Name the indicated geometric figures for the figure shown. Be sure to use correct notation
A Name a point.
B Name a ray through Y.
C Name a line through Z.
D Name a plane.

Answer:

y=-2/3x+3

Step-by-step explanation:

the equation of line J is y=3/2x-5

perpendicular slope would be -2/3

you want it at point (6, -1) so sub the points into y=-2/3x+b

-1=-2/3(6)+b

-1=-4+b

3=b

y=-2/3x+3

Answer:

The number is 6.

Step-by-step explanation:

[tex]4x-13=x+5\\3x-13=5\\3x=18\\x=6[/tex]

Answer:

12

Step-by-step explanation:

Since Emily eats four times the amount that Charlotte eats, then Emily will eat: = (4 × x) = 4x. Therefore, Charlotte eats 12 strawberries

Answer:

the unit rate is 4mi per minute.

Step-by-step explanation:

if you find the slope between point A and point B, you see that the line rises at 4 mi (distance) per minute (time). thus the unit rate is 4mi per minute. please correct me if I'm wrong, I hope this answer helps.

In mathematics, a limit is the value that a function (or sequence) approaches as the input (or index) approaches some value.

g(x) , one may look at how big f(x) and g(x) are. For example: If f(x) is close to some positive number and g(x) is close to 0 and positive, then the limit will be ∞. If f(x) is close to some positive number and g(x) is close to 0 and negative, then the limit will be −∞.

Answer:

There are 12 oxygens for 6 sulfur

Step-by-step explanation:

let George money will be X and Albert be Y

30$+x=y

x-50$=5y

30+x=y

x=y-30

(y-30)-50=5y

y-80=5y

y-5y=80

-4y=80

y=-20

x=-50

Answer:AlBERT=150; GEORGE=90

Albert-30=George+30....(.1)eq

A=(G+60)

#2 (G-50)5=A+50......(.2)eq

substitute result of #1 for A

5G-250=(G+60)+50

4G=360

G=90

substitute $90 into equation #1

A=90+60=150

Therefore Albert has $150, George has $90, and their total is $240

Answer:

5

Step-by-step explanation:

17 inches is equal to 39 inches and it's answer is 5

Cost of 17 inches of wire = 68 cents

Cost of 1 inch of wire

= 68 cents/17

= 4 cents

Cost of 39 inches of wire

= 4 cents × 39

= 156 cents

= $1.56

The two functions should never intersect.

Since y = y, we can equate the other side of both equations together.

x^2 + 2x + 1 = x^2 + 2x - 2

Rearrange the equation to bring all the terms to one side.

0 = x^2 - x^2 + 2x - 2x - 2 - 1

0 = -3

You can see that does not make sense, so we can conclude that there are no points of intersection between the two functions.

I also graphed the functions. In the first pic you can see that the red is between the blue and they don't intersect. In the second pic I zoomed in so you can see the right side of the graph going up to y = 600 and the red is still between the blue.

Answer:

(2,3)

Step-by-step explanation:

The graph of the given function is attached to the solution.

A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

Given is a function f(x) = 1/4(4)ˣ, we need to graph this,

Put x = 0

f(x) = 1/4

(0, 1/4)

Put x = 1

f(x) = 1

(1, 1)

Put x = 2

f(x) = 4

(2, 4)

Plot these points on a graph, the graph will be the graph of the function,

Since, the function is an exponential function therefore, we will get a curve.

Hence, the graph of the given function is attached to the solution.

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Answer:

2+2

Step-by-step explanation:

2 + 4!

3-5

3_4

3-6

2-5

2+5

2_3

2-5

Answer:

(A) 12x³ - 12x

(B) -288

(C) y = -288x - 673

(D) x = 0, 1, -1

Step-by-step explanation:

See images. If it's not clear let me know.

Answer:

13

5 - -8

When you subtract a negative number it changes to an addition so 5- -8 becomes 5 + 8 which equals 13.

