Answer:
Answer
Let height of the room be 'h' m.
∴ length of the room=2hm
breadth of the room=
2
3
hm.
area of 4 walls=
1.60
179.20
=112m
2
2(l+b)×h=112
2(2h+
2
3
h)×h=112
2×
2
7
×h
2
=112
h
2
=
14
112×2
=16
h=
16
=4m
length=4×2=8m, breadth=
2
3
×4=6m
for, tiling the floor area=l×b=8×6=48m
cost of tiling=48×6.75=Rs.324
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
Answer:
Option C, 832 units²
Step-by-step explanation:
l = 8
w = 7
h = 24
Surface area = 2(wl+hl+hw)
=2×(7×8+24×8+24×7)
=832 units²
Answer: YO ITS ANSWER C)832 UNITS[tex]^{2}[/tex] !!!!
Which two ratios represent quantities that are proportional? A 25/28 and 5/7 B 22/33 and 14/21 C 16/13 and 13/16 D 48/60 and 35/42
Answer:
Step-by-step explanation:
Simplify
1/4(1 - 2/3)* + 1/3
Enter your answer in the box as a fraction in simplest form
Answer:
5/12
frsjnjjuvvffklomjyyrx
24 is between what integers
Answer:
23 and 25
Step-by-step explanation:
Integers are whole numbers that are either positive, negative, or zero. Fractions and decimals are not integers. Therefore, 24 is between 23 and 25.
Answer:
Positive 23 and positive 25
Step-by-step explanation:
What is the simplified equation of 3 divided by the sum of the square root of 8 and the square root of 5?
Answer:
3/root8+root9
Step-by-step explanation:
3/root8+root9
Can someone help me on this math question its confusing ill give brainly when right!!!
Answer:
it is <
Step-by-step explanation:
Which of the following statements is false?
Answer:
c
Step-by-step explanation:
AB and CD are opposite sides of quadrilateral.
PLEASE HELP
Find the probability of “landing” in the shaded region of the figures below.
Answer:
Hello,
p=0.1024
Step-by-step explanation:
The probability is the ratio of the areas of the 2 circles:
[tex]p=\dfrac{\pi*8^2}{\pi*25^2} =\dfrac{64}{625} =0.1024[/tex]
Answer:
64/625.
Step-by-step explanation:
Probability = area of small circle / area of the large one
= 8^2 / 25^2
= 64/625
Function: y= x^2 + 5x - 7
Vertex:
Solutions:
( , ) and
( , )
Answer:
Vertex is (-2.5, - 13.25) and x=(-5±sqrt(53))/2
Step-by-step explanation:
x^2+5x-7
x^2+5x+(2.5)^2-(2.5)^2-7
(x+2.5)^2-13.25. Vertex is (-2.5, - 13.25)
Solution of the functions are x=(-5±sqrt(53))/2
Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 20 feet, 18 feet, and 14 feet long. If the two shortest sides of quadrilateral EFGH are 6 feet long and 5 feet long, how long is the 2nd longest side on quadrilateral EFGH?
A. 9.2 feet
B. 6.4 feet
C. 11.7 feet
D. 7.7 feet
Answer:
7.7 ft
Step-by-step explanation:
The third longest side is also the second shortest side.
The 14 ft side of quadrilateral ABCD corresponds to the 6 ft side of quadrilateral EFGH.
14/6 = 18/x
7/3 = 18/x
7x = 18 * 3
7x = 54
x = 54/7
x = 7.7
Answer: D. 7.7 feet
Answer:
Step-by-step explanation:
7.7
Please help ASAP !!!☹️
Answer: quit
Step-by-step explanation:
it’s really easy .
What does the lines mean around the x: |x|
Answer:
absolute value
Step-by-step explanation:
Answer:
This shows the absolute value of an integer.
Step-by-step explanation:
When you see the lines | | around a number, it should always give you the answer of that number's positive integer. So lets say I out | -2 | the answer for this equation should be 2.
HELP!!
