Answers
Infared = used by police
gamma = short wavelength
radio = largest wavelength
visible = only ones we can see
Answer: police use infred waves,
radio waves have largest wave length, the
only part of the spectrum seen by humans is visible waves
gamma waves have shortest wave length
Explanation:
Related Questions
In which of the following cases is the displacement's magnitude half the distance traveled?
a. 24 steps east followed by 12 steps west
b. 5 steps east followed by 25 steps west
c. 7 steps east followed by 28 steps west
O d. 9 steps east followed by 3 steps west
e. 13 steps east followed by 4 steps west
c
Answers
Answer:
a. 24 steps east followed by 12 steps west
Explanation:
displacement is how much you distance you moved from the starting point so in this example 12 steps even though you move 36 steps all together.
Which statement does not describe brainstorming?
A Keep a record of ideas.
B Keep criticism of other's ideas to yourself.
C Collect only a few ideas.
D Use all of the information found when researching
Answers
Answer:
d
Explanation:
i just know (pls check out my question pls i will give nayone who answers brainiest)
Part One: Defining the Problem and Sub-Problems
Choose one of the real-world problems about natural resources to research. Explain which one you chose here.
Research this problem to learn more about it. Use the research tools given in the lesson if you need help.
After you have researched the problem, explain in your own words who the problem impacts and why it is important.
List two sub-problems that are part of the bigger problem but are more manageable and solvable.
Explain how these sub-problems are related to or a direct result of the overall problem.
Part Two: Criteria, Constraints, and Prioritizations
Choose one sub-problem that you will investigate further and explain which one you chose here.
List two realistic criteria for the sub-problem.
Explain why it is important for these criteria to be met in order to solve the problem.
List two constraints for the sub-problem.
Explain why these constraints exist. (How do they limit solutions to the problem?)
Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.
Ranking Criteria or Constraint Reason for Prioritization
1
2
3
4
Part Three: Generate Solutions
List two solutions that you have generated for the chosen sub-problem.
Describe how the sub-problem can be solved, and include the research supporting each solution.
Explain how prioritization was involved in designing each solution.
Explain how both solutions to the sub-problem play a role in solving the larger problem.
List of the sources (at least three) you used for research, following the MLA style guide.
Answers
Answer:
Part One: Defining the Problem and Sub-Problems
1. Choose one of the real-world problems about natural resources to research. Explain which one you chose here.
o I chose pollution, due to the overwhelming pollution in todays day and age.
2. Research this problem to learn more about it. Use the research tools given in the lesson if you need help.
o There are 4 main types of pollution Air Pollution, Water Pollution, Soil Pollution, Noise Pollution.
o Air pollution refers to the release of harmful contaminants into the earth’s atmosphere.
o Water pollution is said to occur when toxic pollutants and particulate matter are introduced into water bodies such as lakes, rivers and seas.
o Soil pollution, also called soil contamination, refers to the degradation of land due to the presence of chemicals or other man-made substances in the soil.
o Noise pollution refers to the excessive amount of noise in the surrounding that disrupts the natural balance.
o Pollution is harmful things within an environment, that can cause decay within an environment.
3. After you have researched the problem, explain in your own words who the problem impacts and why it is important.
o It impacts the environment, people, animals, water, food, and the atmosphere. Its important to try and stop pollution to- a. make the world a cleaner place and b. stop such harmful substance from killing the environment around us.
4. List two sub-problems that are part of the bigger problem but are more manageable and solvable.
o Man made factories, cars, and garbage dumps.
o Being a litter bug (throwing trash on the ground).
5. Explain how these sub-problems are related to or a direct result of the overall problem.
o Cars create air pollution, along with factories. With being a litter bug and garbage dumps it causes soil pollution.
Part Two: Criteria, Constraints, and Prioritizations
1. Choose one sub-problem that you will investigate further and explain which one you chose here.
o Cars/fuel
2. List two realistic criteria for the sub-problem.
o Reducing fuel and oil can help fix the problem.
o Also using more electric ways to charge the car to run could be based off solar power to create a better environment.
3. Explain why it is important for these criteria to be met in order to solve the problem.
o It would create less air pollution, and could help with sickness, plants dying, and animals dying.
4. List two constraints for the sub-problem.
o Electric cars are a bit to expensive for the average person.
o People need to drive for work/travel, so they need gas for their car and due to the higher priced cars, it makes it almost impossible for this goal to be reached.
5. Explain why these constraints exist. (How do they limit solutions to the problem?)
o They exist due to the underpayment of workers and the average and below average social class. As for limiting the solutions, that is currently happening due to two oil factories shutting down raising the price on gas and limiting more gas for people. But causing more global panic/ angry people, due to not being able to receive what they need to continue their life by driving.
6. Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.
Ranking Criteria or Constraint Reason for Prioritization
1. Fuel and oil Its highly needed to run cars but causes sever pollution.
2. Prices for electric cars We could possibly have less pollution though its too expensive to afford a car that runs off electric. Because it may reduce pollution but the average paid person couldn’t afford it.
3. Under payment Within underpayment it causes more fuel and oil to be used in older cars that cant use electric charging.
4. Solar powered electric charge stations Low pollution and easily earth friendly acceptable.
Part Three: Generate Solutions
1. List two solutions that you have generated for the chosen sub-problem.
o Lowering prices on electric cars.
o Creating solar powered charge stations to reduce more pollution.
2. Describe how the sub-problem can be solved, and include the research supporting each solution.
o Lowering prices on electric cars and creating less fuel and oil providing cars could reduce pollution dramatically due to the burning fuels not polluting the air. And along with lowering car prices creating a solar energy charge station creates a more natural charge station instead of causing soil pollution with factories and under ground pipes.
3. Explain how prioritization was involved in designing each solution.
o Lowering prices on electric cars and creating less fuel and oil providing cars could reduce pollution dramatically due to the burning fuels not polluting the air.
4. Explain how both solutions to the sub-problem play a role in solving the larger problem.
o Both of my solutions would stop both soil and air pollution when it comes to cars and factories.
Hi I need the answer to this please
Answers
Answer:
its A
Explanation:
because that's how reality works
Answer:
B
Explanation:
thermal energy (heat) flows from a highest to lowest
A satellite is a large distance from a planet, and the gravitational force from the planet is the only significant force exerted on the
satellite. The satellite begins falling toward the planet, eventually colliding with the surface of the planet. As the satellite falls,
which of the following claims is correct about how the force that the planet exerts on the satellite Fps changes and how the force
that the satellite exerts on the planet Fsp changes, if at all? What reasoning supports this claim?
A
Fps and Fs both increase. The gravitational forces that two objects exert on one another decrease as the
separation between the objects increases, and these forces are always equal in magnitude.
B
Fps increases while Fsp remains constant. The gravitational force exerted by a planet on a satellite decreases
as the separation between the two objects increases, and the force exerted by the satellite on the planet remains
negligibly small.
с
Fps remains constant while Fgp increases. The gravitational force exerted by a planet on a satellite is a constant
equal to the weight of the satellite, and the gravitational force exerted by the satellite on the planet decreases as
the separation between the two objects increases.
D
Fps and Fs both remain constant
. The gravitational forces that a planet and a satellite exert on one another is a
constant equal to the weight of the satellite.
Answers
Answer:
None of the provided reasoning correct.
Explanation:
Let d be the distance between the center of the planet having mass M and the satellite having mass m.
The gravitational force acting between the planet and the satellite is
[tex]F= \frac {GMm}{d^2}\cdots(i)[/tex]
where G is the universal gravitational constant, d is the distance between the center of two bodies having masses M and m.
This gravitational force, F, is the mutual force between both the objects, so
[tex]F=F_{ps}=F_{sp}[/tex]
Where [tex]F_{ps}[/tex]: the force that the planet exerts on the satellite and
[tex]F_{sp}[/tex] the force that the satellite exerts on the planet.
So, from equation (i),
[tex]F_{ps}=F_{sp}=\frac {GMm}{d^2}\cdots(ii)[/tex]
As the satellite is falling towards the planet, to the distance, d, between the center of the planet and satellite is decreasing.
Now, from equation (ii), as [tex]F_{ps}[/tex] and [tex]F_{sp}[/tex]are inversely proportional to [tex]d^2[/tex]. So, both [tex]F_{ps}[/tex] and [tex]F_{sp}[/tex] increase on decreasing d.
Hence, both [tex]F_{ps}[/tex] and [tex]F_{sp}[/tex] increase as the gravitational forces that two objects exert on one another increases as the separation between the objects decreases, and these forces are always equal in magnitude.
None of the provided reasoning correct.
Which method of heat transfer transmits heat from the lower layers of air to the upper layers of air as the lower layers of air warm up and rise and replace the upper layers of air that cool off and sink down?
Answers
Answer:
Convection
Explanation:
The method of heat transfer that allows heat to rise via vertical transport of heated part of a fluid (gas or liquid) and replace the fluid upper layers is called "convection"
Answer:
Convection
Explanation:
Its Convection
Which substance is the stronger base?
Milk of Magnesia
Sodium Bicarbonate
Ferrous Hydroxide
Distilled Water
Answers
Answer:
Ferrous Hydroxide
Explanation:
What is the wavelength of an FM radio wave of frequency 90Mhz?
a) 0.033m
b) 0.3m
c) 3.3m
d) 30m
Show calculation
Answers
Answer:
3.3m
Explanation:
Given parameters:
Frequency = 90Mhz
Unknown:
Wavelength = ?
Solution:
To find the wavelength, use the expression below;
V = f x wavelength
V is the speed of light = 3 x 10⁸m/s
f is the frequency
Now;
Insert the parameters
3 x 10⁸ = 90 x 10⁶ x wavelength
Wavelength = [tex]\frac{3 x 10^{8} }{9 x 10^{7} }[/tex] = 3.3m
A 5100 kg rocket almost in orbit and traveling horizontally is propelled by a thrust force of 7450 Newtons. How fast is it accelerating while the force is applied? ROUND YOUR ANSWER TO THE NEAREST TENTH DECIMAL PLACE (TEKS 4D)
Answers
Answer:
[tex]a=1.46\ m/s^2[/tex]
Explanation:
Given that,
Mass of a rocket, m = 5100 kg
Thrust force acting on the rocket, F = 7450 N
We need to find the acceleration of the rocket. The net force acting on an object is given by the formula as follows :
F = ma
a is acceleration of the rocket
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{7450}{5100}\\\\a=1.46\ m/s^2[/tex]
So, the acceleration is [tex]1.46\ m/s^2[/tex].
A baseball is hit with an initial velocity of 49 meters per second at an angle of 30 degrees. What is the velocity of the ball in the X direction and what is the velocity of the ball in the y direction?
Answers
Answer:
Higher launch angles have greater times in the air
The time in air is determined by the initial vertical velocity. Since steeper launch angles have a larger vertical velocity component, increasing the launch angle increases the time in air.
Explanation:
Higher launch angles have greater times in the air
The time in air is determined by the initial vertical velocity. Since steeper launch angles have a larger vertical velocity component, increasing the launch angle increases the time in air.
A 120-kg roller coaster cart is being tested on a new track, and a crash-test dummy is loaded into it. The roller coaster starts from rest at point A which is 35 m above the ground. The cart is observed to roll down the track to point B, which is 10 m above the ground. In your own words, what physics ideas would you be able to use to predict how fast the cart is moving at point B? What calculations would you use, what things would you be measuring, and what physics principles or laws would you use to make this calculation?
Answers
Answer:
v₂ = 22.13 m/s
We need to measure heights of both points and the law of conservation of energy is applied to measure this speed.
Explanation:
In order to find the speed at the point B, we will use the Law of conservation of energy between points A and B to get the required results, as follows:
Total Energy of Cart at Point A = Total Energy of Cart Point B
K.E at A + P.E at A = K.E at B + P.E at B
(1/2)mv₁² + mgh₁ = (1/2)mv₂² + mgh²
(1/2)m(v₁² - v₂²) = mg(h₂ - h₁)
(1/2)(v₁² - v₂²) = g(h₂ - h₁)
where,
v₁ = velocity of cart at Point A = 0 m/s
v₂ = Velocity of Cart at Point B = ?
h₁ = height of point A relative to the ground = 35 m
h₂ = height of point B relative to the ground = 10 m
g = 9.8 m/s²
Therefore,
(1/2)[(0 m/s)² - v₂²] = (9.8 m/s²)(10 m - 35m)
- v₂² = - (2)(245 m²/s²)
v₂ = √(490 m²/s²)
v₂ = 22.13 m/s
We need to measure heights of both points and the law of conservation of energy is applied to measure this speed.
explain the Kepler s law of planetary motion
Answers
Which safety rule is MOST important when smelling the product of a chemical reaction?
