Which statement is true about this quadratic equation?
y=x^(2)-11x+7

Answer:

<4 = <1

Step-by-step explanation:

Judging from the picture, <1 and <4 are opposite angles. Opposite angles are always congruent. Hope this helps!

Answer:

Adam runs at a rate of 11 minutes per mile.

Step-by-step explanation:

Take 143 minutes and divide by 13 miles and you will get the answer of 11 minutes.

PLEASE MARK ME BRAINEIST.

Answer:

it would take him 11 minuets to run a mile

Step-by-step

143 divided by 13 is 11 which means each mile takes 11

you can also check the answer by multiplying 13 times 11 which is 143

Answer:

x=5.9

i think this the answer

Answer:

ask in English then I can help u

Answer:

your answer is 2

Step-by-step explanation:

I hope this help

Answer:

it is not function

Step-by-step explanation:

because,

first of all,what do mean function

A function is a relation in which each element of the domain corresponds to exactly one

element of the range.

based on this description

Since the domain element 1 is assigned to two different values in the range, -1 and 1, so that it is

not a function

Answer:

x=74.3

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp /adj

tan 22 = 30/x

x tan 22 = 30

x = 30/ tan 22

x=74.25260

To the nearest tenth

x=74.3

Answer:

The answer is A

Step-by-step explanation:

(-2,-3) (3,-4) (0,-1) (-7,3)

inverse means the opposite signs

(2,3) (-3,4) (0,1) (7,-3)

Answer:

11 and 8

Step-by-step explanation:

Let the integers be x and y. ATQ y-x=3 and x+y^2=129. Solving it, we will get x=8 and y=11

Answer:

8. SU = 24

9. TU = 16√3

Step-by-step explanation:

Recall: SOH CAH TOA

8. Reference angle (θ) = 30°

Opposite = 8√3

Adjacent = SU

Apply TOA,

Tan θ = Opp/Adj

Substitute

Tan 30° = 8√3/SU

Tan 30° × SU = 8√3

SU = 8√3/Tan 30°

SU = 8√3/(1/√3) (tan 30° = 1/√3)

SU = 8√3*√3/1

SU = 8*3

SU = 24

9. Reference angle (θ) = 30°

Opposite = 8√3

Hypotenuse = TU

Apply SOH,

Sin θ = Opp/Hyp

Substitute

Sin 30° = 8√3/TU

Sin 30° × TU = 8√3

TU = 8√3/sin 30°

TU = 8√3/(½) (sin 30° = ½)

TU = 8√3 × 2/1

TU = 16√3

Answer:

50/60 = .8333=  83.33%

Step-by-step explanation:

The probability that the call arrived when the switchboard was not fully busy is 0.75.

A probability distribution that is symmetric about the mean is the normal distribution, sometimes referred to as the Gaussian distribution. It demonstrates that data that are close to the mean occur more frequently than data that are far from the mean. The normal distribution appears as a "bell curve" on a graph.

Given:

Here X follows uniform distribution with parameter a and b.

Where,

a = 0 and b = 1.

Then,

The density function of Y is given by:

P( 15 < Y ≤ 60)

or, P( 0.25 < Y ≤ 1)

So,  P( 0.25 < Y ≤ 1) = [tex]\int\limits^{1}_{0.25}{f(y) \, dy[/tex]

                                = [tex][y]^1 _ {0.25}[/tex]

                                = (1- 0.25)

                                = 0.75

Hence, The probability that the call arrived when the switchboard was not fully busy is 0.75.

