Answer:
ushshdbs the 7th century there where the gall bladder and merchants Bank Ltd bank in the 7th
Write the composite function in the form f(g(x)). [Identify the inner function u = g(x) and the outer function y = f(u).] $ y = e^{{\color{red}5}\sqrt{x}} $
Answer:
The answer is "[tex]\frac{5 e^{5\sqrt{x} }}{2\sqrt{x}}[/tex]".
Step-by-step explanation:
Given:
[tex]y = e^{{\color{\red}5}\sqrt{x}}[/tex]
let
[tex]\to t= 5\sqrt{x}\\\\\frac{dt}{dx}= 5 \frac{1}{2\sqrt{x}}\\\\\frac{dt}{dx}= \frac{5}{2\sqrt{x}}\\\\[/tex]
and
[tex]\to y=e^t\\\\\to \frac{dy}{dt}=e^t\\[/tex]
[tex]\to \frac{dy}{dt}=e^{5\sqrt{x} }\\[/tex]
So,
[tex]\to \frac{dy}{dx}= \frac{dy}{dt} \times \frac{dt}{dx}[/tex]
[tex]=e^{5\sqrt{x} }\times \frac{5}{2\sqrt{x}}\\\\= \frac{5 e^{5\sqrt{x} }}{2\sqrt{x}}[/tex]
OR
[tex]\to g(x) = 5\sqrt{x} \\\\\to f(x) = e^{(x)}\\\\[/tex]
Derivate:
[tex]\to f''g' = \frac{e^{(5\sqrt{x})}5}{(2\sqrt{x})}[/tex]
In a random sample of seven aerospace engineers, the sample mean monthly income is $6824 and the sample standard deviation is $340. Construct a 95% confidence interval for the population mean. Assume that the monthly incomes are normally distributed.
Answer:
The 95% confidence interval for the population mean is ($6510, $7138).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So
df = 7 - 1 = 6
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.4469.
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.4469\frac{340}{\sqrt{7}} = 314[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 6824 - 314 = $6510.
The upper end of the interval is the sample mean added to M. So it is 6824 + 314 = $7138.
The 95% confidence interval for the population mean is ($6510, $7138).
Calls to a customer service center last on average 2.3 minutes with a standard deviation of 2 minutes. An operator in the call center is required to answer 76 calls each day. Assume the call times are independent.
What is the expected total amount of time in minutes the operator will spend on the calls each day?
What is the standard deviation of the total amount of time in minutes the operator will spend on the calls each day? Give your answer to four decimal places.
What is the approximate probability that the total time spent on the calls will be less than 166 minutes? Give your answer to four decimal places. Use the standard deviation as you entered it above to answer this question.
What is the value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95? Give your answer to four decimal places. Use the standard deviation as you entered it above to answer this question.
Answer:
The expected total amount of time in minutes the operator will spend on the calls each day is of 174.8 minutes.
The standard deviation of the total amount of time in minutes the operator will spend on the calls each day is of 17.4356 minutes.
0.3085 = 30.85% approximate probability that the total time spent on the calls will be less than 166 minutes.
The value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95 is [tex]c = 203.4816[/tex]
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
n instances of a normally distributed variable:
For n instances of a normally distributed variable, the mean is:
[tex]M = n\mu[/tex]
The standard deviation is:
[tex]s = \sigma\sqrt{n}[/tex]
Calls to a customer service center last on average 2.3 minutes with a standard deviation of 2 minutes.
This means that [tex]\mu = 2.3, \sigma = 2[/tex]
An operator in the call center is required to answer 76 calls each day.
This means that [tex]n = 76[/tex]
What is the expected total amount of time in minutes the operator will spend on the calls each day?
[tex]M = n\mu = 76*2.3 = 174.8[/tex]
The expected total amount of time in minutes the operator will spend on the calls each day is of 174.8 minutes.
What is the standard deviation of the total amount of time in minutes the operator will spend on the calls each day?
[tex]s = \sigma\sqrt{n} = 2\sqrt{76} = 17.4356[/tex]
The standard deviation of the total amount of time in minutes the operator will spend on the calls each day is of 17.4356 minutes.
What is the approximate probability that the total time spent on the calls will be less than 166 minutes?
This is the p-value of Z when X = 166.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
For this problem:
[tex]Z = \frac{X - M}{s}[/tex]
[tex]Z = \frac{166 - 174.8}{17.4356}[/tex]
[tex]Z = 0.5[/tex]
[tex]Z = 0.5[/tex] has a p-value of 0.6915.
1 - 0.6915 = 0.3085.
0.3085 = 30.85% approximate probability that the total time spent on the calls will be less than 166 minutes.
What is the value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95?
This is X = c for which Z has a p-value of 0.95, so X = c when Z = 1.645. Then
[tex]Z = \frac{X - M}{s}[/tex]
[tex]1.645 = \frac{c - 174.8}{17.4356}[/tex]
[tex]c - 174.8 = 1.645*17.4356[/tex]
[tex]c = 203.4816[/tex]
The value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95 is [tex]c = 203.4816[/tex]
find the sum or difference of 4/5 - (-3 4/5)
Answer:
4 3/5
Step-by-step explanation:
4/5 - (-3 4/5)
Subtracting a negative is like adding
4/5 + 3 4/5
3 8/5
3 5/5 + 3/5
3+1+3/5
4 3/5
I need help with these questions
9514 1404 393
Answer:
17. 25 mile per gallon
18. Eduardo did should have divided by -4.
Step-by-step explanation:
17. The least mileage will be had when the most gas is used to go a given distance. For the given distance, the most gas that could have been used (without adding any) is 18 gallons. Then the least mileage is ...
(450 mi)/(18 gal) = 25 mi/gal
__
18. The appropriate method for solving this inequality is ...
-4x/(-4) < 120/(-4) . . . . divide both sides by -4 (and reverse the > symbol)
x < -30
The step Eduardo took of adding 4 will give ...
-4x +4 > 124 . . . . . puts him one step farther away from a solution
Eduardo chose an operation to perform that did not get him closer to a solution.
The average weight of a professional football player in 2009 was pounds. Assume the population standard deviation is pounds. A random sample of professional football players was selected.
Required:
a. Calculate the standard error of the mean.
b. What is the probability that the sample mean will be less than 230 pounds?
c. What is the probability that the sample mean will be more than 231 pounds?
d. What is the probability that the sample mean will be between 248 pounds and 255 pounds?
Answer:
6.286;
0.0165
0.976
0.1995
Step-by-step explanation:
Given that :
Mean, μ = 243. 4
Standard deviation, σ = 35
Sample size, n = 31
1.)
Standard Error
S. E = σ / √n = 35/√31 = 6.286
2.)
P(x < 230) ;
Z = (x - μ) / S.E
P(Z < (230 - 243.4) / 6.286))
P(Z < - 2.132) = 0.0165
3.)
P(x > 231)
P(Z > (231 - 243.4) / 6.286))
P(Z > - 1.973) = 0.976 (area to the right)
4)
P(x < 248)
P(Z < (248 - 243.4) / 6.286))
P(Z < 0.732) = 0.7679
P(x < 255)
P(Z < (255 - 243.4) / 6.286))
P(Z < 1.845) = 0.9674
0.9674 - 0.7679 = 0.1995
The length of a rectangle is 4 meters longer than the width. If the area is 22 square meters. find the rectangles dimensions. The width is what? The length is what?
Answer:
The width is:
[tex]-2+\sqrt{26}\text{ meters}\text{ }(\text{or approximately 3.0990 meters})[/tex]
And the length is:
[tex]2+\sqrt{26}\text{ meters}\text{ } (\text{or approximately 7.0990 meters})[/tex]
Step-by-step explanation:
Recall that the area of a rectangle is given by:
[tex]\displaystyle A = w\ell[/tex]
Where w is the width and l is the length.
We are given that the length of a rectangle is four meters longer than the width. Thus:
[tex]\ell = w + 4[/tex]
And we also know that the area of the rectangle is 22 square meteres.
Substitute:
[tex](22)=w(w+4)[/tex]
Distribute and isolate the equation:
[tex]w^2+4w-22=0[/tex]
The equation isn't factorable, so we can instead use the quadratic formula:
[tex]\displaystyle w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
In this case, a = 1, b = 4, and c = -22. Substitute:
[tex]\displaystyle w = \frac{-(4)\pm\sqrt{(4)^2-4(1)(-22)}}{2(1)}[/tex]
Evaluate:
[tex]\displaystyle\begin{aligned} w &= \frac{-4\pm\sqrt{104}}{2}\\ \\ &=\frac{-4\pm\sqrt{4\cdot 26}}{2} \\ \\ &=\frac{-4\pm2\sqrt{26}}{2} \\ \\ & = -2\pm \sqrt{26} \end{aligned}[/tex]
Thus, our two solutions are:
[tex]w_1=-2+\sqrt{26}\approx 3.0990\text{ or } w_2=-2-\sqrt{26}\approx-7.0990[/tex]
Since the width cannot be negative, we can ignore the second solution.
Since the length is four meters longer than the width:
[tex]\ell = (-2+\sqrt{26})+4=2+\sqrt{26}\text{ meters}[/tex]
Thus, the dimensions of the rectangle are:
[tex]\displaystyle (2+\sqrt{26}) \text{ meters by } (-2+\sqrt{26})\text{ meters}[/tex]
Or, approximately 3.0990 by 7.0990.
Plz help me find side x and y thanks
Answer:
2sqrt3
Step-by-step explanation:
Since this seems to be a 45, 45, 90 triangle, x and y are the same.
The hypoteneuse is always the side lengths *sqrt2
We divide the hypoteneuse by sqrt 2 and get sqrt12
sqrt12 simplified is 2sqrt3
There are 5 slots, each containing the letters W, R, L, D or O. One letter is picked at random from each slot. What are the odds that the letters stored in these slots read the word WORLD?
Answer:
1/120
Step-by-step explanation:
For the first letter, you have a 1/5 chance of getting w
On the second you have a 1/4 chance to get the r
Then 1/3 and 1/2
Next you just multiply the bottom numbers
That gives you how many diffrent outcomes there can be. Put that over 1 and you have your answer.
Hope this helps <3
Identify the decimals labeled with the letters A B and a C
Answer:
A = 0.46, B = 0.61 and C = 0.46
Step-by-step explanation:
From the number line given, we can see that the distance between 0.5 and the next value is by 0.01, hence to get B, we will add 0.01 to the value of 0.6 as shown;
B = 0.6 + 0.01
B = 0.61
To get A, we will add 0.03 to 0.5 as shown:
A = 0.5 + 0.03
A = 0.53
To get the value of C, we will subtract 0.04 from 0.5
as shown:
C = 0.5 - 0.04
C =0.46
Hence A = 0.46, B = 0.61 and C = 0.46
please help me with geometry
Answer:
How to improve my geometry?
Part 1 of 3: Getting the Grade
Attend every class. Class is a time to learn new things and solidify the information that you may have learned in the previous class.
Draw diagrams. Geometry is the math of shapes and angles. ...
Form a study group. ...
Know how to use a protractor. ...
Do all of the assigned homework. ...
Teach the material. ...
Do lots of practice problems. ...
Seek extra help. ...
Step-by-step explanation:
If you wanted to make a game where you pay $5 if you can't guess a random dogs weight within 16lbs what payout should you offer you make the game zero-expected value
Answer:
Following are the solution to the given question:
Step-by-step explanation:
The population std. dev of the dog weight=8
[tex]\sigma=8\\\\P(\text{guess with in 16 lbs}) = P(|X-\mu|\leq 16)\\\\=P(-2 \leq Z \leq 2) = 0.9544\\\\[/tex]
Calculating the payout w s.t:
[tex]E[netpay]=0=(-5) \times 0.9544+w\times (1-0.9544)\\\\ w =(5 \times \frac{0.9544}{1-0.9544}) =\$ 104.65[/tex]
therefore, we assume that the weight of the dog is a normal distribution with std. deviation that is 8.
Find the missing numerator: 3 1/3 = x/6
[tex]\sf\huge\underline\color{pink}{༄Answer:}[/tex]
[tex]\tt3 \frac{1}{3} = \frac{x}{6} \\ = \tt \frac{10}{3} = \frac{x}{6} \\ = \tt \frac{x}{6} = \frac{10}{3} \\ = \tt6 \frac{x}{6} = 6( \frac{10}{3} ) \\ = \tt\large\boxed{\tt{\color{pink}{x = 20}}}[/tex]
[tex]\color{pink}{==========================}[/tex]
#CarryOnLearning
❤❤❤PLEASE BE RIGHT AND CORRECT BEFORE ANSWERING
Answer:
y=-x+28
Step-by-step explanation:
The slope(rise/run) is -1, and because it starts at y=28, the answer is y=-x+28
Answer:
"C"
The slope is -2 !!! delta y = 20 delta x = 10
the y intercept is 28
Step-by-step explanation:
X/6 - y/3 = 1
please explain in detail!
Answer:
x=12,y=3
Step-by-step explanation:
x/6-y/3=1
x can equal 12 because 12/6 is equal to 2.
y can equal 3 because 3/3 equals 1
2-1=1
Please help on 25 it’s confusing me I need the correct answer
Answer:
X * 0.8 = $64
x = $80
Step-by-step explanation:
Answer:
$80 (D)
Step-by-step explanation:
If Richard is getting a discount and his final price is $64 that means the answer must be above 64. That eliminates A, B, and C.
Use the formula: 20% of x = $64 and substitute the other two options. 20 percent of 84 is 16.8. 84-16.8=67.2 (not the correct answer). 20 percent of 80 is 16. 80-16=64(The Correct Answer).The answer must be $80 (D)
What fraction is equivalent to eight tentHs
What type(s) of symmetry does this figure have?
both rotational and reflectional
rotational
reflectional
This figure is not symmetrical
Answer:
The figure is not symmetrical
Answered by GAUTHMATH
A student found the solution below for the given inequality.Which of the following explains whether the student is correct?The student is completely correct because the student correctly wrote and solved the compound inequality.The student is partially correct because only one part of the compound inequality is written correctly.The student is partially correct because the student should have written the statements using “or” instead of “and.”The student is completely incorrect because there is “ no solution “ to this inequality.
Answer:
The student is completely incorrect because there is no solution to this inequality.
Answer:
D on edge
Step-by-step explanation:
Use the graph below to determine the equation of the circle in (a) center-radius form and (b) general form.
9514 1404 393
Answer:
(x +5)² +(y -3)² = 25x² +y² +10x -6y +9 = 0Step-by-step explanation:
The "center-radius" form is ...
(x -h)² +(y -k)² = r² . . . . . . . circle with center (h, k) and radius r
The graphed circle has its center at (-5, 3) and a radius of 5. Putting these numbers into the above form gives the equation ...
(x +5)² +(y -3)² = 25 . . . . center-radius form
Expanding the parentheses, we get ...
x² +10x +25 +y² -6y +9 = 25
Subtracting 25, and putting in general form, the equation becomes ...
x² +y² +10x -6y +9 = 0 . . . . general form
_____
Additional comment
General form is f(x, y) = 0, where the terms of f(x, y) are lexicographical order and decreasing degree.
Which one and what do I put in the box(s)
Answer:
Option A i the right option.
First blank is 110-[tex]10\sqrt{61}[/tex] or 10(11-[tex]\sqrt{61}[/tex])
Second blank is 31.898
Let me know if anything didn't make sense.
Step-by-step explanation:
So a diagonal through a rectangle makes two triangles. The question wants to know how much walking is saved walking down the diagonal vs walking along two sides that make the diagonal. in this case the two non diagonal sides walked are 60 paces and 50 paces.
A diagonal through a rectangle specifically makes a right triangle, so to find the diagonal we can use the pythagorean theorem.
c^2 = 60^2 + 50^2
c = [tex]\sqrt{60^2 + 50^2}[/tex]
c = [tex]\sqrt{6100} = 10\sqrt{61}[/tex]
if you don't get how to simplify a radical like that let me know.
Anyway, looking at the answers you can see right away the second option says no approximation is necessary. Well, you need to approximate square root of 61, so we can say the second answer is not right. So now we need to know what to fill in for option 1.
it wants the distance saved, well we know the distance of the diagonal is [tex]10\sqrt{61}[/tex] Hopefully you can see the disctance walking the two other sides is just adding them up so 50+60=110.
Now, to find the difference, that is subtraction. So subtract the smaller number from the larger number. You do need to remember with a right triangle, the sum of the to non diagonal (hypotenuse) sides are always longer than said hypotenuse. so that's 110-[tex]10\sqrt{61}[/tex]. That is the exact form. Or you could use 10(11-[tex]\sqrt{61}[/tex]) They are the same.
Then just plug that into a calculator for a decimal approximation.
Suppose that the probability that a person will develop hypertension over a life time is 60%. Of 13 graduating students from the same college are selected at random. find the mean number of the students who develop hypertension over a life time
Answer:
The mean number of the students who develop hypertension over a life time is 7.8.
Step-by-step explanation:
For each person, there are only two possible outcomes, either they will develop hypertension, or they will not. The probability of a person developing hypertension is independent of any other person, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
Suppose that the probability that a person will develop hypertension over a life time is 60%.
This means that [tex]p = 0.6[/tex]
13 graduating students from the same college are selected at random.
This means that [tex]n = 13[/tex]
Find the mean number of the students who develop hypertension over a life time
[tex]E(X) = np = 13*0.6 = 7.8[/tex]
The mean number of the students who develop hypertension over a life time is 7.8.
If
f (x) = 3x +1 and 1-1 = *?
then f-'(7) =
O 22
O-2
02
According to my calculations answer is -2
Which inequality is true?
O A. 1 2 > 2
OB. 8 - T > 5
O C. 1071 > 30
O D. 1+4<7
Answer:
true
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
A
[tex]\frac{12}{2\pi }[/tex] ≈ 1.91 < 2
B
8 - π 8 - 3.14 = 4.86 < 5
C
10π ≈ 31.42 > 30 ← True
D
π + 4 = 3.14 + 4 = 7.14 > 7
Option C is a true inequality
solve: x^2-x-12÷x+5 ≥ 0
Answer:
Step-by-step explanation:
x3−x2+5x−12
x
≥0
Let's find the critical points of the inequality.
x3−x2+5x−12
x
=0
x3−x2+5x−12=0(Multiply both sides by x)
(Use cubic formula)
x=1.836169
Check possible critical points.
x=1.836169(Works in original equation)
Critical points:
x=1.836169(Makes both sides equal)
x=0(Makes left denominator equal to 0)
Check intervals in between critical points. (Test values in the intervals to see if they work.)
x<0(Works in original inequality)
0<x≤1.836169(Doesn't work in original inequality)
x≥1.836169(Works in original inequality)
Answer:
x<0 or x≥1.836169
The cost, c, for mailing books is a function of the number of books, b. The
cost to mail books is $0.50 per book plus a $3.00 flat fee
Answer:
c = 3.00 + .50b
Step-by-step explanation:
The cost is the flat fee plus the cost per book times the number of books
c = 3.00 + .50b
Write the following as an expression: How much water do I need to add to l liters of pure alcohol to obtain a solution of 45% alcohol? The answer is an EXPRESSION, not an actual answer!! WILL MARK BRAINLIST!!!
Answer:
see below
Step-by-step explanation:
amount of water w
l liter of pure alcohol = 100% alcohol
solution is 45 % percent alcohol
total amount of fluid is w+l
(w+l)( .45) = l*.100
Distribute
.45w + .45 l = 1l
.45 w = 1l - .45l
.45 w = .55l
w = .55l / .45
w =11/9 l
any polynomial of degree 2 can have at most two zero is
true and false
Answer:
True
Step-by-step explanation:
Answer is true, the degree of a function tells you at most how many zeroes the function can have.
Point-Slope Form of a Line
Write an expression for the baseball team’s Purchase.
