A train travels a distance of 60 km at uniform speed. If the speed of the train was reduced by 10 kmh-1, the time taken to travel the 60km will increase by 1/2h. Find the speed of the train at the beginning.
Answer:
Initial speed is 32 m/s
At uniform speed, acceleration is 0, (a = 0).
When speed reduced, (v - u) = 2.78 ms-¹, t = 1800 sec, s = 60 ,000 metres.
From first equation of motion:
[tex]{ \boxed{ \bf{v = u + at}}} \\ { \tt{(v - u) = at}}[/tex]
substitute:
[tex]{ \tt{2.78 = (a \times 1800)}} \\ { \tt{acceleration = 0.0015 \: {ms}^{ - 2} }}[/tex]
from second equation of motion:
[tex]{ \boxed{ \bf{s = ut + \frac{1}{2} a {t}^{2} }}}[/tex]
substitute:
[tex]{ \tt{60000 = 1800u + ( \frac{1}{2} \times 0.0015 \times {1800}^{2}) }} \\ { \tt{1800u = 57570}} \\ { \tt{u = 32 \: m {s}^{ - 1} }}[/tex]
Out of the 14641 times Voldemort has brushed his teeth, only 5/11 of the time did he floss immediately beforehand. How many times total has Voldemort NOT flossed right before brushing his teeth?
In this question, we want to find a fraction of a value, which is found multiplying the fraction by the value.
Information:
Voldemort has brushed his teeth 14641 times.
5/11 of the time, he has flossed immediately beforehand.
[tex]1 - \frac{5}{11} = \frac{6}{11}[/tex] of the time, he has NOT flossed immediately beforehand.
How many times total has Voldemort NOT flossed right before brushing his teeth?
6/11 out of 14641, so:
6*14641/11 = 7986.
Thus, Voldemort has NOT flossed right before brushing his teeth 7986 times.
For another example with a fraction of a value, you can check https://brainly.com/question/5501130
Lord Voldemort did not floss his teeth 7986 times.
According to this question, we know the following two facts:
1) Lord Voldemort has brushed his teeth 14641 times.
2) He flossed his teeth beforehand only [tex]\frac{5}{11}[/tex] of the time.
There, he did not floss his teeth [tex]\frac{6}{11}[/tex] of the time and the total number of time that he did not floss is obtained by multiplicating the total number of times that he brushed his teeth and the rational number deducted at the beginning of the paragraph. That is to say:
[tex]x = \left(\frac{6}{11} \right)\cdot (14641)[/tex]
[tex]x = 7986[/tex]
Lord Voldemort did not floss his teeth 7986 times.
If the vertex of an isosceles triangle measures 46°, what is the measure of it’s base angles?
Answer:
67°
Step-by-step explanation:
let the base angle=x
x+x+46=180
2x=180-46=134
x=134/2=67
You are standing 186 feet away from the base of a building and your clinometer
measures 23° when it's looking at the top of the building. (This angle is the one between
the ground and the top of the building). Please calculate the height of the building.
9514 1404 393
Answer:
about 79 ft
Step-by-step explanation:
The relevant trig relation is ...
Tan = Opposite/Adjacent
In this scenario, the angle is 23°, the adjacent side is the distance to the building, and the opposite side is the building height. Then we have ...
height = tan(23°)·(186 ft) ≈ 78.95 ft ≈ 79 ft
The length of a rectangle is 10 m more than its breadth. If the perimeter of rectangle is 80 m, find the dimensions of the rectangle.
if you like my answer then please mark me as brainliest
need help with this!!!
Answer:
It's D I sure about it correspond means identical... The matching number
Kathryn plants two different types of tomato plant. She records the number of tomatoes that she picks from each plant every day. Her records are shown below:
Plant A: 4, 6, 7, 3, 5, 2, 1, 3, 6, 5
Plant B: 5, 6, 7, 6, 8, 9, 6, 7, 7, 9
Which plant has the more consistent yield of tomatoes?
not enough information to tell
they produce about the same amount of plants
Plant A
Plant B
Answer:
Plant B
Step-by-step explanation:
When you compare the number of tomatoes she picks from plant B with plant A, you will notice that plant B has not produced less tomatoes than plant A in any day but it has either produced the same or more number of tomatoes.
PLS HELP WILL GIVE BRAINLY!!
A triangle has sides that measure 4 units, 6 units, and 7.21 units. What is the area of a circle with a circumference that equals the perimeter of the triangle? Use 3.14 for π, and round your answer to the nearest whole number.
17 units2
24 units2
54 units2
94 units2
Answer:
24 units ²
Step-by-step explanation:
In this problem, we are given the circumference of a triangle (after finding the perimeter) and want to find the area of a circle with that circumference. Since the area of a circle is a function based on its radius, we can use the circumference to find the radius to find the area.
First, we can figure out the perimeter of the triangle, which is equal to the sum of its sides. The perimeter is 6+4+7.21 = 17.21 units.
Next, the circumference of a circle is equal to π * diameter = π * 2 * radius. Using 3.14 for π and r for radius, we get
3.14 * 2 * r = 17.21
6.28 * r = 17.21
divide both sides by 6.28 to isolate r
r ≈ 2.74
Furthermore, to find the area from the radius, we can use
area = πr². Plugging 2.74 in for r, we get
2.74² * 3.14 = area
≈23.6, rounding up to 24 units ²
The circumference is equal to the perimeter of the triangle. Then the area of the circle is 23.58 or 24 square units. Option B is correct.
What is a circle?It is a locus of a point drawn equidistant from the center. The distance from the center to the circumference is called the radius of the circle.
A triangle has sides that measure 4 units, 6 units, and 7.21 units.
Then the perimeter of the triangle will be
Perimeter = 6 + 4 + 7.21
Perimeter = 17.21
The circumference is equal to the perimeter of the triangle. Then the radius will be
[tex]2\pi r = 17.21\\\\r = 2.74[/tex]
Then the area of the circle will be given as
[tex]\rm Area = \pi r^2 \\\\Area = \pi \times 2.74^2 \\\\Area = 23.58[/tex]
Thus, the area of the circle is 23.58 square units.
More about the circle link is given below.
https://brainly.com/question/11833983
(a + b)2 = 1a2 + 2ab + 1b2
(a + b)3 = 1a3 + 3a2b + 3ab2 + 1b3
How are binomial expansions related to Pascal’s triangle?
The Pascal triangle terms and binomial are related by the binomial theorem fomrula:
The row of the Pascal triangle is the same as
where n is the same as the row of the Pascal triangle.
For example,
.
is the same as the 2nd row of the Pascal triangle.
.
Also know the leading coefficient and last term degree will be the nth row of the Pascal triangle.
The first term, a will be 1 less than the previous terms and the second term, b will be 1 more than the previous terms. For example, look at
.
Another example is
.
The third row of Pascal Triangle
.
.
Pascal's triangle provides a systematic way to determine the coefficients of binomial expansions, making it a valuable tool in algebra and combinatorics.
Binomial expansions are directly related to Pascal's triangle.
Pascal's triangle is a triangular arrangement of numbers in which each number is the sum of the two numbers directly above it. The first and last numbers in each row of Pascal's triangle are always 1.
The coefficients of the terms in a binomial expansion correspond to the numbers in Pascal's triangle. Each row of Pascal's triangle represents the coefficients of the corresponding power of the binomial.
For example, in the expansion of (a + b)², the coefficients are 1, 2, and 1. These coefficients can be found in the third row of Pascal's triangle: 1, 2, 1. Similarly, in the expansion of (a + b)³, the coefficients are 1, 3, 3, and 1, which can be found in the fourth row of Pascal's triangle: 1, 3, 3, 1.
In summary, Pascal's triangle provides a systematic way to determine the coefficients of binomial expansions, making it a valuable tool in algebra and combinatorics.
Learn more about Pascal's triangle here;
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pls help. And can someone tell me how give brainliest so i can give it?
Answer:
n - 324 = 394
STEP BY STEP EXPLANATION
You're playing a game where you defend your village from an orc invasion. There are 3 characters (elf, hobbit, or human) and 5 defense tools (magic, sword, shield, slingshot, or umbrella) to pick from. If you randomly choose your character and tool, what is the probability that you wont be a hobbit or use an umbrella
Answer:
The probability that you won't be a hobbit=
[tex] \frac{2}{3} [/tex]
The probability that you won't choose an umbrella=
[tex] \frac{4}{5} [/tex]
Step-by-step explanation:
The characters are 3, minus the hobbit gives you 2. So the probability of that=
[tex] \frac{2}{3} [/tex]
The weapons are 5, minus the umbrella is 4. So the probability of that=
[tex] \frac{4}{5} [/tex]
What is the measure of m?
6
24
n
m
m =
[?]
Enter
the measure of m is24 according to the questions
If m
Please Help!!!!!!!!!!!!