Learn more about Normal Distribution here:

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Answer: 90 sides

Step-by-step explanation:

Let's say the circle has a center at  A and B and C are at the vertices of a polygon. Since this figure is inscribed in a circle, we can draw two radii through the vertices. Because all radii are congruent, we know segment BA is congruent to Segment CA. If a triangle has at least 2 congruent sides, we can identify the triangle as an isosceles triangle. With this we can conclude <ACB is congruent to <ABC. By the definition of congruent angles, m<ACB = M<ABC. Let's say m<ACB = x. By the Triangle Sum Theorem, 40 + x + m<ABC = 180. By substitution, 40 + x + x = 180. When we solve we get x =70. Since radii bisect interior angles we know that each interior angle of this polygon is 140 degrees. If we plug in 140 to our equation, [tex]\frac{(n-2)180}{n}[/tex]  where n is the number of sides, we get n = 90. So we can conclude this polygon has 90 sides

9514 1404 393

Answer:

  13064 feet

Step-by-step explanation:

We can rewrite the formula so that x is in feet. Equating the new formula to 8.743 PSI, we have ...

  8.743 = 14.7e^(-0.21x/5280)

Dividing by 14.7 and taking natural logs, we have ...

  ln(8.743/14.7) = -0.21x/5280

Multiplying by the inverse of the coefficient of x gives ...

  x = 5280·ln(8.743/14.7)/-0.21 ≈ 13064.0806

The peak of the mountain is about 13,064 feet high.

Answer:

8+2x-2 = 5

2x+6 =5

2x = -1

Step-by-step explanation:

8+2(x-1)=5

Distribute

8+2x-2 = 5

Combine like terms

2x+6 =5

Subtract 6

2x+6-6=5-6

2x = -1

Answer:

$3735

Step-by-step explanation:

2/5 = 8/20

8/20 + 7/20 = 15/20 = 3/4

3/4*4980 = 3735

Answer:

60

Step-by-step explanation:

Use similar triangles or the ratios from the right triangle altitude theorem.

x/36 = (64 + 36)/x

x² = 3600

x = 60

According to the given values in the question:

The Amortization period is:

= [tex]8 \ years\times 12 \ months[/tex]

= [tex]96 \ months[/tex]

Number of months of Amortization is:

= [tex]3 \ months \ in \ 2020+(4 \ years\times 12 \ months)[/tex]

= [tex]3+48[/tex]

= [tex]51 \ months[/tex]

Now,

On bonds payable, the premium will be:

= [tex]Issue \ price - Face \ value[/tex]

= [tex](100000\times 103 \ percent)- 100000[/tex]

= [tex]103000-100000[/tex]

= [tex]3000[/tex] ($)

The Unamortized premium will be:

= [tex]Premium - Unamortized \ premium[/tex]

= [tex]3000-(3000\times \frac{51}{96} )[/tex]

= [tex]3000-1593.75[/tex]

= [tex]1406.25[/tex] ($)

hence,

The carrying value as of December  31, 2024 will be:

= [tex]100000+1406.25[/tex]

= [tex]101406.25[/tex] ($)

Learn more about the bond carrying value here:

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Answer:

[tex]Domain = \{-3,0,2,1,6,3\}[/tex]

[tex]Range = \{4,6,-2,-3,-7,2\}[/tex]

Step-by-step explanation:

Given

[tex]\{(- 3,4), (0,6), (2, - 2), (1, - 3), (6, - 7), (3, 2)\}[/tex]

Required

The domain and range

A function is represented as:

[tex]Function = \{(x_1,y_1),(x_2,y_2),....(x_n,y_n)\}[/tex]

Where

[tex]x \to[/tex] domain

[tex]y \to[/tex] range

So, we have:

[tex]Domain = \{-3,0,2,1,6,3\}[/tex]

[tex]Range = \{4,6,-2,-3,-7,2\}[/tex]

Answer:

50√3 square units.

Step-by-step explanation:

Let the two sides of the triangle given be 'a' and 'b'.

Let the angle between them be θ

From the question given above, the following data were obtained:

Side a = 20 units

Side b = 10√3

Angle (θ) = 30°

Area (A) =?

