Answer:
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Step-by-step explanation:
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Help me plz help me plz plz
Im sorry I don't know the answer to the question
The graph shows the solution of the following system of equations. y=-5/3x+3 y=1/3x-3 What is the solution? A. (-3,2) B. (3,2) C. (-3,-2) D. (3,-2)
Answer:
(3,-2)
Step-by-step explanation:
-5/3x + 3 = 1/3x - 3
-5/3x = 1/3x - 6
-2x = -6
x = 3
y = -5/3(3) + 3
y = -5 + 3
y = -2
NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW. Find each measurement. Round your answers to the nearest tenth. Part 2dd
Answer:
see explanation
Step-by-step explanation:
Using the Sine rule in all 3 questions
[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] = [tex]\frac{c}{sinC}[/tex]
(2)
[tex]\frac{b}{sinB}[/tex] = [tex]\frac{c}{sinC}[/tex] , substitute values
[tex]\frac{45}{sin133}[/tex] = [tex]\frac{c}{sin26}[/tex] ( cross- multiply )
c × sin133° = 45 × sin26° ( divide both sides by sin133° )
c = [tex]\frac{45sin26}{sin133}[/tex] ≈ 27.0 ( to the nearest tenth )
(4)
[tex]\frac{b}{sinB}[/tex] = [tex]\frac{c}{sinC}[/tex] , substitute values
[tex]\frac{19}{sinB}[/tex] = [tex]\frac{30}{sin97}[/tex] ( cross- multiply )
30 sinB = 19 sin97° ( divide both sides by 30 )
sinB = [tex]\frac{19sin97}{30}[/tex] , then
∠ B = [tex]sin^{-1}[/tex] ( [tex]\frac{19sin37}{30}[/tex] ) ≈ 38.9° ( to the nearest tenth )
(6)
[tex]\frac{b}{sinB}[/tex] = [tex]\frac{c}{sinC}[/tex], substitute values
[tex]\frac{18}{sin102}[/tex] = [tex]\frac{xAB}{sin45}[/tex] ( cross- multiply )
AB sin102° = 18 sin45° ( divide both sides by sin102° )
AB = [tex]\frac{18sin45}{sin102}[/tex] ≈ 13.0 ( to the nearest tenth )
help with q25 please. Thanks.
First, I'll make f(x) = sin(px) + cos(px) because this expression shows up quite a lot, and such a substitution makes life a bit easier for us.
Let's apply the first derivative of this f(x) function.
[tex]f(x) = \sin(px)+\cos(px)\\\\f'(x) = \frac{d}{dx}[f(x)]\\\\f'(x) = \frac{d}{dx}[\sin(px)+\cos(px)]\\\\f'(x) = \frac{d}{dx}[\sin(px)]+\frac{d}{dx}[\cos(px)]\\\\f'(x) = p\cos(px)-p\sin(px)\\\\ f'(x) = p(\cos(px)-\sin(px))\\\\[/tex]
Now apply the derivative to that to get the second derivative
[tex]f''(x) = \frac{d}{dx}[f'(x)]\\\\f''(x) = \frac{d}{dx}[p(\cos(px)-\sin(px))]\\\\ f''(x) = p*\left(\frac{d}{dx}[\cos(px)]-\frac{d}{dx}[\sin(px)]\right)\\\\ f''(x) = p*\left(-p\sin(px)-p\cos(px)\right)\\\\ f''(x) = -p^2*\left(\sin(px)+\cos(px)\right)\\\\ f''(x) = -p^2*f(x)\\\\[/tex]
We can see that f '' (x) is just a scalar multiple of f(x). That multiple of course being -p^2.
Keep in mind that we haven't actually found dy/dx yet, or its second derivative counterpart either.
-----------------------------------
Let's compute dy/dx. We'll use f(x) as defined earlier.
[tex]y = \ln\left(\sin(px)+\cos(px)\right)\\\\y = \ln\left(f(x)\right)\\\\\frac{dy}{dx} = \frac{d}{dx}\left[y\right]\\\\\frac{dy}{dx} = \frac{d}{dx}\left[\ln\left(f(x)\right)\right]\\\\\frac{dy}{dx} = \frac{1}{f(x)}*\frac{d}{dx}\left[f(x)\right]\\\\\frac{dy}{dx} = \frac{f'(x)}{f(x)}\\\\[/tex]
Use the chain rule here.
There's no need to plug in the expressions f(x) or f ' (x) as you'll see in the last section below.
Now use the quotient rule to find the second derivative of y
[tex]\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{dy}{dx}\right]\\\\\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{f'(x)}{f(x)}\right]\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-f'(x)*f'(x)}{(f(x))^2}\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2}\\\\[/tex]
If you need a refresher on the quotient rule, then
[tex]\frac{d}{dx}\left[\frac{P}{Q}\right] = \frac{P'*Q - P*Q'}{Q^2}\\\\[/tex]
where P and Q are functions of x.
-----------------------------------
This then means
[tex]\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} + \left(\frac{f'(x)}{f(x)}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} +\frac{(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2+(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\[/tex]
Note the cancellation of -(f ' (x))^2 with (f ' (x))^2
------------------------------------
Let's then replace f '' (x) with -p^2*f(x)
This allows us to form ( f(x) )^2 in the numerator to cancel out with the denominator.
[tex]\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*f(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*(f(x))^2}{(f(x))^2} + p^2\\\\-p^2 + p^2\\\\0\\\\[/tex]
So this concludes the proof that [tex]\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2 = 0\\\\[/tex] when [tex]y = \ln\left(\sin(px)+\cos(px)\right)\\\\[/tex]
Side note: This is an example of showing that the given y function is a solution to the given second order linear differential equation.
What is the value of the expression
below?
(7)3
Answer:
21
Step-by-step explanation:
Please help no links.Mr. Longley is buying a $15 box of trail mix at Whole Foods, where tax is 6%. If Mr. Longley has
a coupon for 10% off the price of any item, how much does he end up paying?
I
Answer:
$14.40
Step-by-step explanation:
my way of doing things:
15/100=0.15=1%of total amount
0.15 x 6=0.9= the 6% which is the tax
0.15 x 10 = 1.5=the coupon
Take the coupon amount $1.50 minus the tax amount $0.90 =$0.60. Because the coupon amount is greater than the tax the 60 cents gets taken away from the original 15 dollars leaving Mr. Longely only having to pay $14.40.
Charlie puts $50000 in a stock account, but it loses money at a rate of 20%
every month. Which of the expressions below models the number of dollars
Charlie's account has after t months?
Answer:
You dind't include the answer choices but it should look something like
[tex]50000(.8)^t[/tex]
5/10+4/16 in simplest form
Lucinda is writing a coordinate proof to show that a diagonal of a parallelogram partitions the parallelogram into two equal areas.
A parallelogram graphed on a coordinate plane. The vertices of rectangle are labeled as K L M and N. The vertex labeled as K lies on begin ordered pair 0 comma 0 end ordered pair. The vertex labeled as L lies on begin ordered pair x comma 2 y end ordered pair. The coordinate of vertex M is left blank. The vertex labeled as N lies on begin ordered pair 3 x comma 0 end ordered pair. A diagonal is drawn between points K and M.
Enter your answers in the boxes to complete Lucinda's proof.
Since KLMN is a parallelogram and a parallelogram's opposite sides are parallel and congruent, the coordinates for M are (4x, 2y).
In △KMN, the length of the base is and the height is . So an expression for the area of △KMN is .
In △KLM, the length of the base is 3x and the height is 2y. So an expression for the area of △KLM is .
Comparing the area of the two triangles that are formed by a diagonal of the parallelogram shows that a diagonal of a parallelogram partitions the parallelogram into two equal areas.
9514 1404 393
Answer:
ΔKMN: base, 3x; height, 2y; area, 3xyΔKLM: area, 3xyStep-by-step explanation:
ΔKMNThe base length is the length of the horizontal line segment KN. That length is the difference of the x-coordinates: 3x -0 = 3x.
The height is the difference of the y-coordinate of point M and the y-coordinate of horizontal segment KN. That difference is 2y -0 = 2y.
The area is half the product of base and height:
A = (1/2)bh
A = 1/2(3x)(2y) = 3xy
In ΔKMN, the length of the base is 3x and the height is 2y. So an expression for the area of ΔKMN is 3xy.
__
ΔKLMIn ΔKLM, the length of the base is 3x and the height is 2y. So an expression for the area of ΔKLM is 3xy.
what is symmetrical line
Answer:
assuming youre asking for line of symmetry, it's a line that cuts a shape exactly in half.
for example, a square has 4 lines of symmetry
How are the functions y = x and y = x+ 5 related? How are their graphs related?
a. Each output for y = x + 5 is 5 less than the corresponding output for y = x.
The graph of y = x+ 5 is the graph of y = x translated down 5 units.
b. Each output for y = x+ 5 is 5 more than the corresponding output for y = x.
The graph of y = x+ 5 is the graph of y = x translated up 5 units.
Each output for y = x+5 is 5 more than the corresponding output for y = x.
The graph of y = x+5 is the graph of y = x translated down 5 units.
d. Each output for y = x + 5 is 5 less than the corresponding output for y=x.
Answer:
b
Step-by-step explanation:
the graph gets translated 5 units above its parent graph of y = x
Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially. The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722. What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body
Answer:
The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.
Step-by-step explanation:
After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.
This means that the amount of caffeine after t hours is given by:
[tex]A(t) = A(0)e^{-kt}[/tex]
In which A(0) is the initial amount and k is the decay rate, as a decimal.
The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.
1 - 0.2722 = 0.7278, thus, [tex]A(10) = 0.7278A(0)[/tex]. We use this to find k.
[tex]A(t) = A(0)e^{-kt}[/tex]
[tex]0.7278A(0) = A(0)e^{-10k}[/tex]
[tex]e^{-10k} = 0.7278[/tex]
[tex]\ln{e^{-10k}} = \ln{0.7278}[/tex]
[tex]-10k = \ln{0.7278}[/tex]
[tex]k = -\frac{\ln{0.7278}}{10}[/tex]
[tex]k = 0.03177289938 [/tex]
Then
[tex]A(t) = A(0)e^{-0.03177289938t}[/tex]
What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?
We have to find find A(5), as a function of A(0). So
[tex]A(5) = A(0)e^{-0.03177289938*5}[/tex]
[tex]A(5) = 0.8531[/tex]
The decay factor is:
1 - 0.8531 = 0.1469
The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.
A farmer plants the same amount every day, adding up to 2 1/4 acres at the end of the year. If the year is 3/4 over, how many acres has the farmer planted?
Answer:
9/4 * 3/4 = 27/16 = 1 [tex]\frac{9}{16}[/tex]
Step-by-step explanation:
Please help me please please help ASAP
Step-by-step explanation:
70 + 45 = 115
180 - 115 = 65
angle c = 65
use sohcahtoa
cos angle = adjacent
hypotenuse
cos 65 = 2.5
b
b cos 65 = 2.5
use the calc for further answers
hope that helped
y = 60x + 20
y = 65x
Answer:
4=x y=325
Step-by-step explanation:
60x + 20 = 65x
group the variables
20=5x
because you subtracted 60x from both
4=x
because you divided 5 from both
now substitute 5 for x
65×5 is 325
y=325
Identify the factorization of 36 + 25x2.
Answer:
86
Step-by-step explanation:
First, we should use the rule of:
B: bracket
O: of
D: division
M: multiplication
A: addition
S: subtraction
so, before adding we should multiply
or;36+50
or;86 ans.
The answer pl shhaoksngausinxbbs pls
Answer:
D. 3
Step-by-step explanation:
A triangle can be defined as a two-dimensional shape that comprises three (3) sides, three (3) vertices and three (3) angles.
Simply stated, any polygon with three (3) lengths of sides is a triangle.
In Geometry, a triangle is considered to be the most important shape.
Generally, there are three (3) main types of triangle based on the length of their sides and these include;
I. Equilateral triangle: it has all of its three (3) sides and interior angles equal.
II. Isosceles triangle: it has two (2) of its sides equal in length and two (2) equal angles.
III. Scalene triangle: it has all of its three (3) sides and interior angles different in length and size respectively.
In Geometry, an acute angle can be defined as any angle that has its size less than ninety (90) degrees.
