Answer:
6/5
Explanation:
Step 1
Multiply the denominator by the whole number
5 × 1 = 5
Step 2
Add the answer from Step 1 to the numerator
5 + 1 = 6
Step 3
Write answer from Step 2 over the denominator
6/5I hope this answer helps you out! Brainliest would be appreciated.Which best describes the relationship between the line that passes through the points (-6,5) and (-
2,7) and the line that passes through the points (4, 2) and (6, 6)?
Answer:
Slope passes through (-6, 5) and (-2, 7)
[tex]m_1=\frac{y_2-y_1}{x_2-x_1} =m_1=\frac{7-5}{-2+6}[/tex]
[tex]m_1=\frac{2}{4} =\frac{1}{2}[/tex]
Slope passes through (4, 2) and (6, 6)
[tex]m_2=\frac{6-2}{6-4}[/tex]
[tex]\frac{4}{2} =2[/tex]
[tex]m_1\times m_2 \neq -1[/tex] [tex]m_1\neq m_2[/tex]
Answer:- A) neither perpendicular nor parallel.
OAmalOHopeO
5 A machine puts tar on a road at the rate of 4 metres in 5 minutes.
a) How long does it take to cover 1 km of road
b) How many metres of road does it cover in 8 hours?
Answer:
5 a) Total = 20.83 hrs = 20 hrs and 50 mins (1250mins total)
5 b) Total = 96 meters. = 0.096km in 8 hrs.
Step-by-step explanation:
1km = 1000 meters
5 mins = 4 meters
1000/4 = 250 multiplier
250 x 5mins = 1250 minutes
1250/60 = 20hrs + 50 minutes
50 / 60 = 0.83 = 20.83hrs
b) 8 hrs = 8 x 60 = 480 minutes
480/5 = 24 multiplier of 4 meters
24 x 4 = 96 meters
Sequence of transformation that take the graph y=x^2 to y=-2(x-5)^2+4
Answer:
(x-5) so translated 5 units to the right
Multiplied with 2, p vertically compressed
+4 means translated 4 units up
A 7% acid solution will be mixed with a 15% acid solution. 20 L of a 12% acid solution needs to be made.
Identify the two variables in the problem by completing the following statements: * Let r represent: Let y represent:
Answer:
Let r = amount of the 7% solution
y represent the amount of the 15 percent solution
r =7.5 L
y = 12.5 L
Step-by-step explanation:
Let r = amount of the 7% solution
y represent the amount of the 15 percent solution
.07r + .15 y = (r+y) .12
r+y = 20
y = 20-r
.07r + .15 (20-r) = (20) .12
0.07r+0.15(20-r)=2.4
.07r+ 3 - .15r = 2.4
-.08r = 2.4-3
-.08r = -.6
Divide by-.08
r =7.5
y = 20-7.5
y = 12.5
How do u do this I don’t understand pls and thanks
Answer: Look it up on internet
Step-by-step explanation: INTERNET
Use the numbers 6 2 9 5 2 3
to make 36.
Answer:
6+2+9+5+2+3+6+3 = 36
Step-by-step explanation:
If you like my answer than please mark me brainliest
The graph below represents which of the following functions?
Answer:
D
Step-by-step explanation:
The correct answer is D, try graphing them on desmos.
Consider the following.
3^5x − 1 = 7
(a) Find the exact solution of the exponential equation in terms of logarithms.
(b) Use a calculator to find an approximation to the solution rounded to six decimal places.
Answer:
Step-by-step explanation:
You've typed the equation incorrectly. 3^5x-1 = 3⁵x-1.
It needs to be typed as 3^(5x-1) = 7.
An object is moving at a speed of 5 kilometers every 4.5 hours. Express this speed in miles per minute
Answer:
Step-by-step explanation:
1 km = 0.621 mi
1 hr = 60 min
(5 km)/(4.5 hr) × (0.621 mi)/km × (1 hr)/(60 min) = (0.0115 mi)/min
Find the least common multiple of 14 and 22.
6 x ____ = 9
6 times what number equals 9
Answer:
3/2
Step-by-step explanation:
6 * _x___ = 9
Divide each side by 6
6 x __x__ = 9
x = 9/6
Simplify
x = 3/2
Answer:
1.5
Step-by-step explanation:
Well, in this form you'd multiply 1 and .5 by 6 separately and then add them together. This makes 1*6 = 6 and 0.5*6=3, add them together and you get 9.
Cho A=( căn x -4x /1-4x -1) : (1+2x/1-4x -2căn x/ 2căn x -1 -1)
Answer:
0.85714285714286 x 100 = 85.7143%.
Step-by-step explanation:
Find the reflection of the point (x,y) in the line y=mx+c
Answer:
[tex]\displaystyle \left(\frac{-(m^{2}-1)\, x + 2\, m\, y - 2\, m \, c}{m^{2} + 1},\, \frac{(m^{2} - 1)\, y + 2\, m \, x + 2\, c}{m^{2} + 1}\right)[/tex].
Step-by-step explanation:
Consider the line that is perpendicular to [tex]y = m\, x + c[/tex] and goes through [tex](x,\, y)[/tex].
Both [tex](x,\, y)[/tex] and the reflection would be on this new line. Besides, the two points would be equidistant from the intersection of this new line and line [tex]y = m\, x + c[/tex].
Hence, if the vector between [tex](x,\, y)[/tex] and that intersection could be found, adding twice that vector to [tex](x,\, y)\![/tex] would yield the coordinates of the reflection.
Since this new line is perpendicular to line [tex]y = m\, x + c[/tex], the slope of this new line would be [tex](-1/m)[/tex].
Hence, [tex]\langle 1,\, -1/m\rangle[/tex] would be a direction vector of this new line.
[tex]\langle m,\, -1\rangle[/tex] (a constant multiple of [tex]\langle 1,\, -1/m\rangle[/tex] would also be a direction vector of this new line.)
Both [tex](x,\, y)[/tex] and the aforementioned intersection are on this new line. Hence, their position vectors would differ only by a constant multiple of a direction vector of this new line.
In other words, for some constant [tex]\lambda[/tex], [tex]\langle x,\, y \rangle + \lambda\, \langle m,\, -1 \rangle = \langle x + \lambda \, m,\, y - \lambda \rangle[/tex] would be the position vector of the reflection of [tex](x,\, y)[/tex] (the position vector of [tex](x,\, y)\![/tex] is [tex]\langle x,\, y \rangle[/tex].)
[tex]( x + \lambda \, m,\, y - \lambda )[/tex] would be the coordinates of the intersection between the new line and [tex]y = m\, x + c[/tex]. [tex]\lambda\, \langle m,\, -1 \rangle[/tex] would be the vector between [tex](x,\, y)[/tex] and that intersection.
Since that intersection is on the line [tex]y = m\, x + c[/tex], its coordinates should satisfy:
[tex]y - \lambda = m\, (x + \lambda \, m) + c[/tex].
Solve for [tex]\lambda[/tex]:
[tex]y - \lambda = m\, x + m^{2}\, \lambda + c[/tex].
[tex]\displaystyle \lambda = \frac{y - m\, x - c}{m^{2} + 1}[/tex].
Hence, the vector between the position of [tex](x,\, y)[/tex] and that of the intersection would be:
[tex]\begin{aligned} & \lambda\, \langle m,\, -1 \rangle \\= \; & \left\langle \frac{m\, (y - m\, x - c)}{m^{2} + 1},\, \frac{(-1)\, (y - m\, x - c)}{m^{2} + 1}\right\rangle \\ =\; &\left\langle \frac{-m^{2}\, x + m\, y - m\, c }{m^{2} + 1},\, \frac{-y + m\, x + c}{m^{2} + 1}\right\rangle \end{aligned}[/tex].
Add twice the amount of this vector to position of [tex](x,\, y)[/tex] to find the position of the reflection, [tex]\langle x,\, y \rangle + 2\, \lambda \,\langle m,\, -1 \rangle[/tex].
[tex]x[/tex]-coordinate of the reflection:
[tex]\begin{aligned} & x + 2\, \lambda\, m \\ = \; & x + \frac{-2\, m^{2}\, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1} \\ =\; & \frac{-(m^{2} - 1) \, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].
[tex]y[/tex]-coordinate of the reflection:
[tex]\begin{aligned} & y + (-2\, \lambda)\\ = \; & y + \frac{- 2\, y + 2\, m\, x + 2\, c}{m^{2} + 1} \\ =\; & \frac{(m^{2} - 1) \, y + 2\, m \, x + 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].
Find the value of m.
L
R
A
3m +21 U
6m
O A. 14
ОВ. 7
Answer:
B
Step-by-step explanation:
Since LR=LA, RU=RA. 3m+21=6m, 3m=21, m=7
What is the area in square units of trapezoid ABCD shown Below ?
Answer: Choice B) 50 square units
Work Shown:
A = h*(b1+b2)/2
A = 5*(12+8)/2
A = 5*(20)/2
A = 100/2
A = 50 square units (choice B)
Notice how the b1 and b2 are the parallel bases, while the height h = 5 is perpendicular to both of these bases.
The area of Trapezium ABCD is 50 square unit.
what is area of Trapezium?
The formula to calculate the area of trapezium is:
Area = ½ x Sum of parallel sides x Distance between the parallel sides
Given:
base 1= 8 , base 2 = 12 unit
height= 5 unit
so, the area of Trapezium
= 1/2 ( base 1 + base 2) /2
= 1/2 (8 + 12) x5
= 1/2 x 20 x 5
= 10 x 5
= 50 square unit.
Learn more about area of Trapezium here:
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What integer is equal to 5!×2!?
Answer:
240
Step-by-step explanation:
! means factorial or to multiply by the previous number down to one so 5!=5*4*3*2*1=120 120*2=240.
Analyze the key features of the graph of the quadratic function f(x) = –x^2 + 4x – 3.
1. Does the parabola open up or down?
2. Is the vertex a minimum or a maximum?
3. Identify the axis of symmetry, vertex and the y-intercept of the parabola.
9514 1404 393
Answer:
downmaximumx=2; (2, 1), -3Step-by-step explanation:
1. The negative leading coefficient (-2) tells you the parabola opens downward.
__
2. The fact that the parabola opens downward tells you the vertex is a maximum.
__
3. For quadratic ax^2 +bx +c, the axis of symmetry is x = -b/(2a). For this parabola, that is x = -4/(2(-1)) = 2. The y-value of the vertex is f(2) = -2^2+4(2)-3 = -4+8-3 = 1. The y-intercept is the constant, c = -3.
axis of symmetry: x = 2vertex: (2, 1)y-intercept: (0, -3)14. Solve for p. Assume that none of the denominators are equal to 0
Plz help me
Answer:
Step-by-step explanation:
Divide by y
kl/y = f/(p + n) + r/u Subtract r/u from both sides
kl/y - r/u = f/(p + n) Multiply both sides by (p + n)
(kl/y - r/u ) (p + n) = f Divide by (kl/y - r/u)
p + n = f / (kl/y - r/u) Subtract n from both sides
p = f / (kl/y - r/u) - n
I think I'd leave this as the answer. I don't think you are expected to make it a 2 tier fraction.
Draw the perpendicular bisector of the given line segment a.9.4 cm b. 8.6cm c. 10 cm
Answer:
Please do it by your shelf because if we measure it and send you may not be able to do by online .So, please do it by by yourself using your scale .
Evaluate [x + 1/y]^m × [x-1/y]^n /[y+1/x]^m [y-1/x]^n
9514 1404 393
Answer:
(x/y)^(m+n)
Step-by-step explanation:
[tex]\displaystyle\frac{\left(x+\frac{1}{y}\right)^m\left(x-\frac{1}{y}\right)^n}{\left(y+\frac{1}{x}\right)^m\left(y-\frac{1}{x}\right)^n}=\left(\frac{x}{y}\right)^m\left(\frac{x}{y}\right)^n\\\\=\boxed{\left(\frac{x}{y}\right)^{m+n}}[/tex]
what number should be added to -5/8 to get -3/2
Answer:
-7/8
Step-by-step explanation:
-5/8+x=-3/2
x= -3/2+5/8=-12/8+5/8= -7/8
help with 5 please( question tuped below too).
Prove that y=x+2 is a tangent to the locous P(2t²,4t).
find the point of contact of this tangent to this locous and hence find the equation of normal at the point.
thanks
9514 1404 393
Answer:
tangent point: (2, 4)normal: y = -x +6Step-by-step explanation:
The derivative of P with respect to t is ...
P' = (x', y') = (4t, 4)
so the slope of the curve for some value of t is ...
dy/dx = y'/x' = 4/(4t) = 1/t
The line we want to be a tangent is y = x +2, which has a slope of 1. The curve will have a slope of 1 where ...
1/t = 1 ⇒ t = 1
At t=1, the point P is (2·1², 4·1) = (2, 4). For x=2, the point on the desired tangent is y = x +2 = 2 +2 = 4, or (x, y) = (2, 4).
The curve and the given line both have a slope of 1 at the point (2, 4), so that is the tangent point.
__
The normal to the curve at (2, 4) will have a slope that is the opposite reciprocal of the slope of the tangent: -1/1 = -1. Then point-slope form of the equation of the normal line is ...
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
y -4 = -1(x -2) . . . . . . line with slope -1 through point (2, 4)
y = -x +6 . . . . . . . . equation of the normal line in slope-intercept form
Ugh I’m going insane trying to do this. Please help.
Answer:
y(x)=6^(x)-3
Step-by-step explanation:
Let the exponential function be y(x) = ab^(x) but since the graph is translated 3 units down, y(x) = ab^(x)-3. Now, y(0)=-2=a*b^(0)-3. a=1. The equation is nearly complete but we need b, we can find it by using the point y(1)=3. y(x)=b^(x) - 3. y(1)=3=b-3, b=6. The equation of the function is y(x)=6^(x)-3
Answer:
I agree with the first one
solve for x. Solve for x solve for x solve for x
Answer:
x=29
Does the answer help you?
Answer:
x=29
Step-by-step explanation:
Find the measure of ZJ, the smallest angle in a triangle
with sides measuring 11, 13, and 19. Round to the
nearest whole degree.
O 30°
O 34°
o 42°
O 47°
What would the equation be if I multiplied each side by 12
Answer:
It's option a. 36 + 6x^2 = 28x
Step-by-step explanation:
The graph of y=x√ is translated 5 units to the left and 7 units up. What is the equation of the graph that results from this translation?
Answer:
[tex]y = \sqrt{x - 5} + 7[/tex]
solve for x! please help (show work)
Answer:
[tex]x=4[/tex]
Step-by-step explanation:
Solving for [tex]x[/tex], we get:
[tex]16=2(3x-6)+x[/tex]
[tex]16=2*3x+2(-6)+x[/tex] (Distributive Property of Multiplication)
[tex]16=6x-12+x[/tex] (Multiply distributed terms)
[tex]16=7x-12[/tex] (Combine like terms)
[tex]16+12=7x-12+12[/tex] (Add [tex]12[/tex] to both sides of the equation to isolate [tex]x[/tex])
[tex]28=7x[/tex] (Combine like terms / Simplify)
[tex]\frac{28}{7}=\frac{7x}{7}[/tex] (Divide both sides of the equation by [tex]7[/tex] to get rid of [tex]x[/tex]'s coefficient)
[tex]\bf x=4[/tex] (Simplify / Symmetric Property of Equality)
Hope this helps!
Step-by-step explanation:
[tex]16 = 2(3x - 6) + x \\ 16 = 6x - 12 + x \\ - 6x - x = - 12 - 16 \\ - 7x = - 12 - 16 \\ 7x = 12 + 16 \\ 7x = 28 \\ x = \frac{28}{7} \\ x = 4[/tex]
1. In the past, Sam cashed his paycheck each month at Ready Cash, a check cashing service that
charges a 5% fee. He recently opened a checking account at Bank of America so he can now
deposit and/or cash his paycheck without a fee. If Sam is making $28,500 per year, how much will
he save by not going to Ready Cash anymore?
Step-by-step explanation:
28000 ÷ 100
=280
280 × 5
=1400
Which table represents a function?
GO
х
-3
0
-2
8
y
-1
0
-1
1
х
-5
0
-5
6
y
-5
0
5
-6
х
-4
-2
-2
0
у
8
2
4
2
х
-4
3
1
-4
у
2.
5
3
0
The table that represents a function in the options given is: Table A. (see image attached below).
Recall:
If a relation represents a function, the relation must have exactly one y-value assigned or related to each x-value.In the tables given, only the first table has exactly one y-value assigned or related to every x-value given.
Therefore, the table that represents a function in the options given is: Table A. (see image attached below).
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Answer:
Graph A
Step-by-step explanation:
