Below is the graph of a polynomial function with real coefficients

(a) The function f is increasing over which intervals? Choose all that apply.
D(-0, -8)
O (-5,-2) O (-8, -2) O (-2,
2) (2,5)
O (5, 0 )
?
(b) The functionfhas local maxima at which x-values? If there is more than one value,
separate them with commas.
(c) What is the sign of the leading coefficient of f?
Select One
(d) Which of the following is a possibility for the degree of f? Choose all that apply.
4
5
6

Please help if you can thank you

Answer:

There isn't enough evidence to indicate that the mean number of TVs in Rocklin households is higher than the reported national average .

Step-by-step explanation:

This is a one sample mean test ;

H0 : μ = 2.7

H1 : μ > 2.7

Given the data :

2, 3, 3, 1, 2, 5, 3, 4, 1, 2, 4, 3

Sample size, n = 12

The sample mean, xbar = ΣX / n = 33/12 = 2.75

The sample standard deviation, s = 1.215 ( from calculator)

The test statistic :

(xbar - μ) ÷ (s/√(n))

T = (2.75 - 2.7) ÷ (1.215/√(12))

T = 0.05 / 0.3507402

T = 0.1426

The critical value from Tscore ;

df = 12 - 1 = 11

Critical value = 1.796

Since ; Test statistic < Critical value ;WE fail to reject the Null and conclude that there isn't enough evidence to indicate that the mean number of TVs in Rocklin households is higher than the reported national average

Answer:

Write an algorithm to add two numbers entered by user. Step 2: Declare variables num1, num2 and sum. Step 3: Read values num1 and num2. Step 4: Add num1 and num2 and assign the result to sum.

Answer:

z =  (17+4w)/(w-m)

Step-by-step explanation:

w • (-4+ z) = mz + 17

Distribute

-4w +wz = mz+17

Subtract mz from each side

-4w +wz - mz = mz+17-mz

-4w +wz-mz = 17

Add 4w to each side

-4w +4w+wz-mz = 17+4w

wz-mz = 17+4w

Factor out z

z(w-m) = 17+4w

Divide by (w-m)

z(w-m)/(w-m) = (17+4w)/(w-m)

z =  (17+4w)/(w-m)

Answer: Missing segment = 45

Step-by-step explanation:

Concept:

Here, we need to know the idea of a similar triangle, ratio, and cross-multiplication.

In similar triangles, one can be obtained from the other by uniformly scaling (enlarging or reducing), possibly with additional translation, rotation and reflection. If two objects are similar, each is congruent to the result of a particular uniform scaling of the other.

A ratio is a quantitative relation between two amounts showing the number of times one value contains or is contained within the other.

Cross-multiplication means multiplying the numerator of each fraction by the other's denominator or the other way round.

If you are still confused, please refer to the attachment below for a graphical explanation.

Solve:

Let x be the length of missing segment

Step One: write the proportion ratio

56 / 56 + 24 = 105 / 105 + x

Step Two: Cross-multiplication

56 (105 + x) = 105 ( 56 + 24)

Step Three: Simplify parenthesis and expand it

56 ( 105 + x) = 105 (80)

5880 + 56x = 8400

Step Four: Subtract 5880 on both sides

5880 + 56x - 5880 = 8400 - 5880

56x = 2520

Step Five: Divide 56 on both sides

56x / 56 = 2520 / 56

x = 45

Hope this helps!! :)

Please let me know if you have any questions

Step-by-step explanation:

The perimeter of the rectangle is

[tex]P = 2(4x + 2x) = 12x[/tex]

The perimeter of the octagon is

[tex]P = 8(1.5x) = 12x[/tex]

So for x = 1, the perimeter of the rectangle, as well as the octagon, is 12 cm. For x = 2, its 24 cm. For x = 3, it's 36 and so on. So the pattern here is with each integer increase in x, the perimeter increases by 12 cm. Also that the perimeters of both shapes are equal.

From the graph, we can write that

The equatuon of line passes through (0,4) and

(-8,0) points.

So

[tex] \sf \: slope \: \: m = \frac{4 - 0}{0 - ( - 8)} = \frac{4}{8} = \frac{1}{2} \\ \therefore \green{\sf \: m = \frac{1}{2} }[/tex]

Intercept of Y-axis c = 4

So equation is :

[tex] \bf \: y = mx + c \\ \bf = > y = \frac{1}{2} x + 4 \\ \bf = > 2y = x + 4 \\ \bf= > \orange{ \boxed{ \bf \: x - 2y + 4 = 0}}[/tex]

Answer:

The student took the numbers for the factors 5, -4 for the zeros  instead of solving the equation

The zeros are -5, 4

Step-by-step explanation:

x^2 +x - 20=0

What 2 number multiply to -20 and add to 1

5*-4 = -20

5+-4 = 1

(x+5)(x-4) =0

Using the zero product property

x+5 = 0  x-4 =0

x=-5  x=4

Answer:

Solution given:

equation is:

x²+x-20=0

doing middle term factorisation

note:we need to get 1 while subtracting factor of the product of constant and coefficient of x².

20*1=20=2*5*2*1

we get 1 while subtracting 5-2*2=5-4

now substitute value 5-4 at coefficient of x

we get

x²+(5-4)x-20=0

now

distribute

x²+5x-4x-20=0

taking common from each two term

x(x+5)-4(x+5)=0

again taking common (x+5) and keeping remaining at another bracket

(x+5)(x-4)=0

either

x+5=0

x=-5

or

x-4=0

x=4

Error is:

x= 4 not -4

x=-5 not 5.

9514 1404 393

Answer:

  a) RM2256.09 . . . principal paid by 8th payment

  b) RM1791.10 . . . . interest paid by 12th payment

Step-by-step explanation:

First of all, we need to find the payments.

The payment amount is the amount that makes the future value of the series of payments equal to the future value of the loan at the given interest rate.

The future value of a single amount is ...

  FV = P(1 +r)^n . . . . . where r is the annual rate, and n is the number of years in the future

The future value of a series of payments is ...

  FV = P((1 +r)^n -1)/r . . . . . where n is the number of payments of P earning annual rate r

For payments in a series that does not end at the end of the loan, the future value is the product of that of the series and the effect of the accumulation of interest for the remaining time.

__

The first 4 payments will have a future value at the end of the loan period of ...

  s1 = X((1 +0.05)^4 -1)/0.05×(1 +0.05)^11 = X(1.05^15 -1.05^11)/0.05

  s1 = 7.3717764259X

The next 5 payments will have a future value at the end of the loan period of ...

  s2 = 2X((1 +0.05)^5 -1)/0.05×(1 +0.05)^6 = 2X(1.05^11 -1.05^6)/0.05

  s2 = 14.8097486997X

The last 6 payments will have a future value at the end of the loan period of ...

  s3 = 4X((1 +0.05)^6 -1)/0.05 = 27.20765125X

So, the total future value of the series of payments is ...

  payment value = 7.3717764259X +14.8097486997X +27.20765125X

  = 49.3891763756X

__

The future value of the loan amount after 15 years is ...

  loan value = 60,000(1 +0.05)^15 = 124,735.69

In order for these amounts to be the same, we must have ...

  49.3891763756X = 124,735.69

  X = 124,735.69/49.3891763756 = 2,525.57

__

At this point, it is convenient to use a spreadsheet to find the interest and principal portions of each of the loan payments. (We find the interest charge to be greater than the payment amount for the first 4 payments. So, the loan balance is increasing during those years.)

In the attached, we have shown the interest on the beginning balance, and the principal that changes the beginning balance to the ending balance after each payment. (That is, the interest portion of the payment is on the row above the payment number.)

The spreadsheet tells us ...

A) the principal repaid in the 8th payment is RM2,256.09

B) the interest paid in the 12th payment is RM1,791.10

_____

Additional comment

The spreadsheet "goal seek" function could be used to find the payment amount that makes the loan balance zero at the end of the term.

We have used rounding to sen (RM0.01) in the calculation of interest payments. The effect of that is that the "goal seek" solution is a payment value of 2525.56707 instead of the 2525.56734 that we calculated above. The value rounded to RM0.01 is the same in each case: 2525.57.

Answer:

±√6

Step-by-step explanation:

[tex]15n=10(n+\frac{3}{n} )[/tex] is your expression first muiltiply out the 10 to get 15n= 10n+10 3/n next subtract  10 n from both sides to get 5n=10+3/n multiply both sides by n to get 5n^2=13 combine both sides and use the quadratic equation to solve to get your solution of ±√6

We are given a system of equations,

[tex]\begin{cases}-x+2y=0\\y=-2\\ \end{cases}[/tex]

This will translate into a 2x2 matrix of coefficients (because 2 equations and 2 unknowns),

[tex]\begin{bmatrix}-1&2\\0&1\\ \end{bmatrix}[/tex]

The matrix will then be applied to the vector (lower dimensions on top),

[tex]\begin{bmatrix}x\\y\\ \end{bmatrix}[/tex]

And the result vector will be whats on the other side of equals sign,

[tex]\begin{bmatrix}0\\-2\\ \end{bmatrix}[/tex]

So to put everything together,

[tex]\begin{bmatrix}-1&2\\0&1\\ \end{bmatrix}\begin{bmatrix}x\\y\\ \end{bmatrix}=\begin{bmatrix}0\\-2\\ \end{bmatrix}[/tex]

Hope this helps :)

Answer:

75 inches

Step-by-step explanation:

with this we use change of subject

V=1/3

Pie=3.14

radius =3

height =8

so therefore

V=1/3 ×3.14×3×3×8

V=75.36

Answer:

-7

Step-by-step explanation:

f(x) = 5 - 4x

f(3) = 5 - 4(3)                         (since x = 3)

f(3) = 5 - 12

f(3) = -7

Answer:

see below

Step-by-step explanation:

CALVIN

v=[tex]\pi[/tex]× r ² × h

v=3.14 × 3² × 12

v=3.14×9 × 12

v=3.14 × 108

v = 339.12

JAMEL

v=[tex]\pi[/tex] × r ²×h

v=3.14× 6 ² × 6

v=3.14 × 36×6

v=3.14×216

v=678.24

9514 1404 393

Answer:

  16.9

Step-by-step explanation:

The marked sides are the hypotenuse and the one opposite the angle. The relevant trig function is ...

  Sin = Opposite/Hypotenuse

Multiplying by the hypotenuse gives an equation for the opposite side.

  x = 22·sin(50°)

  x ≈ 16.9

Answer:

A)

[tex]k=0[/tex]

B)

[tex]\displaystyle \begin{aligned} 2k + 1& = 2\ln 20 + 1 \\ &\approx 2.3863\end{aligned}[/tex]

C)

[tex]\displaystyle \begin{aligned} k - 3&= \ln \frac{1}{2} - 3 \\ &\approx-3.6931 \end{aligned}[/tex]

Step-by-step explanation:

We are given the function:

[tex]\displaystyle h(x) = 20e^{kx} \text{ where } k \in \mathbb{R}[/tex]

A)

Given that h(1) = 20, we want to find k.

h(1) = 20 means that h(x) = 20 when x = 1. Substitute:

[tex]\displaystyle (20) = 20e^{k(1)}[/tex]

Simplify:

[tex]1= e^k[/tex]

Anything raised to zero (except for zero) is one. Therefore:

[tex]k=0[/tex]

B)

Given that h(1) = 40, we want to find 2k + 1.

Likewise, this means that h(x) = 40 when x = 1. Substitute:

[tex]\displaystyle (40) = 20e^{k(1)}[/tex]

Simplify:

[tex]\displaystyle 2 = e^{k}[/tex]

We can take the natural log of both sides:

[tex]\displaystyle \ln 2 = \underbrace{k\ln e}_{\ln a^b = b\ln a}[/tex]

By definition, ln(e) = 1. Hence:

[tex]\displaystyle k = \ln 2[/tex]

Therefore:

[tex]2k+1 = 2\ln 2+ 1 \approx 2.3863[/tex]

C)

Given that h(1) = 10, we want to find k - 3.