Answer:
45 degrees
Step-by-step explanation:
the 2 angles are supplementary (add up to 180 degrees)
180-135=45
Which will result in a difference of squares?
a
(negative 7 x + 4)(negative 7 x + 4)
b
(negative 7 x + 4)(7 x minus 4)
c
(negative 7 x + 4)(negative 7 x minus 4)
d
(negative 7 x + 4)(4 minus 7 x)
Answer:
C
Step-by-step explanation:
The correct answer is C, love from Gauthmath
Answer:
the correct answer is option C
Step-by-step explanation:
(negative 7 x + 4)(negative 7 x minus 4)
Complete the equation to represent finding x, the greater integer. x(x – ) = 143 What is the greater integer?
Answer:
[tex]x * (x - 2) = 143[/tex]
Where [tex]x = 13[/tex]
Step-by-step explanation:
Given
[tex]x (x - \_) = 143[/tex]
Required
Complete the blank
The complete question implies that the product include 2 consecutive odd numbers.
Two numbers whose products equal 143 are: 11 and 13
i.e. [tex]11 * 13 = 143[/tex]
So, we have:
[tex]x * (x - \_) = 13 * 11[/tex]
By comparison, we have:
[tex]x = 13[/tex]
[tex]x - \_ = 11[/tex]
Collect like terms
[tex]\_ = x - 11[/tex]
Substitute 13 for x
[tex]\_ = 13 - 11[/tex]
[tex]\_ = 2[/tex]
So, the complete equation is:
[tex]x * (x - 2) = 143[/tex]
Where [tex]x = 13[/tex]
Answer:
2
and
13
Step-by-step explanation:
Got it right on edge.
The difference between interior angle in centesimal measurement and sexagesimal measurement is 15° of a regular polygon. Find the number of sides of the polygon.
Answer:
8
Step-by-step explanation:
x = centesimal angle (100 degrees in a right angle)
y = sexagesimal angle (90 degrees in a right angle)
x - y = 15
x×90/100 = y
x×9/10 = y
x - x×9/10 = 15
10x/10 - 9x/10 = 15
x/10 = 15
x = 150
y = 150×9/10 = 15×9 = 135
using centesimal system :
the sum of all external angles in a polygon is 400 degrees (a full circle).
one external angle is the complement of one internal angle to 200 degrees = 200-150=50 degrees.
to find the number of sides of the polygon we need to find the number of angles or corners. and that is how many external angles fit into the full circle.
n = 400/50 = 8
the polygon has 8 sides
what is the approximate shadow in feet of the tree in the figure below.
Answer:
224 ft
Step-by-step explanation:
The tree makes a 90° angle with the ground, so we have a right triangle.
For the 32° angle, the height of the tree is the opposite leg. The length of the shadow on the ground is the adjacent leg.
The trig ratio that relates the opposite leg to the adjacent leg is the tangent.
Let the length of the shadow of the tree on the ground be x.
tan A = opp/adj
tan 32° = 140 ft/x
x = 140 ft/tan 32°
x = 224 ft
Answer: 224 ft
without using tables or calculator, evaluate
[tex] \frac{ \sin(20 \degree) }{ \cos(70\degree) } + \frac{ \cos(35\degree) }{ \sin( 65\degree)} [/tex]
Answer->[tex] \frac{ \sin(20 \degree) }{ \cos(70\degree) } + \frac{ \cos(35\degree) }{ \sin( 65\degree)} [/tex]
we know:-[tex] \sin( \theta) = \cos(90 - \theta) \\ \\ \cos( \theta) = \sin(90 - \theta) [/tex]
So putting down the value
[tex] \frac{ \cos(90 - 20 \degree) }{ \cos(70\degree) } + \frac{ \sin(90 - 35\degree) }{ \sin( 65\degree)} [/tex]
[tex] \frac{ \cos(70\degree) }{ \cos(70\degree) } + \frac{ \sin(65\degree) }{ \sin( 65\degree)} [/tex]
[tex]\frac{\cancel{\cos(70\degree)}}{ \cancel{\cos(70\degree)}} + \frac{\cancel{\sin(65\degree)}}{\cancel{\sin( 65\degree)}} [/tex]
[tex] \frac{1}{1} + \frac{1}{1} \\ 1 + 1 = 2 \: \: ans[/tex]
What is a linear system?
Answer:
Linear systems are systems of equations in which the variables are never multiplied with each other but only with constants and then summed up
The curve C has parametric equations x = t², y = (2 - t)^1/2, for 0 ≤ t ≤2.
Find d2y/dx2 in terms of t.
Can I have the full workings also please?
