To calculate the volume of a chemical produced in a day a chemical manufacturing company uses the following formula below:
[tex]V(x)=[C_1(x)+C_2(x)](H(x))[/tex]
where represents the number of units produced. This means two chemicals are added together to make a new chemical and the resulting chemical is multiplied by the expression for the holding container with respect to the number of units produced. The equations for the two chemicals added together with respect to the number of unit produced are given below:
[tex]C_1(x)=\frac{x}{x+1} , C_2(x)=\frac{2}{x-3}[/tex]
The equation for the holding container with respect to the number of unit produced is given below:
[tex]H(x)=\frac{x^3-9x}{x}[/tex]
a. What rational expression do you get when you combine the two chemicals?
b. What is the simplified equation of ?
c. What would the volume be if 50, 100, or 1000 units are produced in a day?
d. The company needs a volume of 3000 How many units would need to be produced in a day?
Answers
Answer:
[tex]V(x) = [\frac{x}{x + 1} + \frac{2}{x-3}] * \frac{x^3 - 9x}{x}[/tex]
[tex]V(x) = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]
[tex]V(50) = 2548.17[/tex] [tex]V(100) = 10098.10[/tex] [tex]V(1000) = 999201.78[/tex]
[tex]x = 54.78[/tex]
Step-by-step explanation:
Given
[tex]V(x) = [C_1(x) + C_2(x)](H(x))[/tex]
[tex]C_1(x) = \frac{x}{x+1}[/tex]
[tex]C_1(x) = \frac{2}{x-3}[/tex]
[tex]H(x) = \frac{x^3 - 9x}{x}[/tex]
Solving (a): Expression for V(x)
We have:
[tex]V(x) = [C_1(x) + C_2(x)](H(x))[/tex]
Substitute known values
[tex]V(x) = [\frac{x}{x + 1} + \frac{2}{x-3}] * \frac{x^3 - 9x}{x}[/tex]
Solving (b): Simplify V(x)
We have:
[tex]V(x) = [\frac{x}{x + 1} + \frac{2}{x-3}] * \frac{x^3 - 9x}{x}[/tex]
Solve the expression in bracket
[tex]V(x) = [\frac{x*(x-3) + 2*(x+1)}{(x + 1)(x -3)}] * \frac{x^3 - 9x}{x}[/tex]
[tex]V(x) = [\frac{x^2-3x + 2x+2}{(x + 1)(x -3)}] * \frac{x^3 - 9x}{x}[/tex]
[tex]V(x) = [\frac{x^2-x+2}{(x + 1)(x -3)}] * \frac{x^3 - 9x}{x}[/tex]
Factor out x
[tex]V(x) = [\frac{x^2-x+2}{(x + 1)(x -3)}] * \frac{x(x^2 - 9)}{x}[/tex]
[tex]V(x) = [\frac{x^2-x+2}{(x + 1)(x -3)}] * (x^2 - 9)[/tex]
Express as difference of two squares
[tex]V(x) = [\frac{x^2-x+2}{(x + 1)(x -3)}] * (x- 3)(x + 3)[/tex]
Cancel out x - 3
[tex]V(x) = [\frac{x^2-x+2}{(x + 1)}] *(x + 3)[/tex]
[tex]V(x) = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]
Solving (c): V(50), V(100), V(1000)
[tex]V(x) = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]
Substitute 50 for x
[tex]V(50) = [\frac{(50^2-50+2)(50 + 3)}{(50 + 1)}][/tex]
[tex]V(50) = \frac{(2452)(53)}{(51)}][/tex]
[tex]V(50) = 2548.17[/tex]
Substitute 100 for x
[tex]V(100) = [\frac{(100^2-100+2)(100 + 3)}{(100 + 1)}][/tex]
[tex]V(100) = \frac{9902)(103)}{(101)}[/tex]
[tex]V(100) = 10098.10[/tex]
Substitute 1000 for x
[tex]V(1000) = [\frac{(1000^2-1000+2)(1000 + 3)}{(1000 + 1)}][/tex]
[tex]V(1000) = [\frac{(999002)(10003)}{(10001)}][/tex]
[tex]V(1000) = 999201.78[/tex]
Solving (d): V(x) = 3000, find x
[tex]V(x) = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]
[tex]3000 = [\frac{(x^2-x+2)(x + 3)}{(x + 1)}][/tex]
Cross multiply
[tex]3000(x + 1) = (x^2-x+2)(x + 3)[/tex]
Equate to 0
[tex](x^2-x+2)(x + 3)-3000(x + 1)=0[/tex]
Open brackets
[tex]x^3 - x^2 + 2x + 3x^2 - 3x + 6 - 3000x - 3000 = 0[/tex]
Collect like terms
[tex]x^3 + 3x^2- x^2 + 2x - 3x - 3000x + 6 - 3000 = 0[/tex]
[tex]x^3 + x^2 -3001x -2994 = 0[/tex]
Solve using graphs (see attachment)
[tex]x = -54.783[/tex] or
[tex]x = -0.998[/tex] or
[tex]x = 54.78[/tex]
x can't be negative. So:
[tex]x = 54.78[/tex]
Related Questions
If there are
12 books in the rack, a person has to choose 5
out of them. In how many ways
can he choose books,if one
book is never selected?
Answers
Answer:
462 ways
Step-by-step explanation:
One book never selected means 12 - 1 = 11.
So to find the number of ways, 11C5 which equals to: 11!/(5!(11-5)!) = 462
Evaluate. (1/5) exponent -1 x 4 exponent 0
Answers
9514 1404 393
Answer:
5
Step-by-step explanation:
A calculator can be useful when you want to evaluate a numerical expression.
__
The applicable rules of exponents are ...
a^-b = 1/a^b
a^0 = 1 . . . . . . a≠0
__
Your expression evaluates to ...
(1/5)^-1 × 4^0 = (5/1)^1 × 1 = 5
An article in the Journal of Composite Materials describes the effect of delamination on thenatural frequency of beams made from composite laminates. Five such delaminated beams were subjected to loads, and the resulting frequencies were as follows (in Hz):
230.66, 233.05, 232.58, 229.48, 232.58
(a) Find a 90% two-sided CI on mean natural frequency. Round your answers to 2 decimal places.
(b) Do the results of your calculations support the claim that mean natural frequency is 235 Hz?
(A). _____________<= U<= _______________
(B). YES OR NO ?
Answers
Answer:
(230.21 ; 233.13)
Step-by-step explanation:
Given the data :
230.66, 233.05, 232.58, 229.48, 232.58
To calculate the 90% CI
WE obtain the mean and standard deviation of the sample data :
Mean of sample, ΣX /n = 1158.35/5 = 231.67
The standard deviation of the sample, s = 1.531 (Using calculator).
(The 90% Tcritical value, 2 sided, df = 4) = 2.132
The confidence interval, CI :
Mean ± Tcritical * s/√n
C.I = 231.67 ± (2.132 * (1.531/√5)
C. I = 231.67 ± 1.4597
(231.67 - 1.4597) ; (231.67 + 1.4597)
(230.21 ; 233.13)
A number increase by three is two more twice the number.find the number.
Answers
Answer:
1
Step-by-step explanation:
1 increased by 3=1+3=4
Twice of 1=1+1=2
4 is two more than 2.
Therefore, the number=1
The point A(−8,−4) is reflected over the origin and its image is point B. What are the coordinates of point b?
Answers
9514 1404 393
Answer:
B(8, 4)
Step-by-step explanation:
Reflection across the origin negates both coordinate values.
(x, y) ⇒ (-x, -y) . . . . . reflection across the origin
A(-8, -4) ⇒ B(8, 4)
Which functions represent a vertical stretch of the parent function, f(x) = 1/x? Check all that apply.
g(x) = 3/x
g(x) = -2/x
g(x) = 1/4x
g(x) = 5/2x
g(x) = 1/2x
Answers
Answer:
[tex]g(x) = \frac{3}{x}[/tex]
[tex]g(x) =-\frac{2}{x}[/tex]
[tex]g(x) =\frac{5}{2x}[/tex]
Step-by-step explanation:
Given
[tex]f(x)=\frac{1}{x}[/tex]
Required
Which represents vertical stretch of f(x)
The transformation is represented as:
[tex]g(x) = a* f(x)[/tex]
Where:
[tex]|a| > 1[/tex]
So, the functions are:
[tex]g(x) = \frac{3}{x}[/tex] ---- [tex]|3| > 1[/tex]
[tex]g(x) =-\frac{2}{x}[/tex] --- [tex]|-2|>1[/tex]
[tex]g(x) =\frac{5}{2x}[/tex] --- [tex]|\frac{5}{2}| > 1[/tex]
Answer:
the other person is correct if you need them quick it is a b and d
Step-by-step explanation:
what us 10 to the power of two
Answers
the answer is
10² ( ten square )
step by step :
10² = 10 × 10
= 100
Answer: 100
Step-by-step explanation: 10*10=100
Write the English phrase as an algebraic expression. Then simplify the expression. Let x represent the number. Six times the sun of 4 and a number
Answers
Answer:
6x + 24
Step-by-step explanation:
6 * (4 + x) = 6 * 4 + 6 * x = 6x + 24
find the area of the shaded regions. ANSWER IN PI FORM AND DO NOT I SAID DO NOT WRITE EXPLANATION
Answers
Answer: 18π
okokok gg
Step-by-step explanation:
Here angle is given in degree.We have convert it into radian.
[tex] {1}^{\circ} =( { \frac{\pi}{180} } )^{c} \\ \therefore \: {80}^{\circ} = ( \frac{80\pi}{180} ) ^{c} = {( \frac{4\pi}{9} })^{c} \: = \theta ^{c} [/tex]
radius r = 9 cmArea of green shaded regions = A
[tex] \sf \: A = \frac{1}{2} { {r}^{2} }{ { \theta}^{ c} } \\ = \frac{1}{2} \times {9}^{2} \times \frac{4\pi}{9} \\ = 18\pi \: {cm}^{2} [/tex]
To study the mean respiratory rate of all people in his state, Frank samples the population by dividing the residents by towns and randomly selecting 12 of the towns. He then collects data from all the residents in the selected towns. Which type of sampling is used
Answers
Answer:
Cluster Sampling
Step-by-step explanation:
Cluster Sampling involves the random sampling of observation or subjects, which are subsets of a population. Cluster analysis involves the initial division of population subjects into a number of groups called clusters . From the divided groups or clusters , a number of groups is then selected and it's elements sampled randomly. In the scenario above, the divison of the population into towns where each town is a cluster. Then, the selected clusters (12) which are randomly chosen are analysed.
A married couple had a combined annual income of $81,000. The wife made $9000 more than her husband. What was each of their incomes?
Answers
Step-by-step explanation:
Let the husband's income be x
Wife's income be x + 9000
X + X + 9000 = 81000
2X + 9000 – 9000 = 81000 – 9000
2X= 72000
X = 36000
Husband, 36000,
Wife, 9000+36000, 45000
According to government data, the probability than an adult never had the flu is 19%. You randomly select 70 adults and ask if he or she ever had the flu. Decide whether you can use the normal distribution to approximate the binomial distribution, If so, find the mean and standard deviation, If not, explain why. Round to the nearest hundredth when necessary.
Answers
Answer:
Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.
The mean is 13.3 and the standard deviation is 3.28.
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex], if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex].
The probability than an adult never had the flu is 19%.
This means that [tex]p = 0.19[/tex]
You randomly select 70 adults and ask if he or she ever had the flu.
This means that [tex]n = 70[/tex]
Decide whether you can use the normal distribution to approximate the binomial distribution
[tex]np = 70*0.19 = 13.3 \geq 10[/tex]
[tex]n(1-p) = 70*0.81 = 56.7 \geq 10[/tex]
Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.
Mean:
[tex]\mu = E(X) = np = 70*0.19 = 13.3[/tex]
Standard deviation:
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{70*0.19*0.81} = 3.28[/tex]
The mean is 13.3 and the standard deviation is 3.28.
I need help answering this question asap
Answers
Answer:
Step-by-step explanation:
The median for the given set of six ordered data values is 29.5
9 12 25_ 41 50
What is the missing value?
Answers
Answer:
34
Step-by-step explanation:
let the missing value is x
(25+x) /2 = 29.5
25+x = 29.5(2)
25+x = 59
x = 59-25
x = 34
Ben travels a regular distance of 80 miles to reach office. Today, he used an alternative route that covered a distance of only 75 miles. What is the decrease in the percentage of the distance travelled by ben
Answers
Answer:
Ben traveled 93.75% of his usual distance.
Step-by-step explanation:
Given that Ben travels a regular distance of 80 miles to reach office, and today he used an alternative route that covered a distance of only 75 miles, to determine what is the decrease in the percentage of the distance traveled by Ben, the following calculation must be done:
80 = 100
75 = X
75 x 100/80 = X
93.75 = X
Therefore, Ben traveled 93.75% of his usual distance.
Is this the correct answer?
Answers
Answer:
25.40
Step-by-step explanation:
tickets ( 2 at 10.95 each) = 2* 10.95 = 21.90
popcorn ( 1 at 7.50) = 7.50
Total cost before discount
21.90+7.50=29.40
subtract the discount
29.40-4.00 =25.40
Answer:
Yep! That's correct!
Step-by-step explanation:
We know that Marilyn and her sister are each getting a ticket that cost $10.95. They are also getting a $7.50 popcorn to share. Let's add those values up.
(10.95 * 2) + 7.50 {Multiply 10.95 by 2 to get 21.90.}
21.90 + 7.50 {Add 7.50 to 21.90 to get 29.40}
$29.40 (without the credit) in toal
A credit on a movie reward card functions as a discount, so what we need to do next is subtract 4 from 29.40. That will get us $25.40 as the total cost.
After doing the math, I can deduce that your answer is correct!
Find the solution of x – 13 = 25, and verify your solution using substitution.
options:
A)
x = 12, 12 + 13 = 25, 25 = 25
B)
x = 39, 39 – 13 = 25, 25 = 25
C)
x = 37, 37 – 13 = 25, 25 = 25
D)
x = 38, 38 – 13 = 25, 25 = 25
Answers
Answer:
x = 38
Step-by-step explanation:
x-13 = 25
Add 13 to each side
x-13+13 = 25+13
x = 38
Check
38-13 = 25
25=25
Find the median of the following number 40,30,32,39,34,35,35,37
Answers
Terms given
40,35,32,39,34,35,35,37No of terms=8
We know
[tex]\boxed{\sf Mean=\dfrac{Sum\;of\:terms}{No\;of\:terms}}[/tex]
[tex]\\ \sf\longmapsto Mean=\dfrac{40+35+32+39+34+35+35+37}{8}[/tex]
[tex]\\ \sf\longmapsto Mean=\dfrac{270}{8}[/tex]
[tex]\\ \sf\longmapsto Mean=35[/tex]
Final Answer:
35
Step-by-step explanation:
-median is the middle number in the data set-
arrange the data set from least to greatest:
40, 30, 32, 39, 34, 35, 35, 37 ⇒ 30, 32, 34, 35, 35, 37, 39, 40
we start from the lowest number and the highest number and work your way to the middle:
30, 32, 34, 35, 35, 37, 39, 40
notice that there is no middle number:
30, 32, 34, 35, ?, 35, 37, 39, 40
so what we do is add both 35's and then divide it by 2
35 + 35 = 70 ÷ 2 = 35
median: 35
Convert the following numbers into scientific notation. ( i did them but I feel like they wrong can y’all correct them if they are?)
Answers
Answer:
only 4 is incorrect...
1,450,000 = 1.45 x [tex]10^{6}[/tex] NOT
1,450,000 = 1.45 x [tex]10^{7\\}[/tex]
Step-by-step explanation:
A study was conducted to determine if there was a difference in the driving ability of students from West University and East University by sending a survey to a sample of 100 students at both universities. Of the 100 sampled from West University, 15 reported they were involved in a car accident within the past year. Of the 100 randomly sampled students from East University, 12 students reported they were involved in a car accident within the past year. True or False. The difference in driving abilities at the two universities is statistically significant at the .05 significance level.
Answers
Answer:
False
Step-by-step explanation:
Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Subtraction between normal variables:
When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.
West University:
15 out of 100, so:
[tex]p_W = \frac{15}{100} = 0.15[/tex]
[tex]s_W = \sqrt{\frac{0.15*0.85}{100}} = 0.0357[/tex]
East University:
12 out of 100, so:
[tex]p_E = \frac{12}{100} = 0.12[/tex]
[tex]s_E = \sqrt{\frac{0.12*0.88}{100}} = 0.0325[/tex]
Test the difference in driving abilities at the two universities:
At the null hypothesis we test if there is no difference, that is, the subtraction of the proportions is 0, so:
[tex]H_0: p_W - p_E = 0[/tex]
At the alternative hypothesis, we test if there is a difference, that is, if the subtraction of the proportions is different of 0. So
[tex]H_1: p_W - p_E \neq 0[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{s}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, and s is the standard error.
0 is tested at the null hypothesis:
This means that [tex]\mu = 0[/tex]
From the two samples:
[tex]X = p_W - p_E = 0.15 - 0.12 = 0.03[/tex]
[tex]s = \sqrt{s_W^2+s_E^2} = \sqrt{0.0357^2+0.0325^2} = 0.0483[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{s}[/tex]
[tex]z = \frac{0.03 - 0}{0.0483}[/tex]
[tex]z = 0.62[/tex]
P-value of the test and decision:
The p-value of the test is the probability that the proportions differ by at least 0.03, which is P(|z| > 0.62), that is, 2 multiplied by the p-value of z = -0.62.
Looking at the z-table, z = -0.62 has a p-value of 0.2676.
2*0.2676 = 0.5352.
The p-value of the test is 0.5352 > 0.05, which means that the difference in driving is not statistically significant at the .05 significance level, and thus the answer is False.
Find the missing segment in the image below
Answers
Answer:
x = 12
Step-by-step explanation:
Missing length of the segment is the altitude of the right triangle.
Based on the geometric mean theorem, we would have the following:
h = √(ab)
Where,
h = x
a = 16
b = 9
Plug in the values:
x = √(16*9)
x = √144
x = 12
Weekly wages at a certain factory are
normally distributed with a mean of
$400 and a standard deviation of $50.
Find the probability that a worker
selected at random makes between
$350 and $400.
Answers
Answer:
b or a
Step-by-step explanation:
Solve the following equation for
d
d. Be sure to take into account whether a letter is capitalized or not.
Answers
Hope this helps
whats 5 + 5 i need help my iq is 1 i need help pls pls pls pls
Answers
Answer:
Here are some activities you can do to improve various areas of your intelligence, from reasoning and planning to problem-solving and more.
Memory activities. ...
Executive control activities. ...
Visuospatial reasoning activities. ...
Relational skills. ...
Musical instruments. ...
New languages. ...
Frequent reading. ...
Continued education.
p(x)=Third-degree, with zeros of −3, −1, and 2, and passes through the point (1,12).
Answers
Answer:
The polynomial is:
[tex]p(x) = -x^3 - 2x^2 + 5x + 6[/tex]
Step-by-step explanation:
Zeros of a function:
Given a polynomial f(x), this polynomial has roots [tex]x_{1}, x_{2}, x_{n}[/tex] such that it can be written as: [tex]a(x - x_{1})*(x - x_{2})*...*(x-x_n)[/tex], in which a is the leading coefficient.
Zeros of −3, −1, and 2
This means that [tex]x_1 = -3, x_2 = -1, x_3 = 2[/tex]. Thus
[tex]p(x) = a(x - x_{1})*(x - x_{2})*(x-x_3)[/tex]
[tex]p(x) = a(x - (-3))*(x - (-1))*(x-2)[/tex]
[tex]p(x) = a(x+3)(x+1)(x-2)[/tex]
[tex]p(x) = a(x^2+4x+3)(x-2)[/tex]
[tex]p(x) = a(x^3+2x^2-5x-6)[/tex]
Passes through the point (1,12).
This means that when [tex]x = 1, p(x) = 12[/tex]. We use this to find a.
[tex]12 = a(1 + 2 - 5 - 6)[/tex]
[tex]-12a = 12[/tex]
[tex]a = -\frac{12}{12}[/tex]
[tex]a = -1[/tex]
Thus
[tex]p(x) = -(x^3+2x^2-5x-6)[/tex]
[tex]p(x) = -x^3 - 2x^2 + 5x + 6[/tex]
#include
using namespace std;
int main()
{
int x,y=0;
x=1123;
while (x!=0){
y+=x%10;
x/=10;
}
cout<
}
Answers
Answer:
main aapki madad karna chahti hun per Mujhe Ae Jahan question Nahin Aata sorry I don't know
sorry dear friend
Step-by-step explanation:
ok I don't know
A baseball stadium has a fixed cost of $12,000 per night game. In addition, there is a total cost of $2
each fan that attends the game that evening. Which of the following is the cost equation for the baseball
stadium?
C = 12,002x
C = 2x - 12,000
C= 12,000x + 2
C = 2x + 12,000
Answers
x(x+3)(x+3)=0
solve the equation only one answer
Answers
Answer:
0
Step-by-step explanation:
it says the answer is zero
. Two mutually exclusive projects have projected cash flows as follows:
YEAR PROJECT A PROJECT B
0 Ksh. -2m Ksh. -2m
1 1m 0
2 1m 0
3 1m 0
4 1m 6m
Required:
a) Determine the internal rate of return for each project. [2 Marks]
b) Determine the net present value for each project at discount rates of 0, 5,10,20,30, and 35 percent. [2 Marks]
c) Plot a graph of the net present value of each project at the different discount rates. [2 Marks]
d) Which project would you choose? Why? [ 2 Marks]
e) What is each project’s MIRR if the cost of capital is 12 percent?
Answers
Answer:
yes
Step-by-step explanation:
A plane flying horizontally at an altitude of 3 mi and a speed of 460 mi/h passes directly over a radar station. Find the rate at which the distance from the plane to the station is increasing when it is 4 mi away from the station (Round your answer to the nearest whole number.) 368 X mi/h Enhanced Feedback Please try again. Keep in mind that distance - (altitude)2 + (horizontal distance)? (or y = x + n ). Differentiate with respect to con both sides of the equation, using the Chain Rule, to solve for the given speed of the plane is x.
Answers
Answer:
[tex]\frac{dy}{dt}=304mi/h[/tex]
Step-by-step explanation:
From the question we are told that:
Height of Plane [tex]h=3mi[/tex]
Speed [tex]\frac{dx}{dt}=460mi/h[/tex]
Distance from station [tex]d=4mi[/tex]
Generally the equation for The Pythagoras Theorem is is mathematically given by
[tex]x^2+3^2=y^2[/tex]
For y=d
[tex]x^2+3^2=d^2[/tex]
[tex]x^2+3^2=4^2[/tex]
[tex]x=\sqrt{7}[/tex]
Therefore
[tex]x^2+3^2=y^2[/tex]
Differentiating with respect to time t we have
[tex]2x\frac{dx}{dt}=2y\frac{dy}{dt}[/tex]
[tex]\frac{dy}{dt}=\frac{x}{y}\frac{dx}{dt}[/tex]
[tex]\frac{dy}{dt}=\frac{\sqrt{7}}{4} *460[/tex]
[tex]\frac{dy}{dt}=304.2614008mi/h[/tex]
[tex]\frac{dy}{dt}=304mi/h[/tex]
