Solar System - Scaling. When you look at Neptune in a telescope, you are actually looking into the past as the light has to travel from Neptune to your eyes. If the speed of light is ~300,000 km/s, how far back into the past are you looking (or put another way, how long does it take light to travel from Neptune to your eyes on Earth)

Answers

Answer 1

Answer:

Distance from sun to Neptune = 4.495E9 km

Time for light to travel = 4.495E9 / 3E5 sec = 14,980 sec

That is from sun to Neptune time fof light = 250 min

Time for light to travel from sun to earth is about 8 min

So the time from Neptune would be 242 to 258 min depending on position of Neptune - Note that Neptune is about 30X as far from the sun as earth and

250 min / 8 min is roughly 30

Answer 2

The uniform motion of kinematics allows us to find the time it takes for light to arrive from Neptune to Earth, which varies between:

          t₁ = 1.45 10⁴ s and t₂₂= 1.55 10⁴ s

depending on the relative distance of the two planets

given parameters

The speed of light c = 300,000 km / s = 3 10⁸ m / s The distance from Neptune to Sum

to find

The time when light arrives from Neptune to Earth

They  velocit of an electromagnetic wave is constant, so we can use the uniform motion relationships

             v = d / t

             t = d / v

where v is the speed of light, d the distance and y time, in this case the speed of the wave is the speed of light (v = c)

We look in the tables for the distances and the rotation periods around the sun

                           distance ( m)         period (s)

Sun Neptunium     4.50 10¹²             5.2 10⁹

Sun - Earth             1.5    10¹¹              3.2 10⁷

With the data of the period it is observed that the rotation of Neptune is much greater than that of Eart rotation around the sun, for which we will assume that Neptunium is fixed in space and the Earth may be in its aphelion or perihelion, maximum approach o away distance from the sun, consequently we calculate the time for the two cases:

Maximum approach

positions relative distance from the dos Plantetas is

         Δd = [tex]x_{Neptuno - Sum} - x_{Earth - Sum}[/tex]d  

     

         Δd = 4.50 10¹²  - 1.5 10¹¹

         Δd = 43.5 10¹¹ m

the time it takes for Neptune's light to reach Earth is

        Δt = [tex]\frac{ 43.5 \ 10^{11} }{3 \ 10^8}[/tex]  

        Δt = 14.5 10³ s

        Δt = 1.45 10⁴ s

       

We reduce to hours

        Δt = 1.45 10⁴ s (1 h / 3600 s) = 4.03 h

Maximum away

         Δd = [tex]x_{Neptune - Sum} + x_{Neptune-Sum}[/tex]  

         Δd = 4.50 10¹² + 1.5 10¹¹

         Δd = 46.5 10¹¹

The time is

         Δt = [tex]\frac{46.5 \ 10^{11}}{ 3 \ 10^8}[/tex]  

         Δt = 15.5 10³

         Δt = 1.55 10⁴ s

We reduce to hours

         Δt = 1.55 10⁴ s (1 h / 3600 s) = 4.31 h

In conclusion, the time it takes for light to arrive from Neptune to Earth varies between:

          t₁ = 1.45 10⁴ s and t₂ = 1.55 10⁴ s

depending on the relative distance of the two plants

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Related Questions

On her camping trip, Penelope was in charge of collecting firewood. The firewood she found had a mass of 120 g and a volume of 480 cm3. What is the density of the firewood? Explain the steps you took to solve this problem.

Answers

Answer:

D = .25g/cm³

Explanation:

D = m/V

D = 120g/480cm³

D = .25g/cm³

what is the value of x if x-36=5?​

Answers

Answer:

Therefore, the value of x is 41

Explanation:

x=5+36

x=41

A circular parallel-plate capacitor whose plates have a radius of 25 cm is being charged with a current of 1.3 A. What is the magnetic field 11 cm from the center of the plates

Answers

The magnetic field at 11 cm from the center of the plates is 2.364 x 10⁻⁷ T.

Given;

radius of the circular plate, d = 25 cm = 0.25 m

current in the plate, I = 1.3 A

distance from the center of the circular plate, r = 11 cm = 0.11 m

To find:

magnetic field (B)

The magnetic field from the given distance is calculated as from Biot Savart equation:

[tex]B = \frac{\mu_o I}{2\pi r} \\\\where;\\\\\mu_o \ is \ permeability \ of \ free \ space \ 4\pi \times 10^{-7} \ T.m/A\\\\B = \frac{(4\pi \times 10^{-7} ) \times (1.3)}{2\pi \times 0.11} \\\\B = 2.364 \ \times 10^{-6} \ T[/tex]

Therefore, the magnetic field 11 cm from the center of the plates is 2.364 x 10⁻⁷ T.

Learn more here: https://brainly.com/question/17035710

the number of significant figures in the measurement 4.300×10^5 km are​

Answers

Answer:

6

Explanation

Any numbers in scientific notation are considered significant. For example, 4.300 x 10-4 has 4 significant figures.

Answer From Gauth Math

Puerto Rico is a U.S. territory that is southeast of the mainland United States. Which letter on the map represents the location of Puerto Rico?

Answers

The letter that represents the location of Puerto Rico on the map is A.

As the question noted, Puerto Rico is to the southeast of the United States. The first step therefore, would be to find the United States.

The United States is located in the center of the map and is painted orange. I have highlighted it in the attachment.

A place that is southeast of the United States would be both:

downward because it is south and,rightward because it is east.

The only place matching that description is labeled A so we can conclusively say that Puerto Rico is labeled the place labeled A.

For more information on Puerto Rico check https://brainly.com/question/23481183.

Answer:

its a im puerto rican so i know it is a

Explanation:

give the guy below brain award

According to the conservation of mechanical energy, the kinetic energy before plus the kinetic energy after equals the
potential energy before plus the potential energy after.
True
False

Answers

Answer:

False

Explanation:

The conservation of mechanical energy says that the kinetic energy before plus the potential energy before equals the kinetic energy after plus the potential energy after.

The answer is false

A block of mass 2 kg is launched by compressing a spring of force constant 1200 N/m. The block slides on a frictionless surface, up a 1 meter tall ramp, then it enters a region of rough surface. It comes to a stop after traveling 3 meters over the rough surface. The coefficient of kinetic friction between the block and the rough surface is 0.40.

Required:
a. How many forces end up doing work on the block from release to stop?
b. What is the total non-conservative work done on the block?
c. What is the change in the spring potential energy of the block?

Answers

Answer:

zzyibgsdwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwe

Explanation:

Can Some1 help??

When using the "ball and stick" drawing method of drawing a compound, which element usually goes in the center of the model?

Answers

What type of problem it is

Two students try to move a heavy box. One pushes with the force of the 20N while the other pulls with a force of 30N in the same direction. What is the work done by each boy after 10 seconds if the box can\t be moved? Show your equation.

Answers

Answer:

Explanation:

Time is not part of the Work equation. That's the only conclusion that you can come to.

Work = Force * distance.

Not enough information is given to go any further. You don't have enough information to calculate the distance.

We don't know if the box can be moved or not. It says heavy. 50 N is really not very much.

I would guess that you are intended to answer that the box didn't move, but it's really hard to tell.

The magnetic flux that passes through one turn of a 8-turn coil of wire changes to 5.0 Wb from 8.0 Wb in a time of 0.098 s. The average induced current in the coil is 140 A. What is the resistance of the wire

Answers

Answer:

Resistance is 1.75 ohms

Explanation:

Magnetic flux:

[tex]{ \phi{ = NBA}}[/tex]

N is number of turns, N = 8

B is magnetic flux

A is area of projection.

From faradays law:

[tex]E = - \frac{ \triangle \phi}{t} [/tex]

where E is the Electro motive force.

