9514 1404 393
Answer:
6000 mL
Step-by-step explanation:
The prefix "milli-" is an SI standard prefix meaning 1/1000. So, 1 mL = (1/1000)L.
When doing dimension changes, you always want to use scale factors that have a value of 1, which is to say the numerator is equal to the denominator. For converting liters to milliliters, the scale factor you want will have mL in the numerator and L in the denominator:
(1 mL)/(1/1000 L) or (1000 mL)/(1 L)
To do your conversion, multiply your liter volume by this factor.
[tex](6\text{ L})\times\dfrac{1000\text{ mL}}{1\text{ L}}=\dfrac{6\times1000\text{ mL$\cdot$L}}{1\text{ L}}=6000\text{ mL}[/tex]
6 liters is 6000 milliliters.
__
You will notice that the dimensions "L" cancel, which is the point of the exercise.
_____
Additional comment
6 L is closer to 202.884 fluid ounces. The conversion factor is ...
[tex]\dfrac{128\text{ fl oz}}{231\text{ in}^3}\times\dfrac{1\text{ in}^3}{(0.254\text{ dm})^3}\times\dfrac{1\text{ dm}^3}{1\text{ L}}=\dfrac{128\text{ fl oz}}{3.785411784\text{ L}}\quad\text{exactly}[/tex]
The acute angle of the right angle triangle are in the ratio of 4:5
Answer:
Since the triangle is a right angled triangle, one of the angles is 90°. In the right angled triangle, the acute angles are in the ratio 4:5. Let the measures of the acute angles of the triangle in degrees be 4k and 5k, where k is a constant.
Step-by-step explanation:
hope it helps.
Answer:
40and50
Step-by-step explanation:
let the acute angles be 4x and 5x then,
4x+5x+90=180 [sum of all angles of a right angled triangle]
or,9x=180-90
or,x=90/9
x=10
4x=4×10=40
5x=5×10=50
plz help me on this question best and right answer gets brainliest
Answer:
| - 5| 5
| 6 | 6
| - 9 | 9
the numbers will be positive when they come out from the absolute value
Answer and Step-by-step explanation:
The absolute value of a value is the positive version of that value.
| | <- Brackets are used to show that a value is being absolute.
|-5| = 5 The negative 5 with absolute brackets becomes a positive 5.
|6| = 6 A positive 6 with absolute brackets stays a positive 6.
|-9| = 9 A negative 9 with absolute brackets becomes a positive 9.
#teamtrees #PAW (Plant And Water)
What is the equation of a line that passes through points A
(1, 2) and B (4, 3)?
Answer:
3y=x+5
Step-by-step explanation:
The slope of the line is (1/3). The equation of the line is y=(1/3)x+5/3 or 3y=x+5
hat is the measure of the unknown angle?
Image of a straight angle divided into two angles. One angle is ninety seven degrees and the other is unknown
pls
Let on of the angle be x
ATQ
97 + x = 180
x = 180 - 97 (Angles on same line adds upto 180°) (Linear pair cuz 2 angles)
x = 83
The unknown angle is 83°
Must click thanks and mark brainliest
It’s question 14 I need help with please it’s due soon
if you are trying to work out -3/4 - (-1/4 - 1/2) then the answer is 0
Please help me to find out the answer
9514 1404 393
Answer:
80.99 m
Step-by-step explanation:
The hypotenuse of the triangle is given, and the desired side length is the one adjacent to the angle marked. The relevant trig relation is ...
Cos = Adjacent/Hypotenuse
Multiplying by the hypotenuse, we find ...
RY = (82 m)cos(9°) ≈ 80.99 m
How do I graph x+3y≥12?
look at the image below
Answer:
4.2 mi²
Step-by-step explanation:
Volume of a cone = (1/3)πr²h, where r = radius and h = height
(1/3)πr²h
= (1/3)×π×1²×4
= 4π/3
= 4.2 mi² (rounded to the nearest tenth)
Help me with this question plz
9514 1404 393
Answer:
17
Step-by-step explanation:
The points at the ends of the interval are ...
