Which one and what do I put in the box(s)

Which One And What Do I Put In The Box(s)

Answers

Answer 1

Answer:

Option A i the right option.

First blank is 110-[tex]10\sqrt{61}[/tex] or 10(11-[tex]\sqrt{61}[/tex])

Second blank is 31.898

Let me know if anything didn't make sense.  

Step-by-step explanation:

So a diagonal through a rectangle makes two triangles.  The question wants to know how much walking is saved walking down the diagonal  vs walking along two sides that make the diagonal.  in this case the two non diagonal sides walked are 60 paces and 50 paces.

A diagonal through a rectangle specifically makes a right triangle, so to find the diagonal we can use the pythagorean theorem.  

c^2 = 60^2 + 50^2

c = [tex]\sqrt{60^2 + 50^2}[/tex]

c = [tex]\sqrt{6100} = 10\sqrt{61}[/tex]

if you don't get how to simplify a radical like that let me know.

Anyway, looking at the answers you can see right away the second option says no approximation is necessary.  Well, you need to approximate square root of 61, so we can say the second answer is not right.  So now we need to know what to fill in for option 1.

it wants the distance saved, well we know the distance of the diagonal is [tex]10\sqrt{61}[/tex]  Hopefully you can see the disctance walking the two other sides is just adding them up so 50+60=110.

Now, to find the difference, that is subtraction.  So subtract the smaller number from the larger number.  You do need to remember with a right triangle, the sum of the to non diagonal (hypotenuse) sides are always longer than said hypotenuse.  so that's 110-[tex]10\sqrt{61}[/tex].  That is the exact form.  Or you could use 10(11-[tex]\sqrt{61}[/tex])  They are the same.

Then just plug that into a calculator for a decimal approximation.


Related Questions

consider the differential equation x3y ''' + 8x2y '' + 9xy ' − 9y = 0; x, x−3, x−3 ln(x), (0, [infinity]). Verify that the given functions form a fundamental set of solutions of the differential equation on the indicated interval. The functions satisfy the differential equation and are linearly independent since W(x, x−3, x−3 ln(x)) = ≠ 0 for 0 < x < [infinity].

Answers

Verifying that a given expression is a solution to the equation is just a matter of plugging in the expression and its derivatives, and making sure that the given expressions are indeed linearly independent.

For example, if y = x, then y' = 1 and the other derivatives vanish. So the DE after substitution reduces to

9x - 9x = 0

which is true for all 0 < x < ∞.

To check for linear independence, you compute the Wronskian, which, judging by what you wrote, you've already done...

commission received

Answers

Yes commission has been received

Answer:

Commission Received refers to a percentage amount received by the company (or) an individual on the total sales incurred. It is an indirect income/revenue recorded on the credit side of profit and loss account.

Step-by-step explanation:

mark me brainliest if my answer is correct

Use the following information to answer the next six exercises. There are 23 countries in North America, 12 countries in South America, 47 countries in Europe, 44 countries in Asia, 54 countries in Africa, and 14 in Oceania (Pacific Ocean region).
Let A = the event that a country is in Asia.
Let E = the event that a country is in Europe.
Let F = the event that a country is in Africa.
Let N = the event that a country is in North America. Let O = the event that a country is in Oceania.
Let S = the event that a country is in South America.
18. What is the probability of drawing a red card in a standard deck of 52 cards?
19. What is the probability of drawing a club in a standard deck of 52 cards?

Answers

The probabilities we found in this exercise are.

0.2268 = 22.68% probability that a country is in Asia.0.2423 = 24.23% probability that a country is in Europe.0.2784 = 27.84% probability that a country is in Africa.0.1186 = 11.86% probability that a country is in North America.0.0722 = 7.22% probability that a country is in Oceania.0.0619 = 6.19% probability that a country is in South America.0.5 = 50% probability of drawing a red card in a standard deck of 52 cards.0.25 = 25% probability of drawing a club in a standard deck of 52 cards.

In this exercise, probability concepts are used.

A probability is the number of desired outcomes divided by the number of total outcomes.

Total number of countries:

23 + 12 + 47 + 44 + 54 + 14 = 194

Let A = the event that a country is in Asia.

44 of the 194 countries are in Asia, thus:

[tex]P(A) = \frac{44}{194} = 0.2268[/tex]

0.2268 = 22.68% probability that a country is in Asia.

Let E = the event that a country is in Europe.

47 out of 194 countries are in Europe, thus:

[tex]P(E) = \frac{47}{194} = 0.2423[/tex]

0.2423 = 24.23% probability that a country is in Europe.

Let F = the event that a country is in Africa.

54 out of 194 countries are in Africa, thus:

[tex]P(F) = \frac{54}{194} = 0.2784[/tex]

0.2784 = 27.84% probability that a country is in Africa.

Let N = the event that a country is in North America.

23 out of 194 countries are in North America, thus:

[tex]P(N) = \frac{23}{194} = 0.1186[/tex]

0.1186 = 11.86% probability that a country is in North America.

Let O = the event that a country is in Oceania.

14 out of 194 countries are in Oceania, thus:

[tex]P(O) = \frac{14}{194} = 0.0722[/tex]

0.0722 = 7.22% probability that a country is in Oceania.

Let S = the event that a country is in South America.

12 out of 194 countries are in South America, thus:

[tex]P(S) = \frac{12}{194} = 0.0619[/tex]

0.0619 = 6.19% probability that a country is in South America.

18. What is the probability of drawing a red card in a standard deck of 52 cards?

In a standard deck of 52 cards, 26 are red, and thus:

[tex]p = \frac{26}{52} = 0.5[/tex]

0.5 = 50% probability of drawing a red card in a standard deck of 52 cards.

19. What is the probability of drawing a club in a standard deck of 52 cards?

In a standard deck of 52 cards, 13 are clubs, and thus:

[tex]p = \frac{13}{52} = 0.25[/tex]

0.25 = 25% probability of drawing a club in a standard deck of 52 cards.

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What is the sum of 2 and 3 subtracted from the product of 2 and the difference of 7 and 4? The answer is 1, but how is it solved?

Answers

Answer: -1

Step-by-step explanation:

sum of 2 and 3   subtracted   from the product of 2    difference of 7 and 4

            (2+3)            -                         2                                 (  7    -    4   )   =  -1  

       (2+3)-2(7-4) =

        5 - 2(3) =

         5-6 = -1

The sum of 2 and 3 subtracted from the product of 2 and the difference of 7 and 4 is equivalent to 1.

What is Equation Modelling?

Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

We have the sum of 2 and 3 subtracted from the product of 2 and the difference of 7 and 4

From the question, we can model the equation as -

x = 2 × (7 - 4) - (2 + 3)

x = 2(3) - 5

x = 6 - 5

x = 1

Therefore, the sum of 2 and 3 subtracted from the product of 2 and the difference of 7 and 4 is equivalent to 1.

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Twenty students randomly assigned to an experimental group receive an instructional program; 30 in a control group do not. After 6 months, both groups are tested on their knowledge. The experimental group has a mean of 38 on the test (with an estimated population standard deviation of 3); the control group has a mean of 35 (with an estimated population standard deviation of 5). Using the .05 level, evaluate the researcher's hypothesis that the instructional program affects students' knowledge. What is the correct cutoff score(s)

Answers

Answer:

The solution according to the problem given is provided below in the explanation segment.

Step-by-step explanation:

According to the question,

[tex]H_o: \mu_1=\mu_2[/tex]

[tex]H_a: \mu_1 \neq \mu_2[/tex]

Level of significance,

[tex]\alpha = .05[/tex]

The test statistics will be:

⇒ [tex]Z = \frac{(\bar x_1 - \bar x_2)}{\sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} } }[/tex]

       [tex]=\frac{(38-35)}{\sqrt{\frac{(3)^2}{30} +\frac{(5)^2}{30} } }[/tex]

       [tex]=2.82[/tex]

The p-value will be:

= [tex]0.0024[/tex]

If the slope of a wheelchair ramp is 1/11 then what is the angle of inclination to the nearest tenth of a degree?

