
The steps to calculate the Zeff is :
1) Write the electronic configuration.
Carbon: 1s2 2s2 2p2
Oxygen: 1s2 2s2 2p4
2) there are two core electrons in each atom and four in carbon and six in oxygen.
1s) (2s2p)
3) as mentioned the shielding of electrons within the same shell is negligible.
4) for electron of s or p orbital the shielding contribution by the electrons having a principal quantum number less by one would be 0.85 each. And all electrons further left would contribute an amount of 1.0 each.
5) For oxygen:
Zeff = Z - S
S = 2X0.85 = 1.7
Zeff = 8- 1.7 = 6.3
For carbon
Zeff = Z - S
S = 2X0.85 = 1.7
Zeff = 6- 1.7 = 4.3
Rubric #2
Forensic Science
1. Define Nucleus.
2. Define Cytoplasm.
3. Define Cell Membrane.
4. Define DNA.
5. Define Plant.
6. Define Chlorophyll.
7. Define Photosynthesis.
8. How do Plant cells and Animal cells differ?
9. Define Cell Wall.
10. Define Vacuole.
11. Why do cells differentiate in multicellular organisms?
12. Define Multicellular.
13. Complete the Eukaryotic cells and Cell Differentiation assessment.
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848d-89929101140d/concepts/co0fef01-33e7-4116-8819.
143e289e15ba/tabs/6e1551ab-57b8-42d4-8e5b-25549791c760/pages/de4182af-aa 60-
454f-ae5e-28df6f4eb3ac
Explanation:
1. Nucleus is a memberane bound organelle that contains cell,s chromosomes.
What is the maximum most that can be extracted from 76 g og Cr2O3.
A) 36 g
B) 52 g
C) 104 g
D) 152 g
Answer:
D) 152 g
Explanation:
a mass of 1 mol Cr2O3 = 2 × 52 + 3 × 16 = 152 g number of moles of Cr2O3.
number is equal to 6022 x 10^23
Answer:
The Avogadro's number
Explanation:
the number is 6.02214x10 to the 23 power
Explain why you get a basic solution when you dissolve NaF in water.
Answer:
The fluoride ion is capable of reacting, to a small extent, with water, accepting a proton. The fluoride ion is acting as a weak Brønsted-Lowry base. The hydroxide ion that is produced as a result of the above reaction makes the solution slightly basic.
So
we get a basic solution when you dissolve NaF in water.
Na is a alkaline earth metal
Metallic compound dissolved in water acts as base
Also there is another reason
Na F is ioniC
Fluorine is known as having highest electron affinity in world
It can accept a line pair of OH-
So it's Bronsted Lowry base .
It can also acts as Arrhenius baseHence its basic
how many moles of oxygen atoms are present in 0.4 moles of oxygen gas
Answer:
Each molecule of O2 is made up of 2 oxygen atoms. So 1 mole of O2 molecules is made up of 2 moles of oxygen atoms. Therefore 1 mole of oxygen gas contains 2 moles of oxygen atoms. And 0.4 moles of oxygen gas contains 0.8 moles of oxygen atoms.
There are 0.8 moles of oxygen atoms in 0.4 moles of oxygen gas.
Oxygen gas (O₂) consists of two oxygen atoms bonded together. Therefore, to determine the number of moles of oxygen atoms present in a given amount of oxygen gas, we can simply multiply the number of moles of oxygen gas by the number of oxygen atoms per molecule, which is 2.
Given that we have 0.4 moles of oxygen gas, we can calculate the number of moles of oxygen atoms as follows:
Number of moles of oxygen atoms = Number of moles of oxygen gas × Number of oxygen atoms per molecule
= 0.4 moles × 2
= 0.8 moles
Therefore, there are 0.8 moles of oxygen atoms present in 0.4 moles of oxygen gas.
This calculation is based on the stoichiometry of oxygen gas, which indicates that each molecule of O₂ contains two oxygen atoms. By considering the mole ratio between oxygen gas and oxygen atoms, we can determine the number of moles of oxygen atoms in a given quantity of oxygen gas.