(0, f(0)) = (0, 0)
(7, f(7)) = (7, 119)
The average rate of change is given by the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (119 -0)/(7 -0) = 119/7 = 17
look at the image below
that's what I got, you can confirm if it's correct or not... I'm not sure
have a nice dayʘ‿ʘ
Use the distributive property to simplify
the equation below.
с
8(2a + 4b - c)
[? ]a + [ ]b - [
[ ]
Answer:
16a +32b - 8c
Step-by-step explanation:
8(2a + 4b - c)
Distribute
8*2a + 8*4b+ 8*(-c)
16a +32b - 8c
Answer:
16a + 32b - 8c
Step-by-step explanation:
You bring 8 inside the parenthesis and then multiply it with everything. so for a you put 16, b you put 32 and c you put 8
(b) An economy has an agricultural industry and a textile industry. Each unit of agricultural output requires 0.4 unit of agricultural input and 0.1 unit of textiles input. Each unit of textiles output requires 0.1 unit of agricultural input and 0.2 unit of textiles input.
(i) Write the technology matrix for this economy. [2 marks]
(ii) If surpluses of 5 units of agricultural products and 195 units of textiles are desired, find the gross production of each industry
Leontief input output model (technology matrix) is an economic model that shows the quantitative relationship and sectorial interdependency in a national economy
The responses with regards to the question are;
(i) The technology matrix for the economy is presented as follows;
[tex]\mathbf{ A} =\left[\begin{array}{ccc}Agric&&Textile\\0.4&&0.1\\&&\\0.1&&0.2\end{array}\right] \begin{array}{ccc}\mathbf{Per \ Unit}\\Agriculture\\\\Textile\end{array}\right][/tex]
(ii) The required gross production of each industry to meet the desired surplus are;
50 units of agriculture and 250 units of textile
The reason the above values are correct is as follows:
(i) The given parameters are;
The industries in the economy = Agricultural industry and textile industry
Units of agricultural input required per unit of agricultural output = 0.4
Units of textile input required per unit of agricultural output = 0.1
Units of agricultural input required per unit of textile output = 0.1
Units of textile input required per unit of textile output = 0.2
Let X represent agriculture, and let Y represent textile, we have;
[tex]Agric \ for \ agric = \dfrac{0.4 \ units \ of \ agriculture}{1\ unit \ of \ agric \ produced} \times X \ Agric \ produced= 0.4 \cdot X[/tex]
[tex]Agric \ for \ textile = \dfrac{0.1 \ units \ of \ agriculture}{1\ unit \ of \ textile \ produced} \times Y \ textile \ produced= 0.1 \cdot Y[/tex]
We also have;
Textile for agriculture = 0.1·X
Textile for textile = 0.2·Y
Therefore;
X = 0.4·X + 0.1·Y
Y = 0.1·X + 0.2·Y
Therefore;
The technology matrix for the economy is presented as follows;
[tex]\mathbf{Technology \ matrix, A} =\left[\begin{array}{ccc}Agric&&Textile\\0.4&&0.1\\&&\\0.1&&0.2\end{array}\right] \begin{array}{ccc}\mathbf{Per \ Unit}\\Agriculture\\\\Textile\end{array}\right][/tex]
(ii) Let P represent the production vector, and let d represent the demand vector, we have;
[tex]P = \left[\begin{array}{c}X \\Y\end{array}\right][/tex], [tex]d = \left[\begin{array}{c}5 \\195\end{array}\right][/tex]
P = A·P + d
∴ P - A·P = d
Therefore;
[tex]P = \mathbf{ \dfrac{d}{(I - A)}}[/tex]
Where I = The 2 by 2 identity matrix
We get;
[tex]I - A =\left[\begin{array}{ccc}1&&0\\&&\\0&&1\end{array}\right] - \left[\begin{array}{ccc}0.4&&0.1\\&&\\0.1&&0.2\end{array}\right] = \mathbf{\left[\begin{array}{ccc}0.6&&-0.1\\&&\\-0.1&&0.8\end{array}\right]}[/tex]
With the use of a graphing calculator, we have;
[tex]P =\left[\begin{array}{c}X \\Y\end{array}\right] = \dfrac{\left[\begin{array}{c}5 \\195\end{array}\right]}{\left[\begin{array}{ccc}0.6&&-0.1\\&&\\-0.1&&0.8\end{array}\right]} = \left[\begin{array}{ccc}50\\\\\ 250\end{array}\right][/tex]
The required gross product of agriculture, X = 50 units
The required gross product of textile, Y = 250 units
Learn more about the Leontief input output model here:
https://brainly.com/question/15417573
We have that he technology matrix for this economy and the the gross production of each industry are
a) [tex]X= \begin{vmatrix}0.4 & 0.1 \\0.1 & 0.2\end{vmatrix}[/tex]
b) [tex]\begin{vmatrix}A\\T\end{vmatrix}=\begin{vmatrix}50\\250\end{vmatrix}[/tex]
From the Question we have told that
Each unit of agricultural output requires 0.4 unit of agricultural input
Each unit of agricultural output requires 0.1 unit of textiles input.
Each unit of textiles output requires 0.1 unit of agricultural input
Each unit of textiles output requires 0.2 unit of textiles input.
Generally the technology matrix for this economy is given below
With
X =Agricultural industry Gross output
Y= Textile industry Gross Output
Therefore
[tex]X= \begin{vmatrix}0.4 & 0.1 \\0.1 & 0.2\end{vmatrix}[/tex]
b)
From the Question we are told that
Surpluses of 5 units of agricultural products and 195 units of textiles are desired.
Therefore, we have Desired surplus matrix of
[tex]D= \begin{vmatrix}5\\195\end{vmatrix}[/tex]
Generally the Technology equation is mathematically given as
[tex](I-X)\phi=D[/tex]
Where
X =Agricultural industry Gross output
I=A Unit matrix
\phi=Matrix of gross production
Therefore
[tex]\begin{vmatrix}1 & 0\\0 & 1\end{vmatrix}-(\begin{vmatrix}0.4 & 0.1 \\0.1 & 0.2\end{vmatrix}))\begin{vmatrix}A\\T\end{vmatrix}=\begin{vmatrix}5\\195\end{vmatrix}[/tex]
[tex]\begin{vmatrix}A\\T\end{vmatrix}=\begin{vmatrix}50\\250\end{vmatrix}[/tex]
In conclusion
The technology matrix for this economy and the the gross production of each industry are
[tex]X= \begin{vmatrix}0.4 & 0.1 \\0.1 & 0.2\end{vmatrix}[/tex]
[tex]\begin{vmatrix}A\\T\end{vmatrix}=\begin{vmatrix}50\\250\end{vmatrix}[/tex] Respectively
In conclusion
https://brainly.com/question/16863924
Describe the transformation in the given image.
1
2
Rotation
Reflection
3
Translation
O Dilation
4
Answer:
Translation
Step-by-step explanation:
In Euclidean geometry, a translation is a geometric transformation that moves every point of a figure or a space by the same distance in a given direction. A translation can also be interpreted as the addition of a constant vector to every point, or as shifting the origin of the coordinate system.
I hope this helps :3 Please feel free to ask any questions that you may have.
An employee works 22 days per month if they work an average of 8 and a quarter hours per day how many hours do they work per month
Answer:
181 1/2 hours a month.
Step-by-step explanation:
You multiply the days per month=22
By the hours they work per day=8 1/4
(Optional) You turn 1/4 into .25
Then: 22 × 8.25= 181.5/181 1/2
I hope this answer helps you out. Brainliest would be appreciated. Have a very nice day/night.
solve the following inequality -1≤d+2/5≤6∕5
Answer:
-7/5≤d≤4∕5
Step-by-step explanation:
-1≤d+2/5≤6∕5
Subtract 2/5 from all parts
-1-2/5≤d+2/5-2/5≤6∕5-2/5
-5/5-2/5≤d+≤4∕5
-7/5≤d≤4∕5
Ann,Ryan and Keith have a total of $114 in their wallets. Ryan has three times what Keith has. Keith has nine dollars less than Ann. how much do they have in their wallets?
