If a ants can dig b tunnels in c hours, how many tunnels can b ants dig in a hours?

Answer:

M = (1,3) - 1 right, 3 up

A = (4,0) - 4 right, 0 up

T = (3,6) - 3 right, 6 up

H = (6,2) - 6 right, 2 up

Step-by-step explanation:

Remember, to write the ordered pair using the correct order (x,y) x means it moves either left or right and y moves up or down.

First identify the x-coordinate of a point on a graph. Start at (0,0) which is where the x and y axis meet. (Basically the center of the coordinate plane.)

Then move either left or right and count the number of spaces you move until you are under or over the coordinate. The number of spaces you counted it the x value.

Next, identify the y-coordinate of a point. Now move up or down and count the number of spaces until you meet the coordinate. The number of spaces you counted is the y value.

I tried my best to explain. Let me know if you are still confused.

Answer:

Answer B and C

Step-by-step explanation:

Z is the center of the circle passing through H,G,J:

HZ=85=ZG=ZJ ==> ZJ=85 : B is true

HK=KG=136/2=68: C is true.

The two options that are true are ZK = JL and ZL = JM.

The given information is that ZK, ZL, and ZM are perpendicular bisectors of AGHJ. This means that ZK, ZL, and ZM each bisect one of the sides of triangle AGHJ and form a right angle with that side.

In triangle AGJ, ZK is the perpendicular bisector of AG, so ZK = JL.

In triangle AHJ, ZL is the perpendicular bisector of AH, so ZL = JM.

The other two options are not true. ZK = GH is not true because ZK is the perpendicular bisector of AG, not GH. ZM = MG is not true because ZM is the perpendicular bisector of AH, not MG.

To learn more about perpendicular bisectors, here

https://brainly.com/question/24753075

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[tex]\\ \qquad\quad\sf\longmapsto ^nC_2=^nC_4[/tex]

[tex]\boxed{\sf ^nC_r=\dfrac{n!}{r!(n-r)!}}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{n!}{2!(n-2)!}=\dfrac{n!}{4!(n-4)!}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{2\times 1(n-2)!}=\dfrac{1}{4\times 3\times 2\times 1(n-4)(n-3)(n-2)!}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 2=24(n-4)(n-3)[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 2=24\left\{n(n-3)-4(n-3)\right\}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 2=24(n^2-3n-4n+12)[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 2=24(n^2-7n+12)[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 2=24n^2-168n+288[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 24n^2-168n=-286[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 24n^2-168n+286=0[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 12n^2-84n+143=0[/tex]

[tex]\\ \qquad\quad\bf\longmapsto n=\dfrac{7}{3}\pm \dfrac{1}{3}\sqrt{3}[/tex]

Answer:

n = 6

Step-by-step explanation:

There's a secret formula for this:

If nCx = nCy,

Then n = x + y.

Hence, for this question, n = 2 + 4 = 6

Answer:

hello bro

Step-by-step explanation:

can you translate it on english so i can help you

Answer:

0.70 = 7/10

Step-by-step explanation:

Answer:

70/100 or 7/10 (Simplified)

Step-by-step explanation:

0.70 is basically .70 of 1. You can wrote this as a fraction, 70/100. If you divide 70 by 100, it gives you .70.

If you want to simplify it, it becomes 7/10, and if you divide 7 by 10, it also gives you 0.70.

Depends if you want your fraction simplified or not.

have a great day.

Answer:

Heyy mate... here's ur ans ;)

they asked us to apply pythagarus theorem becoz that theorem proves

that it is rectangle so lets get started

( p - perpendicular / b - base / h - hypotenuse )

a) =>

B = 8.1 m

P = 6.3 m

H = 10.15m

Now applying thm => H^2=p^2+b^2

(8.1)^2 + (6.3)^2 = (10.15)^2

65.61 + 39.69 = 103.02

so now LHS = 105.3 and RHS = 103.02 hence

LHS not equal to RHS

so is not rectangle

b) =>

B = 14.4

P = 5.2

H = 15.31

Now applying thm => H^2=p^2+b^2

(5.2)^2 + (14.4)^2 = (15.31)^2

27.04 + 207.36 = 234.39

LHS = 234.4 and RHS = 234.39

just taking approximation rhs is 234.4

hence

LHS = RHS

so it is a rectangle

please mark it brainliest <3

Answer:

y≤0

Step-by-step explanation:

The line is 0 for all x so y must be the one being manipulated

Because the line is solid and shaded on the negative side, y must be less than or equal to 0

Answer: a = 52/7

Step-by-step explanation:

remove the parentheses, move the constant to the right, calculate, then divide both sides

Answer:

The answer is, a = 52/7, or a = 7.42 in decimal form

Follow the steps below for better explanation:

Start with a volume of a cuboid,

[tex]V=abc=3\cdot2\cdot3=18\mathrm{cm^3}[/tex]

The side of the cube we need equals to the LCM of the cubiod's sides,

[tex]\mathrm{LCM}(a,b,c)=\mathrm{LCM}(3,2,3)=6[/tex]

Now compute the volume of such cube,

[tex]V=\mathrm{LCM}(a,b,c)^3=6^3=216\mathrm{cm^3}[/tex]

Divide the volumes to get how many cubiods are in such cube,

[tex]\dfrac{V_{\mathrm{cube}}}{V_{\mathrm{cubiod}}}=\dfrac{216}{18}=\boxed{12}[/tex]

Hope this helps :)

Answer:

Hi,

Answer: 12

Step-by-step explanation:

lcm(3,2,3)=6

Volume of a cuboid=3*2*3=18 (cm³)

Volume of the cube=6³=216 (cm³)

Number of cuboids=216/18=12.

9514 1404 393

Answer:

  all real numbers

Step-by-step explanation:

The arrows on the ends of the curve indicate that the graph extends to infinity horizontally. The domain is the horizontal extent, so is all real numbers.

__

Additional comment

Apparently, y=-7 is a horizontal asymptote, so the range is y > -7.

Step-by-step explanation:

heres the answer to your

Answer:

3 large frames

Step-by-step explanation:

Let the large frames she bought be x in number and small frames be y in number.

ATQ, 17x+6y=141 and x+y=18. Solving it, we will get x=3 and y=15. So she bought 3 large frames

Answer:

5n-7

simply like terms

Answer:

5n - 7

Step-by-step explanation:

n- 10 + 3 + 4n

n +  4n = 5n

-10 + 3 = -7

5n- 7

Answer:

D

Step-by-step explanation:

Exponential functions always will end up being bigger than quadratic functions and since g(x) is probably the exponential it makes f(x) the quadratic because it is growing slower than the function g(x)

The function g(x) increases faster than the function f(x). Then the correct option is D.

The function is an expression, rule, or law that defines the relationship between one variable to another variable. Functions are ubiquitous in mathematics and are essential for formulating physical relationships.

The table below shows the values of f(x) and g(x) for different values of x.

One of the functions is a quadratic function, and the other is an exponential function.

The quadratic function f(x) will be

f(x) = ax² + bx + c

At x = 1, f(x) will be 3

a + b + c = 3 ...1

At x = 2, f(x) will be 6

4a + 2b + c = 6 ...2

At x = 3, f(x) will be 11

9a + 3b + c = 11 ...3

On solving equations 1, 2, and 3, we have

a = 1, b = 0, and c = 2

Then the quadratic function will be

f(x) = x² + 2

The exponential function g(x) will be given as

g(x) = abˣ

At x = 1, g(x) will be 3

ab = 3 ...4

At x = 2, g(x) will be 9

ab² = 9 ...5

From equations 4 and 5, we have

a = 1 and b = 3

Then the exponential function will be

[tex]\rm g(x) = 3^x[/tex]

More about the function link is given below.

https://brainly.com/question/5245372

Answer:

7

Step-by-step explanation:

if the number is x then you know 2x-9=5

2x=14

x=7

so the number is 7

Answer:

b=14 cm

Step-by-step explanation:

Use pythagorean equation

A^2+b^2=c^2

1^2+b^2=14^2

1+b^2=196

b^2=195

b=13.964

Answer:

33. That means (A) can be any number and b times any number wilo get 0 so any numbr will do

34.It is wrong because if x equals 40 anything multiply that will be more than that and so isnt a good reasoning

Answer:

(a^3/b^7)^2 = (a^6/b^14)

Answer:

B

Step-by-step explanation:

yes, we need two numbers that multiplied with each other results in -48.

that means already that one of them has to be positive and the other negative.

that gives us (with all +/- alternating sign combinations)

2 and 24

3 and 16

4 and 12

6 and 8

to pick from there we see that the "middle" term is -2x.

that means that the absolute value of the negative number has to be 2 more than the positive number (so that when adding the intermediate multiplication terms we end up with -2x).

the only choice is therefore 6 and -8.

and that makes B the right answer.

Answer:

108.82

Step-by-step explanation:

Answer:

15- 6 =9

Step-by-step explanation:

- ×- =+ now above the question .we can say that _ 5×_ 3=15 .similarly _ 2×_ 3 = 6 now,

15 _6 =9

Answer:

c(X)=R(X)

125x+18000=215x

18000=215x-125x

18000=90x (divede both sides by 90)

X=200

Answer:

Answer:

-7.692%

Step-by-step explanation:

a.)Buying: total cost

Total cost= commission + (price per share* # of shares ) ;

Total cost= 12 + (11.06*750)= 12+8295 = $8,307

b.)Net gain or loss;

First, find cash received from sale of stock and deduct commission;

Cash from sale =10.24 * 750= 7,680

deduct commission= 7680-12= $7,668

Gain or loss= sale-cost = 7668-8307 = -$639, meaning there is a loss.

c.) Annual rate of return= (net gain or loss/amount paid)*100%

return= -639/(8307)*100 = -7.692%

Step-by-step explanation:

[tex]\boxed{\sf I=\dfrac{PRT}{100}}[/tex]

[tex]\\ \sf\longmapsto I=\dfrac{2000(12)(2.5)}{100}[/tex]

[tex]\\ \sf\longmapsto I=\dfrac{24000(2.5)}{100}[/tex]

[tex]\\ \sf\longmapsto I=\dfrac{60000}{100}[/tex]

[tex]\\ \sf\longmapsto I=600[/tex]

[tex] \large\begin{gathered} {\underline{\boxed{ \rm {\red{S.I \: = \: \frac{P × R × T}{100} }}}}}\end{gathered} [/tex]

As we know that , first we need to convert 2 years 6 months into years.

[tex] \sf \ \implies \: 1 \: \: year \: = \: 12 \: \: months[/tex]

[tex] \sf \implies \: 2 \: \: years \: \: and \: \: 6 \: \: months \: = \: 30 \: \:months[/tex]

[tex] \sf \implies \: \:\frac{ \cancel{30} \: \: ^{2.5 \: \: years} }{ \cancel{12 \: }} \\ [/tex]

[tex]\bf{\blue{ Time \: = \: 2.5 \: \: years}}[/tex]

[tex]\Large\rm{\orange{ \begin{cases} \large\begin{gathered} {\underline{\boxed{ \rm {\purple{S.I \: = \: \frac{P × R × T}{100} }}}}}\end{gathered} \end{cases}}}[/tex]

[tex] \tt \large \longrightarrow \: \: S.I \: = \: \frac{2000 \: × \: 12 × \: 2.5}{100} \\ [/tex]

[tex] \tt \large \longrightarrow \: \: S.I \: = \frac{60000}{100} \\ [/tex]

[tex]\tt \large \longrightarrow \: \: S.I \: = \frac{600 \cancel0 \cancel0}{1 \cancel0 \cancel0} \\ [/tex]

[tex]\tt \large \longrightarrow \: \: S.I \: = \: 600[/tex]

[tex]\large \underbrace{\textrm {{{\color{navy}{Simple Interest \: = \: 600}}}}}[/tex]