What is the discriminat of 2x+5x^=1

Answers

Answer 1

Answer:

don't know...........

Answer 2
It's 24 hope that's helps u out

Related Questions

4. find possible value for m if
X=-3 and (3m-x)2=81

Answers

Answer:

m = 12.5

Step-by-step explanation:

x = - 3

(3m - x) 2= 81

(3m - (-3)) 2= 81

(3m + 3) 2= 81

6m + 6  = 81

      - 6     - 6

6m = 75

[tex]\frac{6m}{6}[/tex] = [tex]\frac{75}{6}[/tex]

m = 12.5

hope this helps! if you have an questions, pls let me know!

What is the distance between (-5,-5) and (-9,-2)

Answers

Answer:

A (5)

Step-by-step explanation:

The distance is the slope/gradientIn the pythogaras theorem [tex]c^{2} = a^{2} + b^{2}[/tex],

        c represents the slope and a and b represent the two shorter sides of the right angled triangle ( x,y)

x = -9 - (-5 ) = -9 +5 = -4y = -2 - (-5) = -2 +5 = 3

       [tex]c^{2}[/tex] = [tex]-4^{2} + 3^{2}[/tex]

            = 16 + 9

             = 25,

therefore [tex]\sqrt{c^{2} }[/tex] = [tex]\sqrt{25}[/tex]

                   c = 5

                                                                                     

A survey of 30-year-old males provided data on the number of auto accidents in the previous 5 years. The sample mean is 1.3 accidents per male. Test the hypothesis that the number of accidents follows a Poisson distribution at the 5% level of significance.

No. of accident No. of males
0 39
1 22
2 14
3 11
>=4 4

Required:
a. What's the Expected probability of finding males with 0 accidents?
b. What's the Expected probability of finding males with 4 or more accidents?

Answers

Answer:

0.2725

0.0431

Step-by-step explanation:

The distribution here is a poisson distribution :

λ = 1.3

The poisson distribution :

p(x) = [(e^-λ * λ^x)] ÷ x!

Expected probability of finding male with 0 accident ; x = 0

p(0) = [(e^-1.3 * 1.3^0)] ÷ 0!

p(0) = [0.2725317 * 1] ÷ 1

p(0) = 0.2725317

= 0.2725

2.)

P(x ≥ 4) = 1 - P(x < 4)

P(x < 4) = p(x = 0) + p(x. = 1) + p(x = 2) + p(x = 3)

p(x = 0) =  p(0) = [(e^-1.3 * 1.3^0)] ÷ 0! = 0.2725

p(x = 1) = p(1) = [(e^-1.3 * 1.3^1)] ÷ 1! = 0.35429

p(x = 2) = p(2) = [(e^-1.3 * 1.3^2)] ÷ 2! = 0.23029 p(x = 3) = p(3) = [(e^-1.3 * 1.3^3)] ÷ 0! = 0.09979

P(x < 4) = 0.2725 + 0.35429 + 0.23029 + 0.09979 = 0.95687

P(x ≥ 4) = 1 - 0.95687 = 0.0431

A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean life of 83 months with a variance of 81. If the claim is true, what is the probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors? Round your answer to four decimal places.

Answers

Answer:

0.9922 = 99.22% probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The production manager claims they have a mean life of 83 months with a variance of 81.

This means that [tex]\mu = 83, \sigma = \sqrt{81} = 9[/tex]

Sample of 146:

This means that [tex]n = 146, s = \frac{9}{\sqrt{146}}[/tex]

What is the probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors?

This is 1 subtracted by the p-value of Z when X = 81.2. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{81.2 - 83}{\frac{9}{\sqrt{146}}}[/tex]

[tex]Z = -2.42[/tex]

[tex]Z = -2.42[/tex] has a p-value of 0.0078.

1 - 0.0078 = 0.9922.

0.9922 = 99.22% probability that the mean monitor life would be greater than 81.2 months in a sample of 146 monitors.

In one year the population of
Zebras in the park was 3400. In
the following year the population
reduced by 25%. What was the
size of the population after


reduction?​

Answers

After reduction, the population decreases to 2550.

