There is 10% salt solution and a 30% salt solution. How much of each is needed to make 10L mixture that is 25% salt solution?

Answers

Answer 1

Answer:

2.5L of 10% salt solution and 7.5L of the 30% salt solution

Step-by-step explanation:

let the amount of L in the 10% solution be 'x'

let the amount of L in the 30% solution be '10-x'

* because they add up to a total of 10L

10%(x) + 30%(10-x) = 25%(10)

0.1x + 3 - 0.3x = 2.5

-0.2x = -0.5

x = 2.5

x =2.5

10-x = 7.5

2.5 of 10% solution and 7.5% of 30% solution


Related Questions

What is the surface area of the cube, in square inches?

Answers

Answer:

The surface area of the cube is 648.96 sq in.

Step-by-step explanation:

This problem is made a lot easier by the fact that it's a cube.

So we first calculate the area of one of the faces. The length of the side of the side is 10.4 inches, and 10.4 * 10.4 = 100.16.

There are six faces, so we multiply the area of 1 face by 6. 100.16 * 6 = 648.96.

Therefore, the surface area of the cube is 648.96 sq inches.

Hope This Helps!

3x°
30°
x =
degrees dhdjdjdjdjfj

Answers

Answer:

x=10

Step-by-step explanation:

since the angles seem similar they're most likely to be the same but since its 3x and you have to find the value of x then we will do 3 x ?=30, which is 10. if you want to check there is one way, since the angle on a straight line is 180 you can do 180 - 30 =150 which will be the unknown value next to the given angle. Since the unknown angle is on the line with the 150 degree angle we can do 180 - 50 to get the unknown angle (3x) which is 30. So in conclusion x will be 10

Answer: x = 10

Step-by-step explanation:

The angles are voa which means vertically opposite angles which means they are conguerent and also equal

ATQ

⇒3x = 30

⇒x = 30/3

⇒x = 10

Therefore x = 10 degrees

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A landscaping company placed an order for 40 new trees. The red oak trees cost $25 a piece and the sugar maples trees cost $18. If the total order was for $790, how many of each type of tree did they order?

Answers

Answer:

its 30 sugar maple trees and 10 red oak trees

Step-by-step explanation:

Number of red oak trees = 10

And, Number of sugar maples trees = 30

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

A landscaping company placed an order for 40 new trees.

And, The red oak trees cost $25 a piece and the sugar maples trees cost $18. the total order was for $790.

Let number of red oak trees = x

And, Number of sugar maples trees = y

Hence, We can formulate;

⇒ x + y = 40

⇒ 25x + 18y = 790

By solving we get;

y = 30

x = 10

Thus, Number of red oak trees = 10

And, Number of sugar maples trees = 30

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Warren has money to go see a movie after he pays $8 for the MOVIE he will have $14 left right and solve an equation to show how much money Warren has before paying for the movie

Answers

Answer:

$(8+14)

Step-by-step explanation:

Amount of money Warren has at first=$8+$14=$22

Evaluate the expression for x=-5,y=-7, and z=9

Answers

Answer:

Is 11

Step-by-step explanation:

x+(-y)+z —> -5 +(+7)+9 = -5+7+9 = 11

Find the area and the perimeter of a triangle (shown below)

PLZZZ

Answers

Answer:

A = 120, P = 55

Step-by-step explanation:

Triangle

Area = (bh)/2

A = (20x12)/2

A =240/2

A = 120

Perimeter = a + b + c

to find c, use a^2 +b^2 = c^2

20^2 + 12^2 = c^2

400 + 144 = c^2

544 = c^2

c = about 23

20 + 12 + 23 = 55

Lisa is on the west shore of Mighty River, which is 1 mile wide and has two parallel shorelines running exactly north-to-south. She wishes to get to a point on the opposite shore that is 1 mile south of where she is now as quickly as possible. (So this point is sqrt (2) miles due southeast from her starting position.) Assuming that Lisa can walk twice as fast as she can swim, and that she wants to swim across the river first before walking any necessary distance along the opposite shoreline, at what course (in degrees) should she start swimming?


(The angle is measured from north, so 90 degrees is due east, meaning she swims directly across the river, and 135 degrees is due southeast, meaning she swims directly to her destination point.)

Answers

Lisa should start swimming at an angle of [tex]120^{\circ}[/tex] to reach her destination as quickly as possible.