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Hello, I am a bit stuck on this. Could someone help?
Spinocerebellar Ataxia
What problem is associated with high stability of polymers?
Explanation:
they do not break down quickly or easily and create a lot of pollution (like microplastics)
why is repetition important in science?
Answer:
the repetition principle is important in scientific research, because the observational indexes are random variables,which requires a certain amount of samples to reveal their changing regularity
The valves in the heart open and close to move blood in between heart chambers. O a) three directions O b) two directions O c) four directions d) one direction
Answer:
im not sure but i think its four directions
Hi,
The valves in the heart open and close to move blood in between heart chambers.
Answer:
d) one direction
What 2 variables are needed to calculate the percent yield?
Answer:
isn’t it reactants and products?
Explanation:
Answer: reactants and products
Explanation:
Write chemical equations for the acid-base reactions that occur when:
a. Solutions of HC₂H₃O₂ (acetic acid) and KOH are mixed.
b. Solutions of HCN (hydrocyanic acid) and Na₂CO₃ are mixed.
Acetic acid is basically known as CH_3COOH.
Chemical Equation:-
[tex]\boxed{\sf {CH_3COOH\atop Acetic\:acid}+{KOH\atop Potassium\:Hydroxide}\longrightarrow {CH_3COOK\atop Potassium\: Acetate}+{H_2O\atop Water}}[/tex]
This kinda reaction is called Neutralization Reaction.Solution:-2
[tex]\boxed{\sf {HCN\atop Hydrogen\:Cyanate}+{Na_2CO_3\atop Sodium\:Carbonate}\longrightarrow {NaCN\atop Sodium\:Cyanate}+{H_2O\atop water}+{CO_2\atop Carbon\:dioxide}}[/tex]
Hydro cyanic acid is also called HydrogenCyanate.g We've all blown up balloons. When you blow into a balloon, you are putting in more moles of gas. Let's say that on the second exhalation (blow) you blow in the exact same number of moles as you did with the first exhalation. So, you doubled the number of moles in the balloon. If the temperature and pressure remained constant, what is true about the volume of the gas in the balloon
According to ideal gas equation if the temperature and pressure remained constant, then the volume of the gas in balloon is fixed.
What is ideal gas equation?The equation of state for a fictitious perfect gas is known as the ideal gas law, sometimes known as the generic gas equation. Although it has some restrictions, it is a good approximation of the behavior of numerous gases under various circumstances. The sole interaction between molecules of an ideal gas would be an elastic collision when they collided or an elastic collision with the container walls.
The volume of a specific quantity of a gas is inversely proportional to its pressure at constant temperature. The following is a concise description of what is now known as Boyle's law: When held at a fixed temperature, the volume of a given quantity of gas is inversely proportional to the pressure at which it is measured.
Thus, according to ideal gas equation if the temperature and pressure remained constant, then the volume of the gas in balloon is fixed.
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Which of the following substances can be used to neutralize HF?
A: HF
B: SO2
C: HCI
D: NaOH
Answer:
option (D) NaOH is right answer
A neutralization reaction is "a reaction in which an acid and a base react to form water and a salt and involves H+ ions and OH- ions to produce water.
What is an acid?An acid is "any hydrogen-containing substance that is capable of donating a proton or hydrogen ion to another substance".
What is base?Base is "a substance that gets dissociated in an aqueous solution to form hydroxide ions OH-".
Hence, NaOH can be used to neutralize HF.
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Draw a relative energy diagram showing a conformational analysis of 2,2-dichloropropane along C1-C2 bond. Clearly label all staggered conformations and all eclipsed conformations with the corresponding Newman projections.
Answer:
^#))(899900000)My020
Provide two real world examples of habitats and niches within ecosystems? Explain the interdependence that exists within those ecosystems.