Answer:
Ann has $30
Ryan has $63
Keith has $21
Step-by-step explanation:
First I assigned variables to the amounts each owns. It doesn't really matter what letters, but I said x represents Ann's money, y represents Ryan's money, and z represents Keith's money.
We know that with all their money added up, they have 114. This gives us our first equation;
114=x+y+z
Ryan has 3 times what Keith has, which, in terms of variables, is
y=3z
Keith has nine dollars less than Ann. Less, in word problems, always means subtraction. This gives us our third equation:
z=x-9
Okay so the impulse is to put z=x-9 and y=3z into the first equation, but the goal is to create an equation with only one variable so this will not work.
What we do instead is sub z=x-9 into y=3z. This gives
y=3(x-9)=3x-27
Now that both y and z are in terms of x, we plug those equations into the first and then solve for x;
114=x+3x-27+x-9
114=5x-36
150=5x
30=x
Now that we know x, we can find z and y using the equations from earlier:
z=30-9=21
y=3(21)=63
x=30, y=63, and z=21, thus Ann has $30, Ryan has $63, and Keith has $21.
A manufacturer of computer memory chips produces chips in lots of 1000. If nothing has gone wrong in the manufacturing process, at most 7 chips each lot would be defective, but if something does go wrong, there could be far more defective chips. If something goes wrong with a given lot, they discard the entire lot. It would be prohibitively expensive to test every chip in every lot, so they want to make the decision of whether or not to discard a given lot on the basis of the number of defective chips in a simple random sample. They decide they can afford to test 100 chips from each lot. You are hired as their statistician.
There is a tradeoff between the cost of eroneously discarding a good lot, and the cost of warranty claims if a bad lot is sold. The next few problems refer to this scenario.
Problem 8. (Continues previous problem.) A type I error occurs if (Q12)
Problem 9. (Continues previous problem.) A type II error occurs if (Q13)
Problem 10. (Continues previous problem.) Under the null hypothesis, the number of defective chips in a simple random sample of size 100 has a (Q14) distribution, with parameters (Q15)
Problem 11. (Continues previous problem.) To have a chance of at most 2% of discarding a lot given that the lot is good, the test should reject if the number of defectives in the sample of size 100 is greater than or equal to (Q16)
Problem 12. (Continues previous problem.) In that case, the chance of rejecting the lot if it really has 50 defective chips is (Q17)
Problem 13. (Continues previous problem.) In the long run, the fraction of lots with 7 defectives that will get discarded erroneously by this test is (Q18)
Problem 14. (Continues previous problem.) The smallest number of defectives in the lot for which this test has at least a 98% chance of correctly detecting that the lot was bad is (Q19)
(Continues previous problem.) Suppose that whether or not a lot is good is random, that the long-run fraction of lots that are good is 95%, and that whether each lot is good is independent of whether any other lot or lots are good. Assume that the sample drawn from a lot is independent of whether the lot is good or bad. To simplify the problem even more, assume that good lots contain exactly 7 defective chips, and that bad lots contain exactly 50 defective chips.
Problem 15. (Continues previous problem.) The number of lots the manufacturer has to produce to get one good lot that is not rejected by the test has a (Q20) distribution, with parameters (Q21)
Problem 16. (Continues previous problem.) The expected number of lots the manufacturer must make to get one good lot that is not rejected by the test is (Q22)
Problem 17. (Continues previous problem.) With this test and this mix of good and bad lots, among the lots that pass the test, the long-run fraction of lots that are actually bad is (Q23)
Step-by-step explanation:
A manufacturer of computer memory chips produces chips in lots of 1000. If nothing has gone wrong in the manufacturing process, at most 7 chips each lot would be defective, but if something does go wrong, there could be far more defective chips. If something goes wrong with a given lot, they discard the entire lot. It would be prohibitively expensive to test every chip in every lot, so they want to make the decision of whether or not to discard a given lot on the basis of the number of defective chips in a simple random sample. They decide they can afford to test 100 chips from each lot. You are hired as their statistician.
There is a tradeoff between the cost of eroneously discarding a good lot, and the cost of warranty claims if a bad lot is sold. The next few problems refer to this scenario.
Problem 8. (Continues previous problem.) A type I error occurs if (Q12)
Problem 9. (Continues previous problem.) A type II error occurs if (Q13)
Problem 10. (Continues previous problem.) Under the null hypothesis, the number of defective chips in a simple random sample of size 100 has a (Q14) distribution, with parameters (Q15)
Problem 11. (Continues previous problem.) To have a chance of at most 2% of discarding a lot given that the lot is good, the test should reject if the number of defectives in the sample of size 100 is greater than or equal to (Q16)
Problem 12. (Continues previous problem.) In that case, the chance of rejecting the lot if it really has 50 defective chips is (Q17)
Problem 13. (Continues previous problem.) In the long run, the fraction of lots with 7 defectives that will get discarded erroneously by this test is (Q18)
Problem 14. (Continues previous problem.) The smallest number of defectives in the lot for which this test has at least a 98% chance of correctly detecting that the lot was bad is (Q19)
(Continues previous problem.) Suppose that whether or not a lot is good is random, that the long-run fraction of lots that are good is 95%, and that whether each lot is good is independent of whether any other lot or lots are good. Assume that the sample drawn from a lot is independent of whether the lot is good or bad. To simplify the problem even more, assume that good lots contain exactly 7 defective chips, and that bad lots contain exactly 50 defective chips.
Problem 15. (Continues previous problem.) The number of lots the manufacturer has to produce to get one good lot that is not rejected by the test has a (Q20) distribution, with parameters (Q21)
Problem 16. (Continues previous problem.) The expected number of lots the manufacturer must make to get one good lot that is not rejected by the test is (Q22)
Problem 17. (Continues previous problem.) With this test and this mix of good and bad lots, among the lots that pass the test, the long-run fraction of lots that are actually bad is (Q23)
please help me!
simplify
Answer:
sec^2(x)
Tell me if I'm correct or wrong. If I'm correct, plz mark me brainliest!
Step-by-step explanation:
Recall that
[tex]\sin (\frac{\pi}{2} - x) = \cos x[/tex]
[tex]\cos (\frac{\pi}{2} - x) = \sin x[/tex]
So we can rewrite the given expression as
[tex]\dfrac{\cos^2 x}{\sin^2 x} + (\sin^2 x + \cos^2 x)[/tex]
[tex]\Rightarrow \dfrac{\cos^2 x}{\sin^2 x} + 1[/tex]
or
[tex]\dfrac{\cos^2 x + \sin^2 x}{\sin^2 x} = \dfrac{1}{\sin^2 x} = \csc^2 x[/tex]
.2333 repeating as a fraction
Answer and Step-by-step explanation:
0.2333...
First, multiply the number by 10 (because there is 1 number being repeated.
2.333.....
Now subtract by the original number.
2.333...
- 0.2333...
2.10
Write this as an equation:
(10 x fraction) - fraction = 2.1 (10 x fraction) - fraction = 9 x fraction
9 x fraction = 2.1 (Divide both sides by 9)
[tex]\frac{2.1}{9}[/tex] = [tex]\frac{7}{30}[/tex]
[tex]\frac{7}{30}[/tex] is the answer.
(To check, do 7 divided by 30 in a calculator, and you will get 0.233 repeating)
#teamtrees #PAW (Plant And Water)
I hope this helps!
- 18 = -3x + 6
Plz help
Answer:
8 =x
Step-by-step explanation:
- 18 = -3x + 6
Subtract 6 from each side
-18-6 = -3x+6-6
-24 = -3x
Divide each side by -3
-24/-3 = -3x/-3
8 =x
Answer:
x= 8
Step-by-step explanation:
[tex]\sf{}[/tex]
=> -3x+6 = -18
=> -3x+6-6= -8-6
=> -3x= -24
=> x= 8
A computer is priced at $2,000. If the sales tax rate is 7.5%, find the total cost of the
computer?
9514 1404 393
Answer:
$2150
Step-by-step explanation:
The tax is 7.5% of the price, so is ...
$2000 × 0.075 = $150
The total cost is the price with tax added:
$2000 +150 = $2150
if f(x) = 5x^2 -3 and g(x) = x^2-4x find (f-g) (x)
Answer:
10x-2x-4=8x-4 اتمنى لك التوفيق
Select the correct answer.plz answer fast due at 11:59
What is the solution for x in the equation?
-4 + 5x − 7 = 10 + 3x − 2x
A. x=4/13
B. x=13/4
C. x=4/21
D. x=21/4
Question: -4 + 5x -7 = 10 + 3x -2x
⇒ 5x -11 = 10 + x
⇒ 5x - x = 10+11
⇒ 4x = 21
⇒ x = 21/4
Answer is Option D
x = 21/4
Must click thanks and mark brainliest
I need help to fine the statement that is true
Answer:
option A
Step-by-step explanation:
wx and zy making 90 angle with each other therefore they are perpendicular.
wx and ab making 0 angle with each other therefore they are parallel
llana has 70¢ in her purse. All the coins have the same value. What could describe all the coins she has in her
purse?
71 pennies
8 dimes
1 0 0
14 nickels
3 quarters
Answer:
14 nickels
Step-by-step explanation:
One nickel is worth 5 cents, so find the value of 14 nickels by multiplying 14 by 5:
14(5)
= 70
So, 14 nickels is equal to the 70 cents that she has in her purse.
The correct answer is 14 nickels.
Simplify i to the 31st power
Answer:
?
How did you simplify
Three research departments have 6, 9,
and 7 members, respectively. Each
department is to select a delegate
and an alternate to represent the
department at a conference. In how
many ways can this be done?
Answer:
I don't know because I don't understand what you mean
A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a random sample of 36 bins, the sample mean amount was 50.67 pounds and the sample standard deviation was 3.9 pounds.
a) Conduct the appropriate hypothesis test using a 0.1 level of significance.
b) What is the test statistic? Give your answer to four decimal places.
c) What is the P-value for the test? Give your answer to four decimal places.
d) What is the appropriate conclusion?
i. Fail to reject the claim that the mean amount per bin is 50 pounds because the P-value is larger than 0.1.
ii. Fail to reject the claim that the mean amount per bin is 50 pounds because the P-value is smaller than 0.1.
iii. Reject the claim that the mean amount per bin is 50 pounds because the P-value is larger than 0.1.
iv. Reject the claim that the mean amount per bin is 50 pounds because the P-value is smaller than 0.1.
Answer:
Step-by-step explanation:
99% =2.58
xbar / Point Est. 50.67
µ 50
σ 3.9
n 36
Confidence Interval
50-> (48.9,52.44) -> Fail to Reject H0
Test Statistic 1.0308
P-Value 0.1549
find the derivative of e power ax divide by log bx
Answer:
Step-by-step explanation:
2067 Supp Q.No. 2a Find the sum of all the natural numbers between 1 and 100 which are divisible by 5. Ans: 1050
5
Answer:
1050
Step-by-step explanation:
Natural Numbers are positive whole numbers. They aren't negative, decimals, fractions. We can just divide 5 into 100 to find how many natural numbers go up to 100 and just add them but that is just to much.
There is a easier method.
E.g: Natural Numbers that are divisible by a Nth Number. is the same as adding the Nth Numbers to a multiple of that Nth Term. For example, let say we need to find numbers divisible by 2. We know that 4 is divisible by 2 because 4/2=2. We can add the Nth numbers which is 2 to 4. 4+2=6. And 6 is divisible by 2 because 6/2=3. We can call this a arithmetic series. A series which has a pattern of adding a common difference
Back to the problem, we can use the sum of arithmetic series formula,
[tex]y = x( \frac{z {}^{1} + {z}^{n} }{2} )[/tex]
Where x is the number of terms in our sequence. Z1 is the fist term of our series. ZN is our last term. And y is the sum of all of the terms
The first term is 5, the numbers of terms being added is 20 because 100/5=20. The last term is 100.
[tex]y = 20( \frac{5 + 100}{2} )[/tex]
[tex]y = 20( \frac{105}{2} )[/tex]
[tex]y = 1050[/tex]