HELP PLS HELPIf the length of the minor axis of an ellipse is 6 units and the length of the major axis is 10 units, how far from the center are the foci located?

Answer:

R colon open bracket y is an element of all real numbers such that y is greater than or equal to negative 3 close bracket

Answer:

This is an odd function because f (–x) = f (x)

Step-by-step explanation:

This is an odd function because f (–x) = f (x)

f(x) = -2x^5 + 6x^3 + 2x.

All the powers are odd powers  and the sum of odd functions is odd

All of the terms are odd functions so the total function is odd

Answer:

CORRECT

Step-by-step explanation:

Answer:

$0.40

Step-by-step explanation:

let a hamburger be X and soda b y

then X + Y is equals to 1.45

2 X + Y is equals to 2.50

using elimination method we will fine the value of x

2 X + Y = 2.50

- X + Y= 1.45

X = 1.05

now how to find the value of Y

we know that X + Y = 1.45

putting the value of x

we get Y is equals to 1.45-1.05

$0.40

Answer:

4

Step-by-step explanation:

ln(e)=1 since ln= log_e

log(x^y)=y*log(x) so ln(e^4)=4*ln(4)=4*1=4

Answer:

D

Step-by-step explanation:

ln(e^4)

The 4 comes down in front of the natural log (ln). You get 4 ln(e)

The natural log of e (ln e )  is 1.

So the answer is 4 * 1 = 4

That may not be clear to you. We could try it another way.

e = 2.718281828

ln (2.718281828) = 1

ln(2.718281828)^4 = 4.  The calculator gags until you get it right.  You need the y^x key (or the x^y key of ^) It does come back with 4.

You have to monkey around with the calculator to get this to happen.  

Answer:

3

Step-by-step explanation:

Answer: 3

Step-by-step explanation:

Answer:

Option A, 90

Step-by-step explanation:

105×2-120

= 210-120

= 90

Answer:

5

Step-by-step explanation:

Use pythagorean theorem. A^2+B^2=C^2

13 is c because it is the hypotenuse and across from the right angle

a is unknown and b is 12

A^2+12^2=13^2

A^2 +144 = 169

A^2 = 169- 144

A^2= 25

now take the sq root of both side

A = 5

Answer:

17.7

Step-by-step explanation:

Answer:

The answers are below,...

Step-by-step explanation:

1. LN = 37

2. NM = 23

3. x = 4

4. EF = 58 / x = 16

5.

6.

7.

8.

Moreover explanation:

Okay so with 5-8 I was unable to figure out the answer,... I guess I shouldn't be answering your questions if I have to figure them out as well. lol,... I did however try (I've been working on just 5-6 for the last hour or so) so I guess brownie points for me for that,... so sorry I couldn't help completely though,... I asked my older brother how to solve them and he is going to get back to me on them (he also has a schedule to keep) I'll hopefully get back to you soon so stay tuned (or not cause hopefully someone else has already answered them) again, so sorry. and the best of luck to you! later!

Hey there!

I believe your answer would be a transformation, and not a translation.

A transformation is an operation that moves, flips, or otherwise changes a figure to create a new figure.

Hope this helps!

Have a wonderful day! :)

Answer:

6ft by 8ft

Step-by-step explanation:

12 / 2 is 6 and 16 / 2 is 8

Answer:

532

A

Step-by-step explanation:

A=86

B=180

C=94

D=266

now,

a+b+c+d_94

=86+180+94+266_94

=532

Answer:

GCF

1.18

2.18

LCM

1.24

2. 36

X - 3/8 = 13/2

Add 3/8 to both sides:

X = 13/2 + 3/8

Rewrite 13/2 to have 8 as the denominator:

13/2 x 4 = 52/8

X = 52/8 + 3/8

X = 55/8

Answer:

55/8

Step-by-step explanation:

Add 3/8 to both sides

X - 3/8 = 13/2

X = 13/2 + 3/8

make sure the denominators are equal so we can add. so multiply 4/4 by 13/2 and that equals 52/8

X = 52/8+3/8

X= 55/8

Answer:

[tex]x=-\frac{11}{8}[/tex]

Step-by-step explanation:

Hi there!

[tex](x - 4) - (x + 7) = 8x[/tex]

Open up the parentheses

[tex]x - 4 - x - 7 = 8x[/tex]

Combine like terms

[tex]x -x - 4 - 7 = 8x\\-4-7=8x\\-11=8x[/tex]

Divide both sides by 8 to isolate [tex]x[/tex]

[tex]-\frac{11}{8}=x[/tex]

I hope this helps!

