what is a 200% increase of 50
​

Answer:

Angelique has traveled further than Jamila by about 6 km.

Step-by-step explanation:

Make them the same unit (I will make them both kilometers)

There is about 1.609 km in 1 mile

75 miles * 1.609 km/1 mile = 120.675

120.675 km>115 km

Answer:

C. (-3x+15)/2

Step-by-step explanation:

y = (15-2x)/3

To find the inverse, exchange x and y

x = (15-2y)/3

Solve for y

Multiply each side by 3

3x = (15-2y)/3 *3

3x= 15-2y

Subtract 15 from each side

3x-15 = 15-2y-15

3x-15 = -2y

Divide by -2

(3x-15)/-2 = -2y/-2

(-3x+15)/2 = y

Answer:

3 +4 i

Step-by-step explanation:

x + sqrt(yz)

Let x = 3 y=2  and z = -8

3 + sqrt(2*-8)

3+ sqrt(-16)

3 + sqrt(16) sqrt(-1)

We know sqrt(-1) = i

3 +4 i

Answer:

78,073

Step-by-step explanation:

Subtract 8,420 from 86,493...86,493-8,420=78,073 is the answer

Double check by using inverse operations...78,073+8,420=86,493

It is correct, as I ended up with 86,493, the starting number of the equation.

Answer:

D. 359 nm

[tex]{ \boxed{ \bf{ energy = \frac{hc}{ \lambda} }}} [/tex]

lambda is the wavelength

c is the speed of light

h is the Planck's constant

[tex]{ \sf{5.53 \times {10}^{ - 19} = \frac{(6.626 \times {10}^{ - 34}) \times (3.00 \times { {10}^{8} }) }{ \lambda} }} \\ \\ { \sf{\lambda = 3.59 \times {10}^{ - 7} }} \\ { \sf{\lambda = 359 \: nm}}[/tex]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

You want a line that goes through (0, 0) and has a slope of 5. That means it will also go through (1, 5) and (2, 10), for example. I like the attached graphing tool because it will draw the graph directly from the equation.

18/24, 20/24

Step-by-step explanation:

3/4=?/24

5/6=?/24

3X6=18

4X6=24

5X4=20

6X4=24

Answer:

7/8 = 21/24

5/6 = 20/24

3/4 = 18/24

Step-by-step explanation:

What you do to the denominator, you do the same to the numerator.

[tex]\frac{7}{8} * \frac{3}{3} = \frac{21}{24}[/tex]

[tex]\frac{5}{6} * \frac{4}{4} = \frac{20}{24}[/tex]

[tex]\frac{3}{4} * \frac{6}{6} = \frac{18}{24}[/tex]

Answer:

I guess the the correct answer is D

Answer:

You’ve worked 7 hours and 30 minutes

Step-by-step explanation:

Answer:

12 x 3/5 = 7 1/5

Step-by-step explanation:

12 x 3/5

Add 1 below 12 as a denominator to make it an improper fraction

= 12/1 x 3/5

Multiply numerators from both fractions as long as the denominators:

12 x 3 = 36

1 x 5 = 5

12/1 x 3/5 = 36/5

36/5 SIMPLIFIED IS 7 1/5

Hope this helps!

Answer:

36/5 = 7.2 = 7 1/5

Step-by-step explanation:

12 x 3/5

Change 12 into fraction form to make it easier.

12/1 x 3/5

Now multiply the numerators and the denominators.

12 x 3 = 36

1 x 5 = 5

12/1 x 3/5 = 36/5

If you don't want the answer as an improper fraction, 36/5 = 7.2 which is also equal to 7 1/5

Answer:

16384

Step-by-step explanation:

4×4×4×4×4×4×4

= 4⁷

= 16384 ways

7 answers can be answered by guessing in 4⁷ ways.

A permutation is an arrangement of things where order matters, AB and BA are two different permutations.

The combination is a selection of things where order does not matter, AB and BA are the same combinations.

Given, A multiple-choice test has 7 questions, with 4 possible answers for each question.

Now the first question can be guessed in 4 different ways.

Similarly, 7 answers can be answered by guessing in 4⁷ ways.

= 16,384.

learn more about permutation and combination here :

https://brainly.com/question/28720645

#SPJ2

Hi

Income tax is  progressive

So with  50 000  we have  :  

0.02*3000 + 0.03 ( 5000 -3001) + 0.05 ( 17 000-5001) + 0.0575 ( 50 000 - 17 001) =  60+ 59.97+599.95 + 1897.44 =  2617.36

tax is = 2617.36

Answer:

120 degrees move in 10 hours

Answer:

3 2/3 servings

Step-by-step explanation:

Take the total amount of strawberries and divide by the number of strawberries in a serving.

11/12÷ 1/4

Copy dot flip

11/12 * 4/1

Rewriting

11/1 * 4/12

11/1 *1/3

11/3

Changing to a mixed number

3 2/3 servings

☆No of servings =Total strawberries weight/Per servings weight

[tex]\\ \sf\longmapsto \dfrac{11}{12}\div \dfrac{1}{4}[/tex]

[tex]\\ \sf\longmapsto \dfrac{11}{12}\times \dfrac{4}{1}[/tex]

[tex]\\ \sf\longmapsto \dfrac{11(4)}{12}[/tex]

[tex]\\ \sf\longmapsto \dfrac{44}{12}[/tex]

[tex]\\ \sf\longmapsto \dfrac{11}{3}[/tex]

Answer:

C

Step-by-step explanation:

Plug each ordered pair into the equation

A: 4 = 3(-1)-1

4=-3-1

This is false

B: 2= 3(-1)-1

2=-3-1

This is false

C: -4 = 3(-1)-1

-4=-3-1

This is true

Step-by-step explanation:

f'(x) is usually used in calculus to denote the first derivative of f(x) so f'(2) will simply be the first derivative of f(2).

f(x)=x+3

f'(x)=1

thus x does affect the first derivative and your answer for f'(x)=1

Answer:

a.83%

b. 48%

c.36%

d.35%

e.69%

f.36%

g.30%

h.69%

Answer:

Step-by-step explanation:

(-1) × 1 = -1

Answer:

-1

Step-by-step explanation:

anything times 1 =1. except 0.

Answer:

x = 1/2

Step-by-step explanation:

8(-2x+1) =0

Divide each side by 8

-2x+1 = 0

Add 2x to each side

-2x+1+2x = 2x

1 = 2x

Divide by 2

1/2 = 2x/2

1/2 =x

Answer:

1/2

Step-by-step explanation:

8(-2x+1)=0

Use distributive property first

-16x+8=0

Subtract 8 on both sides

-16x=-8

Divide both sides by -16 to get x by itself

x=0.5

Which is also equal to 1/2

Therefore, x is equal to 1/2

Let side be a

We know

[tex]\\ \sf\longmapsto Area=(side)^2[/tex]

[tex]\\ \sf\longmapsto a^2=111[/tex]

[tex]\\ \sf\longmapsto a=\sqrt{111}[/tex]

[tex]\\ \sf\longmapsto a=10.3units[/tex]

Split up C into two component paths C₁ and C₂, where each line segment is respectively parameterized by

r₁(t) = (1 - t ) (3i + k) + t (4i + 3j + k) = (t + 3) i + 3t j + k

r₂(t) = (1 - t ) (4i + 3j + k) + t (4i + 5j + 4k) = 4i + (2t + 3) j + (3t + 1) k

both with 0 ≤ t ≤ 1.

It's a bit unclear what function you're supposed to integrate (looks like xyz ?) so I'll give a more general result. The line integral of a scalar function f(x, y, z) along the given path C is

[tex]\displaystyle \int_C f(x,y,z)\,\mathrm ds = \int_{C_1}f(\mathbf r_1(t))\left\|\frac{\mathrm d\mathbf r_1}{\mathrm dt}\right\|\,\mathrm dt + \int_{C_1}f(\mathbf r_2(t))\left\|\frac{\mathrm d\mathbf r_2}{\mathrm dt}\right\|\,\mathrm dt[/tex]

We have

dr₁/dt = i + 3j   ==>   || dr₁/dt || = √(1² + 3²) = √10

dr₂/dt = 2j + 3k   ==>   || dr₂/dt || = √(2² + 3²) = √13

Then the integrals reduce to

[tex]\displaystyle \int_0^1 \left(\sqrt{10}\,f(t+3,3t,1) + \sqrt{13}\,f(4,2t+3,3t+1)\right)\,\mathrm dt[/tex]

If indeed f(x, y, z) = xyz, then we have

[tex]\displaystyle \int_0^1 \left(3\sqrt{10}\,t(t+3) + 4\sqrt{13}\,(2t+3)(3t+1)\right)\,\mathrm dt = 11\sqrt{\frac52}+42\sqrt{13}[/tex]

answer:

2 on the picture is the amplitude

Answer:

5(3x+4y)

Step-by-step explanation:

The solution to he word problem leading to simultaneous equation is as follows;

The number of problems Pema is able to solve correctly is 15 problems

The method by which we arrived at the above value is as follows:

The given parameters of the question are;

Amount Pema's dad promise to pay her for every problem she gets right = Nu 5

Amount he would take away for any problem missed = Nu 3 (Therefore, Nu -3)

Amount Pema was paid after working 20 problems = Nu 60

Solution;

Let x represent the number of problems she gets right (solves correctly), and let y represent the number of problems she missed, we have the following system of (simultaneous) equations;

x + y = 20...(1)

5·x - 3·y = 60...(2)

Multiplying equation (1) by 3 and adding the result to equation (2) gives;

3 × (x + y = 20) ⇒ 3·x + 3·y = 60

[tex]{}[/tex]   5·x - 3·y = 60

+ 3·x + 3·y = 60

  [tex]{}[/tex]8·x + 0 = 120

x = 120/8 = 15

x = 15

The number of problems she solves correctly, x = 15

Learn more about word problem leading to simultaneous equations here;

https://brainly.com/question/14294864

Answer:

$3.20

Step-by-step explanation:

Divide the number 16 (as in the cost per Jacket) by 5. (The amount of shirts you could buy with $16)

Then once you have divided 16 by 5, your answer should be 3.2, so the cost of one shirt is $3.20

(A) f(x) = 7 is constant, so f(x + h) = 7, too, which makes f(x + h) - f(x) = 0. So f'(x) = 0.

(B) f(x) = 5x + 1   ==>   f(x + h) = 5 (x + h) + 1 = 5x + 5h + 1

==>   f(x + h) - f(x) = 5h

Then

[tex]\displaystyle f'(x) = \lim_{h\to0}\frac{5h}h = \lim_{h\to0}5 = 5[/tex]

(C) f(x) = x ² + 3   ==>   f(x + h) = (x + h)² + 3 = x ² + 2xh + h ² + 3

==>   f(x + h) - f(x) = 2xh + h ²

[tex]\implies\displaystyle f'(x) = \lim_{h\to0}\frac{2xh+h^2}h = \lim_{h\to0}(2x+h) = 2x[/tex]

(D) f(x) = x ² + 4x - 1   ==>   f(x + h) = (x + h)² + 4 (x + h) - 1 = x ² + 2xh + h ² + 4x + 4h - 1

==>   f(x + h) - f(x) = 2xh + h ² + 4h

[tex]\implies \displaystyle f'(x) = \lim_{h\to0}\frac{2xh+h^2+4h}h = \lim_{h\to0}(2x+h+4) = 2x+4[/tex]