But E = IR

where I is current and R is resistance:

[tex]IR = \frac{( \phi_{1} - \phi _{2}) }{t} \\ \\ 140 \times R = \frac{8 \times (8 - 5)}{0.098} \\ \\ R = \frac{24}{0.098 \times 140} \\ \\ resistance = 1.75 \: ohms[/tex]


Which wave has the highest frequency when traveling through the indicated metal?
Wavelength of 2.1 m in copper
Wavelength of 1.4 m in lead
Wavelength of 0.9 m in brass
Wavelength of 1.8 m in gold

Answers

Answer:

wavelength of 1.4in lead

Answer:

0.9

Explanation:

g Suppose that the Red cart has a mass of 500 grams, and the blue cart has a mass of 250 grams, and they are connected with a spring of spring constant 100 N/m. If the Red cart is held, and the Blue cart is pulled away with a force 19.2 N, what will be the force on the Red cart (write your answer in newtons, magnitude only)

Answers

Answer:

19.2 N

Explanation:

After any transients dissipate, all forces must balance. The red cart never moves.

Mention the importance of occupation??​

Answers

Answer:

ln the contemporary time , farming can be considered as comparitively important occupation as it can feed the population , So agriculture is having a greater importance than any other occupation.

When you exert 75 N on a jack to lift a 6000 N car, what is the jack’s actual mechanical advantage? Show your work.

Answers

Answer:

80

Explanation:

the mechanical advantage is the ratio of the load to the effort so it doesn't have units.to calculate it you use the formula

mechanical advantage=load/effort

in this case the load is 6000N and the effort is 75N

Ma=6000/75

=80

I hope this helps

A load of 25 kg is applied to the lower end and of a steal wire of length 25 m and thickness 3.0mm .The other end of wire is suspeded from a rigid support calculate strain and stress produced in the wire​

Answers

Answer:

the weight of the wire + 25kg

Explanation:

the acceleration due to gravity jupiter is 25m/s Square . what does it mean

Answers

Answer:

The acceleration due to gravity of Jupiter is 25 m/s^2. means that, Any object dropped near Jupiter's Surface will accelerate downward (towards the Jupiter's surface) at the rate of 25 m/s^2 due to the gravity of Jupiter

Explanation:

hope it's help

Answer:

Explanation:

If any object is dropped from a height above the Jupiter's surface the object will fall towards jupiter's surface with a constant acceleration of 25m/s^2.

Trong thực nghiệm nhiễu xạ qua 1 khe hẹp, bề rộng khe là 2.10-5 m, màn quan sát đặt cách khe 0,5 m. Chiếu ánh sáng có bước sóng 480 nm xuyên qua khe và thấy có nền nhiễu xạ trên màn quan sát. Tính bề rộng của vân sáng liền kề vân sáng trung tâm.

Answers

Answer:

tyygggghgtyhyrdfgyyyhjjillbxsrfvgygvnjj

Explanation:

cffczhxucuxoyitxohvojcdivbjv ohxc

The strength of the magnetic field of a magnet

A. Remains the same at any distance from a magnet.
B. Decreases as distance from the magnet decreases.
C. Decreases as distance from the magnet increases.
D. Increases as distance from the magnet increases.

Answers

Answer:

C

Explanation:

further away = less strength because the magnetic field is weaker

Which factor affects kinetic energy but not potential energy?

Answers

Answer:

mass

Explanation:

because as the mass increase kinetic energy also increase

I REALLY NEED HELP WITH PHYSICS ASAP!!!
Vf^2 = v0^2 + 2a (xf - x0)


Solve for a

Answers

Answer:

a. solve for a

[tex]vf ^{2} = vo ^{2} + 2a(xf - xo) \\ 2a(xf - xo) = vf^{2} - vo ^{2} \\ a = \frac{vf^{2} - vo^{2} }{2(xf - xo)} \\ a = \frac{vf ^{2} - vo ^{2} }{2xf - 2xo} [/tex]

I hope I helped you ^_^

RADIOWAVES of constant amplitude can be generated with
1) FET
2) filter
3)rectifier
4)oscillator​

Answers

Answer:

4) oscillator

Explanation:

4) oscillator

In the Bohr model of the hydrogen atom, an electron in the 3rd excited state moves at a speed of 2.43 105 m/s in a circular path of radius 4.76 10-10 m. What is the effective current associated with this orbiting electron

Answers

Answer:

Current =,charge / time

Charge = e = 1.6E-19 coulombs

t = T time for 1 revolution  (period)

v = S / T = distance traveled in 1 revolution / time for 1 revolution

T = S / v = 2 pi * 4.76E-10 / 2.43E5 = 1.23E-14

I = Q / T = 1.6E-19 / 1.23E-14 = 1.30E-5

Why do you think scientists needed to invent a temperature scale, instead of deciding if things were hot or cold?

