Two friends are carrying a 200-kg crate up a flight of stairs. The crate is 1.25 m long and 0.500 m high, and its center of gravity is at its center. The stairs make a 45.0° angle with respect to the floor. The crate also is carried at a 45.0° angle, so that its bottom side is parallel to the slope of the stairs (Fig. 2). If the force each person applies is vertical, what is the magnitude of each of these forces?

Answers

Answer 1

Let consider the whole system to be at equilibrium where the net force is zero. The forces [tex]F_A[/tex] and [tex]F_B[/tex] are acting in the upward direction while the weight (w) of the crate is acting in the downward direction.

The force at equilibrium in the y-direction is computed as:

[tex]\sum F_y = ma_y[/tex]

[tex]F_A +F_B= mg[/tex]

[tex]\mathbf{F_A = mg -F_B}[/tex]  ---- (1)

Recall that the weight w = mg

where;

mass (m) = 200 g g(constant gravity) = 9.8 m/s²

w = 200 × 9.8

w = 1960 N

The torque about the bottom end is also zero. i.e.

[tex]\sum \tau=0[/tex]

[tex]F_B L_Z - wL_w = 0[/tex] --- (2)

[tex]F_B L_Z= wL_w[/tex]

[tex]F_B = \omega (\dfrac{L_w}{L_z})[/tex]

[tex]F_B =1960\times (\dfrac{0.375\times cos 45^0}{1.25\times cos 45^0})[/tex]

[tex]F_B =1960\times (0.3)[/tex]

[tex]\mathsf{F_B = 588 \ N}[/tex]

Replacing the value for the force of B into equation (1); we have:

[tex]F_A = mg - F_B[/tex]

[tex]F_A = 1960 - 588[/tex]

[tex]\mathsf{F_A = 1372 N}[/tex]

Thus, we can conclude that the magnitude of these forces i.e force B and force A are 588 N and 1372 N respectively.

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Two Friends Are Carrying A 200-kg Crate Up A Flight Of Stairs. The Crate Is 1.25 M Long And 0.500 M High,

Related Questions

If ∲E.ds=0, inside a surface, that means :-
(a) there is no net charge present inside the surface
(b) uniform electric field inside the surface
(c) discontinues field lines inside the surface
(d) charge present inside the surface

Answers

Answer:

(a) there is no net charge present inside the surface

Explanation:

when ∲E.ds=0,

net charge = 0

Therefore no net charge.

someone can help me?
FORMACION DE IMÁGENES EN UN ESPEJO
1. Un objeto es situado frente a un espejo cóncavo, como se muestra en la figura
Con ayuda de los rayos notables, dibuja en donde se forma la imagen y responde
a) ¿Qué tipo de imagen es?:
b) ¿Qué dirección tiene?:
c) ¿Cuál es su tamaño?:
TRANSLATION:
FORMATION OF IMAGES IN A MIRROR
1. An object is placed in front of a concave mirror, as shown in the figure
With the help of the noticeable rays, draw where the image is formed and respond
a) What kind of image is it?:
b) What is your address?:
c) What is its size?:

Answers

When the object is placed at a further distance from the center of the mirror's curvature (twice the focal length), we will get a thumbnailposition of the image from the mirror; Between focus and center of curvature of the mirror (double focal length) picture description; real, inverted, mini

* This picture is to draw the rays, just replace the candle with an apple .

Do you want me to write it in Spanish to help you?? ^_^

I hope I helped you^_^

A ferrari has a mass of 1485kg.what is it's weight on Earth ​

Answers

F = m · g

m = 1485 kg

g = 10 N/kg

F = 1485 kg · 10 N/kg = 14 850 N = 14,85 kN

Answer: The weight on Earth is 14,85 kN.

A pulley system is made of 3 pulley write its velocity ratio

Answers

Almost 3 times fast than normal pulley system

mark me

3 times fasten than normal pulley

Robin fired a bullet of mass 100 gm from a gun of mass 5 kg. The bullet leaves the gun with a speed of 400 m/s. After penetrating 4 cm of a plank of 10 cm, the bullet loses one third of its initial velocity.
a. Calculate the backward velocity of the gun?
b. Can the bullet penetrate the plank of the wood completely? Explain mathematically.

please help

Answers

(a) The recoil or backward velocity of the gun is 8 m/s.

(b) The bullet cannot penetrate the plank of the wood completely.

The given parameters include;

mass of the bullet, m₁ = 100 g = 0.1 kgmass of the gun, m₂ = 5 kginitial velocity of the bullet, u₁ = 400 m/sthickness of the plank, x = 10 cm

(a) The backward or recoil velocity of the gun is calculated by applying the principle of conservation of linear momentum.

let the backward or recoil  velocity of the gun = u₂

m₁u₁  + m₂u₂ = 0

m₂u₂ = -m₁u₁

[tex]u_2 = -\frac{m_1u_1}{m_2} \\\\u_2 = - \frac{0.1 \times 400}{5} \\\\u_2 = -8 \ m/s[/tex]

Thus, the recoil or backward velocity of the gun is 8 m/s.

(b) determine if the bullet can penetrate the plank of the wood completely

the bullet traveled 4 cm and lost ¹/₃ of u₁the remaining distance to completely penetrate the plank = 6 cmthe final velocity of the bullet at 4 cm, v = 400 - ¹/₃ x 400 m/s  = 266.67 m/s

the acceleration of the bullet is calculated as;

v² = u₁² + 2as

2as = v² - u²

[tex]a = \frac{v^2 -u_1^2}{2s} \\\\a = \frac{(266.67)^2 -(400)^2}{2\times 0.04} = -1.111 \times 10^6 \ m/s^2[/tex]

Finally, determine the distance traveled by the bullet when it comes to a complete stop, that is the final velocity = 0

[tex]v_f^2 = v^2 + 2ad\\\\2ad = v_f^2 - v^2\\\\d = \frac{v_f^2 - v^2}{2a} \\\\d = \frac{(0) - (266.67)^2}{2(-1.111\times 10^6)} \\\\d = 0.032 \ m[/tex]

d = 3.2 cm

The total distance traveled by the bullet inside the plank = 4 cm + 3.2 cm = 7.2 cm

Therefore, the bullet cannot penetrate the plank completely.

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How can you show that an enclosed liquid exerts pressure in all directions equally?

Answers

Answer:

Now make holes in all the directions. Now fill with water. The water comes out of the bottle in all the direction. This shows that liquids exert pressure in all direction

What is meant by the term wave front?

Answers

Explanation:

Wave front, imaginary surface representing corresponding points of a wave that vibrate in unison. ... Wave fronts for longitudinal and transverse waves may be surfaces of any configuration depending on the source, the medium, and the obstructions encountered.

A ship going from sea water to river water has to displace more water to (a) change the buoyant force (b) decrease the buoyant force in the same buoyant force (d) none of these​

Answers

Answer:

Change, or increase, the buoyant force.

Explanation:

As the salt water of the sea is denser than the river's fresh water, the boat will rise when entering the sea from the river and sink (to increase the buoyant force) when entering the river from the sea.

Convert 400 mm to m using the method of dimensional analysis

Answers

Answer:

To convert 400 mm to m you can apply the formula [m] = [mm] / 1000; use 400 for mm. Thus, the conversion 400 mm m is the result of dividing 400 by 1000. 0.4

PLEASE MARK AS BRAINLIEST ANSWER

1. A bicycle initially moving with a velocity
5.0 m s-1 accelerates for 5 s at a rate of 2 m s? Wh
will be its final velocity ?

Answers

Answer:

[tex]\boxed {\boxed {\sf 15 \ m/s \ or \ 15 \ m*s^{-1}}}[/tex]

Explanation:

We are asked to find the final velocity. We are given the acceleration, time, and initial velocity, so we can use the following kinematics formula.

[tex]v_f= v_i+ at[/tex]

In this formula, [tex]v_f[/tex] is the final velocity, [tex]v_i[/tex] is the initial velocity, [tex]a[/tex] is the acceleration, and [tex]t[/tex] is the time.

The bicycle has an initial velocity of 5.0 m *s⁻¹ or m/s, acceleration of 2 m/s², and a time of 5 seconds.

[tex]\bullet \ v_i = 5.0 \ m/s \\\bullet \ a= 2\ m/s^2\\\bullet \ t= 5 \ s[/tex]

Substitute the values into the formula.

[tex]v_f=5.0 \ m/s + ( 2\ m/s^2 * 5 \ s)[/tex]

Solve inside the parentheses.

[tex]\frac {2 \ m}{s^2}* 5 \ s = \frac{ 2 \ m}{s} * 5 = \frac{ 10 \ m}{s} = 10 \ m/s[/tex]

[tex]v_f= 5.0 \ m/s + (10 \ m/s)[/tex]

Add.

[tex]v_f= 15 \ m/s[/tex]

The units can also be written as:

[tex]v_f= 15 \ m*s^{-1}[/tex]

The bicycle's final velocity is 15 meters per second.

Define the term ‘matter’ in physics.

Answers

Answer:

Matter is any substance that has mass and takes up space by having volume

How do longshore currents shape the land?

Answers

Longshore drift has a very powerful influence on the shape and composition of the coastline. It changes the slopes of beaches and creates long, narrow shoals of land called spits, that extend out from shore. Longshore drift may also create or destroy entire “barrier islands” along a shoreline.

Answer:

Longshore drift has a very powerful influence on the shape and composition of the coastline. It changes the slopes of beaches and creates long, narrow shoals of land called spits, that extend out from shore. Longshore drift may also create or destroy entire “barrier islands” along a shoreline.

How can you distinguish wave motion and particle motion?​

Answers

Answer:

The particle is defined as the small quantity of matter under the consideration. ... The wave is defined as the propagating dynamic distrubance. The energy of the wave is calculated based on the wavelength and velocity

I HOPE THIS WILL HELP YOU IF NOT THEN SORRY :)

Explanation:

In Physics, we distinguish between wave motion and particle motion. Wave motion refers to the movement of a wave-like pattern from one location on the medium to another. ... When you observe the motion of these points, you are observing particle motion - the motion of particles of the rope.

Question 4: Scientists and engineers often plan investigations to see how changing one variable affects the outcome. A variable is any trait, condition or feature of something being tested. Imagine a team is testing the speed of a toy car. In trial 1, they test the car and measure how long it takes it to travel 2 meters. In trial 2, they want to investigate how changing a variable affects the car's speed. Which of the following plans is BEST for trial 2?

Answers

A variable, as its name implies, is something that can change, ideally, as the scientists and engineers want to.

Particularly we care for the independent variables, which are the ones we can control and affect the dependent variables, which are the outcomes we study.

For a quick example, think of an experiment where you heat something on an oven. The temperature of the oven can be set by the scientist, so the temperature is an independent variable because they can control it.

Now let's see the given experiment.

The team is testing the speed of the toy car.

remember that:

distance/time = speed.

We know that in the first trial, they test how long takes the car to travel 2 meters.

Now, what we can change for the second trial, knowing that the speed is the output that we are studying?

The answer is trivial, the only thing we can change in the given setup is the distance that the car travels, so in the next trial we should change the variable "distance travelled by the car" and see if it affects the output "speed of the car".

If you want to learn more about variables, you can read:

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A ball is launched from the ground with the horizontal speed of 30 m/s and vertical speed of 30 m/s what angle was the ball launch at?

