Answer:
Streamline the body of the rocket to reduce drag
Keep weight to a minimum
Use higher pressures
Use the right amount of water
an object with a mass of 7.5 kg accelerates 8.3 m/s2 when an unknown force is applied to it. what is the amount of the force?
Answer:
I believe the answer is 62.25 N
Explanation:
You just multiply 7.5 and 8.3 and you get 62.25
Answer:
62.25N or 62.25 newtons
Explanation:
F=ma where F is the force in newtons, m is the mass in kilograms (kg), and a is the acceleration
m=7.5kg
a=8.3m/s^2
Therefore, F=ma=7.5*8.3=62.25N
The amount of force is 62.25N or 62.25 newtons
A computational model predicts the maximum potential energy a roller coaster car can have given its mass and its speed at the lowest point of its journey. Its mass is 350 kg, and it speed at a height of 0 m is 25 m/s. What is the prediction for its maximum potential energy?
109,375 J
765,625 J
218,750 J
87,750 J
Answer:
The prediction for its maximum potential energy is 109,375 J
Explanation:
Given;
mass of the coaster car, m = 350 kg
speed of the coaster car at the lowest point, v = 25 m/s
The coaster car will have maximum kinetic energy at the lowest point and based on law of conservation of mechanical energy, the maximum kinetic energy of the coaster car at the lowest point will be equal to maximum potential energy at the highest point.
[tex]K.E_{max} = P.E_{max}[/tex]
[tex]K.E_{max} = \frac{1}{2} mv^2\\\\K.E_{max} = \frac{1}{2} (350)(25)^2\\\\K.E_{max} =109,375 \ J[/tex]
[tex]Thus, P.E_{max} = 109,375 \ J[/tex]
Therefore, the prediction for its maximum potential energy is 109,375 J
Check how you understand the principles of working of lenses. In some optical setup consisting of a single lens and an object magnification factor is measured as m-+4. We can conclude that:__________ a. Lens is converging, image is at the opposite side of lens from the object b. Lens is converging, image is the same side of lens as object c. Lens is diverging, image is at the opposite side of lens from the object d. Lens is diverging, image is the same side of lens as object
Answer:
b. Lens is converging, image is the same side of lens as object
Explanation:
A single converging lens is often used as a magnifying glass. The reason, behind its use as a magnifying glass is the configuration of the converging lens, when an object is placed inside its focal length. It forms the image of that object as magnified and at the same side as the object. So, the image is both magnified and erect. In this way, the converging lens serves as a magnifying glass with certain magnification factor, single handedly. The ray diagram of a magnifying glass is attached for reference. So, the correct option is:
b. Lens is converging, image is the same side of lens as object
Can power be negative in physics? I am doing a lab in which I run down the stairs as quickly as possible. They are 5.4m tall and my work is 5321.7 J. After calculating work, I got -5321.7 J. I am supposed to calculate my power used over 3 trials. The time for trial 1 was 4.69 and the seconds for trials 2 and 3 are 4.25. After calculating my power I got -1134.69 W and -1252.16 W. I am not sure if I got my power right. Is my power really negative or is my power positive?
Answer:
Yes.
Explanation:
A negative power would just represent a loss of power. So in your case it lost -1252.16 W
A car with a mass of 1.5 × 103 kilograms is traveling west at a velocity of 22 meters/second. It hits a stationary car with a mass of 9.0 × 102 kilograms. If the collision is inelastic, what is the final direction and approximate velocity of the two cars?
Answer:
A. 14 meters/second to the west
Explanation:
The collision is inelastic, which means that:
- only the total momentum is conserved (not the kinetic energy)
Answer:
14 meters/second to the west
Explanation:
That's the answer!
Problem (8):
A projectile is fired at an angle of 53° above the horizontal with initial speed of 10.0 m/s. After
one second, what is X and Y components of the position of that projectile?
A60m 20 m
B. 6.0 m. 8.0 m
C. 3.0 m, 6.0 m
D.4.0 m, 3.0 m
Answer:
x=6 m, y= 3 m
Explanation:
Projectile Motion
It's the type of motion that experiences an object launched near the Earth's surface and moves along a curved path under the action of gravity.
Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the components of the velocity at a given time t are:
[tex]v_x=v_o\cos\theta[/tex]
[tex]v_y=v_o\sin\theta-g.t[/tex]
And the components of the displacement are:
[tex]x=v_o\cos\theta .t[/tex]
[tex]\displaystyle y=v_o\sin\theta.t-\frac{g.t^2}{2}[/tex]
The projectile of the problem is fired at θ=53° with an initial speed of vo=10 m/s.
Thus, after 1 second, the components of the displacement are:
[tex]x=10\cos 53^\circ \cdot 1[/tex]
[tex]x\approx 6~m[/tex]
[tex]\displaystyle y=10\sin 53^\circ\cdot 1-\frac{9.8\cdot 1^2}{2}[/tex]
[tex]y\approx3~m[/tex]
Answer: x=6 m, y= 3 m
None of the options match this answer.
A train slows from 44 m/s to 19 m/s in 9 seconds. What is the train's acceleration? Show your work.
Answer:
a = 2.77 [m/s²]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f} =v_{o} -a*t[/tex]
where:
Vf = final velocity = 19 [m/s]
Vo = initial velocity = 44 [m/s]
a = acceleration [m/s²]
t = time = 9 [s]
Note: The negative sign in the above equation means that the train is decreasing its velocity.
19 = 44 - a*9
9*a = 44 -19
a = 2.77 [m/s²]
On an alien planet, a simple pendulum of length 0.300 m has oscillation frequency 0.709 Hz. Find the period of the pendulum. Find the acceleration due to gravity on this planet's surface. What must be the length of a simple pendulum if its oscillation frequency is to be equal to that of an air-track glider of mass 0.450 kg attached to a spring of force constant 9.75 N/m?
Answer:
1.41s
5.95m/s
0.2746m
Explanation:
The time period
T = 1/f
= 1/0.709s
= 1.41 seconds
We have
T = 2π√l/g
T² = 4π²l/g
g = 4π²l/T²
g = 4x3.14²x0.300/1.41²
g = 5.95m/s² this is the acceleration due to gravity.
Then the time period of the glide
T2 = 2π√m/k
Length of pendulum = l
Time period T
T2 = 2π√l/g
Then T1 = T2
2π√m/k = 2π√l/g
M/k = l/g
L = g.m/k
L = 5.95x0.450/9.75
L = 0.2746
This must be the length of the simple pendulum
what is the mass of an object with a density of 74 g/mL and a volume of 7 mL?
Answer:
518 gExplanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volume
From the question we have
mass = 74 × 7
We have the final answer as
518 gHope this helps you
Two car's are racing! The winner of the race will always be be the vehicle with the greater...
An unknown mass is hung from a very light spring with a spring constant of 13.6 N/m. Neglect the mass of the spring. If the period of oscillation of the mass-spring system is 3.35 s, then the unknown mass is:__________
Answer:
The unknown mass is 3.87 kg.
Explanation:
Given;
spring constant of the spring, k = 13.6 N/m
period of oscillation, T = 3.35 s
The period of oscillation of the mass-spring system is given by;
[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]
where;
m is the mass attached to the spring
[tex]T = 2\pi \sqrt{\frac{m}{k} }\\\\\frac{T}{2\pi} = \sqrt{\frac{m}{k} }\\\\\frac{T^2}{4\pi^2}= \frac{m}{k}\\\\m = \frac{kT^2}{4\pi^2}\\\\m = \frac{(13.6)(3.35)^2}{4\pi^2}\\\\m = 3.87 \ kg[/tex]
Therefore, the unknown mass is 3.87 kg.
What happens in a convection current?
Answer:
Convection currents are the result of differential heating. Lighter (less dense), warm material rises while heavier (more dense) cool material sinks. It is this movement that creates circulation patterns known as convection currents in the atmosphere, in water, and in the mantle of Earth.
Explanation:
An airplane takes off northwest from Dallas to Amarillo. This is an example of-
a. Speed
b. Velocity
c. Acceleration
Answer:
the answers is C. acceleration
A nail driven into a board increases in temperature.
If 59.0 % of the kinetic energy delivered by a 1.60 kg hammer with a speed of 7.70 m/s is transformed into heat that flows into the nail and does not flow out, what is the increase in temperature of an 7.60 g aluminum nail after it is struck 10 times?
Answer:
ΔT = 40.91 °C
Explanation:
First we find the kinetic energy of one hit to the nail:
K.E = (1/2)mv²
where,
K.E = Kinetic energy = ?
m = mass of hammer = 1.6 kg
v = speed of hammer = 7.7 m/s
Therefore,
K.E = (1/2)(1.6 kg)(7.7 m/s)²
K.E = 47.432 J
Now, for 10 hits:
K.E = (10)(47.432 J)
K.E = 474.32 J
Now, we calculate the heat energy transferred (Q) to the nail. As, it is the 59% of K.E. Therefore,
Q = (0.59)K.E
Q = (0.59)(474.32 J)
Q = 279.84 J
The change in energy of nail is given as:
Q = mCΔT
where,
m = mass of nail = 7.6 g = 0.0076 kg
C = specific heat capacity of aluminum = 900 J/kg.°C
ΔT = Increase in temperature = ?
Therefore,
279.84 J = (0.0076 kg)(900 J/kg.°C)ΔT
ΔT = (279.84 J)/(6.84 J/°C)
ΔT = 40.91 °C
As you take the stoppered part of the tube up the staircase you begin to see the water level drop around the 4th floor. As you continue up it does not continue up with you but stays at a constant level. What does that mean?
a. The pressure in the tubing is equal to the barometric pressure.
b. The tubing was unable to supply any more water to the tube for use.
c. The pressure outside the tube is higher that the water pressure inside the tube.
Answer:
a. The pressure in the tubing is equal to the barometric pressure.
Explanation:
Since in the question it is mentioned that the if you take the stoppert part of the tube than the level of warer would be fall approx 4th floor and if it is continued than it wont be continue but remains constant.
Now here first we do that the tube i.e. connected to the bucket should be taken up. In the first instance, the bucket supplies the water to the tube but it would not increased far away to the level of the barometric pressure
Hence, the correct option is a.
A segment of wire of total length 3.0 m carries a 15-A current and is formed into a semicircle. Determine the magnitude of the magnetic field at the center of the circle along which the wire is placed. a. 1.6 mu T b. 4.9 mu T c. 1.0 mu T d. 9.8 mu T e. 15 mu T
Answer:
c. 1.0 mu T
Explanation:
From, the ampere's circuit law:
∫B.dl = μ₀ I
B.(2πr) = μ₀ I
where,
B = Magnetic Field = ?
r = radius of the circle = length of wire = 3 m
μ₀ = Permeability of free space = 4π x 10⁻⁷ Tm/A
I = Current = 15 A
Therefore,
B(2π)(3 m) = (4π x 10⁻⁷ Tm/A)(15 A)
B = 10 x 10⁻⁷ T
B = 1 x 10⁻⁶ T = 1 μT
Hence, the correct option is:
c. 1.0 mu T
A sphere has a mass of 8.5 kg and a radius of 10cm. How much work is it necessary to do on the ball to get it to a speed of 6.0m/s?
Answer:
153JExplanation:
Step one:
given data
mass m= 8.5kg
radius r= 10cm in meters = 0.01m
velocity v= 6m/s
The work done will be the same as the energy possessed by the sphere at such speed
Required
the work one in Joules
we know that
KE=1/2mv^2
KE=1/2*8.5*6^2
KE= 1/2*8.5*36
KE=306/2
KE=153J
A ball rolls to the right across a grassy field slowing down as it does so. Which of the following must be true?
Answer: i could prolly answer if it made more sense. which of the following where?
Answer:
D: the ball is not accelerating because it is slowing down
Explanation:
if the was no friction, then the ball would most likely pick up speed and never stop, like it would with it being on a hill covered in ice, it would pick up speed and never slow down (well, it would slow down, just at a point where it looks like it would never stop.
A wire 50.0 m long and 2.00 mm in diameter is connected to a source with a potential difference of 9.11 V, and the current is found to be 36.0 A. Find the resistivity of the material.
Answer:
ρ = 1.6*10⁻⁸ Ω/m.
Explanation:
Applying Ohm's Law to the wire, assuming that it can be treated as a pure resistance, the resistance of the wire can be obtained as follows:[tex]R = \frac{V}{I} = \frac{9.11V}{36.0A} = 0.253 \Omega (1)[/tex]
At the same time, we know that there exists a relationship between the resistance, the resistivity ρ, the length L and the area A of the wire, that is given for the following expression:[tex]R = \rho* \frac{L}{A} (2)[/tex]
The area of the circular section of the wire, can be expressed as a function of the diameter d, as follows:[tex]A = \frac{\pi*d^{2} }{4} = \frac{\pi*(0.002m)^{2}}{4} = \pi*10e-6 (3)[/tex]
Replacing the left side of (2) by (1), and (3) on the right side, we can solve for the resistivity ρ as follows:[tex]\rho = \frac{R*A}{L} = \frac{0.253\Omega*\pi*10e-6}{50.0m} = 1.6e-8 \Omega/m[/tex]
ρ = 1.6*10⁻⁸ Ω/mNicki rides her bike at a constant speed for 6 km. That part of her ride takes her 1 h. She then rides her bike at a constant speed for another 9
km. That part of her trip takes her 2 h. What is her average speed?
Answer:
24km/h
Explanation:
go it right on ingenuity 2020
A projectile is fired horizontally off the top of a cliff with an initial velocity of 30 m/s. It hits the ground 2.0 seconds later. What is the height of the cliff?
Answer:no
Explanation:
30.6*X+-2.56
Pls help
Answer: 10.16
Explanation:
8.
'A 6.00 kg ball, A, moving at velocity 3.00 m/s due east collides with a 6.00 kg ball, B, at rest.
After the collision, A moves off at 40.0°N of E and ball B moves off at 50.0° S of E
please help me.
Answer:
brrrrrakabrrrrrrrrra
Explanation:
A student walks 300 meters due east and then 100 meters due north,
then 500 meters due west. The total distance travelled by the student
-
is
meters.
Answer:
900 meter hhgffhffhhfcbjhggjdswexaazcgh
Answer:
900 meters
Explanation:
If you are talking about how many meters student walked then its 900 metes
But if you are talking about how many meters student travelled from the start point then its 200 meter
In the picture below, sphere X swings down and collides with sphere Y. Identify the action and reaction forces.
Action force:
Reaction force:
Answer:
Action force is force acting in one direction. Reaction force is force acting in the opposite direction.
Does lighting striking the earth considered the speed of light?
Answer:
i would tell you but im a hobbit
Explanation:
biden 2020
What would the distance be if a bicyclist traveled 4.5 hours at a speed of 20.0km/h?
A group of big city tenants were upset about rising rent for their apartments, and decided to play a prank on the Building Manager. They went up to the top floor of the
building, which was 176.4 m above the sidewalk, and waited. They wanted to drop the balloon at just the right time, so they needed to make a quick calculation. How many
seconds before the Building Manager walks to the spot should they drop the balloon?
Answer:
t = 6 s
Explanation:
This is a free fall exercise
y = y₀ + v₀ t - ½ g t²
If the balloon is released its initial velocity is zero, when it reaches the floor its height is also zero, we substitute
0 = y₀ + 0 - ½ g t2
t = √(2yo / g)
let's calculate
t = √ (2 176.4 / 9.8)
t = 6 s
the balloon must be released 6 s before the person reaches the building
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Comentarios
In the flowchart representation of the scientific method (the one that embraces the use of constructing models), what does one do immediately after making observations?
Answer:
The correct answer is - ask a question based on observation and then postulate a hypothesis.
Explanation:
The scientific method is the step by step process to find an answer to any scientific question with the help of scientific investigation or experiment. The steps that make an investigation successful are should be in the correct order. These steps are as follows:
*Make an Observation
*Ask a Question
*Do Background Research
*Form a Hypothesis
*Conduct an Experiment
*Analyze Results and Draw a Conclusion
*Report Your Results
The mass of an empty flask is 49.74 g. Filled with 120 cm 3 of acetone, the mass of the flask is found to be 144.78 g. What is the density of acetone?
Answer:
0.79g/cm³
Explanation:
Given parameters:
Volume of acetone = 120cm³
Mass of empty flask = 49.74g
Mass of flask + acetone = 144.78g
Unknown:
Density of acetone = ?
Solution:
Density is the mass per given volume of a substance. It is mathematically expressed as;
Density = [tex]\frac{mass}{volume}[/tex]
Mass of acetone =( mass of flask + acetone) - mass of empty flask
Mass of acetone = 144.78 - 49.74 = 95.04g
Now insert the parameters and solve;
Density = [tex]\frac{95.04}{120}[/tex] = 0.79g/cm³