Again, this meas that h(x) = 10 when x = 1. Substitute:

[tex]\displaystyle (10) = 20e^{k(1)}[/tex]

Simplfy:

[tex]\displaystyle \frac{1}{2} = e^k[/tex]

Take the natural log of both sides:

[tex]\displaystyle \ln \frac{1}{2} = k\ln e[/tex]

Therefore:

[tex]\displaystyle k = \ln \frac{1}{2}[/tex]

Therefore:

[tex]\displaystyle k - 3 = \ln\frac{1}{2} - 3\approx-3.6931[/tex]

9514 1404 393

Answer:

Step-by-step explanation:

The sum of torques about the pivot point is zero when the system is in equilibrium. That means the total of clockwise torques is equal to the total of counterclockwise torques. For this purpose, torque can be modeled by the product of mass and its distance from the pivot. The uniform beam can be modeled as a point mass at its center.

__

a) Let E represent the location of the center of mass of the beam. So, AE = 1.5 m. Then the distance from C to E is AC-AE = AC -1.5 and the CCW torque due to the beam's mass is (16 kg)(AC -1.5 m).

The distance from B to C is 3 m - AC, so the CW torque due to the particle at B is (7 kg)(3 -AC m)

These are equal, so we have ...

  16(AC -1.5) = 7(3 -AC)

  16AC -24 = 21 -7AC . . . . . eliminate parentheses

  23AC = 45 . . . . . . . . . . . add 7AC+24

  AC = 45/23 ≈ 1.957 . . divide by the coefficient of AC

  AC ≈ 2.0 meters . . . . rounded to 1 dp

__

b) The torques in this scenario are ...

  M(0.7) = 16(0.8) +7(2.3) . . . . . . AD = 0.7 m, DE = 0.8 m, DB = 2.3 m

  M = 28.9/0.7 ≈ 41.286 . . . . simplify, divide by the coefficient of M

  M = 41.3 kg . . . . rounded to 1 dp

_____

Additional comment

Torque is actually the product of force and distance from the pivot. Here, the forces are all downward, and due to the acceleration of gravity. The gravitational constant multiplies each mass, so there is no harm in dividing the equation by that constant, leaving the sum of products of mass and distance.

9514 1404 393

Answer:

  1.56×10^10 cL

Step-by-step explanation:

There are 1000 liters in a cubic meter, so 10^5 centiliters in a cubic meter. The 1.56×10^5 cubic meters will then have ...

  (1.56×10^5 m^3)×(10^5 cL/m^3) = 1.56×10^10 cL

_____

That's 15,600,000,000 cL.

"Centi-" is a prefix meaning 1/100.

Answer:

C. [tex]k[/tex] is greater than zero.

Step-by-step explanation:

We know that graph is obtained from the function of the form [tex]f(x) = a\cdot (x+k)^{1/n} + c[/tex]. According to the graph and if [tex]x + k = 0[/tex], we find that:

[tex]x = -k[/tex] (1)

[tex]x < 0[/tex] (2)

By (1) and (2):

[tex]-k < 0[/tex]

[tex]k > 0[/tex]

Hence, correct answer is C.

Answer:

The P-value is < significance value ( 0.05 ) hence we reject the Null hypothesis ( i.e. There is an association between the race and average age at marriage )

Step-by-step explanation:

Conducting an F-test to determine association between race and average age at marriage

step 1 : State the hypothesis

H0 : ц1 = ц2 = ц3

Ha : ц1 ≠ ц2 ≠ ц3

step 2 : determine the mean square between

Given mean value of all groups = 23.33

SS btw = 113*(25.39 - 23.33)² +  904*(22.99 - 23.33)² + 144*(23.89 - 23.33)^2            = 113(4.2436) + 904(0.1156) + 144(0.3136)

= 629.1876

hence:  df btw = 3 - 1 = 2

             df total = 1161 - 1 = 1160

              df within = 1160 - 2 = 1158

              SS within = 36.87*1158 = 42695.46

Therefore the MS between =  629.19 / 2 = 314.60

The F-ratio = 314.59 / 36.87 = 8.53

using the values for Btw the P-value = 0.00021

The P-value is < significance value ( 0.05 ) hence we reject the Null hypothesis ( i.e. There is an association between the race and average age at marriage )

Answer:

900 cm

Step-by-step explanation:

1 : 50

We need the first number to be 18 so multiply by 18

1:18 : 50*18

18 cm : 900 cm

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a p-value of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 1.96\frac{2050}{\sqrt{49}} = 574[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Answer:

Hence, data does not suggest the true average gap detection threshold for CTS subjects exceeds that for normal subjects.

Step-by-step explanation:

H0 : μ1 = μ2

H1 : μ1 < μ2

Given :

m = 8 ; x1 = 1.71 ; s1 = 0.53

n = 10 ; x2 = 2.53 ; s2 = 0.87

The test statistic :

(x1 - x2) / √(s1²/m + s2²/n)

(1.71 - 2.53) / √(0.53²/8 + 0.87²/10)

-0.82 / √0.1108025

Test statistic = - 0.82 / 0.3328700

Test statistic = - 2.463

The degree of freedom using the conservative approach :

Smaller of (10 - 1) or (8 - 1)

df = 7

TCritical value(0.01, 7) = 2.998

Decision region :

Reject H0 if |Test statistic| > |critical value|

Since, 2.463 < 2.998 ; WE fail to reject H0 ; Hence result is not significant at α = 0.01

Solution :

Given data :

20.1     33.5     21.7      58.4     23.2     110.8     30.9

24.0    74.8     60.0

n = 10

Range : Arranging from lowest to highest.

20.1,   21.7,   23.2,    24.0,   30.9,    33.5,    58.4,    60.0,    74.8,   110.8

Range = low highest value - lowest value

           = 110.8 - 20.1

           = 90.7

Mean = [tex]$\frac{\sum x}{n}$[/tex]

         [tex]$=\frac{20.1+21.7+23.2+24.0+30.9+33.5+58.4+60.0+74.8+110.8}{10}$[/tex]

          [tex]$=\frac{457.4}{10}$[/tex]

         [tex]$=45.74$[/tex]

Sample standard deviation :

[tex]$S=\sqrt{\frac{1}{n-1}\sum(x-\mu)^2}$[/tex]

[tex]$S=\sqrt{\frac{1}{10-1}(20.1-45.74)^2+(21.7-45.74)^2+(23.2-45.74)^2+(24.0-45.74)^2+(30.9-45)^2}$[/tex]  

      [tex]\sqrt{(33.5-45.74)^2+(58.4-45.74)^2+(60.0-45.74)^2+(74.8-45.74)^2+(110.8-45.74)^2}[/tex]

[tex]$S=\sqrt{\frac{1}{9}(657.4+577.9+508.0+472.6+220.2+149.8+160.2+203.3+844.4+4232.8)}$[/tex][tex]$S=\sqrt{\frac{1}{9}(8026.96)}$[/tex]

[tex]$S=\sqrt{891.88}$[/tex]

S = 29.8644

Variance = [tex]S^2[/tex]

               [tex]=(29.8644)^2[/tex]

               = 891.8823

Answer:

The correct answer is "Test 20%, Service 10%".

Step-by-step explanation:

As we know,

The coefficient of variation (CV) is:

⇒ [tex]CV=\frac{Standard \ deviation}{Mean}\times 100[/tex]

Now,

CV of test will be:

= [tex]\frac{40}{200}\times 100[/tex]

= [tex]20[/tex] (%)

CV of service will be:

= [tex]\frac{2}{20}\times 100[/tex]

= [tex]10[/tex] (%)

9514 1404 393

Answer:

  smaller : larger = 3 : 4

Step-by-step explanation:

The scale factor is the ratio of corresponding dimensions. If we use the width dimensions, we have ...

  smaller/larger = 9/12 = 3/4

The scale factor is 3/4.

Answer:

Carlos

Step-by-step explanation:

Hope this helps

Answer:

see above is the answer handwriting is bad sorry for that

Answer : 19.6cm

I hope this helps you! Have a good day!

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