1/3 / 4 what does it equal

Answer:

B. Solitary

Step-by-step explanation:

Fur trappers often lived solitary lives in the woods.  They stayed there for months at a time.  Their life was not predictable, they might not find many animals in their area.  Their life was not refined, they lived in rough cabins in the middle of the forest.  Their life was not civilized, since they barely had many of the comforts of life.

Answer:

Kaylaa   do you use  desmos graphing calculator?  it's an online graphsing tool and would make this very easy for you. Maybe you are not allowed to use a calculator?

Step-by-step explanation:

with out  a calculator it's a long math process,  1st because each of the equations are equal to  Y,  we can set each of them equal to each other. like this

[tex]\sqrt{x-8}[/tex] + 3  =  - [tex](x-5)^{2}[/tex] + 18

[tex]\sqrt{x-8}[/tex]     =  - [tex](x-5)^{2}[/tex]  +18 -3

[tex]\sqrt{x-8}[/tex]   =    - [tex](x-5)^{2}[/tex]  + 15

[tex]\sqrt{x-8}[/tex]   = -[ (x-5)*(x-5) ] + 15

[tex]\sqrt{x-8}[/tex]  = -[ [tex]x^{2}[/tex] - 10x + 25] +15

[tex]\sqrt{x-8}[/tex]  = -[tex]x^{2}[/tex] + 10x -25 +15

 [tex]\sqrt{x-8}[/tex] = -[tex]x^{2}[/tex] + 10x -10

-  [tex]\sqrt{x-8}[/tex]  = [tex]x^{2}[/tex] - 10x +10

(-  [tex]\sqrt{x-8}[/tex])^2  = (  [tex]x^{2}[/tex]- 10x +10)^2

this turns into a 4 order polynomial.   I used a solver to find x

x = 8.75884....  approx

so the question asks what is the point at the nearest 1000th,  which is 8.759  

then they ask what is the point at the nearest 100th, which is  

8.76

I'm attaching the graph, if it helps  :P

The value of arcsin(1) is 90° and the value of arctan√3 is 60°

From the question, we are to determine the values of arcsin(1) and arctan√3. That is, sin⁻¹ (1) and tan⁻¹(√3)

NOTE:

If sin x° = y, then sin⁻¹ y = x°

If cos x° = y, then cos⁻¹ y = x°

If tan x° = y, then tan⁻¹ y = x°

From the trigonometry table of values, we have that

sin 90° = 1

∴ sin⁻¹ (1) = 90°

arcsin(1) = 90°

Alos, from the trigonometry table of values, we have that

tan 60° =  √3

∴ tan⁻¹(√3) = 60°

arctan√3 = 60°

Hence, the value of arcsin(1) is 90° and the value of arctan√3 is 60°

Learn more on Evaluating trigonometric functions here: https://brainly.com/question/2254250

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Answer:

10 maybe

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

SUM/COUNT = formula

8+13+15/3

36/3

= 12

CALCULATE THE AREA

=LENGTH X BREADTH

=6M X 1M

[tex]6 {m}^{2} [/tex]

NOW CHANGE THE METRES TO MILLIMETRES

=1000MM=1M

SO,IF 1M=1000MM

THEN 6M=MORE

IF MORE LESS WILL DIVIDE

GIVING YOU

[tex] \frac{6}{1} \times 1000mm[/tex]

[tex]6000mm[/tex]

Answer:

Perimeter = [tex]16\sqrt{5}[/tex]

Area = [tex]80[/tex]

Step-by-step explanation:

To find the perimeter of the square, you can use the square perimeter formula, [tex]P=4a[/tex], where [tex]a[/tex] is equal to the length of one side:

[tex]P=4a[/tex]

[tex]P=4(4\sqrt{5})[/tex]

[tex]P=16\sqrt{5}[/tex]

Then, to find the area of the square, you can use the square area formula, [tex]A=a^2[/tex], where [tex]a[/tex] is equal to the length of one side:

[tex]A=a^2[/tex]

[tex]A=(4\sqrt{5})^2[/tex]

[tex]A=80[/tex]

Therefore, the perimeter of the square is [tex]16\sqrt{5}[/tex] millimeters and the area of the square is [tex]80[/tex] square millimeters.

I hope this helps!

Answer:

D. 8.5

Step-by-step explanation:

The full value of √8 is 8.48528137...

Hope this helped!

the diagram shows a regular dodecagon is the size of one interior angle

Answer:

i really dont know, i need help with it too

Step-by-step explanation:

Answer:

1-30ft (half circle) /60ft (full circle)

2-22in  (half circle) 44in (full circle)

3-19yd  (half circle) 38yd (full circle)

4-12yd  (half circle) 24 yd (full circle)

5-6in  (half circle) 12 in (full circle)

6 34ft  (half circle) 58 (full circle)

Give brainliest :)

Step-by-step explanation:

the answer s correspond to the way the questions are arranged

-2

0

-1

-1

0

Answer:

234 students

Step-by-step explanation:

% Don't ride the bus = 100% - % Ride the bus

Number of students who don't ride the bus :

Answer:

[tex]P(5)=\frac{1}{6}[/tex]

Step-by-step explanation:

Since the number 5 appears once on a 6-sided die, then [tex]P(5)=\frac{1}{6}[/tex]

Answer:

Step-by-step explanation:

1440.

Answer:

C

Step-by-step explanation:

57 is a composite number

Answer:

V = 58.14 ft²

Step-by-step explanation:

the volume (V) of the prism is calculated as

V = Bh ( h is the perpendicular height )

here B = 11.4 and h = 5.1 , then

V = 11.4 × 5.1 = 58.14 ft²

Answer:

V = 58.14 ft³

Step-by-step explanation:

V = B × h

  = 11.4×5.1

  = 58.14 ft³

The random sample is that where every result (student for the case) has the same probability to be selected.