Given:

The river is 1 mile wideThe end point is 1 mile south of the starting pointLisa's speed of walking is twice that of her speed of swimmingLisa wants to swim across the river first before walking the rest of the distance along the opposite shoreline

To find: The course (in degrees) at which she should start swimming so that she can reach the end point as quickly as possible

To solve this problem, we need to know the following:

Pythagoras theorem states that in a right angled triangle, the square of the length of hypotenuse is the sum of the squares of lengths of perpendicular and baseCosine of an angle is the ratio of base and hypotenuse in the right angled triangleA single variable function is minimized by a value for which, the first derivative of the function is zero and the second derivative of the function is positive

Let us assume that Lisa starts swimming at a course such that she needs to swim for 'x' miles to reach the opposite shore, as shown in the figure.

Labelling the points in the figure, we can say that,

AB = 1 mile (given)

BD = 1 mile (given)

AC = x miles (by our assumption)

It is clear that ABC forms a right angled triangle where,

Perpendicular: BC

Base: AB

Hypotenuse: AC

Using Pythagoras Theorem for triangle ABC, we have,

[tex](Hypotenuse)^{2} =(Perpendicular)^{2} +(Base)^{2}[/tex], which implies,

[tex](AC)^{2} =(BC)^{2} +(AB)^{2}[/tex]

Put AC = x, AB = 1 in the above equation to get,

[tex]x^{2} =(BC)^{2} +1^{2}[/tex]

[tex]x^{2} =(BC)^{2} +1[/tex]

[tex](BC)^{2}=x^{2} -1[/tex]

[tex]BC=\sqrt{x^{2} -1}[/tex]

From the figure, we can say that,

[tex]CD=BD-BC[/tex]

Put [tex]BC=\sqrt{x^{2} -1}[/tex] and [tex]BD=1[/tex] in the above equation to get,

[tex]CD=1-\sqrt{x^{2} -1}[/tex]

According to our assumption, Lisa swims the distance of AC and walks the distance of CD, that is, she swims a distance of [tex]x[/tex] miles and walks a distance of [tex]1-\sqrt{x^{2} -1}[/tex] miles.

Now, let us assume that Lisa's speed of swimming is [tex]k[/tex] miles/hour. It is given that Lisa's speed of walking is twice that of her speed of swimming. Then, accordingly, Lisa's speed of walking must be [tex]2k[/tex] miles/hour. We note that these speeds are constants for Lisa.

We know that,

[tex]Speed=\frac{Distance}{Time}[/tex]

Then,

[tex]Time=\frac{Distance}{Speed}[/tex]

This implies that,

Time spent by Lisa on swimming = [tex]\frac{x}{k}[/tex]

Similarly, time spent by Lisa on walking = [tex]\frac{1-\sqrt{x^{2} -1} }{2k}[/tex]

Then, total time taken by Lisa to travel the whole distance from the starting point to the end point is,

[tex]\frac{1-\sqrt{x^{2} -1} }{2k} +\frac{x}{k}[/tex]

[tex]\frac{1}{2k}( 1-\sqrt{x^{2} -1} +2x )[/tex]

Since Lisa wishes to get to the end point as quickly as possible, we must minimize the total time taken by her to travel the entire distance.

Total time taken: [tex]T=\frac{1}{2k}( 1-\sqrt{x^{2} -1} +2x )[/tex]

Differentiating with respect to 'x', we have,

[tex]T'=\frac{1}{2k}( -\frac{x}{\sqrt{x^{2} -1}} +2 )[/tex]

Differentiating with respect to 'x' again, we have,

[tex]T''=\frac{1}{2k(\sqrt{x^{2} -1})^{3}}[/tex]

Equating the first derivative to 0, we have,

[tex]\frac{1}{2k}( -\frac{x}{\sqrt{x^{2} -1}} +2 )=0[/tex]

[tex]-\frac{x}{\sqrt{x^{2} -1}} +2 =0[/tex]

[tex]\frac{x}{\sqrt{x^{2} -1}} =2[/tex]

[tex]2\sqrt{x^{2} -1}= x[/tex]

Squaring both sides,

[tex]4(x^{2} -1)= x^{2}[/tex]

[tex]4x^{2} -4= x^{2}[/tex]

[tex]3x^{2} =4[/tex]

[tex]x^{2} =\frac{4}{3}[/tex]

[tex]x=\frac{2}{\sqrt{3}}[/tex]

Note that we assumed the positive square root for 'x' because 'x' denotes a distance which cannot be negative.

