What is the difference about the center of a quasar, when contrasted with a spiral galaxy?

Answer:

3622.5 K

Explanation:

The radiation of red giant star is 800nm.

We need to find the surface temperature of the star. Let it is T.

Using Wein's displacement law to find it as follows :

[tex]\lambda=\dfrac{C}{T}[/tex]

C is constant an T is temperature

[tex]T=\dfrac{C}{\lambda}\\\\T=\dfrac{2.898\times 10^{-3}}{800\times 10^{-9}}\\\\ T=3622.5\ K[/tex]

So, the surface temperature of the star is 3622.5 K.

Answer:

The average power of the engine of the sports car is 56.32 kW

Explanation:

Given;

mass of the sports car, m = 1100 kg

initial velocity of the sports car, u = 0 m/s

final velocity of the sports car, v = 32 m/s

time of motion, t = 10 s

The kinetic energy of the car is given by;

K.E = ¹/₂m(v² - u²)

K.E = ¹/₂mv²

K.E = ¹/₂ x 1100 x 32²

K.E = 563200 J

The average power of the engine of the sports car is given by;

Pavg = Energy / time

Pavg = 563200 / 10

Pavg = 56320 W

Pavg = 56.32 kW

Therefore, the average power of the engine of the sports car is 56.32 kW

27.52g grams of sodium would there be in 70 g of NaCl.

The molecular mass gives the total mass of the molecule, it is the sum of masses of all the atoms present in a molecule. for example in Nacl, there is one atom of Na and one atom of Cl both makes NaCl. the sum of masses of Na and Cl gives the mass of the NaCL. Molecular mass is expressed in amu. 1 amu = Avogadro's number of atom or molecule.

The Molar mass is defined as the mass of a given substance divided by the amount of a substance. its unit is g/mol.

Here I have direct method for the calculation of mass of particular atom in the molecule.

Molecular weight of the NaCl is,

(23+35.5)g=58.5g where 23= mass of Na and 35.5 mass Cl.

in this we can see that 58.5 g of Nacl contains 23 g of Na.

we can write 58.5 NaCl = 23g Na

therefore 70g of NaCl = (23÷58.5)×70 Na

70g of NaCl = 27.52g of Na

Hence 70g of NaCl contains 27.52g of sodium.

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Answer:

it should be a new moon

Explanation:

Answer:

5778.1931

Explanation:

Given that:

Mass (M) = 5.98 x 10^24 kg

Radius (r) = 6.96 x 10^6 m

Gravitational constant (G) = 6.67 * 10^-11

Using the relation:

T² / R³ = 4π² / GM

Where T = period of orbit

T = 2π√(R³ /GM)

T = 2π√((6.96 x 10^6)³) /(6.67 * 10^-11) * (5.98 x 10^24)

T = 2π√((3.37153 * 10^20) / (39.866 * 10^13))

T = 2π √845715.64

T = 2π * 919.62799

T = 5778.1931

Answer:

Air and water i think

Explanation:

Cause Air =25% and water=25% so that equals 50%

Answer:

77852x∧100 kgms

Explanation:

Answer:

The speed of these two sea creatures just after their collision is 5.55 m/s.

Explanation:

Given;

mass of the whale, m₁ = 1235 kg

initial speed of the whale, u₁ = 6.4 m/s

mass of the seal, m₂ = 189 kg

initial speed of the seal, u₂ = 0

let their final speed after collision, = v

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(1235 x 6.4) + (189 x 0) = v(1235 + 189)

7904 = 1424v

v = 7904 / 1424

v = 5.55 m/s

Therefore, the speed of these two sea creatures just after their collision is 5.55 m/s.

Answer:

Eeeeeeeeeeeeeeeeeeeeeeeeeee

Answer:

Water in dal lake is test for any heavy metals and pollutant, sewage and drainage system are also monitored for the same.

Explanation:

Answer:

Hey buddy, here is your answer. Hope it helps you.

Explanation:

Yes, weight of a body is not constant, it varies with the value of acceleration due to gravity, g. Weight of a body is zero, when it is taken to the centre of the earth or in the interplanetary space, where g=0. Mass is the total matter in a body, while weight is the force by which the body is attracted.

Weight is never constant while mass is. So we can have weight zero but with some mass. This will happen when an object is at the centre of earth, as g=0 at centre of earth , so weight will be 0 while mass will always be constant everywhere

Answer:

yes a body can have mass but no wt at a centre of the earth

Explanation:

this is because acceleration due to gravity decreases as we go deep into earth and becomes 0 at the centre

Answer:

V = I R    

expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

Explanation:

In a purely resistive circuit, the Ohm relation, m for which

          V = I R

We see that the previous expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

This does not happen in circuits with capacitors or inductors where there is an explicit dependence on frequency.

Answer:

the minimum energy that needed to break the nucleus is  1.12608 × 10^-12 J

Explanation:

The computation of the minimum energy that needed to break the nucleus is shown below:

The Change in mass is

= 11.99671 - 3 × 4.00151

= 0.00782

The Energy = mc^2

= (0.00782 × 1.6 × 10^{-27}) × (3 × 10^8)^2

= 1.12608 × 10^-12 J

Hence, the minimum energy that needed to break the nucleus is  1.12608 × 10^-12 J

The same is to be considered

The simple machines can help make work easier by working quicker than the people and making other peoples jobs easier.

Explanation:

I hope this helped.

Answer:

It’s b

Explanation:

Everyone else is wrong and I tried this and got it right

Answer:

the answer is b or "The sound wave will not be generated, so there will be no echoes received."

Explanation:

Answer:

300 L of water

Explanation:

Answer:

Inertia

Explanation:

Inertia is a force which keeps stationary objects at rest and moving objects in motion at constant velocity.

Answer:

[tex]\boxed {\boxed {\sf 7.84 \ Joules}}[/tex]

Explanation:

The formula for potential energy is:

[tex]PE=m*g*h[/tex]

where m is the mass, g is the gravitational acceleration, and h is the height.

The mass of the book is 0.4 kilograms. The gravitational acceleration on Earth is 9.8 m/s². The height of the book is 2 meters.

[tex]m=0.4 \ kg \\g=9.8 \ m/s^2 \\h=2\ m[/tex]

Substitute the values into the formula.

[tex]PE=(0.4 \ kg)(9.8 \ m/s^2)(2 \ m)[/tex]

Multiply the first two numbers.

[tex]PE=(3.92 \ N )(2 \ m)[/tex]

Multiply.

[tex]PE=7.84 \ J[/tex]

Answer:

7.84 is your answer ok bye

the outer shell of the star are blown off with big clouds of gas and dust which is know as a nebula

Answer:

Newton

Explanation:

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question we have

[tex]k = \frac{1}{2} \times 4 \times {8}^{2} \\ = 2 \times 64[/tex]

We have the final answer as

Hope this helps you

Mass of toy the car = 4 kg

Velocity of toy the car = 8 m/s

Kinetic energy of an object is the energy that it possesses due to its motion.

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity.

Formula of Kinetic energy:

[tex] \boxed{ \bf{KE = \dfrac{1}{2}mv^2}}[/tex]

KE → Kinetic energy of the Object (J)

m → Mass of the Object (kg)

v → Speed of the Object (m/s)

By substituting values in the formula, we get:

[tex] \rm \longrightarrow KE = \dfrac{1}{2} \times 4 \times 8^2 \\ \\ \rm \longrightarrow KE = \dfrac{1}{2} \times 4 \times 64\\ \\ \rm \longrightarrow KE = 2 \times 64 \\ \\ \rm \longrightarrow KE = 128 \: J[/tex]

[tex] \therefore [/tex] Kinetic energy of the toy car = 128 J

Answer:

Explanation:

Using the formula for calculating range expressed as;

R = U√2H/g

U is the speed = 300m/s

H is the maximum height = 78.4m

g is the acceleration due to gravity = 9.8m/s²

Substitute into the fromula;

R = 300√2(78.4)/9.8

R = 300 √(16)

R = 300*4

R = 1200m

Hence the projectile travelled 1200m before hitting the ground

Answer:

Option 1.

Explanation:

To know which option is correct, let us calculate the net force in each case to know which will move to the right direction.

Option 1:

Force to the right (Fᵣ) = 8 N

Force to the left (Fₗ) = 6 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 8 – 6

Fₙ = 2 N to the right

Option 2:

Force to the right (Fᵣ) = 8 N

Force to the left (Fₗ) = 10 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 10 – 8

Fₙ = 2 N to the left

Option 3:

Force to the right (Fᵣ) = 10 N

Force to the left (Fₗ) = 10 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 10 – 10

Fₙ = 0 (no movement)

Option 4:

Force to the right (Fᵣ) = 10 N

Force to the left (Fₗ) = 13 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 13 – 10

Fₙ = 3 N to the left

From the illustrations made above, only option 1 has a net force toward the right direction. Therefore, only option 1 will have an acceleration towards the right direction.

Answer:

Option 1

Explanation:

Answer:

True

Nitrogen family elements consists of atoms having 5 electrons in their outer energy level.

Please mark me the brainliest

Hope it may helps you

Answer:

The gravitational force between Royce and Earth would be doubled at 16 years.

Explanation:

"Newton's law of universal gravitation states that gravitation force between two masses is proportional to the magnitude of their masses and inverse-squared of their distance".

Royce Scenario

At the age of 10 Royce's mass = 30kg

At the age of 16 Royce's mass = 60kg

From Newton's law of universal gravitation, an Increase in the mass of a body would amount to a corresponding increase in the gravitational force.

In the case of Royce, the mass double between the age of 10 and 16, so there would be an increase of the gravitation force by double.

The gravitational force at the age of 60 is doubled of the gravitational force at the age of 10. A complete solution is below.

Given:

At 10 years old,

Mass,

now,

→ [tex]Gravitational \ force (F_1) = \frac{GMm}{r^2}[/tex]

                                          [tex]= mg[/tex]

or,

→ [tex]g = \frac{GM}{r^2}[/tex]

then,

Gravitational force = 30 g

Now,

At 16 years old,

Mass,

Now,

→ [tex]\frac{F_1}{F_2} = \frac{30}{60}[/tex]

       [tex]=\frac{1}{2}[/tex]

  [tex]F_2 = 2F_1[/tex]

Thus the above response is right.

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Answer:

The magnitude of the magnetic force on the proton is 9.532 x 10⁻¹⁷ N

Explanation:

Given;

speed of proton, v = 850 m/s

magnitude of magnetic field, B = 0.7 T

Charge of proton, q = 1.602 x 10⁻¹⁹ C

The magnitude of the magnetic force on the proton;

F = qvB

F = ( 1.602 x 10⁻¹⁹)(850)(0.7)

F = 9.532 x 10⁻¹⁷ N.

Therefore, the magnitude of the magnetic force on the proton is 9.532 x 10⁻¹⁷ N

Answer:

Meeee

Explanation: