What does x equal in the following equation 3x + 5 = 17 A x = 2 B x = 4 C x = 5

Answer:

f(3) = 2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Functions

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 2x - 4

Step 2: Evaluate

The association between the given lines is that they are 'neither perpendicular nor parallel.'

To prove, let's convert the given equations in their slope-intercept form i.e. 'y = mx + b'

-7x + 2y = 3

2y = 7x + 3

y = 7/2x + 3/2

-6x + 3y = 2

3y = 6x + 2

y = 2x + 2/3

This shows that both the lines have different slopes, as well as, intercepts of y. And,

[tex]m_{1} * m_{2}[/tex] = 2 * 7/2 ≠ -1

Thus, it is not perpendicular also.

Therefore, option D i.e. 'neither perpendicular nor parallel' is the correct answer.

Learn more about 'slope' here:

brainly.com/question/10973849

Answer:

[tex]{26}[/tex]

Step-by-step explanation:

[tex] \sqrt{(0 - ( - 5) ){}^{2} + (0 - 1) {}^{2} } [/tex]

[tex] = \sqrt{ {(5)}^{2} + {( - 1)}^{2} } [/tex]

[tex] = \sqrt{25 + 1} [/tex]

[tex] = \sqrt{26} [/tex]

Answered by GAUTHMATH

Answer:

26

Step-by-step explanation:

(-5, 1) (0, 0)

sqrt(5^2 + (-1^2))

sqrt(25 + 1)

sqrt(26)

So, 26 goes under the radical.

Answer:

Domain x ≥ - 5

Range y ≥ - 2

Step-by-step explanation:

x ≥ - 5

y ≥ - 2

Answer:

assuming that it is  [tex](1/3)^{6}[/tex] that would be

  [tex]\frac{1}{729}[/tex]

Step-by-step explanation:

Answer:

MATH

Step-by-step explanation:

Answer:

0

Step-by-step explanation:

Replace q with 7 .

[tex]7 + ( - 7) = 0[/tex]

[tex] \sf \: q + ( - 7) \\ \sf \: q = 7 \\ \\ \sf \: q + ( - 7) \\ \sf= 7 + ( - 7) \\ \sf= 7 - 7 \\ \sf= \boxed{\bf \: 0}[/tex]

Hope it helps.

RainbowSalt2222

Answer:

The correct solution is "(0.092, 0.148)".

Step-by-step explanation:

Given:

Sample size,

n = 500

True proportion,

[tex]\hat {p} = \frac{60}{500}[/tex]

  [tex]=0.12[/tex]

The standard error will be:

[tex]SE=\sqrt{\frac{\hat p(1-\hat p)}{n} }[/tex]

     [tex]=\sqrt{\frac{0.12(1-0.12)}{500} }[/tex]

     [tex]=\frac{0.12(0.88)}{500}[/tex]

The confidence interval is "1.96".

hence,

The required confidence interval will be:

= [tex](\hat p - 1.96 SE, \hat p + 1.96 SE)[/tex]

By substituting the values, we get

= [tex](0.12-1.96\sqrt{\frac{0.12(0.88)}{500} }, 0.12+1.96\sqrt{\frac{0.12(0.88)}{500} } )[/tex]

= [tex](0.092, 0.148)[/tex]

Answer:

17) 250 km²

18) never

19) sometimes

20) 288 in³

Step-by-step explanation:

17)

this polygon can be seen as the combination of two shapes : a 16×13 rectangle on top, and a right-angled triangle at the bottom.

this triangle has the side lengths

15 km

(16 - 10) = 6 km

(27 - 13) = 14 km

the total area is the area of the rectangle plus the area of the triangle.

the area of the rectangle (length×width)

Ar = 16×13 = 208 km²

the area of the triangle (baseline×height/2)

since it is a right-angled triangle, we use one side of the 90 degree angle as baseline and the other as height

At = 6×14/2 = 3×14 = 42 km²

so the total area of the polygon

Ap = Ar + At = 208 + 42 = 250 km²

18) the first quadrant is the area between the right (positive) side of the x axis and the upper (positive) part of the y axis. all points here have always and only positive x and y values. never any negative ones.

19) when a point is on the x-axis, well, left of point 0 on the x -axis are only negative values of x. and right of point 0 of the x-axis are only positive values of x. so, for some of these points the x value is positive, and for some it is negative. therefore "sometimes".

20) the volume of a box is length×width×height.

