Which of the following is true about the quotient -2/0?
A.
The quotient is equal to -2.
B.
The quotient is undefined because the denominator is zero.
C.
The quotient is undefined because the numerator is negative.
D.
The quotient is equal to 0.

Answers

Answer 1

Answer:

B.The quotient is undefined because the denominator is zero.

Step-by-step explanation:

You cannot divide by zero.  Take a piece of paper and divide into zero pieces.  It cannot be done as we know it.  That is undefined.

Answer 2

The quotient is undefined because the denominator is zero.

Option (B) is the correct answer.


Related Questions

3. In the following formal proof, what is the missing reason?

Answers

Answer:

A

Step-by-step explanation:

Start with 2x = 12, and end with x = 6.

To do that, you need to divide both sides by 2.

Answer: A

The answer is A
I just know it

7(3b-1)=2b-26 please help and give me step by step ☺️​

Answers

Answer:

b = -1

Step-by-step explanation:

7(3b-1): 7 goes into the numbers by multiplying. This will give you 21b-7.

So now the equation should be like 21b-7=2b-26.

-7 and 2b swap places, making 21b-2b=7-26. It will give you 19b= -19.

Finally divide the two numbers (-19 / 19) and the solution will be b= -1.

If I didn't make a clear answer or a good explanation, please comment. I sometimes mess up my steps, and this is my first time using this.

Answer:

b = -1

Step-by-step explanation:

7(3b -1 ) = 2b - 26

First, distribute.

21b - 7 = 2b - 26

Then, add 7 to both sides AND subtract 2b on both sides

21b - 7 + 7 - 2b = 2b - 2b - 26 + 7

Add common terms

19b = -19

Divide by 19

b = -1

Which rational number is the greatest
a. 0.55
b. 0.6
c. 9/20
d. 1/2

Answers

I think d.1/2 number is the greatest rational number .

help help help help help

Answers

E’(5,-2)
F’(1,-2)
G’(5,1)
H’(5,5)
Please check if I understand the question correct

Correct answer gets brainliest

Answers

Answer:

1.C submit ..............................................

Answer:

A

Step-by-step explanation:

Calculate the distance using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = C (2, - 1) and (x₂, y₂ ) = D (5, 3)

CD = [tex]\sqrt{(5-2)^2+(3-(-1))^2}[/tex]

      = [tex]\sqrt{3^2+(3+1)^2}[/tex]

      = [tex]\sqrt{9+4^2}[/tex]

      = [tex]\sqrt{9+16}[/tex]

      = [tex]\sqrt{25}[/tex]

      = 5 units → A

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