Answer:
y''=(4-3t)/[16 t^3 (2-t)^(3/2)]
Step-by-step explanation:
x = t², y = (2 - t)^1/2
dy/dx=dy/dt×dt/dx by chain rule
dy/dt=1/2 (2-t)^(1/2-1) × (-1)
dy/dt=-1/2 (2-t)^(-1/2)
dy/dt=-1/[2(2-t)^(1/2) ]
dx/dt=2t
dy/dx=-1/[2(2-t)^(1/2) ] × 1/[2t]
dy/dx=-1/[4t (2-t)^(1/2) ]
We need to find the second derivative now.
That is we calculate d/dt(dy/dx in terms of t) then divide by derivative of x in terms of t).
dy/dx=-1/[4t (2-t)^(1/2) ]
Let's find derivative of this with respect to t.
d/dt(dy/dx)=
[0[4t (2-t)^(1/2)]-(-1)(4(2-t)^(1/2)+-4t(1/2)(2-t)^(-1/2))]/ [4t (2-t)^(1/2) ]^2
Let's simplify
d/dt(dy/dx)=
[(4(2-t)^(1/2)+-4t(1/2)(2-t)^(-1/2))]/ [4t (2-t)^(1/2) ]^2
Continuing to simplify
Apply the power in the denominator
d/dt(dy/dx)=
[(4(2-t)^(1/2)+-4t(1/2)(2-t)^(-1/2))]/ [16t^2 (2-t) ]
Multiply by (2-t)^(1/2)/(2-t)^(1/2):
d/dt(dy/dx)=
[(4(2-t)+-4t(1/2)]/ [16t^2 (2-t)^(3/2)]
Distribute/multiply:
d/dt(dy/dx)=
[(8-4t+-2t)]/ [16t^2 (2-t)^(3/2)]
Combine like terms:
d/dt(dy/dx)=
[(8-6t)]/ [16t^2 (2-t)^(3/2)]
Reducing fraction by dividing top and bottom by 2:
d/dt(dy/dx)=
[(4-3t)]/ [8t^2 (2-t)^(3/2)]
Now finally the d^2 y/dx^2 in terms of t is
d/dt(dy/dx) ÷ dx/dt=
[(4-3t)]/ [8t^2 (2-t)^(3/2)] ÷ 2t
d/dt(dy/dx) ÷ dx/dt=
[(4-3t)]/ [8t^2 (2-t)^(3/2)] × 1/( 2t)
d/dt(dy/dx) ÷ dx/dt=
[(4-3t)]/ [16t^3 (2-t)^(3/2)]
Or!!!!!!
x = t², y = (2 - t)^1/2
Since t>0, then t=sqrt(x) or x^(1/2).
Make this substitution into the equation explicitly solved for y:
y = (2 - x^1/2)^1/2
Differentiate:
y' =(1/2) (2 - x^1/2)^(-1/2) × -1/2x^(-1/2)
y'=-1/4(2 - x^1/2)^(-1/2)x^(-1/2)
y'=-1/4(2x-x^3/2)^(-1/2)
Differentiate:
y''=1/8(2x-x^3/2)^(-3/2)×(2-3/2x^1/2)
y''=(2-3/2x^1/2)/[8 (2x-x^3/2)^(3/2)]
Replace x with t^2
y''=(2-3/2t)/[8 (2t^2-t^3)^(3/2)]
Multiply top and bottom by 2
y''=(4-3t)/[16 (2t^2-t^3)^(3/2)]
Factor out t^2 inside the 3/2 power factor:
y''=(4-3t)/[16 (t^2)^(3/2) (2-t)^(3/2)]
y''=(4-3t)/[16 t^3 (2-t)^(3/2)]
(12, 9, 4) What is the area of the parallelogram shown below?
area of the parallelogram is: b x h
12 x 4 = 48 (d)
What quadratic formula do I need to use to solve 3x(x+6)=-1
Answer:
[tex]\Large \boxed{x_1=\frac{9+\sqrt{51} }{3} \ \ ; \ \ x_2=\frac{9-\sqrt{51} }{3} }[/tex]
Step-by-step explanation:
[tex]\displaystyle \Large \boldsymbol{} 3x(x+6)=-10 \\\\3x^2+18x=-10 \\\\3x^2+18x+10=0 \\\\D=324-120=204 \\\\ x_{1;2}=\frac{18\pm2\sqrt{51} }{6} =\frac{9\pm\sqrt{51} }{3}[/tex]
Instructions: Find the missing side. Round your answer to the nearest tenth.
8
16
Answer:
the answer is 40
Step-by-step explanation:
the right side dose not exist so you only have to add the the 2 sides and then it becumes solved
Answer:
Step-by-step explanation:
45 ĐỘ
Zoe walks at a speed of 10 miles/h and jogs at a speed of 20 miles/h. She goes to the park to walk 2 miles on a Monday. How long will she take to walk 2 miles?
Answer:
12 minutes
Step-by-step explanation:
Given
[tex]s_1 = 10mi/h[/tex] --- walk speed
[tex]s_2 = 20mi/h[/tex] --- jog speed
[tex]d = 2\ miles[/tex] --- distance
Required
The time to walk the given distance
Time is calculated as:
[tex]Time = \frac{distance}{speed}[/tex]
In this case, the speed is the speed at which she walks.
So, we have:
[tex]Time = \frac{d}{s_1}[/tex]
Substitute known values
[tex]Time = \frac{2mi}{10mi/h}[/tex]
[tex]Time = 0.2hr[/tex]
Convert to minutes
[tex]Time = 0.2 * 60mins[/tex]
[tex]Time =12mins[/tex]
toán 9 nha mọi người
Answer:
Thamkhao
Step-by-step explanation:
A particle moves along a line with a velocity v(t)=t2−t−6, measured in meters per second. Find the total distance the particle travels from t=0 seconds to t=4 seconds.
The total distance the particle travels from t=0 seconds to t=4 seconds would be 11.33 meters.
Used the concept of integration that states,
In Maths, integration is a method of adding or summing up the parts to find the whole. It is a reverse process of differentiation, where we reduce the functions into parts.
Given that,
A particle moves along a line with a velocity v(t) = t² - t - 6, measured in meters per second.
Now the total distance the particle travels from t=0 seconds to t=4 seconds is,
D = ∫₀⁴ |(t² - t - 6)| dt
D = ∫₀⁴ (t²) dt - ∫₀⁴ (t) dt - ∫₀⁴ (6) dt
D = (t³/3)₀⁴ - (t²/2)₀⁴ - 6 (t)₀⁴
D =| (64/3) - (16/2) - 6 (4)|
D = | (64/3) - 8 - 24 |
D = | (64/3) - 32|
D = 11.33 meters
Therefore, the total distance is 11.33 meters.
To learn more about integration visit:
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double a number plus 54 equals 8 times the number
2x+54=8x
So. The Answer is 7
The temperature on a mountain peak was 7 degreesFahrenheit (F) at 6:00 p.m. By 8:00 p.m., thetemperature had dropped to 0F. If the temperaturecontinued to drop at about the same rate, which isthebestestimate of the temperature at 11:00 p.m
A -20 / B. -14 / C -10 / D -9 /
Given:
The temperature on a mountain peak was 7°F at 6:00 p.m.
By 8:00 p.m., the temperature had dropped to 0°F.
To find:
The temperature at 11:00 p.m. if the temperature continued to drop at about the same rate.
Solution:
Time between 6:00 p.m. to 8:00 p.m. is 2 hours.
Change in temperature in 2 hours is -7°F.
Change in temperature in 1 hours is [tex]-\dfrac{7}{2}^\circ[/tex]F.
Time between 8:00 p.m. to 11:00 p.m. is 3 hours.
Change in temperature in 3 hours is [tex]3\times \dfrac{-7}{2}^\circ[/tex]F, i.e., [tex]-\dfrac{21}{2}^\circ[/tex]F.
Now, the temperature at 11:00 p.m is:
[tex]0-\dfrac{21}{2}=-10.5[/tex]
Therefore, the temperature at 11:00 p.m. is -10.5°F.
Note: All options are incorrect.
Can someone please help me with this problem!!
Graph g(x)= -5^x +5
8. Colleen times her morning commute such that there is an equal likelihood that she will arrive early or late to work on any given day. If she always arrives either early or late, what is the probability that Colleen will arrive late to work no more than twice during a five-day workweek
Solution :
Case I :
If Collen is late on [tex]0[/tex] out of [tex]5[/tex] days.
[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} $[/tex]
[tex]$=\frac{1}{32}[/tex]
Case II :
When Collen is late on [tex]1[/tex] out of [tex]5[/tex] days.
[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_1$[/tex]
[tex]$=\frac{1}{32} \times 5$[/tex]
[tex]$=\frac{5}{32}[/tex]
Case III :
When Collen was late on [tex]2[/tex] out of [tex]5[/tex] days.
[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_2$[/tex]
[tex]$=\frac{1}{32} \times 10$[/tex]
[tex]$=\frac{5}{16}[/tex]
Therefore, the [tex]\text{probability}[/tex] that Collen will arrive late to work no more than [tex]\text{twice}[/tex] during a [tex]\text{five day workweek}[/tex] is :
[tex]$=\frac{1}{32} + \frac{5}{32} + \frac{5}{16} $[/tex]
[tex]$=\frac{1}{2}$[/tex]
