For a line that contains the point (3, 4) and has a slope of 4, please name another point on this line. Show the work you did to find this answer.

Answer:

This is a 4th degree polynomial!

Step-by-step explanation:

Because the polynomial starts of the a number with a 4th degree and decreases down with lower numbers. Simply put, because (x^4) has the largest degree.

Hope this helps, good luck! :)

Answer:

x = 14.5/a

Step-by-step explanation:

ax – 2 = 12.5

Add 2 to each side

ax – 2+2 = 12.5+2

ax = 14.5

Divide by a

ax/a = 14.5/a

x = 14.5/a

Answer:

6

Step-by-step explanation:

4n - 12 < 2n + 2 is for n=6

4×6 -12 < 2×6 +2

24 - 12 < 12 + 2

12 < 14 correct

for n=7

4×7 - 12 < 2×7 + 2

16 < 16 incorrect

for n=8

4×8 - 12 < 2×8 + 2

20 < 18 incorrect

for n=9

4×9 - 12 < 2×9 + 2

24 < 20 incorrect

so, only for n=6 is the expression true.

Answer:

6

Step-by-step explanation:

4n - 12 < 2n + 2 is for n=6

4×6 -12 < 2×6 +2

24 - 12 < 12 + 2

12 < 14 correct

for n=7

4×7 - 12 < 2×7 + 2

16 < 16 incorrect

for n=8

4×8 - 12 < 2×8 + 2

20 < 18 incorrect

for n=9

4×9 - 12 < 2×9 + 2

24 < 20 incorrect

so, only for n=6 is the expression true.Step-by-step explanation:

Answer:

15

Step-by-step explanation:

first find f which is (8-3) × ( 1/4 × 7 + 5)

simplify

5 × (1/4 ×12)

5 × 3

15 is thw answer

Answer:

Step-by-step explanation:

Equation of a parabola with vertex (h, k) is given by,

y - k = a(x - h)²

Equation of a function 'f' with vertex (0, 3) will be,

y - 3 = a(x - 0)²

y - 3 = ax²

Since, graph of this function passes through (1, 4),

4 - 3 = a(1)²

a = 1

Therefore, equation will be,

y - 3 = (x - 0)²

f(x) = x² + 3

Equation of function 'g' with vertex at (0, -3) will be,

y - (-3) = a(x - 0)²

y + 3 = ax²

y = ax² - 3

Since, the graph passes through (1, -1),

-1 = a(1)² - 3

a = 2

Therefore, equation will be,

y = 2x²- 3

g(x) = 2x² - 3

Equation of the function 'j' with the vertex (0, -3) will be,

y - (-3) = a(x - 0)²

y + 3 = ax²

y = ax²- 3

Since, the graph of the function passes through (1, -5),

-5 = a(1)² - 3

a = -2

Therefore, function 'j' will be,

j(x) = -2x² - 3

Equation of the function 'h' with the vertex (0, -3) will be,

y - (-3) = a(x - 0)²

y + 3 = ax²

y = ax² - 3

Since, the graph of the function passes through (2, 1)

1 + 3 = a(2)²

4 = 4a

a = 1

Therefore, equation of the function 'h' will be,

h(x) = x² - 3

Answer:

Step-by-step explanation:

This is a geometric means problem. Namely, n is the geometric mean between the 2 smaller triangles within that larger one. Set up the problem accordingly:

[tex]\frac{28}{n}=\frac{n}{7}[/tex] and cross multiply:

[tex]n^2=196[/tex] so

n = 14

Answer:

It is 36

Step-by-step explanation:

Hopefully this help

             Have a good day bye

Answer:

Step-by-step explanation:

Volume of a cone formula is

[tex]V=\frac{1}{3}\pi r^2h[/tex] where r is radius and h is height. Filling in:

[tex]V=\frac{1}{3}(3.14)(10)^2(7)[/tex] and doing all the math on that and rounding gives us

V = 733 units cubed

Answer:

Step-by-step explanation:

150% = 150 ÷ 100 150% = 1.5

Answer:

hello,

answer A c=n+2

Step-by-step explanation:

if n=0 then c=2

if n=2 then c=4

slope=m=(4-2)/(2-0) =2/2=1

c-2=1*(n-0)

c=n+2

Answer:

the answer is

tan (B)=p/b

=5/12

Answer: C)5/12

Step-by-step explanation:

Answer:

4, yes through the middle    5, yes through the middle 6, yes through the middle  all of them reflect from the center

Step-by-step explanation:

Answer:

The range is the difference of the greatest and smallest numbers:

Semi-interquartile of the range is:

Since Q1 = 15, find Q3:

Note. Probably the numbers mixed up in the question.

If we swap them:

Given data:

The mean:

Variance, the average of the squared differences from the mean:

Answer:

please i need educere answers

Step-by-step explanation:

i have one day left and i cannot finish please reply with any way to contact you

Answer:

y^7

Step-by-step explanation:

We know that a^b / a^c = a^( b-c)

y^9/y^2

y^(9-2)

y^7

Answer:

Step-by-step explanation:

The rule for division when the bases are like is to subtract the exponents:

[tex]\frac{y^9}{y^2}=y^{9-2}=y^7[/tex]

Answer: tan A=4/3

Step-by-step explanation:

Theo đề ta có: 5sinA=4 suy ra: sinA=4/5, mà ta đã biết là: sinA= cạnh đối/cạnh huyền, suy ra: cạnh đối của góc A =4, cạnh huyền =5

Áp dụng định lí py ta go ta đc:

5^2=4^2+x^2

=) x=3

Vậy cạnh kề của góc A=3

Mà tanA = cạnh đối/cạnh kề

Vậy giá trị của tanA=4/3

(bạn vẽ hình ra thì có thể nhìn rõ hơn đấy, cảm ơn bạn đã tham khảo câu trả lời của mik)

Answer:

Option (C)

Step-by-step explanation:

System of the equations have been given as,

[tex]y=x+1[/tex] --------(1)

[tex]y=-\frac{1}{2}x+4[/tex] -------(2)

Substitute the value of y from equation (1) to equation (2),

[tex]x+1=-\frac{1}{2}x+4[/tex]

[tex]x+1=-\frac{1}{2}x+4[/tex]

[tex]x+\frac{1}{2}x=4-1[/tex]

[tex]\frac{3}{2}x=3[/tex]

[tex]x=2[/tex]

Substitute the value of 'x' in equation (1),

[tex]y=2+1[/tex]

[tex]y=3[/tex]

By using a graphing utility, graph of the equations that will intersect each other at a point (2, 3).

Therefore, solution of the system of equations will be [tex](2,3)[/tex].

Option (C) will be the answer.

Answer:

(2,3) C

Step-by-step explanation:

Solve using y = mx + b and graph!

Answer:

Step-by-step explanation:

RHS = (1 +Sec Ф)(1 - Cos Ф)

       = 1*1 -  1*Cos Ф + Sec Ф *1 - Sec Ф *Cos Ф

      = 1 - Cos Ф + Sec Ф - 1              {Sec Ф = [tex]\frac{1}{Cos \ theta}[/tex] )

       =Sec Ф - Cos Ф

       = [tex]\frac{1}{Cos \ theta}[/tex] - Cos Ф

       [tex]= \frac{1}{Cos \ theta}-\frac{Cos \ theta*Cos \ theta}{Cos \ theta}\\\\= \frac{1-Cos^{2} \ theta}{Cos \ theta}\\\\= \frac{Sin^{2} \ theta}{Cos \ theta}\\\\=\frac{Sin \ theta*Sin \ theta}{Cos \ theta}\\\\= Sin \ theta*\frac{Sin \ theta}{Cos \ theta}[/tex]

        = Sin  Ф* tan  Ф = LHS

Answer:

C. 5.2 in.

Step-by-step explanation:

Answer:

2xy^2

Step-by-step explanation:

8/4=2

x^3/x^2=x

y^5/y^3=y^2

Answer:

2xy^2

Step-by-step explanation:

First, 8/4 is 2.