A = ½ × ab × Sineθ

A = ½ × 20 × 10√3 × Sine 30

A = ½ × 20 × 10√3 × ½

A = 10 × 5√3

A = 50√3 square units

Therefore, the area of the triangle is 50√3 square units

Step-by-step explanation:

volume of sphere = 288

based on formula, V = 4/3πr³

288 = 4/3(3.14)r³

288 = 4.187(r³)

r³ = 288/4.187

r =

[tex] \sqrt[3]{68.78} [/tex]

r = 4.09

= 4.1

As both angles are supplementary

[tex]\\ \Large\sf\longmapsto 3x+(2x+3y)=180°[/tex]

[tex]\\ \Large\sf\longmapsto 3x+2x+3y=180[/tex]

[tex]\\ \Large\sf\longmapsto 5x+3y=180[/tex]

[tex]\\ \Large\sf\longmapsto 3y=180-5x[/tex]

[tex]\\ \Large\sf\longmapsto y=\dfrac{180-5x}{3}[/tex]

And

[tex]\\ \Large\sf\longmapsto 3x=90[/tex]

[tex]\\ \Large\sf\longmapsto x=\dfrac{90}{3}[/tex]

[tex]\\ \Large\sf\longmapsto x=30[/tex]

Now

[tex]\\ \Large\sf\longmapsto y=\dfrac{180-5x}{3}[/tex]

[tex]\\ \Large\sf\longmapsto y=\dfrac{180-5(30)}{3}[/tex]

[tex]\\ \Large\sf\longmapsto y=\dfrac{180-150}{3}[/tex]

[tex]\\ \Large\sf\longmapsto y=\dfrac{30}{3}[/tex]

[tex]\\ \Large\sf\longmapsto y=10[/tex]

Answer:

Option B.)

Step-by-step explanation:

Just took the test and got 100% :]

The system of logarithmic equation is graphed and the point of intersection of the equation is log₃ ( 5x ) = log₅ ( 2x + 8 ) is A ( 1.0 , 1.4 )

Graphs behave differently at various x-intercepts. Sometimes the graph will cross over the x-axis at an intercept. Other times the graph will touch the x-axis and bounce off.

Identify the even and odd multiplicities of the polynomial functions' zeros.

Using end behavior, turning points, intercepts, and the Intermediate Value Theorem, plot the graph of a polynomial function.

The graphs cross or are tangent to the x-axis at these x-values for zeros with even multiplicities. The graphs cross or intersect the x-axis at these x-values for zeros with odd multiplicities

Given data ,

Let the solution to the logarithmic equation be represented as A

Now , the value of A is

log₃ ( 5x ) = log₅ ( 2x + 8 )

On simplifying , we get

log₃ ( 5x ) = log₁₀ ( 5x ) / log₁₀ ( 3 )

log₅ ( 2x + 8 ) = log₁₀ ( 2x + 8 ) / log₁₀ ( 5 )

Substituting the logarithmic quantities , we get

log₁₀ ( 5x ) / log₁₀ ( 3 ) = log₁₀ ( 2x + 8 ) / log₁₀ ( 5 )

On cross multiplying , we get

log₁₀ ( 5x ) / log₁₀ ( 2x + 8 ) = log₁₀ ( 3 ) / log₁₀ ( 5 )

( 5x ) / ( 2x + 8 ) = 3/5

On cross multiplying , we get

25x = 6x + 24

Subtracting 6x on both sides , we get

19x = 24

Divide by 19 on both sides , we get

x = 1.26

Therefore , the approximate values of the function on graphing is A ( 1.0 , 1.4 )

Hence , the solution of function from graphing is A ( 1.0 , 1.4 )

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Answer:

The distribution of the number of snacks grabbed is skewed right with a center around 18 and varies from 12 to 45. There are possible outliers at 38, 42, and 45.

Step-by-step explanation:

First, we can see if the graph is symmetric. A symmetric graph is even on both sides of the center. As there are a lot more students that grabbed a small number of snacks, and the data is not even around the center (which is somewhere around 20 or 30 snacks). This means that the graph is not symmetric, making the second answer incorrect.

