Answer:
it's answer is 1 newton
A ball rolls from x = -9.8 m to x = 11.0 m in 5.0 seconds what was its average velocity
Explanation:
avg velocity = total displacement / total time taken = (11 - (-9.8)) / 5.0 = 4.16m/s to the right when taken right to be positive
need help with these 4 ASAP. if u can answer even 1 of them that would be amazing! formula sheet provided
1. a) a mass of 5.0kg is at rest at the top of an inclined plane, 5.0m above the ground. if the inclined plane is frictionless, calculate the final velocity of the mass as it reaches the bottom of the inclined plane?
b) if the mass slides down the plane and encounters a spring with a force constant of 8000.00 N/m by how much will the spring be compressed when the mass comes to a stop?
c) if the mass is found to move down the inclined plane at a constant velocity what is the force of friction between the ramp and the mass? (the angle of incline is 30°)
2. a 12 m long ramp has its high end 4.0m above the low end. a crate of mass 10kg is given a sharp push so that it begins to slide down the ramp from the top of the ramp with an initial speed of 4.0m/s. the force of friction along the ramp is 20N. determine the speed of the crate at the bottom of the ramp.
3. a 7.0 kg crate is dropped from a window 8.0m above the ground. if the average air resistance on the crate is 20.0N, what is the crates kinetic energy and velocity upon reaching the ground?
4. a 0.25 kg puck moving with a constant speed across a 2.0m stretch of horizontal frictionless ice. how much work is done?
you may want to google the answers cuz that is a lot
. If an object has a mass of 200 kg ant a velocity of 30 m/s... what is the Kinetic Energy
(KE) of the object?
Answer:
90,000 JExplanation:
The kinetic energy (KE) of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
From the question we have
[tex]k = \frac{1}{2} \times 200 \times {30}^{2} \\ = 100 \times 900[/tex]
We have the final answer as
90,000 JHope this helps you
Answer:
When it hits a wooden target, the ball exerts a force on the fibers in the wood, splintering. First, heavier objects that are moving have more kinetic energy than lighter ones: a In equation form: kinetic energy (joules) = 1/2 x mass (kg) x velocity2 (m/s) Note that: 200 kg-m2/s2 = 200 (kg-m/s2) x m = 200 N x m = 200 joules.
Explanation:
How much heat is absorbed by 60 g of copper (c=385 J/kg K) when it is heated
from 20°C to 80°C?
Answer:
Q = 1386 J
Explanation:
Mass, m = 60 g = 0.06 kg
Specific heat of copper, c=385 J/kg K
It is heated from 20°C to 80°C.
We need to find the heat absorbed. It can be given by the formula as follows :
[tex]Q=mc\Delta T\\\\Q=0.06\times 385 \times (80-20)\\\\Q=1386\ J[/tex]
So, 1386 J of heat is absorbed.
This diagram shows two different forces acting on a skateboarder. The
combined mass of the skateboard and the person is 65.2 kg. Based on this
information, what is the acceleration of the skateboarder?
Answer:
Option C. 0.36 m/s² to the left.
Explanation:
The following data were obtained from the question:
Mass of skateboarder = 65.2 Kg
Force in the right direction (Fᵣ) = 31.8 N
Force in the left direction (Fₗ) = 55.2 N
Acceleration of the skateboarder =.?
Next, we shall determine the net force acting on the skateboarder. This can be obtained as illustrated below:
Force in the right direction (Fᵣ) = 31.8 N
Force in the left direction (Fₗ) = 55.2 N
Net force (Fₙ) =?
Fₙ = Fₗ – Fᵣ
Fₙ = 55.2 – 31.8
Fₙ = 23.4 N to the left
Thus, the net force acting on the skateboarder is 23.4 N to the left.
Finally, we shall determine the acceleration of the skateboarder. This can be obtained as follow:
Mass of skateboarder = 65.2 Kg
Net force (Fₙ) = 23.4 N to the left
Acceleration (a) of the skateboarder =.?
Net force = mass × acceleration
23.4 N = 65.2 × a
Divide both side by 65.2
a = 23.4 / 65.2
a = 0.36 m/s² to the left.
Therefore, the acceleration of the skateboarder is 0.36 m/s² to the left.
Answer:
C. 0.36 [tex]m/s^{2}[/tex] to the left
Explanation:
If a 8.1g ring is heated using 10.0 ), its temperature rises 21.7°C. Calculate the specific
heat capacity of the ring.
Explain What determines the amount of
chemical energy a substance has?
What household item turns electrical energy into radiant energy
Answer:
Television,video game consoles
Answer:
A toaster
Explanation:
Since it heats up with heat waves of radiant energy
explain the change of frequency of the wave if the tension of the string is increased
Answer:
Increasing the tension on a string increases the speed of a wave, which increases the frequency (for a given length). Pressing the finger at different places changes the length of string, which changes the wavelength of standing wave, affecting the frequency.
Explanation:
What does it mean to say that the speed of a vehicle is 40 mi/h?
A 50 kg pitcher throws a baseball with a mass of 0.15 kg, if the ball is thrown with a positive velocity of 35 m/s, and there is no net force on the system, what is the velocity of the pitcher?
Answer: A. -0.1 m/s
Explanation:
Answer:
The Answer is the first one, A. Or -0.1 m/s.
Explanation:
How do you deal with unanswered questions after death?
Answer: you have loved ones who help you get through it and help answer the questions they know.
Answer:
you have loved ones who help you get through it and help answer the questions they know.
Explanation:
*
Which of the following is an example of projectile motion
A student sitting at their desk staring at their test
An eraser resting on the desk
A pencil mid air falling toward the ground
O A back pack placed underneath the desk
1. Two forces F~ 1 and F~ 2 are acting on a block of mass m=1.5 kg. The magnitude of force F~ 1 is 12N and it makes an angle of θ = 37◦ with the horizontal as shown in figure-1. The block is sliding at a constant velocity over a frictionless floor.
(a) Find the value of the normal force on the block.
(b) Find the magnitude of force F~2 that is acting on the block
(c) Find the magnitude of force F~ 2 if the block accelerates with a magnitude of a = 2.5 m/s2 along the direction of F~ 2 .
Answer:
Normal force=7.48 N
Explanation:
N+F~1 sinθ-mg=0
=>N=1.5*9.8-12 sin37◦
=>N=14.7-7.22=7.48 N
Giving brainlist ASAP!
Check all that apply!!
Answer:
metal seat belt and door handle
Explanation:
bc its all medal it _____ heat (forgot the word mybad)
3.1
power
Every day a certain household uses a 4.4 KW electric stove for 70 minutes, seven 150 W light bulbs for 7
hours each and miscellaneous appliances amounting to 1.8 KW/h. The 4 KW hot water cylinder switches
on for a total of 120 minutes during the day. If electricity cost 50c a KW/h. what is the monthly electricity
bill. (5 marks)
Answer:
The value is [tex]C = 30729\ c[/tex]
Explanation:
From the question we are told that
The power rating of the stove is [tex]P = 4.4 KW = 4.4 *10^{3} \ W[/tex]
The duration of its use everyday is [tex]t_1 = 70 \ minutes = 1.167 \ hours[/tex]
The rating of the light bulbs is [tex]P_2' = 150 W[/tex]
The number is [tex]n = 7[/tex]
The power rating of the total bulb is [tex]P_2 = 7 * 150 = 1050 \ W[/tex]
The duration of its use everyday is [tex]t_2 = 7 hours[/tex]
The power rating of miscellaneous appliance [tex]P_3 = 1.8 \ KW = 1.8 *10^{3} \ W[/tex]
The duration of its use everyday is [tex]t_3 = 1 hour[/tex]
The power rating of hot water [tex]P = 4 KW = 4 *10^{3} \ W[/tex]
The duration of its use everyday is [tex]t_4 = 120 \ minutes = 2 hours[/tex]
Generally the total electrical energy used in 1 month is mathematically represented as
[tex]E = P_1 * t_1 * 30 + P_2 * t_2 * 30 + P_3 * t_3 * 30+ P_4 * t_4 * 30[/tex]
=> [tex]E = 4.4*10^{3} * 1.167 * 30 + 1050 * 7 * 30 + 1.8 *1 * 30+ 4*10^{3} * 2 * 30[/tex]
=> [tex]E = 614598 \ W \cdot h[/tex]
=> [tex]E = 614.6 \ K W \cdot h[/tex]
Generally the monthly electricity bill is mathematically represented as
[tex]C = 614.6 * 50[/tex]
=> [tex]C = 30729\ c[/tex]
A spherical brass shell has an interior volume of 1.26 x 10-3 m3. Within this interior volume is a solid steel ball with volume of 0.63 x 10-3 m3. The space between the steel ball and the inner surface of the brass shell's filled completely with mercury. A hole's drilled through the brass, and the temperature of the arrangement in increased by 18 C°. How much mercury spills out?
Answer:
ΔV = 2.04 x 10⁻⁶ m³ = 2.04 cm³
Explanation:
First we will find the initial volume of mercury by subtracting the volume of the steel ball from the interior volume of the brass shell:
V = Vs - Vb
where,
V = Initial Volume of Mercury = ?
Vb = Volume of brass shell = 1.26 x 10⁻³ m³
Vs = Volume of Steel Ball = 0.63 x 10⁻³ m³
Therefore,
V = (1.26 x 10⁻³ m³) - (0.63 x 10⁻³ m³)
V = 0.63 x 10⁻³ m³
Now, we find the change in volume of mercury that will spill out due to increase in temperature:
ΔV = βVΔT
where,
ΔV = Amount of Mercury Spilled out = ?
β = Coefficient of Volumetric Expansion of mercury = 1.8 x 10⁻⁴ °C⁻¹
ΔT = Increase in temperature = 18 °C
Therefore,
ΔV = (1.8 x 10⁻⁴ °C⁻¹)(0.63 x 10⁻³ m³)(18 °C)
ΔV = 2.04 x 10⁻⁶ m³ = 2.04 cm³
The volume of mercury that spills out due to increase in temperature is [tex]2.04 \times 10^{-6} \ m^3[/tex].
The given parameters;
outer volume, V₁ = 1.26 x 10⁻³ m³inner volume, V₂ = 0.63 x 10⁻³ m³change in temperature, Δt = 18 ⁰CThe volume of mercury in the given shell is calculated as;
[tex]V= V_1 - V_2\\\\V= 1.26 \times 10^{-3} \ - \ 0.63 \times 10^{-3} \\\\V = 6.3 \times 10^{-4} \ m^3[/tex]
The change in the volume of the mercury is calculated as follows;
[tex]\Delta V = \beta V \Delta t\\\\[/tex]
where;
β is the coefficient of volumetric expansion of mercury[tex]\Delta V = (1.8 \times 10^{-4} ) \times (6.3\times 10^{-4}) \times 18\\\\\Delta V = 2.04 \times 10^{-6} \ m^3[/tex]
Thus, the volume of mercury that spills out due to increase in temperature is [tex]2.04 \times 10^{-6} \ m^3[/tex].
Learn more here:https://brainly.com/question/15662518
6. A painter weighing 800 newtons stands on a single board scaffold that is supported at each end
by a vertical rope from above. If one rope has a tension of 550 newtons and the other has a
tension of 450 newtons, what is the weight of the board?
Answer:
The weight of the board is 200 N
Explanation:
Translational Equilibrium
An object is in translational equilibrium if the velocity of its translational motion is constant or if it's at rest.
The painter is standing on the single board scaffold, obviously at rest. This means the sum of all translational forces must be zero.
If the tensions of both ropes are T1 and T2, the weight of the painter is Wp, and the weight of the board is Wb, then:
T1 + T2 - Wp - Wb = 0
Both tensions go vertically up and both weights go vertically down.
Solving for Wb:
Wb = T1 + T2 - Wp
Wb = 550 N + 450 N - 800 N
Wb = 200 N
The weight of the board is 200 N
a rocket leaving the lanch pad is ana exmaple of which law
Answer:
Newton's Third Law
The boat goes forward, you go backward! A rocket can lift off from a launch pad only when it expels gas out of its engine. The rocket pushes on the gas, and the gas in turn pushes on the rocket.
Explanation:
Newton's Third Law
The boat goes forward, you go backward! A rocket can lift off from a launch pad only when it expels gas out of its engine
Explanation:
Photons of infrared radiation with wavelengths longer than those of visible light will have what kind of energy compared to that of visisble light?
Answer:
Infrared photons carry lower radiation energy than the visible light.
Explanation:
Each photon carries an energy that is directly proportional to its frequency, being this proportionality constant the Planck's constant h.So, we can write the energy of a single photon as follows:[tex]E = h*\nu (1)[/tex]
Since there exists an inverse relationship between wavelength and frequency, and infrared radiation has longer wavelengths, this means that its frequency is lower than the one of the visible light.So, an infrared photon carries less energy that one of the visible light.Infrared photons carry lower radiation energy than the visible light.
What are visible and infrared radiation?
Visible light is the section of the spectrum of electromagnetic radiation which are visible to human eyes. The wavelength range of this light varies from 400 nm to 700 nm .
Each photon carries an energy that is directly proportional to its frequency, being this proportionality constant the Planck's constant h.
So, we can write the energy of a single photon as follows:
[tex]E=h\nu[/tex]
Since there exists an inverse relationship between wavelength and frequency, and infrared radiation has longer wavelengths, this means that its frequency is lower than the one of the visible light.
So, an infrared photon carries less energy than one of the visible light.
To know more about Visible and infrared radiation, follow
https://brainly.com/question/11847490
Convert this number to standard notation: 1.4 x 10^-2*
Answer:
0.014
Explanation:
here
1.4 x 10^-2
=0.014
may this help
Which change in an object will increase its thermal energy?
A. A decrease in either mass or temperature
B. An increase in either mass or velocity
C. A decrease in either mass or velocity
D. An increase in either mass or temperature
Answer:
Heat decreases the thermal energy of an object as energy moves to the air. Heat causes the thermal energy of the object to increase as energy moves from the warmer air to the colder object. Heat has no effect on thermal energy, but it increases the potential energy of an object.
which transition metals have more in common than other
a) alkali metals
b) lanthanides
c) actinides
d) lanthanides and actinides
Answer:
A. alkali metals
Explanation:
im not sure about that
Answer:
c
Explanation:
haha signs d d Sd Didi d do f idi
You are looking straight down on a magnetic compass that is lying flat on a table. A wire is stretched horizontally under the table, parallel to and a short distance below the compass needle. The wire is then connected to a battery so that a current I flows through the wire. This current causes the north pole of the compass needle to deflect to the left. The questions that follow ask you to compare the effects of different actions on this initial deflection.
If the wire is lowered farther from the compass, how does the new angle of deflection of the north pole of the compass needle compare to its initial deflection?
Answer:
It is smaller
Explanation:
a ball is thrown downward from the top of roof with a speed of 25 m/s. after 2 s, its velocity will be:
Answer:
12.5
Explanation:
first, v=d/t
v=25/2
v=12.5
The final velocity of the ball is 44.6 m/s.
The given parameters;
initial velocity of the ball, u = 25 m/stime of motion of the ball, t = 2 sThe velocity of the ball increases as the ball moves downward and it will become maximum before the ball hits the ground.
This velocity is known as the final velocity of the ball.
The final velocity of the ball is calculated as follows;
v = u + gt
where;
v is the final velocity of the ballg is the acceleration due t gravity = 9.8 m/s²v = 25 + 9.8(2)
v = 44.6 m/s
Thus, the final velocity of the ball is 44.6 m/s.
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Cliff divers at Acapulco jump into the sea from a cliff 36 meters high. At the level of the sea, there is an outcropping of rock that sticks out a horizontal distance of 6 meters. With what minimum horizontal velocity must the cliff divers leave the top of the cliff if they are to miss this rocky outcropping?
Answer:
The cliff drivers must leave the top of the cliff at 2.21 m/s
Explanation:
Horizontal Motion
When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.
The range or maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
If the range is known and we are required to find the initial speed of launch, then we can solve the above equation for v as follows:
[tex]\displaystyle v=d\cdot\sqrt{\frac {g}{2h}}[/tex]
Cliff drivers jump into the sea from a height of h=36 m and must pass over an obstacle d=6 meters away from the cliff.
Let's calculate the speed needed:
[tex]\displaystyle v=6~m\cdot\sqrt{\frac {9.8~m/s^2}{2\cdot 36~m}}[/tex]
[tex]\displaystyle v=6~m\cdot\sqrt{\frac {9.8~m/s^2}{72~m}}[/tex]
[tex]v=2.21~m/s[/tex]
The cliff drivers must leave the top of the cliff at 2.21 m/s
what force is needed to accelerate 300kg rock as a rste of 4m/s
Answer:
60 maybe
Explanation:
Answer:
1200 newton
and that's 4m/s² not 4 m/s
A 10.0-V battery is connected to a 120-Ω resistor. Ignoring the internal resistance of the battery, calculate the power delivered to the resistor.
Answer:
0.83W
Explanation:
Given parameters:
Voltage of the battery = 10V
Resistance = 120Ω
Unknown:
Power delivered by the resistor = ?
Solution:
The power delivered by the resistor can be derived using the expression below;
Power = [tex]\frac{V^{2} }{R}[/tex]
V is the voltage
R is the resistance
Now, insert the parameters and solve
Power = [tex]\frac{10^{2} }{120}[/tex] = 0.83W
A spy satellite uses a telescope with a 1.7-m-diameter mirror. It orbits the earth at a height of 180 km.
What minimum spacing must there be between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope?
Assume the telescope's resolution is limited only by diffraction and that it is recording light with a wavelength of 500 nm.
Answer: the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm
Explanation:
Given that;
diameter of the mirror d = 1.7 m
height h = 180 km = 180 × 10³ m
wavelength λ = 500 nm = 5 × 10⁻⁹ m
Now Angular separation from the peak of the central maximum is expressed as;
sin∅= 1.22 λ / d
sin∅ = (1.22 × 5 × 10⁻⁹) / 1.7
sin∅ = 3.588 × 10⁻⁷
we know that;
sin∅ = object separation / distance from telescope
object separation = sin∅ × distance from telescope
object separation = 3.588 × 10⁻⁷ × 180 × 10³
object separation =6.45 × 10⁻² m
then we convert to centimeter
object separation = 6.45 cm
Therefore the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm
A wire carrying a current is shaped in the form of a circular loop of radius 4.0 mm. If the magnetic field strength at its center is 1.1 mT with no external magnetic fields contributing to it, what is the magnitude of the current that flows through the wire? A) 17 A B) 28 A C) 14 A D) 7.0 A
Answer:D) 7.0 A
Explanation:
The magnetic field strength at the center of a circular loop is calculated using the formulae
B = μ₀I / 2R
where B = ,magnetic field strength= 1.1mT = 1.1 X 10^-3T
μ₀= magnetic constant or the permeability of free space=4π X 10^-7 H/m
R = radius = 4.0mm =4.0 x 10^-3m
I= Current = ?
B=μ₀I / 2R
I = B2R /μ₀
I = 1.1 X 10^-3T X 2 X 4.0 x 10^-3m / 4π X 10^-7 H/m
I =7.00 A
Therefore magnitude of the current that flows through the wire is 7.0 A
