1) The position of an object to the north of a flagpole is given by x(t) = bt2 – c , where b and c are constants.
a) What is v(t), the velocity of the object as a function of time?
b) What is a(t), the acceleration of the object as a function of time?
c) At some time t the object is located at the flagpole. What is the velocity of the
object at that instant?
Answer:
a) The velocity of the object as a function of time, v(t) is 2·b·t
b) The acceleration of the function of time, a(t) is 2·b
c) The time at which the object is at the flagpole is t = √(c/b)
Explanation:
The function that gives the position of the object north of the flagpole, x(t) is presented as follows;
x(t) = b·t² - c (b and c are constants)
a) The velocity of the object as a function of time, v(t), is derived as follows
v(t) = x'(t) = d(b·t² - c)/dt = 2·b·t
The velocity of the object as a function of time, v(t) = 2·b·t
b) The acceleration of the function of time, a(t) = v'(t) = d(2·b·t)/dt = 2·b
c) The time at which the object is at the flagpole is given by the x-intercept of the function, where x(t) = 0, as follows;
At the x-intercept, we have, x(t) = 0 and x(t) = b·t² - c
∴ 0 = b·t² - c, which gives
b·t² = c
t² = c/b
t = ±√(c/b), we reject the negative value to get;
The time at which the object is at the flagpole, t = √(c/b).
state the formula for period of sham in terms of acceleration and displacement
Answer:
Finding time period of SHM from equation of displacement
Explanation:
0
Say for example I've got the equation of a SHM as:
x=Acos(ωt+ϕ)
where A is the amplitude.
How do I find the time period of this motion?
I tried by finding the second order differential of the given equation.
a=d2xdt2=−Aω2cos(ωt+ϕ)
Comparing it with the general equation for acceleration a=−ω2x, we can find ω from here.
But that is where the problem is coming. It makes no sense if I write ω=ωA−−√.
What is the correct method to find the time period of the SHM? What am I missing?
There is a very simple mistake in your math. Notice A is part of x, it is factored so you'll get to ω=ω again. If you want to find a meaning to ωT=2π, consider the fact that cos (or sin) are periodic functions with period 2π. Hence, every time you have a time difference such that ω(t1−t2)=2π you are back at the same point. Hence the period is given by ωT=2π.
Suppose the charged sphere is made from a conductor, rather than an insulator. Do you expect the magnitude of the force between the point charge and the conducting sphere to be greater than, less than, or equal to the force between the point charge and an insulating sphere
Answer:
* Point charge outside the radius of the sphere r> R, the force in the two systems is the same
* Point charge inside the sphere r <R, therefore the force in the system with the insulating sphere is greater
Explanation:
To answer this question let's use the relation
F = q E
with q being the point charge and E the electric field created by the sphere.
If we use Gauss's law
The electric field flux is proportional to the wax charge within the surface.
Let's analyze our situation.
* Point charge outside the radius of the sphere
r> R
where R is the radius of the sphere and r the distance from the center of the sphere to the point charge
in this case the waxed charge for the insulating and conducting sphere is the same, therefore the force in the two systems is the same
* Point charge inside the sphere
r <R
conductive sphere.
As the charges are mobile, they are located on the surface of the sphere and there is no waxed charge within a Gaussian surface that passes through the point charge, therefore the electric field is zero and consequently the force
F = 0
insulating sphere
Charges cannot move therefore there is a fraction of charge within a surface that passes through the point charge, consequently the electric field is different from zero
Fe> 0
for this second position the force on the conducting sphere is zero
therefore the force in the system with the insulating sphere is greater
Answer:
am I the only one seeing blink
A railroad car (with a mass of 3250 kg) moves at 8.1 m/s . It collides with and couples to another car that was initially at rest. After the collision, the two cars move together at a speed of 4.50 m/s. What is the mass of the second car?
