Answers
Answer:
Hello
Step-by-step explanation:
[tex]Formula: \\\\\boxed{\Large a^3\pm b^3=(a \pm b)(a^2 \mp ab+b^2)}\\\\8x^3+1=(2x)^3+1^3=(2x+1)(4x^2-2x+1)\\\\8x^3-1=(2x)^3-1^3=(2x-1)(4x^2+2x+1)\\[/tex]
The factors of the expression 8x³ + 1 and 8x³ - 1³ will be (2x + 1) & (4x² – 2x + 1) and (2x – 1) & (4x² + 2x + 1), respectively.
What is a polynomial?A polynomial expression is an algebraic expression with variables and coefficients. Unknown variables are what they're termed. We can use addition, subtraction, and other mathematical operations. However, a variable is not divisible.
The expression is given below.
8x³ + 1 and 8x³ - 1³
(2x)³ + 1³ and (2x)³ - 1³
We know that the formula is given as,
a³ + b³ = (a + b) (a² – ab + b²)
a³ – b³ = (a – b) (a² + ab + b²)
Then the expression is written as,
(2x)³ + 1³ = (2x + 1) [(2x)² – 2x + 1²]
(2x)³ + 1³ = (2x + 1) (4x² – 2x + 1)
(2x)³ – 1³ = (2x – 1) [(2x)² + 2x + 1²]
(2x)³ – 1³ = (2x – 1) (4x² + 2x + 1)
The factors of the expression 8x³ + 1 and 8x³ - 1³ will be (2x + 1) & (4x² – 2x + 1) and (2x – 1) & (4x² + 2x + 1), respectively.
More about the polynomial link is given below.
https://brainly.com/question/17822016
#SPJ2
Related Questions
For a $1,000 loan at a rate of 16 3/4 % for 5 years, the simple interest is
Answers
Answer:
$837.50
Step-by-step explanation:
(1000×16.75×5)/100
83750/100=
$837.50
The work shows how to use long division to find?
Answers
Answer:
remainder = [tex]\frac{1}{x-2}[/tex]
Step-by-step explanation:
The remainder is the value of the subtraction of the last 2 lines in the procedure.
5x - 9
- (5x - 10)
That is
5x - 5x = 0 and - 9 - (- 10) = - 9 + 10 = 1
over the divisor x- 2 , gives
remainder = [tex]\frac{1}{x-2}[/tex]
What is the sum of the arithmetic sequence 3, 9, 15
if there are 34 terms?
Answers
===================================================
Work Shown:
a = first term = 3
d = common difference = 6
S(n) = sum of the first n terms of an arithmetic sequence
S(n) = (n/2)*(2a + d(n-1))
S(34) = (34/2)*(2*3 + 6(34-1))
S(34) = 3468
--------
Check:
3+9+15+21+27+33+39+45+51+57+63+69+75+81+87+93+99+105+111+117+123+129+135+141+147+153+159+165+171+177+183+189+195+201 = 3468
I used GeoGebra to generate the 34 terms shown above. You could do so by hand (start at 3; add 6 to each term to get the next one), but it's a tedious busywork type of problem in my opinion. It's best left to computer software.
When it was built, the given stadium held 31,080 fans per game. Today, it holds 86,047. How many more fans could attend per year (12 games) compared to the year it was built?
Answers
Answer:
659604 students
Step-by-step explanation:
86047-31080=54967 more students per game
54967 students per game x 12 games = 659,604 students
This one is confusing
Answers
Answer:
it s just asking for negative d
Step-by-step explanation:
Answer:
D(-1) = 2
Step-by-step explanation:
replace x with D(x), which in this case is -1
D(x) = x²-2x-1
replace x with -1
D(x) = (-1)²-2(-1)-1
Now solve using PEMDAS
