The circle below is centered at (2, 3) and has a radius of 4. What is its
equation?
A. (x-3)2 + (y - 2)2 = 16
O B. (x-3)2 + (y-2)2 = 4
C. (x - 2)2 + (y - 3)2 = 16
O D. (x-2)2 + (y-6)2 = 4

Answer:

It is a direct variation...

The price of flour does not increase or decrease the

more that you purchase (no discount for large purchases)

(1,0.5) means that a pound of flour costs 50

40 pounds would cost $20

Step-by-step explanation:

The test statistic is given by t and t is calculated with the help of the test statistic formula. The value of t is 4.45.

The test statistic summarizes the observation data into a unique number using central tendency, the variation, sample, and size in your statistical model.

here, we have,

The given information will be shown below.

The first sample size n₁ = 36

The second sample size n₂ = 34

The mean of the first sample x₁ = 68.5

The mean of second sample x₂ = 70

Then the test statistic will be given as:

t = -4.45

The test statistic | t | = |–4.45| = 4.45

More about the test statistic link is given below.

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complete question:

g A test was conducted to determine if there is a difference between Canadian and American average heart rates. A group of 36 Canadians and 34 Americans were randomly selected and their heart rates measured in beats per minute (bpm). The mean heart rate for Canadians was 68.5 and 70 for Americans. The pooled standard deviation of 2.0 beats/minute was calculated. Estimate a plausible range of differences between the mean heart rate of Canadians and Americans. What statistical procedure should be used to answer this research question

Answer:

The numbers that 430 is divisible by are 1, 2, 5, 10, 43, 86, 215, and 430.

Answer:

1,2,5

A,B,E

Intelligence

Study habits

Work schedule

ED2021

Intelligence and study habits could be mitigated by random assignments.

Options A and B are the correct answer.

Random assignment refers to the process of randomly assigning participants to either the treatment or control group in an experiment.

We have,

Random assignment is done to minimize the effect of extraneous variables, such as intelligence and study habits, that could potentially affect the results of the experiment.

By randomly assigning participants to either the treatment or control group, the differences between the two groups are assumed to be due to chance alone.

Variables such as the professor, course textbook, and work schedule are not affected by random assignments.

These variables are considered to be controlled variables that are held constant across both the treatment and control groups.

Thus,

Intelligence and study habits could be mitigated by random assignments.

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A rectangle can be constructed using a straightedge, and a setsquare or compass

Please find attached the drawing of rectangle ABCD

The steps to construct the rectangle ABCD are as follows:

Question:

The missing part of the question is the name of the rectangle = ABCD

The given parameters are;

The length of the side AB = 8 cm

The length of the diagonal of the rectangle ABCD = AC = 10 cm

The steps to construct a rectangle are;

h² = [tex]\overline{AC}[/tex]² - [tex]\overline{AB}[/tex]²

∴ h² = 10² - 8² = 36

h = √36 = 6

h = 6 cm = The length of the sides [tex]\mathbf{\overline{AD}}[/tex] and [tex]\mathbf{\overline{CB}}[/tex]

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Answer: r = 50 miles/h

Step-by-step explanation:

Let r be the rate of average speed.

Then

r = D/t

r = 150/3

r = 50 miles/h

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Answer:

40 mph.

Step-by-step explanation:

Suppose grandma's house is  30 miles away (any distance would do but 30 is convenient).

Speed = distance / time

time = distance / speed

Time to get there =  30/60 = 1/2 hour.

Time to get back = 30/30 = 1 hour

Average speed  = total distance/ total time

=  (30 + 30) / ( 1 + 1/2)

= 60 / 1.5

=  40 miles per hour.

You cannot take the average of the speeds directly

(60+ 30)/2  = 45 is not correct as you cannot average ratios ( speed is a ratio).

Let breadth be x

Length=5x

ATQ

[tex]\\ \sf \longmapsto Area=Length\times breadth[/tex]

[tex]\\ \sf \longmapsto 5x(x)=180[/tex]

[tex]\\ \sf \longmapsto 5x^2=180[/tex]

[tex]\\ \sf \longmapsto x^2=\dfrac{180}{5}[/tex]

[tex]\\ \sf \longmapsto x^2=36[/tex]

[tex]\\ \sf \longmapsto x=\sqrt{36}[/tex]

[tex]\\ \sf \longmapsto x=6in[/tex]

The last part answers the first part for you, just look at the y-values.

In other words:

A' (-8, 2)

B' (-4, 3)

C' (-2, 8)

D' (-10, 6)

Explanation:

When you reflect any point over the x-axis, the y-value of the ordered pair is going to change.

This makes sense especially considering that the x-axis is horizontal, so the only way you could cross is to move up or down. If you were to move left or right, you'd only be able to cross the y-axis, since it's vertical.

Now for the last part, as I mentioned above, if you are reflecting across the y-axis, the x-values of the ordered pair is going to change.

A'' (8, 2)

B'' (4, 3)

C'' (2, 8)

D'' (10, 6)

Take note that the only thing that changes for the respective value is its sign, while the number itself stays the same.

9514 1404 393

Answer:

  (c)  On a coordinate plane, a dashed straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the left of the line is shaded.

Step-by-step explanation:

The x-coefficient is positive, so we can determine the shading from ...

  2x ... < ... (pay attention to the x-term and the inequality symbol)

That is, the solution region will have x values that are less than those on the (dashed) boundary line. Lower x-values are to the left, hence shading is on the left side of the boundary. (That's all you need to know here to make the correct choice.)

_____

Additional comment

If the choices are "above" or "below", then you will want to look at the y-term and the inequality symbol. If the coefficient of the variable of interest is negated (as it is for y here), then you need to consider the inequality symbol reversed: -y < ...   ⇔   y > .... Here, that means the shading is above the line. Since the slope of the line is positive, "left" and "above" are the same thing.

Answer:

c

Step-by-step explanation:

E2021

9514 1404 393

Answer:

  221 hours

Step-by-step explanation:

The population is given by the exponential equation ...

  population = (initial value) × (1 +growth rate)^t

where the units of t are the same as the units of growth rate.

This lets us write ...

  p(t) = 5000×1.01^t

We want this to be 45000, so ...

  45000 = 5000×1.01^t

  9 = 1.01^t . . . . . . . . . . . . divide by 5000

  log(9) = t×log(1.01) . . . . take logs

  t = log(9)/log(1.01) ≈ 220.8

It will take about 221 hours for the population to reach 45000.

Answer:

Step-by-step explanation:

P = 2(3x-20) + 2(2x+4) = (6x-40) + (4x+8) = 10x-32

The required perimeter of the playground is 10x-32.

The length of the playground measures (3x-20) metres.
The width of the playground measures (2x+4) metres.

Perimeter, is the measure of the figure on its circumference.

The Required perimeter is for the playground is given by
= 2(3x-20) + 2(2x+4)

= 10x-32

Thus the required perimeter of the playground is 10x-32.

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Answer:

84.16, 84.31, 675/8, 423/5

Step-by-step explanation:

We need to find the amount of money Janet invested in 10 years to yield 7425 EUR

She invested EUR 21,214.29

Simple interest = P × R × T

Where,

P = principal = ?

R = interest rate = 3.5% = 0.035

T = Time = 10 years

Simple interest = 7425 EUR

Simple interest = P × R × T

7425 = p × 0.035 × 10

7425 = p × 0.35

7425 = 0.35p

Divide both sides by 0.35

P = 7425 / 0.35

= 21,214.285714285

Approximately,

P = EUR 21,214.29

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If y = y(x), then the derivative with respect to x is dy/dx. Differentiating both sides of the given equation gives

d/dx [4x ² + y ²] = d/dx [36]

8x + 2y dy/dx = 0

2y dy/dx = -8x

dy/dx = -4x/y

The turning points of the curve, taken as a function of x, are those points where the derivative vanishes.

-4x/y = 0   ===>   x = 0

This value of x corresponds to two points on the curve,

4×0² + y ² = 36   ===>   y ² = 36   ===>   y = ±6

So there are two turning points, (0, -6) and (0, 6).

9514 1404 393

Answer:

  f(x) = (2x -9)/(x -2)

Step-by-step explanation:

We can use the fact that g(g^-1(x)) = x.

  [tex](f\circ g)(x) = f(g(x))\\\\(f\circ g)(g^{-1}(x))=f(g(g^{-1}(x)))=f(x)[/tex]

So, we need to know the inverse of g(x):

  x = g(y)

  x = 5y +2

  x -2 = 5y

  y = (x -2)/5 . . . . inverse of g(x)

Then we have ...

  [tex]f(x)=(f\circ g)(g^{-1}(x))=(f\circ g)\left(\dfrac{x-2}{5}\right)\\\\f(x)=\dfrac{2\left(\dfrac{x-2}{5}\right)-1}{\left(\dfrac{x-2}{5}\right)}=\dfrac{2x-4-5}{x-2}\\\\\boxed{f(x)=\dfrac{2x-9}{x-2}}[/tex]

Answer: no, the vertical scale does not start at zero.

