You need to design a rectangle with a perimeter of 14.2 cm. The length must be 2.4 cm. What is the width of the
rectangle? (You might want to draw a picture.)

a) Let w = the width of the rectangle. Write the equation you would use to solve this problem.


b) Now solve your equation
* cm.
The width of the rectangle must be. Cm

Answer:

D. Neither perpendicular nor parallel

Step-by-step explanation:

Let's find the slope (m) of both lines:

✔️Slope (m) of the line that passes through (6, -1) and (11, 2):

Slope (m) = change in y/change in x

Slope (m) = (2 -(-1))/(11 - 6) = 3/5

✔️Slope (m) of the line that passes through (5, -7) and (8, -2)

Slope (m) = change in y/change in x

Slope (m) = (-2 -(-7))/(8 - 5) = 5/3

✅The slope of both lines are not the same, therefore they are not parallel nor same line.

Also, the slope of one is not the negative reciprocal of the other, therefore they are not perpendicular.

Answer:

30

Step-by-step explanation:

Permutation equation: [tex]\frac{n!}{(n-r)!}[/tex]

n = Total number of objects, r = Number of objects selected

[tex]_6P_2=\frac{6!}{(6-2)!}=30[/tex]

Answer:

1. a. 1

2. a. N(10 , 1. 0050)

Step-by-step explanation:

The average time for the people waiting for the bus will be no longer than 15 minutes. There are 33 people who were observed and their waiting time did not exceed 15 minutes. The probability is therefore 1 for the wait time.

Recall the angle sum identity for cosine:

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

cos(x - y) = cos(x) cos(y) + sin(x) sin(y)

==>   sin(x) sin(y) = 1/2 (cos(x - y) - cos(x + y))

Then rewrite the equation as

sin(4x) sin(5x) + sin(4x) sin(3x) - sin(2x) sin(x) = 0

1/2 (cos(-x) - cos(9x)) + 1/2 (cos(x) - cos(7x)) - 1/2 (cos(x) - cos(3x)) = 0

1/2 (cos(9x) - cos(x)) + 1/2 (cos(7x) - cos(3x)) = 0

sin(5x) sin(-4x) + sin(5x) sin(-2x) = 0

-sin(5x) (sin(4x) + sin(2x)) = 0

sin(5x) (sin(4x) + sin(2x)) = 0

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

Rewrite the equation again as

sin(5x) (2 sin(2x) cos(2x) + sin(2x)) = 0

sin(5x) sin(2x) (2 cos(2x) + 1) = 0

sin(5x) = 0   or   sin(2x) = 0   or   2 cos(2x) + 1 = 0

sin(5x) = 0   or   sin(2x) = 0   or   cos(2x) = -1/2

sin(5x) = 0   ==>   5x = arcsin(0) + 2nπ   or   5x = arcsin(0) + π + 2nπ

… … … … …   ==>   5x = 2nπ   or   5x = (2n + 1)π

… … … … …   ==>   x = 2nπ/5   or   x = (2n + 1)π/5

sin(2x) = 0   ==>   2x = arcsin(0) + 2nπ   or   2x = arcsin(0) + π + 2nπ

… … … … …   ==>   2x = 2nπ   or   2x = (2n + 1)π

… … … … …   ==>   x = nπ   or   x = (2n + 1)π/2

cos(2x) = -1/2   ==>   2x = arccos(-1/2) + 2nπ   or   2x = -arccos(-1/2) + 2nπ

… … … … … …    ==>   2x = 2π/3 + 2nπ   or   2x = -2π/3 + 2nπ

… … … … … …    ==>   x = π/3 + nπ   or   x = -π/3 + nπ

(where n is any integer)

Answer:

4

Step-by-step explanation:

Number of Identical small cubes = 27

Determine the largest number of completely red faces of the large cube that he can make

Given that 2 adjacent faces of each cube is painted

and the number of cubes = 27

The number of complete red face Large cube he can make = 4

Answer:

Answer:

7 / 17 ;

10 / 17 ;

5 / 17

Step-by-step explanation:

Guests :

Mother = 1

Aunts = 3

Uncles = 3

Brothers = 4

Male cousin = 1

Female cousin = 5

_________________

Total guests = 17

Since each of the guests have an equal probability of arrival :

Probability that first guest to arrive :

Brother or uncle :

Number of brothers =4

Number of uncles = 3

P(brother or uncle) = required outcome / Total possible outcomes

Required outcome (number of brothers + uncles) = (4 + 3) = 7

Total possible outcomes = total guests = 17

P(brother or uncle) = 7 / 17

2.)

P(brother or cousin) :

Required outcome = (number of brothers + cousins) = (4 + 1 + 5) = 10

Total possible outcomes = total guests = 17

P(brother or cousin) = 10/17

3.)

P(brother or mother) ;

Required outcome = (number of brothers + mother) = (4+1) = 5

Total possible outcomes = total guests = 17

P(brother or mother) = required outcome / Total possible outcomes = 5 / 17

Answer:

378 and 380

Step-by-step explanation:

The two even consecutive numbers that add up to 758 are going to be very close to half of 758. This is because two half of 758 are going to be the most similar addends of 758. This is important because the answers will be consecutive and therefore, must also be very similar. To solve, first, divide 758 by 2. This is 379, which is not an even number. So, to find the needed addends subtract and add 1 to 379. Both of these will be even and consecutive. These two numbers are 378 and 380. Then, to check you, can add them and see that they do sum 758.

Answer:

Step-by-step explanation:

Let the first number = x

Let the second number = x + 2

x + x + 2 = 758                      Collect like terms

2x + 2 = 758                         Subtract 2

2x = 758 - 2                          Combine

2x = 756                                Divide by 2

2x/2 = 756/2

x = 378

The first number is 378

The second number 380

If your teacher is really fussy, you can do it this way.

Let the first number = 2x

Let the second number = 2x + 2

The reason for this is to guarantee that both numbers were even to start with.

2x + 2x+2 = 758                    Combine like terms

4x + 2 = 758                          Subtract 2

4x = 756                                Divide by 4

x = 756/4

x = 189

Therefore 2x = 378

2x + 2 = 380                 Just as before.

√50x³y

= √5²×2×x²×x×y

= 5x√2xy

d is the correct answer

Answer:

here

Step-by-step explanation:

Answer:

0.53%

Step-by-step explanation:

hope it is well understood

Answer:

TRUE

Step-by-step explanation:

I SEEN SOME ONE ELSE WIT 5 STARS SAY SO(:

The given segment can form triangle. Therefore, the given statement is true.

A polygon has three edges as well as three vertices is called a triangle. It's one of the fundamental geometric shapes. In Euclidean geometry, each and every three points that are not collinear produce a distinct triangle and a distinct plane. In other words, every triangle was contained in a plane, and there is only single plane that encompasses that triangle.

All triangles are enclosed in a single plane if all of geometry is the Euclidean plane, however this is no longer true in higher-dimensional Euclidean spaces. Unless when otherwise specified, this article discusses triangles within Euclidean geometry, namely the Euclidean plane. The given segment can form triangle.

Therefore, the given statement is true.

To know more about triangle, here:

https://brainly.com/question/14712269

#SPJ7

Distance = √[ ( 7 - 3 )^2 + ( 2p - 0 )^2 ]

Distance = √(4)^2 + ( 2p)^2

Distance = √16 + 4p^2

As the question said : Distance = √80

√80 = √16 + 4p^2

Thus :

16 + 4p^2 = 80

Subtract both sides 16

16 - 16 + 4p^2 = 80 - 16

4p^2 = 64

Divide both sides by 4

4p^2 ÷ 4 = 64 ÷ 4

p^2 = 16

Thus :

p = 4 or p = - 4

can u plz check if the question is right

Answer:

Yes 7i is the answer

Step-by-step explanation:

they are equivalent.

Answer:

Step-by-step explanation:

New median:40100

New mode:385100

Given:

Consider the below figure attached with this question.

The value in the given figure are:

[tex]a=0.2094539899[/tex]

[tex]b=2.507467975[/tex]

[tex]r^2=0.9435996398[/tex]

[tex]r=0.9713905701[/tex]

To find:

The exponential regression equation for the given values (Rounded to three decimal places).

Solution:

The general form of exponential regression equation is:

[tex]y=a\cdot b^x[/tex]          ...(i)

Where, a is the initial value and b is the growth/decay factor.

The given values are:

[tex]a=0.2094539899[/tex]

[tex]b=2.507467975[/tex]

Round these numbers to three decimal places.

