The plot below shows the amount of time Mira spent on maths questions. If Mira had spent the same total amount of time, but spent an equal amount of time on each problem, how many minutes would each problem have taken?

Answers

Answer 1

Answer:

See explanation

Step-by-step explanation:

Given

[tex]n = 5[/tex] --- number of questions

Required

The time spent on each question

The question has missing details, as the required plot to calculate the total time is not given.

However, the formula to use is as follows

[tex]Each = \frac{Total}{n}[/tex]

Substitute 5 for n

[tex]Each = \frac{Total}{5}[/tex]

Assume the calculated total time is 60 minutes; The equation becomes

[tex]Each = \frac{60}{5}[/tex]

[tex]Each = 12\ mins[/tex]

Answer 2

Answer:

9 minutes

Step-by-step explanation:

I got it wrong from the other guy so i put get help and that's the Awnser LOL


Related Questions

What is the y-intercept of the line shown?
1
0
10
2
4
-10
ОО
01
03
3.5

Answers

Answer:

y-intercept = 3

Step-by-step explanation:

value that's on the y - axis

sin(2x-pi/2)=sin pi/3

Answers

This is the answer for your question!

Write these sums as decimals:

2/100 + 3/1,000 =

1/10 + 4/10,000 =

Answers

Answer:

1 ) 0.023

2 ) 0.1004

Step-by-step explanation:

2 / 100 + 3 / 1000

= 0.02 + 0.003

= 0.020 + 0.003

= 0.023

1 / 10 + 4 / 10,000

= 0.1 + 0.0004

= 0.1000 + 0.0004

= 0.1004

if f(x) = 2x/2x+1 and g(x) = 1/2x+1, find f(x) / g(x)

Answers

Answer:

2x

Step-by-step explanation:

Just solve the function operation:

f/g=(2x/2x+1)/(1/2x+1) = 2x since (2x/1)/(2x+1/2x+1) simplifies to 2x/1 the answer is 2x

Simplify the following, leaving your answer with a positive exponent:
x^-12/ x^-7

Answers

Answer:

[tex]\frac{1}{x^{5} }[/tex]

Step-by-step explanation:

x^-12/ x^-7

= x^(-12-(-7))

= x^-5

= 1/x^5

Find the real or imaginary solutions by factoring.
X^4 -3x^2 = -2x^2

Answers

Look in the images it is solved.

Which of the following statements is false?

Answers

Answer:

option D is false it's not parallelogram

20 points PLEASE HELP IT'S DUE TODAY

Answers

Answer:

Step-by-step explanation:

Arc length of the circle is given by,

Arc length = [tex]\frac{\theta}{360^{\circ}}(2\pi r)[/tex]

Area of the sector of a circle = [tex]\frac{\theta}{360^{\circ}}(2\pi r)[/tex]

22). Arc length of the circle having central angle = [tex]\frac{\pi}{3}[/tex]

                                                                                 = 60°

Arc length = [tex]\frac{60^{\circ}}{360^{\circ}}(2\pi )(7)[/tex]

                 = [tex]\frac{14\pi }{6}[/tex]

                 = 7.33 cm

23). Arc length of the circle having central angle = 225°

Arc length = [tex]\frac{225^{\circ}}{360^{\circ}}(2\pi )(10)[/tex]

                 = 12.5π

                 = 39.27 km

24). Central angle = [tex]\frac{5\pi }{4}[/tex]

                              = [tex]\frac{5\times 180^{\circ}}{4}[/tex]

                              = 225°

Area of the sector = [tex]\frac{225^{\circ}}{360^{\circ}}(2\pi )(11)[/tex]

                               = 43.20 yd²

25). Area of the sector = [tex]\frac{270^{\circ}}{360^{\circ}}(2\pi )(14)[/tex]

                                      = 65.97 yd²

ASAP!! can i get help on this one and can i please get a vivid explanation thank you.