2x^3y^5 / 4x^2y^3

Then, we can bring the x^2 up. It becomes the -x^2. Combined with the x^3, we have x. Finally, we can bring the y^3 up, where it becomes -y^3. Combined with the y^5, we get y^2.

Our final answer is 2xy^2.

Answer:

554,000

Step-by-step explanation:

that is the answer

Emma earns $554,064.80  in total in the first 11 years of her career

We are to determine the future value of $39,000 each year for 11 years given the growth rate of 5%

The formula for calculating future value:

FV = P (1 + r)^n

Where :

FV = Future value  

P = Present value  

R = interest rate  

N = number of years

First year =  $39,000

Second year = 39,000 x (1.05) = $40,950

Third year = 39,000 x (1.05)^2 = $42,997.50

Fourth year = 39,000 x (1.05)^3 = $45,147.38

Fifth year = 39,000 x (1.05)^4 = $47,404.75

Sixth year = 39,000 x (1.05)^5 = $49,774.99

seventh year = 39,000 x (1.05)^6 = $52,263.74

eighth year = 39,000 x (1.05)^7 = $54,876.93

ninth year = 39,000 x (1.05)^8 = $57,620.78

tenth year = 39,000 x (1.05)^9 = $60,501.82

eleventh year = 39,000 x (1.05)^10 = $63,526.91

Sum of the earnings for the first eleven years = $554,064.80

To learn more about the future value of income, please check : https://brainly.com/question/19407218?referrer=searchResults

Answer:

There is an asymptote at x = 0

There is an asymptote at y = 23

Step-by-step explanation:

Given the function:

(23x+14)/x

Vertical asymptote is gotten by equating the denominator to zero

Since the denominator is x, hence the vertical asymptote is at x = 0. This shows that there is an asymptote at x = 0

Also for the horizontal asymptote, we will take the ratio of the coefficient of the variables in the numerator and denominator

Coefficient of  x at the numerator = 23

Coefficient of x at the denominator = 1

Ratio = 23/1 = 23

This means that there is an asymptote at y = 23

Answer:

1/27

Step-by-step explanation:

The outcomes when rolling a die are 1,2,3,4,5,6

getting less than 3 = 1,2

P( less than 3) = outcomes of less than 3 / total

                        = 2/6 = 1/3

Since the events are independent we can multiply the probabilities

P( less than 3, less than 3, less than 3) = 1/3 * 1/3*1/3 = 1/27

Answer:

The profit or loss combined is $2.99

Step-by-step explanation:

Given;

cost price of first radio, CP = $25.50

profit percent, = 8%

The profit made is calculated as;

[tex]\frac{Profit}{CP} \times 100\% = \frac{SP-CP}{CP} \times 100\% = 8\%\\\\Profit = SP-CP = 0.08CP = 0.08\times \$25.50 = \$ 2.04[/tex]

Cost price of the second radio, CP = $6.30

loss percent = 15%

The loss incurred is calculated as;

[tex]\frac{Loss}{CP} \times 100\% = 15\%\\\\Loss = 0.15CP\\\\Loss = 0.15 \times \$6.30 = \$0.95[/tex]

The profit or loss combined = $2.04 + $0.95

                                               = $2.99

Answer:

total pages = 20

Step-by-step explanation:

60% of an unknown number is 12

Let the unknown number (total pages) be x.