[tex]a\approx 0.209[/tex]

[tex]b\approx 2.507[/tex]

Putting [tex]a=0.209, b=2.507[/tex] in (i) to find the exponential regression equation.

[tex]\hat{y}=0.209\cdot 2.507^x[/tex]

Hence, the correct option is C.

Answer: This quadratic equation has two real solutions.

Step-by-step explanation:

[tex]y=x^{2} -11x+7\\\\D=(-11)^{2} -4 \cdot 7=121-28=93 \: > 0\\\\x=\dfrac{11 \pm \sqrt{93} }{2}[/tex]

Given:

The five number summary of two data sets are given as:

a) 0, 4, 12, 14, 20

b) 2, 8, 14, 18, 20

To find:

The range for the outliers.

Solution:

We know that,

An observation is considered an outlier if it is below [tex]Q_1-1.5(IQR)[/tex]

An observation is considered an outlier if it is above [tex]Q_3+1.5(IQR)[/tex]

Where, IQR is the interquartile range and [tex]IQR=Q_3-Q_1[/tex].

The five number summary of two data sets are given as:

0, 4, 12, 14, 20

Here, [tex]Q_1=4[/tex] and [tex]Q_3=14[/tex].

Now,

[tex]IQR=14-4[/tex]

[tex]IQR=10[/tex]

The range for the outliers is:

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[4-1.5(10),14+1.5(10)][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[4-15,14+15][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[-11,29][/tex]

An observation is considered an outlier if it is below -11.

An observation is considered an outlier if it is above 29.

The five number summary of two data sets are given as:

2, 8, 14, 18, 20

Here, [tex]Q_1=8[/tex] and [tex]Q_3=18[/tex].

Now,

[tex]IQR=18-8[/tex]

[tex]IQR=10[/tex]

The range for the outliers is:

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[8-1.5(10),18+1.5(10)][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[8-15,18+15][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[-7,33][/tex]

An observation is considered an outlier if it is below -7.

An observation is considered an outlier if it is above 33.

let the line between 2 tria be y

sin 60/8√2 = sin 90/y

y=13.06

sin 45/13.06 = sin 90/x

x=18.46

Answer:

First, find the hypotenuse of the right triangle with the 60° & 30°.

[tex]sin(60) = \frac{8\sqrt{2}}{h} \\\\sin(60)h=8\sqrt{2}\\\\\frac{\sqrt{3}}{2} h=8\sqrt{2}\\\\h=\frac{8\sqrt{2}}{\frac{\sqrt{3}}{2}}=8\sqrt{2}*\frac{2}{\sqrt{3}} =\frac{16\sqrt{2} }{\sqrt{3}} =\frac{16\sqrt{2}(\sqrt{3}) }{\sqrt{3}(\sqrt{3})} =\frac{16\sqrt{6} }{3}[/tex]

Use that side length to find x.

[tex]sin(45)=\frac{\frac{16\sqrt{6}}{3}}{x}\\\\sin(45)x=\frac{16\sqrt{6}}{3} \\\\\frac{\sqrt{2}}{2}x=\frac{16\sqrt{6}}{3} \\\\x=\frac{\frac{16\sqrt{6}}{3}}{\frac{\sqrt{2}}{2}}=\frac{16\sqrt{6}}{3}*\frac{2}{\sqrt{2}}=\frac{16\sqrt{2}\sqrt{3}(2)}{3\sqrt{2} }=\frac{32\sqrt{3} }{3}[/tex]

I dont know what you mean by the question but according to me.

If y=x^5

y=x^5+3

Then y+3=x^5+3

Answered by Gauthmath must click thanks and mark brainliest

============================================

Explanation for part (a)

All distances mentioned are in feet.

We'll have a right triangle which allows us to apply the pythagorean theorem. Refer to the diagram below.

a^2+b^2 = c^2

x^2+y^2 = z^2

Apply the derivative to both sides with respect to t. We'll use implicit differentiation and the chain rule.