Work Shown:

tan(angle) = opposite/adjacent

tan(x) = 17/29

x = arctan(17/29)

x = 30.379 which is approximate

x = 30

Side note: arctan is the same as inverse tangent [tex]\tan^{-1}[/tex]

Answer:

Answer:

x = 67°

Step-by-step explanation:

The 2 base angles x are congruent , then

x = [tex]\frac{180-46}{2}[/tex] = [tex]\frac{134}{2}[/tex] = 67°

Answer:

X= 67 degrees.

Step-by-step explanation:

All triangles must add up to 180°. This is an isosceles triangle which means once you have one degree you can find the other two.

In order to get the answer start with 180°-46°

180-46=134

The two x's equal each other. So you can divide the remaining degrees by 2 to get the answer.

134÷2=67.

So the answer is 67°.

Answer:

always

never

always

always

Answer:

Step-by-step explanation:

y=3(x−3)^2+75

Answer:

(x - 3)² = - 25

Step-by-step explanation:

Given

- 3x² = - 18x + 102 ( add 18x to both sides )

- 3x² + 18x = 102 ( divide through by - 3 )

x² - 6x = - 34

To complete the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(- 3)x + 9 = - 34 + 9

(x - 3)² = - 25

I think the answer is 240

Answer:

y = -2x +13

Step-by-step explanation:

you know the point is (5,3) and slope is -2

sub into the linear equation y=mx+b

3 = -2(5) +b

rearrange and solve for b

b= 3 + 10

b = 13

Answer:

15x + 7

Step-by-step explanation:

x + (7 + 14x)

x + 7 + 14x

15x + 7

Answer:

15x + 7

Step-by-step explanation:

Remove parenthesis:

x + 7 + 14x

Combine like terms:

14x + x = 15x

Add the seven:

15x + 7

Hope this helped.

Answer:

To be a function, each input must only have one output. In this case, input 4 has two outputs, so (4 , -2) can be removed for it to be a function.

Let me know if you have any other questions!

The ordered pair (4,2) could be removed to make the given relation a function.

A relation is a function if for every input (x-value) there is exactly one output (y-value).

If there are two or more ordered pairs with the same x-value but different y-values, then the relation is not a function. In this case, one of those ordered pairs would need to be removed in order to make it a function.

As per the question, the relation was given as {(-5,0), (2, -3), (-1, -3), (4, -2), (4, -2), (6,-1)}, the ordered pair (4,-2) would need to be removed because there are two outputs (-2 and 2) for the input of 4.

Thus, removing (4,2) would result in the function.

Learn more about the relations here:

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Answer:

823.7 m^2

Step-by-step explanation:

The ratio of the side lengths is 6/5.

The ratio of the areas is the square of the ratio of the side lengths, 36/25.

572 m^2 * 36/25 = 823.7 m^2

Answer:

The name of the given figure in two different ways are - J⇔U and U⇔J

Answer:

x=4,  -5

Step-by-step explanation:

Factor and set each factor equal to zero

Answer:

X = -4 , x= 4

Step-by-step explanation:

20=x^2-x=0

-20+x^2+x=0

x^2+x-20=0

x×(x+5)-4(x+5)=0

(x+5)×(x-4)=0

x+5=0

×-4=0

x=-5

x=4

The solution to each of the question takes different approach, as the questions are taken from different concepts; however, a common operation among all questions, is factorization.

[tex](1)\ (-xy)^3(xz)[/tex]

Expand

[tex](-xy)^3(xz) = (-x)^3* y^3*(xz)[/tex]

[tex](-xy)^3(xz) = -x^3* y^3*xz[/tex]

Rewrite as:

[tex](-xy)^3(xz) = -x^3*x* y^3*z[/tex]

Apply law of indices

[tex](-xy)^3(xz) = -x^4y^3z[/tex]

[tex](2)\ (\frac{1}{3}mn^{-4})^2[/tex]

Expand

[tex](\frac{1}{3}mn^{-4})^2 =(\frac{1}{3})^2m^2n^{-4*2}[/tex]

[tex](\frac{1}{3}mn^{-4})^2 =\frac{1}{9}m^2n^{-8[/tex]

[tex](3)\ (\frac{1}{5x^4})^{-2}[/tex]

Apply negative power rule of indices

[tex](\frac{1}{5x^4})^{-2}= (5x^4)^2[/tex]

Expand

[tex](\frac{1}{5x^4})^{-2}= 5^2x^{4*2}[/tex]

[tex](\frac{1}{5x^4})^{-2}= 25x^{8[/tex]

[tex](4)\ -x(2x^2 - 4x) - 6x^2[/tex]

Expand

[tex]-x(2x^2 - 4x) - 6x^2 = -2x^3 + 4x^2 - 6x^2[/tex]

