Hey there!
2w^2 - 3w + 7
= 2(-2)^2 - 3(-2) + 7
(-2)^2
= (-2)(-2)
= 4
= 2(4) - 3(-2) + 7
2(4) = 8
3(-2) = -6
= 8 - (-6) + 7
= 8 + 6 + 7
8 + 6 = 14
14 + 7
= 21
Answer: 21
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Four spinners are spun. Spinner 1 has outcomes Spinner 2 has outcomes Spinner 3 has outcomes Spinner 4 has outcomes The outcomes for each spinner are equally likely. is the sum of the numbers that come up on the spinners. What is the expected value of
Complete Question
Four spinners are spun. Spinner 1 has outcomes {1,2,3,4,5,6,7,8} Spinner 2 has outcomes {1,2,3,4,5,6} Spinner 3 has outcomes {1,2,3,4,5,6} Spinner 4 has outcomes {1,2,3,4,5} The outcomes for each spinner are equally likely. S is the sum of the numbers that come up on the spinners. What is the expected value of S?
Answer:
[tex]E(s)=14.5[/tex]
Step-by-step explanation:
From the question we are told that:
Spinner 1 ={1,2,3,4,5,6,7,8}
Spinner 2= {1,2,3,4,5,6}
Spinner 3 = {1,2,3,4,5,6}
Spinner 4 {1,2,3,4,5}
Generally the equation for expected outcome is mathematically given by
[tex]E(s)=\sum P(x).x[/tex]
Where
[tex]x=\frac{n(n+1)}{2}[/tex]
For Spinner 1
[tex]E(s_1)=\sum \frac{1}{8}*\frac{8(8+1)}{2}[/tex]
[tex]E(s_1)=4.5[/tex]
For Spinner 2
[tex]E(s_2)=\sum \frac{1}{6}*\frac{6(6+1)}{2}[/tex]
[tex]E(s_2)=3.5[/tex]
For Spinner 3
[tex]E(s_2)=E(s_3)[/tex]
For Spinner 3
[tex]E(s_4)=\sum \frac{1}{6}*\frac{6(6+1)}{2}[/tex]
[tex]E(s_4)=3[/tex]
Therefore The Expected Value
[tex]E(s)=\sum E(s 1..4)[/tex]
[tex]E(s)=4.5+2(3.5)+3[/tex]
[tex]E(s)=14.5[/tex]
A regular 2016-gon with all vertices on the unit circle is given. Find its perimeter, as a decimal to the nearest hundredth. (I have been stuck on this problem for half a hour I need help asap)
Answer:
6.28 unitsStep-by-step explanation:
Interior angle opposite to each side of the polygon is:
(360/2016)°Since the circle is unit circle, its radius is 1 unit.
Let the side is a, then as per definition of sine we have:
sin ((360/2016)/2) = (a/2)/1a = 2 sin (180/2016)°a = 0.00311665811The perimeter is:
P = 2016a = 2016(0.00311665811) ≈ 6.28 unitsEstimating Mean SAT Math Score
Type numbers in the boxes.
aby Part 1: 5 points
The SAT is the most widely used college admission exam. (Most community
aby Part 2: 5 points
colleges do not require students to take this exam.) The mean SAT math score
varies by state and by year, so the value of u depends on the state and the year. 10 points
But let's assume that the shape and spread of the distribution of individual SAT math scores in each
state is the same each year. More specifically, assume that individual SAT math scores consistently
have a normal distribution with a standard deviation of 100. An educational researcher wants to
estimate the mean SAT math score (u) for his state this year. The researcher chooses a random
sample of 661 exams in his state. The sample mean for the test is 494.
Find the 99% confidence interval to estimate the mean SAT math score in this state for this year.
(Note: The critical z-value to use, zc, is: 2.576.)
Your answer should be rounded to 3 decimal places.
Answer:
(483.981 ; 504.019)
Step-by-step explanation:
Given :
σ = 100
Sample size, n = 661
xbar = 494
We use the Z distribution since we are working with the population standard deviation ;
C.I = xbar ± (Zcritical * σ/√n)
Zcritical at 99% = 2.576
C.I = 494 ± (2.576 * 100/√661)
C.I = 494 ± 10.019
Lower boundary = (494−10.019) = 483.981
Upper boundary = (494+10.019) = 504.019
C.I = (483.981 ; 504.019)
PLZ HELP ASAP
A student poll on campus wanted to analyze the correlation of the Number of calories consumed per day to the weight of a student. in the form of a paragraph describe which visual display is most appropriate to represent the data. explain your reasons for choosing this type of visual display.
Answer:
Each kids weight in a chart
Step-by-step explanation:
I chose this because its the most organized way of doing that
square root of v-5=6
[tex] \sqrt{x - 5 = 6}[/tex]
Answer:
I think you mean this :
[tex] \sqrt{x - 5} = 6 \\ = > {( \sqrt{x - 5} })^{2} = {6}^{2} \\ = > x - 5 = 36 \\ = > x = 36 + 5 \\ = > x = 41[/tex]
Or,
Square root of x-5=6 is :
[tex] \sqrt{x - 5} \:=\:\sqrt{6} [/tex]
If f(x) = 5x squared -3 and g(x) = x squared - 4x -8, find (f-g)(x)
Answer:
[tex]4x^2+4x+5[/tex]
Step-by-step explanation:
[tex]f(x)=5x^2-3\\g(x)=x^2-4x-8[/tex]
Set up an expression.
[tex]5x^2-3-(x^2-4x-8)[/tex]
Distribute the negative (-1)
[tex]5x^2-3-x^2+4x+8[/tex]
Solve / Simplify
[tex]4x^2+4x+5[/tex]
I'm late, but I hope this helps!
Solve 2x2 – 3x = 12 using the quadratic formula.
Quadratic Formula: (-b +/- sqrt(b^2 - 4ac)) / 2a
2x^2 - 3x = 12
2x^2 - 3x - 12 = 0
a = 2
b = -3
c = -12
(--3 +/- sqrt( (-3)^2 - 4(2)(-12) )) / 2(2)
3 +/- sqrt( 9 + 96 ) / 4
3 +/- sqrt(105) / 4
Answers: [tex]\frac{3 + \sqrt{105} }{4}[/tex], [tex]\frac{3 - \sqrt{105} }{4}[/tex]
Hope this helps!
Susan has calculated that she needs $58000 her first year of retirement to maintain her standard of living. She expects to receive
$1000 per month from her employer defined-benefit pension and $1500 per month from Social Security. What is her annual
retirement income shortfall?
answer options:
28,000
40,000
58,000
150,000
Answer:
$28000
Step-by-step explanation:
12×1000 + 12×1500 = 12000 + 18000 = $30000
the shortfall is the difference between $58000 and $30000
58000 - 30000 = $28000
Use differentials to estimate the amount of material in a closed cylindrical can that is 10 cm high and 4 cm in diameter if the metal in the top and bottom is 0.1 cm thick, and the metal in the sides is 0.05 cm thick.
Answer:
dv = attached below
dr = 0.05 cm
dh = 0.2 cm
Approximate volume of metal = 2.8 * π cm^3
Step-by-step explanation:
height of can ( h ) = 10 cm
diameter = 4 cm ; r = 4/2 = 2cm
thickness of metal in top and bottom = 0.1 cm
thickness of metal in sides = 0.05 cm
attached below is the detailed solution
The age of Paul is 1/3 that of Kennedy. In four years time the age of Paul will be the same as Kennedy present age. How old is Paul now?
Answer:
Paul is 2 and Kennedy is 6
Step-by-step explanation:
6 × 1/3 = 2
2 + 4 =6
In the past, Alpha Corporation has not performed incoming quality control inspections but has taken the word of its vendors. However, Alpha has been having some unsatisfactory experience recently with the quality of purchased items and wants to set up sampling plans for the receiving department to use. For a particular component, X, Alpha has a lot tolerance percentage defective of 52 percent. Zenon Corporation, from which Alpha purchases this component, has an acceptable quality level in its production facility of 20 percent for component X. Alpha has a consumer's risk of 10 percent and Zenon has a producer's risk of 5 percent. a. When a shipment of Product X is received from Zenon Corporation, what sample size should the receiving department test
Answer:
The answer is "28"
Step-by-step explanation:
[tex](LTPD) = 52\%\\\\(AQL) = 20\%\\\\\to \frac{LTPD}{AQL} = \frac{52\%}{20\%}= 2.6\\\\[/tex]
The value of [tex]\frac{LTPD}{AQL} = 2.6[/tex] that value of [tex]\frac{LTPD}{AQL} = 2.618[/tex]
Acceptance number, [tex]c = 9[/tex]
Value of [tex]n\times AQL = 5.426[/tex]
Sample size [tex]n = n\times \frac{AQL}{AQL} =\frac{5.426}{20\%} = 27.13=28[/tex]
What is the equation of a parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2)? x= –y216+6y16–4116 y= –x216+6x16–4116 y=x216–6x16+4116 x=y216–6y16+4116
Answer:
y=x216–6x16+4116
Step-by-step explanation:
plato :)
The equation of the parabola is in option (C) if the parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2) option (C) is correct.
What is a parabola?It is defined as the graph of a quadratic function that has something bowl-shaped.
(x - h)² = 4a(y - k)
(h, k) is the vertex of the parabola:
a = √[(c-h)² + (d-k²]
(c, d) is the focus of the parabola:
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
It is given that:
The equation of a parabola that has a vertical axis, passes through the point (–1, 3)
The vertex of the parabola is at (3, 2)
As we know, in the standard form of the parabola (h, k) represents the vertex of the parabola.
h = 3
k = 2
Plug the above point in the equation:
[tex]\rm y\ =\ \dfrac{x^{2}}{16}-\dfrac{6x}{16}+\dfrac{41}{16}[/tex]
x = 3
y = 2
[tex]\rm 2\ =\ \dfrac{3^{2}}{16}-\dfrac{6(3)}{16}+\dfrac{41}{16}[/tex]
= 9/16 - 18/16 + 41/16
= (9-18+41)/16
= 32/16
2 = 2 ( true)
The equation of the parabola is:
[tex]\rm y\ =\ \dfrac{x^{2}}{16}-\dfrac{6x}{16}+\dfrac{41}{16}[/tex]
Thus, the equation of the parabola is in option (C) if the parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2) option (C) is correct.
Learn more about the parabola here:
brainly.com/question/8708520
#SPJ2
What is the image of (3, -12) after a dilation by a scale factor of į centered
at the origin?
Answer:
9 is. ................m.m..mk
Solve the following system of equations by graphing.
y = -x-1
y = 14x - 4
A) (-4,3)
B) (-3,4)
C) (4,-3)
D) (3,4)
Answer:
(0.2, -1.2)
Step-by-step explanation:
When solving a system of equations by graphing, we first plot the two equations on a graph, then the point of intersection of the two graphs is the solution to the system of equations.
Therefore giving the equations y = - x - 1; and y = 14x - 4, we have to first plot the both linear equations using online geogebra graphing tool. The intersection of both linear graphs is the solution to the problem.
We can see that the point of intersection is A(0.2, -1.2)
2xy+x+2y answer please
Step-by-step explanation:
2 x y + x + 2 y is equal to 3 x y + 2 y final answer is 5xy
Solve for the value of x
x= 55°
according to the picture .........
Given f (x) = 4x - 3,g(2) = x3 + 2x
Find (f - g) (4)
A local grocery store receives strawberries from suppliers in Florida and California. Currently there are 18 strawberry containers on the shelf and 11 of them are from Florida. A shopper selects three containers to purchase. What is the probability that exactly one of the containers is from the Florida supplier
Using the hypergeometric distribution, it is found that there is a 0.2831 = 28.31% probability that exactly one of the containers is from the Florida supplier.
The containers are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes. N is the size of the population. n is the size of the sample. k is the total number of desired outcomes.In this problem:
There are 18 containers, hence [tex]N = 18[/tex]11 of those are in Florida, hence [tex]k = 11[/tex].A sample of 3 containers is taken, hence [tex]n = 3[/tex]The probability that exactly one of the containers is from the Florida supplier is P(X = 1), hence:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 1) = h(1,18,3,11) = \frac{C_{11,1}C_{7,2}}{C_{18,3}} = 0.2831[/tex]
0.2831 = 28.31% probability that exactly one of the containers is from the Florida supplier.
A similar problem is given at https://brainly.com/question/24826394
Can someone please help me with this
Answer:
d
Step-by-step explanation:
h
3x+2y <
11 2x-y<9
Does this graph match this equation?
Answer:
No.
Step-by-step explanation:
3x+2y<11 doesn't have a y-intercept of 6 and doesn't have a x-intercept of 4.
2x-y<9 is not the same direction as 3x+2y<11.
What is the slope of a line perpendicular to line A?
How much does college tuition cost? That depends, of course, on where you go to college. Construct a weighted average. Using the data from "College Affordable for Most," estimate midpoints for the cost intervals. Say 46% of tuitions cost about $4,500; 21% cost about $7,500; 7% cost about $12,000; 8% cost about $18,000; 9% cost about $24,000; and 9% cost about $31,000. Compute the weighted average of college tuition charged at all colleges.
Answer:
0.127
Step-by-step explanation:
How many numbers multiple of 3 are in the range [2,2000]?
Answer:
There are 666 numbers multiple of 3 in the interval.
Step-by-step explanation:
Multiples of 3:
A number is a multiple of 3 if the sum of it's digits is a multiple of 3.
Range [2,2000]:
First multiple of 3 in the interval: 3
Last: 1998
How many:
[tex]1 + \frac{1998 - 3}{3} = 1 + 665 = 666[/tex]
There are 666 numbers multiple of 3 in the interval.
A population of values has a normal distribution with μ= 180.1
and σ=100. You intend to draw a random sample of size n=94
What is the mean of the distribution of sample means?
What is the standard deviation of the distribution of sample means?
(Report answer accurate to 2 decimal places.)
A sample of size n taken from a normally distributed population with mean µ and standard deviation σ has a sample mean of µ and standard deviation of σ/√n.
So the sample mean would still be 180.1, while the sample standard deviation would be 100/√94 ≈ 10.31.
Relate what you know about simplifying expressions to what you know about
factoring. For example, before you can factor 12x + 20y + y, you need to simplify it.
Explain why.
2) Consider the quadratic sequence 72, 100, 120, 132
2.1.1) Determine Tn the nth term of the quadratic.
9514 1404 393
Answer:
Tn = -4n² +40n +36
Step-by-step explanation:
A graphing calculator readily performs the quadratic regression, yielding the formula ...
Tn = -4n² +40n +36
__
The first and second differences of the given sequence terms are ...
28, 20, 12 and -8, -8
The coefficient of the squared term is half the second difference, so is -4. Then the sequence of squared terms is -4n²:
-4, -16, -36, -64
Subtracting these values from the original sequence gives the linear sequence ...
76, 116, 156, 196
which has first term 76 and common difference 40. The equation for the n-th term of this is ...
an = 76 +40(n -1) = 36 +40n
Adding this linear sequence to the sequence of squared terms, we get ...
Tn = -4n² +40n +36
ZDAC = ZBAD.
What is the length of BD?
Round to one decimal place.
Answer:
BD = 4.1
Step-by-step explanation:
DA is an angle bisector which also divides the opposite side of the angle it bisects in a way that it is proportional to tye other two sides.
By implication, we would have the following:
AB/BD = AC/DC
AB = 5.3
AC = 5.5
DC = 4.3
BD = ?
Plug in the values
5.3/BD = 5.5/4.3
Cross multiply
BD*5.5 = 4.3*5.3
BD*5.5 = 22.79
Divide both sides by 5.5
BD = 22.79/5.5
BD = 4.1 (to 1 decimal place)
Find the equation for the line that passes through the points ( - 1, - 10) and ( - 6,9). Give your
answer in point-slope form. You do not need to simplify.
Answer:
The point slope form of the equation is,
[tex]y + 10 = - \frac{19(x + 6)}{5} [/tex]
m = (y2-y1)/(x2-x1) = (9-(-10))/((-6)-(-1)) = -19/5
b = y1-mx1 = -69/5
Answered by GAUTHMATH
As a marketing manager, you are tasked with selecting a website to place your advertisement. The following sampled data shows the number of user visits per month over the last 3 three years:
Website 1: 10357, 10537, 10767, 10561, 10544, 10581, 10602, 10665, 10335, 10419, 10737, 10410, 10485, 10601, 10458, 10472, 10435, 10375, 10436, 10510, 10345, 10559, 10520, 10425, 10351, 10465, 10491, 10671, 10366, 10440, 10618, 10606, 10406, 10538, 10449, 10462
Website 2: 11067, 11029, 10888, 10789, 10914, 10663, 10787, 11140, 11042, 11074, 10868, 10853, 10900, 11088, 10991, 10928, 10959, 11126, 11033, 11114, 11150, 11155, 11027, 10900, 11015, 11123, 10953, 11181, 10855, 10731, 10971, 10770, 11070, 11122, 11018, 10903 Since the behavior of internet users can be considered a natural process, consider the number of views to follow normal distribution. In addition, please assume no autocorrelation or time-series nature of the data. Based on the data above, provide the answers to the following question:
A. What is the average and standard deviation of viewership of each website?
B. Is viewership different between these two websites? If yes, which website provides more views?
C. Suppose that your manager requires at least 12000 views per month. What is the probability of 12000 views happening on each website?
D. Which website provides more consistent view? How would you measure it?
E. Which website would you recommend for your advertisement?
Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
Website 1 : 10357, 10537, 10767, 10561, 10544, 10581, 10602, 10665, 10335, 10419, 10737, 10410, 10485, 10601, 10458, 10472, 10435, 10375, 10436, 10510, 10345, 10559, 10520, 10425, 10351, 10465, 10491, 10671, 10366, 10440, 10618, 10606, 10406, 10538, 10449, 10462
Mean, xbar = ΣX/ n ; n = sample size = 36
Xbar = 377999 / 36 = 10499.9722
Standard deviation, s = √[(x - xbar)² / (n-1]
Using calculator :
Standard deviation (Website 1 :), s = 110.239865
Website 2 : 11067, 11029, 10888, 10789, 10914, 10663, 10787, 11140, 11042, 11074, 10868, 10853, 10900, 11088, 10991, 10928, 10959, 11126, 11033, 11114, 11150, 11155, 11027, 10900, 11015, 11123, 10953, 11181, 10855, 10731, 10971, 10770, 11070, 11122, 11018, 10903
Mean, xbar = ΣX/ n ; n = sample size = 36
Xbar = 395197 / 36 = 10977.6944
Standard deviation, s = √[(x - xbar)² / (n-1]
Using calculator :
Standard deviation (Website 2), s = 132.617995
2.)
Yes, the viewership between the two websites are different with the second website has a higher mean viewership with a mean of 10977.6944.
3.)
The probability of 12000 views per month on each website :
Probability = Mean viewership per month / required viewership
Website 1 :
P(12000) = 10499.9722 / 12000 = 0.8749
Website 2 :
P(12000) = 10977.6944 / 12000 = 0.9148
4.)
More consistent website :
We use the standard deviation value, the higher the standard deviation, the higher the variability :
Website 1 should be more consistent has it has a Lower standard deviation score, hence, should show lower variability than website 2.
5.)
Website suitable for advertisement should be one with higher viewership per month in other to reach a larger audience. Hence, website 2 should be recommended for advertisement.
help me solve this trig
Hello there!
Previously, we learnt that to solve the equation, we have to isolate the sin, cos, tan, etc first.
First Question
The first question has sin both sides. Notice that if we move sin(theta) to left. We get:-
[tex] \displaystyle \large{2 {sin}^{2} \theta - sin \theta = 0}[/tex]
We can common factor out the expression.
[tex] \displaystyle \large{sin \theta(2sin \theta - 1) = 0}[/tex]
It is a trigonometric equation in quadraric pattern.
We consider both equations:-
First Equation
[tex] \displaystyle \large{sin \theta = 0}[/tex]
Remind that sin = y. When sin theta = 0. It means that it lies on the positive x-axis.
We know that 0 satisfies the equation, because sin(0) is 0.
Same goes for π as well, but 2π does not count because the interval is from 0 ≤ theta < 2π.
Hence:-
[tex] \displaystyle \large { \theta = 0,\pi}[/tex]
Second Equation
[tex] \displaystyle \large{2sin \theta - 1 = 0}[/tex]
First, as we learnt. We isolate sin.
[tex] \displaystyle \large{sin \theta = \frac{1}{2} }[/tex]
We know that, sin is positive in Quadrant 1 and 2.
As we learnt from previous question, we use π - (ref. angle) to find Q2 angle.
We know that sin(π/6) is 1/2. Hence π/6 is our reference angle. Since π/6 is in Q1, we only have to find Q2.
Find Quadrant 2
[tex] \displaystyle \large{\pi - \frac{\pi}{6} = \frac{6\pi}{6} - \frac{\pi}{6} } \\ \displaystyle \large{ \frac{5\pi}{6} }[/tex]
Hence:-
[tex] \displaystyle \large{ \theta = \frac{\pi}{6} , \frac{5\pi}{6} }[/tex]
Since both first and second equations are apart of same equation. Therefore, mix both theta from first and second.
Therefore, the solutions to the first question:-
[tex] \displaystyle \large \boxed{ \theta = 0,\pi, \frac{\pi}{6} , \frac{5\pi}{6} }[/tex]
Second Question
This one is a reciprocal of tan, also known as cot.
[tex] \displaystyle \large{cot3 \theta = 1}[/tex]
For this, I will turn cot to 1/tan.
[tex] \displaystyle \large{ \frac{1}{tan3 \theta} = 1}[/tex]
Multiply whole equation by tan3 theta, to get rid of the denominator.
[tex] \displaystyle \large{ \frac{1}{tan3 \theta} \times tan3 \theta = 1 \times tan3 \theta } \\ \displaystyle \large{ 1= tan3 \theta }[/tex]
We also learnt about how to deal with number beside theta.
We increase the interval, by multiplying with the number.
Since our interval is:-
[tex] \displaystyle \large{0 \leqslant \theta < 2\pi}[/tex]
Multiply the whole interval by 3.
[tex] \displaystyle \large{0 \times 3 \leqslant \theta \times 3 < 2\pi \times 3} \\ \displaystyle \large{0 \leqslant 3 \theta < 6\pi }[/tex]
We also know that tan is positive in Quadrant 1 and Quadrant 3.
and tan(π/4) is 1. Therefore, π/4 is our reference angle and our first theta value.
When we want to find Quadrant 3, we use π + (ref. angle).
Find Q3
[tex] \displaystyle \large{\pi + \frac{\pi}{4} } = \frac{5\pi}{4} [/tex]
Hence, our theta values are π/4 and 5π/4. But that is for [0,2π) interval. We want to find theta values over [0,6π) interval.
As we learnt previously, that we use theta + 2πk to find values that are in interval greater than 2π.
As for tangent, we use:-
[tex] \displaystyle \large{ \theta + \pi k = \theta}[/tex]
Because tan is basically a slope or line proportional graph. So it gives the same value every π period.
Now imagine a unit circle, and make sure to have some basic geometry knowledge. Know that when values addition by 180° or π would give a straight angle.
We aren't using k = 1 for this because we've already found Q3 angle.
Since we know Q1 and Q3 angle in [0,2π).
We can also use theta + 2πk if you want.
First Value or π/4
[tex] \displaystyle \large{ \frac{\pi}{4} + 2\pi = \frac{9\pi}{4} } \\ \displaystyle \large{ \frac{\pi}{4} + 4\pi = \frac{17\pi}{4} }[/tex]
Second Value or 5π/4
[tex] \displaystyle \large{ \frac{5\pi}{4} + 2\pi = \frac{13\pi}{4} } \\ \displaystyle \large{ \frac{5\pi}{4} + 4\pi = \frac{21\pi}{4} }[/tex]
Yes, I use theta + 2πk for finding other values.
Therefore:-
[tex] \displaystyle \large{3 \theta = \frac{\pi}{4} , \frac{5\pi}{4} , \frac{9\pi}{4}, \frac{17\pi}{4} , \frac{13\pi}{4} , \frac{21\pi}{4} }[/tex]
Then we divide every values by 3.
[tex] \displaystyle \large \boxed{\theta = \frac{\pi}{12} , \frac{5\pi}{12} , \frac{9\pi}{12}, \frac{17\pi}{12} , \frac{13\pi}{12} , \frac{21\pi}{12} }[/tex]
Let me know if you have any questions!
