determine if it is a function, find the domain and the range.
{(9,−3),(4,−2),(1,−1), (0,0),(1,1),(4,2),(9,3)}

Answer: oranges 1.2 Kg and apples 0.75 Kg.

Step-by-step explanation:

Oranges (4)(1.5)/5

Apples (3)(2)/8

9514 1404 393

Answer:

  geometric sequence

Step-by-step explanation:

The terms of the sequence have a common ratio of -12/3 = -4, so the sequence is geometric. The general term is ...

  an = 3(-4)^(n-1)

so the sum can be written as ...

  [tex]\displaystyle\sum_{n=0}^\infty3(-4)^n[/tex]

(Note the summation starts at n=0, corresponding to a first term of 3.)

Answer:

24 boxes, 1 chocolate remaining

Step-by-step explanation:

289 chocolates total, each box is 12.

just divide it and whatever is left will be your remainder.

289/12 = 24 boxes, 1 chocolate remaining

sub to gauthmath sub reddit for more help like this !

Answer:

what is the time given ???

Step-by-step explanation:

either initial velocity is 0 or final velocity is zero

V=U+AT

converting it we get

V/T = u+a

V/T - U= a

where

v= final velocity

u= initial velocity

a= acceleration

t= time

plz write the full question

The length of the curve (and thus the total distance traveled by the particle along the curve) is

[tex]\displaystyle\int_0^{3\pi}\sqrt{x'(t)^2+y'(t)^2}\,\mathrm dt[/tex]

We have

x(t) = 3 sin²(t )   ==>   x'(t) = 6 sin(t ) cos(t ) = 3 sin(2t )

y(t) = 3 cos²(t )   ==>   y'(t) = -6 cos(t ) sin(t ) = -3 sin(2t )

Then

√(x'(t) ² + y'(t) ²) = √(18 sin²(2t )) = 18 |sin(2t )|

and the arc length is

[tex]\displaystyle 18 \int_0^{3\pi} |\sin(2t)| \,\mathrm dt[/tex]

Recall the definition of absolute value: |x| = x if x ≥ 0, and |x| = -x if x < 0.

Now,

• sin(2t ) ≥ 0 for t ∈ (0, π/2) U (π, 3π/2) U (2π, 5π/2)

• sin(2t ) < 0 for t ∈ (π/2, π) U (3π/2, 2π) U (5π/2, 3π)

so we split up the integral as

[tex]\displaystyle 18 \left(\int_0^{\pi/2} \sin(2t) \,\mathrm dt - \int_{\pi/2}^\pi \sin(2t) \,\mathrm dt + \cdots - \int_{5\pi/2}^{3\pi} \sin(2t) \,\mathrm dt\right)[/tex]

which evaluates to 18 × (1 - (-1) + 1 - (-1) + 1 - (-1)) = 18 × 6 = 108.

Answer:

On the way out the train traveled at about 40 mph, while on the return it did so at 20 mph.

Step-by-step explanation:

Since an empty freight train traveled 60 miles from an auto assembly plant to an oil refinery, and there, its tank cars were filled with petroleum products, and it returned on the same route to the plant, and the total travel time for the train was 4.5 hours, if the train traveled 20 mph slower with the tank cars full, to determine how fast did the train travel in each direction the following calculation must be performed:

60/20 = 3

60/40 = 1.5

60/20 = 3

3 + 1.5 = 4.5

Therefore, on the way out the train traveled at about 40 mph, while on the return it did so at 20 mph.

Answer:

Ray weighed 150 pounds two years ago.

Step-by-step explanation:

11/100 = 16.5/x

11x = 16.5(100)

11x = 1,650

(11x)/11 = (1,650)/11

x = 150

About time that he should start going to the gym!

Answer:

Angle b is congruent to angle E

CA=FD

Step-by-step explanation:

If _______, then triangle ABC and triangle DEF are congruent by the ASA criterion.  ASA is angle side angle .  We know angle C= angle F and side CB = side FE We need to know angle B = angle E

If _______, then triangle ABC and triangle DEF are congruent by the SAS criterion.  SAS is side angle side,  we know side CB = side FE  and then angle C= angle F then we need side CA = side FD

If ∠ABC = ∠DEF, then ΔABC and ΔDEF are congruent by the ASA criterion.

If AC = DF, then ΔABC and ΔDEF are congruent by the SAS criterion.

Two figures are said to be congruent of they have the same shape and all the corresponding sides and angles are congruent.

The HL (hypotenuse leg) congruence theorem states that if the hypotenuse and one leg of a triangle is congruent to another triangle, then both triangles are congruent.

In triangle ABC and DEF;

BC = EF and ∠ACB ≅ ∠DFE

Hence:

If ∠ABC = ∠DEF, then ΔABC and ΔDEF are congruent by the ASA criterion.

If AC = DF, then ΔABC and ΔDEF are congruent by the SAS criterion.

Find out more on congruent figures at: https://brainly.com/question/1675117

Answer:

45°

Step-by-step explanation:

[tex] \sin \: m\angle F = \frac{EG}{FG} \\ \\ \sin \: m\angle F = \frac{2 \sqrt{11} }{2 \sqrt{22} } \\ \\ \sin \: m\angle F = \frac{\sqrt{11} }{ \sqrt{22} } \\ \\ \sin \: m\angle F = \frac{1}{ \sqrt{2} } \\ \\ \sin \: m\angle F = \sin \: 45 \degree \\ \\ \huge \boxed{ \purple{m\angle F = 45 \degree }}[/tex]

Answer:

34.55

Step-by-step explanation:

S = 34.55 represents the standard deviation of the residuals which is the correct answer that would be option (B).

A standard deviation (σ) is a measure of the distribution of the data in reference to the mean.

Students' proficiency in math and English is assessed by a particular standardized test. Ten students were chosen at random, and their math and English test results were recorded and examined.

The computer output displays the outcomes.

Predictor    Coef     SE Coef     t-ratio        p

Constant   -124.13     78.712      0.046

Math           1.223      0.1966      6.220  0.000

S = 34.55     R-Sq = 82.8%      R-Sq (Adj) = 83.5%

In the above ANOVA table, S = 34.55 represents the residual standard deviation.

Therefore, the correct answer is Option B = 34.55.

Option A = 1.223 represents the coefficient of the math score.

Option C = 78.712 represents the Standard Error (S.E).

Option D = 124.13 is the coefficient value.

Hence, the correct answer would be an option (B).

Learn more about the standard deviation here:

https://brainly.com/question/16555520

#SPJ2

A factor is a natural number that can be multiplied by another natural number to get a value. The greatest common factor refers to when one compares the factors of two numbers, the largest natural number that both numbers have in common is the number's greatest common factor.

In the case of ([tex]m^2[/tex]) and ([tex]m^4[/tex]), the greatest common factor is ([tex]m^2[/tex]) because there are no factors of ([tex]m^2[/tex]) that are larger than it. No number can have a factor larger than itself. Since ([tex]m^2[/tex]) is also a factor of ([tex]m^4[/tex]) it is the greatest common factor of the two numbers.

Answer:

Binomial probability refers to the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes (commonly called a binomial experiment).

Answer:

Step-by-step explanation:

a) 0.5*0.365=18.25%

b) (100%-20,7%-50%)=29.3

Answer:

12.56 cents

14.08 cent

Step-by-step explanation:

The unit price for each of the following items could be obtained thus :

The unit price = price of one item

Therefore, given that x numbers of a certain item cost y ;

The unit price will be : y / x

frozen orange juice

16.0 oz at $2.01

12 oz at $1.69

If 16 oz cost $2.01

1 oz = $2.01 / 16 = $0.125625 * 100 = 12.56 cents

If 12 oz = $1.69

1 oz = $1.69 / 12 = $0.1408333 * 100 = 14.08 cent

Answer:

hey, how you're day going

Step-by-step explanation:

.................

Answer:

Step-by-step explanation:

5 pts = $1

$43 × (5 pts)/$1 = 43×5 pts = 215 pts

Answer:

A

Step-by-step explanation:

I guess that is it may be

Answer:

0.2587 = 25.87% probability you will roll a purple on your next toss of the die.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In an experimental probability, which is the case in this question, the number of outcomes is taken from previous experiments.

In this question:

44 + 37 + 41 + 21 = 143 tosses.

37 purple.

What is the probability you will roll a purple on your next toss of the die?

[tex]p = \frac{37}{143} = 0.2587[/tex]

0.2587 = 25.87% probability you will roll a purple on your next toss of the die.

Solution :

It is given that the device works satisfactorily if it makes an average of no more than [tex]0.2[/tex] errors per hour.

The number of errors thus follows the Poisson distribution.

It is given that in [tex]5[/tex] hours test period, the number of the errors follows is

= [tex]0.2 \times 5[/tex]

= 1 error

Let X = the number of the errors in the [tex]5[/tex] hours

[tex]$X \sim \text{Poisson } (\lambda = 0.2 \times 5 =1)$[/tex]

Now that we want to find the [tex]\text{probability}[/tex] that a [tex]\text{satisfactory device}[/tex] will be misdiagnosed as "[tex]\text{unsatisfactory}[/tex]" on the basis of this test. We know that device will be unsatisfactory if it makes more than [tex]1[/tex] error in the test. So we will determine probability that X is greater than [tex]1[/tex] to get required answer.

So the required probability is :

[tex]P(X>1)[/tex]

[tex]$=1-P(X \leq 1)$[/tex]

[tex]$=1-[P(X=0)+P(X=1)]$[/tex]

[tex]$=1- \left( \frac{e^{-1} 1^0}{0!} + \frac{e^{-1} 1^0}{1!} \right) $[/tex]

[tex]$=1-(2 \times e^{-1})$[/tex]

[tex]$=1-( 2 \times 0.367879)$[/tex]

[tex]$=1-0.735759$[/tex]

[tex]=0.264241[/tex]

So the [tex]\text{probability}[/tex] that the [tex]\text{satisfactory device}[/tex] will be misdiagnosed as "[tex]\text{unsatisfactory}[/tex]" on the basis of the test whose result is 0.264241

Answer:

The probability of getting two numbers whose sum is 10 is 25%.