Answers

For the same reason that we need units of length, instead of just "long" or "short". And units of distance instead of "near" and "far". And units of time instead of "early" and "late" or "old" and "new". And units of weight instead of "light" and "heavy". And units of sound-pressure instead of "loud" and "soft".

"Hot" and "cold" mean different things to different people, and may even mean different things to the same person at different times.

A person who grew up in Panama, and comes to visit Chicago in July, says it's cold.

A person who lives in Chicago, and goes to visit Jamaica in January, says it's hot.

A professional chef, following a recipe, can't just cook the steak until it's "hot inside". He needs a number, so he can cook it the same every time.

A technician in a Chemistry lab may have two solutions, and he's supposed to pour half of the cooler one into the warmer one. One of them is 25°C and the other one is 22°C. He's got a problem. He can't tell the difference. He never learned temperature scales. All he knows is "hot" and "cold", and they both feel luke-warm to him. He doesn't even have a way to measure them, because temperature scales were never invented. He's stumped. And while he's standing there scratching his head, both solutions drift to the same temperature, and the lab goes up in flames. The technician is so petrified, he becomes overwhelmed with shame and regret, and makes himself sick and feverish. His forehead feels hot but nobody can measure his temperature, so nobody knows how sick he is.

All because Franz Fahrenheit and Sven Celsius had planned to invent measurable scales in their lab, but decided to go fishing that day.

lanet R47A is a spherical planet where the gravitational acceleration on the surface is 3.45 m/s2. A satellite orbitsPlanet R47A in a circular orbit of radius 5000 km and period 4.0 hours. What is the radius of Planet R47A

Answers

[tex]2.6×10^6\:\text{m}[/tex]

Explanation:

The acceleration due to gravity g is defined as

[tex]g = G\dfrac{M}{R^2}[/tex]

and solving for R, we find that

[tex]R = \sqrt{\dfrac{GM}{g}}\:\:\:\:\:\:\:(1)[/tex]

We need the mass M of the planet first and we can do that by noting that the centripetal acceleration [tex]F_c[/tex] experienced by the satellite is equal to the gravitational force [tex]F_G[/tex] or

[tex]F_c = F_G \Rightarrow m\dfrac{v^2}{r} = G\dfrac{mM}{r^2}\:\:\:\:\:(2)[/tex]

The orbital velocity v is the velocity of the satellite around the planet defined as

[tex]v = \dfrac{2\pi r}{T}[/tex]

where r is the radius of the satellite's orbit in meters and T is the period or the time it takes for the satellite to circle the planet in seconds. We can then rewrite Eqn(2) as

[tex]\dfrac{4\pi^2 r}{T^2} = G\dfrac{M}{r^2}[/tex]

Solving for M, we get

[tex]M = \dfrac{4\pi^2 r^3}{GT^2}[/tex]

Putting this expression back into Eqn(1), we get

[tex]R = \sqrt{\dfrac{G}{g}\left(\dfrac{4\pi^2 r^3}{GT^2}\right)}[/tex]

[tex]\:\:\:\:=\dfrac{2\pi}{T}\sqrt{\dfrac{r^3}{g}}[/tex]

[tex]\:\:\:\:=\dfrac{2\pi}{(1.44×10^4\:\text{s})}\sqrt{\dfrac{(5×10^6\:\text{m})^3}{(3.45\:\text{m/s}^2)}}[/tex]

[tex]\:\:\:\:= 2.6×10^6\:\text{m}[/tex]

A mass weighing 64 pounds stretches a spring 6 inches. The mass moves through a medium offering a damping force that is numerically equal to β times the instantaneous velocity. Determine the values of β > 0 for which the system will exhibit oscillatory motion. (Enter your answer as a single inequality.)

Answers

Answer:

chk photo

Explanation:

The values of β for which the system will exhibit oscillatory motion are those greater than 0.

What is oscillatory motion?

To determine the values of β for which the system will exhibit oscillatory motion, you need to perform a damped oscillation analysis on the system.

The equation of motion for a damped oscillator is given by:

F = ma = -kx - βv

where F is the force, m is the mass, a is the acceleration, k is the spring constant, x is the displacement of the mass from its equilibrium position, β is the damping coefficient, and v is the velocity of the mass.

To determine the values of β for which the system will exhibit oscillatory motion, you need to solve for the roots of the characteristic equation, which is obtained by setting the acceleration (a) equal to zero:

0 = -kx - βv

βv + kx = 0

x(β + k) = 0

The roots of this equation are x = 0 and x = -(β + k). If x = 0 is a root of the characteristic equation, then the system will exhibit steady-state behavior (i.e., the mass will come to rest at its equilibrium position and not oscillate). If x = -(β + k) is a root of the characteristic equation, then the system will exhibit oscillatory behavior (i.e., the mass will oscillate around its equilibrium position).

Therefore, the values of β for which the system will exhibit oscillatory motion are those for which x = -(β + k) is a root of the characteristic equation. This means that β must be such that:

-(β + k) < 0

β > -k

Since k is a positive value (the spring constant is always positive), the inequality simplifies to:

β > 0

Learn more about oscillation, here:

https://brainly.com/question/30111348

#SPJ5

Can someone log into my acc FOR ME I will pay you to complete my physics assignments for money or points?!!

Answers

Answer: no sorry../

Explanation:

explain why our sweat is salty?​

Answers

Answer:

Sweat also contains ammonia and urea, which are produced by the body when it breaks down proteins from the foods you eat.

Hope this helps..

A note of frequency 2000Hz has a velocity of 400 ms! What is the wavelength of the note?​

Answers

Answer:

Explanation:

frequency=c/λ

c=400m/s

putting values

2000=400/λ

λ=0.2m

f = c / λ and c = 400m/s

2000 = 400 / λ

λ = 400 / 2000

λ = 0.2 m

A rock with a mass of 16 kilograms is put aboard an airplane in New York City and flown to Boston. How much work does the gravitational field of the earth do on the rock

Answers

The work done by the gravitational field of the earth on the rock is 9.998 x 10⁸ J.

The given parameter include:

the mass of the object, m₁ = 16 kg

Note: the mass of the earth, m₂ = 5.972 x 10²⁴ kg

The work done by the gravitational field of the earth is given as;

Work done = gravitational force (F) x radius of the earth (R)

[tex]Work \ done = \frac{Gm_1m_2}{R^2} \times R\\\\Work \ done = \frac{Gm_1m_2}{R} \\\\where;\\\\R \ is \ the \ radius \ of \ the \ earth = 6,378 \ km = 6,378,000 \ m\\\\G \ is \ the \ universal \ gravitation \ constant = 6.674 \times 10^{-11} Nm^2/kg^2\ \\\\Work \ done = \frac{(6.674 \times 10^{-11} ) \times (5.972\times 10^{24}) \times (16)}{6,378,000 } \\\\Work \ done = 9.998 \times 10^{8} \ J[/tex]

Therefore, the work done by the gravitational field of the earth on the rock is 9.998 x 10⁸ J.

To learn more about work done by gravitational field of the earth visit: https://brainly.com/question/13934028

a youthful person run at 7km/h in a north- west direction across the derk of a ship in which is streaming due east at 40 km/h .ifind the velocity of the boy relative to the Sea
ii,And the velocity of the sea relative to the boy​

Answers

Answer:

velocity of ship wrt sea= 7i∧

velocity of women on deck= 40j∧

velocity of women relative to sea will be resultant of above two velocoties,

7i∧ + 40j∧ magnitude is

square root (7 x 7 + 40x40)

=√49+1600

=√1612

=40.14 m/s

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