A freely falling object near the Earth's surface has a constant?
acceleration of 1.0 m/s
acceleration of 9.8 m/s
velocity of 1.0 m/s
velocity of 9.8 m/s

Answers

Answer 1

Answer:

answer is B (CROWN ME)

Explanation:

One should revise his/ her research questions very well in the week before the exam. They should contribute at least 15-20 hours for going through these questions in that particular week. They must put some extra efforts on weekends.

Answer 2

A freely falling object near the Earth's surface has a constant: B. acceleration of 9.8 [tex]m/s^2[/tex].

Gravity can be defined as a force that controls the movement of the planets such as Earth around the Sun, hold stars grouped in galaxies together, and galaxies grouped in clusters.  This ultimately implies that, gravity is a universal force of attraction that acts between all objects that are having both mass and energy, and can occupy space.

Furthermore, the gravity near the Earth's surface makes it possible for all physical objects to possess weight and experience a free fall.

Generally, the acceleration due to gravity for an object experiencing a free fall near the Earth's surface is 9.8 [tex]m/s^2[/tex].

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Related Questions

A projectile is fired horizontally from a height of 78.4 m at a speed of 300 m/sec. How far did it travel horizontally before hitting the ground?​

Answers

Answer:

Explanation:

Using the formula for calculating range expressed as;

R = U√2H/g

U is the speed = 300m/s

H is the maximum height = 78.4m

g is the acceleration due to gravity = 9.8m/s²

Substitute into the fromula;

R = 300√2(78.4)/9.8

R = 300 √(16)

R = 300*4

R = 1200m

Hence the projectile travelled 1200m before hitting the ground

A body can have zero average velocity but not zero average speed. Why?​

Answers

displacement can be zero so velocity is zero but the distance won’t be zero so speed won’t be zero

A student rides a bicycle in a circle at a constant speed and constant radius. A force diagram for the student-bicycle system is
shown in the figure above. The value for each force is shown in the figure. What is the acceleration of the student-bicycle system?
m
А
0
2
B
0.2"
C) 5
D
25"

Answers

Solution:

The gravitational force that acts on the bicycle system is

[tex]$F_{g} = 500 \ N$[/tex]

Now the force, that is the gravitational force is related to mass of the system and the acceleration due to gravity of the system, 'm' and 'g' respectively.

Therefore, we can write

[tex]$F_g=mg$[/tex]

500  = m x 10    (since , g = 10 m/s-s)

∴ m = 50 kg

Now the net vertical force acting on the student bicycle system is 0. And the vertical acceleration of system is also 0. The total horizontal force acts to the right of the system. So by Newton's 2nd law of motion, we can write

[tex]$F_f = ma$[/tex]

[tex]$a=\frac{F_f}{m}$[/tex]

  [tex]$=\frac{250}{50}$[/tex]

Therefore [tex]$a= 5 \ m/s^2$[/tex]

Hence (C) is correct option.  

A metal block of density 900kgm^-3 weighs 60N in air, find its weight when it is immersed in paraffin wax of density 800kgm^-3

Answers

Given;Density of metal block : 900 kg/m3Weight in air of block : 60NWeight of block when it is immerse in paraffin wax = ? Mass of block = 6kg

NOW,

Volume = 6 kg / 900 kg/m3 = 0.0067 m3And

Mass = 800 × 0.0067

= 5.333And Weight = 5.33 × 10 =53.33

What is the kinetic energy of a 4-kg toy car moving at a velocity of 8 m/s?
O 32J
64 J
O
128 J
256 J

Answers

Answer:

128 J

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question we have

[tex]k = \frac{1}{2} \times 4 \times {8}^{2} \\ = 2 \times 64[/tex]

We have the final answer as

128 J

Hope this helps you

Mass of toy the car = 4 kg

Velocity of toy the car = 8 m/s

Kinetic energy of an object is the energy that it possesses due to its motion.

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity.

Formula of Kinetic energy:

[tex] \boxed{ \bf{KE = \dfrac{1}{2}mv^2}}[/tex]

KE → Kinetic energy of the Object (J)

m → Mass of the Object (kg)

v → Speed of the Object (m/s)

By substituting values in the formula, we get:

[tex] \rm \longrightarrow KE = \dfrac{1}{2} \times 4 \times 8^2 \\ \\ \rm \longrightarrow KE = \dfrac{1}{2} \times 4 \times 64\\ \\ \rm \longrightarrow KE = 2 \times 64 \\ \\ \rm \longrightarrow KE = 128 \: J[/tex]

[tex] \therefore [/tex] Kinetic energy of the toy car = 128 J

What's the name for how you see the world through your perception
in cognitive theory.

Answers

i’m sorry what- that’s so

Answer:

Perception: Perception is a cognitive process that allows people to take in information through their senses (sensation) and then utilize this information to respond and interact with the world. Thought: Thought is an essential part of every cognitive process.

I hope it helped

N stands for _____________________, which is an SI unit of force.

Answers

Answer:

Newton

Explanation:

A car with a mass of 1.5 × 103 kilograms is traveling west at a velocity of 22 meters/second. It hits a stationary car with a mass of 9.0 × 102 kilograms. If the collision is inelastic, what is the final direction and approximate velocity of the two cars?

Answers

Answer:

A. 14 meters/second to the west

Explanation:

The collision is inelastic, which means that:

- only the total momentum is conserved (not the kinetic energy)

Answer:

14 meters/second to the west

Explanation:

That's the answer!

(30points pls help ASAP) How many grams of sodium would there be in 70 g of NaCl?

Answers

I believe 1.05g:))))))

27.52g grams of sodium would there be in 70 g of NaCl.

What is molecular mass ?

The molecular mass gives the total mass of the molecule, it is the sum of masses of all the atoms present in a molecule. for example in Nacl, there is one atom of Na and one atom of Cl both makes NaCl. the sum of masses of Na and Cl gives the mass of the NaCL. Molecular mass is expressed in amu. 1 amu = Avogadro's number of atom or molecule.

The Molar mass is defined as the mass of a given substance divided by the amount of a substance. its unit is g/mol.

Here I have direct method for the calculation of mass of particular atom in the molecule.

Molecular weight of the NaCl is,

(23+35.5)g=58.5g where 23= mass of Na and 35.5 mass Cl.

in this we can see that 58.5 g of Nacl contains 23 g of Na.

we can write 58.5 NaCl = 23g Na

therefore 70g of NaCl = (23÷58.5)×70 Na

70g of NaCl = 27.52g of Na

Hence 70g of NaCl contains 27.52g of sodium.

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How much heat does 56 L of water need to absorb to raise its temperature from 350C to 740C?​

Answers

Answer:

300 L of water

Explanation:

In which type of collision is the kinetic energy of the system unchanged?
A. Perfectly inelastic
O B. Elastic
C. No type of collision
D. Inelastic

Answers

B.) Elastic

Took the test and this is the answer

Picture question please answer do in 5 mins

Answers

Answer:

Can't see anything, please share clearly

Two car's are racing! The winner of the race will always be be the vehicle with the greater...

Answers

velocity i believe ?
The velocity using the speed down flow of the wind and aerodynamics of the cars body and build it would be velocity with a higher down flow to the ground it go’s faster because it’s closer the the ground like an F1 racing car especially if the car has a spoiler is brings it closer down to the ground

Witch is not true about longitudinal waves?

Answers

Answer:

light is a longitudinal wave.

Explanation:

lol

When Royce was 10 years old, he had a mass of
30 kg. By the time he was 16 years old, his mass
increased to 60 kg. How much larger is the
gravitational force between Royce and Earth at
age 16 compared to age 10?

Answers

Answer:

The gravitational force between Royce and Earth would be doubled at 16 years.

Explanation:

"Newton's law of universal gravitation states that gravitation force between two masses is proportional to the magnitude of their masses and inverse-squared of their distance".

Royce Scenario

At the age of 10 Royce's mass = 30kg

At the age of 16 Royce's mass = 60kg

From Newton's law of universal gravitation, an Increase in the mass of a body would amount to a corresponding increase in the gravitational force.

In the case of Royce, the mass double between the age of 10 and 16, so there would be an increase of the gravitation force by double.

The gravitational force at the age of 60 is doubled of the gravitational force at the age of 10. A complete solution is below.

Given:

At 10 years old,

Mass,

m = 30 kg

now,

→ [tex]Gravitational \ force (F_1) = \frac{GMm}{r^2}[/tex]

                                          [tex]= mg[/tex]

or,

→ [tex]g = \frac{GM}{r^2}[/tex]

then,

Gravitational force = 30 g

Now,

At 16 years old,

Mass,

m = 60 kg

Now,

→ [tex]\frac{F_1}{F_2} = \frac{30}{60}[/tex]

       [tex]=\frac{1}{2}[/tex]

  [tex]F_2 = 2F_1[/tex]

Thus the above response is right.

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A book on a 2-meter high shelf has a mass of 0.4 kg. What is its potential energy?

Answers

Answer:

[tex]\boxed {\boxed {\sf 7.84 \ Joules}}[/tex]

Explanation:

The formula for potential energy is:

[tex]PE=m*g*h[/tex]

where m is the mass, g is the gravitational acceleration, and h is the height.

The mass of the book is 0.4 kilograms. The gravitational acceleration on Earth is 9.8 m/s². The height of the book is 2 meters.

[tex]m=0.4 \ kg \\g=9.8 \ m/s^2 \\h=2\ m[/tex]

Substitute the values into the formula.

[tex]PE=(0.4 \ kg)(9.8 \ m/s^2)(2 \ m)[/tex]

Multiply the first two numbers.

0.4 kg*9.8 m/s²= 3.92 kg*m/s²If we convert the units now, the problem will be much easier later on. 1 kg*m/s² is equal to 1 Newton. So, our answer of 3.92 kg*m/s² is equal to 3.92 N

[tex]PE=(3.92 \ N )(2 \ m)[/tex]

Multiply.

3.92 N* 2 m=7.84 N*m1 Newton meter is equal to 1 Joule (this is why we converted the units). Our answer is equal to 7.84 Joules.

[tex]PE=7.84 \ J[/tex]

Answer:

7.84 is your answer ok bye


What is responsible for keeping an object at rest or maintaining an object's
constant velocity?

Answers

Answer:

Inertia

Explanation:

Inertia is a force which keeps stationary objects at rest and moving objects in motion at constant velocity.

According to the Law of the Conservation of Matter, if you dissolve 25 grams of sugar into 150 grams of water, the mixture should weigh how much?

Answers

19grams becauce if u

give a strong idea to protect , purify and the beautify of the Dal lake​

Answers

Answer:

Water in dal lake is test for any heavy metals and pollutant, sewage and drainage system are also monitored for the same.

Explanation:

Dal lake is located in Srinagar that is the state capital of Kashmir and is known for recreation and tourism purposes. The area covers about 18 km sq. and forms a part of natural wetlands. The lake is prone to pollution and has recently undergone restoration measures. To address the problems of eutrophication algae and large-scale microplankton have been removed from the water. The government of India has taken various measures to check the pollution by setting up a committee to monitor the proper use of allotted funds.

the nitrogen group has 5 electrons true or false

Answers

Answer:

True

Nitrogen family elements consists of atoms having 5 electrons in their outer energy level.

Please mark me the brainliest

Hope it may helps you

can a body have mass but no weight give reasion for your answer​

Answers

Answer:

Hey buddy, here is your answer. Hope it helps you.

Explanation:

Yes, weight of a body is not constant, it varies with the value of acceleration due to gravity, g. Weight of a body is zero, when it is taken to the centre of the earth or in the interplanetary space, where g=0. Mass is the total matter in a body, while weight is the force by which the body is attracted.

Weight is never constant while mass is. So we can have weight zero but with some mass. This will happen when an object is at the centre of earth, as g=0 at centre of earth , so weight will be 0 while mass will always be constant everywhere

Answer:

yes a body can have mass but no wt at a centre of the earth

Explanation:

this is because acceleration due to gravity decreases as we go deep into earth and becomes 0 at the centre

If we increase the driving frequency in a circuit with purely resistive load, how do the amplitudes VR and IR change?

Answers

Answer:

V = I R    

expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

Explanation:

In a purely resistive circuit, the Ohm relation, m for which

          V = I R

We see that the previous expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

This does not happen in circuits with capacitors or inductors where there is an explicit dependence on frequency.

What is the minimum energy (in MeV) that is required to break a nucleus of 12C (of mass 11.99671 u) into three nuclei of 4He (of mass 4.00151 u each)?

Answers

Answer:

the minimum energy that needed to break the nucleus is  1.12608 × 10^-12 J

Explanation:

The computation of the minimum energy that needed to break the nucleus is shown below:

The Change in mass is

= 11.99671 - 3 × 4.00151

= 0.00782

The Energy = mc^2

= (0.00782 × 1.6 × 10^{-27}) × (3 × 10^8)^2

= 1.12608 × 10^-12 J

Hence, the minimum energy that needed to break the nucleus is  1.12608 × 10^-12 J

The same is to be considered

HURRY
An ultrasound tech is trying to identify an object, but the screen of the machine is broken. Which statement best describes this situation?

The generated sound wave will not be able to reflect off of the object.
The sound wave will not be generated, so there will be no echoes received.
The echoes will be made but will not be able to be received by the machine.
The machine will not be able to process the received echoes into images.

Answers

Answer:

It’s b

Explanation:

Everyone else is wrong and I tried this and got it right

Answer:

the answer is b or "The sound wave will not be generated, so there will be no echoes received."

Explanation:

What name is given to the rate at which velocity changes?
Answer mere

Answers

Answer:

Acceleration

Explanation:

The diagrams below show forces acting on a toy car as it moves to the right which diagram shows the toy car that will most likely accelerate to the right based on these conditions?

Answers

Answer:

Option 1.

Explanation:

To know which option is correct, let us calculate the net force in each case to know which will move to the right direction.

Option 1:

Force to the right (Fᵣ) = 8 N

Force to the left (Fₗ) = 6 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 8 – 6

Fₙ = 2 N to the right

Option 2:

Force to the right (Fᵣ) = 8 N

Force to the left (Fₗ) = 10 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 10 – 8

Fₙ = 2 N to the left

Option 3:

Force to the right (Fᵣ) = 10 N

Force to the left (Fₗ) = 10 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 10 – 10

Fₙ = 0 (no movement)

Option 4:

Force to the right (Fᵣ) = 10 N

Force to the left (Fₗ) = 13 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 13 – 10

Fₙ = 3 N to the left

From the illustrations made above, only option 1 has a net force toward the right direction. Therefore, only option 1 will have an acceleration towards the right direction.

Answer:

Option 1

Explanation:

Help please an observer at the North Pole sees the moon phase shown below. What Moon phase will be observed approximately one week later?

Answers

Answer:

it should be a new moon

Explanation:

ok who love lizard can we talk plz

Answers

Answer:

Meeee

Explanation:

An unknown mass is hung from a very light spring with a spring constant of 13.6 N/m. Neglect the mass of the spring. If the period of oscillation of the mass-spring system is 3.35 s, then the unknown mass is:__________

Answers

Answer:

The unknown mass is 3.87 kg.

Explanation:

Given;

spring constant of the spring, k = 13.6 N/m

period of oscillation, T = 3.35 s

The period of oscillation of the mass-spring system is given by;

[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]

where;

m is the mass attached to the spring

[tex]T = 2\pi \sqrt{\frac{m}{k} }\\\\\frac{T}{2\pi} = \sqrt{\frac{m}{k} }\\\\\frac{T^2}{4\pi^2}= \frac{m}{k}\\\\m = \frac{kT^2}{4\pi^2}\\\\m = \frac{(13.6)(3.35)^2}{4\pi^2}\\\\m = 3.87 \ kg[/tex]

Therefore, the unknown mass is 3.87 kg.

The Sputnik 1 satellite orbited Earth
(mass = 5.98 x 1024 kg) in a circle of
radius 6.96 x 106 m. What was its
period of orbit in seconds?
[?] s

Answers

Answer:

5778.1931

Explanation:

Given that:

Mass (M) = 5.98 x 10^24 kg

Radius (r) = 6.96 x 10^6 m

Gravitational constant (G) = 6.67 * 10^-11

Using the relation:

T² / R³ = 4π² / GM

Where T = period of orbit

T = 2π√(R³ /GM)

T = 2π√((6.96 x 10^6)³) /(6.67 * 10^-11) * (5.98 x 10^24)

T = 2π√((3.37153 * 10^20) / (39.866 * 10^13))

T = 2π √845715.64

T = 2π * 919.62799

T = 5778.1931

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