Resolve into factors:
8 – 6а – 9a^2 + 27a^3
[tex]\\ \sf\longmapsto 8-6a-9a^2+27a^3[/tex]
[tex]\\ \sf\longmapsto 27a^30-9a^2-6a+8[/tex]
Take 3a common[tex]\\ \sf\longmapsto 3a(9a^2-3a-2)+8[/tex]
Hence doneI need help, please come answer this
Answer:
[tex]8 \times \frac{15}{5} - (5 + 9) \\8 \times 3 - (14) \\ 24 - 14 \\ = 10[/tex]
I hope I helped you^_^
Plz explain q22 in detail, and if you could the fastest way to do it.
Answer:
Hello,
Step-by-step explanation:
30°=π/6 (rad)
[tex]L=\theta*R=\dfrac{\pi}{6} *120\\\\=20*\pi\\\\\approx{20*3=60\ (cm)}[/tex]
A boat goes 24 miles at a constant speed in 4 hours against a river current. It takes the boat 3 hours to go the same distance at the same speed with the current of the river. What is the speed of the boat and what is the current of the river?
Boat speed: Speed of Current:
Answer: 7 miles/h and 1 miles/h
Step-by-step explanation:
With the speed of current = x + 1
Against the speed of current = x - 1
ATQ
4(x-1) = 3(x+1)
4x-4 = 3x+3
4x - 3x = 3+4
x = 7
Speed of boat = 7miles/h
Current of river = 1 miles/h
please click thanks and mark brainliest if you like :)
Answer:
Hello,
Boat speed=7 miles/h
Current speed = 1 mile/h
Step-by-step explanation:
I am going to try to explain.
Let say V the speed of the boot (V like vitesse in french)
Let say v the speed of the current.
distance=24 miles
[tex]\left\{\begin{array}{ccc}V-v&=&\dfrac{24}{4} \\V+v&=&\dfrac{24}{3} \\\end{array}\right.\\\\\left\{\begin{array}{ccc}V-v&=&6 \\V+v&=&8 \\\end{array}\right.\\\\Adding\ the\ 2\ equations\ and\ substracting\ them \\\\\\\left\{\begin{array}{ccc}2V&=&14 \\2v&=&2 \\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}V&=&7 \\v&=&1 \\\end{array}\right.\\\\[/tex]
Boat speed=7 miles/h
Current speed = 1 mile/h
Part C Next, find the length of BC place point F at (4,4) and draw BF and FC now you hav the right ∆BFC with BC as the hypotenuse find BC and FC ising the coordinates of B,C, and,F then use the Pythagorean theorem to find BC show your work need help ASAP giving thanks and points away I just need these answer fast ???
Answer:
BF = |4 – 1| = 3
FC = |4 – 0| = 4
Using the Pythagorean Theorem to find BC:
BC2 = BF2 + FC2
BC2 = 32 + 42
BC2 = 9 + 16
BC = sqaure root 25
BC = 5
Step-by-step explanation:
The length of BC is 5 unit.
What is Pythagoras Theorem?If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:
|AC|^2 = |AB|^2 + |BC|^2
where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).
We need to find the length of BC place point F at (4,4) and draw BF and FC now you have the right ∆BFC with BC as the hypotenuse find BC and FC using the coordinates of B,C, and,F then use the Pythagorean theorem to find BC.
Using the Pythagorean Theorem to find BC:
BC^2 = BF^2 + FC^2
BC^2 = 32 + 42
BC^2 = 9 + 16
BC = √25
BC = 5
So, BF = |4 – 1| = 3
FC = |4 – 0| = 4
Learn more about Pythagoras theorem here:
https://brainly.com/question/12105522
#SPJ2
HELP PLS HELPIf the length of the minor axis of an ellipse is 6 units and the length of the major axis is 10 units, how far from the center are the foci located?
Answer:
4
Step-by-step explanation:
The distance between the center are the foci located 8 units.
It is required to find the focus is c.
What is ellipse?A closed plane curve generated by a point moving in such a way that the sums of its distances from two fixed points is a constant.
Given that:
The length of the major axis is 2a,
length of the major axis
2a=10
a=5
The length of the minor axis is 2b.
Length of the minor axis
2b=6
b=3
The distance between the center and either focus is c,
c^{2} =a^{2} -b^{2}
c^{2} =5^{2} -3^{2}
c^{2} =25-9
c=8
So, the distance between the center are the foci located 8 units.
Learn more about ellipse here:
https://brainly.com/question/24330006
#SPJ2
if you can travel 25 miles in 35 minutes, how long should it take you to travel 12 miles?
Answer:
It's going to take you 17 min to travel 12 miles
assuming you are going with mph
Step-by-step explanation:
I looked at a speed calculator and calculated that to go 25 miles in 35 min, you were going 42 mph. so I changed the imput to 12 miles and I got my answer.
The table shows the steps for solving the given inequality 4-3(x-5)>6x-17
Step-by-step explanation:
(=) 1 ( x-5 ) > 6x-17
(=) x-5 > 6x -17
(=) -5x > -12
=> x < 12/5
Find the inverse of the given function. f(x) = 7x – 4
Hi there!
[tex]\large\boxed{y = \frac{x + 4}{7}}[/tex]
f(x) = 7x - 4
Rewrite f(x) with y:
y = 7x - 4
Swap the x and y variables:
x = 7y - 4
Solve for y:
x + 4 = 7y
y = (x + 4)/7
Evaluate ∫4x cos(2-3x)dx
Answer:
[tex]{ \sf{ \int 4x \cos(2 - 3x) dx = {4x}^{2} \cos(2 - 3x) + c }}[/tex]
Step-by-step explanation:
From integration by parts:
[tex]{ \boxed{ \bf{ \int u \: \frac{dv}{dx} = uv - \int v \: \frac{du}{dx} }}}[/tex]
let u be cos(2-3x) and let dv/dx be 4x:
[tex]{ \sf{ \frac{du}{dx} = 3 \sin(2 - 3x) }} \\ \\ { \sf{ v = \int 4x = 2 {x}^{2} }}[/tex]
Substitute in formular box:
[tex]{ \sf{ = (2 {x}^{2} \times \cos(2 - 3x)) - \int 2 {x}^{2} .3 \sin(2 - 3x) dx}} \\ = { \sf{2 {x}^{2} ( \cos(2 - 3x) - 3 \int \sin(2 - 3x)dx }} \\ { \sf{ = 2 {x}^{2} ( \cos(2 - 3x) - 3( - \frac{1}{3} \cos(2 - 3x) ) + c}} \\ { \sf{ = {4x}^{2} \cos(2 - 3x) + c}}[/tex]
1/a+b + 1/a-b +2b/a^2-b^2 simplify
Answer:
[tex]\frac{2}{a-b}[/tex]
Step-by-step explanation:
Given
[tex]\frac{1}{a+b}[/tex] + [tex]\frac{1}{a-b}[/tex] + [tex]\frac{2b}{a^2-b^2}[/tex] ← a² - b² is a difference of squares
= [tex]\frac{1}{a+b}[/tex] + [tex]\frac{1}{a-b}[/tex] = [tex]\frac{2b}{(a-b)(a+b)}[/tex] ← LCD is (a - b)(a+b)
= [tex]\frac{a-b+a+b+2b}{(a-b)(a+b)}[/tex]
= [tex]\frac{2a+2b}{(a-b)(a+b)}[/tex]
= [tex]\frac{2(a+b)}{(a-b)(a+b)}[/tex] ← cancel common factor (a + b) on numerator/ denominator
= [tex]\frac{2}{a-b}[/tex]
which of the following represents 10 on a number line
Answer:
don't understand....................
Me ajudem
1- a) 5 ( x – 1) = 30
b) 3 (x + 10 ) – 2 ( x – 5 ) = 0
Answer:
a)7, b)-40
Step-by-step explanation:
a) 5(x-1)=30
=>5x -5=30
=>5x=30+5
=>5x=35
=>x=35/5
so, x=7
b)3(x+10)-2(x-5)=0
=>3x+30-2x+10=0
=>x+40=0
so,x=-40
What is the radius of one of the circles?
Answer:
[tex]\sqrt{3}[/tex]
Step-by-step explanation:
[tex]\frac{2\sqrt{3} }{2}=\sqrt{3}[/tex]
I hope this helps!
pls ❤ and give brainliest pls
solve it please. Just wanted to check my drawing skill but please solve it
Answer:
Step-by-step explanation:
I'm assuming that strange looking thing is a 9, so begin by multiplying both sides by that denominator to get:
[tex]x-9=\sqrt{x}+3[/tex] then subtract 3 from both sides to get
[tex]x-12=\sqrt{x}[/tex] and then square both sides to get
[tex]x^2-24x+144=x[/tex] and get everything on one side to solve for x by factoring:
[tex]x^2-25x+144=0[/tex] and factor that however it is you have learned to factor second-degree polynomials to get that
x = 16 and x = 9. We have to check for extraneous solutions because anytime you manipulate an equation, as we did by squaring both sides, you run the risk of these solutions that actually don't work when you plug them back into the original equation. Let's try 16 first:
[tex]\frac{16-9}{\sqrt{16}+3 }=1[/tex] If 16 is a solution, then this statement will be mathematically true.
[tex]\frac{7}{4+3}=1[/tex] and [tex]\frac{7}{7}=1[/tex] so 16 works. Let's try 9:
[tex]\frac{9-9}{\sqrt{9}+3 }=1[/tex] We know that one doesn't work, because 9-9 = 0 and 0 over anything = 0, not 1.
x = 16 is the only solution.
Answer:
x = 16
Step-by-step explanation:
[tex]\frac{x-9}{\sqrt{x}+3}=1[/tex]
Cross multiply,
x - 9 = √x + 3
Subtract 3 from both sides
x - 9 - 3 = √x
x - 12 = √x
Square both sides
(x -12)² = (√x)²
x² - 2 * x*12 + 12² = x
x² - 24x + 144 = x
x² - 24x + 144 - x = 0
x² - 25x + 144 = 0
Sum = -25
Product = 144
Factors = -9 , -16 {(-9)+(-16) = -25 & (-)*(-16) = 144}
x² - 25x + 144 = 0
x² - 16x - 9x + (-9)*(-16) = 0
x(x - 16) - 9(x - 16) = 0
(x - 16) (x - 9) = 0
x - 16 = 0 ; x - 9 = 0
x = 16 ; x = 9
x = 9 is an extraneous solution.
When we plug in 9 in the LHS of the equation,
LHS = [tex]\frac{9-9}{\sqrt{9}+3}[/tex]
[tex]= \frac{0}{3+3}[/tex]
= 0 ≠ RHS
So, x = 16 is the only solution
help?!?!??!!?!?????!
Answer:
[tex]n=10[/tex]
Step-by-step explanation:
[tex]\frac{4^8}{(4^2)^-^3}\ / 4^4=4^n[/tex]
Simplify, remember, an exponent raised to the power of another exponent is equal to the product of the two exponents,
[tex]\frac{4^8}{(4^2)^-^3}\ / 4^4=4^n[/tex]
[tex]\frac{4^8}{4^-^6}\ / 4^4=4^n[/tex]
Now bring the term in the denominator (number under the fraction bar) to the numerator (number over the fraction bar). This can be done by multiplying the exponent of the denominator by (-1).
[tex]\frac{4^8}{4^-^6}\ / 4^4=4^n[/tex]
[tex]4^8(4^(^-^1^)^(^-^6^))\ / 4^4=4^n[/tex]
Simplify,
[tex]4^8(4^6)\ / 4^4=4^n[/tex]
Remember, multiplying two numbers of the same base is the same as adding their exponents, apply this property here,
[tex]4^8(4^6)\ / 4^4=4^n[/tex]
[tex]4^1^4\ / 4^4=4^n[/tex]
Dividing two numbers of the same base is the same as subtraction their exponents,
[tex]4^1^4\ / 4^4=4^n[/tex]
[tex]4^1^0=4^n[/tex]
Thus, the following statement can be made,
[tex]4^1^0=4^n[/tex]
[tex]n=10[/tex]
Explain the steps necessary to convert a quadratic function in standard form to vertex form.
Answer:
A quadratic function in standard form is converted to vertex form by completing the square. The first two terms are used to create a perfect square trinomial after a zero pair is added. The zero pair is found by taking half of the x-term coefficient and squaring it. The original constant term and the negative value of the zero pair are then combined.
Step-by-step explanation:
Answer:
A quadratic function in standard form is converted to vertex form by completing the square. The first two terms are used to create a perfect square trinomial after a zero pair is added. The zero pair is found by taking half of the x-term coefficient and squaring it. The original constant term and the negative value of the zero pair are then combined.
Step-by-step explanation:
Sample response
I really need this answered!
Answer:
Its AA similaroty theorem
