Answer:
1.8m/s^2
Explanation:
Since the two ropes are going up, their combined force is 105+115=220N. With a gravitational force of 186N, the force of the two ropes pulling up the will be 220-186=34N.
Now we need the mass of the bucket itself in order to find the acceleration of the bucket (remember that F=ma and m is needed to find a). Since gravitational acceleration is 9.8m/s^2 and F=186N, 186/9.8=18.97959184 kg for the mass of the bucket.
Now that we have the mass of the bucket, we can find the acceleration of the bucket. Since F=34N from earlier, 34N/18.97959184kg=1.791397849m/s^2=1.8m/s^2 is the acceleration of the bucket.
Therefore, 1.8m/s^2 is the correct answer.
Please mark brainliest!
Answer:
1.8
Explanation:
honestly i jus took the test
In physics, a is a group of related objects that interact with each other and form a complex whole.
Answer: a system
Explanation: just did the test
Answer:
system is correct
Explanation:
in a distance vs time graph what does the slope represent
You are building a house of cards. Explain how you know if the forces
acting on the cards are not balanced
Answer:
Equilibrium
Explanation:
For something to be balanced like a house of cards all forces acting on it have to be in equilibrium.
All the cards will fall down if they the forces acting on them aren't balances. That's how, it can be known that the forces acting on the cards are not balanced.
What are balanced force and unbalanced force?The forces acting on a body are said to be balanced if the total force of all the forces acting on it equals zero. Let's examine a few instances of balanced forces to better comprehend how the motion of the body is unaffected.
Unbalanced forces are those acting on a body when the net force acting on the body is greater than zero. The body alters its state of motion when unbalanced forces act on it.
If the forces acting on the cards are not balanced, every card will fall. It is possible to determine that the forces affecting the cards are not balanced in this way.
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How do the nuclei of covalently bonded atoms help keep the bond together.
Answer:
Explanation:
How do the nuclei of covalently bonded atoms help keep the bond together? ... -Positive particles in the nucleus are attracted to shared electrons, so the atoms stay close together. Positive particles in the nucleus are attracted to shared electrons, so the atoms stay close together.
The shared electrons in the nucleus attract positive particles, keeping the atoms close to one another. The shared electrons in the nucleus attract positive particles, keeping the atoms close to one another.
What are atoms?The smallest unit of matter that may be divided without producing electrically charged particles is the atom. It is also the smallest piece of substance with chemical element-like characteristics. As a result, the atom serves as the fundamental unit of chemistry.
The atom is mostly made up of void space. The remaining material is made up of an electron cloud that is negatively charged and is encircled by a positively charged nucleus made up of protons and neutrons.
In contrast to the nucleus, which is compact and dense, the electrons—the lightest charged particles in nature—are big and sparse. Electric forces in an atom bind the electrons to the nucleus, making them drawn to the nucleus by any positive charge.
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Question:why do some liquids flow really fast and other flow really slow?does temperature affect the rate of flow?
If the thickness of the liquid affects its flow rate
Then————
Figure out the then part by the question
Answer:
Some liquids flow really fast and some flow really slow.
Explanation:
This is because of a liquids viscosity , If the liquids viscosity is high it will flow really slow like syrup. But if it has high viscosity it will flow really fast much like water.
Hope this helped!! :)
Describe the agronomic significance of the upper and lower plastic limits, and of the plasticity index?
Answer:It shows the size of the range of the moisture contents at which the soil remains plastic. In general, the plasticity index depends only on the amount of clay present. It indicates the fineness of the soil and its capacity to change shape without altering its volume.
Nicole is making smoothies. She uses 1.2 kilograms of
apples and 600 grams of strawberries. How many
kilograms of fruit does Ann use in all?
I
Answer:
1.8 kg
Explanation:
Nicole is making smoothies. She uses 1.2 kilograms of apples and 600 grams of strawberries.
1.2 kg = 1200 gram
600 grams
Now,
1200 + 600 = 1800 gram
1800 gram = 1.8 kg
Thus, 1.8 kilograms of fruit does Ann use in all
-TheUnknownScientist
What features will your car have to reduce the forces of friction and drag?
please help , i’m doing online class & my teacher doesn’t teach, we just read and try our best & i have no idea what this even means
Answer:
To decrease friction in machinery, low-friction materials such as Teflon and other plastics are used. Contact surfaces are designed to be smooth as possible. Lubricants are introduced to reduce friction. To decrease drag on an airplane, smooth surfaces and a streamlined design are used.
Is a bike standing still potential or kinetic?
Answer:
potential
Explanation:
Potential energy is stored
Plz mark brainliest
check the correctness of formula t=2π √m/k, dimensionally
Hi there! Lets see!
m is mass, and its units are kgk is the elastic constant measured in newtons per meter (N/m), or kilograms per second squared kg/s²Therefore:
[tex]\sqrt{\dfrac{m}{k}} =\sqrt{\dfrac{[kg]}{[\dfrac{kg}{s^2}]}} =\sqrt{\dfrac{[kg]}{[kg]}\cdot s^2} = \sqrt{[s]^2} = s[/tex]
The period is given in seconds so the formula is dimensionally correct.
state newton's three laws of motion
I. Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it.
Ex: You roll a ball. It slows down by friction.
II. Acceleration is produced when a force acts on a mass. The greater the mass (of the object being accelerated) the greater the amount of force needed (to accelerate the object).
Ex: You cannot kick a brick wall down, but you can kick a soccer ball because the brick wall is more massive.
III. For every action there is an equal and opposite re-action.
Ex:when a rocket lifts off, the rocket's action is to push down on the ground with the force of its engines, and the reaction is that the ground pushes the rocket upwards with an equal force.
Which statement does not describe brainstorming?
A Keep a record of ideas.
B Keep criticism of other's ideas to yourself.
C Collect only a few ideas.
D Use all of the information found when researching
Answer:
d
Explanation:
i just know (pls check out my question pls i will give nayone who answers brainiest)
Which the organism having prokaryotic cell
Answer:
Animals
Explanation:
1000-kg car travelling down on a steepest road, which has inclined angle of 18
degree. Coefficient of kinetic friction is 0.3.
Calculate
1. Weight (force due to gravity).
2.Horizontal and vertical component of the weight
3. Normal force
4.Friction force
5. Net force along the plane down
6. Acceleration
Answer:
1
Explanation:
it was thinking about how much and then the other than you can get it would be able to ask her to be able and then the way you have been sent from your browser
A block of wood weighs 160 N and has a specific gravity of 0.60. To sink it in fresh water requires an additional downward force of:_______A. 54N B. 64N C. 96N D. 110N E. 240N
Answer:
Your answer is: D) 110N
Hope this helped : )
Explanation:
In order for the wood to sink, it's specific gravity must equal 1 (or greater).
Specific gravity = .6 kg/m^3= Mass/volume
F (Newtons or kg x m/s^2) = Mass*9.8m/s^2.
Therefore, Mass = 160 N / 9.8 m/s^2= 16.32 kg
Volume = Mass/Specific Gravity = 16.32kg/.6 kg/m^3 = 27.2 m^3
Desired Specific gravity = 1 = (Mass + additional force/9.8m/s^2)/Volume = (16.32 kg +X / 9.8m/s^2)/27.2m^3
Solving for the additional force: X = 106.66...N
The answer is D, 110 N will be required to sink the block of wood.
A 40g bullet traveling at 450 m/s passed through a board and comes out traveling 300m/s. The board is 7.6cm thick. What is the force of friction applied by the wood to the bullet?
Answer:
f = 29605.2 [N]
Explanation:
To solve this problem we must use the following equation of kinematics, then use Newton's second law.
[tex]v_{f}^{2} =v_{o}^{2} -2*a*x[/tex]
where:
Vf = final velocity = 300 [m/s]
Vo = initial velocity = 450 [m/s]
a = acceleration [m/s²]
x = distance = 7.6 [cm] = 0.076 [m]
Now replacing and clearing a
2*a*0.076 = (450² - 300²)
a = 740131.57 [m/s²]
Now using Newton's second law which tells us that the force on a body is equal to the product of mass by acceleration.
f = m*a
where:
f = friction force [N]
m = mass = 40 [g] = 0.04 [kg]
f = 0.04*740131.57
f = 29605.2 [N]
What is the difference about the center of a quasar, when contrasted with a spiral galaxy?
Answer:
I don't understand the question SRRY!!
Can you plz answer my most recent question??
The difference about the center of a quasar, when contrasted with a spiral galaxy are
For Quasars:
Quasars are known to move with a lot of speed. Quasars are small. Quasar's often emit lines shifts far to the red wavelength as far as 15% to 96% the speed of lightQuasars are often very bright and more distant objects and can be detected without observing the underlying galaxies. They are also very luminous centers of galaxies in their infancy. They are supermassive black holes surrounded by bright accretion discsThe Spiral galaxies
Spirals are known to be flattened or 'disk' galaxies. They rotate differentially. That is the time to complete a full rotation often increases with distance from the center. The disk often wind up into a spiral form as a result of disturbance.A lot of spiral galaxies has a central bulge often surrounded by a flat, rotating disk of stars.two-thirds of spiral galaxies has a bar structure via their center.Learn more from
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Students start to walk across a bridge at 1.5 m/s. If it takes them 360 seconds to cross the bridge, how long is the bridge (in meters)?
Which substance is the stronger base?
Milk of Magnesia
Sodium Bicarbonate
Ferrous Hydroxide
Distilled Water
Answer:
Ferrous Hydroxide
Explanation:
A satellite is a large distance from a planet, and the gravitational force from the planet is the only significant force exerted on the
satellite. The satellite begins falling toward the planet, eventually colliding with the surface of the planet. As the satellite falls,
which of the following claims is correct about how the force that the planet exerts on the satellite Fps changes and how the force
that the satellite exerts on the planet Fsp changes, if at all? What reasoning supports this claim?
A
Fps and Fs both increase. The gravitational forces that two objects exert on one another decrease as the
separation between the objects increases, and these forces are always equal in magnitude.
B
Fps increases while Fsp remains constant. The gravitational force exerted by a planet on a satellite decreases
as the separation between the two objects increases, and the force exerted by the satellite on the planet remains
negligibly small.
с
Fps remains constant while Fgp increases. The gravitational force exerted by a planet on a satellite is a constant
equal to the weight of the satellite, and the gravitational force exerted by the satellite on the planet decreases as
the separation between the two objects increases.
D
Fps and Fs both remain constant
. The gravitational forces that a planet and a satellite exert on one another is a
constant equal to the weight of the satellite.
Answer:
None of the provided reasoning correct.
Explanation:
Let d be the distance between the center of the planet having mass M and the satellite having mass m.
The gravitational force acting between the planet and the satellite is
[tex]F= \frac {GMm}{d^2}\cdots(i)[/tex]
where G is the universal gravitational constant, d is the distance between the center of two bodies having masses M and m.
This gravitational force, F, is the mutual force between both the objects, so
[tex]F=F_{ps}=F_{sp}[/tex]
Where [tex]F_{ps}[/tex]: the force that the planet exerts on the satellite and
[tex]F_{sp}[/tex] the force that the satellite exerts on the planet.
So, from equation (i),
[tex]F_{ps}=F_{sp}=\frac {GMm}{d^2}\cdots(ii)[/tex]
As the satellite is falling towards the planet, to the distance, d, between the center of the planet and satellite is decreasing.
Now, from equation (ii), as [tex]F_{ps}[/tex] and [tex]F_{sp}[/tex]are inversely proportional to [tex]d^2[/tex]. So, both [tex]F_{ps}[/tex] and [tex]F_{sp}[/tex] increase on decreasing d.
Hence, both [tex]F_{ps}[/tex] and [tex]F_{sp}[/tex] increase as the gravitational forces that two objects exert on one another increases as the separation between the objects decreases, and these forces are always equal in magnitude.
None of the provided reasoning correct.
When a 5.0 kg box is hung from a spring, the spring stretches to 50 mm beyond its relaxed length. (a) In an elevator accelerating upward at 2.0 m/s2 , how far does the spring stretch with the same box attached? (b) How fast and in which direction should the elevator accelerate for the spring stretch to be zero (that is, the spring returns to its relaxed length)?
Answer:
a) the spring will stretch 60.19 mm with the same box attached as it accelerates upwards
b) spring will be relaxed when the elevator accelerates downwards at 9.81 m/s²
Explanation:
Given that;
Gravitational acceleration g = 9.81 m/s²
Mass m = 5 kg
Extension of the spring X = 50 mm = 0.05 m
Spring constant k = ?
we know that;
mg = kX
5 × 9.81 = k(0.05)
k = 981 N/m
a)
Given that; Acceleration of the elevator a = 2 m/s² upwards
Extension of the spring in this situation = X1
Force exerted by the spring = F
we know that;
ma = F - mg
ma = kX1 - mg
we substitute
5 × 2 = 981 × X1 - (5 ×9.81 )
X1 = 0.06019 m
X1 = 60.19 mm
Therefore the spring will stretch 60.19 mm with the same box attached as it accelerates upwards
B)
Acceleration of the elevator = a
The spring is relaxed i.e, it is not exerting any force on the box.
Only the weight force of the box is exerted on the box.
ma = mg
a = g
a = 9.81 m/s² downwards.
Therefore spring will be relaxed when the elevator accelerates downwards at 9.81 m/s²
The extension of the spring in the elevator is 60 mm.
For the extension of the spring to be zero, the elevator must be moving downwards under free fall.
The given parameters;
mass of the box, m = 5 kgextension of the spring, x = 50 mm = 0.05 mThe spring constant is calculated as follows;
F = kx
mg = kx
[tex]k = \frac{mg}{x} \\\\k = \frac{5 \times 9.8}{0.05} \\\\k = 980 \ N/m[/tex]
The tension on the spring in an elevator accelerating upwards is calculated as follows;
T = mg + ma
T = m(g + a)
T = 5(9.8 + 2)
T = 59 N
The extension of the spring is calculated as follows;
[tex]T = kx\\\\x = \frac{T}{k} \\\\x = \frac{59}{980} \\\\x = 0.06 \ m\\\\x = 60 \ mm[/tex]
For the extension of the spring to be zero, the elevator must be under free fall, such that the tension on the spring is zero.
For free fall, a = g
T = m(g - a) = 0
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will be required to accelerate a 1100kg car to .5 m/s
Answer:
550 N
Explanation:
Use Newton's second law:
F = ma
F is the force required to accelerate the car
m is the mass of the car
a is the acceleration of the car
In this problem, the mass is m=1100 kg, while the acceleration is a=0.5 m/s^2, therefore the force required to accelerate the car is 550 N
A mason stretches a string between two points 70 ft apart on the same level with a tension of 20 lb at each end. If the string weighs 0.18 lb, determine the sag h at the middle of the string.
Answer:
Explanation:
Let tension be T in each string . Let angle with horizontal be θ in the middle
The sum of vertical components of tension of two string will balance the weight
2Tsinθ = mg
2 x 20 sinθ = .18
sinθ = .18 / 40 = .0045
θ = .25783 degree
If sag be y
y / 70 = tan .25783
y = 70 x tan.25783
= .3150 m
= 31.50 cm .
1. A 500 N force applied to a box at a 50 degree angle above the horizontal surface. Find the x and y
components. Use the cheat sheet located in your blue resource folder, and show all work.
Answer:
The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.
Explanation:
At first we present a figure describing the situation explained on statement, the x and y components of the force are determined by the following trigonometric expressions:
[tex]F_{x} = F\cdot \cos \alpha[/tex] (1)
[tex]F_{y} = F\cdot \sin \alpha[/tex] (2)
Where:
[tex]F[/tex] - Magnitude of the force, measured in newtons.
[tex]\alpha[/tex] - Direction of the force above the horizontal surface, measured in sexagesimal degrees.
If we know that [tex]F = 500\,N[/tex] and [tex]\theta = 50^{\circ}[/tex], then the components of the force is:
[tex]F_{x} = (500\,N)\cdot \cos 50^{\circ}[/tex]
[tex]F_{x} = 321.394\,N[/tex]
[tex]F_{y} = (500\,N)\cdot \sin 50^{\circ}[/tex]
[tex]F_{y} = 383.023\,N[/tex]
The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.
The speed of sound through liquid glycerol is about 1900 m/s. Which of the following could be the speed of sound through solid steel?
A.
150 m/s
B.
730 m/s
C.
1900 m/s
D.
5950 m/s
150 m/ssssssssssssssssssssssssssssssssssss
If the speed of sound through liquid glycerol is about 1900 meters per second, then 5950 meters per second could be the speed of sound through solid steel, therefore the correct answer is option D.
What is a sound wave?It is a particular variety of mechanical waves made up of the disruption brought on by the movements of the energy. In an elastic medium like the air, a sound wave travels through compression and rarefaction.
As given in the problem statement The speed of sound through liquid glycerol is about 1900 m / s , then we have t find out which of the following could be the speed of sound through solid steel,
The speed of the sound is greater in the solid medium as compared to the liquid and gaseous mediums.
Thus, the correct answer is option D.
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Can someone help me?
Answer: (1, 30), (2,10), (3,40), (4,20)
Explanation:
NEED HELP
If a 6 volt battery is connected in series to resistances of 2 ohms, 8 ohms, and 14 ohms, what is the amount of the current that is flowing?
Answer:
I = 0.25 [amp]
Explanation:
To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance.
V = I*R
where:
V = voltage [Volt]
I = amperage or current [amp]
R = resistance [ohm]
Since all resistors are connected in series, the total resistance will be equal to the arithmetic sum of all resistors.
Rt = 2 + 8 + 14
Rt = 24 [ohm]
Now clearing I for amperage
I = V/Rt
I = 6/24
I = 0.25 [amp].
The acceleration of gravity on the
Moon is 1.62 m/s2. The mass of the
Moon is 7.35 x 10^22 kg. From this
information, what is the radius of the
Moon?
Answer:
Near the Earth's surface, the acceleration due to gravity is approximately constant. ... Its value is = 6.673 x 10-11 N·m2/kg2. ... The mass of the moon is 7.35 x 1022 kg. ... moon, the distance to the center of mass is the same as the radius: r = 1.74 x ... Handwriting · Spanish · Facts · Examples · Formulas · Difference Between ...
Explanation:
The acceleration of gravity on the Moon is 1.62 m/s2. The mass of the Moon is 7.35 x 10^22 kg. From this information, then the radius of the Moon is 3 * 10¹² m.
What is moon ?The sole natural satellite of Earth is the Moon. With a diameter around one-quarter that of Earth (equivalent to the breadth of Australia), it is the largest and most massive compared to its home planet and the fifth largest satellite in the Solar System. The Moon is bigger than any known dwarf planets of the Solar System and is a planetary-mass object with a distinct rocky body, making it a satellite planet according to geophysical definitions of the word. There isn't much of an atmosphere, hydrosphere, or magnetic field there. With a surface gravity of 0.1654 g, it has a gravity that is around one-sixth that of Earth. Jupiter's moon Io is the only satellite in the Solar System that is known to have a greater gravity and density.
The Moon travels an average distance around Earth.
Given,
g = 1.62 m/s²
m = 7.35*10²² kg
according to formula,
g = GM/r²
1.62 = 6.67× 10⁻¹¹ m³ kg⁻¹ s⁻²*7.35*10²² kg/r²
solving this for r we get
r = 1.7 * 10⁶ m
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FLAMING OR ALBERT .........
Answer:
Albert
Explanation:
An amateur astronomer looks at the moon through a telescope with a 15-cm-diameter objective. What is the minimum separation between two objects on the moon that she can resolve with this telescope? Assume her eye is most sensitive to light with a wavelength of 550 nm.
A. 120 m B. 1.7 km C. 26 km D. 520 km
Answer:
y = 128.0 km
Explanation:
The minimum separation of two objects is determined by Rayleygh's diffraction criterion, which establishes that two bodies are solved if the first minino of diffraction of one coincides with the central maximum of the second, with this criterion the diffraction equation remains
the diffraction equation for the first minimum is
a sin θ = λ
In the case of circular openings, the equation must be solved in polar coordinates, leaving the expression, we use the approximation that the sine of tea is very small.
θ = 1.22 λ / d
d = 15 cm
to find the distance we can use trigonometry
tan θ = y / L
tan θ = sin θ / cos θ = θ
substituting
y / L = λ / d
y = L λ /d
let's calculate
y = 384 10⁸ 500 10⁻⁹ / 0.15
y = 1.28 10⁵ m
Let's reduce to km
y = 1.28 10⁵ m (1km / 10³ m)
y = 128.0 km
the correct answer is 120 km away