Answer:
m_2 = 2600kg
Explanation:
P_1 = P_2
P = (m_1)*(v_1)+(m_2)(v_2)
P_1 = (3250kg)(8.1m/s)+(m_2)(0m/s)
P_1 = 26,325 kg*m/s
P_2 = (3250kg)(4.5m/s)+(m_2)(4.5m/s)
P_2 = 14,625kg*m/s+(4.5m/s)m_2
26,325 kg*m/s = 14,625kg*m/s+(4.5m/s)m_2
11,700kg*m/s = (4.5m/s)m_2
m_2 = 2600kg
Please help
25 Points
What Mathematical leads to the formulas for the magnitudes of displacement, velocity, and acceleration?
Answer:
displacement=specific distance
*Velocity=∆displacement/time
*acceleration=∆velocity/time
Difference between gravitational force and frictional
Explanation:
gravitational force or gravity is the force of attraction between objects that have mass.
frictional force is the forec that opposes motion (movement) when two surface are in contact. (acts in the opposite direction of motion)
so to sum it up,
- gravtional force is the force of attraction between objects that have mass.
- objects on the earth have weight because of gravitational force between them and the earth.
frictional force
- oppose motion
- slow down and stop moving objects and;
- produce heat
hope it helps :)
If the wave is detected 12.5 minutes after the earthquake, estimate the distance from the detector to the site of the quake
Answer:
Remember the relation:
Speed*Time = Distance.
We can estimate that the speed at which an earthquake "moves", in the surface, is:
S = 6km/s (this is a low estimation actually)
Then if the wave is detected 12.5 minutes after the earthquake, we know that it traveled for 12.5 minutes before reaching the detector.
So we know the speed of the wave and the time it took to reach the detector, then we can use the equation:
Speed*Time = Distance.
to find the distance.
First, we should write the time in seconds
we know that:
1 min = 60 s
then:
12.5 min = 12.5*(60 s) = 750 s
Then, the wave traveled with a speed of 6 km/s for 750 seconds until it reached the detector, then the distance that it traveled is:
(6km/s)*750s = 4500 km
The distance between the detector and the site of the quake is around 4500 km.
Un cuerpo es saltado desde cierta altura , llegando al piso luego de 7 s. Determine de altura se le soltó . (g=10m/segundo al cuadrado )
Answer:
Maximum height, H = 35 meters
Explanation:
Given the following data;
Time = 7 seconds
Acceleration due to gravity, g = 10 m/s²
To find the maximum height;
Mathematically, the maximum height is given by the formula;
H = ½gt²
H = ½ * 10 * 7
H = 5 * 7
Maximum height, H = 35 meters
Object A has a mass of 5 kg and a velocity of 6 m/s to the east while Object 1 point B has a mass of 12 kg and velocity 0.6 m/s also to the east. What is the momentum of the system? (Let east be positive)
help plss I got family
Answer:
Momentum of system = 37.2 Kgm/s.
Explanation:
Given the following data;
Mass A = 5 kgVelocity A = 6 m/sMass B = 12 kgVelocity B = 0.6 m/sTo find the momentum of the system;
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
Momentum = mass * velocity
For object A;
Momentum A = 5 * 6
Momentum A = 30 Kgm/s
For object B;
Momentum B = 12 * 0.6
Momentum B = 7.2 Kgm/s
Next, we would determine the momentum of this system using the formula;
Momentum of system = Momentum A + Momentum B
Substituting the values into the formula, we have;
Momentum of system = 30 + 7.2
Momentum of system = 37.2 Kgm/s.
why do black holes have a large gravitational pull that even light cannot escape from
Answer:
Because matter has been squeezed into a tiny space.
Explanation:
According to NASA, this can happen when a star is dying.
A black hole has no more gravity than the same amount of matter in any other form.
But remember that the gravitational forces are stronger as you get closer to the center of the body. The mass of a black hole is packed into such a small size (theoretically zero !) that you can get very close to its center. THAT'S where its gravity is hugely strong.
If if two non zero vectors are acted on a body in what condition the resultant vector on the body will be zero ?