Group of answer choices
Keep nose directly above open container.
Hold with tongs
Wear closed -toed shoes.
use a wafting motion.
Answers
Answer:
group of answer choices
Explanation:
What is the magnitude of the applied electric field inside an aluminum wire of radius 1.5 mm that carries a 5.5-A current?
Answers
Answer:
E = 2.17 x 10⁻² V/m
Explanation:
First we will find out the current density by using the formula:
J = I/A
where.
J = Current Density = ?
I = Current = 5.5 A
A = Cross-Sectional Area = πr² = π(1.5 x 10⁻³ m)² = 7.068 x 10⁻⁶ m²
Therefore,
J = 5.5 A/7.068 x 10⁻⁶ m²
J = 0.778 x 10⁶ A/m²
Now, we calculate the magnitude of applied field:
E = ρJ
where,
E = Magnitude of applied field = ?
ρ = resistivity of Aluminum = 2.8 x 10⁻⁸ Ω.m
Therefore,
E = (2.8 x 10⁻⁸ Ω.m)(0.778 x 10⁶ A/m²)
E = 2.17 x 10⁻² V/m
A car accelerates at a rate of 8.8 m/s2 with a force from the tires of 11,968 N.
What is the mass of the car?
Answers
Answer:
1360 kgExplanation:
The mass of the car can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{11968}{8.8} \\ [/tex]
We have the final answer as
1360 kgHope this helps you
Answer:
[tex]\displaystyle 1360\:kg.[/tex]
Explanation:
[tex]\displaystyle am = F_{net} \\ \\ \frac{11968}{8,8} = \frac{8,8m}{8,8} \\ \\ \boxed{1360 = m}[/tex]
I am joyous to assist you at any time.
Find the y-component of this
vector:
Answers
Answer:
Dy = 49.01 [m]
Explanation:
The vertical component of the vector can be determined with the sine of the angle.
Dy = 92.5*sin(32)
Dy = 49.01 [m]
A block of wood weighs 160 N and has a specific gravity of 0.60. To sink it in fresh water requires an additional downward force of:_______A. 54N B. 64N C. 96N D. 110N E. 240N
Answers
Answer:
Your answer is: D) 110N
Hope this helped : )
Explanation:
In order for the wood to sink, it's specific gravity must equal 1 (or greater).
Specific gravity = .6 kg/m^3= Mass/volume
F (Newtons or kg x m/s^2) = Mass*9.8m/s^2.
Therefore, Mass = 160 N / 9.8 m/s^2= 16.32 kg
Volume = Mass/Specific Gravity = 16.32kg/.6 kg/m^3 = 27.2 m^3
Desired Specific gravity = 1 = (Mass + additional force/9.8m/s^2)/Volume = (16.32 kg +X / 9.8m/s^2)/27.2m^3
Solving for the additional force: X = 106.66...N
The answer is D, 110 N will be required to sink the block of wood.
Which statements describe independent assortment? Check all that apply. Independent assortment occurs during meiosis II. Independent assortment happens during fertilization. Independent assortment results in different combinations of genes in sex cells. Independent assortment makes offspring identical to their parents. Independent assortment occurs when chromosomes randomly line up in the middle of the cell.
Answers
Answer:
The CORRECT answer is:
C. Independent assortment results in different combinations of genes in sex cells.
E. Independent assortment occurs when chromosomes randomly line up in the middle of the cell.
The statements describe independent assortment are Independent assortment results in different combinations of genes in sex cells and Independent assortment occurs when chromosomes randomly line up in the middle of the cell.
The correct options are C and E.
What is independent assortment?The Principle of Independent Assortment depicts how various qualities autonomously separate from each other when regenerative cells create. Free combination of qualities and their comparing attributes was first seen by Gregor Mendel in 1865 during his investigations of hereditary qualities in pea plants.
So, Independent assortment results in different combinations of genes in sex cells.
Also, Independent assortment occurs when chromosomes randomly line up in the middle of the cell.
Thus, correct options are C and E.
Learn more about independent assortment.
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A student is walking back up the hill from the field to the school building. His
friends are slow, so he stops for a moment to wait for them to catch up. Once
they do, the group heads to class. Pick the graph that correctly shows the
motion in the story.