Evaluate like terms

[tex]-x(2x^2 - 4x) - 6x^2 = -2x^3 -2x^2[/tex]

Factor out x^2

[tex]-x(2x^2 - 4x) - 6x^2 = (-2x-2)x^2[/tex]

Factor out -2

[tex]-x(2x^2 - 4x) - 6x^2 = -2(x+1)x^2[/tex]

[tex](5)\ \sqrt{\frac{4y}{3y^2}}[/tex]

Divide by y

[tex]\sqrt{\frac{4y}{3y^2}} = \sqrt{\frac{4}{3y}}[/tex]

Split

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{\sqrt{4}}{\sqrt{3y}}[/tex]

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2}{\sqrt{3y}}[/tex]

Rationalize

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2}{\sqrt{3y}} * \frac{\sqrt{3y}}{\sqrt{3y}}[/tex]

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2\sqrt{3y}}{3y}[/tex]

[tex](6)\ \frac{8}{3 + \sqrt 3}[/tex]

Rationalize

[tex]\frac{8}{3 + \sqrt 3} = \frac{3 - \sqrt 3}{3 - \sqrt 3}[/tex]

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{(3 + \sqrt 3)(3 - \sqrt 3)}[/tex]

Apply difference of two squares to the denominator

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{3^2 - (\sqrt 3)^2}[/tex]

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{9 - 3}[/tex]

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{6}[/tex]

Simplify

[tex]\frac{8}{3 + \sqrt 3} = \frac{4(3 - \sqrt 3)}{3}[/tex]

[tex](7)\ \sqrt{40} - \sqrt{10} + \sqrt{90}[/tex]

Expand

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =\sqrt{4*10} - \sqrt{10} + \sqrt{9*10}[/tex]

Split

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =\sqrt{4}*\sqrt{10} - \sqrt{10} + \sqrt{9}*\sqrt{10}[/tex]

Evaluate all roots

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =2*\sqrt{10} - \sqrt{10} + 3*\sqrt{10}[/tex]

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =2\sqrt{10} - \sqrt{10} + 3\sqrt{10}[/tex]

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =4\sqrt{10}[/tex]

[tex](8)\ \frac{r^2 + r - 6}{r^2 + 4r -12}[/tex]

Expand

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r^2 + 3r-2r - 6}{r^2 + 6r-2r -12}[/tex]

Factorize each

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r(r + 3)-2(r + 3)}{r(r + 6)-2(r +6)}[/tex]

Factor out (r+3) in the numerator and (r + 6) in the denominator

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{(r -2)(r + 3)}{(r - 2)(r +6)}[/tex]

Cancel out r - 2

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r + 3}{r +6}[/tex]

[tex](9)\ \frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14}[/tex]

Cancel out x

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x^2 - 5x - 14}[/tex]

Expand the numerator of the 2nd fraction

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x^2 - 7x+2x - 14}[/tex]

Factorize

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x(x - 7)+2(x - 7)}[/tex]

Factor out x - 7

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{(x + 2)(x - 7)}[/tex]

Factor out 4 from 4x + 8

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4(x + 2)}{x} \cdot \frac{1}{(x + 2)(x - 7)}[/tex]

Cancel out x + 2

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4}{x} \cdot \frac{1}{(x - 7)}[/tex]

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4}{x(x - 7)}[/tex]

[tex](10)\ (3x^3 + 15x^2 -21x) \div 3x[/tex]

Factorize

[tex](3x^3 + 15x^2 -21x) \div 3x = 3x(x^2 + 5x -7) \div 3x[/tex]

Cancel out 3x

[tex](3x^3 + 15x^2 -21x) \div 3x = x^2 + 5x -7[/tex]

[tex](11)\ \frac{m}{6m + 6} - \frac{1}{m+1}[/tex]

Take LCM

[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m(m + 1) - 1(6m + 6)}{(6m + 6)(m + 1)}[/tex]

Expand

[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m^2 + m- 6m - 6}{(6m + 6)(m + 1)}[/tex]

[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m^2 - 5m - 6}{(6m + 6)(m + 1)}[/tex]

[tex](12)\ \frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}}[/tex]

Rewrite as:

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} \div \frac{2}{y^2 - 9}[/tex]

Express as multiplication

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{y^2 - 9}{2}[/tex]

Express y^2 - 9 as y^2 - 3^2

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{y^2 - 3^2}{2}[/tex]

Express as difference of two squares

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{(y - 3)(y+3)}{2}[/tex]

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{1} * \frac{(y+3)}{2}[/tex]

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{y+3}{2}[/tex]

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Answer:

[tex]we \: know \: that \: commutative \: prop \\ = x + y = y + x \\ then \\ 4xy + 0 = 0 + 4xy \\ thank \: you[/tex]