Then you cannot use any method that select one student with preference.

Two possible valid methods are:

- Write the number of each student in separate papers, put all the papers in a closed box and  blind choose 102 papers.

- Assign a number to each student of the school and use a method to generate 102 random numbers.

Answer:

1: 250 000

( There are 1000 metres in a km and 100 cm in a m, thus you multiply 5 km by 100 000 to convert it to cm, then you divide by 2 in order to get the simplist form of the ratio )

Answer:

FA Is the closest so thats your answer.

Step-by-step explanation:

By using trigonometric relations, we see that the horizontal distance is 196.6.

Remember the relation:

tan(a) = (opposite cathetus)/(adjacent cathetus).

In this case, the adjacent cathetus is the horizontal distance between the towers, the opposite cathetus is 40, and the angle is 11.5°.

Then we can write:

tan(11.5°) = 40/x

Solving for x:

x = 40/tan(11.5°)

This is the equation that you got, and it gives:

x = 40/tan(11.5°) = 196.6

Why you don't get this?

The problem may be that your calculator is in radians instead of degrees. It should say "DEG" instead of "RAD" if you want to evaluate trigonometric functions in degrees.

If you want to learn more about right triangles:

https://brainly.com/question/2217700

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By dividing both sides by 3, we conclude that each person gets $6.25.

Here we want to solve the equation:

3n = 18.75

for n.

Remember that if we perform the same operation in both sides of the equality, then the equality remains true.

So here we can divide both sides of the equation by 3, so we get:

(3n)/3 = 18.75/3

n = 18.75/3 = 6.25

n = 6.25

So we can conclude that each one gets $6.25

If you want to learn more about divisions:

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Answer:

its just like doing normal area just work it out then add the different sdhapes areas together

Step-by-step explanation:

Answer:

[tex]\boxed{k = \frac{L^2 + p}{4t}}[/tex]

General Formulas and Concepts:

Algebra I

Basic Equality Properties

Step-by-step explanation:

Step 1: Define

Identify given.

[tex]\displaystyle L = \sqrt{4kt - p}[/tex]

Step 2: Solve for k
We can use equality properties to help us rewrite the equation to get k as our subject:

Let's first square both sides:

[tex]\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}[/tex]

Next, add p to both sides:

[tex]\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}[/tex]

Next, divide 4t by both sides:

[tex]\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}[/tex]

We can rewrite the new equation by swapping sides to obtain our final expression:

[tex]\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}[/tex]

∴ we have changed the subject of the formula.

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Topic: Algebra I

Answer:  

If the two side planks are equal lengths then the answer is 26 1/3.

Answer:

Option B is correct.

Explanation:

Remove the denominators:

[tex]\sf \rightarrow \dfrac{1}{2}x - \dfrac{1}{5} y = 2[/tex]

make the denominator's same

[tex]\sf \rightarrow \dfrac{5}{10}x - \dfrac{2}{10} y = 2[/tex]

Join the fraction's:

[tex]\sf \rightarrow \dfrac{5x-2y}{10} = 2[/tex]

Multiply both sides by 10

[tex]\sf \rightarrow {5x-2y} = 20[/tex]

Remove the denominators:

[tex]\rightarrow \sf x + \dfrac{2}{3}y =5[/tex]

make the denominator's same

[tex]\rightarrow \sf \dfrac{3x}{3} + \dfrac{2}{3}y =5[/tex]

Join the fraction's:

[tex]\rightarrow \sf \dfrac{3x+2y}{3} =5[/tex]

Multiply both sides by 3

[tex]\rightarrow \sf 3x+2y} =15[/tex]

Answer:

B)  5x - 2y = 20  and  3x + 2y = 15

Step-by-step explanation:

Rewrite both equations in standard form:

Equation 1

[tex]\dfrac{1}{2}x-\dfrac{1}{5}y=2[/tex]

Multiply both sides by 10:

[tex]\implies \dfrac{1 \cdot 10}{2}x-\dfrac{1 \cdot 10}{5}y=2 \cdot 10[/tex]

[tex]\implies \dfrac{10}{2}x-\dfrac{10}{5}y=20[/tex]

[tex]\implies 5x-2y=20[/tex]

Equation 2

[tex]x+\dfrac{2}{3}y=5[/tex]

Multiply both sides by 3:

[tex]\implies x \cdot 3+\dfrac{2 \cdot 3}{3}y=5 \cdot 3[/tex]

[tex]\implies 3x+2y=15[/tex]

Therefore, the equivalent system is:

5x - 2y = 20  and  3x + 2y = 15

Answer:

first we all know that minus multiply by minus will give you plus so,

-255-15=-270

Answer:

$980

Step-by-step explanation:

Regular hours- 40 per week

Regular wage- $10/hour

Regular Pay- (40 hours + 40 hours) × $10.00/hour = $800

First week: 43 hours = 40 hours regular + 3 hours overtime

Second week: 49 hours = 40 hours regular + 9 hours overtime

Overtime hours- 3 hours + 9 hours = 12 hours

Overtime wage- $10/hour × 1.5 = $15/hour

Overtime Pay- 12 hours × $15/hour = $180

Gross Pay-​ $800 + $180 = $980

Check the picture below, so the parabola looks more or less like so.

the vertex is always half-way between the focus point and the directrix, and since the parabola is opening downwards, the "p" distance is negative.

[tex]\textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{cases} h=5\\ k=1\\ p=-1 \end{cases}\implies 4(-1)(y-1)~~ = ~~(x-5)^2\implies -4(y-1)=(x-5)^2 \\\\\\ y-1=-\cfrac{1}{4}(x-5)^2\implies y=-\cfrac{1}{4}(x-5)^2 + 1[/tex]