Which of the following equations is modeled by the graph?



A)

a = 50t

B)

a = 5t

C)

a = 50 + t

D)

a = 10t

Answer:

The answer is "0.7616".

Step-by-step explanation:

Using formula:

[tex]\text{P( at least one de-fective) = 1 - P( all calculators work )}[/tex]

                                          [tex]= 1-(\frac{34}{48}\times \frac{33}{47}\times \frac{32}{46}\times \frac{31}{45})\\\\= 1-(\frac{34}{1}\times \frac{11}{47}\times \frac{1}{23}\times \frac{31}{45})\\\\=1-(\frac{11594}{48647})\\\\=\frac{48647-11594}{48647}\\\\=\frac{37051}{48647}\approx 0.7616[/tex]

Answer:

$4,966.25

Step-by-step explanation:

3 x 15 = 45

After 15 years, Naomi would have earned a total of 45% interest rate.

3,425 x 1.45 = 4,966.25

Don't use .45 as the multiplier

3,425 x .45 = 1,541.25 <- incorrect

9514 1404 393

Answer:

  (a) Yes , the base is 1/e

Step-by-step explanation:

The variable is in the exponent, so this is an exponential function.

The base is the number that has the exponent. The base is (1/e).

Answer:

Step-by-step explanation:

bvxbvxbvxbvcvbbb cv

Answer:

Hello,

Step-by-step explanation:

Let say t the time the hose is left running

235 ≤ t < 245 (in min)

Let say d the amount of water coming out of the hose each minute

2.05 ≤ d < 2.15 (why d : débit in french)

235*2.05 ≤ t*d < 245*2.15

481.75 ≤ t*d < 526.75    (litres)

Answer:

Lower bound: [tex]495\; \rm L[/tex] (inclusive.)

Upper bound: [tex]505\; \rm L[/tex] (exclusive.)

Step-by-step explanation:

The amount of water from the hose is the product of time and the rate at which water comes out.

When multiplying two numbers, the product would have as many significant figures as the less accurate factor.

In this example, both factors are accurate to two significant figures. Hence, the product would also be accurate to two significant figures. That is:

[tex]240 \times 2.1 = 5.0 \times 10^{2}\; \rm L[/tex] ([tex]500\; \rm L[/tex] with only two significant figures.)

Let [tex]x[/tex] denote the amount of water in liters. For [tex]x\![/tex] to round to [tex]5.0 \times 10^{2}\; \rm L[/tex] only two significant figures are kept, [tex]495 \le x < 505[/tex]. That gives a bound on the quantity of water from the hose.

Answer:

1250 supermarkets

Step-by-step explanation:

Given

[tex]\frac{dN}{dt} = N(1 - 0.0008N)[/tex]

[tex]N(0) = 1[/tex]

Required

Number of supermarkets over a long period of time

To do this, we simply set

[tex]\frac{dN}{dt} = 0[/tex]

So, we have:

[tex]N(1 - 0.0008N) = 0[/tex]

Split

[tex]N = 0\ or\ 1 - 0.0008N = 0[/tex]

Solve: [tex]1 - 0.0008N = 0[/tex]

Collect like terms

[tex]0.0008N = 1[/tex]

Make N the subject

[tex]N = \frac{1}{0.0008}[/tex]

[tex]N = 1250[/tex]

So:

[tex]\lim_{t \to \infty} N(t) = 1250[/tex]

Answer:

The answer is "[tex]\chi^2_{L} = 4.575 \ and\ \chi^2_{U}= 19.675[/tex]"

Step-by-step explanation:

[tex]n=12\\\\\ c= 0.9[/tex]

Calculating the level of significance [tex](\alpha) = 1 -c[/tex]

                                                                  [tex]=1-0.9\\\\=0.1[/tex]

Calculating the degrees of freedom:

[tex]df=n-1=12-1=11[/tex]

Calculating the critical value:

Applying the Chi-Square table, the critical values for the two-tailed test with a degree of freedom  (11) for the significance level of [tex]\alpha = 0.1[/tex]:

[tex]\chi^2_{L} = 4.575 \\\\\chi^2_{U}= 19.675[/tex]

Answer:

The two squares are 81 and 100, and their difference is 19

Step-by-step explanation:

Hey there!

Let's take out the square of 1st ten natural numbers to find out the exact answer.

1² = 1

2² = 4

3² = 9

4² = 16

5² = 25

6² = 36

7² = 49

8² = 64

9² = 81

10² = 100

Now; You can take any of these numbers and subtract from their squares.

So, let's check 6² and 5²

36-25 = 11 which is not equal to 19

Again check for 10²-9²

100 - 81 = 19 (True value)

Therefore, 19 can be expressed as the difference of square of 10 and 9.

Hope it helps!

Answer:

There is no sufficient evidence to support the claim.

Step-by-step explanation:

Given the data:

7.91, 7.85, 6.82, 8.01, 7.46, 6.95, 7.05, 7.35, 7.25, 7.42

Sample size, n = 10

The sample mean, xbar = ΣX/ n = 74.07 / 10 = 7.407

The sample standard deviation, s = 0.41158 ( from calculator)

The hypothesis :

H0 : μ = 7

H0 : μ ≠ 7

The test statistic :

(xbar - μ) ÷ (s/√(n))

(7.047 - 7) ÷ (0.41158/√(10))

0.047 / 0.1301530

Test statistic = 0.361

Testing the hypothesis at α = 0.05

The Pvalue ;

df = n - 1 ; 10 - 1 = 9

Two tailed test

Pvalue(0.361, 9) = 0.7263

Since the Pvalue > α ; we fail to reject the Null and conclude that there isn't sufficient evidence to support the claim.

Answer:

142

Step-by-step explanation:

If the enrollment is five times as big, then that is six different things. So, take 852 and divide it by 6 to get 142. Or in other words:

852÷6=142

142x6=856

I hope this helps. Cheers^^

Answer:

Step-by-step explanation:

For each game played the chance of winning is 0.05 and losing is 0.95.

If the student wins, they get $5 -$1 = $4, but they lose $1.

Expected value is:

It means you will make $0.75 per average game.

Answer:

21.8

Step-by-step explanation:

Step 1

This is a problem on finding the mean of continuous grouped data. We first find the midpoint of each interval. For example, the first interval or class is 0 - 10. The mid-point of this class will be (0 + 10)/2 = 5.

fullscreen

Step 2

We now calculate the product of mid-point and frequency for each class. Here, the number of athletes in each class is the frequency of that class. For example, for the first class 0 – 10, its frequency is 3.

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Step 3

We can now use the formula to calculate mean. Note that t...

Answer:

43

Step-by-step explanation:

only 7 out of the 50 got both wrong

Answer:

Step-by-step explanation:

Write the options so they are homogeneous in content. • Use answers given in previous open-ended exams to provide realistic distractors. 2. Use a Question ...

Answer:

x=6

Step-by-step explanation:

5x - 11 = 19

5x = 30

x = 6

20characters

5x = 19+11 5x = 30 x = 30/5 x = 6

Answer:

1 and 5 sevenths of a bag

Step-by-step explanation:

2/7 males half to it takes 4/7 to make a full one multiply 4 by 3 and you get 12/7 so that makes 1 and 5/7

Answer:

1¼ cups

Step-by-step explanation:

2¼ ÷ 1/4/5 =

9/4 ÷ 9/5 =

9/4 x 5/9 =

5/4 = 1¼

9514 1404 393

Answer:

  35 miles

Step-by-step explanation:

The relevant relation is ...

  distance = speed × time

The total distance the trolley traveled is ...

  d = (20 mi/h) × (3.5 h) = 70 mi

The distance is the same in both directions, so the trolley traveled half this distance in one direction.

The trolley traveled 35 miles in one direction.

9514 1404 393

Answer:

  146.0 m²

Step-by-step explanation:

The lateral areas of the cylinder and cone are given by the formulas ...

  A = πrs . . . . cone area; radius r, slant height s

  A = 2πrh . . . . cylinder area; radius r, height h

__

The total area lateral area of the silo is ...

  A = π(2.8 m)(6.6 m) +2π(2.8 m)(5 m) = π(2.8 m)(6.6 m +2(5 m)) = 46.48π m²

  A ≈ 146.0 m² . . . area of sides and roof of silo

_____

Additional comment

The answer is requested in cubic meters. Area has units of square meters. There is nothing in this problem statement that seems to be requesting a volume, which is what would have units of cubic meters.

Answer:

The materials price variance is usually the responsibility of the purchasing manager. The materials quantity and labor efficiency variances are usually the responsibility of production managers and supervisors.

Let missing side be x

If both polygons are similar

[tex]\\ \sf\longmapsto \dfrac{3}{4}=\dfrac{18}{x}[/tex]

[tex]\\ \sf\longmapsto 3x=4(18)[/tex]

[tex]\\ \sf\longmapsto 3x=72[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{72}{3}[/tex]

[tex]\\ \sf\longmapsto x=24[/tex]

Answer:

The minimum number of subjects needed is 385.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

95% confidence, within 5 percentage points, and a previous estimate is not known.

The sample size is n for which M = 0.05. We don't know the true proportion, so we use [tex]\pi = 0.5[/tex]

Then

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.05 = 1.96\sqrt{\frac{0.5*0.5}{n}}[/tex]

[tex]0.05\sqrt{n} = 1.96*0.5[/tex]

[tex]\sqrt{n} = \frac{1.96*0.5}{0.05}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96*0.5}{0.05})^2[/tex]

[tex]n = 384.16[/tex]

Rounding up:

The minimum number of subjects needed is 385.

Answer:

f(x) = 2x + 1, g(x) = 3x - 2 and fg(x) = 5

Step-by-step explanation:

Answer:

320/3

Step-by-step explanation:

First find the common ratio

20/80 = 1/4

The sum of an infinite geometric series

sum = a1/ (1-r)  where a1 is the first term and r is the common ratio

         =80/ ( 1-1/4)

         = 80/(3/4)

        = 80 *4/3

      = 320/3

Answer:

Kindly check explanation

Step-by-step explanation:

H0 : μ = 15.7

H1 : μ < 15.7

This is a one sample t test :

Test statistic = (xbar - μ) ÷ (s/√(n))

n = sample size = 33

Using calculator :

The sample mean, xbar = 15.41

The sample standard deviation, s = 0.419

Test statistic = (15.41 - 15.70) ÷ (0.419/√(33))

Test statistic = - 3.976

Using the Pvalue calculator :

Degree of freedom, df = n - 1 ; 33 - 1 = 32

Pvalue(-3.976, 32) = 0.000187

Decison region :

Reject H0 if Pvalue < α

Since Pvalue < α ; we reject H0

There is significant evidence to conclude that the true average height of the seedlings treated with an extract from Vinca minor roots is less than 15.7 cm.

Answer:

[tex]\boxed {\boxed {\sf x \approx 1.9}}[/tex]

Step-by-step explanation:

We are asked to find x, a missing side in a triangle.

This is a right triangle because there is a small square in the corner representing a 90 degree or right angle. Therefore, we can use right triangle trigonometry. The three main functions are:

Examine the triangle. We will use angle S, measuring 54 degrees, for theta. Side QR, measuring x, is opposite angle S. Side QS, measuring 2.3, is the hypotenuse because it is opposite the right angle. Since we have the opposite and hypotenuse, we will use sine.

[tex]sin \theta = \frac {opposite}{hypotenuse}[/tex]

[tex]sin (54)= \frac{ x}{2.3}[/tex]

We are solving for x, so we must isolate the variable. It is being divided by 2.3 The inverse operation of division is multiplication, so we multiply both sides by 2.3

[tex]2.3* sin (54)= \frac{x}{2.3}*2.3[/tex]

[tex]2.3* sin (54)=x[/tex]

[tex]2.3*0.8090169944=x[/tex]

[tex]1.860739087 =x[/tex]

Round to the nearest tenth. The 6 in the hundredth place to the right tells us to round the 8 up to a 9.

[tex]1.9 \approx x[/tex]

x is approximately 1.9

please mark this answer as brainlist

Answer:

Placements are basically extended internships or work experience assignments

Step-by-step explanation:

Answer:

Hi!

Step-by-step explanation:

1234567890987654211234567890......

Step-by-step explanation:

12345678890098764321

Answer: y=2/3X- 4/3

Step-by-step explanation:

Slope = (4-2)/(4-1)=2/3

Y-2=2/3(x-1)

Y-2=2/3x-2/3

Y=2/3X-2/3+2

Y=2/3X-4/3

Answer:

hxvkgyjdh ht yshysfhyys is not working properly configured form and the kids will not work with a little over again. thank you

Answer:

12.6 mi

Step-by-step explanation:

Arc length = 2πr (Θ/360)

2π(12) (60/360)

= 12.6 mi

Answered by g a u t h m a t h