Put [tex]x=\frac{2}{\sqrt{3}}[/tex] in the expression for second derivative to get,

[tex]T''=\frac{1}{2k(\sqrt{(\frac{2}{\sqrt{3}} )^{2} -1})^{3}}[/tex]

[tex]T''=\frac{1}{2k(\sqrt{\frac{4}{3} -1})^{3}}[/tex]

[tex]T''=\frac{1}{2k(\sqrt{\frac{1}{3}})^{3}}>0[/tex]

The last expression is positive because 'k' denotes a speed which is always positive.

This implies that the obtained value [tex]x=\frac{2}{\sqrt{3}}[/tex] minimizes the quantity of total time taken.

Now, from the figure, we can say that,

[tex]cos(\angle BAC)=\frac{AB}{AC}[/tex]

Put AC = x, AB = 1 in the above equation to get,

[tex]cos(\angle BAC)=\frac{1}{x}[/tex]

Put the obtained minimizing value, [tex]x=\frac{2}{\sqrt{3}}[/tex] in the above equation to get,

[tex]cos(\angle BAC)=\frac{1}{\frac{2}{\sqrt{3}} }[/tex]

[tex]cos(\angle BAC)=\frac{\sqrt{3}}{2 }[/tex]

[tex]cos(\angle BAC)=cos(30^{\circ})[/tex]

Then,

[tex]\angle BAC=30^{\circ}[/tex]

Since the angle is measured from the north, the required angle is, [tex]90^{\circ}+30^{\circ}=120^{\circ}[/tex]

Thus, Lisa should start swimming at an angle of [tex]120^{\circ}[/tex] to reach her destination as quickly as possible.

Learn more about finding optimum course here:

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A candy store owner wants to mix some candy costing $1.25 a pound
with some candy costing $1.45 a pound to make 50 pounds of candy
costing $1.30 a pound. How much of the $1.25 a pound candy should
she use?

Answers

The candy store owner should use 37.5 pounds of the candy costing $1.25 a pound.

Given:

Candy costing $1.25 a pound is to be mixed with candy costing $1.45 a poundThe resulting mixture should be 50 pounds of candyThe resulting mixture should cost $1.30 a pound

To find: The amount of candy costing $1.25 a pound that should be mixed

Let us assume that the resulting mixture should be made by mixing 'x' pounds of candy costing $1.25 a pound.

Since the total weight of the resulting mixture should be 50 pounds, 'x' pounds of candy costing $1.25 a pound should be mixed with '[tex]50-x[/tex]' pounds of candy costing $1.45 a pound.

Then, the resulting mixture contains 'x' pounds of candy costing $1.25 a pound and '[tex]50-x[/tex]' pounds of candy costing $1.45 a pound.

Accordingly, the total cost of the resulting mixture is [tex]1.25x+1.45(50-x)[/tex]

However, the resulting mixture should be 50 pounds and should cost $1.30 a pound. Accordingly, the total cost of the resulting mixture is [tex]1.30 \times 50[/tex]

Equating the total cost of the resulting mixture obtained in two ways, we get,

[tex]1.25x+1.45(50-x)=1.30 \times 50[/tex]

[tex]1.25x+72.5-1.45x=65[/tex]

[tex]0.2x=7.5[/tex]

[tex]x=\frac{7.5}{0.2}[/tex]

[tex]x=37.5[/tex]

This implies that the resulting mixture should be made by mixing 37.5 pounds of candy costing $1.25 a pound.

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When the candy costs [tex]\bold{\$1.25}[/tex] a pound, the candy store owner must use [tex]\bold{37.5}[/tex]pounds. [tex]\bold{\$1.25}[/tex] per-pound candy is to be blended with [tex]\bold{\$1.45}[/tex] per-pound candy.There must be [tex]\bold{50\ pounds}[/tex] of candy in the mixture So, the [tex]\bold{\$1.30}[/tex] per-pound ought to be the cost of a final mixture.This is the amount of [tex]\bold{\$1.25}[/tex] candy per pound which should be blended when 'x' pounds of candy cost [tex]\bold{\$1.25}[/tex]  a pound, therefore the resultant combination must be constructed by joining 'x' pounds of candy together.The x pounds of candy costing [tex]\bold{\$1.25}[/tex] per pound must be combined with "[tex]\bold{50-x}[/tex]" pounds of candy costing [tex]\bold{\$1.45}[/tex] per pound because the total weight of its final mixture must be [tex]\bold{50\ pounds}[/tex].Later, 'x' pounds of candy costing [tex]\bold{\$1.25}[/tex] per-pound is mixed with '[tex]\bold{50-x}[/tex]' pounds of candy costing [tex]\bold{\$1.45}[/tex] per pound to achieve the desired mixture. As a result, the overall total cost of the final mixture is:[tex]\to \bold{1.25x+1.45(50-x)}[/tex]A 50-pound batch of a mixture will cost [tex]\bold{\$1.30}[/tex] per pound, and As an outcome, your total cost of the resulting mixture is [tex]\bold{1.30 \times 50}[/tex].It might calculate the overall cost of the resulting mixture by multiplying it by two.

                      [tex]\to \bold{ 1.25x+1.45(50-x)= 1.30 \times 50}\\\\ \to \bold{ 1.25x+72.5-1.45x= 65}\\\\ \to \bold{ -0.2x= -7.5}\\\\ \to \bold{ x=\frac{7.5}{0.2}}\\\\ \to \bold{ x=37.5}\\\\[/tex]

It implies that [tex]\bold{37.5\ pounds}[/tex] of candy at [tex]\bold{\$1.25}[/tex] a pound must be used to make the final concoction.

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Two trains leave the station at the same, one heading west and the other east. The westbound train travels at 55 miles per hour. The eastbound train travels at 75 miles per hour. How long will it take for the two trains to be 156 miles apart?

Answers

The time that taken for the two trains is 1.2 hours.

The computation of the time taken for the two trains is shown below:

Given that

The westbound train travels 55 miles per hour.

And, the eastbound train travels 75 miles per hour.

So, the total speed is

= 55 miles per hour + 75 miles per hour

= 130 miles per hour

The distance is 156 miles

So, the time taken is

[tex]= \frac{distance}{speed}\\\\= \frac{156\ miles}{130\ miles\ per\ hour}\\\\[/tex]

= 1.2 hours

Therefore we can conclude that the time that taken for the two trains is 1.2 hours.

Learn more about the speed here: brainly.com/question/21791162

Answer:

1.2 hours

Step-by-step explanation:

Given data:

Speed of the westbound train = [tex]55 miles/hr[/tex]

Speed of the eastbound train = [tex]75 miles/hr[/tex]

Since the trains are moving in the opposite direction their relative speed becomes,

[tex]55 miles/hr +75 miles/hr=130 miles/hr[/tex].

Since, time = distance / speed

Now the time taken for the two trains to be 156 miles apart

[tex]time = \frac{156 miles}{130 miles/hr} \\=1.2 hours[/tex]

Hence, the time taken for the two trains to be 156 miles apart = [tex]1.2 hours[/tex]

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Help me pls pls help me

Answers

Answer:

F. 1/2

Step-by-step explanation:

If the ratio of team assistants to players are 1/6 and there are 36 players that means that there are 6 team assistants. If we do the ratio of coaches to assistant that would be 3/6 or F. 1/2

Solve for x.
5x – 3 = 2x +12

Answers

Answer:

X = 5

HOPE IT IS HELPFULLY.

Solve for b.
-32 + 10b = -22

Answers

Answer: b = 1

Step-by-step explanation:

= -32 + 10b = -22

-32 + 10 = -22

b = 1

Check: -32 + 10(1) = -22

= -22

Answer:

b=1

Step-by-step explanation:

Hello,

We would like to solve for b in the equation -32+10b=-22.

When we want to solve for a variable, we want to isolate it on one side (have it on one side by itself. No other numbers.)  

So to start, add 32 to both sides to remove it from the left side (-32+32=0).

-32+10b=-22

+32         +32

______________

10b=10

Now, there isn't anything with 10b, but we want the value of b by itself (1b), as 10b is 10 times the value of what b is.

So divide both sides by 10

b=1

Hope this helps!

Finance A bicycle shop hires road bikes for £25 per day and tandems for £40 per day. One day a family pays £155.
a Which type of bicycles did they hire?
b How many people are in the family?

Answers

Answer:

3 road bikes and 2 tandems

7 people

Step-by-step explanation:

25b + 40t = 155

b=3   and t = 2

Check

25*3  + 40*2 = 155

75+80 = 155

Assuming 1 person per road bike and 2 people per tandem

3*1 + 2*2 = 3+4 = 7

#3 1/3x = 15 Find value of X

Answers

Answer:

x = 45

Step-by-step explanation:

1/3x = 15          (Given)

3(1/3x) = 15(3)  (Multiply 3 on both sides)

x = 45              (Simplify)

Answer:

45

Step-by-step explanation:

1/3x = 15

Multiplying 3 on both sides,

3(1/3x) = 15(3)

x = 15 x 3

x = 45

a cylinder with radius 7 and height 4 is in table,then find its volume?

