Answer:
y=-(x+2)(x+4)
y=-(x^2+4x+2x+8)
y=-(x^2+6x+8)
y=-(x^2+4x+2x+8)
Y=-x(x+4)+2(x+4)
y=-(x+2)(X+4)
So vertex is (2,4)
can yall answer it in the box like the numbers
Answer:
Hi!
Step-by-step explanation:
1234567890987654211234567890......
Step-by-step explanation:
12345678890098764321
Naomi invested $3,425 in an account that
pays 3% simple interest. what was the total
balance of the account after 15 years?
Answer:
$4,966.25
Step-by-step explanation:
3 x 15 = 45
After 15 years, Naomi would have earned a total of 45% interest rate.
3,425 x 1.45 = 4,966.25
Don't use .45 as the multiplier
3,425 x .45 = 1,541.25 <- incorrect
Calculate the minimum number of subjects needed for a research study regarding the proportion of respondents who reported a history of diabetes using the following criteria:
95% confidence, within 5 percentage points, and a previous estimate is not known.
Answer:
The minimum number of subjects needed is 385.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
The margin of error is:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
95% confidence, within 5 percentage points, and a previous estimate is not known.
The sample size is n for which M = 0.05. We don't know the true proportion, so we use [tex]\pi = 0.5[/tex]
Then
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.05 = 1.96\sqrt{\frac{0.5*0.5}{n}}[/tex]
[tex]0.05\sqrt{n} = 1.96*0.5[/tex]
[tex]\sqrt{n} = \frac{1.96*0.5}{0.05}[/tex]
[tex](\sqrt{n})^2 = (\frac{1.96*0.5}{0.05})^2[/tex]
[tex]n = 384.16[/tex]
Rounding up:
The minimum number of subjects needed is 385.
Describe who is responsible for the cost and efficiency variances for direct materials, direct labor, and manufacturing overhead
Answer:
The materials price variance is usually the responsibility of the purchasing manager. The materials quantity and labor efficiency variances are usually the responsibility of production managers and supervisors.
A trolley travels in one direction at an average of 20 miles per hour, then turns around and travels on the same track in the opposite direction at 20 miles per hour of the total time waveling on the trolleys 3.5 hours, how far did the trolley travel in one direction?
mi
Enter your answer in the answer box and then click Check Answer
Clear All
Help Me Solve This
an Example
Get More Help
9514 1404 393
Answer:
35 miles
Step-by-step explanation:
The relevant relation is ...
distance = speed × time
The total distance the trolley traveled is ...
d = (20 mi/h) × (3.5 h) = 70 mi
The distance is the same in both directions, so the trolley traveled half this distance in one direction.
The trolley traveled 35 miles in one direction.
A biologist was interested in determining whether sunflower seedlings treated with and an extract from Vinca minor roots resulted in a lower average height of sunflower seedlings that the standard height of 15.7 cm. The biologist treated a random sample of 33 seedlings with the extract and subsequently measured the height of those seedlings. At the 0.01 significance level, is there evidence that the true average height of the seedlings treated with an extract from Vinca minor roots is less than 15.7 cm?
Height
15.5
15.8
15.7
15.1
15.1
15.5
15.2
15.7
15.8
15.4
16.2
15.5
16.2
15.5
15.4
16.3
14.9
15.3
15.1
16.1
15.3
15.4
15.1
15.3
14.6
15.1
15.0
15.3
15.8
15.5
14.8
15.2
14.8
a. State the null and alternative hypotheses.
b. Report the value of the test statistic. Round answer to 2 decimal places. (Either calculate or use software such as minitab)
c. Using the p-value, do you reject the null hypothesis or fail to reject the null hypothesis? Explain your decision.
d. Based on your decision in part (c), write a conclusion within the context of the problem.
Answer:
Kindly check explanation
Step-by-step explanation:
H0 : μ = 15.7
H1 : μ < 15.7
This is a one sample t test :
Test statistic = (xbar - μ) ÷ (s/√(n))
n = sample size = 33
Using calculator :
The sample mean, xbar = 15.41
The sample standard deviation, s = 0.419
Test statistic = (15.41 - 15.70) ÷ (0.419/√(33))
Test statistic = - 3.976
Using the Pvalue calculator :
Degree of freedom, df = n - 1 ; 33 - 1 = 32
Pvalue(-3.976, 32) = 0.000187
Decison region :
Reject H0 if Pvalue < α
Since Pvalue < α ; we reject H0
There is significant evidence to conclude that the true average height of the seedlings treated with an extract from Vinca minor roots is less than 15.7 cm.