Answer:
An ecosystem encompasses living organisms and the nonliving elements of their environments. Hence, the components of an ecosystem include animals, plants, microorganisms, rocks, soil, minerals, atmosphere, and the surrounding water masses. An ecosystem can be huge, cutting across several nations, or it can be relatively small, such as the body of an animal, which is home to numerous microorganisms.
We can describe ecosystems under two headings – natural ecosystems and unnatural ecosystems. Unnatural ecosystems, which include agricultural and urban areas, are greatly modified and maintained by human activity. Conversely, natural ecosystems are self-sufficient, balanced ecological units, with a high proportion of native biodiversity and minimal human disruption.
The natural ecosystem is broad. It is divided into two major groups – terrestrial and aquatic ecosystems. These are further divided into many other smaller types of ecosystems as outlined in this article.
Explanation:
Hope it helps.. if yes, plz mark me as brainliest
The functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound, C5H10O2, exhibits strong, broad absorption across the 2500-3200 cm^1 region and an intense absorption at 1715 cm'^-1. Relative absorption intensity: (s)=strong, (m)-medium, (w) weak. What functional class(cs) docs the compound belong to List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly. Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm^1. The functional class(es) of thla compound is(are) alkane (List only if no other functional class applies.) alkene terminal alkyne internal alkyne arene alcohol ether amine aldehyde or ketone carboxylic acid ester nitrile
Answer:The functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound, C5H10O2, exhibits strong, broad absorption across the 2500-3200 cm^1 region and an intense absorption at 1715 cm'^-1. Relative absorption intensity: (s)=strong, (m)-medium, (w) weak. What functional class(cs) docs the compound belong to List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly. Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm^1. The functional class(es) of thla compound is(are) alkane (List only if no other functional class applies.) alkene terminal alkyne internal alkyne arene alcohol ether amine aldehyde or ketone carboxylic acid ester nitr
Nombre para la siguiente estructura de compuesto orgánico
Explanation:
Introducción:
La designación de los compuestos orgánicos puede hacerse utulizando alguno de los
siguientes sistemas:
a) Mediante nombres triviales o comunes, que expresen alguna propiedad característica
(sabor, color, acción fisiológica, etc.) o hagan referencia a la materia de la cual se extrajo el
compuesto.
b) Mediante nombres racionales que proporcionen una idea de su constitucion química y
destaquen sus analogías estructurales.
La necesidad de una nomenclatura sistemática, que expresara en forma clara, conforme
a normas precisas, el nombre y la estructura de los compuestos orgánicos, ha sido motivo de
preocupación permanente y observada a través de los numerosos congresos internacionales
que, al efecto, se han realizado en diversas oportunidades.
Las bases del actual sistema de nomenclatura fueron establecidas por una comisión que
se reunió en Ginebra en 1892. Posteriormente, fue perfeccionado y ampliado por el Comité de
Nomenclatura de la Unión Internacional de Química Pura y Aplicada, por lo que se conoce
como sistema I.U.P.A.C. (International Union of Pure and Applied Chemistry).
En las reglas aprobadas se ha tratado de introducir los menores cambios posibles a la
terminología universalmente adoptada. El sistema tiene la necesaria flexibilidad como para
adaptar la forma precisa de las palabras, de las terminaciones, etc. a las características de
distintos idiomas.
El nombre de los hidrocarburos consta de tres partes: a) la raíz, que indica el esqueleto
carbonado; b) la terminación o sufijo, que indica el grado de saturación, y c) el prefijo que
diferencia las distintas estructuras isoméricas (distintas estructuras construidas con exactamente
los mismos átomos).
Ej.: CH3-CH2-CH2-CH2-CH3 pentano (tambien llamado n-pentano)
penta: raíz que señala el número de átomos de carbono que componen la cadena principal
del compuesto.
-ano: sufijo que indica que el hidrocarburo es saturado
Identify the conjugate pairs in the following acid-base reaction
H₂CO₃(aq) + C₅H₅N(aq) HNO₃-(aq) + HC₅H₅N+(aq)
H2CO3 is an acid because it gave away a proton to become HNO3~.
HNO3~ is a conjugate Base because Acids become conjugate Bases after giving away a proton.
C5H5N is a base because it accepted the proton from H2CO3 to become HC5H5N+.
HC5H5N+ is a conjugate Acid because Bases become Conjugate Acids after accepting a proton.
How does a smoke detector utilize radiation?
A. Beta radiation creates a stead stream of electrons. When the stream is broken by smoke particles, it sets off the alarm.
B. Alpha radiation ionizes the air. When smoke interacts with the ionized particles it causes the alarm to sound.
C. Gamma radiation creates a stead stream of electrons. When the stream is broken by smoke particles, it sets off the alarm.
D. Beta radiation ionizes the air. When smoke interacts with the ionized particles it causes the alarm to sound.
what are the properety of covalent bond
Explanation:
1. boiling and melting point
2. electrical conductivity
3. Bond strength
4. bond length
A covalent bond consists of negative electrons that are shared in between atoms. Because of this bond, they possess and manifest physical abilities, including electrical pressure/conductivity and lower melting points compared to ionic compounds.
What makes it possible
for a vascular plant to
be a long distance from
a water source?
A. long leaves
B. flowers
C. long roots
D. long stems
Answer:
I think long roots
Explanation:
The conversion of CICH=CHCI to CI2C=CC12 can be carried out with:
C12 / H20
C12
C12/ hv
C12 / aq. NaOH
Answer:
I think third C12/hv is right answer
22 SEE ** AL A large number of organic compounds have been discovered and isolated from natural sources by the first quarter of the 19th century but till then, none of the organic compounds could be prepared in the laboratory. It was believed that organic compounds followed laws of formation different from inorganic compounds and that some vital force was necessary to produce the organic compounds. Synthesis of these organic compounds in the lab was impossible due to the absence of vital force, which only known to exist in the living organisms. In 1828, Friedrich Wöhler produced the compound urea, H2N-CO-NH2 in the laboratory. Why was the result of this experiment significant in the history of Organic chemistry? (5 marks) Write equations showing the synthesis of urea from ammonium cyanate. (3 marks)
This reaction achieved by Friedrich Wöhler led to the birth of synthethic organic chemistry.
Prior to the successful synthesis of urea by Friedrich Wöhler in the year 1828, chemists believed that it is purely impossible to synthesize various organic substances in the laboratory owing to the absence of an imaginary "vital force". responsible for the formation of those substances.
However, the synthesis of urea by Friedrich Wöhler opened up the idea of laboratory organic synthesis which have blossomed into the present synthetic organic chemistry.
The equation for the synthesis of urea from ammonium cyanate is shown in the image attached.
Organic compounds which occur in nature could now be synthesized and studied under laboratory conditions.
Hence, this reaction achieved by Friedrich Wöhler led to the birth of synthethic organic chemistry.
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(08.02 MC)
What is the molarity of a solution prepared by dissolving 20.0 grams of NaOH in sufficient water to make a solution with a
total volume of 2.40 liters? (5 points)
Select one:
a.0.120 M NaOH
6.0.208 M NaOH
c.0.416 M NaOH
O
d.0.833
Answer:
d. 0.208 M NaOH
Explanation:
M[NaOH] = 23+16+1= 40g/mol
2.40L = 2.4dm3
M=m/Mv
M=20.0g/40g/mol×2.4dm3
M=20.0g ÷ 96
M= 0.208 M NaOH
The statement of the molarity of a solution is "0.208 M NaOH."
What is molarity?The amount of a chemical substance in a defined volume of the solution is measured in molarity (M). The moles of a solute per litre of a solution is known as molarity. The molar concentration of a solution is also known as molarity.
In order to determine the molarity, initially calculate the number of moles of sodium hydroxide by dividing the given mass by molar mass of NaOH.
Gram to mole conversion factor,
Moles of NaOH
[tex]= (20.0\;g) * \frac{(1\;mol\;NaOH)}{(39.998\;g)} \\= 0.50\;mol[/tex]
Now, the molarity of the solution comes out to be,
[tex]Molarity = \frac{Moles\;of\;the\;solute}{Volume\;of\;the\;solution}[/tex]
So,
[tex]= \frac{0.0500 \;mol}{2.40\;L} \\= 0.208\;\frac{mol}{L} = 0.208\;M[/tex]
Hence the correct option is b.
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Which is an example of genetic engineering?
A.
humans’ ability to digest cow milk
B.
some bacteria’s resistance to antibiotics
C.
golden rice enriched with vitamin A
D.
lizards with longer legs for surviving floods
Answer:
C. Golden rice enriched with vitamin A
Calculate the percent error in the atomic weight if the mass of a Zn electrode increased by 0.3681g and 6.514x10-3 moles of Zn was produced. You may assume the molar mass of elemental zinc is 65.38 g/mol.
a. -13.5%
b. 13.52%
c. -13.52%
d. 13.5%
Answer:
13.5%
Explanation:
To answer this you need to understand that percentage error can never be negative as we use absolute value in the equation
To get molar/atomic mass = mass/moles
=0.3681g/(6.514×10^-3)moles
=56.509g/moles
percentage error = (65.38-56.509)/65.38 ×100
=13.56% (this is what I'm getting without rounding off your question wasn't specific on how many d.p to use)
A sample of gas is held at constant volume. If the number of moles of this sample of gas is doubled and the pressure of this sample of gas is halved, what happens to the absolute temperature of the gas?
Select one
a. The absolute temperature is doubled.
b. The absolute temperature is halved.
c. The absolute temperature is quadrupled.
d. The absolute temperature is quartered.
e. The absolute temperature stays the same.
Answer:
number of moles of gas increases the volume also increases.
Q1: A stock solution containing Mn+2 ions was prepared by dissolving 1.584 g pure manganese metal in nitric acid and diluting to a final volume of 1.000 L. The following solutions were then prepared by dilution: For solution A, 50.00 mL of stock solution was diluted to 1000.0 mL. For solution B, 10.00 mL of solution A was diluted to 250.0 mL. For solution C, 10.00 mL of solution B was diluted to 500.0 mL. Calculate the concentrations of the stock solution and solutions A, B, and C.
The concentration of a solution is the amount of solute in a solution.
We have from the question that he mass of manganese = 1.584 g
Hence;
Amount of [tex]Mn^2+[/tex] = 1.584 g/55g/mol = 0.0288 moles
Recall that;
Number of moles = concentration * volume
Let the concentration of the solution be C
0.0288 moles = C * 1 L
C = 0.0288 moles/ 1 L
C= 0.0288 mol/L
Hence concentration of stock solution = 0.0288 mol/L
For solution A
From the dilution formula;
C1V1 = C2V2
where;
C1 = initial concentration
C2 = final concentration
V1 = initial volume
V2= final volume
C1 = 0.0288 mol/L
V1 = 50.00 mL
C2 = ?
V2 = 1000.0 mL
C2 = 0.0288 mol/L * 50.00 mL/1000.0 mL
C2 = 0.00144 mol/L
Hence, concentration of solution A is 0.00144 mol/L
For solution B
C1V1 = C2V2
C1 = 0.00144 mol/L
V1 = 10.00 mL
C2 = ?
V2 = 250.0 mL
C2 = 0.00144 mol/L * 10.00 mL/250.0 mL
C2 = 0.0000576 mol/L
Hence, concentration of solution B is 0.0000576 mol/L
For solution C
C1 = 0.0000576 mol/L
V1 = 10.00 mL
C2 = ?
V2 = 500.0 mL
C2 = 0.0000576 mol/L * 10.00 mL/500.0 mL
C2= 0.000001152 mol/L
Hence, concentration of solution C is 0.000001152 mol/L
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công thức phân tử của glucozo
C₆H₁₂O₆ is the molecular formula of gulcozo.