[tex]x^2+y^2 = z^2\\\\\frac{d}{dt}[x^2+y^2] = \frac{d}{dt}[z^2]\\\\\frac{d}{dt}[x^2]+\frac{d}{dt}[y^2] = \frac{d}{dt}[z^2]\\\\2x*\frac{dx}{dt}+2y*\frac{dy}{dt}=2z*\frac{dz}{dt}\\\\x*\frac{dx}{dt}+y*\frac{dy}{dt}=z*\frac{dz}{dt}\\\\[/tex]

Now we'll plug in (x,y,z) = (4000,3000,5000). The x and y values are given. The z value is found by use of the pythagorean theorem. Ie, you solve 4000^2+3000^2 = z^2 to get z = 5000. Or you could note that this is a scaled copy of the 3-4-5 right triangle.

We know that dx/dt = 0 because the horizontal distance, the x distance, is not changing. The rocket is only changing in the y direction. Or you could say that the horizontal speed is zero.

The vertical speed is dy/dt = 800 ft/s and it's when y = 3000. It's likely that dy/dt isn't the same value through the rocket's journey; however, all we care about is the instant when y = 3000.

Let's plug all that in and isolate dz/dt

[tex]4000*0+3000*800=5000*\frac{dz}{dt}\\\\2,400,000=5000*\frac{dz}{dt}\\\\\frac{dz}{dt} = \frac{2,400,000}{5000}\\\\\frac{dz}{dt} = 480\\\\[/tex]

At the exact instant that the rocket is 3000 ft in the air, the distance between the camera and the rocket is changing by an instantaneous speed of 480 ft/s.

-----------------------------------------------------------------------

Explanation for part (b)

Again, refer to the diagram below.

We have theta (symbol [tex]\theta[/tex]) as the angle of elevation. As the rocket's height increases, so does the angle theta.

We can tie together the opposite side y with the adjacent side x with the tangent function of this angle.

[tex]\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(\theta) = \frac{y}{x}[/tex]

Like before, we'll apply implicit differentiation. This time we'll use the quotient rule as well.

[tex]\tan(\theta) = \frac{y}{x}\\\\\frac{d}{dt}[\tan(\theta)] = \frac{d}{dt}\left[\frac{y}{x}\right]\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{\frac{dy}{dt}*x - y*\frac{dx}{dt}}{x^2}\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{800*4000 - 3000*0}{4000^2}\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{3,200,000}{16,000,000}\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{32}{160}\\\\\sec^2(\theta)*\frac{d\theta}{dt} = \frac{1}{5}\\\\[/tex]

Let's take a brief detour. We'll return to this later. Recall earlier that [tex]\tan(\theta) = \frac{y}{x}\\\\[/tex]

If we plug in y = 3000 and x = 4000, then we end up with [tex]\tan(\theta) = \frac{3}{4}\\\\[/tex] which becomes [tex]\tan^2(\theta) = \frac{9}{16}[/tex]

Apply this trig identity

[tex]\sec^2(\theta) = 1 + \tan^2(\theta)[/tex]

and you should end up with [tex]\sec^2(\theta) = 1+\frac{9}{16} = \frac{25}{16}[/tex]

So we can now return to the equation we want to solve

[tex]\sec^2(\theta)*\frac{d\theta}{dt} = \frac{1}{5}\\\\\frac{25}{16}*\frac{d\theta}{dt} = \frac{1}{5}\\\\\frac{d\theta}{dt} = \frac{1}{5}*\frac{16}{25}\\\\\frac{d\theta}{dt} = \frac{16}{125}\\\\\frac{d\theta}{dt} = 0.128\\\\[/tex]

This means that at the instant the rocket is 3000 ft in the air, the angle of elevation theta is increasing by 0.128 radians per second.

This is approximately 7.334 degrees per second.

The distance from the television camera to the rocket is changing at 480 ft/s while the camera's angle of elevation is changing at 0.128 rad/s

Let x represent the distance from the camera to the rocket and let h represent the height of the rocket.

a)

[tex]x^2=h^2+4000^2\\\\2x\frac{dx}{dt}=2h\frac{dh}{dt} \\\\x\frac{dx}{dt}=h\frac{dh}{dt} \\\\At \ h=3000\ ft, \frac{dh}{dt}=800\ ft/s;\\x^2=3000^{2} +4000^2\\x=5000\\\\\\x\frac{dx}{dt}=h\frac{dh}{dt} \\\\5000\frac{dx}{dt}=3000*800\\\\\frac{dx}{dt}=480\ ft/s[/tex]

b)

[tex]tan(\theta)=\frac{h}{4000} \\\\h=4000tan(\theta)\\\\\frac{dh}{dt}=4000sec^2(\theta)\frac{d\theta}{dt} \\\\\\At\ h=3000\ ft;\\\\tan\theta = \frac{3000}{4000}=\frac{3}{4} \\\\sec^2(\theta)=1+tan^2(\theta)=1+(\frac{3}{4})^2=\frac{25}{16} \\\\\\\frac{dh}{dt}=4000sec^2(\theta)\frac{d\theta}{dt}\\\\800=4000*\frac{25}{16}* \frac{d\theta}{dt}\\\\\frac{d\theta}{dt}=0.128\ rad/s[/tex]

Hence, The distance from the television camera to the rocket is changing at 480 ft/s while the camera's angle of elevation is changing at 0.128 rad/s

Find out more at: https://brainly.com/question/1306506

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Answer:

  (b)  √6 mi

Step-by-step explanation:

Putting the given heights into the formula, we find the difference in distances to be ...

  Adam' horizon distance = √((3/2)(400)) = 10√6 . . . miles

  Pam's horizon distance = √((3/2)(324)) = 9√6 . . . . miles

Then the difference Adam can see is farther than the distance Pam can see by ...

  10√6 -9√6 = √6 . . . miles

Answer:

b

Step-by-step explanation:

ANSWER. EXPLANATION. The given logarithmic function is. The transformation,. stretches the graph of y=f(x) vertically by a factor of c units ...

4 votes

ANSWER[tex]y = - 3 ln(x - 7) [/tex]EXPLANATIONThe given logarithmic function is [tex]f(x) = ln(x) [/tex]The transformation, [tex]y = - cf(x - k)[/tex]stretches

We need to find the percent, let's start but making the equation.

The price is 2.69

The tax cost is 0.13

So what percent of 2.69 is = 0.13.

Equation: X/100 x 2.69 = 0.13

Multiply each side by 100 so we can get x alone with the price: 2.69x = 13

Now to get x alone, we must divide both sides by 2.69: x = 4.8

Finally, we just round 4.8 to the nearest whole number, which is 5 (5 or above give it a shove, 4 or below let it go, we have 8 so we give it a shove). This means that the answer will be 5%.

I hope this helps! :)

Answer: (x, y) = (5,8)

Step-by-step explanation:

x + y = 13       2x - y = 2

y = -x + 13

2x - (-x + 13) = 2   3x =15

x=5

x=5       y = -x + 13

y = -(5) + 13 = 8

Answer:

4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Step-by-step explanation:

Step 1: Define

Identify

2x - (4y - 3) + 5xz

x = -3

y = 2

z = -1

Step 2: Evaluate

Answer:

The correct answer is B. It will take them 7.2 hours.

Step-by-step explanation:

Given that to collect data on the signal strengths in a neighborhood, Briana must drive from house to house and take readings, and she has a graduate student, Henry, to assist her, and Briana figures it would take her 12 hours to complete the task working alone, and that it would take Henry 18 hours if he completed the task by himself, to determine how long will it take Briana and Henry to complete the task together the following calculation must be performed:

1/12 + 1/18 = X

18 / (12 x 18) + 12 / (18 x 12) = X

30/216 = X

5/36 = X

36/5 = 7.2

Therefore, they will be able to finish the task in 7.2 hours.

9514 1404 393

Answer:

  d) Listen to his suggestions to see what might work

Step-by-step explanation:

A supervisor or team leader cannot be expected to know everything, or be completely up-to-date with the latest innovations. A lot of what comprises "best practice" is developed on the job, or propagated by personnel transfers or word of mouth. A different point of view can often be beneficial, planting the seed for a beneficial change, even if the specific suggestion is not workable.

Ursula should pay attention to all of her team members, Tom included.

Answer:

False

Step-by-step explanation:

The point that is equidistant from the vertices of a triangle is called the circumcenter.

9514 1404 393

Answer:

  False

Step-by-step explanation:

The incenter is the center of the inscribed circle, which is tangent to all of the sides of the triangle. The incenter is equidistant from the sides, not the vertices.

_____

Additional comment

The circumcenter is the center of the circumscribing circle. Each of the vertices of the triangle is on the circumcircle, so the circumcenter is equidistant from the vertices.

The incenter is located at the intersection point of the angle bisectors. The circumcenter is located at the intersection point of the perpendicular bisectors of the sides.