Answers

Answer:

V = ≈615.75

Step-by-step explanation:

hopefully that helped

Write the equation of the directrix of the parabola shown below.

y^2+16y+4x+4=0

Answers

Answer:

Hello,

F=(14,-8)

directrice: x=16

Step-by-step explanation:

Making reduce form:

[tex]y^2+16y+4x+4=0\\y^2+2*8y+64-64+4x+4=0\\\\(y+8)^2-60+4x=0\\\\x=-\dfrac{(x+8)^2}{4} +15\\[/tex]

Since i prefere working with y=...: exchanging x and y

[tex]y=-\dfrac{(x+8)^2}{4} +15\\\\Comparing\ to\ y=\dfrac{(x-a)^2}{2(b-k)} +\dfrac{b+k}{2} \\\\a=-8 :\ S=(-8,15)\\\\\\b-k=-2\ and\ b+k=30 \ \longrightarrow\ b=14\ and\ k=16\\\\Exchanging\ x\ and\ y:\\\\Focus=(14,-8)\\\\x=16[/tex]

Who has hegarty maths as there school home work?

If you do please let me know below :):):):):):):)

Answers

Answer:

1200$

Step-by-step explanation:

All right, you usually pay 160 dollars but with the extra 25% off sale, you pay 120(160 ÷ 4 = 40, 160 - 40 = 120). BUT you have the extra VAT charge you will pay 150 dollars every day. You stay for 8 nights so 150 × 8 = 1200

Hello! can anyone help me with this question

Answers

Answer:

3

Step-by-step explanation:

m = y2 - y1 / X2 - X1

-1 is your X1 . -4 is your y1

2 is your X2 . 5 is your y2

just replace what's in the equation

m= 5 - (-4) / 2 - (-1)

m= 9 / 3

m = 3

hi there

the explanation is in the picture

Simplify the radical expression

Answers

Answer:

The above equals

(32x^2*y^5)1/2

Therefore

32^1/2*x*y^5/2

Is this right answer??????………

Answers

Yes ?!???!?!?!?!?!??!?

Answer:

6 is correct....

actually this problem is quite si,p;e to see that it is correct

notice that the length of the triangle is 4 and the height is 3

thus a rectangle 4*3 area is twelve ...

if you make a copy of the triangle and flip it you will see it makes

a 4x3 rectangle ... the original and copy = 12 thus 1/2 of the 12 is the area of the original triangle

Step-by-step explanation:

Farmer McDonald raises ducks and cows. His animals have a total of 20 heads and
64 legs. How many ducks and how many cows does Mr. McDonald have?

Answers

Answer:

8 ducks, 12 cows

Step-by-step explanation:

Let the ducks be x in number and cows be y in number

ATQ, x+y=20 and 2x+4y=64, solving we get y=12 and x=8.

If farmer McDonald raises ducks and cows. His animals have a total of 20 heads and 64 legs. Mr. McDonald has 8 ducks and 12 cows.

What is the equation?

An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.

It is given that, Farmer McDonald raises ducks and cows. His animals have a total of 20 heads and 64 legs.

Suppose the number of head and legs be x and y respectively.

If His animals have a total of 20 heads and 64 legs,

x+y=20

2x+4y=64,

Solving the above equations we get y=12 and x=8.

Thus, if a farmer McDonald raises ducks and cows. His animals have a total of 20 heads and 64 legs. Mr. McDonald has 8 ducks and 12 cows.

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Herbert has sold 92, 28, 83 and 75 suits in the last four months, respectively. How many suits will he need to sell this month to maintain an average of at least 71 sales per month? ​

Answers

Answer: 77 suits

Step-by-step explanation:

Let sales of this month = x

Sales for last 4 months = 92, 28, 83, 75

Average = Sum of Observation ÷ No of Observation

Now, we can form an equation

(92+28 +83+75+x) ÷ 5 =71

(92+28 +83+75+x) = 71 × 5

278 + x = 355

x = 355 - 278

x = 77

4 month



Find the average of last 4 month
Find mean
Sum of Numbers divided by the count of numbers

92+ 28+ 28 +75 divided 4
278 divided by 4
69.5

If 4month = 69.5
x. =. 71

Cross multiply

69.5x =71 *4
69.5x.= 284
Divide both side by x
x= 284 / 69.5
x= 4.08 to whole number
x = 4 months

I need help ASAP!!!Please explain your answer

Answers

Answer:

Step-by-step explanation:

There are 2 possibilities. Either you need to know the angles connect to the common side (that would give you ASA) or you need to know GF = UT. The latter would give you SAS

In an interview for a secretary position at the dealer, a typist claims a tying speed of 45 words per minute. On the basis of 70 trials, she demonstrated an average speed of 43 words per minute with a standard deviation of 15 words per minute. Test at 5% significance level on the typist’s claim.

