Finance A bicycle shop hires road bikes for £25 per day and tandems for £40 per day. One day a family pays £155.
a Which type of bicycles did they hire?
b How many people are in the family?

Answer:

Step-by-step explanation:

[tex]sin^3xcosx+sinxcos^3x\\=sinx cosx(sin^2x+cos^2x)\\=sinx ~cosx(1)\\=sin~x~cos~x[/tex]

Answer:

A={x| x>7} = 8,9

B= {5,6}

1,

2,{5,6,8,9}

3,{}

4{}

Answer:

Step-by-step explanation:

One - 44

88% of 50 is 44

Two - 55296 60,000-4%-4%=55296

Answer:

4w = 40

Step-by-step explanation:

Using the addition property of equality to add 8 on both sides gives us the answer to what 4w equals.

[tex]4w - 8 + 8 = 32 + 8\\4w=40[/tex]

Answer:

Range = maximum number - minimum number

Range = 99 - 62 = 37

Answer:

37

Step-by-step explanation:

The range is the difference between the highest number and the smallest number.

Looking at the stem and leaf plot we can identify the largest and smallest number

Largest number: 99

Smallest number: 62

If range = largest number - smallest number then range = 99 - 62 = 37

Answer:

3p+2p+8-3=15

5p+5=15

5p=15-5

5p=10

p=10/5

p=2

have a great dayy.

Answer:

p = 2

Step-by-step explanation:

One is given the following equation:

3p + 2p + 8 - 3 = 15

Combine like terms. In essence, if two number have the same variable, then one can perform operations between their coefficients. If two number have no variables, then these two terms are also like terms. After combing like terms, simplify the expression.

3p + 2p + 8 - 3 = 15

5p + 8 - 3 = 15

5p + 5 = 15

Inverse operations,

5p + 5 = 15

5p = 10

p = 2

Answer:

Step-by-step explanation:

Let the amount of gas in the tank before filling was x.

We have:

let the amount of gas be x

[tex]\\ \sf\longmapsto x+2\dfrac{4}{7}=4[/tex]

[tex]\\ \sf\longmapsto x+\dfrac{18}{7}=4[/tex]

[tex]\\ \sf\longmapsto x=4-\dfrac{18}{7}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{28-18}{7}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{10}{7}[/tex]

[tex]\\ \sf\longmapsto x=1\dfrac{3}{7}[/tex]

The coordinates of the resulting image will be at (1, 1), (3, 4) and (1, 2)

Assuming the coordinate of the triangle ABC is A(4, 4), (12, 16) and (-4, -8).

If the coordinate is dilated by a factor of 1/4, the resulting coordinates will be at:

Hence the coordinates of the resulting image will be at (1, 1), (3, 4) and (1, 2)

Learn more on dilation here: https://brainly.com/question/10253650

Answer:

The slope is -3/4 and the y intercept is 5

Step-by-step explanation:

- 3x - 4y= -20

Slope intercept form is

y = mx+b where m is the slope and b is the y intercept

Solve for y

Add 3x to each side

- 3x - 4y+3x=3x -20

-4y = 3x-20

Divide by -4

-4y/-4 = 3x/-4  -20/-4

y = -3/4 x+5

The slope is -3/4 and the y intercept is 5

Answer:

Slope: [tex]\displaystyle-\frac{3}{4}[/tex]

Y-intercept: 5

Step-by-step explanation:

Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex], where m is the slope and b is the y-intercept.

[tex]-3x-4y=-20[/tex]

To find the slope and y-intercept of the given line, rearrange the equation into slope-intercept form. We can do this by isolating y.

Add 3x to both sides:

[tex]-3x-4y+3x=-20+3x\\-4y=3x-20[/tex]

Divide both sides by -4:

[tex]y=\displaystyle -\frac{3}{4} x+5[/tex]

Now, we can identify [tex]\displaystyle-\frac{3}{4}[/tex] to be in place of m, the slope, and 5 to be in place of b, the y-intercept. Here is a comparison:

[tex]y=\displaystyle -\frac{3}{4} x+5[/tex]

[tex]y=mx+b[/tex]

I hope this helps!

Answer:

207.35yd²

Step-by-step explanation:

Answer:

13

Step-by-step explanation:

[2×1+6×4]÷2

[2+24]÷2

26÷2

13

Answer:

here we can go for two solution

Answer:

12 ft

Step-by-step explanation:

l = 2w

P = 2(l+w)

36 = 2(2w+w)

36 = 2(3w)

36 = 6w

Divide each side by 6

36/6 = 6w/6

6 =w

l = 2w

l = 2(6)

l = 12

Answer:

11 m

Step-by-step explanation:

The area of a square is given by

A = s^2 where s is the side length

121 = s^2

Take the square root of each side

sqrt(121) = sqrt(s^2)

11 = s

Answer:

Consider the reflection of the parallelogram PQRS across the line of reflection wy if RR = 14 Then RZ= If SX=5 then = 5

Step-by-step explanation:

Answer:

So if x= 1 , y= -20 , z = -5 , we just have to replace those values on the equation

[tex]\frac{\sqrt{yz}}{(z-x)^{2} + y } =[/tex]  [tex]\frac{\sqrt{(-20) * (-5)}}{(-5-1)^{2} + (-20) } =[/tex]  [tex]\frac{\sqrt{100}}{(-6)^{2} -20 }[/tex]  [tex]= \frac{10}{16} =\frac{5}{8}[/tex]

Answer:

Answer:

-3 + 5 + 6 g = 11 - 3 g - 3 + 5 + 6 g = 11 - 3 g

6 g + 2 = 3 g + 13 = 11 - 3 g

{g = 11/3, g = 1, g = -1/3}

{3 g = 11, g = 1, 3 g + 1 = 0}

{3 g + 13 = 2 (3 g + 1), 11 - 3 g = 2 (3 g + 1), 11 - 3 g = 3 g + 13}

Hi, I'm happy to help!

First, we need to solve for x. We know that ABD is 78 degrees. (5x+3), and (5x-5) combined are also 78 degrees. So, we combine the like terms of these to get a new expression.

(5x+3) +(5x-5)

10x-2=78

From here, we want to single out the x, by editing both sides in the same way.

10x-2=78

    +2  +2

10x=80

÷10 ÷10

x=8

Now that we know what x is, we can plug it in to the previous expressions to get the angles of ABC and DBC.

(5x-5)

((5·8)-5)

(40-5)

35

Now, we know that ABC is 35 degrees.

(5x+3)

((5·8)+3)

(40+3)

43

Now, we also know that DBC is 43 degrees.

To verify our answer we can add ABC and DBC together to check if it totals to ABD.

35+43=78

Now, we know that the answer: ABC is 35 degrees and DBC is 43 degrees is correct.

I hope this was helpful, keep learning! :D

Answer:

18

Step-by-step explanation:

One way to solve this would be to just solve for random lengths, left to right, until we come to find UC.

We know JK = JH + HM + MK = 82 and JH = 22, so

82 = 22 + HM + MK

subtract 22 from both sides to isolate the unknowns

60 = HM + MK = HK

96 = HK + KU - HU

We know HK = 60

96 = 60 + KU

subtract 60 from both sides to isolate the unknown

We know KU = 36

105 = KN = KU + UC + CN

We know KU = 36 and CN = 51

105 = 36 + 51 + UC

105 = 87 + UC

subtract 87 from both sides to isolate the unknown

18 = UC

UC is what we're looking for, so the problem is solved

Answer:

[tex]12 - 3[/tex]

Step-by-step explanation:

[tex]( - 12 + 3) \\ = 12 - 3 \\ =- 9[/tex]

Answer:

f ( -2) = − 3 ^245fsaf

Step-by-step explanation:

f ( -2) = − 3 ^2wqs

f(-2)= -3^2

f(-2) = -3 × (-3)

f(-2) = 9

Must click thanks and mark brainliest

Answer:

Low = 72/895

Medium = 112/895

High = 711/895

Step-by-step explanation:

Low = number of low quality products over the total number of products

72 / 72 + 112 + 711

Medium = number of medium quality products over the total number of products

112 / 72 + 112 + 711

High = number of high quality products over the total number of products

711 / 72 + 112 + 711

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

Low

72/895

Medium

112/895

High

711/895

Step-by-step explanation:

Step-by-step explanation:

please check the attachment for solutions

Step-by-step explanation:

We have

1-cot²a + cot⁴a = sin²a(1+cot⁶a)

First, we can take a look at the right side. It expands to sin²a + cot⁶(a)sin²(a) = sin²a + cos⁶a/sin⁴a (this is the expanded right side) as cot(a) = cos(a)/sin(a), so cos⁶a = cos⁶a/sin⁶a. Therefore, it might be helpful to put everything in terms of sine and cosine to solve this.

We know 1 = sin²a+cos²a and cot(a) = cos(a)/sin(a), so we have

1-cot²a + cot⁴a = sin²a+cos²a-cos²a/sin²a + cos⁴a/sin⁴a

Next, we know that in the expanded right side, we have sin²a + something. We can use that to isolate the sin²a. The rest of the expanded right side has a denominator of sin⁴a, so we can make everything else have that denominator.

sin²a+cos²a-cos²a/sin²a + cos⁴a/sin⁴a

= sin²a + (cos²(a)sin⁴(a) - cos²(a)sin²(a) + cos⁴a)/sin⁴a

We can then factor cos²a out of the numerator

sin²a + (cos²(a)sin⁴(a) - cos²(a)sin²(a) + cos⁴a)/sin⁴a

= sin²a + cos²a (sin⁴a-sin²a+cos²a)/sin⁴a

Then, in the expanded right side, we can notice that the fraction has a numerator with only cos in it. We can therefore write sin⁴a in terms of cos (we don't want to write the sin²a term in terms of cos because it can easily add with cos²a to become 1, so we can hold that off for later) , so

sin²a = (1-cos²a)

sin⁴a = (1-cos²a)² = cos⁴a - 2cos²a + 1

sin²a + cos²a (sin⁴a-sin²a+cos²a)/sin⁴a

= sin²a + cos²a (cos⁴a-2cos²a+1-sin²a+cos²a)/sin⁴a

= sin²a + cos²a (cos⁴a-cos²a+1-sin²a)/sin⁴a

factor our the -cos²a-sin²a as -1(cos²a+sin²a) = -1(1) = -1

sin²a + cos²a (cos⁴a-cos²a+1-sin²a)/sin⁴a

=  sin²a + cos²a (cos⁴a-1 + 1)/sin⁴a

= sin²a + cos⁶a/sin⁴a

= sin²a(1+cos⁶a/sin⁶a)

= sin²a(1+cot⁶a)