Please help I need this done ASAP
10 points + crown for whoever has the most accurate answer

Answer:

1

Step-by-step explanation:

a/b=3------equation 1

a+b=2-----equation 2

from equation 2

b=2-a

substitute b=2-a in equation 1

a/2-a=3

a=3(2-a)

a=6-3a

a+3a=6

a=6/4

a=3/2

substitute a=3/2 in equation 2

3/2+b=2

3+2b=4

2b=1

b=1/2

a-b=3/2-1/2

a-b=(3-1)/2

a-b=2/2

a-b=1

Answer:

1.572

Step-by-step explanation:

For a standard normal distribution,

P(z > c) = 0.058

To obtain C ; we find the Zscore corresponding to the proportion given, which is to the right of the distribution ;

Using technology or table,

Zscore equivalent to P(Z > c) = 0.058 is 1.572

Hence, c = 1.572

Answer:

you're right

Step-by-step explanation:

As the number of copies increases, the dimensions of the images continue to decrease but never reach 0. Option A is correct.

As of the given statement,
Both copy machines reduce the dimensions of images that run through the machines. which statment is true is to be justified.

In mathematics, dimensions are the measurements of the size or distance of an item, region, or space in one direction. In layman's words, it is the measurement of something's length, width, and height. Length is the most commonly used dimension.

here,
Both copy machines diminish the size of images that pass through them. Which statement is correct must be justified. So, As the number of copies increases, the image dimensions drop but never reach zero.

Thus, the image dimensions decrease as the number of copies grows, but never reaches zero.

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Solution :

Defining the following events as :

B : Being a Business major

α : Studying at the library

∴ Given that :

[tex]$P(B) = \frac{45}{100}$[/tex]

         = 0.45

Again, P [ Studying at the library | Being a Business major ] = 2 P [ Studying at the library | Being a non business major ]

[tex]$P[ \alpha | B] = 2 P[\alpha | B^C]$[/tex]   .......(1)

Again,

[tex]$P[\text{Studying at the library } | \text{ Being a business major}] = \frac{1}{2} = 0.50$[/tex]

[tex]$P(\alpha | B) = 0.50$[/tex]

From (1), we get

[tex]$P(\alpha | B^C) = \frac{1}{2} . P(\alpha | B)$[/tex]

              [tex]$=\frac{1}{2} \times 0.50$[/tex]

              = 0.25

Therefore, we need,

= P[  The students is a Business major | The student studies at the library ]

[tex]$=P(B | \alpha)$[/tex]

By Bayes theorem

[tex]$=\frac{P(B). P(\alpha | B)}{P(B).P(\alpha | B) + P(B^C). P(\alpha | B^C)}$[/tex]

[tex]$=\frac{0.45 \times 0.50}{0.45 \times 0.50 + 0.55 \times 0.25}$[/tex]

= 0.6207

Answer:

yes it is. a polygon is any closed shape with at least 3 connected lines (eg. triangle, square, pentagon, hexagon, heptagon, octagon, etc)

Step-by-step explanation:

Answer:

3 tenths means 3 over ten represented as as 3/10 and 10 has one zero I.e tenth different from hundredths which has 2 zeros so our decimal shld also have one zero which is 0.3...so 0.3 is the answe hope it helps❤

Answer:

Since both [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the necessary conditions are satisfied.

0.9945 = 99.45% probability that at most 85 out of 136 DVDs will work correctly.

Step-by-step explanation:

Test if the normal curve can be used as an approximation to the binomial probability by verifying the necessary conditions.

It is needed that:

[tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex]

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

Assume the probability that a given DVD will work correctly is 52%.

This means that [tex]p = 0.52[/tex]

136 DVDs

This means that [tex]n = 136[/tex]

Test the conditions:

[tex]np = 136*0.52 = 70.72 \geq 10[/tex]

[tex]n(1-p) = 136*0.48 = 65.28 \geq 10[/tex]

Since both [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the necessary conditions are satisfied.

Mean and standard deviation:

[tex]\mu = E(X) = np = 136*0.52 = 70.72[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{136*0.52*0.48} = 5.83[/tex]

Consider the probability that at most 85 out of 136 DVDs will work correctly.

Using continuity correction, this is [tex]P(X \leq 85 + 0.5) = P(X \leq 85.5)[/tex], which is the p-value of Z when X = 85.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{85.5 - 70.72}{5.83}[/tex]

[tex]Z = 2.54[/tex]

[tex]Z = 2.54[/tex] has a p-value of 0.9945.

0.9945 = 99.45% probability that at most 85 out of 136 DVDs will work correctly.

↪[tex] \huge\rm{answer: } \: \boxed{ \purple{24 }}[/tex]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

M(6)= {0, 6, 12, 18, 24, 30, 36, 42, 48, 54, 60 ...}

M(8) = {0, 8, 16, 24, 32, 40, 48, 56, 64, 72, 80...}

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

I hope you understood!✏

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

[tex] \huge\boxed{ \boxed{ \rm{Hope \: this \: helps }}}[/tex]

Answer:

6=0,6,12,18,24,30,36,42,48,54,60

8=0,8,16,24,32,40,48,56,64,72,80

HCF=24,48

LCM=0,6,12,18,,30,36,42,48,54,60,8,16,24,32,40,,56,64,72,80

Answer:

A

Step-by-step explanation:

Because we can rearrange the equation and get:

x²=5+4

x²=9

[tex]x = \sqrt{9} [/tex]

[tex]x = + 3 \: \: or \: \: - 3[/tex]

9514 1404 393

Answer:

  not tangent

Step-by-step explanation:

AB will be tangent to circle O if AB ⊥ BO. That can be tested by checking to see if AB, BO, and AO satisfy the Pythagorean theorem.

According to the Pythagorean theorem, the length of the hypotenuse of a right triangle with legs 3.75 and 8 will be ...

  hypotenuse = √(3.75² +8²) = √78.0625 ≈ 8.835

The length of AO is somewhat greater than that, so AB cannot be a tangent to the circle.

__

The angle ABO is obtuse.

Answer:

16

Step-by-step explanation:

an area is always calculated by multiplying 2 dimensions.

when changing the dimensions, then the change factors for EACH dimension go into the calculation too.

therefore, when both dimensions of an area are enlarged 4 times, then the area is enlarged 4×4 = 16 times.

this just propagates to the whole surface area of an object, as each individual area of the overall surface area is enlarged by the same factor. and so, the sum of all the individual areas (= altogether the surface area of the object) is also enlarged in total by the same factor.

just think

16×a + 16×b + 16×c ... = 16×(a+b+c+...)

and you understand why.

9514 1404 393

Answer:

Step-by-step explanation:

Reflection over the x-axis changes the sign of the y-coordinate. Reflection over the y-axis changes the sign of the x-coordinate. We can summarize the transformations as ...

  preimage point ⇒ reflection over x ⇒ reflection over y

A(−8,−2) ⇒ A'(-8, 2) ⇒ A"(8, 2)

B(−4,−3) ⇒ B'(-4, 3) ⇒ B"(4, 3)

C(−2,−8) ⇒ C'(-2, 8) ⇒ C"(2, 8)

D(−10,−6) ⇒ D'(-10, 6) ⇒ D"(10, 6)

Answer:

No, binomial distribution cannot be applied.

Step-by-step explanation:

We known that a Binomial Distribution depends on provided experiment , a binomial distribution have only 2 outcomes. For example, when we flip a coin in the air, then the possible outcomes are Head and Tail.

But in the context, an American roulette wheel has [tex]37[/tex] outcomes. It means when we spin the American Roulette wheel, ball may lend on any of the numbers between 0 to 36. So there are more than [tex]2[/tex] outcomes.

Therefore, binomial distribution can not be applied here.

Answer:

-  x³ - 2x² + 3 - 1 / x

Step-by-step explanation:

(4x³ - 8x² + 12x - 4) / (-4x)

-  x³ - 2x² + 3 - 1 / x

Step-by-step explanation:

4n + 3n2 + 2 + n + 6n – 1 Expand with – 1

3n2 + 4n + n + 6n + 2 – 1 Grouped liked terms

3n2 + 11n – 1

Answer: total cost to be saved is $2600. Her saving pattern is 2, 4, 8,…

a) The pattern of her saving is in geometric sequence. i.e. a=2, r=4/2=2 0r 8/4=2 ( a = First term, r = common ratio) so, expression for amount saved on day (n) = t(n) = ar^(n-1), where: a = first day of saving r = common ration n = number of day

b) Expression that represents the total amount saved by day (n) (including day n) = S = a(r^n-1)/r-1 where: S = sum of amount saved a = first day of saving r = common ration n = number of day

c) To buy the car, she needs at least $2600 which is equal 260000 cents.  S = a(r^n-1)/r-1 = 260000 = 2(2^n-1)/r-1 = 260000/2 = 2^n-1/2-1 = 130000 = 2n^-1 = 130000+1 = 2^n = 130001 = 2^n = n = ln(130001)/ln(2) = n = 16.988

So… for n to satisfy the least value of 130001 cents, n should be at least 17 Therefore it will take at least 17 days for her to save enough money to buy a car

Step-by-step explanation:

It will take her about 17 days to buy the car worth 260000 cents

If a student decides she wants to save money to buy a used car that cost $2600 (260,000 cents)

If she saves 2 cents the first day and doubles the amount thereafter, the sequence of savings will be:

2, 4, 8...

This sequence is geometric in nature

In order to determine how long it will take her to save 260,000, we will use the sum of a GP formula expressed as:

[tex]S_n = \frac{a(r^n-1)}{r-1}[/tex]

Given the folowing

a = 2

r = 4/2 = 8/4 = 2

Sn = 260,000

Substitute into the formula the given parameters

[tex]260000= \frac{2(2^n-1)}{2-1}\\260000/2=2^n-1\\130000 = 2^n - 1\\2^n = 130000 + 1\\2^n = 130001\\nlog 2=log130001\\n = \frac{log130001}{log2} \\n \approx 17[/tex]

This shows that it will take her about 17 days to buy the car worth 260000 cents

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Answer:

12% percent of fish in own

The % of people surveyed own fish is 12%.

To find the % of people surveyed own fish.

Relative frequency refers to the percentage or proportion of times that a given value occurs within a set of numbers, such as in the data recorded for a variable in a survey data set.

Given that:

In a survey conducted at a pet store, 150 customers were asked if they owned birds or fish.

By the data on the table:

Total (own fish) = 0.04 + 0.08 = 0.12

So, own fish = 0.12

=12/100= 12%

So, 12% of the people surveyed own fish.

Learn more about relative frequency here:

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Answer:

95%

Step-by-step explanation:

Mean , xbar = 64.3; standard deviation, s= 2.4

Using the empirical formula where ;

68% of the distribution is within 1 standard deviation from the mean ;

95% of the distribution is within 2 standard deviation from the mean

percent of heights that lie between 59.5 inches and 69.1 inches.

Number of standard deviations from the mean /

Z = (x - μ) / σ

(x - μ) / σ < Z < (x - μ) / σ

(59.5 - 64.3) / 2.4 < Z < (69.1 - 64.3) / 2.4

-2 < Z < 2

Thia is within 2 standard deviations of the means :

2 standard deviation form the mean = 95% according to the empirical rule.

Answer:

The company should use a mean of 12.37 ounces.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The distribution for the amount of beer dispensed by the machine follows a normal distribution with a standard deviation of 0.17 ounce.

This means that [tex]\sigma = 0.17[/tex]

The company can control the mean amount of beer dispensed by the machine. What value of the mean should the company use if it wants to guarantee that 98.5% of the bottles contain at least 12 ounces (the amount on the label)?

This is [tex]\mu[/tex], considering that when [tex]X = 12[/tex], Z has a p-value of [tex]1 - 0.985 = 0.015[/tex], so when [tex]X = 12, Z = -2.17[/tex].

Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-2.17 = \frac{12 - \mu}{0.17}[/tex]

[tex]12 - \mu = -2.17*0.17[/tex]

[tex]\mu = 12 + 2.17*0.17[/tex]

[tex]\mu = 12.37[/tex]

The company should use a mean of 12.37 ounces.

Answer:

[tex]\sqrt{8}+\sqrt{9}[/tex]

Step-by-step explanation:

By definition, the conjugate of a binomial is when you switch the operator (either + or -) in between the terms. For example, the conjugate of [tex]a+b\sqrt{c}=a-b\sqrt{c}[/tex] as we are just changing the addition symbol (+) to a subtraction symbol (-).

Therefore, the conjugate of [tex]\sqrt{8}-\sqrt{9}[/tex] occurs when we change the subtraction symbol to an additional symbol, hence the answer is [tex]\boxed{\sqrt{8}+\sqrt{9}}[/tex]

The sine curve equation, y = 10·sin(x·π/24), that models the entrance of the

tunnel with a cross section that is the shape of half of a sine curve and the

height of the tunnel at the edge of the road, (approximately 7.07 ft.) are

found by applying the following steps

(a) The equation for the sine curve is y = 10·sin(x·π/24)

(b) The height of the tunnel at the edge of the road is approximately 7.07 feet

The reason for the above answers are presented as follows;

(a) From a similar question posted online, the missing part of the question

is, what is the height of the tunnel at the edge of the road

The known parameters;

The shape of the tunnel = One-half sine curve cycle

The height of the road at its highest point = 10 ft.

The opening of the tunnel at road level = 24 ft.

The unknown parameter;

The equation of the sine curve that fits the opening

Method;

Model the sine curve equation of the tunnel using the general equation of a sine curve;

The general equation of a sine curve is y = A·sin(B·(x - C) + D

Where;

y = The height at point x

A = The amplitude = The distance from the centerline of the sine wave to the top of a crest

Therefore;

The amplitude, A = The height of half the sine wave = The height of the tunnel = 10 ft.

D = 0, C = 0 (The origin, (0, 0) is on the left end, which is the central line)

The period is the distance between successive points where the curve passes through the center line while rising to a crest

Therefore

The period, T = 2·π/B = 2 × Opening at the road level = 2 × 24 ft. = 48 ft.

T = 48 ft.

We get;

48 = 2·π/B

B = 2·π/48 = π/24

By plugging in the values for A, B, C, and D, we get;

y = 10·sin((π/24)·(x - 0) + 0 = 10·sin(x·π/24)

The equation of the sine curve that fits the opening is y = 10·sin(x·π/24)

(b) The height of the tunnel at the edge of the road is given by substituting

the value of x at the edge of the road into the equation for the sine curve

as  follows;

The width of the shoulders = 6 feet

∴ At the edge of the road, x = 0 + 6ft = 6 ft., and 6 ft. + 12 ft. = 18 ft.

Therefore, we get;

y = 10 × sin(6·π/24) = 10 × sin(π/4) = 5×√2

y = 10 × sin(18·π/24) = 10 × sin(3·π/4) = 5×√2

The height of the, y, tunnel at the edge of the road where, x = 6, and 18 is y = 5·√2 feet ≈ 7.07 ft.

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Answer:

Step-by-step ex0.72

Answer:

A. Mutually Exclusive

Step-by-step explanation:

Mutually exclusive events:

Two events are mutually exclusive if they cannot happen together, that is, supposing the events are A and B:

[tex]P(A \cap B) = 0[/tex]

Choosing a student who is a French major or a chemistry major

Since each student only has one major, the student cannot be both a French and a Chemistry major, that is, [tex]P(A \cap B) = 0[/tex], so they are mutually exclusive and the correct answer is given by option A.

Answer:

All have exactly one solution

Step-by-step explanation:

a) -13x + 12 = 13x - 13

   +13x         +13x

-------------------------------

          12 = 26x - 13

         +13           +13

         -------------------

           25 = 26x

          -----   ------

           26     26

          25/26 = x

b) 12x + 12 = 13x - 12

   -12x          -12x

  -----------------------

          12 = x - 12

        +12       +12

        -----------------

            24 = x

c) 12x + 12 = 13x + 12

  -12x          -12x

 -----------------------------

           12 = x + 12

           0 = x

d) -13x + 12 = 13x + 13

   +13x           +13x

 -----------------------------

         12 = 26x + 13

        -13             -13

      -----------------------

          -1  = 26x

          ---      -----

          26       26

          -1/26 = x

Answer:

3.3km

Step-by-step explanation:

200m on first day

Increase 200 by 100 = 300 (200+100)

From 2nd day to 11th day

300×11

3300m

If 1000m = 1km

3300m =?

3300/1000

3.3km

I hope it helps

Answer:

V: x = 1; H: y = 4

Step-by-step explanation:

Point A is at x = 1 and y = 4

A vertical line at x=1 and a horizontal line at y = 4

I think that car travelled 128 km in one hour and 384km in 3 hours

Answer: 384 km

Step-by-step explanation:

Convert m/ph to k/ph by multiplying the equivalent of 1 mile in kilometers    

 (1m = about  1.6km) by the total number of miles.

 80  x  1.6 =  128

 You now have the distance traveled per hour in m/ph converted to k/ph.

 All you do now is multiply it by the time traveled:

 (128 kilometers per one hour for 3 hours)

 128 kph x 3 = 384km

Answer: [tex](\frac{2}{5},0) ; (0,2)[/tex]

Step-by-step explanation:

(to find the x-intercept, plug in 0 for y)

(to find the y-intercept, plug in 0 for x)

[tex]0=-5x+2\\5x=2\\x=\frac{2}{5}\\(\frac{2}{5},0)\\y=-5(0)+2\\y=2 \\(0,2)[/tex]