what’s is the quotient for the rational expression shown below?

Answer:

b 3.1 and 3.2

Step-by-step explanation:

3.15 is the average number of 3.1 and 3.2, because

(3.1+3.2)/2=3.15

Answer:

B

Step-by-step explanation:

sin(theta) = sqrt(1-cos^2(theta)

sin(theta)=sqrt(1-1/2)=sqrt(1/2)=sqrt(2)/2 but as theta is in IV quadrant, sin(theta) will be negative

Answer:

[tex]f^{-1}[/tex](x) = 0.5x + 2

Step-by-step explanation:

let y = f(x) and rearrange making x the subject , that is

y = 2x - 4 ( add 4 to both sides )

y + 4 = 2x ( divide both sides by 2 )

[tex]\frac{y+4}{2}[/tex] = x

Change y back into terms of x with x = [tex]f^{-1}[/tex] (x)

[tex]f^{-1}[/tex] (x) = [tex]\frac{x+4}{2}[/tex] = 0.5x + 2

Answer: F -1(x)  = 0.5 x + 2

Step-by-step explanation:

Just took the test on edmentum and got a 100

Answer:

Step-by-step explanation:

Answer:

x = 3 , x = -5

Step-by-step explanation:

Given x^2 +2x=15 add 1 to both sides to get:

x^2 + 2x + 1 =16

(x+1)^2 = 16

x + 1 = ± [tex]\sqrt{16}[/tex] = ± 4

x = -1 ± 4

x = 3 or x = -5

Answer:

4.4 cm

Step-by-step explanation:

Arc length = 2*pi*r*(central angle) / 360

Arc length = 2*(22/7)*3.5*(72/360)=4.4 cm

9514 1404 393

Answer:

  $36,259.78

Step-by-step explanation:

The formula for compound interest is ...

  A = P(1 +r/n)^(nt)

where principal P is invested at annual rate r for t years compounded n times per year.

Here, you have P = 17000, r = 0.06, n = 1, t = 13.

  A = 17000(1 +0.06)^13 = 17000(2.13292826) = 36,259.78

The accumulated value after 13 years is $36,259.78.

Answer:

f(2) = 8

Step-by-step explanation:

f(x) = x^2 + 8x – 12

Let x = 2

f(2) = 2^2 + 8*2 – 12

     = 4 + 16 -12

        =20-12

        = 8

Answer:

[tex]f(x) = {x}^{2} + 8x - 12 \\ f(2) = (2)^{2} + 8(2) - 12 \\ = 4 + 16 - 12 \\ f(2) = 8[/tex]

I hope I helped you^_^

Answer:

| h-52 | < or equal to 1

Step-by-step explanation:

Answer:

Step-by-step explanation:

These are really difficult, but one thing I noticed pretty much across the board is that we state our trig ratios in terms of sin and cos using the Pythagorean identity:

[tex]sin^2x+cos^2x=1[/tex], even this one where tangents are involved. Let's begin:

If tan⁻1(x) = u (this is just a substitution to make things easier down the road), then tan(u) = x

If tan⁻1(y) = v, then tan(v) = y.

If that be the case, what we have as a rewrite from our original problem is

sin(u + v) which, according to the identity is:

[tex]sin(u-v)=sin(u)cos(v)-sin(v)cos(u)[/tex] which also tells us that we need those tangents in terms of sines and cosines, as stated earlier. We will take the Pythagorean identity and solve it for both sinx and cosx. Sinx first:

If [tex]cos^2x+sin^2x=1[/tex] then solving for sin:

[tex]\frac{cos^2x}{sin^2x}+\frac{sin^2x}{sin^2x}=\frac{1}{sin^2x}[/tex] (as you can see, I just divided everything by sin-squared):

[tex]cot^2x+1=\frac{1}{sin^2x}[/tex] and

[tex]\frac{1}{tan^2x}+1=\frac{1}{sin^2x}[/tex] and work on eliminating the denominators by multiplying through by sin-squared times tan-squared:

[tex]sin^2x*tan^2x(\frac{1}{tan^2x}+1=\frac{1}{sin^2x})[/tex] which simplifies to

[tex]sin^2x+sin^2x*tan^2x=tan^2x[/tex] and factor out on the left:

[tex]sin^2x(1+tan^2x)=tan^2x[/tex] and solve for sin-squared:

[tex]sin^2x=\frac{tan^2x}{1+tan^2x}[/tex] and take the square root of both sides:

[tex]sinx=\frac{tanx}{\sqrt{1+tan^2x} }[/tex] .  Do the same to solve for cos(x) to get:

[tex]cosx=\frac{1}{\sqrt{1+tan^2x} }[/tex] and now we're ready to fill in our formula for sin(u + v):

[tex]\frac{tanu}{\sqrt{1+tan^2u} }*\frac{1}{\sqrt{1+tan^2v} }[/tex]  -  [tex]\frac{tanv}{\sqrt{1+tan^2} }*\frac{1}{\sqrt{1+tan^2u} }[/tex]  and...

since tanu = x and tanv = y:

[tex]\frac{x}{\sqrt{1+x^2}}*\frac{1}{\sqrt{1+y^2}}-\frac{y}{\sqrt{1+y^2}}*\frac{1}{\sqrt{1+x^2} }[/tex] which, in the end, simplifies to

[tex]\frac{x-y}{\sqrt{1+x^2}*\sqrt{1+y^2} }[/tex] and you're done! Yikes to that!!!!

a:-

f(x)=2x+3

[tex]\\ \rm\Rrightarrow f(1)=2(1)+3=2+3=5[/tex]

[tex]\\ \rm\Rrightarrow f(-5)=2(-5)+3=-10+3=-7[/tex]

[tex]\\ \rm\Rrightarrow f(a)=2a+3[/tex]

[tex]\\ \rm\Rrightarrow f(a+2)=2(a+2)+3=2a+4+3=2a+7[/tex]

[tex]\\ \rm\Rrightarrow f(b)=2b+3[/tex]

b:-

f(x)=x+4

[tex]\\ \rm\Rrightarrow f(-2)=(-2)+4=2[/tex]

[tex]\\ \rm\Rrightarrow f(3)=3+4=7[/tex]

[tex]\\ \rm\Rrightarrow f(7)=7+4=11[/tex]

Step-by-step explanation:

[tex]thank \: you[/tex]

Answer:

5a(6[tex]b^{4}[/tex] - [tex]a^{5}[/tex])

Step-by-step explanation:

Given

30a[tex]b^{4}[/tex] - 5[tex]a^{6}[/tex] ← factor out 5a from each term

= 5a(6[tex]b^{4}[/tex] - [tex]a^{5}[/tex] ) ← in factored form

Answer:

I CANT SEE THE QUESTION CAN U UPLOAD IT AGAIN

Step-by-step explanation:

Answer:

range

Step-by-step explanation:

The difference between the largest and smallest value in a data set is the range

Answer:

Range

Step-by-step explanation:

I hope this will help you buddy

Answer:

Not sure if this will help but that looks like a bisection of angles BAC and TSR.

Answer:

y=x^2-11

y=6^2-11

6×6=36

36-11=35

y=35

Answer:

one and a half quaters

Step-by-step explanation:

4/4 is a whole

The they take one 1/4

then that gives you 3/4

which is then 1.5/4 left for you

Answer:

3/8

Step-by-step explanation:

Hi! So what really helps me sometimes is to draw a circle and split it. I shaded 1/4 (Lionel's quarter) first. Now, there is 3/4 of the cake left. Helen has half of the rest, which means she has half of 3/4. 1/2 of 3/4 (which is basically 1/2 x 3/4) = 3/8. This means Helen has 3/8 of the cake. I then split my circle into eighths and shaded in 3. This left me with 3/8 of the cake left for Sophie. This means the fraction that remains for her is 3/8.  

I hope this helped :)

Answer:

Hello,

Step-by-step explanation:

Q.5(b) The population {(P) in millions} of a country is estimated by the function, P=125e0.035t, t = time measured in years since 1990. (a) what is the population expected to equal in year 2000 (b) determine the expression for the instantaneous rate of change in the population (c) what is the instantaneous rate of change in the population expected to equal in year 2000.

[tex]P(t)=125*e^{0.035*t}\\a)\\P(2000)=125*e^{0.035*(2000-1990)}=177.38...\\\\b)\\P'(t)=125*0.035*e^{0.035*t}\\\\c)\\\\P'(2000)=125*0.035*e^{0.035*(2000-1990)}=6.2084...[/tex]

Answer:

x p t^2

p = 0

t = 0

x = 0

Δ = 0

Paridad

extraño

d/dx(x p t^2) = p t^2

Step-by-step explanation:

Answer:

1.3

Step-by-step explanation:

bc for each time x increases by 1, it multiplies by 1.3

i cant think of any other way to explain it

but   i hope this helped :D

Answer:

1.3 times

Step-by-step explanation:

f(x)= 68 (1.3) ^x

it, means each year, the expected number of squirrels is 1.3 times, the number the year before.

x=0 so, f(0)=68

New x=1, so f(1)= 68(1.3)¹

= 68 × 1.3

f (1)= f(0) × 1.3

So, 1.3 times

OAmalOHopeO

Answer:

5785.12

Step-by-step explanation:

I showed the picture instead of explaining

Answer:

80

Step-by-step explanation:

Let's write out the equation:

8(20+80/2)/[(54/9+14)/4]

For the first part we get 8(100/2)

Then 50x8

Then 400

For the second part we have (6+14)/4 as we divide 54 by 9. PEMDAS

Then 20/4

Then 5

So our final answer is 400/5 which is 80.

Hope this helps!

The given mathematical statement can be written in the form of mathematical expression as -{x} = {(20 + 80)/(2 x 8)} ÷ [{54/(9 + 14)}/4].

A function is a relation between a dependent and independent variable.

We can write the examples of function as -

y = f(x) = ax + b

y = f(x, y, z) = ax + by + cz

Given is the mathematical statement as -

(20+80 divided by 2x8) divided [(54 divided by 9+14)divided by 4]

We can write the given statement in the form of mathematical expression as -

{x} = {(20 + 80)/(2 x 8)} ÷ [{54/(9 + 14)}/4]

Simplifying, we get -

{x} = {100/16} ÷ {54/23}/4

{x} = 100/16 ÷ 54/92

{x} = 100/16 x 92/54

{x} = 10.64

Therefore, the given mathematical statement can be written in the form of mathematical expression as -{x} = {(20 + 80)/(2 x 8)} ÷ [{54/(9 + 14)}/4].

To solve more questions on functions, visit the link below-https://brainly.com/question/30194223

#SPJ2

Answer:

3/4 cup of milk.

Step-by-step explanation:

1 1/2= 6/4. 6÷2=3.

Answer:

3/4

Step-by-step explanation:

Half the recipe means multiply by 1/2

1 1/2 * 1/2

Change the mixed number to an improper fraction

(2*1+1)/2 * 1/2

3/2 * 1/2

3/4

Answer:

Step-by-step explanation:

Amount of work done by 15 men is:

Same work can be done by 25 men, in 15 days, so 10 more men should be added.

(u × v) • w makes sense, since u × v is another vector, and so (u × v) • w is a scalar.

u × (v • w) does not make sense, since v • w is a scalar, and the cross product is not defined between a vector and a scalar.

(u × v) × w makes sense, since u × v is a vector and so is w.

u • (v • w) does not make sense, since v • w is scalar, and the dot product is not defined between a vector and a scalar.

Answer:

[tex]x = -5 \text{ or } x =3[/tex]

Step-by-step explanation:

We want to find the real solutions to the equation:

[tex]\displaystyle 8^{x^2 + 2x - 15} = 1[/tex]

Recall that any value raised to zero (except for zero itself) is one.

In other words, the exponent must equal zero:

[tex]x^2 + 2x - 15 = 0[/tex]

Solve for x. Factor:

[tex](x+5)(x-3) = 0[/tex]

Zero Product Property:

[tex]x + 5 = 0\text{ or } x - 3 = 0[/tex]

Solve for each case. Hence:

[tex]x = -5 \text{ or } x =3[/tex]

In conclusion, our two real solutions are:

[tex]x = -5 \text{ or } x =3[/tex]

Step-by-step explanation:

As we know that,

In area of triangle , breadth =6inch,similarily ,height =8inch

now ,

Area of triangle = 1/2 ×b×h

= 1/2 × 8 ×6

=24inch^2

also,

In another figure,we can say

a=10 inch,b=16 inch and h=9 inch

similarly,

Area of trapizium = 1/2 h(a+b)

= 1/2 ×9(10+16)

=9/2 ×26

=9×13

=117inch^2

now ,

total area of figure =117 +24 =141inch^2

therefore,total area of figure is 141 inch^2

Answer:

12

Step-by-step explanation:

4s multiples:

4,8,12,16,20,24

6s multiples:

6,12,18,24,30,36

lowest number that is a common multiple between both 4 and 6:

12

Answer: 2

Step-by-step explanation:

Answer: -46

Step-by-step explanation:

[tex]u_1=50=50-(1-1)*4\\u_2=46=50-(2-1)*4\\u_3=42=50-(3-1)*4\\...\\\\u_n=50-(n-1)*4\\\\\\u_{25}=50-(25-1)*4=-46\\\\\\Answer\ -46\\[/tex]