(x+y)^2 where x= 4 and y= -3​

Answer:

graph C

Step-by-step explanation:

Amanda needs to have a score higher than 86 on her final.

That means she can't get lower than 86 (Obviously) but not even an 86.

It has to be higher than 86 for her to pass

Let x represent Amanda's score

[tex]x>86[/tex]

Bolded dots on graphs mean that she can have a 86 but if it's not a bolded dot she can have either higher or lower

Just keep that in mind

The answer will be C. because it describes Amanda's score higher than 86

Answer:

c

Step-by-step explanation:

Answer:

1,4,16,64,245,1024

Step-by-step explanation:

a1 =1

an = 4 * an-1

Let n = 2

a2 = 4*a1 = 4*1=4

Let n = 3

a3 = 4*a2 = 4*4 = 16

Let n = 4

a4 = 4*a3 = 4*16 = 64

Let n = 5

a5 = 4*a4 = 4*64 = 256

Let n = 6

a6 = 4*a5 = 4*256 = 1024

Answer:

x > 43

Step-by-step explanation:

Open circle at 43, which means it is not equal to 43

Line goes to the right, which means x is greater than

x > 43

Answer:

B

Step-by-step explanation:

Answer:

75 km

Step-by-step explanation:

Area = Length × Width

= 300m and 250m

= 75000m

M to Km => ÷1000

= 75000m ÷ 1000

= 75 km #

Answer:

3=3 + 10

3 = 13(NO)

x-4y=15

7--8=15

15=15(YES)

Answer:

0,375

Step-by-step explanation:

Divide de 3 percent from 8 percent den u get your answer

Pleasure helping you, hope it was helpful

Answer:

Step-by-step explanation:

4x - 13 = x +  5           Add 13 to both sides

4x = x + 18                 Subtract x

3x = 18                       Divide by 3

x = 6

I'm going to assume that "−" is supposed to be some kind of minus character, so that the given system of DEs is supposed to be

[tex]\begin{cases}\dfrac{\mathrm d^2x}{\mathrm dt^2} + x - y = 0 \\ \dfrac{\mathrm d^2y}{\mathrm dt^2} + y - x = 0 \\ x(0) = 0, x'(0) = -6, y(0) = 0, y'(0) = 1\end{cases}[/tex]

Take the Laplace transform of both sides of both equations. Recall the transform for a second-order derivative,

[tex]L_s\left\{\dfrac{\mathrm d^2f(t)}{\mathrm dt^2}\right\} = s^2 F(s) - sf(0) - f'(0)[/tex]

where F(s) denotes the transform of f(t). You end up with

[tex]\begin{cases}s^2X(s)-sx(0)-x'(0) + X(s) - Y(s) = 0 \\ s^2Y(s) - sy(0) - y'(0) + Y(s) - X(s) = 0\end{cases} \\\\ \begin{cases}(s^2+1)X(s) - Y(s) = -6 \\ (s^2+1)Y(s) - X(s) = 1\end{cases}[/tex]

and solving for X(s) and Y(s) (nothing tricky here, just two linear equations) gives

[tex]X(s) = -\dfrac{6s^2+5}{s^2(s^2+2)} \text{ and } Y(s) = \dfrac{s^2-5}{s^2(s^2+2)}[/tex]

Now solve for x(t) and y(t) by computing the inverse transforms. To start, split up both X(s) and Y(s) into partial fractions.

• Solving for x(t) :

[tex]-\dfrac{6s^2+5}{s^2(s^2+2)} = \dfrac as + \dfrac b{s^2} + \dfrac{cs+d}{s^2+2} \\\\ -6s^2-5 = as(s^2+2) + b(s^2+2) + (cs+d)s^2 \\\\ -6s^2-5 = (a+c)s^3 + (b+d)s^2 + 2as + 2b \\\\ \implies \begin{cases}a+c=0\\b+d=-6\\2a=0\\2b=-5\end{cases} \implies a=c=0, b=-\dfrac52, d=-\dfrac72[/tex]

[tex]\implies X(s) = -\dfrac5{2s^2} - \dfrac7{2(s^2+2)}[/tex]