Answers

According to the typist claim, we build an hypothesis test, find the test statistic and the p-value relative to this test statistic, reaching a conclusion that:

The p-value of the test is 0.1333 > 0.05, which means that there is not enough evidence to reject the typist's claim.

-------------------------------------------------------------

In an interview for a secretary position at the dealer, a typist claims a tying speed of 45 words per minute.

At the null hypothesis, we test if the mean is of at least 45, that is:

[tex]H_0: \mu \geq 45[/tex]

At the alternative hypothesis, we test if the mean is of less than 45, that is:

[tex]H_1: \mu < 45[/tex]

-------------------------------------------------------------

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

-------------------------------------------------------------

45 is tested at the null hypothesis:

This means that [tex]\mu = 45[/tex]

On the basis of 70 trials, she demonstrated an average speed of 43 words per minute with a standard deviation of 15 words per minute.

This means that [tex]n = 70, X = 43, s = 15[/tex]

Value of the test statistic:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{43 - 45}{\frac{15}{\sqrt{70}}}[/tex]

[tex]t = -1.12[/tex]

-------------------------------------------------------------

P-value of the test and decision:

The p-value of the test is found using a left-tailed test(test if the mean is less than a value), with 70 - 1 = 69 degrees of freedom and t = -1.12.

Using a t-distribution calculator, the p-value is of 0.1333.

The p-value of the test is 0.1333 > 0.05, which means that there is not enough evidence to reject the typist's claim.

A similar problem can be found at https://brainly.com/question/24241851

m/HCB = 60°, m/DCB = 9x-1, and m/DCH = 2x+ 16. Find x​

Answers

Answer:

[tex]x=11[/tex]

Step-by-step explanation:

Note that ∠DCB is the sum of ∠HCB and ∠DCH. Hence:

[tex]m\angle DCB = m\angle HCB + m\angle DCH[/tex]

Substitute in the appropriate values/expressions:

[tex](9x-1) = (60) + (2x+16)[/tex]

Solve for x. Combine like terms:

[tex]9x - 1 = 2x + 76[/tex]

Subtract 2x from both sides:

[tex]7x - 1 = 76[/tex]

Add one to both sides:

[tex]7x = 77[/tex]

And divide. Hence:

[tex]x=11[/tex]

Answer:

x=11

Step-by-step explanation:

<DCB = <DCH + < HCB

9x-1 = 2x+16 + 60

Combine like terms

9x-1 = 2x+76

Subtract 2x from each side

9x-1-2x= 2x+76-2x

7x-1 = 76

Add 1 to each side

7x-1 +1 = 76+1

7x = 77

Divide by 7

7x/7 = 77/7

x=11

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!

Answers

The answer would be D.) 904.78 cm cubes because the formula for a cylinder is V=πr2h meaning you have to do the radius which is 6 squared which comes out to 36 times pi to get 113.04 which you multiply by the height of 8 to get Answer D.) 904.78cm cubed

4(x — 8)+10 = -10
What is the solution to this equation?

Answers

Answer:

x = 3

Step-by-step explanation:

We are given the equation 4(x - 8) + 10 = -10 and are asked to find the solution, solution meaning to get x alone.

To do so, first distribute the 4 on the outside of the parenthesis to both values on the inside of the parenthesis :

4(x - 8)

(4 * x - 4 * 8)

4x - 32

4x - 32 + 10 = -10

Now combine like terms :

4x - 22 = -10

Now it's time to get x alone, first get rid of -22 by adding 22 to both sides :

4x = 12

Now get x alone by dividing both sides by 4 :

x = 3

What is the answer for this question

Answers

Answer:

option d. is the correct answer

1/6 of a loop around the circle would be a rotation of how many degrees (q)?

A=6
B=60
C=30
D=36

Answers

Answer:

60

Step-by-step explanation:

A circle is 360 degrees

1/6 of 360

1/6 * 360 = 60

(y+3) solve by using the distributive property ​

Answers

Answer:

y-3

Step-by-step explanation:

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