How do I solve this problem: 6c - 8 - 2c = -16
Answer:
c = -2
Step-by-step explanation:
6c-8-2c = -16
4c -8 =-16
4c = -16 +8
4c = -8
4c/4 = -8/4
c = -2
Answred by Gauthmath
The solution of the equation 6c - 8 - 2c = -16 is -2 calculated by combining like terms and isolating the variable then dividing the equation by coefficient of the c variable.
To solve the equation 6c - 8 - 2c = -16, isolate the variable c on one side of the equation.
Combine like terms on the left side of the equation:
6c - 2c = 4c
The equation now becomes:
4c - 8 = -16
Take constant term on the right side of the equation by adding 8 to both sides:
4c - 8 + 8 = -16 + 8
The equation simplifies to:
4c = -8
To find the value of c, divide both sides of the equation by 4:
4c / 4 = -8 / 4
c = -2
Hence, the value of c is -2 in the equation 6c - 8 - 2c = -16.
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4.
The table shows the estimated number of deer living in a forest over a five-year period. Are the data best represented by a linear, exponential, or quadratic model? Write an equation to model the data.
A. quadratic; y = 0.62x2 + 89
B. exponential; y = 89 • 0.62x
C. linear; y = 0.62x + 89
D. quadratic; y = 89x2 + 0.62
Answer:
B. exponential; y = 89 • 0.62x
Step-by-step explanation:
Answer:
exponential; y = 89 • 0.62^x
...............................................................................................................................................
Answer:
Option B exponential y = 89 · 0.62x
Step-by-step explanation:
The table shows the estimated number of deer living in a forest over a five year period.
Year Number of deers
0 89
1 55
2 34
3 21
4 13
Now we have to find the model representing this situation. Difference in number of deer, in the forest.
We can see there is a common ratio between each successive term r = = 0.618
r = = 0.618
so it can be represented by an exponential model.
Option B is the answer.
...............................................................................................................................................
Solve for “X”
a. 7/3 =X/49
Answer:
[tex]x = \frac{343}{3} [/tex]Step-by-step explanation:
Given,
[tex] \frac{7}{3} = \frac{x}{49} [/tex]
[tex] = > x = \frac{7}{3} \times 49[/tex]
[tex] = > x = \frac{343}{3} (ans)[/tex]
Answer:
343/3 or 114 1/3
Step-by-step explanation:
7/3 = x/49
Using cross products
3x = 7*49
3x =343
Divide by 3
3x/3 = 343/3
x =343/3
x =114 1/3
How to find interquartilte range
============================================================
Explanation:
Each x represents a data point location.
So, for example, having an x over 60 means 60 is part of the set.
The set of values we're working with is
{59,60,61,63,63,64,66,68,70,71,71,73}
The repeated values are due to the fact we have a stack of two 'x' markers, and they occur at 63 and 71.
To find the IQR (interquartile range), we'll first need to find the median of this set. That's the middle most value.
Count out the number of values to find that there are n = 12 values.
The list splits into two halves that are n/2 = 12/2 = 6 items each
Between slots 6 and 7 is where the median is located.
The value in slot 6 is 64 and the value in slot 7 is 66. Average those two items to get (64+66)/2 = 65
The median is 65
---------------------------------
Next, we'll form two groups L and U such that
L = set of items lower than the median
U = set of items larger than the median
Because n is even, we simply just break the original set into two equal groups (6 items each)
L = {59,60,61,63,63,64}
U = {66,68,70,71,71,73}
The values of Q1 and Q3 represent the medians of L and U in that order.