If one ruler and three pencils cost N120 and two
rulers and one pencil cost N140. Find the cost of
one ruler and one pencil

Answers

Answer:

N80

Step-by-step explanation:

One ruler is N60 and one pencil is N20.

Need the value of P please

Answers

Answer:

B. 35°

Step-by-step explanation:

First, find the two interior angles that are adjacent to angles 90° and 125° respectively.

Thus:

Interior angle 1: 180° - 90° = 90° (linear pair)

Interior angle 2: 180° - 125° = 55° (linear pair)

P + 90° + 55° = 180° (sum of interior angles in a triangle)

P + 145° = 180°

Subtract 145° from each side

P = 180° - 145°

P = 35°

18. A triangle has side lengths of 6, 8, and 9. What type of triangle is it?

acute

obtuse

equiangular

right

Answers

Answer:

obtuse                    

aniuhafjhnfajfnha

The resistors produced by a manufacturer are required to have an average resistance of 0.150 ohms. Statistical analysis of the output suggests that the resistances can be approximated by a normal distribution with known standard deviation of 0.005 ohms. We are interested in testing the hypothesis that the resistors conform to the specifications.

Requied:
a. Determine whether a random sample of 10 resistors yielding a sample mean of 0.152 ohms indicates that the resistors are conforming. Use alpha = 0.05.
b. Calculate a 95% confidence interval for the average resistance. How does this interval relate to your solution of part (a)?

Answers

Answer:

a) The p-value of the test is 0.2076 > 0.05, which means that the sample indicates that the resistors are conforming.

b) The 95% confidence interval for the average resistance is (0.147, 0.153). 0.152 is part of the confidence interval, which means that as the test statistic in item a), it indicates that the resistors are conforming.

Step-by-step explanation:

Question a:

The resistors produced by a manufacturer are required to have an average resistance of 0.150 ohms.

At the null hypothesis, we test if this is the average resistance, that is:

[tex]H_0: \mu = 0.15[/tex]

We are interested in testing the hypothesis that the resistors conform to the specifications.

At the alternative hypothesis, we test if it is not conforming, that is, the mean is different of 0.15, so:

[tex]H_1: \mu \neq 0.15[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

0.15 is tested at the null hypothesis:

This means that [tex]\mu = 0.15[/tex]

Sample mean of 0.152, sample of 10, population standard deviation of 0.005.

This means that [tex]X = 0.152, n = 10, \sigma = 0.005[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.152 - 0.15}{\frac{0.005}{\sqrt{10}}}[/tex]

[tex]z = 1.26[/tex]

P-value of the test and decision:

The p-value of the test is the probability of the sample mean differing from 0.15 by at least 0.152 - 0.15 = 0.002, which is P(|z| > 1.26), given by two multiplied by the p-value of z = -1.26.

Looking at the z-table, z = -1.26 has a p-value of 0.1038.

2*0.1038 = 0.2076

The p-value of the test is 0.2076 > 0.05, which means that the sample indicates that the resistors are conforming.

Question b:

We have to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a p-value of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 1.96\frac{0.005}{\sqrt{10}} = 0.003[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 0.15 - 0.003 = 0.147.

The upper end of the interval is the sample mean added to M. So it is 0.15 + 0.003 = 0.153.

The 95% confidence interval for the average resistance is (0.147, 0.153). 0.152 is part of the confidence interval, which means that as the test statistic in item a), it indicates that the resistors are conforming.

What is the solution of log(4-3) = log(17-41)?
O4
O 5
O 15
O 20

Answers

Answer: Choice A) 4

Explanation:

The rule is that if log(A) = log(B), then A = B

Using this idea, we can then say,

log(t - 3) = log(17 - 4t)

t - 3 = 17 - 4t

t+4t = 17+3

5t = 20

t = 20/5

t = 4

The solution to the logarithmic equation is t = 5

What is Logarithm?

The power to which a number must be increased in order to obtain another number is known as the logarithm. A power is the opposite of a logarithm. In other words, if we subtract an exponentiation from a number by taking its logarithm

The properties of Logarithm are :

log A + log B = log AB

log A − log B = log A/B

log Aⁿ = n log A

Given data ,

Let the logarithmic equation be represented as A

Now , the value of A is

log ( t - 3 ) = log  (17 - 3t )   be equation (1)

On simplifying , we get

The bases of the logarithm are equal

So , the values are equal and therefore  

t - 3 = 17 - 3t

Adding 3t on both sides , we get

4t - 3 = 17

Adding 3 on both sides , we get

4t = 20

Divide by 4 on both sides , we get

t = 20 / 4

t = 5

Therefore , the value of t is 5

Hence , the logarithmic equation is solved

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Molly and Lynn both set aside money weekly for their savings. Molly already has $650 set aside and adds $35 each week. Lynn already has $825 set aside but adds only $15 each week. Which inequality could they use to determine how many weeks, w, it will take for Molly’s savings to exceed Lynn’s savings?

Answers

FINAL ANSWER: D

Given : Molly and Lynn both set aside money weekly for their savings.

Molly already has $650 set aside and adds $35 each week.

Lynn already has $825 set aside but adds only $15 each week.

To Find :  inequality   to determine how many weeks, w, it will take for Molly’s savings to exceed Lynn’s savings

Solution:

Molly already has $650

adds $35 each week.

=> added in w  weeks  = 35w

After w weeks  = 650 + 35w

Lynn already has $825

adds $15 each week.

added in w  weeks  = 15w

After w weeks  = 825 + 15w

Molly’s savings to exceed Lynn’s savings

⇒ 650 + 35w >  825 + 15w

⇒  20w  >  175

⇒   4w >  35

⇒  w  >  35 /4

At least 9 weeks

Answer:

D

Step-by-step explanation:

First, to eliminate some answers you can figure out which way the sign should go. The question wants to know when Molly's savings will be larger so the sign should open towards her side of the equation. Since her savings are represented on the left the sign should be a greater than, >.

Then, figure out where the variables belong. The variable represents the number of weeks that have passed, so they should be multiplied by the number that is affected by the passing of weeks. This is the amount each person saves, aka the independent variable. So the "w" variable should be next to the 35 and 15.

bHhHshsbsnsnsnsnsnsbsbsbckclccllcxldkdldkdkdk HELP

Answers

Answer:

Step-by-step explanation:

The reasons for each statement are inside the parentheses

1. <1 and <2 are complementary (given)

2. m<1 + m<2 = 90° (definition of complementary angles)

3. m<2 = 74° (given)

4. m<1 + 74° = 90° (Substitution)

5. m<1 = 16° (Subtraction property of equality)

This is gotten by subtracting 74° from both sides as follows:

m<1 + 74° - 74° = 90° - 74°

m<1 = 16°

if for men working for hours for 4 days complete for unit of work then how many unit of work will be completed by two men working for two hours per day?​

Answers

The 2 men working for 2 hours per 2 days will complete 1/2 unit of work. This is calculated by using the proportions formula.

What is the formula for calculating equal proportions?

The formula for the given proportions is,

a: b = c: d

⇒ a/b = c/d

⇒ ad = bc

In this way, the required variable is calculated.

Calculation:

For the given question, the proportion we can write

M1 × H1 × D1: M2 × H2 × D2 = W1: W2

⇒ M1 × H1 × D1 × W2 = M2 × H2 × D2 × W1

Where M1 = 4; H1 = 4; D1 = 4; M2 = 2; H2 = 2; D2 = 2 and W1 = 4

We need to calculate W2 -  required units of work

So, on substituting,

M1 × H1 × D1 × W2 = M2 × H2 × D2 × W1

⇒ 4 × 4 × 4 × W2 = 2 × 2 × 2 × 4

⇒ 64 × W2 = 32

⇒ W2 = 32/64

∴ W2 = 1/2

Thus, the required units of work are 1/2.

So, 2 men working for 2 hours for 2 days will complete 1/2 unit of work.

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Disclaimer: The given question is incomplete. Here is the complete question.

Question: If 4 men working for 4 hours for 4 days complete 4 units of work then how many unit of work will be completed by two men working for two hours per 2 days?​

The angle θ between 5i-j+k & 2i-j+k is​

Answers

Step-by-step explanation:

Let,

[tex] \sf \vec{a} = 5 \hat{i} - \hat{j} + \hat{k} \\ \therefore \: \sf \: | \vec{a}| = \sqrt{ {5}^{2} + {( - 1)}^{2} + {1}^{2} } \\ = \sqrt{25 + 1 + 1} \\ = \sqrt{27} \\ \\ \sf \vec{b} = 2\hat{i} - \hat{j} + \hat{k} \\ \therefore \: \sf \: | \vec{b}| = \sqrt{ {2}^{2} + {( - 1)}^{2} + {1}^{2} } \\ = \sqrt{4 + 1 + 1} \\ = \sqrt{6} \\ \\\sf \: \vec{a}. \vec{b} = (5 \hat{i} - \hat{j} + \hat{k}).(2\hat{i} - \hat{j} + \hat{k}) \\ = 5 \times 2 + ( - 1) \times ( - 1) + 1 \times 1 \\ = 10 + 1 + 1 \\ = 12 \\ \\ \sf \: angle \: between \: \vec{a} \: and \: \vec{b} \: = \theta \\ \\ \: so \\ \sf \vec{a}. \vec{b} = | \vec{a}| . | \vec{b}| cos\theta \\ = > \sf \: cos \theta \: = \frac{ \vec{a}. \vec{b}}{ | \vec{a}| . | \vec{b}| } \\ = > cos \theta = \frac{12}{ \sqrt{27} \times \sqrt{6} } = 0.94 \\ = > \theta = {cos}^{ - 1} (0.94) \\ = > \green{\theta = 19.47 ^{ \circ} }[/tex]

What is the height of spanning tree obtained from Wn by the breadth-first search, starting at the central vertex of Wn?

Answers

Answer:

The height of the spanning tree is one by the breadth-first search at the central vertex of Wn.

Step-by-step explanation:

The graph is connected and has a spanning tree where the tree can build using a depth-first search of the graph. Start with chosen vertex, the graph as the root, and root add vertices and edges such as each new edge is incident with vertex and vertices are not in path. If all vertices are included, it will do otherwise, move back to the next level vertex and start passing. It is for depth-first search. For breadth-first search, start with chosen vertex add all edges incident to a vertex. The new vertex is added and becomes the vertices at level 1 in the spanning tree, and each vertex at level 1 adds each edge incident to vertex and other vertex connected to the edge of the tree as long as it does not produce.

PLEASE HELP OR IM gonna FAILLLLLLLL!!!!!!!!

Answers

Answer:

C. 1/(4^10)

Step-by-step explanation:

Let's break it down: 4^-2 = 1/(4^2)(1/(4^2))^5 = (1^5)/(4^2)^5 = 1/(4^10)

if qqq=90 what's qqqq+87​

Answers

Answer: [tex]90\sqrt[3]{90}+87[/tex]

Step-by-step explanation:

[tex]qqq=90\\q^3=90\\\sqrt[3]{q^3} =\sqrt[3]{90}\\q= \sqrt[3]{90}\\\\qqqq+87\\q^3q^1+87\\90\sqrt[3]{90}+87[/tex]

How much wrapping is needed to cover a cubed gift box that is 9 inches high? (Include the bow which takes 115 sq. inches.)

Answers

Answer:

601 in²

Step-by-step explanation:

To obtain the amount of wrapping needed to cover the cube shaped gift box, including the bow

Area of bow = 115 in²

Surface area of cube shaped box = 6a²

a = side length of cube = 9

Hence,

Surface area of gift box = 6 * 9²

Surface area = 6 * 81 = 486 in²

Total wrapping required = area of gift box + area of bow = (486 in² + 115 in²) = 601 in²

For the function f(x) = x^2 + 4x -5 solve the following f(x)=0

Answers

That's a question about quadratic function.

Any quadratic function can be represented by the following form:

[tex]\boxed{f(x)=ax^2+bx+c}[/tex]

Example:

[tex]f(x)= -3x^2-9x+57[/tex] is a function where [tex]a=-3[/tex], [tex]b=-9[/tex] and [tex]c=57[/tex].

Okay, in our problem, we need to find the value of x when [tex]f(x)=0[/tex]. That's mean that the result of our function is equal to zero. Therefore, we have the quadratic equation below:

[tex]x^2+4x-5=0[/tex]

To solve a quadratic equation, we use the Bhaskara's formula. Do you remember the value of a, b and c? They going to be important right now. This is the Bhaskara's formula:

[tex]\boxed{x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} }[/tex]

So, let's see the values of a, b and c in our equation and apply them in the Bhaskara's formula:

In [tex]x^2+4x-5=0[/tex] equation, [tex]a=1[/tex], [tex]b=4[/tex] and [tex]c=-5[/tex]. Let's replace those values:

[tex]x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]

[tex]x=\frac{-4\pm \sqrt{4^2-4\times1\times(-5)} }{2\cdot1}[/tex]

[tex]x=\frac{-4\pm \sqrt{16-(-20)} }{2}[/tex]

[tex]x=\frac{-4\pm \sqrt{16 + 20)} }{2}[/tex]

[tex]x=\frac{-4\pm \sqrt{36} }{2}[/tex]

[tex]x=\frac{-4\pm 6 }{2}[/tex]

From now, we have two possibilities:

To add:

[tex]x_1 = \frac{-4+6}{2} \\x_1=\frac{2}{2} \\x_1=1[/tex]

To subtract:

[tex]x_2=\frac{-4-6}{2} \\x_2=\frac{-10}{2} \\x_2=-5[/tex]

Therefore, the result of our problem is: [tex]x_1 = 1[/tex] and [tex]x_2=-5[/tex].

I hope I've helped. ^^

Enjoy your studies.  \o/

Graph the function g(x) = 3^x + 3 and give its domain and range using interval notation.

Answers

When a function is plotted on a graph, the domain and the range of the function are the x-coordinate and the y-coordinate respectively.

The domain and the range of the given function are:

Domain: [tex](-\infty,\infty)[/tex]

Range: [tex](3,\infty)[/tex]

 The given function is:

[tex]g(x) = 3^x + 3[/tex]

First, we plot the graph of g(x)

To do this, we need to generate values for x and g(x). The table is generated as follows:

[tex]x = 0 \to g(0) = 3^0 + 3 = 4[/tex]

[tex]x = 1 \to g(1) = 3^1 + 3 = 6[/tex]

[tex]x = 2 \to g(2) = 3^2 + 3 = 12[/tex]

[tex]x = 3 \to g(3) = 3^3 + 3 = 30[/tex]

[tex]x = 4 \to g(4) = 3^4 + 3 = 84[/tex]

The generated values in tabular form are:

[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ g(x) & {4} & {6} & {12} & {30} & {84} \ \end{array}[/tex]

Refer to the attached image for graph of g(x)

To determine the domain, we simply observe the x-axis.

The curve stretches through the x-axis, and there are no visible endpoints on the axis.  This means that the curve starts from [tex]-\infty[/tex] to [tex]+\infty[/tex]

Hence, the domain of the function is: [tex](-\infty,\infty)[/tex]

To determine the range, we simply observe the y-axis.

The curve of g(x) starts at y = 3 on the y-axis and the curve faces upward direction.  This means that the curve of g(x) is greater than 3 on the y-axis.

Hence, the range of the function is: [tex](3,\infty)[/tex]

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Function: [tex]g(x) = 3^{x} + 3[/tex]. Domain: [tex]Dom \{g(x)\} = \mathbb{R}[/tex], Range: [tex]Ran \{g(x) \} = (3, +\infty)[/tex], respectively.

In Function Theory, the domain of a function [tex]f(x)[/tex] represents the set of values of the independent variable ([tex]x[/tex]), whereas the range of the function is the set of values of the dependent variable.

The Domain of the Function represents the set of values of [tex]x[/tex] (horizontal axis), whereas the Range it is the set of values of [tex]y[/tex] (vertical axis). After analyzing the existence of Asymptotes, we complement with graphic approaches and conclude where domain and range (in Interval notation) are.

Analytically speaking, the domain of exponential functions is the set of all real numbers and the range of [tex]g(x)[/tex] is any number between [tex]\lim_{x \to -\infty} g(x)[/tex] and [tex]\lim_{x \to +\infty} g(x)[/tex]. In a nutshell, we get the following conclusions in interval notation:

Domain: [tex]Dom \{g(x)\} = (-\infty, +\infty)[/tex], Range: [tex]Ran \{g(x) \} = (3, +\infty)[/tex]

Lastly, we proceed to complement this analysis by graphing function with the help of a graphing tool.

According to the image, domain and range coincides with outcomes from analytical approaches.

A soccer team wants new uniforms. A jersey costs $42, shorts cost $26, socks cost $6, and shinguards cost $18. How much does one
uniform cost?
$62
$74
$83
$92

Answers

Answer:

$92

Step-by-step explanation:

42 + 26 + 6 + 18 = 92

Need to know Anwser yes or no

Answers

Answer:

Reflective symmetry over the line y = 4 is No

Reflective symmetry over the line y = 1/7x + 3 is Yes

Which expression is equivalent to
-32 3/5
-8
-3/325
3/325
1/8

Answers

Answer:

[tex]-32^\frac{3}{5} = -8[/tex]

Step-by-step explanation:

Given

[tex]-32^\frac{3}{5}[/tex]

Required

The equivalent expression

We have:

[tex]-32^\frac{3}{5}[/tex]

Rewrite as:

[tex]-32^\frac{3}{5} = (-32)^\frac{3}{5}[/tex]

Expand

[tex]-32^\frac{3}{5} = (-2^5)^\frac{3}{5}[/tex]

Remove bracket

[tex]-32^\frac{3}{5} = -2^\frac{5*3}{5}[/tex]

[tex]-32^\frac{3}{5} = -2^3[/tex]

[tex]-32^\frac{3}{5} = -8[/tex]

Help! I need help with these two questions (10 points each!)

Answers

Answer:

see image...

the (x-h) shifts the curve left right (east west)

and the +k at the end shifts it up/down (north/south)

Step-by-step explanation:

Q: Solve for x: 8x-2-5x=8
A. OX=13
B. OX=2 1/2
C. OX=3 1/3
D. OX=7

Answers

Answer:

c. 3 1/3

Step-by-step explanation:

8x-2-5x=8

3x=10

x=10/3=3 1/3

Answer:

x=[tex]3\frac{1}{3}[/tex]

Step-by-step explanation:

Hi there!

We want to find the value of x in this expression:

8x-2-5x=8

Our goal is to isolate x on one side

Combine like terms on the left side (add the terms with x together)

3x-2=8

Add 2 to both sides (-2+2=0)

3x-2=8

   +2  +2

__________

3x=10

Divide both sides by 3

x=[tex]\frac{10}{3}[/tex]

Simplify the improper fraction

x=[tex]3\frac{1}{3}[/tex]

Hope this helps!

*20 points*
how do you get the weighted average from this table?

Answers

Answer:

it is

[(2+3+4+6)-2*4]:4=1.75

I THINK

Step-by-step explanation:

If using the method of completing the square to solve the quadratic equation x 2 − 9 x − 8 = 0 x 2 −9x−8=0, which number would have to be added to "complete the square"?

Answers

Answer:

Add 81/4 to both sides.

Step-by-step explanation:

x^2 − 9x − 8 = 0

x^2 - 9x = 8

Take the coefficient of the x term: -9

Divide by 2: -9/2

Square it: 81/4

Add 81/4 to both sides.

PLEASE HELPPPPPPPPPP

Answers

Answer: SORRY NEED AN ACCOUNT ON - 10

Step-by-step explanation:

To resolve the proposed issue, an explanation is needed in which the subject is addressed

please help find the solution to the system of equations

Answers

Answer:

x = 2     y = 3

Step-by-step explanation:

-2x + 7 = 5x - 7

-7x + 7 = -7

-7x = -14

x = 2

y = -2(2) + 7

y = -4 + 7

y = 3

a. 15
b. 16
c. 9
d. 14

Answers

a. 15
0 +0=0
0 +1 = 1
1+2=3
3+3=6
6+4=10
10+5 = 15

Answer:

15

Step-by-step explanation:

1-0 =1

3-1 =2

6-3=3

10-6=4

We are adding 1 more each time

10+5 = 15

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