Answers

Answer

4.8 degrees to the nearest tenth.

Step-by-step explanation:

The slope = rise / run = opposite side / adjacent side.

So the angle of inclination is the angle whose tangent is 1/12.

To the nearest tenth of a degree it is 4.8 degrees.

The answer is 4.8 degrees

Which expressions are equivalent to -6(b+2)+8
Choose all answers that apply:
A. -6b+2+8

B. -6b-4

C. None of the above

Answers

Answer:

B. -6b-4

Step-by-step explanation:

-6(b+2)+8

Distribute

-6b-12+8

Combine like terms

-6b-4

What type of line is PQ?
A. altitude
B. angle bisector
C. side bisector
D. median

Answers

the answer for your question is altitude

The line PQ of the triangle is an altitude. The correct option is A.

What is the altitude of the triangle?

A line segment passing through a triangle's vertex and running perpendicular to the line containing the base is the triangle's height in geometry.

The extended base of the altitude is the name given to this line that contains the opposing side. The foot of the altitude is the point at where, the extended base and the height converge.

In the given triangle the line segment PQ is passing through a triangle's vertex and running perpendicular to the line containing the base is the triangle's height in geometry.

Therefore, the line PQ of the triangle is an altitude. The correct option is A.

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Use the information below to complete the problem: p(x)=1/x+1 and q(x)=1/x-1 Perform the operation and show that it results in another rational expression. p(x) + q(x)

Answers

Answer:

hope u will understand...if u like this answer plz mark as brainlist

Answer:

[tex]\displaystyle p(x) + q(x) = \frac{2x}{(x+1)(x-1)}[/tex]

The result is indeed another rational expression.

Step-by-step explanation:

We are given the two functions:

[tex]\displaystyle p(x) = \frac{1}{x+1}\text{ and } q(x) = \frac{1}{x-1}[/tex]

And we want to perform the operation:

[tex]\displaystyle p(x) + q(x)[/tex]

And show that the result is another rational expression.

Add:

[tex]\displaystyle = \frac{1}{x+1} + \frac{1}{x-1}[/tex]

To combine the fractions, we will need a common denominator. So, we can multiply the first fraction by (x - 1) and the second by (x + 1):

[tex]\displaystyle = \frac{1}{x+1}\left(\frac{x-1}{x-1}\right) + \frac{1}{x-1}\left(\frac{x+1}{x+1}\right)[/tex]

Simplify:

[tex]=\displaystyle \frac{x-1}{(x+1)(x-1)} + \frac{x+1}{(x+1)(x-1)}[/tex]

Add:

[tex]\displaystyle = \frac{(x-1)+(x+1)}{(x+1)(x-1)}[/tex]

Simplify. Hence:

[tex]\displaystyle p(x) + q(x) = \frac{2x}{(x+1)(x-1)}[/tex]

The result is indeed another rational expression.

write your answer as an integer or as a decimal rounded to the nearest tenth​

Answers

Answer:

Step-by-step explanation:

CE and are the sides making up the sine of an angle.

CE is the side opposite the angle

DE is the side hypotenuse.

<D = 61 degrees

Sin(D) = opposite / hypotenuse

hypotenuse = 8

Sin(61) = 0.8746

CE = ?

sin(61) = CE / 8                multiply both sides  by 8

8 sin(61) = CE

CE = 8 * 0.8746

CE = 6.9969

CE = 7.0

That 0 should be included in the answer, but I think it is safe to say that if you enter 7, you will get it right.

Answer:

7.0

Step-by-step explanation:

The scatterplot shows the number of bedrooms in a house and the selling price for that house.



Calculate the residual for the house with 6 bedrooms, to the nearest thousand.

The residual for the house with 6 bedrooms is ___
-30k
-26k
26k
30k

Answers

Answer:

-26k, -26,000 ; (B)

ED2021

The residual for the house with 6 bedrooms is -26k.

What is Scatterplots?

Scatterplots are the plotting of set of points on a vertical axis and an horizontal axis. The shows the correlation extent between the numbers of the observed quantities.