Answer:

b

Step-by-step explanation:

sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{s\sqrt{3} }{2s}[/tex] ( cancel s on numerator/ denominator ), then

sinA = [tex]\frac{\sqrt{3} }{2}[/tex] → b

Answer:

yep it's D

Step-by-step explanation:

Answer:

Hello,

Step-by-step explanation:

[tex]A)\\g(x)=\dfrac{x-5}{-3} =\dfrac{-x}{3} +\dfrac{5}{3} \\\\(gog)(x)=g(g(x))=g(\dfrac{-x}{3} +\dfrac{5}{3})\\\\=\dfrac{\dfrac{-x}{3} +\dfrac{5}{3} }{3}+\dfrac{5}{3} \\\\\\=\dfrac{-x}{9} +\dfrac{5}{9} +\dfrac{5}{3}\\\\=-\dfrac{x}{9}+\dfrac{20}{9} \\\\\\(gog)(2)=-\dfrac{2}{9}+\dfrac{20}{9} =\dfrac{18}{9}=2 \\\\[/tex]

[tex]B)\\f(x)=y=-3x-5\\exchanging\ y\ and\ x\\x=-3y-5\\3y=-x-5\\\\y=\dfrac{-x}{3} -\dfrac{5}{3} \\\\f^{-1}(x)=\dfrac{-x}{3} -\dfrac{5}{3} \\\\[/tex]

[tex]C)\\\\(fog)(x)\ must\ be\ equal\ to\ x\\\\\\(fog)(x)=g(f(x))=g(-3x-5)\\\\=\dfrac{-(-3x-5)}{3} +\dfrac{5}{3} \\\\=x+\dfrac{5}{3} +\dfrac{5}{3} \\\\\\=x+\dfrac{10}{3}\ and\ not\ x\ !!!\\[/tex]

f(x) and g(x) are not inverse functions.

Answer:

y=-1/3x+7

Step-by-step explanation:

y=mx+c

m=-1/3, c=7

y=-1/3x+7

Answer:

1: Equal

2: Negation

3: Negation

4: Neither

Step-by-step explanation:

Sorry if I got any of them wrong

Answer:

m=-1 I think

Step-by-step explanation:

22

Step-by-step explanation:

For simplicity, let

x = teary smiley

y = tongue smiley

z = plain smiley

So now our system of equations is

[tex]x + x + x = 12\:\:\:\:\:\:(1)[/tex]

[tex]y + z + x = 18\:\:\:\:\:\:\:(2)[/tex]

[tex]z + z + y = 22\:\:\:\:\:\:\:(3)[/tex]

[tex]z + y + 2x= ??\:\:\:\:\:\:(4)[/tex]

From Eqn(1), we plainly see that

[tex]3x = 12 \Rightarrow x = 4[/tex]

Now subtract Eqn(2) from Eqn(3) to get

[tex](2z + y) - (y + z + x) = 22 - 18[/tex]

[tex]\Rightarrow z - x = 4[/tex]

But we know that [tex]x = 4[/tex], which then gives us [tex]z = 8.[/tex]

Using the values of [tex]x[/tex] and [tex]z[/tex] in Eqn(2), we find that [tex]y = 6.[/tex] Now that we the values of all the variables, use them in Eqn(3) and we'll get

[tex](8) + (6) + 2(4) = 22[/tex]

Step-by-step explanation:

132 = 100×1+3×10+2×1

480 = 100×4+8×10+0×1

302 = 100×3+0×10+2×1

I bet you meant "consecutive". If x is the smallest of the 5 numbers, then the other 4 are x + 1, x + 2, x + 3, and x + 4. If their mean is 11, then

(x + (x + 1) + (x + 2) + (x + 3) + (x + 4))/5

= (5x + 10)/5

= x + 2 = 11

==>   x = 9

Then the five numbers are {9, 10, 11, 12, 13}.

Alternatively, since we're talking about an odd number of consecutive integers, the mean among them will always be the number in the middle. So if 11 is the mean, and there are five numbers overall, then we just take the four closest integers to 11, two on either side.

Answer:

Answer is 5√6 ( none of the objectives )

Step-by-step explanation:

[tex] \sqrt{10} \times \sqrt{15} \\ = \sqrt{150} \\ = \sqrt{25 \times 6} \\ = \sqrt{25} \times \sqrt{6} \\ = 5 \times \sqrt{6} \\ = 5 \sqrt{6} [/tex]

Answer:

The equation of the line is y = -2/3x - 29/3

Step-by-step explanation:

The slope of these points (-7,-5) and (-1,-9) is m = -2/3

Once you plug that into the y = mx + b equation, you can see that the y-intercept is -29/3.

Put all of that into the y = mx + b equation and you'll get -->  y = -2/3x - 29/3

9514 1404 393

Answer:

  not

Step-by-step explanation:

The complement of set S is the set of elements in U and not in S.

_____

It's a definition.

Is this question complete?

66) ten less than a number

Let the number be n

= n - 10

67) the product of x and y

= x × y or xy

68) The algebraic expression for ten less than n

= n - 10

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A

(a) You're looking for

[tex]P(X\le 8) = \displaystyle \sum_{x=0}^8 P(X=x)[/tex]

where

[tex]P(X=x) = \begin{cases}\dfrac{\lambda^x e^{-\lambda}}{x!}&\text{if }x\in\{0,1,2,\ldots\}\\0&\text{otherwise}\end{cases}[/tex]

Customers arrive at a mean rate of 6 customers per 10 minutes, or equivalently 12 customers per 20 minutes, so

[tex]\lambda = \dfrac{12\,\rm customers}{20\,\rm min}\times(20\,\mathrm{min}) = 12\,\mathrm{customers}[/tex]

Then

[tex]\displaystyle P(X\le 8) = \sum_{x=0}^8 \frac{12^x e^{-12}}{x!} \approx \boxed{0.155}[/tex]

(b) Now you want

[tex]P(X\ge4) = 1 - P(X<4) = 1 - \displaystyle\sum_{x=0}^3 P(X=x)[/tex]

This time, we have

[tex]\lambda = \dfrac{6\,\rm customers}{10\,\rm min}\times(10\,\mathrm{min}) = 6\,\mathrm{customers}[/tex]

so that

[tex]P(X\ge4) = 1 - \displaystyle \sum_{x=0}^3 \frac{6^x e^{-6}}{x!} \approx \boxed{0.849}[/tex]

B

(a) In other words, you're asked to find the probability that more than 1 customer shows up in the same minute, or

[tex]P(X > 1) = 1 - P(X \le 1) = 1 - P(X=0) - P(X=1)[/tex]

with

[tex]\lambda = \dfrac{6\,\rm customers}{6\,\rm min}\times(1\,\mathrm{min}) = 1\,\mathrm{customer}[/tex]

So we have

[tex]P(X > 1) = 1 - \dfrac{1^0 e^{-1}}{0!} - \dfrac{1^1 e^{-1}}{1!} \approx \boxed{0.264}[/tex]

C

(a) Similar to B, you're looking for

[tex]P(X \le 1) = P(X=0) + P(X=1)[/tex]

with

[tex]\lambda = \dfrac{12\,\rm customers}{6\,\rm min}\times(1\,\mathrm{min}) = 2\,\mathrm{customers}[/tex]

so that

[tex]P(X\le1) = \dfrac{2^0e^{-2}}{0!} + \dfrac{2^1e^{-2}}{1!} \approx \boxed{0.406}[/tex]

Answer:

10%

Step-by-step explanation:

3/30 × 100 = 100

Therefore 3 is 10% of 30

3 is 10 percent of 30.

To determine what percent of 30 is 3, we can use the concept of finding a proportion or ratio.

The proportion can be set up as follows:

3 is what percent of 30?

Let x represent the unknown percentage.

Using the formula for finding the percentage, we can write:

x/100 = 3/30

To simplify the equation, we divide both sides by 3:

x/100 = 1/10

To isolate x, we multiply both sides by 100:

x = (1/10)100

Simplifying the expression, we have:

x = 10

Therefore, 3 is 10% of 30.

To understand this calculation, we can interpret it as follows: If we consider 30 as the whole or 100%, then 3 is a fraction of that whole. By dividing 3 by 30 and multiplying by 100, we find that 3 is equivalent to 10% of 30.

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