We have that 2a+1=1 and b-a=1. What is the value of b?

Answer:

£4.50

Step-by-step explanation:

She is at the car park for 2 hours and 30 minutes.

It would be £4.50 because 2 hours and 30 minutes is between 2-4 hours.

It can't be £3.00 because it would be too little time (2 hours or less) and it wouldn't be £5.50 because she would be paying for more time than she was there for (5 hours or more).

Hope this helps :)

Answer:

16

Step-by-step explanation:

volume= Length x width x height

Answer:

Volume: [tex]1/3\times Area\; of\; base\;\times height[/tex]

[tex]= 1/3\times2\times 2\times 4[/tex]

[tex]=16/3\; ft^{3}[/tex]

[tex]=5.3\; ft^{3}[/tex]

OAmalOHopeO

Answer:

$ 12.16

Step-by-step explanation:

Spent = $ 37.84

Paid = $ 50

Change = $50 - $37.84

Change = $ 12.16

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

$12.16

Step-by-step explanation:

You must subtract his total from his payment. $50-$37.84=$12.16

Answer:

3[tex]\sqrt{10}[/tex]

Step-by-step explanation:

Assuming you mean [tex]\sqrt{90}[/tex]

Using the rule of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex] , then

[tex]\sqrt{90}[/tex]

= [tex]\sqrt{9(10)}[/tex]

= [tex]\sqrt{9[/tex] × [tex]\sqrt{10}[/tex]

= 3[tex]\sqrt{10}[/tex]

9514 1404 393

Answer:

Step-by-step explanation:

"No more than 21" means "less than or equal to 21." The total of flowers Lydia has listed is ...

  8 + 2 + t + 3 + p = 13 +p +t

Lydia wants this less than or equal to 21, so the appropriate inequality is ...

  13 +p +t ≤ 21

__

Subtracting 13 from both sides gives us a relation that helps us better see the possible values of p and t.

  p +t ≤ 8

Then suitable numbers of peonies and tulips will numbers that total 8 or less. Of the choices listed, ones that match that requirement are ...

  2 tulips and 3 peonies

  5 tulips and 3 peonies

[tex]Here, h=41,0.25,y=1+x21

[/tex]

[tex]x     y101.020.25     0.9413 0.250.94140.750.64510.5

[/tex]

[tex]By Simpson's Rule:

[/tex]

[tex]∫011+x2dx=4×31

[/tex]

[tex][(1+0.5)+4(0.941+0.941+0.64)+2(0.8)]

[/tex]

[tex]=121[9.424]=0.785

[/tex]

Answer:

missing side length is 12

Step-by-step explanation:

similar means that all correlating pairs of sides have the same ratio (old side length) / (new side length).

so, when we know the ratio of one pair, we can apply it to any other side to calculate the correlating side.

we see, when we go from small to large, that we have the ratio 32/40 = 4/5.

so, multiplying the larger side by this, we get the shorter side.

15 × 4/5 = 3 × 4 = 12

the proportion part in your picture is a bit confusing :

yes,

x/15 = 32/40 = 32/40

I don't know, why this last expression was repeated.

x/15 = 32/40

x = 15×32/40 = 15×4/5 = 3×4 = 12

as you see we get of course the same result doing it that way.

(3a^4b/2b^3)^3

cube all the terms:

3^3 = 27

b^3

(a^4)^3 = a^(4*3) = a^12

2^3 = 8

(b^3)^3 = b^3*3 = b^9

27a^12b^3 / 8b^9

Divide the b terms to get the final answer:

27a^12 / 8b^6

Answer:

7 quarts

Step-by-step explanation:

total paint = paint used + paint left

total paint = 2 +5

total paint 7

Answer:

see below

Step-by-step explanation:

fx=x^2+2x+3​

This is a parabola that opens upward

f(x) = (x^2 +2x)+3

     = (x^2+2x+1) +3-1

   = (x+1)^2 +2

This is in vertex form  y =a(x-h)^2 +h where the vertex is (h,k)

This has a vertex as (-1,2)

And has a y intercept at (0,3)

this does not cross the x axis

Answer:

Step-by-step explanation:

It's the first / top most option. This is because n < -3 means the variable n is less than 3. It's also the open circle because the less than symbol is not underlined. Hope this helps!

Answer:

11980

Step-by-step explanation:

This is simple interest.

We use the formula i=prt. Interest = price x rate x time

You just plug in your numbers, 10000 is your price, 5.5 years is the time, and 3.6% interest is rate.

Now our equation looks like this: i = 10000 x 5.5 x 0.036

(i converted the percent to a decimal)

So the interest is 1980, but the question asks for the final value, so we add the interest to the initial deposit, 1980 + 10000, and we get 11980 for our final value.

I apologize if my answer is wrong, but if it isn't I hope I helped :)

9514 1404 393

Answer:

  $12,190

Step-by-step explanation:

The formula for the balance in an account where continuous compounding occurs is ...

  A = Pe^(rt) . . . . where P is the principal invested at annual rate r for t years

  A = $10,000e^(0.036·5.5) = $10,000e^0.198

  A ≈ $12189.62 ≈ $12,190 . . . . rounded to the nearest dollar

Answer: All real numbers

Step-by-step explanation:

Let's find the critical points of the inequality.

2y2+1=

−9

5

y−6

2y2+1−(

−9

5

y−6)=

−9

5

y−6−(

−9

5

y−6)(Subtract (-9)/5y-6 from both sides)

2y2+

9

5

y+7=0

For this equation: a=2, b=1.8, c=7

2y2+1.8y+7=0

y=

−b±√b2−4ac

2a

(Use quadratic formula with a=2, b=1.8, c=7)

y=

−(1.8)±√(1.8)2−4(2)(7)

2(2)

y=

−1.8±√−52.76

4

since it was too long, I just made this python code in order to solve for it:

from math import *

data = [35, 27, 24, 42, 25, 31, 41, 34, 32, 46, 29, 44, 29, 35, 39, 27, 41, 63, 52, 31, 38, 46, 39, 27, 58, 32, 33, 47, 36, 28, 65, 53, 40, 32, 39, 44, 48, 59, 46, 62, 22, 39, 35, 29, 36, 66, 33, 45, 50, 62, 27, 27, 41, 33, 54, 44, 26, 31, 45, 33, 42, 63, 51, 70, 42, 53, 38, 28, 35, 49, 47, 54, 44, 40, 39, 62, 30, 35, 38, 26, 34, 61, 19, 30, 34, 26, 41, 35, 26, 54, 28, 32, 50, 27, 31, 35, 38, 26, 47, 30, 28, 62, 57, 56, 30, 32, 31, 36, 32, 42, 33, 51, 35, 30, 28, 20, 23, 27, 33, 36, 35, 42, 43, 28, 36, 44, 58, 41, 36, 37, 49, 34, 23, 39, 34, 37, 62, 23, 28, 26, 29, 30, 37, 46, 43, 56, 53, 31, 36, 44, 39, 51, 21, 51, 34, 30, 25, 31, 38, 52, 49, 43, 50, 31, 36, 32, 28, 44, 61, 57, 24, 63, 28, 31, 32, 26, 28]

def stand_dev(list_n):

x = 0

sum_num = 0

for x in list_n:

sum_num += list_n[x]

sum_of_n = sum_num

mean = float(sum_of_n / len(list_n))

float(mean)

i = 0

e = 0.0

for i in list_n:

subtract_then_square = (list_n[i] - mean)**2

e += subtract_then_square

result1 = e

new_mean = result1 / len(list_n)

final_result = float(sqrt(new_mean))

return final_result

print(stand_dev(data))

basically, the first chunk of the code calculated the mean of the data. The second chunk would take all of the values from the data, subtract it from the mean, and then square it. I then took the sum of all the new values and average it to get the new mean, then square rooted the new mean to get the answer.

it should be ~= 11.713, but you can always check it by searching up a python compiler online and then insert in the data.

Answer:

I used MS excel and got the attached results.

Note the data is sorted and the data size is 177.

The answer I got is 11.31045226

Answer:

$275 a month

Step-by-step explanation:

Let x represent how much each friend is paying.

The amount Jane pays can be represented by 2x, since she is paying double than her friends.

Add together these terms and set them equal to 550. Then, solve for x:

x + x + 2x = 550

4x = 550

x = 137.5

So, each friend is paying $137.50. Double this to find how much Jane is paying:

137.5(2)

= 275

So, Jane is paying $275 a month

A stationary point at x = 3 means the derivative dy/dx = 0 at that point. Differentiating, we have

dy/dx = 6x ² + 2ax + b

and so when x = 3,

0 = 54 + 6a + b

or

6a + b = -54 … … … [eq1]

The curve passes through the point (4, 2), which is to say y = 2 when x = 4. So we also have

2 = 128 + 16a + 4b - 30

or

16a + 4b = -96

4a + b = -24 … … … [eq2]

Eliminate b by subtracting [eq2] from [eq1] and solve for a, then for b :

(6a + b) - (4a + b) = -54 - (-24)

2a = -30

a = -15   ===>   b = 96

Step-by-step explanation:

=14×(8×2)

=14(16)

=224

Answer:

[tex]y=4x[/tex]

Answer:

y = -4x

hope that helped.........

Answer:

i will say methods try yourself:

How to Determine Maximum Value

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).The first step is to determine whether your equation gives a maximum or minimum. ...

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).The first step is to determine whether your equation gives a maximum or minimum. ...-x2 + 4x - 2.

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).The first step is to determine whether your equation gives a maximum or minimum. ...-x2 + 4x - 2.Since the term with the x2 is negative, you know there will be a maximum point.

.

.

.

.

plzz follow and make brainlist

Answer:

hahahahahahahahahahhahahahahhahahahahhahagagagaggagagagahhahahahahha

Answer:

37

Step-by-step explanation:

Tan(B) = 6/8

B= arctan(3/4)=37

We are given the equations:

x - 3y = 2

3x - 4y = 0

writing the system as matrices

[tex]\left[\begin{array}{ccc}1&-3\\3&-4\end{array}\right][/tex][tex]\left[\begin{array}{ccc}x\\y\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}2\\0\\\end{array}\right][/tex]

which is in the form:

AX = B

solving for X(the matrix holding the variables), we get:

X = (A⁻¹)B

Finding A⁻¹:

now, to do this, we need to find the inverse of A

[tex]\left[\begin{array}{ccc}w&x\\y&z\end{array}\right]^{-1} = \frac{1}{wz-xy}\left[\begin{array}{ccc}z&-x\\-y&w\end{array}\right][/tex]

using this formula to find the inverse of matrix A:

[tex]A^{-1} = \frac{1}{(1*-4)-(-3*3)}\left[\begin{array}{ccc}-4&3\\-3&1\end{array}\right][/tex]

[tex]A^{-1} = \frac{1}{5}\left[\begin{array}{ccc}-4&3\\-3&1\end{array}\right][/tex]

Matrix X:

We know that:

X = A⁻¹B

[tex]X = \frac{1}{5}\left[\begin{array}{ccc}-4&3\\-3&1\end{array}\right] * \left[\begin{array}{ccc}2\\0\end{array}\right][/tex]

[tex]X = \frac{1}{5}\left[\begin{array}{ccc}-8\\-6\end{array}\right][/tex]

since matrix X is just a matrix with the variables

[tex]\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}\frac{-8}{5}\\\frac{-6}{5}\end{array}\right][/tex]

x = -8/5

y = -6/5

Answer:

e = 44/5 = 8.800

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    e/22-(6/15)=0

Step by step solution :

STEP

1

:

           2

Simplify   —

           5

Equation at the end of step

1

:

  e    2

 —— -  —  = 0

 22    5

STEP

2

:

            e

Simplify   ——

           22

Equation at the end of step

2

:

  e    2

 —— -  —  = 0

 22    5

STEP

3

:

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       22

     The right denominator is :       5

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 1 0 1

11 1 0 1

5 0 1 1

Product of all

Prime Factors  22 5 110

     Least Common Multiple:

     110

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 22

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      e • 5

  ——————————————————  =   —————

        L.C.M              110

  R. Mult. • R. Num.      2 • 22

  ——————————————————  =   ——————

        L.C.M              110  

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

e • 5 - (2 • 22)     5e - 44

————————————————  =  ———————

      110              110  

Equation at the end of step

3

:

 5e - 44

 ———————  = 0

   110  

STEP

4

:

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 5e-44

 ————— • 110 = 0 • 110

  110

Now, on the left hand side, the  110  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  5e-44  = 0

Solving a Single Variable Equation:

4.2      Solve  :    5e-44 = 0

Add  44  to both sides of the equation :

                     5e = 44

Divide both sides of the equation by 5:

                    e = 44/5 = 8.800

One solution was found :

e = 44/5 = 8.800

Answer:

e =44/5

Step-by-step explanation:

e          6

----- = --------

22         15

Using cross products

e * 15 = 6 *22

15e = 132

Divide by 15

15e/15 = 132/15

e =44/5

Answer:

y=3x

Step-by-step explanation:

-6/-2=3, -3/-1=3, 3/1=3. 6/2=3

Answer:

Step-by-step explanation:

Consider principle =Rs.P, Time (T)=4 years

Consider principle =Rs.P, Time (T)=4 yearsRate =6

Consider principle =Rs.P, Time (T)=4 yearsRate =6 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P×

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =4000

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200Therefore, Principle =Rs.3200

Answer:

-33

Step-by-step explanation:

-p/3-8=3

or,(-p-24)/3=3

or,(-p-24)=9

or,-p=33

Therefore, p=-33

9514 1404 393

Answer:

  6

Step-by-step explanation:

The compound interest formula tells you the future value of principal P invested at annual rate r compounded n times per year for t years is ...

  A = P(1 +r/n)^(nt)

Solving for t, we get ...

  t = log(A/P)/(n·log(1 +r/n))

Using the given values, we find t to be ...

  t = log(38302/32000)/(12·log(1 +0.03/12)) ≈ 5.9997

The investment was for 6 years.

Answer:

[tex]\frac{7}{2\sqrt{2} }[/tex]

Step-by-step explanation:

substitute 2 in for x. the square root of 2 is already in radical form

Answer:

36

Step-by-step explanation:

3² = 9.

So, the perimeter is 9(4) = 36