The median of set L is (61+63)/2 = 62, so Q1 = 62
The median of set U is (70+71)/2 = 70.5, which is Q3
-----------------------------------
To summarize everything so far, we have found
Q1 = 62Q3 = 70.5Subtract those items to get the IQR
IQR = Q3 - Q1
IQR = 70.5 - 62
IQR = 8.5 which points us to choice C as the final answer.
i need help with this one please
Answer:
A
Step-by-step explanation:
a geometric sequence is where we multiply a factor from element to element.
a1 = $900
a2 = 981 = a1 × f = 900 ×
a3 = 1069.29 = a2 × f = a1 × f × f = s1 × f²
[tex]an = 900 \times {f}^{n - 1} [/tex]
so, now let's try and get f.
remember, 981 = 900 × f
f = 981/900 = 109/100 = 1.09
just to control, we check for s3 :
900 × (1.09)² = 900 × 1.1881 = 1069.29
correct.
so,
a13 = 900 × (1.09)¹² = 2,531.398304
s13 is then the sum of all a1, ..., a13
there is a nice formula for sums of finite sequences
s13 = 900 × (1-f¹³) / (1-f) = 900×(1-(1.09)¹³) / (1-1.09) =
= 900×(1-3.065804612) / (-0.09) =
= 900×(-2.065804612) / (-0.09) = 20,658.04612
.
x423-2
Which expression is equivalent to log12
-?
(x+1)
O 410g,2x+ 2logi z(x2 – 2)- 5logiz(x: 1)
O 410912x+ žlog12. - 5log,2x+log421
o (x2
log124x+10912(x - 2)-510912(x)+1
4109,2x+ 3 109126x - 2)- 5log12(x + 1)
Answer:
D
Step-by-step explanation:
log(x^4*sqrt(x^3-2)/(x+1)^5)=log(x^4)+log(sqrt(x^3-2))-log((x+1)^5)
=> 4log(x)+(1/2)*log(x^3-2)-5log(x+1)
A cube with a volume of 216 cubic feet has all but the top and bottom faces painted. What is the total area of the two unpainted sides?
The volume of a cube is Side ^3
Find the cubic root of the volume to find the side length:
Side = cubicroot(216) = 6 feet.
The area of a face of a cube is s^2
Area of a face = 6^2 = 36 square feet.
Area of 2 faces = 36 x 2 = 72 square feet
Answer: 72 square feet
Answer:
72 ft²
Step-by-step explanation:
To find the length of each side we have to cube root the volume
∛216 = 6
We only have to find the areas for two faces (the top and bottom)
6 x 6 = 36 = area for one face
36 x 2 = 72 = area for two faces
Complete the equation: x2 + 10x +__= (__)^2
Answer:
x2 + 10x +25 = (x+5)^2
Step-by-step explanation:
x^2 + 10x
To complete the square
Take the coefficient of x
10
Divide by 2
10/2 =5
Square it
5^2 =25
Add it
x2 + 10x +25
The coefficient of x divided by 2 is the factor we add to x inside the square
(x+5)^2
Answer:
25 should go in the blank.
Step-by-step explanation:
You can factor and get (x + 5)^2, a perfect square trinomial when put into standard form.
Is A ABC similar to A DEF? Why or why not?
B
E
8 ft
95
6 ft
95°
d
25°
60°
25°
60°
А
10 ft
F
CD
7.5 ft
#
Choice
A.
Yes, because the angles are congruent and the sides are
proportional
B.
Yes, because if at least one pair of angles are equal, the
triangles are similar.
C.
No, because although the angles are congruent, the sides are
not.
D.
We cannot tell because the third side is not given.
A
B
С
D
Answer:
Its either A or B
Step-by-step explanation:
I am not sure tho
Answer:
B ,because they are similar
my teacher told me
I'LL GIVE BRAINLIEST ! ! ! ! ! !
The parabola x=√y-9 opens:
a. left
b. right
c. down
d. up
Answer:
UP
Step-by-step explanation:
x+9 = [tex]\sqrt{y}[/tex]
y = [tex]x^{2}[/tex] +18x + 81
Answer:
Up
Step-by-step explanation:
lol im giving a second answer so the other person can get brainliest :)
I need help ASAP plzzzzzzzzzzzzz
Answer:
3/4
Step-by-step explanation:
Let's say that r is the radius of the large circle or the diameter of the small circle.
Area of the big circle is [tex]\pi r^{2}[/tex] .
Area of the small circle is [tex]\pi \frac{r}{2} ^{2} = \pi \frac{r^{2}}{4}[/tex].