Step-by-step explanation:

Given that a single die is rolled twice, and there are 36 equally-likely outcomes, to find the probability of getting two numbers whose sum is 10 the following calculation must be performed:

1 = +9

2 = +8

3 = +7

4 = +6

5 = +5

6 = +4

7 = +3

8 = +2

9 = +1

9/36 = 0.25

Therefore, the probability of getting two numbers whose sum is 10 is 25%.

Answer: D

Step-by-step explanation:

(lines parallel to each other have the same slope)

slope = m = 2

y = mx + b, (5,6)

6 = 2(5) + b

6 = 10 + b

b = -4

y = 2x - 4

y - 6 = 2(x - 5)

y - 6 = 2x - 10

y = 2x -4

Answer:

hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

;)

The range is virtually the answer to the question,

"In which interval can find all y-values of the function".

So you look at the y-axis and see that your function begins with [tex]y=-5[/tex] (including -5 because of the dot on the graph) and ends at including [tex]y=-1[/tex].

So the interval notation is,

[tex]y\in[-5,-1][/tex]

But you are asked to specify the set notation of the interval, to do so first rewrite the interval using inequality operators, say we find some y in between (and including) -5 and -1,

[tex]-5\leq y\leq-1[/tex]

To specify that this is a set use curly bracelets and a bar,

[tex]\{y\mid-5\leq y\leq-1\}[/tex].

The y before bar is a step function and everything followed after the vertical bar is the range of the step function.

Hope this helps.

Using it's concept, it is found that the range of f(x) is given by:

{y|-5 <= -y <= -1}

The range of a function is the set that contains all possible output values. In a graph, it is given by the values of y, that is, the values of the vertical axis.

In the function described by this graph, the vertical axis assumes values between -1 and -5, inclusive, hence the range is given by:

{y|-5 <= -y <= -1}

More can be learned about the range of a function at https://brainly.com/question/24374080

Answer:

6x10^4

Step-by-step explanation:

========================================================

Explanation:

You can use the AAS (angle angle side) theorem to prove that triangle ABD is congruent to triangle CBD.

From there, we can then say that AD and DC are the same length

AD = DC

3y+6 = 5y-18

3y-5y = -18-6

-2y = -24

y = (-24)/(-2)

y = 12

Answer:

a. L{t} = 1/s² b. L{1} = 1/s

Step-by-step explanation:

Here is the complete question

The The Laplace Transform of a function ft), which is defined for all t2 0, is denoted by Lf(t)) and is defined by the improper integral Lf))s)J" e-st . f(C)dt, as long as it converges. Laplace Transform is very useful in physics and engineering for solving certain linear ordinary differential equations. (Hint: think of s as a fixed constant) 1. Find Lft) (hint: remember integration by parts) A. None of these. B. O C. D. 1 E. F. -s2 2. Find L(1) A. 1 B. None of these. C. 1 D.-s E. 0

Solution

a. L{t}

L{t} = ∫₀⁰⁰[tex]e^{-st}t[/tex]

Integrating by parts  ∫udv/dt = uv - ∫vdu/dt where u = t and dv/dt = [tex]e^{-st}[/tex] and v = [tex]\frac{e^{-st}}{-s}[/tex] and du/dt = dt/dt = 1

So, ∫₀⁰⁰udv/dt = uv - ∫₀⁰⁰vdu/dt w

So,  ∫₀⁰⁰[tex]e^{-st}t[/tex] =  [[tex]\frac{te^{-st}}{-s}[/tex]]₀⁰⁰ -  ∫₀⁰⁰ [tex]\frac{e^{-st}}{-s}[/tex]

∫₀⁰⁰[tex]e^{-st}t[/tex] =  [[tex]\frac{te^{-st}}{-s}[/tex]]₀⁰⁰ -  ∫₀⁰⁰ [tex]\frac{e^{-st}}{-s}[/tex]

= -1/s(∞exp(-∞s) - 0 × exp(-0s)) + [tex]\frac{1}{s}[/tex] [[tex]\frac{e^{-st} }{-s}[/tex]]₀⁰⁰

= -1/s[(∞exp(-∞) - 0 × exp(0)] - 1/s²[exp(-∞s) - exp(-0s)]

= -1/s[(∞ × 0 - 0 × 1] - 1/s²[exp(-∞) - exp(-0)]

= -1/s[(0 - 0] - 1/s²[0 - 1]

= -1/s[(0] - 1/s²[- 1]

= 0 + 1/s²

= 1/s²

L{t} = 1/s²

b. L{1}

L{1} = ∫₀⁰⁰[tex]e^{-st}1[/tex]

= [[tex]\frac{e^{-st} }{-s}[/tex]]₀⁰⁰

= -1/s[exp(-∞s) - exp(-0s)]

= -1/s[exp(-∞) - exp(-0)]

= -1/s[0 - 1]

= -1/s(-1)

= 1/s

L{1} = 1/s