60/100 of x = 12

60/100 * x = 12

3/5 x = 12

x = 12 * 5/3

x = 20

Answer:

[tex] {2}^{1 \div 2[/tex]

Answer:

[tex]\begin{array}{ccl}Year&&End \ of \ year \ balance\\1&&\$4,483.18\\2&& \$3,088.68\\3&&\$1,596.57\\4&&0\end{array}[/tex]

Step-by-step explanation:

The initial amount invested, P = $1,600

Danny's age at which the amount, A, is to be used for his college, t = 19 years

The number of equal annual payments, m, to be withdrawn from the amount = 4

The compound interest on the account, r = 7% = 0.07

Let, A, represent the amount at the year the annual withdrawals starts to be made, we have;

[tex]A = P \times \left(1+\dfrac{r}{n} \right)^{n \times t}[/tex]

n = The number of times the interest is applied annually = 1

Therefore;

[tex]A = 1,600 \times \left(1+\dfrac{0.07}{1} \right)^{1 \times 19} \approx 5,786.444[/tex]

The amount, m, is withdrawn at start of Danny's first year in college to give the amount in the account = A - m

The amount in the account at the end of the first year with compound interest, r = (A - m)×(1 + r)¹ = (A - m)×(1 + r)

At the stat of the second year, the second withdrawal is made to give the starting amount = (A - m)×(1 + r) - m

The amount in the account at the end of the second year = ((A - m)×(1 + r) - m)×(1 + r)

At the start of the third year, the amount in the account =  ((A - m)×(1 + r) - m)×(1 + r) - m

At the end of the third year, we have the amount in the account  = (((A - m)×(1 + r) - m)×(1 + r) - m) × (1 + r)

At the start of the forth year, the last yearly installment is withdrawn from the account and we have 0 balance in the account.

Therefore, on the fourth year, we have the amount in the account = (((A - m)×(1 + r) - m)×(1 + r) - m) × (1 + r) - m = 0

(A - m)×(1 + r)³ - m×(1 + r)² - m × (1 + r) - m = 0

A×(1 + r)³ - m×(1 + r)³ - m×(1 + r)² - m × (1 + r) - m = 0

A×(1 + r)³ = m×(1 + r)³ + m×(1 + r)² + m×(1 + r) + m = m × ((1 + r)³ + (1 + r)² + (1 + r) + 1)

A×(1 + r)³ = m × ((1 + r)³ + (1 + r)² + (1 + r) + 1)

m = A×(1 + r)³/((1 + r)³ + (1 + r)² + (1 + r) + 1)

∴ m = 5,786.444×(1 + 0.07)³/((1 + 0.07)³ + (1 + 0.07)² + (1 + 0.07) + 1) ≈ 1,596.56

The amount withdrawn annually, m ≈ $1,596.56

The amount in the account at the end of the each year is given as follows;

First year = (A - m)×(1 + r) = (5,786.444 - 1,596.56)×(1 + 0.07) ≈ 4,483.17588

Second year = ((A - m)×(1 + r) - m)×(1 + r) = ((5,786.444 - 1,596.56)×(1 + 0.07) - 1,596.56)×(1 + 0.07) = 3,088.68

Third year = (((A - m)×(1 + r) - m)×(1 + r) - m) × (1 + r) = (((5,786.444 - 1,596.56)×(1 + 0.07) - 1,596.56)×(1 + 0.07) - 1,596.56) × (1 + 0.07) = 1,596.57

At the end of the first year, we have $4,483.17588

At the end of the second year, we have $3,088.68

At the end of the third year, we have $1,596.57

At the end of the fourth year, we have 0

Step-by-step explanation:

where is the steps to this question you can't answer it without a question too it SMH

the probability is made of the desired outcome divided by the total outcome.

desired = wins = 8

total = wins and losses = 15

8/15 is the probability (approx. 53%)

hope it helps :)

Answer:

u=1

v = 10

Step-by-step explanation:

For the triangles to be congruent

IG = PR

50 = u+49

50 - 49 = u

1 = u

GH = RQ

v+6 = 16

v = 16-6

v = 10