с
Distance from
home
Distance from
home
Time
Time
A
O
B
is in
Tim
Time
Answers
Answer:
Time cause it's so long ago I was just
1000-kg car travelling down on a steepest road, which has inclined angle of 18
degree. Coefficient of kinetic friction is 0.3.
Calculate
1. Weight (force due to gravity).
2.Horizontal and vertical component of the weight
3. Normal force
4.Friction force
5. Net force along the plane down
6. Acceleration
Answers
Answer:
1
Explanation:
it was thinking about how much and then the other than you can get it would be able to ask her to be able and then the way you have been sent from your browser
A syringe has a fine needle with an inside diameter of 109μm. The barrel has a diameter of 2.22cm and is filled with water. Calculate the velocity of water as it squirts horizontally from the needle if you apply a force of 3.24N onto the plunger. (Hint: you may approximate the area of the barrel to be much larger than the area of the needle).
Answers
Answer: the velocity of water as it squirts horizontally from the needle is 4.09196 m/s
Explanation:
Given that;
inside diameter = 109μm
barrel diameter = 2.22 cm so r = 1.11 cm = 0.0111 m
force fair = 3.24 N
We know that the inside diameter is neglected; from the Bernoulli's equation
so
P_inside + 1/2pv²_inside + egy_inside = P_outside + 12pv²_outside + egy_outside
p_inside - p_outside = 1/2e_airv²outside = Fair / Abannel
Fair = 1/2painv²outside . Abannel
therefore
3.24 = 1/2(1000) v²outside (πr²)
3.24 = 1/2(1000) v²outside (π × (0.0111)²
3.24 = 0.1935 v²_outlet
v²_outlet = 3.24 / 0.1934
v²_outlet = 16.7441
v_outlet = √16.7441
v_outlet = 4.09196 m/s
Therefore the velocity of water as it squirts horizontally from the needle is 4.09196 m/s
If a leaf falls from a tree, has work been done on the leaf? Explain.
Answers
Answer:
Hope this helps!
If a leaf falls from a tree, has work been done on the leaf, yes gravity do positive work and restive force do negative work.
What is work?
Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance travelled for a constant force directed in the direction of motion.
When the force has a component that is parallel to the displacement, positive work results. A system gains energy via constructive effort. When the force contains a component that is opposed to or against the displacement, negative work results. Energy is removed from the system or lost through negative labor.
If a leaf falls from a tree, has work been done on the leaf, yes gravity do positive work and restive force do negative work.
To learn more about work refer to the link:
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The equation of a transverse wave traveling along a string is given by y=0.3sin (0.5x-50t) find the maximum displacement of the particles for the equilibrium position
Answers
Answer:
0.3cm
Explanation:
Y = 0.3 sin(0.5x - 50t) compare with,
y = A sin(kx - wt)
A = 0.3m
A mason stretches a string between two points 70 ft apart on the same level with a tension of 20 lb at each end. If the string weighs 0.18 lb, determine the sag h at the middle of the string.
Answers
Answer:
Explanation:
Let tension be T in each string . Let angle with horizontal be θ in the middle
The sum of vertical components of tension of two string will balance the weight
2Tsinθ = mg
2 x 20 sinθ = .18
sinθ = .18 / 40 = .0045
θ = .25783 degree
If sag be y
y / 70 = tan .25783
y = 70 x tan.25783
= .3150 m
= 31.50 cm .
Nicole is making smoothies. She uses 1.2 kilograms of
apples and 600 grams of strawberries. How many
kilograms of fruit does Ann use in all?
I
Answers
Answer:
1.8 kg
Explanation:
Nicole is making smoothies. She uses 1.2 kilograms of apples and 600 grams of strawberries.
1.2 kg = 1200 gram
600 grams
Now,
1200 + 600 = 1800 gram
1800 gram = 1.8 kg
Thus, 1.8 kilograms of fruit does Ann use in all
-TheUnknownScientist
check the correctness of formula t=2π √m/k, dimensionally
Answers
Hi there! Lets see!
m is mass, and its units are kgk is the elastic constant measured in newtons per meter (N/m), or kilograms per second squared kg/s²Therefore:
[tex]\sqrt{\dfrac{m}{k}} =\sqrt{\dfrac{[kg]}{[\dfrac{kg}{s^2}]}} =\sqrt{\dfrac{[kg]}{[kg]}\cdot s^2} = \sqrt{[s]^2} = s[/tex]
The period is given in seconds so the formula is dimensionally correct.
When a 5.0 kg box is hung from a spring, the spring stretches to 50 mm beyond its relaxed length. (a) In an elevator accelerating upward at 2.0 m/s2 , how far does the spring stretch with the same box attached? (b) How fast and in which direction should the elevator accelerate for the spring stretch to be zero (that is, the spring returns to its relaxed length)?
Answers
Answer:
a) the spring will stretch 60.19 mm with the same box attached as it accelerates upwards
b) spring will be relaxed when the elevator accelerates downwards at 9.81 m/s²
Explanation:
Given that;
Gravitational acceleration g = 9.81 m/s²
Mass m = 5 kg
Extension of the spring X = 50 mm = 0.05 m
Spring constant k = ?
we know that;
mg = kX
5 × 9.81 = k(0.05)
k = 981 N/m
a)
Given that; Acceleration of the elevator a = 2 m/s² upwards
Extension of the spring in this situation = X1
Force exerted by the spring = F
we know that;
ma = F - mg
ma = kX1 - mg
we substitute
5 × 2 = 981 × X1 - (5 ×9.81 )
X1 = 0.06019 m
X1 = 60.19 mm
Therefore the spring will stretch 60.19 mm with the same box attached as it accelerates upwards
B)
Acceleration of the elevator = a
The spring is relaxed i.e, it is not exerting any force on the box.
Only the weight force of the box is exerted on the box.
ma = mg
a = g
a = 9.81 m/s² downwards.
Therefore spring will be relaxed when the elevator accelerates downwards at 9.81 m/s²
The extension of the spring in the elevator is 60 mm.
For the extension of the spring to be zero, the elevator must be moving downwards under free fall.
The given parameters;
mass of the box, m = 5 kgextension of the spring, x = 50 mm = 0.05 mThe spring constant is calculated as follows;
F = kx
mg = kx
[tex]k = \frac{mg}{x} \\\\k = \frac{5 \times 9.8}{0.05} \\\\k = 980 \ N/m[/tex]
The tension on the spring in an elevator accelerating upwards is calculated as follows;
T = mg + ma
T = m(g + a)
T = 5(9.8 + 2)
T = 59 N
The extension of the spring is calculated as follows;
[tex]T = kx\\\\x = \frac{T}{k} \\\\x = \frac{59}{980} \\\\x = 0.06 \ m\\\\x = 60 \ mm[/tex]
For the extension of the spring to be zero, the elevator must be under free fall, such that the tension on the spring is zero.
For free fall, a = g
T = m(g - a) = 0
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A 40g bullet traveling at 450 m/s passed through a board and comes out traveling 300m/s. The board is 7.6cm thick. What is the force of friction applied by the wood to the bullet?
Answers
Answer:
f = 29605.2 [N]
Explanation:
To solve this problem we must use the following equation of kinematics, then use Newton's second law.
[tex]v_{f}^{2} =v_{o}^{2} -2*a*x[/tex]
where:
Vf = final velocity = 300 [m/s]
Vo = initial velocity = 450 [m/s]
a = acceleration [m/s²]
x = distance = 7.6 [cm] = 0.076 [m]
Now replacing and clearing a
2*a*0.076 = (450² - 300²)
a = 740131.57 [m/s²]
Now using Newton's second law which tells us that the force on a body is equal to the product of mass by acceleration.
f = m*a
where:
f = friction force [N]
m = mass = 40 [g] = 0.04 [kg]
f = 0.04*740131.57
f = 29605.2 [N]
How much work does a supermarket checkout attendant do on a can of soup he pushes 0.600 m horizontally with a force of 5.00 N?
Answers
state newton's three laws of motion
Answers
I. Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it.
Ex: You roll a ball. It slows down by friction.
II. Acceleration is produced when a force acts on a mass. The greater the mass (of the object being accelerated) the greater the amount of force needed (to accelerate the object).
Ex: You cannot kick a brick wall down, but you can kick a soccer ball because the brick wall is more massive.
III. For every action there is an equal and opposite re-action.
Ex:when a rocket lifts off, the rocket's action is to push down on the ground with the force of its engines, and the reaction is that the ground pushes the rocket upwards with an equal force.