Answers

Answer:

3x + 11

Step-by-step explanation:

1) Remove Parentheses:

x + 4 + 2x + 7

2) Combine Like Terms:

(2x + x) and (4 + 7)

3) Simplify:

3x + 11

Hope this helps, good luck! Have a good day. :)

Solve the following equation |2x+3|+|x-2|=6x

Answers

Recall the definition of absolute value:

• |x| = x if x ≥ 0

• |x| = -x if x < 0

So you need to consider 4 different cases (2 absolute value expressions with 2 possible cases each).

(i) Suppose 2x + 3 < 0 and x - 2 < 0. The first inequality says x < -3/2 and the second says x < 2, so ultimately x < -3/2. Then

|2x + 3| + |x - 2| = 6x

-(2x + 3) - (x - 2) = 6x

-2x - 3 - x + 2 = 6x

-3x - 1 = 6x

9x = -1

x = -1/9

But -1/9 is not smaller than -3/2, so this case provides no valid solution.

(ii) Suppose 2x + 3 ≥ 0 and x - 2 < 0. Then x ≥ -3/2 and x < 2, or -3/2 ≤ x < 2. Under this condition,

|2x + 3| + |x - 2| = 6x

(2x + 3) - (x - 2) = 6x

2x + 3 - x + 2 = 6x

x + 5 = 6x

5x = 5

x = 1

This solution is valid because it does fall in the interval -3/2 ≤ x < 2.

(iii) Suppose 2x + 3 < 0 and x - 2 ≥ 0. Then x < -3/2 or x ≥ 2. So

|2x + 3| + |x - 2| = 6x

-(2x + 3) + (x - 2) = 6x

-2x - 3 + x - 2 = 6x

-x - 5 = 6x

7x = -5

x = -5/7

This isn't a valid solution, because neither -5/7 < -3/2 nor -5/7 ≥ 2 are true.

(iv) Suppose 2x + 3 ≥ 0 and x - 2 ≥ 0. Then x ≥ -3/2 and x ≥ 2, or simply x ≥ 2.

|2x + 3| + |x - 2| = 6x

(2x + 3) + (x - 2) = 6x

2x + 3 + x - 2 = 6x

3x + 1 = 6x

3x = 1

x = 1/3

This is yet another invalid solution since 1/3 is smaller than 2.

So there is one solution at x = 1.

A square has an area of 49 cm squared what is the length of each side

Answers

Answer:

7

Step-by-step explanation:

[tex]s = {a}^{2} \: thus \: a = \sqrt{s } = \sqrt{49} = 7[/tex]

The length of the of each side of square is 7

How do I find x ………..

Answers

Answer:

x = 94

Step-by-step explanation:

The sum of the 4 angles in a quadrilateral = 360°

Sum the 4 angles and equate to 360

x + x + 2x - 75 + x - 35 = 360

5x - 110 = 360 ( add 110 to both sides )

5x = 470 ( divide both sides by 5 )

x = 94

could someone help me with this (picture) please explain if you could I don't really understand.

Answers

Answer:

10t + D = 40

Step-by-step explanation:

y = mx + b is the equation of a line in slope intercept form. We'll be using this equation since the slope, or distance traveled, is steady (linear). In this case, the slope is 10 since Sarah's pace is 10 km/hr. m is the slope, so m = 10.

y = 10x + b. However, she needs to run 40 km. So we're going to substitute 40 in for y.

40 = 10x + b. Now, we need to use t instead of x since that's what's been asked of us. (The slope represents the distance traveled over time, so t fits.)

10t + b = 40

b needs to become D, the distance in kilometers.

So now we have 10t + D = 40

Answer:

D(t)= 40-10t

Step-by-step explanation:

#KmNn

1 point Write the equation of the line that is parallel to the line given and through the given point. Do not use spaces in your equation y=-x-3 (-3,4)​

Answers

Answer:

y=3x+9......(i)

y=-4x-12...(ii)

these are the equation

What is the distance in units between the points (4, -7) and (1, -7)?

Answers

I think it’s 3 I used a calculator online not sure if it’s right.

