The measurements of a circular object are given in the ratio table.

a. Find the missing dimensions of other circular objects by completing the ratio table.

b. Graph the pairs of values.

using Pythagorean triplet

[tex]\\ \sf\longmapsto P^2=H^2-B^2[/tex]

[tex]\\ \sf\longmapsto x^2=19.6^2-15.4^2[/tex]

[tex]\\ \sf\longmapsto x^2=384.16-237.16[/tex]

[tex]\\ \sf\longmapsto x^2=147[/tex]

[tex]\\ \sf\longmapsto x=\sqrt{147}[/tex]

[tex]\\ \sf\longmapsto x=12.1[/tex]

Answer:

C.) 12.1

Step-by-step explanation:

I got it correct on founders edtell

A(t)=P(1+r)t

A = accrued amount = what you are solving for

P = principle investment = $400

r = rate of growth = 5% = 0.05

t = time = 10 years

A(10) = 400(1.05)10 (use calculator to solve)

A(10) ≈ 4,200

Answer:

The answer is D  

Step-by-step explanation:

there are 8 1/6 five and one sixth in 2/3

Answer:

2.63%

Step-by-step explanation:

11.3/100*23.3/100*100%

Answer:

Hello,

Step-by-step explanation:

[tex]\dfrac{3^{n+1}+9}{3^{n-1}+1} \\\\=\dfrac{9*(3^{n-1}+1)}{3^{n-1}+1}\\\\=9\\[/tex]

Step-by-step explanation:

hope it helps you.......

[tex]\\ \sf\longmapsto 699^2[/tex]

[tex]\\ \sf\longmapsto (700-1)^2[/tex]

[tex]\\ \sf\longmapsto 700^2-2(700(1)+(1)^2[/tex]

[tex]\\ \sf\longmapsto 490000-1400+1[/tex]

[tex]\\ \sf\longmapsto 488600+1[/tex]

[tex]\\ \sf\longmapsto 488601[/tex]

Using Pythagorean Theorem

[tex]\\ \sf\longmapsto H^2=P^2+B^2[/tex]

[tex]\\ \sf\longmapsto H^2=8^2+15^2[/tex]

[tex]\\ \sf\longmapsto H^2=64+225[/tex]

[tex]\\ \sf\longmapsto H^2=289[/tex]

[tex]\\ \sf\longmapsto H=\sqrt{289}[/tex]

[tex]\\ \sf\longmapsto H=17[/tex]

Answer:

[tex] = - \frac{1}{36(6x + 1) ^{6} } + c[/tex]

Answer:

[tex]-\frac{1}{36\left(6x+1\right)^6} +C[/tex]

Step-by-step explanation:

we're going to us u substitution

[tex]\int (6x+1)^-7 dx[/tex]

[tex]u=6x+1[/tex]

[tex]\int\frac{1}{6u^7} du[/tex]

take out the constant, [tex]\frac{1}{6}[/tex]

[tex]\frac{1}{6}[/tex] · [tex]\int u^-7du[/tex]

next use the power rule, [tex]\int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1[/tex]

[tex]\frac{1}{6}\cdot \frac{u^{-7+1}}{-7+1}[/tex]

simplify by substituting [tex]6x+1[/tex] for [tex]u[/tex]

[tex]\frac{1}{6}\cdot \frac{(6x+1)^{-7+1}}{-7+1} = -\frac{1}{36\left(6x+1\right)^6}[/tex]

add a constant, [tex]C[/tex]

[tex]-\frac{1}{36\left(6x+1\right)^6} +C[/tex]

Answer:

Point E.

.................

HA

See In Triangle DEF and Triangle XZY

[tex]\because\begin{cases}\sf \angle E=\angle Z=90° \\ \sf \ FD\sim XY=Hypotenuse\end{cases}[/tex]

Hence

[tex]\sf \Delta DEF\sim \Delta XZY(Angle-Angle)[/tex]

The theorems that verify that Δ DEF ~ Δ XZY is AA theorem of similarity.

Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion.

Given that, two triangles, Δ DEF and Δ XZY, we need to find a theorem that will verify that, Δ DEF and Δ XZY are similar,

So, we have, ∠ X = 40°,

Therefore, ∠ Y = 90°-40° = 50°

Now, we get,

∠ Y = ∠ F = 50°

∠ E = ∠ Z = 90°

We know that,

if two pairs of corresponding angles are congruent, then the triangles are similar.

Therefore, Δ DEF ~ Δ XZY by AA rule

Hence, the theorems that verify that Δ DEF ~ Δ XZY is AA theorem of similarity.

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Answer:

x1 = 3

Step-by-step explanation:

first set up the proportion (write as fractions):

(y1/x1) = (y2/x2)

then fill in the variables:

4/x1 = 8/6

now cross multiply:

8 • x1 = 6 • 4

simple algebra:

8 • x1 = 24

x1 = 24/8

x1 = 3

If y1 = 4, x2 = 6, and y2 = 8, then the value of x1 is 3 which we can solve using ratios.

In a directly proportional relationship, the ratios between the corresponding values of two variables remain constant. This constant ratio is often referred to as the "proportionality constant."

In this problem, you have two pairs of values: (x1, y1) and (x2, y2). We're given that the ratios are directly proportional, which means:

x1 / y1 = x2 / y2

Plugging in the given values:

x1 / 4 = 6 / 8

Now, cross-multiply to solve for x1:

x1 * 8 = 4 * 6

x1 = 24 / 8

x1 = 3

Therefore, the value of x1 is 3.

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Answer:

2

Step-by-step explanation:

Pythagoras. c² = a² + b²

since both "side angles" are equal (45 degrees), we know it is an isosceles triangle, that means also the other side = x.

and so,

8 = x² + x² = 2x²

4 = x²

x = 2

Answer:

x = 2

Step-by-step explanation:

sin(45)/x = sin(90)/[tex]\sqrt{8}[/tex]

[tex]\sin \left(45^{\circ \:}\right)=\frac{\sqrt{2}}{2}[/tex]

x = [tex]\sqrt{8}[/tex] [tex]\sin \left(45^{\circ \:}\right)[/tex]

[tex]x = \sqrt{8} \frac{\sqrt{2}}{2}[/tex]

x = [tex]\frac{\sqrt{16} }{2}[/tex]

x = 4/2

x = 2

Answer:

z -2 = 10

Step-by-step explanation:

11z-9-10z+7 = 10

Combine like terms on the left side

11z -10z     -9+7  =10

z -2 = 10

Answer: z=12

Step-by-step explanation:

[tex]11z-9-10z+7=10\\z-9+7=10\\z-2=10\\z=12[/tex]

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

y = x³

x = ∛y

Switch x and y:

y = ∛x

f⁻¹(x) = ∛x

f⁻¹(12) = ∛12 ≅ 2.29

check:

x = 2.29

f(x)  = 2.29³ ≅ 12

9514 1404 393

Answer:

Step-by-step explanation:

Let x represent the enrollment the first year. Then x(1 -8%) = 0.92x represents the enrollment the second year. The total for the two years is ...

  x + 0.92x = 13,876

  x = 13,876/1.92 = 7227.083 ≈ 7227 . . . . students the first year

  13876 -7227 = 6649 . . . . students the second year

Answer:

4

Step-by-step explanation:

If 1/20 of the metal is lost during casting. Calculate the number of complete slabs casted. (4mks)

Answer:

3/2

Step-by-step explanation:

y2 - y1 / x2 - x1

1 - 7 / -5 - (-1)

-6 / -4

= 3/2

Answer:

m=3/2

Step-by-step explanation:

m=y2-y1/x2-x1

m=1-7/-5-(-1)

m=-6/-4

m=3/2

9514 1404 393

Answer:

  about 3,160,000,000

Step-by-step explanation:

"Increases at a rate proportional to population" means the growth is exponential. It can be modeled by the equation ...

  p = ab^t

We can find 'a' and 'b' using the given data points.