Hence, we can deduce that the greatest number of acute angles that a triangle can contain is three (3) because the sum of all the interior angles of a triangle is 180 degrees.
What is the correct way to read 43.106
Step-by-step explanation:
Forty three thousand one hundred and six
Answer:
Forty three AND one hundred six thousandths
Step-by-step explanation:
If there is a comma ( , ) between the two numbers, you are correct.
If there is a period / dot ( . ) between them, and you need to read the place values, you must read the numbers to the right of the . as decimals. Those are the "th" numbers. 1 is in the tenths place, 0 in the hundredths place and the 6 in the thousandths place.
If you are simply reading out the digit names, without assigning their value, you might say "forty three POINT one hundred six" or "forty three DOT one hundred six" or "forty three DECIMAL one hundred six".
For a sample variance of n = 36 that has a sample variance of 1,296, what is the estimated error for the sample?
Answer:
6
Step-by-step explanation:
Given :
Sample size, n = 36
Sample variance, s² = 1296
The estimated standard error can be obtained using the relation :
Standard Error, S. E = standard deviation / √n
Standard deviation, s = √1296 = 36
S.E = 36/√36
S.E = 36/6
S.E = 6
Hence, estimated standard error = 6
Given that the triangle ABC is at A= (2,4) B= (5,9) C =(1,7) and if the triangle is reflected across the line y=1, what is the new position of point B?
We need not consider a whole triangle but just point B.
Before reflection we know that [tex]B(5,9)[/tex].
Reflecting B over [tex]y=1[/tex] is relatively easy. First because its a reflection over the horizontal line the only coordinates that will change are y coordinates, while x coordinate will not change so half of the reflection is already done for us,
[tex]B(5,a)[/tex]
Now to what has changed, well currently the distance between 9 and 1 on the y axis is 8 up. But because we are reflecting the a must now be 8 down from 1 which means [tex]1 - 8 = -7[/tex] so our point is now [tex]\boxed{B(5,-7)}[/tex].
Hope this helps :)
9514 1404 393
Answer:
(5, -7)
Step-by-step explanation:
Reflection across the line y = c is accomplished by the transformation ...
(x, y) ⇒ (x, 2c -y)
For c=1 and point B, we have ...
B(5, 9) ⇒ B'(5, 2·1 -9) = B'(5, -7)
The image of point B is (5, -7).
Below is the graph of a polynomial function with real coefficients
(a) The function f is increasing over which intervals? Choose all that apply.
D(-0, -8)
O (-5,-2) O (-8, -2) O (-2,
2) (2,5)
O (5, 0 )
?
(b) The functionfhas local maxima at which x-values? If there is more than one value,
separate them with commas.
(c) What is the sign of the leading coefficient of f?
Select One
(d) Which of the following is a possibility for the degree of f? Choose all that apply.
4
5
6
Please help if you can thank you
9514 1404 393
Answer:
(a) (-∞, -8), (-5, -2), (2, 5)
(b) -8, -2, 5
(c) negative
(d) 6
Step-by-step explanation:
(a) The function is increasing on intervals where the graph slopes upward left-to-right. Those are (-∞, -8), (-5, -2), and (2, 5).
__
(b) The local maxima are at the right end of each interval on which the function is increasing: -8, -2, 5.
__
(c) The function opens downward (∩), so has a negative leading coefficient.
__
(d) There are three local maxima and two local minima (left end of an increasing interval), so a total o 5 turning points. The degree of the polynomial is at least one more than this: 6.
Evaluate 20 + 16 ÷ 2 − 5.
is it 13 18 14 23
Answer:
it is 23
Step-by-step explanation:
first divide
then add
then subtract
Answer:
23
Step-by-step explanation:
Follow PEMDAS
16 ÷ 2 = 8
8 + 20 = 28
28 - 5 = 23
Work out m and c for the line: y = 6 x
Answer:
m = 6
c = 0
General Formulas and Concepts:
Algebra I
Slope-Intercept Form: y = mx + c
m - slope c - y-interceptStep-by-step explanation:
Step 1: Define
y = 6x
↓ Compare to Slope-Intercept Form
Slope m = 6
y-intercept c = 0
A circle has a radius of 7ft. Find the radian measure of the central angle θ that intercepts an arc of length 6ft.
Answer:
49.09°
Step-by-step explanation:
c = circumference = 2×π×r
= 2× 22/7 ×7 = 44 ft
θ = 6/c × 360°
= 6/44 × 360° = 49.09°
find the hcf of 100,24
Answer:
4
Step-by-step explanation:
24 = 2^3 x 3
100 = 2^2 x 5^2
HCF = 2^2 = 4
I need to know how to find the area and to simplify it
Area of parallelogram = b × h
Base = x + 7
Height = x + 3
ATQ
Area = (x + 7) ( x + 3)
x² + 3x + 7x + 21
x² + 10x + 21
Answered by Gauthmath must click thanks and mark brainliest
ive gotten it wrong like 4 times n i cannot figure it out pls help
Answer:
x = 74.74 m
Step-by-step explanation:
you need simple trigonometry to solve it
cosine of an angle is the ratio of the adjacent side to the hypotenuse
cos(42.2) is about 0.74
so X / Hypotenuse = 0.74
we know hypotenuse is 101 m
X / 101 = 0.74
x = 74.74 m
hope this helped!
WILL GIVE BRAINLIST IF CORRECT Which function is represented by this graph
Answer:
Step-by-step explanation:
B; So this is a transformation problem from the parent function of f(x)=|x| so the function is is moved 3 units down giving it the -3 at the end and is moved to the right 7 units so it would be x-7
The manager of a movie theater is standing outside the theater complex one evening. He will be asking the moviegoers questions.
Which questions can the manager ask that will result in discrete quantitative data? Check all that apply.
What movie did you just see?
What genre of movie is your favorite?
How much did you spend at the movies today?
Did you order anything from the concession stand?
Answer:
It's How much did you spend at the movies today?
Step-by-step explanation:
The question can the manager asks "How much did you spend at the movies today?". Then the correct option is C.
What is discrete quantitative data?A discrete quantitative parameter has a clear mathematical explanation but could only take certain integer values (instead of every value in intervals).
The manager of a movie theater is standing outside the theater complex one evening.
He will be asking the moviegoers questions.
Then the questions can the manager ask that will result in discrete quantitative data will be
How much did you spend at the movies today?
The question can the manager asks "How much did you spend at the movies today?"
Then the correct option is C.
More about the discrete quantitative data link is given below.
https://brainly.com/question/12831013
#SPJ2
find each measurement indicated round your answers to the nearest tenth. Part 1d. NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!!
Answer:
see explanation
Step-by-step explanation:
Using the Sine rule in all 3 questions
(1)
[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] , substitute values , firstly calculating ∠ B
[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]
[tex]\frac{a}{sin78}[/tex] = [tex]\frac{18}{sin53}[/tex] ( cross- multiply )
a sin53° = 18 sin78° ( divide both sides by sin53° )
a = [tex]\frac{18sin78}{sin53}[/tex] ≈ 22.0 ( to the nearest tenth )
(3)
[tex]\frac{c}{sinC}[/tex] = [tex]\frac{a}{sinA}[/tex] , substitute values
[tex]\frac{35}{sinC}[/tex] = [tex]\frac{45}{sin134}[/tex] ( cross- multiply )
45 sinC = 35 sin134° ( divide both sides by 35 )
sinC = [tex]\frac{35sin134}{45}[/tex] , then
∠ C = [tex]sin^{-1}[/tex] ( [tex]\frac{35sin134}{45}[/tex] ) ≈ 34.0° ( to the nearest tenth )
(5)
Calculate the measure of ∠ B
∠ B = 180° - (38 + 92)° = 180° - 130° = 50°
[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] , substitute values
[tex]\frac{BC}{sin38}[/tex] = [tex]\frac{10}{sin50}[/tex] ( cross- multiply )
BC sin50° = 10 sin38° ( divide both sides by sin50° )
BC = [tex]\frac{10sin38}{sin50}[/tex] ≈ 8.0 ( to the nearest tenth )