V = 8×3×12 = 24×12 = 288 in³

Answer:

Step-by-step explanation:

5y=...:

y=5-13

y=-8=>5y=-58

6x-(-58)=13

6x+58=13

6x =13-58

6x =-45

x =-45:6

x =-7.5

Answer:

false

Step-by-step explanation:

the first quadrant of a coordinate plane is the upper right corner

this means that both x and y coordinates of a point would have to be positive

therefore it's false

hope this helps!

Answer:

y = -26.059x + 722.63

Step-by-step explanation:

The equation that represents the approximate line of best fit for data will be D. y = –26x + 723.

It should be noted that an equation is simply used to illustrate the mathematical expressions between variables.

To find an equation of a line, it's important to identify the slope, the point, and then substitute the values into the point-slope form.

Using the given data you can build the linear regression that is described by the linear function y=ax+b, you can see that a = -26 and b = 723 in the attached diagram.

In this case, the equation that represents the approximate line of best fit for data will be y = –26x + 723. The line expresses the relationship between the points.

Learn more about equations on:

https://brainly.com/question/13763238

#SPJ2

Answer:

Sorry if i'm wrong.

=6x² + 16x - 2

Answer:

a = 8.7

Step-by-step explanation:

The Pythagorean theorem is

a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse

a^2+5^2 = 10^2

a^2 +25 = 100

a^2 = 100-25

a^2 = 75

Taking the square root of each side

sqrt(a^2) =sqrt(75)

a =8.660254038

Rounding to the nearest tenth

a = 8.7

Answer:

(x+2)2(x+1)(x+4)

Because

x=-4. x=2. x=-1

(x+4). (x+2). (x+1)

Answer:

Tanya is reflect y axis and then 90 degrees.  

Kurt is reflect over y=x

Have an amazing day! Hope This Helps :)

a)3-2=1 b)4-2=2 c)8-2=6 d)7-4=3

Answer:

2

Step-by-step explanation:

Basically, the period of a sinusoidal graph is the distance between one cycle to another. As can be visually seen, this is 2.

Answer:

2

Step-by-step explanation:

its right on Acellus

Answer:

4 TOPPING WITH 5 CENTS LEFT

Step-by-step explanation:

A AND B ARE CORRECT ok so $6.50 to spend take out $3 for the cost of a plain hamburger which would leave you with $3.50 to spend on toppings alone so

3.5-0.75=2.75 (1 topping

2.75-0.75=2 (2 topping

2-0.75=1.25 (3 topping

1.25-0.75=0.5 (4 topping

there for you can get 4 toppings with 5 cents left over

To calculate the area of the black material on the flag, we need the shape and the dimensions of the black material itself.

Since the question is incomplete, as the dimension of the flag and the dimension of the black material are not given, I will provide a general explanation.

Assume the shape of the black material is a rectangle.

The area will be calculated as:

[tex]Area = Length * Width[/tex]

Take for instance;

[tex]Length = 4yd;\ Width = 5yd[/tex]

[tex]Area = 4yd * 5yd[/tex]

[tex]Area = 20yd^2[/tex]

Assume the shape of the black material is a square.

The area will be calculated as:

[tex]Area =Length^2[/tex]

Take for instance;

[tex]Length = 4yd[/tex]

[tex]Area = (4yd)^2[/tex]

[tex]Area = 16yd^2[/tex]

Assume the shape of the black material is a triangle

The area will be calculated as:

[tex]Area = 0.5 * Base * Height[/tex]

Take for instance;

[tex]Base = 4yd;\ Height = 5yd[/tex]

[tex]Area = 0.5 * 4yd * 5yd[/tex]

[tex]Area =10yd^2[/tex]

So, in general.

You need to first get the shape of the black segment on the flag, then calculate the area using the appropriate formula.

Read more about areas at:

https://brainly.com/question/24251781

Answer:

there is a 25% decrease in books being read

Answer:

2.6

Step-by-step explanation:

espero ter ajudado

Answer:

(k) cos(θ)·√(1 + cot²θ) = √(cosec²θ - 1)

From trigonometric identities, we have;

1 + cot²θ = cosec²θ

On the Left Hand Side of the equation, we get;

cos(θ)·√(1 + cot²θ) = cos(θ) × cosec(θ) = cot(θ)

On the Right Hand Side of the equation, we have;

√(cosec²(θ) - 1) = √(1 + cot²(θ) - 1) = √(cot²(θ)) = cot(θ)

∴ √(cosec²θ - 1) = cot(θ)

By transitive property of equality, therefore;

cos(θ)·√(1 + cot²θ) = √(cosec²θ - 1)

(l) sin⁶A + cos⁶A = 1 - 3·sin²A·cos²A

sin⁶A + cos⁶A = (sin²A)³ + (cos²A)³

(sin²A)³ + (cos²A)³ = ((sin²A) + (cos²A))³ - 3·((sin²A)·(cos²A))·((sin²A) + (cos²A))

∴ (sin²A)³ + (cos²A)³ = (1)³ - 3·((sin²A)·(cos²A))·(1) = 1 - 3·((sin²A)·(cos²A))

sin⁶A + cos⁶A = (sin²A)³ + (cos²A)³ = 1 - 3·((sin²A)·(cos²A))

sin⁶A + cos⁶A = 1 - 3·((sin²A)·(cos²A))

(m) (sinA - cosecA)² + (cosA - secA)² = cot²A + tan²A - 1

(sinA - cosecA)²  = sin²A - 2×sinA×cosecA + cosec²A = sin²A - 2 + cosec²A

(cosA - secA)² = cos²A - 2×cosA×secA + sec²A = cos²A - 2 + sec²A

∴ (sinA - cosecA)² + (cosA - secA)² = sin²A - 2 + cosec²A + cos²A - 2 + sec²A

Where;

sin²A - 2 + cosec²A + cos²A - 2 + sec²A = sin²A + cos²A  - 2  - 2 + cosec²A + sec²A

sin²A + cos²A  - 2  - 2 + cosec²A + sec²A = 1 - 4 + cosec²A + sec²A

1 - 4 + cosec²A + sec²A = cosec²A + sec²A - 3

Where;

cosec²A = cot²A + 1

sec²A = tan²A + 1

∴ cosec²A + sec²A - 3 = cot²A + 1 + tan²A + 1 - 3 = cot²A + tan²A - 1 = The Right Hand Side of the equation

∴ (sinA - cosecA)² + (cosA - secA)² = cot²A + tan²A - 1

(n) [tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex] = sinA - cosA

Squaring the Right Hand Side of the equation, we get;

(sinA - cosA)² = sin²A -2·sinA·cosA + cos²A = sin²A + cos²A -2·sinA·cosA

sin²A + cos²A -2·sinA·cosA = 1 - 2·sinA·cosA

∴ (sinA - cosA)² =  1 - 2·sinA·cosA

Taking the square root of both sides gives;

√((sinA - cosA)²) = [tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex]

∴ sinA - cosA = [tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex]

By symmetric property of equality, we have;

[tex]\sqrt{1 - 2\cdot siaA\cdot cosA}[/tex] = sinA - cosA

Step-by-step explanation:

Answer:

Step-by-step explanation:

If these were similar, then the ratio 35/18 (the top and bottom measures from each of the polygons) would have to equal the ratio 63/10 (the side measures from each of the polygons).

35/18 = 1.944444

63/10 = 6.3

They are not similar because the simplified ratios are not the same.

Answer:

[tex]x = 1 + \sqrt{5} x = 1 - \sqrt{5} [/tex]

Answer:

Step-by-step explanation:

Use Pythagorean's Theorem:

[tex]c^2=15^2+8^2[/tex] and

[tex]c^2=225+64[/tex] and

[tex]c^2=289[/tex] so

c = 17

Answer:

Step-by-step explanation:

(a - b)(a + b) =a² - b²

(3x + 5)(3x -5) =(3x)² - 5² = 9x² - 25

(x +2)(x+2) = (x+ 2)² = x²+ 2*2*x+2² = x² + 4x + 4

(x+2)(3x -5 ) = x*3x - 5*x +2*3x +2*(-5)

                    = 3x² -5x +6x -10

                    = 3x² + x - 10

[tex]\frac{2*(3x+5)}{x+2}-\frac{5(x+2)}{3x-5}=3\\\\\frac{2*(3x+5)*(3x-5)}{(x+2)(3x-5)}-\frac{5*(x+2)(x+2)}{(3x-5)(x+2)}=3\\\\\frac{2*(9x^{2}-25)-5(x^{2}+4x+4)}{(3x-5)(x+2)}=3[/tex]

[tex]\frac{18x^{2}-25-5x^{2}-20x-20}{3x^{2}+x-10}=3\\\\\frac{18x^{2}-5x^{2}-20x - 25-20}{3x^{2}+x-10}=3\\\\[/tex]

13x² - 20x - 45 = 3*(3x² + x - 10)

13x² - 20x - 45 =9x² + 3x - 30

13x² - 9x² -20x - 3x - 45 + 30 = 0

4x² - 23x - 15 = 0