Ten samples were taken from a plating bath used in an electronics manufacturing process, and the bath pH was determined. The sample pH value are 7.91, 7.85, 6.82, 8.01, 7.46, 6.95, 7.05, 7.35, 7.25, 7.42. Manufacturing engineering believes that pH has a median value of 7.0. Do the sample data indicate that this statement is correct
Answer:
There is no sufficient evidence to support the claim.
Step-by-step explanation:
Given the data:
7.91, 7.85, 6.82, 8.01, 7.46, 6.95, 7.05, 7.35, 7.25, 7.42
Sample size, n = 10
The sample mean, xbar = ΣX/ n = 74.07 / 10 = 7.407
The sample standard deviation, s = 0.41158 ( from calculator)
The hypothesis :
H0 : μ = 7
H0 : μ ≠ 7
The test statistic :
(xbar - μ) ÷ (s/√(n))
(7.047 - 7) ÷ (0.41158/√(10))
0.047 / 0.1301530
Test statistic = 0.361
Testing the hypothesis at α = 0.05
The Pvalue ;
df = n - 1 ; 10 - 1 = 9
Two tailed test
Pvalue(0.361, 9) = 0.7263
Since the Pvalue > α ; we fail to reject the Null and conclude that there isn't sufficient evidence to support the claim.
I'm not sure how to do this
Answer:
1 and 5 sevenths of a bag
Step-by-step explanation:
2/7 males half to it takes 4/7 to make a full one multiply 4 by 3 and you get 12/7 so that makes 1 and 5/7
please help me with this
please mark this answer as brainlist
You plan to charge $1 for each time a student plays, and the payout for a win is $5. According to your calculations, the probability of a win is .05. What is your expected value for this game? The expected value
Answer:
- $0.75Step-by-step explanation:
For each game played the chance of winning is 0.05 and losing is 0.95.
If the student wins, they get $5 -$1 = $4, but they lose $1.
Expected value is:
4*0.05 - 1*0.95 = -0.75It means you will make $0.75 per average game.
Answer:
21.8
Step-by-step explanation:
Step 1
This is a problem on finding the mean of continuous grouped data. We first find the midpoint of each interval. For example, the first interval or class is 0 - 10. The mid-point of this class will be (0 + 10)/2 = 5.
fullscreen
Step 2
We now calculate the product of mid-point and frequency for each class. Here, the number of athletes in each class is the frequency of that class. For example, for the first class 0 – 10, its frequency is 3.
fullscreen
Step 3
We can now use the formula to calculate mean. Note that t...
Solve the equation below:
5x – 11 = 19
x = 4
x = 6
x = 4.4
x = 1.6
pls answer i need help today
Answer:
x=6
Step-by-step explanation:
5x - 11 = 19
5x = 30
x = 6
20characters
5x = 19+11 5x = 30 x = 30/5 x = 6
A hose is left running for 240 minutes to 2 significant figures. The amount of water coming out of the hose each minute is 2.1 litres to 2 significant figures. Calculate the lower and upper bounds of the total amount of water that comes out of the hose.
Answer:
Hello,
Step-by-step explanation:
Let say t the time the hose is left running
235 ≤ t < 245 (in min)
Let say d the amount of water coming out of the hose each minute
2.05 ≤ d < 2.15 (why d : débit in french)
235*2.05 ≤ t*d < 245*2.15
481.75 ≤ t*d < 526.75 (litres)
Answer:
Lower bound: [tex]495\; \rm L[/tex] (inclusive.)
Upper bound: [tex]505\; \rm L[/tex] (exclusive.)
Step-by-step explanation:
The amount of water from the hose is the product of time and the rate at which water comes out.
When multiplying two numbers, the product would have as many significant figures as the less accurate factor.
In this example, both factors are accurate to two significant figures. Hence, the product would also be accurate to two significant figures. That is:
[tex]240 \times 2.1 = 5.0 \times 10^{2}\; \rm L[/tex] ([tex]500\; \rm L[/tex] with only two significant figures.)
Let [tex]x[/tex] denote the amount of water in liters. For [tex]x\![/tex] to round to [tex]5.0 \times 10^{2}\; \rm L[/tex] only two significant figures are kept, [tex]495 \le x < 505[/tex]. That gives a bound on the quantity of water from the hose.
Walnut High Schools Enrollment is exactly five times as large as the enrollment at walmut junior high the total enrollment for the two schools is 852 what is the enrollment at each school
Answer:
142
Step-by-step explanation:
If the enrollment is five times as big, then that is six different things. So, take 852 and divide it by 6 to get 142. Or in other words:
852÷6=142
142x6=856
I hope this helps. Cheers^^
= 10 + 3
=13
Example 6
If f(x) = 2x + 1, g(x) = 3x - 2 and fg(x) = 5, find the value of x,
Answer:
f(x) = 2x + 1, g(x) = 3x - 2 and fg(x) = 5
Step-by-step explanation:
A silo is built in the shape of a cylinder with a cone for a roof. If the height of the
cylinder is 5 m, the radius is 2.8 m and the slant height of the cone is 6,6 m,
determine the amount of material needed to create the rounded sides and conical
roof, Round to the nearest tenth of a cubic m.
9514 1404 393
Answer:
146.0 m²
Step-by-step explanation:
The lateral areas of the cylinder and cone are given by the formulas ...
A = πrs . . . . cone area; radius r, slant height s
A = 2πrh . . . . cylinder area; radius r, height h
__
The total area lateral area of the silo is ...
A = π(2.8 m)(6.6 m) +2π(2.8 m)(5 m) = π(2.8 m)(6.6 m +2(5 m)) = 46.48π m²
A ≈ 146.0 m² . . . area of sides and roof of silo
_____
Additional comment
The answer is requested in cubic meters. Area has units of square meters. There is nothing in this problem statement that seems to be requesting a volume, which is what would have units of cubic meters.
Find the sequence of this term
41,40,48,38 35,--....,...
Answer:
hxvkgyjdh ht yshysfhyys is not working properly configured form and the kids will not work with a little over again. thank you
Remy drinks 2/1/4 cups of water every 1/4/5 hours.
How many cups of water does he drink in 1 hour?
Answer:
1¼ cups
Step-by-step explanation:
2¼ ÷ 1/4/5 =
9/4 ÷ 9/5 =
9/4 x 5/9 =
5/4 = 1¼
The polygons in each pair are similar. Find the missing side length.
Let missing side be x
If both polygons are similar
[tex]\\ \sf\longmapsto \dfrac{3}{4}=\dfrac{18}{x}[/tex]
[tex]\\ \sf\longmapsto 3x=4(18)[/tex]
[tex]\\ \sf\longmapsto 3x=72[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{72}{3}[/tex]
[tex]\\ \sf\longmapsto x=24[/tex]
Solve for x. Round to the nearest tenth, if necessary.
S
540
R
2.3
X
O
Please help
Answer:
[tex]\boxed {\boxed {\sf x \approx 1.9}}[/tex]
Step-by-step explanation:
We are asked to find x, a missing side in a triangle.
This is a right triangle because there is a small square in the corner representing a 90 degree or right angle. Therefore, we can use right triangle trigonometry. The three main functions are:
sinθ= opposite/hypotenuse cosθ= adjacent/hypotenuse tanθ= opposite/adjacentExamine the triangle. We will use angle S, measuring 54 degrees, for theta. Side QR, measuring x, is opposite angle S. Side QS, measuring 2.3, is the hypotenuse because it is opposite the right angle. Since we have the opposite and hypotenuse, we will use sine.
[tex]sin \theta = \frac {opposite}{hypotenuse}[/tex]
θ= 54opposite= x hypotenuse = 2.3[tex]sin (54)= \frac{ x}{2.3}[/tex]
We are solving for x, so we must isolate the variable. It is being divided by 2.3 The inverse operation of division is multiplication, so we multiply both sides by 2.3
[tex]2.3* sin (54)= \frac{x}{2.3}*2.3[/tex]
[tex]2.3* sin (54)=x[/tex]
[tex]2.3*0.8090169944=x[/tex]
[tex]1.860739087 =x[/tex]
Round to the nearest tenth. The 6 in the hundredth place to the right tells us to round the 8 up to a 9.
[tex]1.9 \approx x[/tex]
x is approximately 1.9
Write an equation that represents the line.
Use exact numbers.
Answer: y=2/3X- 4/3
Step-by-step explanation:
Slope = (4-2)/(4-1)=2/3
Y-2=2/3(x-1)
Y-2=2/3x-2/3
Y=2/3X-2/3+2
Y=2/3X-4/3
find the sum of the given infinite geometric series. NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW
Answer:
320/3
Step-by-step explanation:
First find the common ratio
20/80 = 1/4
The sum of an infinite geometric series
sum = a1/ (1-r) where a1 is the first term and r is the common ratio
=80/ ( 1-1/4)
= 80/(3/4)
= 80 *4/3
= 320/3
A 230 pound man, a 140 pound woman, a 750 pound crate of equipment, an 80 pound bag of concrete. What percent of the total weight was concrete?
What percent of the total weight was human?
Is the function f(x) = 1/8 ^x an exponent function? If so , identify the base , if not why not ?

Yes , the base is 1/e
yes, the base is e
No, there is no base that is a positive real number not equal to 1 raised to a variable exponent.
No, the base is the reciprocal of e, a number smaller than 1.
9514 1404 393
Answer:
(a) Yes , the base is 1/e
Step-by-step explanation:
The variable is in the exponent, so this is an exponential function.
The base is the number that has the exponent. The base is (1/e).
Answer:
Step-by-step explanation:
bvxbvxbvxbvcvbbb cv
Find the length of the arc. Round your answer to the nearest tenth
Answer:
12.6 mi
Step-by-step explanation:
Arc length = 2πr (Θ/360)
2π(12) (60/360)
= 12.6 mi
Answered by g a u t h m a t h
The number N(t) of supermarkets throughout the country that are using a computerized checkout system is described by the initial-value problem
dN/dt = N(1 − 0.0008N), N(0) = 1.
Required:
Predict how many supermarkets are expected to adopt the new procedure over a long period of time?
Answer:
1250 supermarkets
Step-by-step explanation:
Given
[tex]\frac{dN}{dt} = N(1 - 0.0008N)[/tex]
[tex]N(0) = 1[/tex]
Required
Number of supermarkets over a long period of time
To do this, we simply set
[tex]\frac{dN}{dt} = 0[/tex]
So, we have:
[tex]N(1 - 0.0008N) = 0[/tex]
Split
[tex]N = 0\ or\ 1 - 0.0008N = 0[/tex]
Solve: [tex]1 - 0.0008N = 0[/tex]
Collect like terms
[tex]0.0008N = 1[/tex]
Make N the subject
[tex]N = \frac{1}{0.0008}[/tex]
[tex]N = 1250[/tex]
So:
[tex]\lim_{t \to \infty} N(t) = 1250[/tex]
Express the prime number 19 as the difference of two squares? 19 =
Answer:
The two squares are 81 and 100, and their difference is 19
Step-by-step explanation:
Hey there!
Let's take out the square of 1st ten natural numbers to find out the exact answer.
1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
6² = 36
7² = 49
8² = 64
9² = 81
10² = 100
Now; You can take any of these numbers and subtract from their squares.
So, let's check 6² and 5²
36-25 = 11 which is not equal to 19
Again check for 10²-9²
100 - 81 = 19 (True value)
Therefore, 19 can be expressed as the difference of square of 10 and 9.
Hope it helps!
What is a placement form from the school mean
Answer:
Placements are basically extended internships or work experience assignments
Step-by-step explanation:
A sample of 4 different calculators is randomly selected from a group containing 14 that are defective and 34 that have no defects. What is the probability that at least one of the 4 calculators in the sample is defective
Answer:
The answer is "0.7616".
Step-by-step explanation:
Using formula:
[tex]\text{P( at least one de-fective) = 1 - P( all calculators work )}[/tex]
[tex]= 1-(\frac{34}{48}\times \frac{33}{47}\times \frac{32}{46}\times \frac{31}{45})\\\\= 1-(\frac{34}{1}\times \frac{11}{47}\times \frac{1}{23}\times \frac{31}{45})\\\\=1-(\frac{11594}{48647})\\\\=\frac{48647-11594}{48647}\\\\=\frac{37051}{48647}\approx 0.7616[/tex]
Teacher gives 2 questions to a class of 50 student. 30 students correctly answer ther first question, 25 students correctly answer the second question, 7 wongly answer both question, there are _ students correctly answer both question
Answer:
43
Step-by-step explanation:
only 7 out of the 50 got both wrong
Answer:
Step-by-step explanation:
Write the options so they are homogeneous in content. • Use answers given in previous open-ended exams to provide realistic distractors. 2. Use a Question ...
Determine the critical values for the confidence interval for the population standard deviation from the given values. Round your answers to three decimal places.
n = 12 and c = 0.9.
Answer:
The answer is "[tex]\chi^2_{L} = 4.575 \ and\ \chi^2_{U}= 19.675[/tex]"
Step-by-step explanation:
[tex]n=12\\\\\ c= 0.9[/tex]
Calculating the level of significance [tex](\alpha) = 1 -c[/tex]
[tex]=1-0.9\\\\=0.1[/tex]
Calculating the degrees of freedom:
[tex]df=n-1=12-1=11[/tex]
Calculating the critical value:
Applying the Chi-Square table, the critical values for the two-tailed test with a degree of freedom (11) for the significance level of [tex]\alpha = 0.1[/tex]:
[tex]\chi^2_{L} = 4.575 \\\\\chi^2_{U}= 19.675[/tex]