Taking the inverse transform, you get

[tex]L^{-1}_t\left\{X(s)\right\} = -\dfrac52 L^{-1}_t\left\{\dfrac{1!}{s^{1+1}}\right\} - \dfrac7{2\sqrt2} L^{-1}_t\left\{\dfrac{\sqrt2}{s^2+(\sqrt2)^2}\right\} \\\\ \implies \boxed{x(t) = -\dfrac52 t - \dfrac7{2\sqrt2}\sin(\sqrt2\,t)}[/tex]

• Solving for y(t) :

[tex]\dfrac{s^2-5}{s^2(s^2+2)} = \dfrac as + \dfrac b{s^2} + \dfrac{cs+d}{s^2+2} \\\\ s^2 - 5 = as(s^2+2) + b(s^2+2) + (cs+d)s^2 \\\\ s^2 - 5 = (a+c)s^3 + (b+d)s^2 + 2as + 2b \\\\ \implies \begin{cases}a+c=0\\b+d=1\\2a=0\\2b=-5\end{cases} \implies a=c=0, b=-\dfrac52, d=\dfrac72[/tex]

[tex]\implies Y(s) = -\dfrac5{2s^2} + \dfrac7{2(s^2+2)}[/tex]

Inverse transform:

[tex]L^{-1}_t\left\{Y(s)\right\} = -\dfrac52 L^{-1}_t\left\{\dfrac{1!}{s^{1+1}}\right\} + \dfrac7{2\sqrt2} L^{-1}_t\left\{\dfrac{\sqrt 2}{s^2+(\sqrt2)^2}\right\} \\\\ \implies \boxed{y(t) = -\dfrac52 t + \dfrac7{\sqrt2} \sin(\sqrt2\,t)}[/tex]

Answer:

5 seconds

Step-by-step explanation:

The speed of an object is the rate of distance over time. The value of time (t) at the greatest speed of the ball is at 2 seconds

First, we calculate the speed using:

[tex]Speed = \frac{h(t)}{t}[/tex] --- i.e. distance/time

At t = 0, h(t) = 5

So;

[tex]Speed = \frac{5}{0} = unde fine d[/tex]

At t = 3, h(t) = 12

[tex]Speed = \frac{12}{3} = 4[/tex]

At t = 6, h(t) = 15

[tex]Speed = \frac{15}{6} = 2.5[/tex]

At t = 9, h(t) = 11

[tex]Speed = \frac{11}{9} = 1.2[/tex]

At t = 12, h(t) = 6

[tex]Speed = \frac{6}{12} = 0.5[/tex]

At t = 15, h(t) = 0

[tex]Speed = \frac{0}{15} = 0[/tex]

By comparing the above values, we notice that as time and height increases, the value of speed reduces.

This means that the greatest value of speed will be at the least value of time (t).

From the given options, the least value of time is at:

[tex]t = 2[/tex]

Hence, the value of time (t) at the greatest speed of the ball is at 2 seconds

Read more about speed at:

https://brainly.com/question/7359669

The slope of the line passing through points A and B is

slope = (b ² - a ²) / (b - a) = ((b - a) (b + a)) / (b - a) = b + a

Since this line passes through (0, 3), its equation would be

y - 3 = (b + a) (x - 0)   ==>   y = (b + a) x + 3

It also passes through (-3/2, 0), so that

y - 0 = (b + a) (x + 3/2)   ==>   y = (b + a) x + 3/2 (b + a)

If these equations describe the same line, then they must have the same slope and y-intercept, so that

3 = 3/2 (b + a)   ==>   a + b = 2

It also passes through (a, a ²), so that

a ² = (b + a) a + 3   ==>   a ² = ab + a ² + 3   ==>   ab = -3

Solving for b in the first underlined equation, we get

b = 2 - a

Substituting into the second equation and solving for a gives

a (2 - a) = -3   ==>   2a - a ² = -3   ==>   a ² - 2a - 3 = (a - 3) (a + 1) = 0

==>   a = 3   or   a = -1

==>   b = -1   or   b = 3

Since a < b, we pick a = -1 and b = 3, so the solution is (a, b) = (-1, 3).

According to the given information, we build the equation for the cost. After we build the equation, the equation that relates these measures is:

[tex]C = 0.99 + xy + 0.2z[/tex]

Cost:

0.3 kilograms of tomatoes, at 3.30 dollars per kilogram.

Thus, the cost starts at:

[tex]C = 0.3*3.3 = 0.99[/tex]

y kilograms of cucumbers, at x dollars per kilogram.

Considering this, the cost will now be of:

[tex]C = 0.99 + xy[/tex]

0.2 kilograms of carrots, at z dollars per kilogram:

Now, we have to consider this for the cost, so:

[tex]C = 0.99 + xy + 0.2z[/tex]

A similar example is given at https://brainly.com/question/14544759

Answer:

Maggie is 11 years old

Step-by-step explanation:

let m be Maggie and b be her brother.

[tex]m+b=59[/tex]

[tex]b=4m-6[/tex]

substitute for b.

[tex]m+4m-6=59[/tex]

[tex]5m-6=59[/tex]

add 6 to both sides

[tex]5m=55[/tex]

divide by 5 on both sides

[tex]m=11[/tex]

double check by finding the brother's age by substituting for m

[tex]11+b=59[/tex]

[tex]b=48[/tex]

Answer:

10

Step-by-step explanation:

2(6+1)-|-10|+3*2

First start with the absolute values and parentheses

2(7)-10+3*2

Then multiply from left to right

14 -10 +6

Then add and subtract from left to right

4 +6

10

Answer:

should be 192

Step-by-step explanation:

Answer:

28 and 30

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

8x- 38

Step-by-step explanation:

3(x-6)+5(x-4)

Distribute

3x- 18+5x -20

Combine like terms

3x+5x -18-20

8x- 38

Answer:

[tex]3(x-6)+5(x-4)[/tex]

[tex]3x-18+5x-20[/tex]

[tex]=(3+5)x-(20x+18)[/tex]

Add:- 3+5= 8, and 20+18= 38

[tex]=8x-38[/tex]

OAmalOHopeO

Step-by-step explanation:

2., 3., 4., 5.

yes, you had the right idea to calculate the half distances between the coordinates. just create the absolute values of the full distance before cutting it in half.

you need to remember : we have to go this half distance from one point to the other (meaning adding our subtracting the half distance to/from the starting point).

2.

(-4, 6) to (10, -10)

in x the distance is 10 - -4 = 14. half is 7.

in y the distance is |-10 - 6| = |-16| = 16. half is 8.

so the midpoint is

(-4 + 7, 6 - 8) = (3, -2)

remember, to go the half distance in the direction towards the second point (so we have to choose properly, when to use "+" and "-" depending on the change of the coordinate : from -4 to 10 we have to add, from 6 to -10 we have to subtract, of course).

3.

(-3, -8) to (-6.5, -4.5)

in x distance : -3 - -6.5 = 3.5. half is 1.75

in y distance : -8 - -4.5 = |-3.5| = 3.5. half is 1.75

midpoint is

(-3 - 1.75, -8 + 1.75) = (-4.75, -6.25)

4.

(3, 7) to (-8, -10)

x : 3 - -8 = 11. half is 5.5

y : 7 - -10 = 17. half is 8.5

midpoint is

(3 - 5.5, 7 - 8.5) = (-2.5, -1.5)

5.

(-6, -13) to (-6.4, -3.8)

x : -6 - -6.4 = 0.4. half is 0.2

y : -13 - -3.8 = |-9.2| = 9.2. half is 4.6

midpoint is

(-6 - 0.2, -13 + 4.6) = (-6.2, -8.4)

6.

(-1, 7) to (5, 1)

x : -1 - 5 = |-6| = 6. 1/3 is 2.

y : 7 - 1 = 6. 1/3 is 2.

1/3 from C to D

(-1 + 2, 7 - 2) = (1, 5)

7.

2/3 of the way from D to C is the same point as in 6. (1/3 from C to D).

again

(1, 5)

8.

2/3 of the way from C to D.

so, we need to double what we added in 6.

(-1 + 4, 7 - 4) = (3, 3)

9.

1/3 of the way from D to C is the same point as in 8. (2/3 of the way from C to D).

again

(3, 3)

10.

exactly. Pythagoras.

the square root of the sum of the squares of the coordinate differences.

distance = sqrt((x1 - x2)² + (y1 - y2)²)

11.

(6, 8) to (-1, 8)

distance = sqrt((6 - -1)² + (8 - 8)²) = sqrt(49) = 7

12.

(5, -6) to (5, 6)

sqrt((5-5)² + (-6-6)²) = sqrt(144) = 12

13.

(-2, 0) to (11, 0)

sqrt((-2 - 11)² + (0-0)²) = sqrt(169) = 13

14.

(1, -5) to (9, 1)

sqrt((1-9)² + (-5 - 1)²) = sqrt(64 + 36) = sqrt(100) = 10

15.

ST and MT are basically the same equation.

MT is half of ST.

ST equation based on 2 points :

y – yS={(yT – yS)/(xT – xS)}(x – xS)

M = (xS + (xT - xS)/2, yS +(yT - yS)/2)

so, let's put that into the general equation :

y - yM={(yT - yM)/(xT - xM)}(x - xM)

y - (yS +(yT - yS)/2) = {(yT - (yS +(yT - yS)/2))/(xT - (xS + (xT - xS)/2))}(x - (xS + (xT - xS)/2))

16.

the two corners farthest away are (5, 10) and (9, 6).

what distance from (0, 0) is now bigger ?

since it is (0, 0), we can skip the 0s and just sum up the squares of the coordinates.

5² + 10² = 125

9² + 6² = 117

so, the corner (5, 10) is the farthest away.

Answer:

Step-by-step explanation:

I assume the sequence is 0, 2, 4, 6

nth term = 2(n-1)

9514 1404 393

Answer:

  (b)  4

Step-by-step explanation:

The point (3, 4) is a "hole" in the graph. The function approaches the value y=4 from either direction, so that is the limit as x → 3.

  [tex]\displaystyle\lim_{x\to3}f(x)=4[/tex]

Answer:

-1

Step-by-step explanation:

Pick two points on the line

(0,2) and (2,0)

Using the slope formula

m = ( y2-y1)/(x2-x1)

    = ( 0-2)/(2-0)

    = -2/2

  = -1

Answer:

-1

Step-by-step explanation:

Use two points on the line to find the slope, using rise over run.

We can use the points (0, 2) and (2, 0).

From the first point to the other, the y value decreases by 2 and the x value increases by 2.

Use rise (change in y value) over run (change in x value):

-2 / 2

= -1

So, the slope is -1.

[tex]\\ \sf\longmapsto 0.9(7x+14)=1.5-(x+2)[/tex]

[tex]\\ \sf\longmapsto 6.3x+12.6=1.5-x-2[/tex]

[tex]\\ \sf\longmapsto 63x+12.6=-x-0.5[/tex]

[tex]\\ \sf\longmapsto 63x+x=-0.5-12.6[/tex]

[tex]\\ \sf\longmapsto 64x=-13.1[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{-13.1}{64}[/tex]

[tex]\\ \sf\longmapsto x=0.2[/tex]

Pls Tell question corretly

Divide 1 by 4 to get a decimal:

1 / 4 = 0.25

Multiply by 100 to get percent:

0.25 x 100 = 25%

Answer: 25%

Points scored by dan = 1/4

Percentage = 1/4×100

= 25%

Therefore he scored 25% of total points.

Must click thanks and mark brainliest

Answer:

Please attach a picture or more details about "each model" so we can help you!

Step-by-step explanation:

Answer:

2000*pi

Step-by-step explanation:

Shaded area= Area of bigger circle - Area of smaller circle

Shaded area= pi*(60)^2-pi*(40)^2=(60+40)(60-40)*pi=2000*pi

Answer:

23.6

Step-by-step explanation:

cos38=x/30

x= 30cos38= 23.6 (nearest tenth)

Answer:

first term (a1) = 3/2

common difference (d) = 7/4-3/2 = 1/4

Answer:

5.45 * 10^7

Step-by-step explanation:

[tex](4.8 * 10^7) +6,500,000[/tex]

= [tex](4.8 * 10^7) + 6.5 * 10^6[/tex]

= [tex](4.8 * 10^7) + (0.65 * 10^7)[/tex]

= [tex]5.45 * 10 ^7[/tex]

Answer:

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