Step-by-step explanation:

The probability that he receives an invitation to work in a bank given that he defends his diploma excellently is [tex]\mathbf{0. \overline 6}[/tex]

The reason for the above probability value is as follows;

The known parameters are;

The probability that a graduate of the Faculty of Finance will defend the diploma excellently, P(A) = 0.6

The probability that he will defend perfectly and receive an invitation to work at a bank, P(A∩B) = 0.4

The unknown parameter is;

The probability that the student will receive an invitation from the bank given that the student defend the diploma excellent, [tex]\mathbf {P(B \ | \ A)}[/tex]

The process;

[tex]\mathbf{ P(B \ | \ A)}[/tex] is found using the conditional probability formula as follows;

[tex]\mathbf {P(B \ | \ A) = \dfrac{P(A \cap B) }{P(A)}}[/tex]

Plugging in the values, we get;

[tex]P(B \ | \ A) = \dfrac{0.4 }{0.6} = \dfrac{2}{3} = 0. \overline 6[/tex]

The probability that the student will receive an invitation from the bank given that the student defend the diploma excellent, [tex]P(B \ | \ A)[/tex] = [tex]\mathbf {0. \overline 6}[/tex]

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Answer:

[tex]y=\frac{3}{2}x-3.5[/tex] or, preferably, [tex]y=\frac{3}{2}x-\frac{7}{2}[/tex]

Step-by-step explanation:

First is to find the perpendicular slope. In this case, you swap the numerator and denominator and then multiply that fraction by -1.

In this case, -2/3's inverse slope is 3/2.

Now, the initial y=3/2 passes through 7.5,5

So, you must subtract 3.5 from that to make it pass through 4,5.

In this way, you get the answer in slope-intercept form.

Answer:

y = [tex]\frac{3}{2}[/tex] x - 1

Step-by-step explanation:

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{2}{3} }[/tex] = [tex]\frac{3}{2}[/tex] , then

y = [tex]\frac{3}{2}[/tex] + c ← partial equation in slope- intercept form

To find c substitute (4, 5) into the partial equation

5 = 6 + c ⇒ c = 5 - 6 = - 1

y = [tex]\frac{3}{2}[/tex] x - 1 ← equation of line

Answer:

13.99 x 2 = 27.98 dollars

now if they were 14 dollars exactly and you doubled that it would be 28 dollars so the difference would be 0.02 cents

Step-by-step explanation:

Answer:

Step-by-step explanation:

87°32' = 86°92'

(86°92')/2 = 43°46'

B = 13/(16cos(43°46')) = 1.125

Answer:

Step-by-step explanation:

Answer:

CD = 38

Step-by-step explanation:

Since AB = 3x + 2, CD = 3x + 2

To solve for the length of CD, we'll need to solve for x first by using the perimeter formula

Solving for x...

[tex](3x+2)+(3x+2)+2x+2x=124[/tex]

[tex]3x + 3x + 2x + 2x = 120[/tex]

[tex]10x=120[/tex]

[tex]x=\frac{120}{10}[/tex]

[tex]x=12[/tex]

Now that we know what x equals, plug in x into the expression of side CD

CD = 3x + 2

CD = 3(12) + 2

CD = 36 + 2

CD = 38

Therefore, the length of side CD = 38

-------------------------------------------------------

Check:

AB = CD | BC = DA

38 + 38 for AB and CD

BC + DA = 2x + 2x

BC + DA = 2(12) + 2(12)

BC + DA = 24 + 24

BC + DA = 48

38 + 38 + 48 = perimeter

perimeter = 124

Answer:

I'm not sure if the kite outside has at least a pair of equal sides. The rest I think are right though? Correct me if I'm wrong.

Answer:

B

Step-by-step explanation:

Total segment bought=190+27=217 segments

Total length of the whole anchor=217*9/2=1953/2=976 1/2 meters

Answer

50.24

Step-by-step explanation:

Answer:

3/5

Step-by-step explanation:

um 3/5+2/5 = 1

[tex]\\ \sf\longmapsto f(-1)[/tex]

[tex]\\ \sf\longmapsto -2x^3+3x^2-22[/tex]

[tex]\\ \sf\longmapsto -2(-1)^3+3(-1)^2-22[/tex]

[tex]\\ \sf\longmapsto -2(-1)+3(1)-22[/tex]

[tex]\\ \sf\longmapsto 2+3-22[/tex]

[tex]\\ \sf\longmapsto 5-22[/tex]

[tex]\\ \sf\longmapsto -17[/tex]