The width of a rectangle is 4 less than half the lenght. If L represents the length, which equation could be used to find the width, w?

Answer:

X= 8cm

Step-by-step explanation:

area of the square = s×s = 16×16 = 256cm

area of the rectangle = l×b = 32×x = 32x

Given , area of triangle = area of square

32x = 256

x= 256/32

x= 8cm

Answer:

[tex]x = 8cm[/tex]

Step-by-step explanation:

we are given a square and rectangle.we want to figure out x which is the width of the rectangle. we are also given a condition i.e

therefore,

[tex] \displaystyle \rm A _{square } = A _{rect}[/tex]

recall the formula of the area of square and rectangle so,

[tex] \displaystyle {s}^{2} = lw[/tex]

now assign variables

thus substitute:

[tex] \displaystyle 32cmx = {16cm}^{2} [/tex]

simplify square:

[tex] \displaystyle 32cmx = 256cm^2[/tex]

divide both sides by 32:

[tex] \displaystyle \boxed{x = 8cm}[/tex]

and we're done!

Answer:

x = 10

Step-by-step explanation:

[tex]x = 3 \times 2 + 4[/tex]

[tex]x = 6 + 4[/tex]

[tex]x = 10[/tex]

From the test the parson wants, and the sample data, we build the test hypothesis and find the p-value.

Suppose  someone wants to claim that more than 55% of adult Catholics in the United  States are in favor of allowing women to become priests.

At the null hypothesis, it is tested that the proportion is of at most 55%, that is:

[tex]H_0: p \leq 0.55[/tex]

At the alternative hypothesis, it is tested that the proportion is of more than 55%, that is:

[tex]H_1: p > 0.55[/tex]

Since we are testing only one proportion, it is a one-sample test. Since we are testing only if the proportion is higher/lower, in this case higher, than a value, it is a one-tailed test.

P-value:

To find the p-value of the test, we first have to find the test statistic.

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the nu

0.55 is tested at the null hypothesis:

This means that [tex]\mu = 0.55, \sigma = \sqrt{0.55*0.45}[/tex]

From the sample:

Survey of 507, 59% answer yes, thus: [tex]n = 507, X = 0.59[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.59 - 0.55}{\frac{\sqrt{0.55*0.45}}{\sqrt{507}}}[/tex]

[tex]z = 1.81[/tex]

P-value from the test statistic:

The p-value of the test is the probability of finding a sample proportion above 1.81, which is 1 subtracted by the p-value of z = 1.81.

Looking at the z-table, z = 1.81 has a p-value of 0.9649.

1 - 0.9649 = 0.0351.

Thus, the p-value of the test is of 0.0351.

For another example of a similar problem, you can check https://brainly.com/question/24166849

Answer:

Question in English please I don't understand your language.

Start with a volume of a cuboid,

[tex]V=abc=3\cdot2\cdot3=18\mathrm{cm^3}[/tex]

The side of the cube we need equals to the LCM of the cubiod's sides,

[tex]\mathrm{LCM}(a,b,c)=\mathrm{LCM}(3,2,3)=6[/tex]

Now compute the volume of such cube,

[tex]V=\mathrm{LCM}(a,b,c)^3=6^3=216\mathrm{cm^3}[/tex]

Divide the volumes to get how many cubiods are in such cube,

[tex]\dfrac{V_{\mathrm{cube}}}{V_{\mathrm{cubiod}}}=\dfrac{216}{18}=\boxed{12}[/tex]

Hope this helps :)

Answer:

Hi,

Answer: 12

Step-by-step explanation:

lcm(3,2,3)=6

Volume of a cuboid=3*2*3=18 (cm³)

Volume of the cube=6³=216 (cm³)

Number of cuboids=216/18=12.

I think because the angles are corresponding/opposite to each other u equate them to 180°

Answer:

It's option A. ± √60

Step-by-step explanation:

x^2  = 60

here ^2 will move to the other side and when it does it'll become a square root to 60.

so, x = √60

now, the answer in its simplified form would be 2√15 and -2√15.

The answer of this square root will be negative as well as positive, so, ±√60.

Answer:

±√60

You'll have to remove the square from the x by squaring the 60, hence the ±60 as the answer

Answer: The population was 2,300,000.