The ratio of these 2 circles is 1/4 (calculation in the comments).
So the shaded part represent 1 - 1/4 = 3/4.
Fiona went jewelry shopping and bought a bracelet for $1 367, a pair of earrings for $800, and a necklace for $4 500. What was the total amount of money she spent?
Answer: $1367 + $800 + $4500 = $6667
15/2 divided by 5/3
Brainlest is one the line
Answer:
[tex] \frac{9}{2} [/tex]
Step-by-step explanation:
[tex] \frac{15}{2} \div \frac{5}{3} = \frac{15}{2} \times \frac{3}{5} = \frac{3}{2} \times \frac{3}{1} = \frac{9}{2} [/tex]
Find the perimeter of the following figure.
Answer:
10 meters
Step-by-step explanation:
Perimeter= 3+3+2+2
=10
Have a nice day:)
A commercial real estate developer creates a scale drawing of a commercial property that he
hopes to sell. The ratio of the area of the drawing to the actual area of the commercial property
is 1 ft? : 900 ft. The developer hopes to sell the commercial space for $1,800,000, which
would be equivalent to $1000 per 1 square foot (ft?) of the property's area. To the nearest
square foot, what is the area of the scale drawing?
Find the area of the actual property by diving the sale price by the price per square foot:
1,800,000 / 1,000 = 1,800 square feet
Divide actual are by the scale:
1800 / 900 = 2
The scale drawing is 2 square inches.
The area of the square draw will be 2 square inches.
What is an area?The space occupied by any two-dimensional figure in a plane is called the area. The scale factor is a way to compare figures with similar appearances but differing scales or measurements. Consider two circles that resemble one another but may have different radii.
Given that area is 900 ft. the developer hopes to sell the commercial space for $1,800,000, which would be equivalent to $1000 per 1 square foot (ft?) of the property's area.
The area of the actual property by diving the sale price by the price per square foot:
1,800,000 / 1,000 = 1,800 square feet
Divide actual are by the scale:
1800 / 900 = 2
Therefore, the area of the square draw will be 2 square inches.
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Can someone help me out
Answer:
28.3
Step-by-step explanation:
A = [tex]\pi r^{2}[/tex]
Plug in:
A = [tex]\pi 3^{2}[/tex]
A = [tex]9 \pi[/tex]
A = 9 × 3.14 = 28.26 = 28.3
The answer is 28.3
Hope this helped.
a cube plus b cube is equal to a + b whole (a square minus a b + b square whole)
Answer:
a =b
Step-by-step explanation:
How can I express this as a single power with positive exponents?
Answer:
5^1
Step-by-step explanation:
[tex]\sqrt{5} =5^{\frac{1}{2} }[/tex] (law of indices - fractional powers)
after converting all the numbers to this form:
[tex]\frac{5^{{\frac{2}{3} } } * 5^{\frac{1}{2} } }{5^{\frac{1}{6} } } \\[/tex]
combine using law of indices:
5^(2/3+1/2-1/6) = 5^1
The rational number -13/-5 lies to the right of zero on the number true or false.
Answer:
true
hope it helps
PLEASE MARK BRAINLIEST
Which answer shows 0.05 written in scientific notation?
Answer:
5x10^-2 option B
Step-by-step explanation:
Answer:
5x10^-2
the second one.
I need help like rq
Answer:
h(x) = ½x + 5
Step-by-step explanation:
From the question given above, the following data were obtained:
Function, f(x) = 2x – 10
Inverse, h(x) =?
The inverse of the function, h(x) can be obtained as follow:
f(x) = 2x – 10
Let f(x) = y
y = 2x – 10
Interchange x and y
x = 2y – 10
Make y the subject by rearranging
x + 10 = 2y
Divide both side by 2
y = (x + 10) / 2
y = ½x + 5
Replace y with h(x)
h(x) = ½x + 5
Thus, the inverse of the function is
h(x) = ½x + 5
Write an inequality and show on a number line all numbers:
greater than (-3) but less than or equal to 3
(enter the inequality in terms of x)
Eg. x<-3; 3 7
Answer:
The inequality is:
- 3 < x ≤ 3And the graph is attached
Greater than -3
x>-3-3<xLess than or equal to 3
x≤3For number line
put a open dot at -3
put a close dot at 3
join them
HELPPPPPPPPP!!!!!!!!!!!!!!!!
Answer:
they are not similar. their one angle is only equal
A 9-pack of golf balls costs $8.74. What is the unit price, rounded to the nearest cent?
per golf ball
Answer:
0.97 per ball
Step-by-step explanation:
Take the total cost and divide by the number of items
8.74 /9
0.97111
Rounding to the nearest cent
0.97
I need help finding the answer
cosA.cos2A.cos4A=sin8A/8sinA
I assume you're supposed to establish the identity,
cos(A) cos(2A) cos(4A) = 1/8 sin(8A) / sin(A)
Recall the double angle identity for sine:
sin(2x) = 2 sin(x) cos(x)
Then you have
sin(8A) = 2 sin(4A) cos(4A)
sin(8A) = 4 sin(2A) cos(2A) cos(4A)
sin(8A) = 8 sin(A) cos(A) cos(2A) cos(4A)
==> sin(8A)/(8 sin(A)) = cos(A) cos(2A) cos(4A)
as required.
Triangle ABC is translated right 8 units and down 15 units to triangle XYZ. Triangle ABC
has these angle measures:
m∠A=45∘
m∠B=53∘
m∠C=82∘
What is the measure of angle Y?
9514 1404 393
Answer:
53°
Step-by-step explanation:
The names of the triangles indicate that angle B corresponds to angle Y. Translation does not affect side lengths or angle measures, so angle Y is the same measure as angle B.
m∠Y = 53°
Answer: 53
Step-by-step explanation:
The expression.1*e^0.0347t models.The balance in thousand of dollars where t represents time.In years after the account was opened. What does the 0.034 represent in this context? Write an expression for the number of years after which there will be 15,000 Dollars in the account?
Answer:
0.0347 = constant of proportionality
[tex]1 * e^{0.0347t} = 15000[/tex]
Step-by-step explanation:
Given
[tex]1*e^{0.0347t}[/tex]
Solving (a): what does 0.0347 represent?
An exponential model is represented as:
[tex]f(t) = a * e^{kt}[/tex]
Where:
[tex]k \to[/tex] constant of proportionality
So, by comparison:
[tex]k = 0.0347[/tex]
Hence:
[tex]0.0347 \to[/tex] constant of proportionality
Solving (b): Formula to calculate when balance equals 15000
To do this, we simply equate the formula to 15000.
So, we have:
[tex]1 * e^{0.0347t} = 15000[/tex]
is the perpendicular bisector of . Point T is the midpoint of . Point U lies on . If the length of is 7 units, the length of is how many units?
Complete question is;
RS is the perpendicular bisector of PQ . Point T is the midpoint of PQ. Point U lies on RS. If the length of UP is 7 units, the length of UQ is ______ units.
Triangle is attached
Answer:
UQ = 7 Units
Step-by-step explanation:
From the image attached, we can see that;
T is the midpoint of PQ
Thus;
PT = TQ
Since RS is perpendicular to PQ, then we can say that;
∠PTU = ∠QTU
Now, from SAS congruence theorem, we can say that;
△PTU = △QTU
Thus, from corresponding sides of both triangles, we can say that;
UP = UQ
Thus,
UQ = 7 Units
Answer:
7 units
Step-by-step explanation:
rs 20736 was distributed to as many rupees as there were. how many students were there
This question is solved by proportions
Doing this, we found that there were 144 students.
20736 was distributed. The number of rupees for each student is the number of students.
Considering n students, the amount each student receives is:
[tex]A = \frac{20736}{n}[/tex]
Considering each student received n rupees:
[tex]n = \frac{20736}{n}[/tex]
Applying cross multiplication:
[tex]n^2 = 20736[/tex]
[tex]n = \sqrt{20736}[/tex]
[tex]n = 144[/tex]
Thus, there were 144 students.
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