Answer:
Yes, when the 2 vectors are same in magnitude and direction. Yes, when the 2 vectors are same in magnitude but opposite in sense. Yes, when the 2 vectors are same in magnitude making an angle of 2π3 with each other.
Explanation:
Hope it helps you
The condition under which the resultant of two vectors will be zero is that the vectors must be in equilibrium.
The conditions under which the resultant of two non zero vectors acting on a body must be zero.
the two vectors must be in equilibriumthe two vectors are forces, then they must lie on the same plane and their line of action must pass through a common point.[tex]\bar R = \bar R_A + \bar R_B = 0[/tex]
Thus, the condition under which the resultant of two vectors will be zero is that the vectors must be in equilibrium.
Learn more here: https://brainly.com/question/17574217
Solar energy is a clean, renewable energy source. It is expensive to build a solar plant, but there is no fuel cost only maintenance. Why does solar energy not play a bigger role in energy production today?
Answer:
Energy production requires the setting up of a complete interconnected chain from generation of energy from the root source of the energy to the storage of the generated energy and the eventual utilization of the energy when required
Solar energy, indirectly, continues to be the main source of energy, however, the direct use of solar energy to power the systems we use in our everyday life, require the development of technologies, such as high efficiency solar cells, means of energy storage, and compatible efficient energy usage which are industrial areas that are seeing good progress but in which the current developed equipment are expensive to produce, and due to their efficiency, are undergoing further research and development
Therefore, due to the continuous increasing improvement in solar technology which can observed, the use of the produced energy through solar is evolving, and therefore, will continue to play a continuously increasing but lower role compared to other sources of energy which have been developed to satisfactory level that can drive an industry, considering the financial investment involved
Explanation:
State any ten reasons why students in Uganda need to study physics?use examples of the possible technological advancements which can be made using the knowledge of physics
Answer:
1.it also hleps us to became doctors becuase without physics you can't be a doctor
2.physics needs to be steady whether you like it or not it helps you in life so everybody must study physics no matter is in Uganda USA and plenty more countries there must be physics to dare to be studied
A uniform bridge span of weight 1200 kN and of
length 17.0 m rests on a support of width 1.0 m at
either end. A stationary lorry of weight 60 kN is the
only object on the bridge. Its centre of mass is 3.0m
from the centre of the bridge.
15.0 m
A body having uniform velocity has zero acceleration? give reason
Answer:
A body having uniform velocity has zero acceleration because
there is not change in velocity.
3.7 kg of a saturated water vapor at 0.4 MPa is isothermally cooled until it is a saturated liquid. Calculate the amount of heat rejected during this process in MJ. (Report your answer in 3 decimal places.)
Answer:
7.894 MJ
Explanation:
Given that:
The mass of the saturated water vapor = 3.7 kg
The pressure of the saturated water vapor = 0.4 MPa
From saturated properties of steam tables when the pressure is at 0.4 Mpa
The enthalpy in (kJ/kg);
hf = 604.7 kJ/kg
hg = 2738.1 kJ/kg
The rejected heat during this process is:
Q = m(hg - hf)
Q = 3.7(2738.1 - 604.7) kJ/kg
Q = 3.7(2133.4) kJ/kg
Q = 7893.58 kJ/kg
Q = 7.894 MJ
Angie walked a distance of 90 meters east in 70 seconds. What was her
velocity?
A. 0.78 m/s east
B. 1.3 m/s east
O C. 7 m/s east
D. 9 m/s east
A 15.0 cm object is 12.0 cm from a convex mirror that has a focal length of -6.0 cm. What is the height of the image produced by the mirror?
• -5.0 cm
• 7.5 cm
• -7.5 cm
• 5.0 cm
Answer:
5.0cm
Explanation:
To get the height of the image, we will use the magnification formula as shown:
m = Hi/H = v/u
Hi is the image height
H is the object height
v is the image distance
u is the object distance
First, we need to get the image distance v
Using the mirror formula;
1/f = 1/v+ 1/u
1/-6 = 1/v + 1/12
1/v = -1/12 - 1/6
1/v = -1-2/12
1/v = -3/12
v = 12/-3cm
v = -4cm
Next is to get the image height Hi
Using the expression;
Hi/H = v/u
Hi/15 = 4/12
Hi/15 = 1/3
3Hi = 15
Hi = 15/3
Hi = 5.0cm
Hence the image height is 5.0cm
Answer:
D. 5.0 cm
Explanation:
got it correct on the test
(b) The power rating of an electrical appliance at 750watt,calculate consumed for using the appliance for 1 hour.
Answer:
750 w : time = 1hour
Explanation:
750x1hour
=750 watt-hours
velocity of body in a circular path is variable why
Velocity is directly propertional to dusplacement.Displacement is the shortest dustance between any two points but in a circle dispalcement changes each time as direction is not constant.So, velocity of body in a circular path is variable......
How do you format short quotations in an MLA-style document?
Answer:
To indicate short quotations (four typed lines or fewer of prose or three lines of verse) in your text, enclose the quotation within double quotation marks.
Which does not affect the gravitational potential energy of an object? mass height speed acceleration due to gravity
Answer:
Speed
Explanation:
The answer is speed. It doesn’t affect potential energy because it’s associated with position. But since kinetic energy is associated with motion speed affects it.
15millas a km alguien pliss para ahorita porfa lo sigo
Answer:
X = 24.135 kilometres
Explanation:
Given the following data;
Distance = 15 miles
To convert the value in miles to kilometers;
Conversion:
1 mile = 1.609 kilometres
15 miles = X kilometres
Cross-multiplying, we have;
X = 1.609 * 15
X = 24.135 kilometres
When n resistance each of value x are connected parallel then resultant resistance x. When these n resistor connected in series. Total resistance
Answer:
Explanation:
Suppose you have 3 resistors each with a value of 3. If you placed them in parallel, would you get 3
1/3 + 1/3 + 1/3 = 1/r
The denominator doesn't change. So add the numerators.
(1 + 1 + 1)/3 = 3/3 = 1
So the question is faulty.
1 = 1/r
1*r = 1
r = 1/1
r = 1
how much would a 70 kg mean weight on the Moon what should be its mass on the earth and on the moon
Answer:
I don't know sorry' please
300 ml of a gas at 27°C is Cooled at -3°c at Constant pressure the final volume is plzz answer fast i will mark brainliest
Answer:V₁=300ml
T₁=27°C
V₂=?
T₂= -3°C
as we know
V₁T₁=V₂T₂
By putting values in formula
300ml×27°C=V₂×(-3°C)
300ml×27°C/-3°C=V₂
8100ml/-3=V₂
-2700ml=V₂
or V₂= -2700ml
why can't we measure temperature or build thermometer if there is no zeroth law? thanks
Explanation:
The Zeroth Law of Thermodynamics states that if two bodies are each in ... to heat, there will be no transfer of heat from one to the other.
Generators?
A)take motion and induce a current
B)take motion and produce a magnetic field
C)take a current produce spin
D)take a magnetic field and produce spin
Answer:
A)take motion and induce a current
Explanation:
i hope it will be helpful
Convert 1nanosecond in to its SI init
Convert 1nanosecond in to its SI init
In SI units, nano is 1000th part of micro which in turn is 1000th part of mini which in turn is 1000th part of main unit. Now, when you affix nano to any unit, here in case, second, it means that you are referring to 1000th part of 1000th part of 1000th part of second or in short, 1000000000th(10^9) part of a second.
In SI units, nano is 1000th part of micro which in turn is 1000th part of mini which in turn is 1000th part of main unit. Now, when you affix nano to any unit, here in case, second, it means that you are referring to 1000th part of 1000th part of 1000th part of second or in short, 1000000000th(10^9) part of a second.So to convert nanosecond into second, just multiply the nanosecond with 0.000000001 or (10^-9)