Step-by-step explanation:

To evaluate such, the following formula is required:

Distance Formula: d(P, Q) = √ (x2 − x1)^2 + (y2 − y1)^2

Denote the following points as the following,

(4, -7). (1, -7)

X1 Y1. X2. Y2

D(P, Q) = √(1 - 4)^2 + (-7 + 7)^2. <== Since there is a double negative, such will be considered addition.

√(-3)^2 + (0)^2

√9 = 3

Thus, the agglomerate distance of such points on the Cartesian plane is disclosed as 3 units.

Meg initially has 3 hours of pop music and 2 hours of classical music in her collection. Every month onwards, the hours of pop music in her collection is 5% more than what she had the previous month. Her classical music does not change. Which function shows the total hours of music she will have in her collection after x months

Answers

Answer:

The answer is "[tex]f(x) = 3(1.05)x + 2[/tex]".

Step-by-step explanation:

She starts off with 3 hours with pop music.

Next month, she will have 3 hours she has had and + 3*0.05.

3hrs + 3*0.05hrs = 3*1.05 hrs

We add 2 hours of classical music to the 3 * 1.05 hours to achieve 3 * (1.05) hours + 2 hours of classical music.

Answer: f(x):2(0.05)^x+3

solve for x. Round to the nearesr tenth of a degree if necessary.

Answers

Answer:

im not sure but i got 30.1

Step-by-step explanation:

[tex] \cos(x) = \frac{45}{52} \\ x = 30.1[/tex]

A set of composite number less than 12.Express it in listing and set-builder methods

Answers

composite numbers less than 12={1,3,4,6,8,9,10}

What shape is this? I’m so confused and I need to get this done really quickly!

Answers

The shape is an irregular pentagon

a) In a group of 60 students, 15 liked maths only, 20 liked science only and 5 did not like
any of two subjects?
(i) How many of them liked at least one subject?
(ii) Find the number of students who liked both the subjects.
(iii) How many of them liked maths?
(iv) How many of them liked science?
(v) Represent the result in a Venn diagram.


PLZ PLZ HELP.........​

Answers

Part (i)

We have 60 students total, and 5 didn't like any of the two subjects, so that must mean 60-5 = 55 students liked at least one subject.

Answer: 55

=========================================================

Part (ii)

We have 15 who like math only, 20 who like science only, and 55 who like either (or both). Let x be the number of people who like both classes.

We can then say

15+20+x = 55

x+35 = 55

x = 55-35

x = 20

This means 20 people liked both subjects

Answer: 20

=========================================================

Part (iii)

There are 15 people who like math only, and 20 who like both. Therefore, there are 15+20 = 35 people who like math (and some of these people also like science)

Answer: 35

=========================================================

Part (iv)

We'll follow the same idea as the previous part. There are 20 people who like science only and 20 who like both subjects. That yields 40 people total who like science (and some of these people also like math).

Answer: 40

=========================================================

Part (v)

We'll draw a rectangle to represent the entire group of 60 students. This is considered the universal set. Inside the rectangle will be two overlapping circles to represent math (M) and science (S).

We'll have 15 go in circle M, but outside circle S to represent the 15 people who like math only. Then we have 20 go in circle S but outside circle M to show the 20 people who like science only. We have another copy of 20 go in the overlapped region between the circles. This is the 20 people who like both classes. And finally, we have 5 go outside both circles, but inside the rectangle. These are the 5 people who don't like either subject.

Note how all of the values in the diagram add up to 60

15+20+20+5 = 60

This helps confirm we have the correct values.

Answer: See the venn diagram below

La señora Angélica fue al mercado y compró 2 visores protectores y 1 mascarilla, pagó $55.00, en total. En el mismo puesto, la señora Silvia compró 1 visor protector y 2 mascarillas y pagó $50.00. ¿Cuál es el precio de una mascarilla? ¿Cuáles el precio de un visor protector?

Answers

Answer:

Cost of 1 goggles = $20

Cost of 1 mask = 15

Step-by-step explanation:

Given:

Cost of 2 goggles and 1 mask = $55

Cost of 1 goggles and 2 mask = $50

Find:

Cost of each goggles and mask

Computation:

Assume;

Cost of 1 goggles = a

Cost of 1 mask = b

So,

2a + b = 55.....EQ1

a + 2b = 50.......EQ2

EQ1 x 2

4a + 2b = 110 ......EQ3

EQ3 - EQ2

3a = 60

a = 20

Cost of 1 goggles = $20

a + 2a = 50

20 + 2b = 50

2b = 30

b = 15

Cost of 1 mask = 15

.

Find g(5)+h(2)
g(x)=2x-5
h(x)=4x+5

Answers

Step-by-step explanation:

g(5)=2(5)-5=5

h(2)=4(2)+5=13

g(5)+h(2)=5+13=18

Out of 120 students in exam, 2/3 of them passed. How many students passed?​

Answers

Out of 120 students in exam, 2/3 of them passed. How many students passed?

now,

no of students passed = 2/3×120

= 0.66×120

=80...

therefore 80 students were passed....

Answer:

80

Step-by-step explanation:

Please Help!Please Help!Please Help!Please Help!Please Help!Please Help!Please Help!Please Help!Please Help!Please Help!Please Help!Please Help!Please Help!

Answers

Answer:

  (a)  no solution

Step-by-step explanation:

Writing the second equation in slope-intercept form, it becomes ...

  3x -y = 2 . . . . given

  y = 3x -2 . . . . add y-2 to both sides

The first equation is already in slope-intercept form:

  y = 3x +3 . . . . first equation

The coefficients of x in the two equations are both 3, so the lines they describe are parallel. They do not intersect, so there is no solution.

Unit Rates
Assignment Active
Completing a Rate Table
Miles
Hours
Margie can walk 3.5 miles in 1 hour.
Find the values of a, b, c, and that complete the table
showing this relationship
3.5
a=
7
v
a
5
3
d=
14
e
5

Answers

Answer:

its c

Step-by-step explanation:

i did it on ed

Answer:

Heres the answer!

Step-by-step explanation:

Which of the following numbers are solutions of the sentence x-3 < 2?
I -3
II 0
III 2
IV 5

O ll only
O III only
O I and III only
O I, II, and III only
O I, II, III, and IV​

Answers

Answer:

O I, II, and III only

Step-by-step explanation:

x-3 < 2

Add 3 to each side

x-3+3< 2+5

x<5

-3 is less than 5

0 is less than 5

2 is less than 5

5 is not less than 5

I , II , II are true

PLEASE HELP ME ASAP!!!

Answers

Answer:

5.30

Step-by-step explanation:

Total cost = flat fee + cost per mile * number of miles

              c(m)  = 3.50 + .60m

Let m=3

c(3)  = 3.50 + .60(3)

    = 3.50 + 1.80

    =5.30

Answer:

B: $5.30

Step-by-step explanation:

Each mile is $0.6, to get the result for 3 miles we would need to multiply $0.6 by 3. $0.60 * 3 = $1.8. Finally we would need to add the 3.50 to $1.8 resulting in $5.30

Help if you know thanks

Answers

x= - 1/2,-1

or

x= - 0.5, -1

Answer:

x = -1/2  x=-1

Step-by-step explanation:

2x( x+1.5) = -1

Distribute

2x^2 + 3x = -1

Add 1 to each side

2x^2 +3x+1 = 0

Factor

(2x+1) (x+1) =0

Using the zero product property

2x+1 = 0   x+1=0

2x = -1    x=-1

x = -1/2  x=-1

Eve got home from school at 2:20 P.M. And played video games for 17 minutes. Then she helped clean the kitchen for 1 hour and 1 minute and spent 1 hour and 7 minutes finishing her homework. What time was it when Eve finished her homework?

Answers

Answer:

4 :45 pm

Step-by-step explanation:

2 : 20 + 17 minutes = 2:37

2:37 + 1hr 1 minute  = 3 : 38

3 : 38 + 1 hr 7 = 4 :45 pm

Please help out explanation need it

Answers

Answer:

SinA= BC/AC=20/55

SinA=4/11

A=Sin^-1(4/11)

A=Sin^-1(0.36)

LA=21.1 ← ans

OAmalOHopeO

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