Next, we can check if the graph is skewed right or left. If the left of the graph represents a smaller amount of snacks and the right of it represents a higher number of snacks, we can see that most of the data is on the left of the graph. There are a few values to the right, but the overwhelming amount of data is on the left, making the distribution skewed to the right. This keeps the first and last answers possible

Moreover, we can find the center of the distribution. This is generally equal to the median, which is 18, so the center is around 18

After that, we can see what the values vary from. The lowest tens value is 1, and the lowest ones value in that is 2, making the lowest value 12. Similarly, the highest tens value is 4, and the highest ones value there is 5, making the range 12 to 45. This leaves the last answer, but we can check the outliers to make sure.

With the data, we can calculate the first quartile to be 15, the third quartile to be 21.5, and the interquartile range to be 21.5-15 = 6.75 . If a number is less than Q₁ - 1.5 * IQR or greater than Q₃ + 1.5 * IQR, it is a potential outlier. Applying that here, the lower bound for non-outliers is 15 - 6.5 * 1.5 = 5.25, and the upper bound if 21 + 6.5 * 1.5 = 30.75. No values are less than 5.25, but there are four values greater than 30.75 in 32, 38, 42, and 45. There are possible outliers at 38, 42, and 45, matching up with the last answer.

Step-by-step explanation:

before Tax

Coast = 888

in 2ND Item = $21

• 888/21

= $42.28

Answer: The alternate hypothesis would disprove the null hypothesis and state that there are a significant difference in preferences/proportions between the two villages.

For instance, let's say:

The null hypothesis would be that p₁ = p₂, while the alternative hypothesis would be that p₁ ≠ p₂.

Answer:

3y=5x-4

Step-by-step explanation:

As the lines are parallel, the slope will be 5/3. The equation of line will be y=(5/3)*x-4/3. 3y=5x-4

Answer:

(a)

[tex]\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}[/tex]

(b)

[tex]P(3 \le x \le 6) = 0.30[/tex]

[tex]P(4 \le x)=0.60[/tex]

Step-by-step explanation:

Given

[tex]F(x) = \left[\begin{array}{ccc}0& x<1 &\\0.30&1 \le x<3 &\\0.40&3 \le x < 4& &0.45 &4 \le x<6 &\\0.60 & 6 \le x < 12 & & 1 & 12 \le x\end{array}\right[/tex]

Solving (a): The pmf

This means that we list out the probability of each value of x.

To do this, we simply subtract the current probability value from the next.

So, we have:

[tex]\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}[/tex]

The calculation is as follows:

[tex]0.30 - 0 = 0.30[/tex]

[tex]0.40 - 0.30 = 0.10[/tex]

[tex]0.45 - 0.40 = 0.05[/tex]

[tex]0.60 - 0.45 = 0.15[/tex]

[tex]1 - 0.60 = 0.40[/tex]

The x values are gotten by considering where the equality sign is in each range.

[tex]1 \le x < 3[/tex] means [tex]x = 1[/tex]

[tex]3 \le x < 4[/tex] means [tex]x = 3[/tex]

[tex]4 \le x < 6[/tex] means [tex]x=4[/tex]

[tex]6 \le x < 12[/tex] means [tex]x = 6[/tex]

[tex]12 \le x[/tex] means [tex]x = 12[/tex]

Solving (b):

[tex](i)\ P(3 \le x \le 6)[/tex]

This is calculated as:

[tex]P(3 \le x \le 6) = F(6) - F(3-)[/tex]

From the given function

[tex]F(6)= 0.60[/tex]

[tex]F(3-) = F(1) = 0.30[/tex]

So:

[tex]P(3 \le x \le 6) = 0.60 - 0.30[/tex]

[tex]P(3 \le x \le 6) = 0.30[/tex]

[tex](ii)\ P(4 \le x)[/tex]

This is calculated as:

[tex]P(4 \le x)=1 - F(4-)[/tex]

[tex]P(4 \le x)=1 - F(3)[/tex]

[tex]P(4 \le x)=1 - 0.40[/tex]

[tex]P(4 \le x)=0.60[/tex]

Answer:

$32

Step-by-step explanation:

Multiply $40*3000 students. Subtract 2 students that might receive a $12000 policy each. Divide by 3000 students to find average payout.