Given is a scatterplot showing the selling price of houses with the number of bedrooms.

Equation of the line of best fit is given as,

y = 6.3x + 4.8

Residual = Actual value - Predicted value

From the scatterplot,

Actual selling price of house with 6 bedrooms = 40 × 10,000 = 400,000

Predicted selling price for 6 bedrooms = (6.3 × 6) + 4.8

                                                                 = 42.6 × 10,000

                                                                 = 426,000

Residual = 400,000 - 426,000

              = -26,000

Hence the residual is -26k.

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What is the surface area of a cube with a side length of 6 m?
156 m2
300 m2
216 m2
360 m2

Answers

Answer:

216 m²

Step-by-step explanation:

Surface area of a cube = 6a², when a = length of one side

so,

6a²

= 6×6²

= 6×36

= 216 m²

Answered by GAUTHMATH

Answer:

216 m²

Step-by-step explanation:

Write the equation of the line in fully simplified slope-intercept form.

Answers

Answer:

y = 6/5x-1

Step-by-step explanation:

We have two points so we can find the slope

(-5,-7) and (5,5)

The slope is

m = ( y2-y1)/(x2-x1)

   = ( 5- -7)/( 5 - -5)

   = (5+7)/(5+5)

    = 12/10

   = 6/5

The slope intercept form of a line is

y = mx+b

y = 6/5x+b

Using the point (5,5)

5 = 6/5(5)+b

5=6+b

b=-1

y = 6/5x-1

Find the area of the shaded regions.

Answers

Answer:

around 22, or 21.98

Step-by-step explanation:

[tex]s1 = {r}^{2} \times \pi = 9 \times 3.14 = 28.26[/tex]

[tex]s2 = 1 \times 3.14 = 3.14[/tex]

[tex]s3 = 28.26 - (3.14 \times 2) = 28.26 - 6.28 = 21.98[/tex]

somebody help me please​

Answers

Answer:

115

Step-by-step explanation:

Since the lines are parallel, PWX+WXR=180, WXR=65. So PWX=(180-65)=115

A 40-foot tree casts a shadow 60 feet long. How long would the shadow of a 6-foot man be at that time?​

Answers

Answer:

26 ft

Step-by-step explanation:

I'm guessing this is how it's done

60-40= 20

there for at this time any shadow would be 20x it's original height/length

so 6+20=26 ft

lmk if I'm correct

Taking ratios

Let the shadow length=x ft

[tex]\\ \sf\longmapsto 40:60=6:x[/tex]

[tex]\\ \sf\longmapsto \dfrac{40}{60}=\dfrac{6}{x}[/tex]

[tex]\\ \sf\longmapsto \dfrac{4}{6}=\dfrac{6}{x}[/tex]

[tex]\\ \sf\longmapsto 4x=6(6)[/tex]

[tex]\\ \sf\longmapsto 4x=36[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{36}{4}[/tex]

[tex]\\ \sf\longmapsto x=9[/tex]

2/5 + 1/10= In simplest form
A. 3/15
B. 5/10
C. 1/4
D. 1/2

Answers

Answer:

1/2

Step-by-step explanation:

2/5 + 1/10

Get a common denominator of 10

2/5 * 2/2 + 1/10

4/10 + 1/10

5/10

simplify

Divide the top and bottom by 5

1/2

Answer:

[tex] \frac{1}{2} [/tex]

Answer D is correct

Step-by-step explanation:

[tex] \frac{2}{5} + \frac{1}{10} \\ \frac{2 \times 2}{5 \times 2} + \frac{1}{10} \\ \frac{4}{10} + \frac{1}{10} \\ \frac{5}{10} \\ \frac{5 \div 5}{10 \div 5} \\ = \frac{1}{2} [/tex]

find the LCM of 210, 280, 360 by prime factorisation​

Answers

Answer:

Step-by-step explanation:

210=2x3x5x7

280=2x2x2x5x7

360=2x2x2x3x3x5

Answer:

210= 2×3×5×7

280=2×2×2×5×7

360=2×2×2×3×3×5

common factors=2×2×2×3×5×7=840

uncommon factors=3

L.C.M=Common factors× uncommon factors

L.C.M=840×3

L.C.M=2520

Step-by-step explanation:

i hope it will be helpful

plzz mark as brainliest

The number of defective circuit boards coming off a soldering machine follows a Poisson distribution. During a specific ten-hour period, one defective circuit board was found. (a) Find the probability that it was produced during the first hour of operation during that period. (Round your answer to four decimal places.) (b) Find the probability that it was produced during the last hour of operation during that period. (Round your answer to four decimal places.) (c) Given that no defective circuit boards were produced during the first five hours of operation, find the probability that the defective board was manufactured during the sixth hour. (Round your answer to four decimal places.)

Answers

Answer:

a) the probability that the defective board was produced during the first hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

b) the probability that the defective board was produced during the  last hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

c) the required probability is 0.2000

Step-by-step explanation:

Given the data in the question;

During a specific ten-hour period, one defective circuit board was found.

Lets X represent the number of defective circuit boards coming out of the machine , following Poisson distribution on a particular 10-hours workday which one defective board was found.

Also let Y represent the event of producing one defective circuit board, Y is uniformly distributed over ( 0, 10 ) intervals.

f(y) = [tex]\left \{ {{\frac{1}{b-a} }\\\ }} \right _0[/tex];   ( a ≤ y ≤ b )[tex]_{elsewhere[/tex]

= [tex]\left \{ {{\frac{1}{10-0} }\\\ }} \right _0[/tex];   ( 0 ≤ y ≤ 10 )[tex]_{elsewhere[/tex]

f(y) = [tex]\left \{ {{\frac{1}{10} }\\\ }} \right _0[/tex];   ( 0 ≤ y ≤ 10 )[tex]_{elsewhere[/tex]

Now,

a) the probability that it was produced during the first hour of operation during that period;

P( Y < 1 )   =   [tex]\int\limits^1_0 {f(y)} \, dy[/tex]

we substitute

=    [tex]\int\limits^1_0 {\frac{1}{10} } \, dy[/tex]

= [tex]\frac{1}{10} [y]^1_0[/tex]

= [tex]\frac{1}{10} [ 1 - 0 ][/tex]

= [tex]\frac{1}{10}[/tex] or 0.1000

Therefore, the probability that the defective board was produced during the first hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

b) The probability that it was produced during the last hour of operation during that period.

P( Y > 9 ) =    [tex]\int\limits^{10}_9 {f(y)} \, dy[/tex]

we substitute

=    [tex]\int\limits^{10}_9 {\frac{1}{10} } \, dy[/tex]

= [tex]\frac{1}{10} [y]^{10}_9[/tex]

= [tex]\frac{1}{10} [ 10 - 9 ][/tex]

= [tex]\frac{1}{10}[/tex] or 0.1000

Therefore, the probability that the defective board was produced during the  last hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

c)

no defective circuit boards were produced during the first five hours of operation.

probability that the defective board was manufactured during the sixth hour will be;

P( 5 < Y < 6 | Y > 5 ) = P[ ( 5 < Y < 6 ) ∩ ( Y > 5 ) ] / P( Y > 5 )

= P( 5 < Y < 6 ) / P( Y > 5 )

we substitute

 [tex]= (\int\limits^{6}_5 {\frac{1}{10} } \, dy) / (\int\limits^{10}_5 {\frac{1}{10} } \, dy)[/tex]

[tex]= (\frac{1}{10} [y]^{6}_5) / (\frac{1}{10} [y]^{10}_5)[/tex]

= ( 6-5 ) / ( 10 - 5 )

= 0.2000

Therefore, the required probability is 0.2000

ko dung may tinh hay so sanh
3√7 vs 7√3

Answers

Answer:

what this makes bi sense haha

Step-by-step explanation:

but ok

Question Which of the following is a benefit of using email to communicate at work ? a) You can express yourself in a limited number of characters b) You don't have to worry about using proper grammar. c) You always get a response right away. d ) You can reach a large audience with one communication .

Answers

Answer:

d) you can reach a large audience with one communication

Step-by-step explanation:

common sense

I need help ASAP please and thank you

Answers

Answer:

"a" is the answer because 3x+2 can not be equal to zero

Step-by-step explanation:

the perimeter of a square is less than or equal to 50 find the range of the value of the length of the square​

Answers

Answer:

12.5  ≥ s >0

Step-by-step explanation:

The perimeter of a square is given by

P = 4s where s is the side length

50 ≥ 4s

Divide each side by 4

50/4 ≥ 4s/4

25/2  ≥ s

12.5  ≥ s

A company pays $20 per hour for up to 8 hours of work, and $30 per hour for overtime hours (hours beyond 8 hours). For up to 8 hours worked, the equation for total pay (y) for hours worked (x) is y = 20x. For over 8 hours worked, what is the equation for total pay (y) as a function of total hours worked (x)?

Answers

Answer: y = 30x

Step-by-step explanation:

Because we are talking about over 8 hours. The question states that you get 30$ per hour for overtime hours. That means if you work over 8 hours your dollars per hour increases to 30. So because the amount of dollars increases to 30 you can infer that all you have to do is make the same equation as the 20 dollar's per hour equation. Except you put 30 making it y = 30x.

Land surveyors outlined a park as shown. What is the area of the park?

Answers

la cuadra se llama 6minutos

Calculus II Question

Identify the function represented by the following power series.

[tex]\sum_{k = 0}^\infty (-1)^k \frac{x^{k + 2}}{4^k}[/tex]

Answers

With some rewriting, you get

[tex]\displaystyle \sum_{k=0}^\infty (-1)^k\frac{x^{k+2}}{4^k} = x^2 \sum_{k=0}^\infty \left(-\frac x4\right)^k[/tex]

Recall that for |x| < 1, you have

[tex]\displaystyle \frac1{1-x} = \sum_{k=0}^\infty x^k[/tex]

So as long as |-x/4| = |x/4| < 1, or |x| < 4, your series converges to

[tex]\displaystyle x^2 \sum_{k=0}^\infty \left(-\frac x4\right)^k = \frac{x^2}{1-\left(-\frac x4\right)} = \frac{x^2}{1+\frac x4} = \boxed{\frac{4x^2}{4+x}}[/tex]

Based on known expressions from Taylor series, the power series [tex]\sum \limits_{k = 0}^{\infty} (-1)^{k}\cdot \frac{x^{k+2}}{4^{k}}[/tex]Taylor series-derived formula of the rational function [tex]\frac{4\cdot x^{2}}{4+x}[/tex].

How to derive a function behind the approximated formula by Taylor series

Taylor series are polynomic approximations used to estimate values both from trascendental and non-trascendental functions. It is commonly used in trigonometric, potential, logarithmic and even rational functions.

In this question we must use series properties and common Taylor series-derived formulas to infer the expression behind the given series. Now we proceed to find the expression:

[tex]\sum \limits_{k = 0}^{\infty} (-1)^{k}\cdot \frac{x^{k+2}}{4^{k}}[/tex]

[tex]x^{2}\cdot \sum\limits_{k = 0}^{\infty} \left(-\frac{x}{4} \right)^{k}[/tex]

[tex]x^{2}\cdot \left(\frac{1}{1+\frac{x}{4} } \right)[/tex]

[tex]\frac{4\cdot x^{2}}{4+x}[/tex]

Based on power and series properties and most common Taylor series- derived formulas, the power series [tex]\sum \limits_{k = 0}^{\infty} (-1)^{k}\cdot \frac{x^{k+2}}{4^{k}}[/tex] represents a Taylor series-derived formula of the rational function [tex]\frac{4\cdot x^{2}}{4+x}[/tex]. [tex]\blacksquare[/tex]

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Estimate the average rate of change from x 1 to x = 4. Enter your estimate as a decimal number (not as a fraction), rounded to one decimal place. Average rate of change = Number​

Answers

Answer:Mark brainliest please

Answer is - 0.5

Step-by-step explanation:

The average rate of change is -0.5 which is the average rate of change from x 1 to x = 4 the answer is -0.5.

