Two thirds of the students in a class have pets. There are
36 students in the class. How many of the students have pets?

Answer:

532

A

Step-by-step explanation:

A=86

B=180

C=94

D=266

now,

a+b+c+d_94

=86+180+94+266_94

=532

Answer:

[tex]x=-\frac{11}{8}[/tex]

Step-by-step explanation:

Hi there!

[tex](x - 4) - (x + 7) = 8x[/tex]

Open up the parentheses

[tex]x - 4 - x - 7 = 8x[/tex]

Combine like terms

[tex]x -x - 4 - 7 = 8x\\-4-7=8x\\-11=8x[/tex]

Divide both sides by 8 to isolate [tex]x[/tex]

[tex]-\frac{11}{8}=x[/tex]

I hope this helps!

Answer:

y = -2x +13

Step-by-step explanation:

you know the point is (5,3) and slope is -2

sub into the linear equation y=mx+b

3 = -2(5) +b

rearrange and solve for b

b= 3 + 10

b = 13

Answer:

64percents

Step-by-step explanation:

25-9=16 grams - weight of copper

(16/25)*100=64 percents

Answer:

18 feet

Step-by-step explanation:

To convert : multiply the length value by 3

=> 6 x 3

=> 18 feet

Answer:

x=5.5

Step-by-step explanation:

Perimeter of ABCD=85

The perimeter is everything around the outside added together.

Form an equation:

3x+4+4x+6x-11+5x-7=85

Collect the like terms:

Like terms are terms that have the same powers and coefficient.

3x+4x+6x+5x=18x

4-11-7= -14

Put it back into an equation:

18x-14=85

Do inverse operations to find out what x is:

85+14=99

18x=99

99÷18=5.5 (we divide because, in algebra, when a number is next to a letter, it means times and as we want the inverse, you would have to divide)

x=5.5

Hope this helps :)

Answer:

5

Step-by-step explanation:

Use pythagorean theorem. A^2+B^2=C^2

13 is c because it is the hypotenuse and across from the right angle

a is unknown and b is 12

A^2+12^2=13^2

A^2 +144 = 169

A^2 = 169- 144

A^2= 25

now take the sq root of both side

A = 5

Answer:

17.7

Step-by-step explanation:

Answer:

x=4,  -5

Step-by-step explanation:

Factor and set each factor equal to zero

Answer:

X = -4 , x= 4

Step-by-step explanation:

20=x^2-x=0

-20+x^2+x=0

x^2+x-20=0

x×(x+5)-4(x+5)=0

(x+5)×(x-4)=0

x+5=0

×-4=0

x=-5

x=4

Answer:

x = 67°

Step-by-step explanation:

The 2 base angles x are congruent , then

x = [tex]\frac{180-46}{2}[/tex] = [tex]\frac{134}{2}[/tex] = 67°

Answer:

X= 67 degrees.

Step-by-step explanation:

All triangles must add up to 180°. This is an isosceles triangle which means once you have one degree you can find the other two.

In order to get the answer start with 180°-46°

180-46=134

The two x's equal each other. So you can divide the remaining degrees by 2 to get the answer.

134÷2=67.

So the answer is 67°.

Answer:

550

Step-by-step explanation:

To round 553 to the tens place, we would need to identify the value of the digit in the ones place.

If the digit in the ones place is greater than 5, we increase the tens place by 1 & convert the ones place into a 0.

If not, we leave the tens place as is & convert the ones place into a 0.

Since 3 is less than 5, we round 553 to 550 so you are correct.

Answer:

Yes

550 has 2 sig figs

553 has 3

Step-by-step explanation:

Work Shown:

tan(angle) = opposite/adjacent

tan(x) = 17/29

x = arctan(17/29)

x = 30.379 which is approximate

x = 30

Side note: arctan is the same as inverse tangent [tex]\tan^{-1}[/tex]

Answer:

ab+bc+ac=47

Step-by-step explanation:

(a+b+c)=12

Square both sides

a^2+b^2+c^2+2(ab+bc+ac)=144

2(ab+bc+ac)=94

ab+bc+ac=47

Answer:

ab + bc + ca = 47

Step-by-step explanation:

Using the algebraic identity

(a + b + c) = a² + b² + c² + 2(ab + bc + ca) , then

12² = 50 + 2(ab + bc + ca)

144 = 50 + 2(ab + bc + ca) ← subtract 50 from both sides

94 = 2(ab + bc + ca) ← divide both sides by 2

47 = ab + bc + ca

Step-by-step explanation:

Answer 1

x+x+y+3y+z+2z

2x+4y+3z

Answer 2

2x+4y+3z

( no like terms are there so it cannot be added)

Answer 3

9xyz

last two answers will also be similar as the question because unlike terms cannot be added..

Hey there!

I believe your answer would be a transformation, and not a translation.

A transformation is an operation that moves, flips, or otherwise changes a figure to create a new figure.

Hope this helps!

Have a wonderful day! :)

Answer:

The name of the given figure in two different ways are - J⇔U and U⇔J

Answer:

c  a = 2.4b

Step-by-step explanation:

y = kx is the form of the equation where k is the constant of proportionality

y and x can be any letters

Replacing y and x with a and b  and k with 2.4

a = 2.4b

Answer:

6ft by 8ft

Step-by-step explanation:

12 / 2 is 6 and 16 / 2 is 8

Answer:

140

Step-by-step explanation:

Left column = x

Right column = y

Rule = 3.5x = y

Because 42/12 = 3.5

3.5 * 40 = 120 + 20 = 140

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

proportion

Step-by-step explanation:

In a proportion, the means or the extremes (or both) may be interchanged. In proportion, the product of the means equals the product of the extremes.

hope it helps :)

mark brainliest!

Answer:

348

Step-by-step explanation:

Volume = Area of cross section x height

Area of cross section = 1/2bh

1/2 (12x5.8) = 34.8

34.8 x 10 = 348

Volume = 348km^3

Answered by g a u t h m a t h

X - 3/8 = 13/2

Add 3/8 to both sides:

X = 13/2 + 3/8

Rewrite 13/2 to have 8 as the denominator:

13/2 x 4 = 52/8

X = 52/8 + 3/8

X = 55/8

Answer:

55/8

Step-by-step explanation:

Add 3/8 to both sides

X - 3/8 = 13/2

X = 13/2 + 3/8

make sure the denominators are equal so we can add. so multiply 4/4 by 13/2 and that equals 52/8

X = 52/8+3/8

X= 55/8

Answer:

[tex]28.07^{\circ}[/tex]

Step-by-step explanation:

We can use basic trig. for a right triangle to solve this problem. In any right triangle, the tangent of an angle is equal to its opposite side divided by the hypotenuse (longest side) of the triangle.

The right triangle we're looking at involves the two dotted lines and an edge of the prism.

The bottom dotted line is a diagonal of the rectangular base of the prism. We can use the Pythagorean Theorem to find its length.

The Pythagorean Theorem states that for any right triangle, [tex]a^2+b^2=c^2[/tex], where [tex]a[/tex] and [tex]b[/tex] are the two legs of the triangle and [tex]c[/tex] is the hypotenuse.

In this case, the two legs are 9 and 12 and we are solving for [tex]c[/tex]:

[tex]9^2+12^2=c^2,\\81+144=c^2,\\225=c^2,\\c=15[/tex]

This is theta's adjacent side. Its opposite side is an edge of the prism labelled as 8 inches. Therefore, we have the following equation:

[tex]\tan \theta = \frac{8}{15}[/tex]

Take the inverse tangent of both sides:

[tex]\arctan(\tan \theta)=\arctan(\frac{8}{15})[/tex]

Simplify using [tex]\arctan(\tan\theta)=\theta, \theta \in (-90^{\circ}, 90^{\circ})[/tex]:

[tex]\theta=\arctan(\frac{8}{15}),\\\theta=28.07248694\approx \boxed{28.07^{\circ}}[/tex]

Answer:

4

Step-by-step explanation:

ln(e)=1 since ln= log_e

log(x^y)=y*log(x) so ln(e^4)=4*ln(4)=4*1=4

Answer:

D

Step-by-step explanation:

ln(e^4)

The 4 comes down in front of the natural log (ln). You get 4 ln(e)

The natural log of e (ln e )  is 1.

So the answer is 4 * 1 = 4

That may not be clear to you. We could try it another way.

e = 2.718281828

ln (2.718281828) = 1

ln(2.718281828)^4 = 4.  The calculator gags until you get it right.  You need the y^x key (or the x^y key of ^) It does come back with 4.

You have to monkey around with the calculator to get this to happen.  

Answer:

Step-by-step explanation:

y=3(x−3)^2+75

Answer:

(x - 3)² = - 25

Step-by-step explanation:

Given

- 3x² = - 18x + 102 ( add 18x to both sides )

- 3x² + 18x = 102 ( divide through by - 3 )

x² - 6x = - 34

To complete the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(- 3)x + 9 = - 34 + 9

(x - 3)² = - 25

The solution to each of the question takes different approach, as the questions are taken from different concepts; however, a common operation among all questions, is factorization.

[tex](1)\ (-xy)^3(xz)[/tex]

Expand

[tex](-xy)^3(xz) = (-x)^3* y^3*(xz)[/tex]

[tex](-xy)^3(xz) = -x^3* y^3*xz[/tex]

Rewrite as:

[tex](-xy)^3(xz) = -x^3*x* y^3*z[/tex]

Apply law of indices

[tex](-xy)^3(xz) = -x^4y^3z[/tex]

[tex](2)\ (\frac{1}{3}mn^{-4})^2[/tex]

Expand

[tex](\frac{1}{3}mn^{-4})^2 =(\frac{1}{3})^2m^2n^{-4*2}[/tex]

[tex](\frac{1}{3}mn^{-4})^2 =\frac{1}{9}m^2n^{-8[/tex]

[tex](3)\ (\frac{1}{5x^4})^{-2}[/tex]

Apply negative power rule of indices

[tex](\frac{1}{5x^4})^{-2}= (5x^4)^2[/tex]

Expand

[tex](\frac{1}{5x^4})^{-2}= 5^2x^{4*2}[/tex]

[tex](\frac{1}{5x^4})^{-2}= 25x^{8[/tex]

[tex](4)\ -x(2x^2 - 4x) - 6x^2[/tex]

Expand

[tex]-x(2x^2 - 4x) - 6x^2 = -2x^3 + 4x^2 - 6x^2[/tex]

Evaluate like terms

[tex]-x(2x^2 - 4x) - 6x^2 = -2x^3 -2x^2[/tex]

Factor out x^2

[tex]-x(2x^2 - 4x) - 6x^2 = (-2x-2)x^2[/tex]

Factor out -2

[tex]-x(2x^2 - 4x) - 6x^2 = -2(x+1)x^2[/tex]

[tex](5)\ \sqrt{\frac{4y}{3y^2}}[/tex]

Divide by y

[tex]\sqrt{\frac{4y}{3y^2}} = \sqrt{\frac{4}{3y}}[/tex]

Split

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{\sqrt{4}}{\sqrt{3y}}[/tex]

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2}{\sqrt{3y}}[/tex]

Rationalize

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2}{\sqrt{3y}} * \frac{\sqrt{3y}}{\sqrt{3y}}[/tex]

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2\sqrt{3y}}{3y}[/tex]

[tex](6)\ \frac{8}{3 + \sqrt 3}[/tex]

Rationalize

[tex]\frac{8}{3 + \sqrt 3} = \frac{3 - \sqrt 3}{3 - \sqrt 3}[/tex]

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{(3 + \sqrt 3)(3 - \sqrt 3)}[/tex]

Apply difference of two squares to the denominator

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{3^2 - (\sqrt 3)^2}[/tex]

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{9 - 3}[/tex]

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{6}[/tex]

Simplify

[tex]\frac{8}{3 + \sqrt 3} = \frac{4(3 - \sqrt 3)}{3}[/tex]

[tex](7)\ \sqrt{40} - \sqrt{10} + \sqrt{90}[/tex]

Expand

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =\sqrt{4*10} - \sqrt{10} + \sqrt{9*10}[/tex]

Split

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =\sqrt{4}*\sqrt{10} - \sqrt{10} + \sqrt{9}*\sqrt{10}[/tex]

Evaluate all roots

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =2*\sqrt{10} - \sqrt{10} + 3*\sqrt{10}[/tex]

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =2\sqrt{10} - \sqrt{10} + 3\sqrt{10}[/tex]

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =4\sqrt{10}[/tex]

[tex](8)\ \frac{r^2 + r - 6}{r^2 + 4r -12}[/tex]

Expand

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r^2 + 3r-2r - 6}{r^2 + 6r-2r -12}[/tex]

Factorize each

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r(r + 3)-2(r + 3)}{r(r + 6)-2(r +6)}[/tex]

Factor out (r+3) in the numerator and (r + 6) in the denominator

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{(r -2)(r + 3)}{(r - 2)(r +6)}[/tex]

Cancel out r - 2

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r + 3}{r +6}[/tex]

[tex](9)\ \frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14}[/tex]

Cancel out x

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x^2 - 5x - 14}[/tex]

Expand the numerator of the 2nd fraction

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x^2 - 7x+2x - 14}[/tex]

Factorize

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x(x - 7)+2(x - 7)}[/tex]

Factor out x - 7

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{(x + 2)(x - 7)}[/tex]

Factor out 4 from 4x + 8

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4(x + 2)}{x} \cdot \frac{1}{(x + 2)(x - 7)}[/tex]

Cancel out x + 2

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4}{x} \cdot \frac{1}{(x - 7)}[/tex]

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4}{x(x - 7)}[/tex]

[tex](10)\ (3x^3 + 15x^2 -21x) \div 3x[/tex]

Factorize

[tex](3x^3 + 15x^2 -21x) \div 3x = 3x(x^2 + 5x -7) \div 3x[/tex]

Cancel out 3x

[tex](3x^3 + 15x^2 -21x) \div 3x = x^2 + 5x -7[/tex]

[tex](11)\ \frac{m}{6m + 6} - \frac{1}{m+1}[/tex]

Take LCM

[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m(m + 1) - 1(6m + 6)}{(6m + 6)(m + 1)}[/tex]

Expand

[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m^2 + m- 6m - 6}{(6m + 6)(m + 1)}[/tex]

[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m^2 - 5m - 6}{(6m + 6)(m + 1)}[/tex]

[tex](12)\ \frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}}[/tex]

Rewrite as:

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} \div \frac{2}{y^2 - 9}[/tex]

Express as multiplication

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{y^2 - 9}{2}[/tex]

Express y^2 - 9 as y^2 - 3^2

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{y^2 - 3^2}{2}[/tex]

Express as difference of two squares

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{(y - 3)(y+3)}{2}[/tex]

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{1} * \frac{(y+3)}{2}[/tex]

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{y+3}{2}[/tex]

Read more at:

https://brainly.com/question/4372544

Answer:

[tex]we \: know \: that \: commutative \: prop \\ = x + y = y + x \\ then \\ 4xy + 0 = 0 + 4xy \\ thank \: you[/tex]

Answer:

Option A, 90

Step-by-step explanation:

105×2-120

= 210-120

= 90