Answers

Answer:

45 degrees

Explanation:

angle of launch=arctan(vertical velocity/ horizontal velocity)

angle = arctan(30/30) = 45 degrees

Evaluate the multi-store model (5 marks)

THIS IS A PSYCHOLOGY QUESTION

Answers

Answer:

OK well

Explanation:

where's the question bring it first

Answer:

ExplanationjakkJXJAKGKXAHLKHQHL:

A bike travels at 3.0 m/s, and then accelerates to a speed of
8.5 m/s in a time of 2.5 seconds. The average acceleration of
the bike is
m/s2

Answers

The average acceleration of the bike is 2.2 m/s²

What is average acceleration?

Acceleration, rate at which velocity changes with time, in terms of both speed and direction.

A point or an object moving in a straight line is accelerated if it speeds up or slows down.

According to the question,

Given, initial velocity, u=3.0m/s and final velocity v=8.5 m/s

Time = 2.5 seconds

If a be the acceleration.

a = [tex]\frac{v-u}{t}[/tex]

a = [tex]\frac{8.5 - 3.0}{2.5s}[/tex]

⟹ a=2.2 m/s²

So, The average acceleration of the bike is 2.2 m/s²

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#SPJ2

-8. A vessel is filled with a 20cm of water. When an irregular body of mass 800gm is immersed the volume of water is increased to 60cm3. What is the density of irregular shaped body? ​

Answers

Answer:

13.33 g/cm3

Explanation:

density = mass/volume

mass of irregular body = 800 grams

new volume = 60 cube cm

= density = 800/60  = 13.333 g/cm3

5. Which of the following is NOT a course goal?
For students to understand fitness principles
For students to establish a habit of physical activity
For students to do nothing
For students to enhance their level of physical fitness

Answers

Answer:

for students to do nothing

Explanation:

because doing nothing is not a course goal

I need help with the question asap.​

Answers

Answer:

whats the question lol

Explanation:

Answer:d

Explanation:

I need help. Please explain

Answers

Answer:

// EDU HACK REDDIT EDITON //

if (running == null) {

var running = null; console.log("Program Loading...");

var iframe = document.getElementById("stageFrame");

for (i = 0; i < 1; i++) {

 setInterval(function() {

  if (running == null) { running = true; console.log('Program Loaded! Enjoy!') }

  if (iframe.contentWindow.document.getElementsByClassName('FrameRight') != null) { iframe.contentWindow.document.getElementsByClassName('FrameRight')[0].onclick(); }

  if (iframe.contentWindow.document.getElementById("invis-o-div") != null) { iframe.contentWindow.document.getElementById("invis-o-div").remove(); }

 },1000);

}

} else {

console.log("Program already running!")

}

Explanation:

Why does a ship float on water when it weighs about 100tones and why a stone of less than a kg sinks

Answers

Answer with Explanation:

Let me answer this in a simple way, since the density of stone is greater than that of water, the stone sinks as the weight of the stone is greater than the weight of water displaced by it. But the ship is designed in such a way that the relative density of the ship always becomes less than that of water. Therefore, the weight of the water displaced becomes equal to the total weight of the ship and thus it floats.

There are many other ways to explain this but this should give you the general idea.

If star A is 20 light years away from earth and star B is 40 light years away from earth,which star appears brighter and by what factor?

Answers

Answer:

Because Star A and Star B have identical luminosities, the difference in their apparent brightness is due solely to distance. Star B is twice as far from Earth as Star A.

Explanation:

Una onda se propaga en un medio P, de tal forma que recorre una distancia 8D en un tiempo 4T. La misma onda cuando se propaga por un medio Q recorre una distancia 4D en el mismo tiempo anterior, es decir, en 4T. Respecto a esta onda es correcto afirmar que *

Answers

Sabemos todo material tiene asociado un coeficiente de difracción n.

De tal forma que la velocidad de una onda electromagnetica que viaja a travez de dicho material, será:

v = c/n

donde c es la velocidad de la luz.

Con la información dada, podremos concluir que el coeficiente de difracción del medio Q es dos veces el del medio P.

Ahora veamos como llegamos a esto:

Sabemos que en el medio P, la onda recorre una distancia 8*D en un tiempo 4*T

entonces la velocidad de la onda en el medio P es:

[tex]V_p = \frac{8*D}{4*T} = 2*\frac{D}{T}[/tex]

Mientras que en el medio Q, recorre una distancia 4*D en un tiempo 4*T, por lo que la velocidad en el medio Q será:

[tex]V_Q = \frac{4*D}{4*T} = \frac{D}{T}[/tex]

Podemos ver que:

[tex]V_P = 2*V_Q[/tex]

Reescribiendo las velocidades como el cociente entre la velocidad de la luz y el correspondiente coeficiente de difracción obtenemos:

[tex]\frac{c}{n_P} = 2*\frac{c}{n_Q} \\\\n_Q = 2*n_P[/tex]

Es decir, podemos concluir que el coeficiente de difracción del medio Q es dos veces el del medio P.

Si quieres aprender más sobre el tema, puedes leer:

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briefly explain what EMF of a cell cell is​

Answers

Answer:

The emf of a cell is the sum of the electric potential differences (PDs) produced by a separation of charges (electrons or ions) that can occur at each phase boundary (or interface) in the cell. The magnitude of each PD depends on the chemical nature of the two contacting phases.

Explanation:

pls mark brainliest

5. True or False: A beginner should start with long workout sessions and work down to shorter ones.
True
False

Answers

Answer:

false...............

Answer:

False A beginners should start from shorter ones to long work sessions

Explanation:

Hope it helps

Mark me as Brainliest plz!!

:DD

ITSMISSBADGURLX

DOES STONE DISPLACE MORE WATER THAN ITS WEIGHT

Answers

Of course it does!!!

Brainstorm and write at least 3 potential challenges or important points to consider when conducting the described
data collection.


Plz help me I need to turn this in tomorrow and I’m working on on it at 10:35 pm

Answers

Although you did not mention the "described data collection," we can help you answer in the following terms.

The three potential challenges or important points to consider when conducting data collection are:

1.- To correctly establish the specific information needed to get as a result of the research.

2.- The kind of methodology appropriate to get that expected data.

3.- The process needed to analyze and interpret that data.

- As well, it is of the utmost importance that the researcher considers the type of data compared to the budget needed to get it. Here, the budget should consider the cost of the collection process.

- Of course, the result of the process has to result in data that is valid and accurate, because that is the nature of a good research project.

Here we have to stress the relevance of the establishment of a good hypothesis to start the collection process, no matter the data collection methods used to get the data such as interviews, focus groups, observations, and so on.

We can conclude that collection data is a rigorous process that should be strictly followed to really obtain the kind of data needed to support the foundation of any research.

Learn more about this topic here:

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the gravitational force between two masses at distance of 2.5×10^6 metre is 250 Newton . what should be distance between them to reduce the gravitational force by half?​

Answers

Answer:

distance between should be 1.25 × 10^6 m

Explanation:

Force is proportional to separation distance.

[tex]250 \: newtons = 2.5 \times {10}^{6} \: metres \\ ( \frac{1}{2} \times 250) \: newtons = d \\ \\ d = \frac{125 \times 2.5 \times {10}^{6} }{250} \\ d = 1.25 \times {10}^{6} \: metres[/tex]

Answer:

distance between should be 1.25×10^6.

Explanation:

force Is proportional to separation .

mrk above answer branilest .

A force of 100 N stretches a spring by 5cm. Calculate the work done.

Answers

Answer:

Work done is 5 J

Explanation:

Workdone = Force × distance

[tex]{ \sf{W = 100 \times (5 \times {10}^{ - 2}) }} \\ { \sf{W = 5 \: joules}}[/tex]

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