What is the rate of change?

It is defined as the change in values of a dependent variable with respect to the independent variables.

As we know an average is a single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.

We have a graph of functions shown in the picture.

Estimate the average rate of change from x 1 to x = 4.

At x = 1,

y = 5

At x = 4

y = 3.5(approx)

The average rate of change = (3.5 - 5)/(4 - 1)

The average rate of change = -1.5/3

The average rate of change = -0.5

Thus, the average rate of change is -0.5 which is the average rate of change from x 1 to x = 4 the answer is -0.5.

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5
13


The probabilities that three men win their respective races are 1/3,3/5and 3/4.what is theprobability that
a) all of them win their races)
b) only one of them win his race?

Answers

Answer:

a

Step-by-step explanation:

1/3 x 3/5 x 3/4 =7/12 so therefore that's what the answer isn't

In a class of students, the following data table summarizes how many students have a cat or a dog. What is the probability that a student who has a cat also has a dog?
Has a cat Does not have a cat
Has a dog 7 6
Does not have a dog 8 2

Answers

Outcome C joint D = 7, D excluding C is 6, C excluding D = 8, no C no D =2. Should be 23 people in total in that class. 7/23.

Differentiate the following Functions
5x^2-2xy + 4y^3= 5

Answers

Answer:

[tex]\displaystyle y' = \frac{y - 5x}{x + 6y^2}[/tex]

General Formulas and Concepts:

Algebra I

Terms/CoefficientsFactoring

Calculus

Differentiation

DerivativesDerivative NotationImplicit Differentiation

Derivative Property [Multiplied Constant]:                                                           [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Derivative Property [Addition/Subtraction]:                                                         [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Derivative Rule [Chain Rule]:                                                                                 [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle 5x^2 - 2xy + 4y^3 = 5[/tex]

Step 2: Differentiate

Implicit Differentiation:                                                                                 [tex]\displaystyle \frac{dy}{dx}[5x^2 - 2xy + 4y^3] = \frac{dy}{dx}[5][/tex]Rewrite [Derivative Property - Addition/Subtraction]:                                 [tex]\displaystyle \frac{dy}{dx}[5x^2] - \frac{dy}{dx}[2xy] + \frac{dy}{dx}[4y^3] = \frac{dy}{dx}[5][/tex]Rewrite [Derivative Property - Multiplied Constant]:                                   [tex]\displaystyle 5\frac{dy}{dx}[x^2] - 2\frac{dy}{dx}[xy] + 4\frac{dy}{dx}[y^3] = \frac{dy}{dx}[5][/tex]Basic Power Rule [Chain Rule]:                                                                     [tex]\displaystyle 10x - 2\frac{dy}{dx}[xy] + 12y^2y' = 0[/tex]Product Rule:                                                                                                 [tex]\displaystyle 10x - 2\bigg[ \frac{dy}{dx}[x]y + x\frac{dy}{dx}[y] \bigg] + 12y^2y' = 0[/tex]Basic Power Rule [Chain Rule]:                                                                     [tex]\displaystyle 10x - 2\bigg[ y + xy' \bigg] + 12y^2y' = 0[/tex]Simplify:                                                                                                         [tex]\displaystyle 10x - 2y + 2xy' + 12y^2y' = 0[/tex]Isolate y' terms:                                                                                             [tex]\displaystyle 2xy' + 12y^2y' = 2y - 10x[/tex]Factor:                                                                                                           [tex]\displaystyle y'(2x + 12y^2) = 2y - 10x[/tex]Isolate y':                                                                                                       [tex]\displaystyle y' = \frac{2y - 10x}{2x + 12y^2}[/tex]Factor:                                                                                                           [tex]\displaystyle y' = \frac{2(y - 5x)}{2(x + 6y^2)}[/tex]Simplify:                                                                                                         [tex]\displaystyle y' = \frac{y - 5x}{x + 6y^2}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Book: College Calculus 10e

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