  100 = ab^(-4) . . . . . . . population 4 days ago

  100,000 = ab^(-2) . . . population 2 days ago

Dividing the second equation by the first, we find ...

  1000 = b^2

  b = 1000^(1/2)

Substituting for b in the first equation, we have ...

  100 = a(1000^(1/2))^(-4) = a(1000^-2)

  100,000,000 = a

Then the population model is ...

  p = 100,000,000×1000^(t/2)

__

Tomorrow (t=1), the population will be ...

  p = 100,000,000 × 1000^(1/2) ≈ 31.6 × 100,000,000

  p ≈ 3,160,000,000 . . . . . bacteria by tomorrow

_____

Additional comment

We could write this as ...

  p = 10^(8+1.5t)

Then for t=1, this is p = 10^(8+1.5) = 10^0.5 × 10^9 = 3.16×10^9

Answer:

$50

Step-by-step explanation:

Let x represent the cost of the cell phone.

Since the TV cost 5 times as much as the cell phone, its cost can be represented by 5x.

Since the computer cost 2.5 times as much as the TV, its cost can be represented by 12.5x.

Create an equation to represent the situation, and solve for x:

x + 5x + 12.5x = 925

18.5x = 925

x = 50

So, the cell phone cost $50

Answer:

$50

Step-by-step explanation:

Let x represent the cost of the cell phone.

Since the TV cost 5 times as much as the cell phone, its cost can be represented by 5x.

Since the computer cost 2.5 times as much as the TV, its cost can be represented by 12.5x.

Create an equation to represent the situation, and solve for x:

x + 5x + 12.5x = 925

18.5x = 925

x = 50

So, the cell phone cost $50

Answer:

the answer is 240 degrees

Answer: Dimension = 27 inches by 39.75 inches

Concept:

A perimeter is a path that encompasses/surrounds/outlines a shape.

Perimeter (rectangle) = 2 (l + w)

l = length

w = width

Solve:

l = 2w - 14.25

w = w

P = 133.5

Given equation

P = 2 (l + w)

Substitute values into the equation

133.5 = 2 (2w - 14.25 + w)

Combine like terms

133.5 = 2 (3w - 14.25)

Distributive property

133.5 = 6w - 28.5

Add 28.5 on both sides

133.5 + 28.5 = 6w - 28.5 + 28.5

162 = 6w

Divide 6 on both sides

162 / 6 = 6w / 6

w = 27 in

l = 2w - 14.25 = 2 (27) - 14.25 = 39.75 in

Hope this helps!! :)

Please let me know if you have any questions

We can conclude that if (c, f(c)) is a point of inflection of the graph of f and f'' exists in an open interval that contains c, then f''(c)=0.

The process of finding derivatives of a function is called differentiation in calculus. A derivative is the rate of change of a function with respect to another quantity.

We can prove this statement using the First Derivative Test and Fermat's Theorem.

First, we know from the First Derivative Test that at a point of inflection, the first derivative of the function (in this case, f') must equal 0. Therefore, at the point (c, f(c)), f'(c) = 0.

Next, we can apply Fermat's Theorem. This theorem states that if a function f has a local maximum or minimum at c, then f'(c) = 0. Since the point (c, f(c)) is a point of inflection, we can apply Fermat's Theorem to say that f'(c) = 0.

Now, since f'' exists in an open interval that contains c, we can use the fact that if f'(c) = 0, then f''(c) = 0.

Therefore, we can conclude that if (c, f(c)) is a point of inflection of the graph of f and f'' exists in an open interval that contains c, then f''(c)=0.

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Answer:

Mean = 36.67

Median = 36.5

Mode = 38

Step-by-step explanation:

Mean = [(35*8) + (37*7) + (37*4) + (38*9) + (39*2)] / (8+7+4+9+2)

Mean = (280 + 252 + 148 + 342 + 78) / 30

Mean = 1100 / 30 = 36.67

Median = Frequency of 35 and 36 is 15 total. Frequency of 37, 38, and 39 is the remainder 15 total. (36+37)/2 = 36.5

Mode = the most frequently-ocurring number = 38 (frequency of 9)

Answer:An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. For instance, the sequence 5, 7, 9, 11, 13, 15.. . is an arithmetic progression with a common difference of 2.

Step-by-step explanation:

Answer:

{(0, 0), (1, ⅔), (2, 4/3), (3, 2)…}

Answer:

Step-by-step explanation:

The diagrammatic expression to understand this question very well is attached in the image below.

By applying the law of cosine rule; we have:

From the diagram attached below, we need to determine the side "b" by using equation (2) from above:

b² = a² + c² - 2ac Cos B

From the information given:

a = 12 miles;  c = 18 miles;   ∠B = 38°

∴

replacing the values into the above equation:

b² = 12² + 18² - 2(12)(18) Cos (38°)

b² = 144 + 324 - 432 × (0.7880)

b² = 468 - 340.416

b² = 127.584

[tex]b = \sqrt{127.584}[/tex]

b = 11.30 miles

However, we are also being told that the speed from A → C = 6.8 mph

Thus, the time required to go from A → C  can be determined by using the relation:

[tex]\mathbf{speed = \dfrac{distance}{time}}[/tex]

making time the subject of the formula, we have:

[tex]\mathbf{time= \dfrac{distance}{speed }}[/tex]

[tex]\mathbf{time= \dfrac{11.30}{6.8}}[/tex]

time = 1.66 hours

By using the paved roads, the speed is given as = 22 mph

thus, the total distance covered = |AB| + |BC|

= (18+12) miles

= 30 miles

∴

[tex]\mathbf{time= \dfrac{distance}{speed }}[/tex]

[tex]\mathbf{time= \dfrac{30}{22}}[/tex]

time = 1.36 hours

Therefore, the time used off-road = 1.661 hours while the time used on the paved road is 1.36 hours.

Since we are considering the shortest time possible;

We can conclude that it would be faster for the bicyclist to ride from A to C on the paved roads since it takes a shorter time to reach its destination compared to the time used off-road.

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It would be faster for the bicyclist to ride from A to C on the paved roads since the time to go from A to C on the paved roads is 1.4 h and the time to go from A to C off-road is 1.7 h.        

To calculate which way would be faster we need to find the distance from point A to C with the law of cosines:

[tex] \overline{AC}^{2} = \overline{AB}^{2} + \overline{BC}^{2} - 2\overline{AB}\overline{BC}cos(38) [/tex]

Where:

[tex]\overline{AB}[/tex]: is the distance between the point A and B = 18 mi

[tex]\overline{BC}[/tex]: is the distance between the point B and C = 12 mi        

[tex] \overline{AC} = \sqrt{(18 mi)^{2} + (12 mi)^{2} - 2*18 mi*12 mi*cos(38)} = 11.3 mi [/tex]

Now, let's find the time for the two following cases.

1. From point A to C on the paved roads (t₁)

[tex] t_{1} = t_{AB} + t_{BC} [/tex]

The time can be calculated with the following equation:

[tex] t = \frac{d}{v} [/tex]    (1)

Where:

d: is the distance

v: is the velocity

Then, the total time that it takes the bicyclist to go from point A to C on the paved roads is:

[tex] t_{1} = t_{AB} + t_{BC} = \frac{18 mi}{22 mph} + \frac{12 mi}{22 mph} = 1.4 h = 84 min [/tex]

2. From point A to C off-road (t₂)

With equation (1) we can calculate the time to go from point A to C off-road:

[tex] t_{2} = \frac{\overline{AC}}{v_{2}} = \frac{11.3 mi}{6.8 mph} = 1.7 h = 102 min [/tex]

Therefore, it would be faster for the bicyclist to ride from A to C on the paved roads.  

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Answer:

Step-by-step explanation: