The time I spend waiting for the bus on any given day has a distribution with mean 4 min- utes and variance off 0.5 minutes. What is the probability that I spend more than 2 hours and 10 minutes waiting for the bus in one month (30 days)? You may assume that waiting times on different days are independent of each other. HINT: Is there a sum of random variables somewhere in here?

Answers

Answer 1

Answer:

0.0049 = 0.49% probability that I spend more than 2 hours and 10 minutes waiting for the bus in one month.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n instances of a normal variable:

For n instances of a normal variable, the mean is:

[tex]M = n\mu[/tex]

[tex]s = \sigma\sqrt{n}[/tex]

Mean of 4 minutes, standard deviation of 0.5 minutes:

This means that [tex]\mu = 4, \sigma = \sqrt{0.5}[/tex]

30 days:

[tex]M = 30(4) = 120[/tex]

[tex]s = \sqrt{0.5}\sqrt{30} = \sqrt{0.5*30} = \sqrt{15}[/tex]

What is the probability that I spend more than 2 hours and 10 minutes waiting for the bus in one month (30 days)?

2 hours and 10 minutes is 2*60 + 10 = 130 minutes, so this probability is 1 subtracted by the p-value of Z when X = 130. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this context, due to the 30 instances of the normal variable:

[tex]Z = \frac{X - M}{s}[/tex]

[tex]Z = \frac{130 - 120}{\sqrt{15}}[/tex]

[tex]Z = 2.58[/tex]

[tex]Z = 2.58[/tex] has a p-value of 0.9951.

1 - 0.9951 = 0.0049

0.0049 = 0.49% probability that I spend more than 2 hours and 10 minutes waiting for the bus in one month.


Related Questions


Find the measures of angles 1 and 2. If necessary, round to the tenths place.
Hint: Do not assume that Point D is the center of the circle.

A. m<1 = 20 m<2= 20
B. m<1 =40 m<2 = 140
C. m<1 = 82.5 m<2 = 97.5
D. m<1 =97.5 m<2= 82.5

Answers

Answer:

Option C

Step-by-step explanation:

From the picture attached,

m∠ABC = 40° [Given]

Since, measure of the intercepted arc is double of the measure of the inscribed angle.

Therefore, m(arc AC) = 2(m∠ABC)

m(arc AC) = 2(40°)

                 = 80°

m(arc FB) = 115° [Given]

By applying theorem of the angles formed by the chords inside a circle,

m∠2 = [tex]\frac{1}{2}(\text{arc}AC+\text{arc}FB)[/tex]

        = [tex]\frac{1}{2}(80^{\circ}+115^{\circ})[/tex]

        = 97.5°

m∠1 + m∠2 = 180° [Linear pair of angles are supplementary]

m∠1 + 97.5° = 180°

m∠1 = 180° - 97.5°

       = 82.5°

Option C is the answer.

Ryanair provides cheap flights in Europe but prides itself on their on-time record. Ryanair quotes a flight time of 2 hours, 5 minutes. Suppose we believe that actual flight times are uniformly distributed between 2 hours and 2 hours, 20 minutes.

What is the expected flight time in minutes?

Answers

Answer:

The expected flight time is 2 hours 10 minutes

Step-by-step explanation:

Given

[tex]a = 2\ hours[/tex]

[tex]b = 2\ hours\ 20\ mins[/tex]

Required

The expected flight time

To do this, we simply calculate the mean using:

[tex]Mean = \frac{a + b}{2}[/tex]

So, we have:

[tex]Mean = \frac{2\ hours + 2\ hours\ 20\ mins}{2}[/tex]

[tex]Mean = \frac{4\ hours\ 20\ mins}{2}[/tex]

[tex]Mean = 2\ hours\ 10\ mins[/tex]

WORTH 15 POINTSSSSSSSSS

Answers

Answer:

15

Step-by-step explanation:

Difference in distances = 75-60 = 15 miles

So Car A travels 15 miles more than Car A in an hour

Answered by Gauthmath

What is the length of the arc of a circle of diameter 8 meters subtended by a central angle of
3pi/4 radians?

Answers

Answer:

9.42 meters

Step-by-step explanation:

diameter = 8 m

radius = 4 m

Length of arc = radius * central angle in radians

= 4 * 3[tex]\pi[/tex] / 4

= 12[tex]\pi[/tex] / 4

= 3[tex]\pi[/tex]

= 66 / 7

= 9.42 m

The length of the arc of a circle of diameter 8 meters subtended by a central angle of 3pi/4 radians is 9.42 meters.

What is the arc of the circle?

The arc period of a circle can be calculated with the radius and relevant perspective using the arc period method.

expalination:

⇒angle= arc/radius

= 3pi/4 radians

diameter = 8 m

radius = 4 m

Length of arc = radius * central angle in radians

⇒4 * 3 / 4

⇒12 / 4 = 3

⇒66 / 7

⇒9.42 m

Hence the arc of a circle is 9.42 m.

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What is the area of a trapezoid.. base 14in and 7in height is 5in?

Answers

if the formula is [tex]\frac{(B+b)}{2} .h[/tex] we just need to plug in the values

21/2 = 10.5 x 5 = 52.5

hope it helps :)

Answer:

A = 52.5 in^2

Step-by-step explanation:

The area of a trapezoid is

A = 1/2 (b1+b2)h

where b1 and b2 are the bases and h is the height

A = 1/2 ( 14+7)*5

A = 105/2

A = 52.5 in^2

33. The population of Canada, y (in millions), can be approximated by the relation y=
0.146x + 31, where x represents the number of years since 2000.
a. Approximate the population of Canada in the year 2006.
b. In what year did the population of Canada reach approximately 32,752,000?

Answers

Answer:x=6573/500,x=13(73/500

Step-by-step explanation:

It will takes 12 years to reach approximately 32,752,000.

What is Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given:

y = 0.146x + 31

where x represents the number of years since 2000.

a) The population of Canada in the year 2006

x= 6

y= 0.146 x 6 + 31

y = 31.876

b) The population of Canada reach approximately 32,752,000 in

y = 32.752

0.146x + 31= 32.752

0.146x = 1.752

x= 1.752/0.146

x= 12

Hence, it will takes 12 years to reach approximately 32,752,000.

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find the product of 8×53×(-125) by using suitable property​

Answers

Answer:

-53,000

Step-by-step explanation:

Now to find this answer you use the PEMDAS rule now that stands for:

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction  

Now the first thing that you do is look for the parenthesis now there is but there is no equation in that so we go to the next one exponents and there are no exponents. So we go to the multiplication and we multiply everything and that is how you get that answer.

Hope it helped!

write your answer as an integer or as a decimal rounded to the nearest tenth

Answers

Answer:

VW ≈ 4.0

Step-by-step explanation:

Using the sine ratio in the right triangle

sin35° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{VW}{VX}[/tex] = [tex]\frac{VW}{7}[/tex] ( multiply both sides by 7 )

7 × sin35° = VW , then

VW ≈ 4.0 ( to the nearest tenth )

Find the measure of the incanted angle to the nearest degree

Answers

Answer:

15.5⁰ or approximately 16⁰

Step-by-step explanation:

let unknown side be x

cos x= 53/55

cos x= 0.9636

x=cos inverse of 0.9636

x=15.5⁰

Answer:

[tex]cosx = \frac{53}{55} \\ x = {cos}^{ - 1} ( \frac{53}{55} ) \\ x = 15.4987[/tex]

95% confident that the true mean difference in mean crying time after being given a vitamin K shot between infants using conventional methods and infants held by their mothers is between ____________and ___________________. In other words, the mean crying time of infants given vitamin K shot using conventional methods is anywhere from ______________ less than to _______________more than the mean crying time of infants given vitamin K shot using new methods.

Answers

Solution :

Two sample T-test and CI : Conventional methods, New methods

Two sample T for conventional method Vs new method

                                                  N        Mean           StDev     Se Mean

Conventional mean                 30        35.3              20.8         3.8

New methods                          30         35.1              22.3          4.1

Difference = μ (conventional method) - μ (new method)

Estimate for difference : 0.17

95% CI for difference : (-10.976, 11.309)

T-Test of difference = 0(vs <): T-value = 0.03   P-value =0.5119  DF = 57

95% confident that the true mean difference in mean crying time after being given a vitamin K shot between infants using conventional methods and infants held by their mothers is between -10.976 and 11.309. In other words, the mean crying time of infants given vitamin K shot using conventional methods is anywhere from -10.976 less than to 11.309 more than the mean crying time of infants given vitamin K shot using new methods.

Shortern this expression pls​

Answers

Answer:

[tex]c =\frac{8}{3}[/tex]

Step-by-step explanation:

Given

[tex]c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}[/tex]

Required

Shorten

We have:

[tex]c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}[/tex]

Rationalize

[tex]c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}[/tex]

Expand

[tex]c = \sqrt{\frac{(4 + \sqrt 7)^2}{4^2 - (\sqrt 7)^2}} + \sqrt{\frac{(4 - \sqrt 7)^2}{4^2 - (\sqrt 7)^2}[/tex]

[tex]c = \sqrt{\frac{(4 + \sqrt 7)^2}{16 - 7}} + \sqrt{\frac{(4 - \sqrt 7)^2}{16 - 7}[/tex]

[tex]c = \sqrt{\frac{(4 + \sqrt 7)^2}{9}} + \sqrt{\frac{(4 - \sqrt 7)^2}{9}[/tex]

Take positive square roots

[tex]c =\frac{4 + \sqrt 7}{3} + \frac{4 - \sqrt 7}{3}[/tex]

Take LCM

[tex]c =\frac{4 + \sqrt 7 + 4 - \sqrt 7}{3}[/tex]

Collect like terms

[tex]c =\frac{4 + 4+ \sqrt 7 - \sqrt 7}{3}[/tex]

[tex]c =\frac{8}{3}[/tex]

Which quadrilateral has equal diagonals
Select one:
a. trapezoid
b. rectangle
c. parallelogram
d. rhombus

Answers

Answer:

Option b: Rectangle

Explanation:

Give branliest pls ;)

X+y=11
Graphing which function

Answers

Answer:

Step-by-step explanation:

slopee -1

y-intercept (0,11)

 x   y

0    11

1     10

PLEASEEEE HELP
In the diagram, AABC-ADEC What is the value of x?

Answers

Similar triangles are proportional, meaning one will be a factor larger or smaller than the other. This factor will be the same for all of the sides. So, we can say that one corresponding pair of sides is equal to another corresponding pair of sides.

BA / ED = AC / CD

42 / 6 = (64 - x) / (x)

6(64 - x) = 42(x)

384 - 6x = 42x

384 = 48x

x = 8

Hope this helps!

A number increased by 100% and decreased by 20% is x. what is the number ? NEEDED TODAY

Answers

Answer:

Let's assume the number be 100.

According to the problem , 100 is increased by 100%.

So, new number will be 100+100=200

Now 200 will decreased by 20%.

So, 20% of 200= 0.20*200= 40.

So, again the number has been changed into 200+40=240.

So, x=240

Step-by-step explanation:

9514 1404 393

Answer:

  x/1.6

Step-by-step explanation:

Let n represent the number. When n is increased by 100%, its new value is ...

  n(1 +100%) = n(1 +1) = 2n

When this value is decreased by 20%, its new value is ...

  (2n)(1 -20%) = (2n)(0.8) = 1.6n

This value is x, so the number is ...

  1.6n = x

  n = x/1.6 . . . . . . . divide both sides by 1.6

The graph shows the distribution of the number of text messages young adults send per day. The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.

A graph titled daily text messaging has number of text on the x-axis, going from 8 to 248 in increments of 30. Data is distributed normally. The highest point of the curve is at 128.

What percentage of young adults send between 68 and 158 text messages per day?

34%
47.5%
81.5%
95%

Answers

Answer:  C) 81.5%

This value is approximate.

====================================================

Explanation:

We have a normal distribution with these parameters

mu = 128 = population meansigma = 30 = population standard deviation

The goal is to find the area under the curve from x = 68 to x = 158, where x is the number of text messages sent per day. So effectively, we want to find P(68 < x < 158).

Let's convert the score x = 68 to its corresponding z score

z = (x-mu)/sigma

z = (68-128)/30

z = -60/30

z = -2

This tells us that the score x = 68 is exactly two standard deviations below the mean mu = 128.

Repeat for x = 158

z = (x-mu)/sigma

z = (158-128)/30

z = 30/30

z = 1

This value is exactly one standard deviation above the mean

-------------------------------------------

The problem of finding P(68 < x < 158) can be rephrased into P(-2 < z < 1)

We do this because we can then use the Empirical rule as shown in the diagram below.

We'll focus on the regions between z = -2 and z = 1. This consists of the blue 13.5% on the left, and the two pink 34% portions. So we will say 13.5% + 34% + 34% = 81.5%

Approximately 81.5% of the the population sends between 68 and 158 text messages per day. This value is approximate because the percentages listed in the Empirical rule below are approximate.

Answer:

C. 81.5%

Step-by-step explanation:

For a 13-person team, how does the actual weekly labor cost compare to the targeted labor cost?

Answers

The actual labor cost is $600 over the targeted labor cost.

Given that,

Work done by each person per week = 40 hours

Required labor hours per week = 600 hours

No. of workers in the team = 13

To find,

Actual weekly labor cost = ?

Procedure:

Actual weekly labor cost = No. of workers * no. of hours performed by them

[tex]= 13 * 40[/tex]

[tex]= 520 hours[/tex]

Given that,

[tex]Regular rate = $ 15.00 per hour[/tex]

[tex]Overtime rate = $ 22.50 per hour[/tex]

Thus,

Actual labor cost = (regular hours worked * regular rate) + (overtime * overtime rate)

[tex]= (520 * 15) + ([600 - 520] * 22.50)[/tex]

[tex]= $ 7,800 + $ 1,800[/tex]

[tex]= $ 9600[/tex]

Targeted Labor cost = $ 9,000 per week

Thus, option C i.e. the actual labor cost is $ 600 over the targeted labor cost.

Learn more about 'Labor Cost' here:

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Find the length of AB

Answers

Since this is a right triangle, we can use one of the three main trigonometric functions: sine, cosine, or tangent.

Remember: SOH-CAH-TOA

Looking from the given angle, we know the opposite side and want to know the hypotenuse. Therefore, we should use the sine function.

sin(54) = 16/AB

AB = 16/sin(54)

AB = 19.78 units

Hope this helps!

find the area of the semi circle plss

Answers

the answer is 39.25

Answer:

Step-by-step explanation:

Which choice correctly shows the solution(s) of the equation x2 = 1442
A)
x= √144
B)
x=V12
X=-
-V144
D)
x = 1V144

Answers

Answer:

Step-by-step explanation:

If the 2s are exponents, you need to indicate this with "^":  

x^2 = 144^2 means x² = 144²

x = ±√144² = ±144

Answer:

Step-by-step explanation:

f the 2s are exponents, you need to indicate this with "^":  

x^2 = 144^2 means x² = 144²

x = ±√144² = ±144

Can anyone help with this math equation please?

Answers

I might be wrong but the first one would be 60 and then the next blank would be 38 correct me if I’m wrong

A group of friends try out a new game that uses a pair of ordinary, fair dice. Points are given to players based on the sum of the two numbers from the rolled pair of dice. If the sum is between 2 and 5, inclusive, the amount of points awarded is the sum minus 1. If the sum is between 6 and 9, inclusive, the amount of points awarded is the sum minus 3. If the sum is between 10 and 12, inclusive, the amount of points awarded is the sum minus 5. Calculate the probability of earning exactly 5 points.

Answers

Answer:

0.2222 = 22.22% probability of earning exactly 5 points.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Possible outcomes:

For the pair of dice:

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

So 36 total outcomes.

If the sum is between 6 and 9, inclusive, the amount of points awarded is the sum minus 3.

Sum of 8 -> 5 points awarded. So

(2,6), (3,5), (4,4), (5,3), (6,2): 5 outcomes.

If the sum is between 10 and 12, inclusive, the amount of points awarded is the sum minus 5.

Sum of 10 -> 5 points awarded. So

(4,6), (5,5), (6,4): 3 outcomes.

Desired outcomes:

5 + 3 = 8

Calculate the probability of earning exactly 5 points.

[tex]p = \frac{D}{T} = \frac{8}{36} = 0.2222[/tex]

0.2222 = 22.22% probability of earning exactly 5 points.

 In one of the examples he is working on, he knows that the two coordinates (0,6) and
(8, 10) are on the function that he is deriving. Using the information from these two
coordinates, determine the slope and y-intercept of the function Mike is looking for, and
then write out the correct function.

Answers

9514 1404 393

Answer:

  y = 1/2x + 6

Step-by-step explanation:

The slope m is given by the formula ...

  m = (y2 -y1)/(x2 -x1)

  m = (10 -6)/(8 -0) = 4/8 = 1/2

The y-intercept is given by the formula ...

  b = y -mx

  b = 6 -(1/2)(0) = 6

Then the slope-intercept equation is ...

  y = mx +b

  y = 1/2x +6

In a random sample of 7 residents of the state of Maine, the mean waste recycled per person per day was 1.4 pounds with a standard deviation of 0.23 pounds.
a. Determine the 95% confidence interval for the mean waste recycled per person per day for the population of Maine. Assume the population is approximately normal.
b. Find the critical value that should be used in constructing the confidence interval.

Answers

Answer:

a) The 95% confidence interval for the mean waste recycled per person per day for the population of Maine is between 1.19 and 1.61 pounds.

b) [tex]T_c = 2.4469[/tex]

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 7 - 1 = 6

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.4469, and the answer to question b is [tex]T_c = 2.4469[/tex]

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.4469\frac{0.23}{\sqrt{7}} = 0.21[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.4 - 0.21 = 1.19 pounds.

The upper end of the interval is the sample mean added to M. So it is 1.4 + 0.21 = 1.61 pounds.

The 95% confidence interval for the mean waste recycled per person per day for the population of Maine is between 1.19 and 1.61 pounds.

Please show work will mark you brainliest!

Answers

QUESTION:- An artist uses 200 tiles to create a tessellation design that covers a rectangle with dimensions 2 ft by 3 ft. He will cover a wall with dimensions 10 ft by 15 ft using the same design and tiles of the same size. How many tiles will he need to cover the entire wall?

ANSWER:-

CASE 1 :- NUMBER OF TILES USED -> 200AREA WHICH IS TO BE COVERED-> 2×3 ft² (given-> rectangle)

CASE 2:-

AREA WHICH IS TO BE COVERED-> 10×15 ft² (given-> rectangle)NUMBER OF TILES:- TO FIND

IT IS GIVEN THAT DESIGN AND SIZE OF TILES R SAME SO WE CAN CONSIDER THAT SAME NUMBER OF TILES WILL COVER SAME AREA IN BOTH CASE.

WE CAN USE UNITARY METHOD FOR SOLVING THIS:-

[tex]6ft² \: is \: covered \: using \: 200 \: tiles \\ 1ft² \: is \: covered \: using \: \frac{200}{6} \: tiles \\ 150ft² \: is \: covered \: using \: \frac{200 \times 150}{6} \: tiles \\ 150ft² \: is \: covered \: using \: \frac{200 \times \cancel{150}^{ \: \: 25} }{ \cancel6 {}^{ \: 1} } \: tiles \\ 150ft² \: is \: covered \: using \: 200 \times 25 \: tiles \\ 150ft² \: is \: covered \: using \: 5000 \: tiles[/tex]

The Online Exam from Applied Statistics consists of 6 questions. Statistics show that there is a 75% chance that the student will answer to any one of Exam problems correctly. If the number of attempts for each question is unlimited, find the following probabilities

a. The student will correctly answer the first question after the 4th attempt.
b. The student will correctly answer three questions after 10 total attempts.
c. What is the average number and SD of attempts up to when the student answers all the questions correctly?

Answers

Solution :

a). The probability that the student will [tex]\text{correctly answer}[/tex] the 1st question after the 4th attempt.

P (correct in the 4th attempt)

= [tex]$(1-0.75)^3 \times 0.75$[/tex]

= 0.01171875

b). The probability that the student will [tex]\text{correctly answer}[/tex] 3 questions after 10 total attempts.

P( X = 3) for X = B in (n = 10, p = 0.75)

= [tex]$C(10,30) \times 0.75^3 \times 0.25^7$[/tex]

= 0.0031

c). The mean and the standard deviation for the number of attempts up to when the students gets all the questions correct is :

There are = 6 success, p = 0.75.

Therefore, this is a case of a negative binomial distribution.

[tex]$E(X)=\frac{k}{p}$[/tex]

         [tex]$=\frac{6}{0.75}$[/tex]

         = 8

So, [tex]$\sigma = \frac{\sqrt{k(1-p)}}{p}$[/tex]

     [tex]$\sigma = \frac{\sqrt{6(1-0.75)}}{0.75}$[/tex]

        = 1.6330

Which equation has a graph that is a parabola with a vertex at (-2, 0)?
y= -2x^2
y = (x + 2)^2
y= (x – 2)^2
y= x^2 – 2

Answers

y=(x+2)^2 has a vertex at (-2,0)

Armando planted a 9-inch tall magical beanstalk. The height of the beanstalk increases by 13% each day. Write a function f that determines the height of the beanstalk in inches in terms of the number of days t since Armando planted the beanstalk.

Answers

Answer:

F(t) = 9(1 + 0.13)^t

Step-by-step explanation:

Given :

Height of beanstalk = initial height = 9 inches

Percentage increase in height per day = 13%

This plant exhibits an exponential increase in growth per day, hence, the function will be modeled using an exponential function.

Using an exponential function :

F(t) = initial height(1 + percentage increase)^t

Where, t = number of days since tree was planted.

The function is :

F(t) = 9(1 + 0.13)^t

I need help please can not figure out this problem

Answers

1. (2x-3)(x-4)
2x(x) =2x^2
2x(-4)= -8x
-3(x)= -3x
-3(-4)= 12
2x^2 -8x-3x+12= 2x^2 -11x+12

2. (x+2)(x+5)
x^2+5x+2x+10= x^2 +7x+10

3. (3x-1)(x+2)
3x^2 +6x-x-2= 3x^2+5x-2

a bus carry 53 passengar on a trif. how many passenger can 9 such carry if each dose 2 trif

Answers

Answer:

954 passengers

Step-by-step explanation:

(Assuming I read the question correctly)

1 bus can carry in 1 trip = 53 passengers

1 bus can carry in 2 trips : 106 passsengers

9 busses can carry in 2 trips = 106 x 9 = 954

Answred by Gauthmath

Other Questions
If the slope of the budget line changes, there MUST have been a change in the consumer's preferences. an increase in the consumer's income. a change in the price of at least one good. a change in the price of both goods. None of these please answer this question!! Which of the following was a major turning point in the history of Vietnam's struggle fornational independence?The election of President Dwight D. EisenhowerThe formation of NATOO The Battle at Dien Bien PhuThe Korean War Carl Linnaeus developed a two-word system for naming organisms. It is called . 13. Describe small intestine and its function. The Japanese economy has been experiencing slow growth. As a result the Prime Minister, who thinks John Maynard Keynes was the greatest economist ever, has decided to increase government spending. As head of the economic council the Prime Minister asks you to determine the size of the increase needed to bring the economy to full employment. Assume there is a GDP gap of 1 billion yen and the marginal propensity to consume (MPC) is .60. What advise do you give the Prime Minister? a. The recessionary gap is equal to 625 million yen. b. The inflationary gap is equal to 1 billion yen divided by 2.5 or 0.4 billion yen. c. The recessionary gap is equal to 1 billion yen divided by 2.5 or 0.4 billion yen. d. The inflationary gap is equal to 1 billion yen divided by 1.66 or 0.625 billion yen. The New England Merchants Bank Building in Boston is 152 m high. On windy days it sways with a frequency of 0.18 Hz , and the acceleration of the top of the building can reach 1.9 % of the free-fall acceleration, enough to cause discomfort for occupants.Required:What is the total distance, side to side, that the top of the building moves during such an oscillation? Find the distance traveled by a particle with position (x, y) as t varies in the given time interval.x = 3 sin^2(t), y = 3 cos^2(t), 0< t Teresa has $451 in a personal bank account,and then withdraws $10 per week.Andrew has $10 in a personal bank account,and then deposits $53 earned from dog grooming each week.After how many weeks will they have the same amount of money in the bank. sepak bola mini termasuk jenis permainan bola 1. Estimate the buoyant force that air exerts on a man. (To do this, you can estimate his volume by knowing his weight and by assuming that his weight density is about equal to that of water. Assume his weight is 940 N.) answer in N2.On a perfect fall day, you are hovering at low altitude in a hot-air balloon, accelerated neither upward nor downward. The total weight of the balloon, including its load and the hot air in it, is 17000 N.(a) What is the weight of the displaced air? answer in N(b) What is the volume of the displaced air? answer in m^3 Ava is obese and concerned about her risk of cancer. Several of her family members are obese as well, and a few of them have either died of cancer or currently have the disease. Ava knows that she has to make some lifestyle changes to reduce her risk of certain cancers.Because Ava is obese, her risk of developing ______________ cancer is higher than a person who is not obese. lung brain skin colon what is a first prime minister of India? Mr. Rodriguez has a cancerous tumor in his lower abdomen. The cancer does not involve any organs, Is encapsulated, and has not spread to other areas of the body. What treatment option will Mr. Rodriguez's cancer specialist MOST LIKELY recommend?1. radiation2. a combination therapy of surgery followed by chemotherapy3. chemotherapy4. surgery 1)Which theme from Macbeth do these lines support?If good, why do I yield to that suggestionWhose horrid image doth unfix my hairAnd make my seated heart knock at my ribs,Against the use of nature? Darkness is dangerous. Ambition unchecked can lead to corruption. Things are not always what they seem. Those without convictions are easily manipulated.2) Which of the following is a theme from Macbeth? Those without convictions are easily manipulated. The visible is more dangerous than the invisible. Firm beliefs will help you succeed. Friendship can withstand any challenge. what is it about American culture that allows homelessness to occur?? Find mF=.....................................................What would it equal??mF= what is it??? help please ITS OF TRIGONOMETRYPROVE Rays weight increased by 11% in the last two years. If he gained 16.5 pounds, what was his weight two years ago? Find out other examples of bodies showing more than one type of motion Tabulate your findings.