Step-by-step explanation:

Let the population in 1950 be x

11,200,000 = 2,000,000+4x

11,200,000-2,000,000 = 4x

0r, 9,200,000=4x

0r, x = 9,200,000/4

so, x = 2,300,000

We have to convert it to m/s

[tex]\boxed{\sf 1km/h=\dfrac{5}{18}m/s}[/tex]

[tex]\\ \sf\longmapsto 40km/h[/tex]

[tex]\\ \sf\longmapsto 40\times \dfrac{5}{18}[/tex]

[tex]\\ \sf\longmapsto \dfrac{200}{18}[/tex]

[tex]\\ \sf\longmapsto 11.1m/s[/tex]

km/h > m/s

when converting km/h to m/s all you need to do is divide by 3.6

and vise versa when converting m/s to km/h multiply by 3.6

so therefore,

40km/h > m/s

= 40 / 3.6

= 11.11 m/s (4sf)

Answer:

I think it is twenty seven

1/tan x = cot x

Cot x + tan x = 1/ sin x cos x

The answer is D.

Answer:

a=3

Step-by-step explanation:

Given points (a, b) and (c,d), the midpoint of the points will be at

((a+c)/2, ((b+d)/2)

Therefore, given (9, 2) and (a,2a), our midpoint is at

((9+a)/2, (2+2a)/2) = (6,4)

Matching the x values to their corresponding x values and doing the same with the y values, we get

(9+a)/2 = 6

(2+2a)/2 = 4

First, we have

(9+a)/2 = 6

multiply both sides by 2 to remove the denominator

9+a = 12

subtract 9 from both sides to isolate a

a = 3

2a = 2 * a = 6

Confirming this, we have

(2+2a)/2 = 4

(2+6)/2 = 4

8/2=4

The value of a is 3 after using the bisection formula and the coordinate of the C is (3, 6).

It is defined as a representation of coordinates in a two-dimensional coordinate plane. It has a list of two elements in it, such as (x, y).

[tex]\rm Area = |\dfrac{(x_1y_2-y_1x_2)+(x_2y_3-y_2x_3)....+(x_ny_1-y_nx_1)}{2}|[/tex]

It is given that:

Point M is the midpoint of CD.

The coordinate of the C is (a, 2a)

The coordinate of the M is (6, 4)

The coordinate of the C is (9, 2)

Using bisection formula:

(a + 9)/2 = 6

The arithmetic operation can be defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. I

a + 9 = 12

a = 12 - 9

a = 3

Or

(2a + 2)/2 = 4

a + 1 = 4

a = 3

Thus, the value of a is 3 after using the bisection formula and the coordinate of the C is (3, 6).

Learn more about the order double here:

brainly.com/question/10757890

#SPJ2

Answer:

the answers for x and y are both 12

Answer:

B.  P(A|B) = P(A).

Step-by-step explanation:

Question

If a and b are independent events then it must be true that P(A|B)=P(A). TRUE OR FALSE.

Answer

The correct answer is:True.Explanation:P(A|B) is read as “the probability of A given B.” If A and B are independent, this means that B has no effect on A. This means the probability of A given B would be the same as the probability of A, since B has no effect.This means that P(A|B) = P(A).

Answer:

B. P(A|B) = P(A)

Step-by-step explanation:

I got it right on edge 2023 :)

Let numbers be a and b

Adding both

[tex]\\ \qquad\quad\sf\longmapsto 2a=24[/tex]

[tex]\\ \qquad\quad\sf\longmapsto a=\dfrac{24}{2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto a=12[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 12-b=9[/tex]

[tex]\\ \qquad\quad\sf\longmapsto b=12-9[/tex]

[tex]\\ \qquad\quad\sf\longmapsto b=3[/tex]

yes I will send you a check tomorrow morning if I have a time for it tomorrow and if you need any more info let us or you get lost and I

Answer:

x = 48

Step-by-step explanation:

Pythagorean thm:

a² + b² = c²

Given:

a = x

b = 36

c = 60

Work:

a² + b² = c²

x² + 36² = 60²

x² + 1296 = 3600

x² = 3600 - 1296

x² = 2304

√x² = √2304

x = 48

Answer:

12/100 *76200 =$9144

so gross pay = $1310 +$9144 =$10454

Answer:

12 days

Step-by-step explanation:

The answer of the problem is the LCM of 3 and 4=12. Hence the answer is 12 days

On 12 March she will swim and cycle on the same day if Amira starts an exercise program on the 3rd of March.

It is defined as the common number of two integers, which is the lowest number that is a multiple of two or more numbers. The full name of LCM is the least common multiple.

We have:

Amira starts an exercise program on the 3rd of March.

She will swim every 3 days and cycle every 4 days.

Total days =3 + 4 = 7 days = 1 week

The day she swims and cycles on the same day = LCM of 3 and 4

= 3, 6, 9, 12, 15

= 4, 8, 12, 16

= 12

Thus, on 12 March she will swim and cycle on the same day if Amira starts an exercise program on the 3rd of March.

Learn more about the LCM here:

brainly.com/question/20739723

#SPJ2

Answer:

b=14 cm

Step-by-step explanation:

Use pythagorean equation

A^2+b^2=c^2

1^2+b^2=14^2

1+b^2=196

b^2=195

b=13.964

Observe the quantities, ie. see what happens if you increase one or decrease the other.

To simplify imagination, expose one quantity. I will expose y.

1.

[tex]-\frac{y}{4}=2x\implies y=-8x[/tex]

So what is their variation or proportion? If I increase x then y is getting more and more negative. So is this direct or inverse or nothing? It is direct.

2.

[tex]14x=\frac{14}{y}\implies y=x, y\neq0[/tex] again if I increase x then y will match, will also increase. This is again direct.

3.

[tex]y=\frac{13}{x}, x\neq0[/tex] this time if I increase x, y will get smaller. When x is exactly 13, y will be 1 and when x is 10000, y will be 0.0013. This is inverse. One quantity gets really small when other quantity gets really big.

4.

[tex]y=x-2[/tex] if I increase x then y will also increase even though by slightly less (-2) it will still increase. However since there is no multiplication this is not a direct variation nor is it inverse. It is nothing/no-variation.

Hope this helps :)

Complete the square in the denominator.

[tex]s^2 - 4s + 8 = (s^2 - 4s + 4) + 4 = (s-2)^2 + 4[/tex]

Rewrite the given transform as

[tex]\dfrac{3s-14}{s^2-4s+8} = \dfrac{3(s-2) - 8}{(s-2)^2+4} = 3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}[/tex]

Now take the inverse transform:

[tex]L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}[/tex]

Answer:

A) 14

B) 7.874

Step-by-step explanation:

perimeter is all 4 sides add

area is l*w

56/4

√62

The true statements about the function include:

It should be noted that a function is simply used to illustrate the relationship between variables.

In this case, the given function is f(x) = x^1/3.

The intercept is (0, 5). Also, it can be deduced that as x approaches oo, h(x) approaches infinity.

Learn more about functions on:

brainly.com/question/25638609

#SPJ5

Answer:

$15798.4

Step-by-step explanation:

We will have to use this formula A = Peᵃᵇ

A = Final amount

P = Initial amount (12,000)

e = Mathematical constant: 2.7183

a = Interest rate (5.5% or 0.055)

b = Years

So our equation will look like this

A = 12,000e⁵ ⁰·⁵⁵

A = 12,000(2.7183)·²⁷⁵

A = 12,000(1.316533)

A = 15798.396

Answer:

KI and HE are parallel

So we apply the law of exterior angles ;

3X=X + 180– 2X

3X +X = 180

4X= 180

X= 180/4

X= 45

I hope I helped you^_^

It looks like the integral you want to find is

[tex]\displaystyle \int_C x^2y\,\mathrm dx - xy^2\,\mathrm dy[/tex]

where C is the circle x ² + y ² = 4. By Green's theorem, the line integral is equivalent to a double integral over the disk x ² + y ² ≤ 4, namely

[tex]\displaystyle \iint\limits_{x^2+y^2\le4}\frac{\partial(-xy^2)}{\partial x}-\frac{\partial(x^2y)}{\partial y}\,\mathrm dx\,\mathrm dy = -\iint\limits_{x^2+y^2\le4}(x^2+y^2)\,\mathrm dx\,\mathrm dy[/tex]

To compute the remaining integral, convert to polar coordinates. We take

x = r cos(t )

y = r sin(t )

x ² + y ² = r ²

dx dy = r dr dt

Then

[tex]\displaystyle \int_C x^2y\,\mathrm dx - xy^2\,\mathrm dy = -\int_0^{2\pi}\int_0^2 r^3\,\mathrm dr\,\mathrm dt \\\\ = -2\pi\int_0^2 r^3\,\mathrm dr \\\\ = -\frac\pi2 r^4\bigg|_{r=0}^{r=2} \\\\ = \boxed{-8\pi}[/tex]